Internal Internal Forces Forces
|
|
- Loraine Morris
- 5 years ago
- Views:
Transcription
1 Internal Forces ENGR 221 March 19, 2003
2 Lecture Goals Internal Force in Structures Shear Forces Bending Moment Shear and Bending moment Diagrams
3 Internal Forces and Bending The bending moment, M. Moment
4 Internal Forces and Bending The shear force, V. Moment
5 Example Internal Forces in a Determine the internal forces in member ACF at point J and in member BCD at point K. Frame Problem
6 Example Internal Forces in a Frame Problem F x Determine the forces at = 0 = R Ex Ex R = 0 N F = 0 = 2400 N + R + R M y Ey F E R + R = Ey F F 2400 N ( ) ( )( ) = 0 = R 4.8 m 2400 N 3.6 m R = 1800 N F R = Ey 600 N R Ex R Ey R F
7 Example Internal Forces in a Look at the member BCD Frame Problem F = 0 = 2400 N + F + F M y By Cy B F + F = By Cy Cy 2400 N ( ) ( )( ) = 0 = R 2.4 m 2400 N 3.6 m R = Cy By 3600 N R = 1200 N
8 Example Internal Forces in a Look at the member ACF Frame Problem F y = 0 = 3600 N N + F = 1800 N Ay F Ay
9 Example Internal Forces in a Look at the member ABE Frame Problem Fy = 0 = 1800 N N N Fy = 0N
10 Example Internal Forces in a Take a look at section ACF at point J 5.4 m θ = tan = m Frame Problem 1 o Which section would you like to have to compute the moments? θ
11 Example Internal Forces in a Frame Problem Take a look at section ACF at point J F M = M 1800 N 1.2 m = 0 J M = 1800 N 1.2 m J J F = 2160 N-m ( ) ( ) = F ( o ) J 1800 N cos x = N ( o ) F y = VJ N sin V = N J
12 Example Internal Forces in a Frame Problem Determine the internal forces in ember BCD at point K. K M = M N 1.5 m = 0 K K M = 1200 N 1.5 m F K K = 1800 N-m F = 0 = x = 0N y K F k ( ) F = V 1200 N V = 1200 N ( )
13 Beams Definition A beam is defined as a structural member designed primarily to support forces acting perpendicular to the axis of the member. The principal i difference between beams and the axially loaded bars and torsionally loaded shafts is in the direction of the applied load.
14 Beams Supports A beam have a variety of supports. - roller ( 1-DOF) - pinned ( 2-DOF) - fixed ( 3-DOF)
15 Beams Loadings A beam have a variety of loads. - point loads - distributed loads - applied moments
16 Beams Types A beam can be classified as statically determinate beam, which means that t it can be solved using equilibrium equations, or it is...
17 Beams Types A beam can be classified as statically indeterminate beam, which h can not be solved with equilibrium equations. It requires a compatibility condition.
18 Beams Types A combination beam can be either statically determinate or indeterminate. i t These two beams are statically determinate, because the hinge provides another location, where the moment is equal to zero.
19 Shear and Bending moment Diagrams In order to generate a shear and bending moment diagram one needs to Draw the free-body diagram Solve for reactions Solve for the internal forces (shear, V, and bending moment, M)
20 Beam Sections A beam with a simple load in the center of the beam. Draw the free-body diagram. F = 0 y M = 0 z
21 Beam Sections Starting from the left side a take a series of section of the beam a compute the shear and bending moment of the beam.
22 Beam Sections The plot of the resulting series of shear and bending moment are the shear and bending moment diagrams. The technique is a cutting method.
23 Example Shear and Bending Moment Diagram Obtain the shear and bending moment diagram for the beam.
24 Example Shear and Bending Moment Diagram Draw the free body diagram and solve for equilibrium. i F = 0 = 20 kn + R 40 kn + R y By D RBy + RD = 60 kn M B ( ) ( ) R ( ) = 0 = 20 kn 2.5 m 40 kn 3.0 m m R = 14 kn D R = 46 kn By D
25 Example Shear and Bending Moment Diagram Look at the sections 1-1. F = 1-1 V = kn M = M = ( ) 20 kn x
26 Example Shear and Bending Moment Diagram Look at the section 2-2. F = V 2 2 = 20 kn M = 22 = M kn ( 2.5m ) M = 50 kn-m 2-2
27 Example Shear and Bending Moment Diagram Look at the section at 3-3. F = V = 20 kn + 46 kn y 3 3 V = kn MB = 0= M kn ( 25m 2.5 ) M = 50 kn-m 3 3
28 Example Shear and Bending Moment Diagram Look at the section 4-4. y Fy = V4 4= 20 kn + 46 kn V4 4= 26 kn M ( ) ( ) == M + 20 kn 5.5 m 46 kn 3.0 m M 4-4 = 28 kn-m
29 Example Shear and Bending Moment Diagram Look at section 5-5. F = V = 20 kn + 46 kn 40 kn y 5 5 V 5 5= 14 kn M5-5 = 0 = M kn ( 5.55 m ) 46 kn ( 3.0 m ) M = kn-m
30 Example Shear and Bending Moment Diagram Look at section 6-6 F = V = 20 kn + 46 kn 40 kn y 6 6 V = 14 kn 6 6 M ( ) ( ) ( ) = 0 = M + 20 kn 7.5 m 46 kn 5.0 m + 40 kn 2.0 m M 6-6 = 0 kn-m
31 Example Shear and Bending Moment Diagram Look at section end Fy = Vend = 20 kn + 46 kn 40 kn + 14 kn V = end 0kN Mend = 0= Mend + 20 kn ( 7.5 m ) 46 kn ( 5.0 m ) + 40 kn ( 2.0 m ) M = end 0 kn-m
32 Example Shear and Bending Moment Diagram Draw the shear and bending moment diagrams. Location (m) Shear (kn) Moment (kn-m)
33 Class Shear and Bending Moment Diagram Draw the shear and bending moment diagram.
34 Relations between Load, Shear, and Bending Moment Look at a section F = = V w x V + V y 0 V = w x V d V = w { = w x dx x 0 d ( )
35 Relations between Load, Shear, and Bending Moment Multiply by dx d V = w dx Integrate over V c to V d V d x d V c d V = w dx Vd Vc = w dx x c x d x c
36 Relations between Load, Shear, and Bending Moment Integrate over V c to V d V d V c x d V = w dx d xd V d V = c w d x x The difference of the shear is the area under the load curve between c and d. x c c
37 Relations between Load, Shear, and Bending Moment Look at a section x x M = 0 = M + w x C 2 V x + M + M ( x ) 2 ( ) M = V x w 2 M x d M = V w { = V x 2 0 dx x
38 Relations between Load, Shear, and Bending Moment Multiply by dx d M = V dx Integrate over M c to M d M d M c x d M = V dx d x M M V dx d c x d = c x c
39 Relations between Load, Shear, and Bending Moment Integrate over M c to M d M M d c x d M = V dx d x xd M = d M c V d x x The difference of the moment is the area under the load curve between c and d. c c
40 Example - Shear and Bending Moment Diagram Draw the shear and bending moment diagram.
41 Example - Shear and Bending Draw free-body diagram and use equilibrium equations. F = 0 = R wl+ R y A B R + R = wl A Moment Diagram B L M A = 0 = wl + RBL 2 wl wl RB = & RA = 2 2
42 Example - Shear and Bending Shear diagram. Moment Diagram wl F ( ) y = V x = wx 2 Note that the area under the load diagram.
43 Example - Shear and Bending Remember that dm M V dx = Where will the maximum moment occur? Moment Diagram
44 Example - Shear and Bending The maximum will occur where dm M dx = Moment Diagram The maximum moment is the positive area under the curve 0 M 1 wl L wl = =
45 Example - Shear and Bending The moment equation M x = ( ) ( ) Moment Diagram V x dx 2 x x w wl = ( ) 2 2 Note that the slope of the moment diagram is equal to the shear.
46 Example - Shear and Bending Moment Diagram Draw the shear and bending moment diagram
47 Example - Shear and Bending Moment Diagram Free-body diagram R Ax F x = 0 = R Ax ( ) R Ay F = 0= R 20 kn/m 6 m + R y Ay C R + R = 120 kn Ay C R C M A = 0 = 20 kn/m ( 6 m )( 3 m ) + R C ( 9 m ) R = 40 kn & R = 80 kn C Ay
48 Example - Shear and Bending Look at the shear V V A B = 80 kn Moment Diagram ( ) = 80 kn 20 kn/m 6 m = 40 kn ( ) Vx = 80 kn 20 kn/m x = 0 kn x = 4 m V = 40 kn - C + V C = 40 kn + 40 kn = 0 kn
49 Example - Shear and Bending Look at the shear diagram V V A B = 80 kn Moment Diagram ( ) = 80 kn 20 kn/m 6 m = 40 kn ( ) Vx = 80 kn 20 kn/m x = 0 kn x = 4 m V = 40 kn - C + V C = 40 kn + 40 kn = 0 kn
50 Example - Shear and Bending Find the moments M 0 m = 0 kn-m M M M 4 m 6 m 9m 1 = 80 kn 4 m 2 = 160 kn-m Moment Diagram ( )( ) 1 = 160 kn-m kn 2 m = 120 kn-m ( )( ) ( )( ) = 120 kn-m + 40 kn 3 m = 0 kn-m
51 Example - Shear and Bending Draw the moment diagram M 0 m = 0 kn-m M M M 4 m 6 m 9m 1 = 80 kn 4 m 2 = 160 kn-m Moment Diagram ( )( ) 1 = 160 kn-m kn 2 m = 120 kn-m ( )( ) ( )( ) = 120 kn-m + 40 kn 3 m = 0 kn-m
52 Class Shear and Bending Moment Diagram Draw the shear and bending moment diagram for the know reactions
53 Class Shear and Bending Moment Diagram Draw the shear and bending moment diagram
54 Class Shear and Bending Moment Diagram Draw the shear and bending moment diagram
55 Homework (Due 3/26/03) Problems: 8-15, 8-20, 8-37, 8-41, 8-51
56 Bonus Problem Shear and Bending Moment Diagram Draw the shear and bending moment diagram
57 Bonus Problem Shear and Bending Moment Diagram Draw the shear and bending moment diagram
Types of Structures & Loads
Structure Analysis I Chapter 4 1 Types of Structures & Loads 1Chapter Chapter 4 Internal lloading Developed in Structural Members Internal loading at a specified Point In General The loading for coplanar
More informationChapter 7: Internal Forces
Chapter 7: Internal Forces Chapter Objectives To show how to use the method of sections for determining the internal loadings in a member. To generalize this procedure by formulating equations that can
More informationENG202 Statics Lecture 16, Section 7.1
ENG202 Statics Lecture 16, Section 7.1 Internal Forces Developed in Structural Members - Design of any structural member requires an investigation of the loading acting within the member in order to be
More informationModule 3. Analysis of Statically Indeterminate Structures by the Displacement Method
odule 3 Analysis of Statically Indeterminate Structures by the Displacement ethod Lesson 16 The Slope-Deflection ethod: rames Without Sidesway Instructional Objectives After reading this chapter the student
More informationSAB2223 Mechanics of Materials and Structures
S2223 Mechanics of Materials and Structures TOPIC 2 SHER FORCE ND ENDING MOMENT Lecturer: Dr. Shek Poi Ngian TOPIC 2 SHER FORCE ND ENDING MOMENT Shear Force and ending Moment Introduction Types of beams
More informationChapter 11. Displacement Method of Analysis Slope Deflection Method
Chapter 11 Displacement ethod of Analysis Slope Deflection ethod Displacement ethod of Analysis Two main methods of analyzing indeterminate structure Force method The method of consistent deformations
More information8-5 Conjugate-Beam method. 8-5 Conjugate-Beam method. 8-5 Conjugate-Beam method. 8-5 Conjugate-Beam method
The basis for the method comes from the similarity of eqn.1 &. to eqn 8. & 8. To show this similarity, we can write these eqn as shown dv dx w d θ M dx d M w dx d v M dx Here the shear V compares with
More information6. Bending CHAPTER OBJECTIVES
CHAPTER OBJECTIVES Determine stress in members caused by bending Discuss how to establish shear and moment diagrams for a beam or shaft Determine largest shear and moment in a member, and specify where
More informationStress Analysis Lecture 4 ME 276 Spring Dr./ Ahmed Mohamed Nagib Elmekawy
Stress Analysis Lecture 4 ME 76 Spring 017-018 Dr./ Ahmed Mohamed Nagib Elmekawy Shear and Moment Diagrams Beam Sign Convention The positive directions are as follows: The internal shear force causes a
More informationEquilibrium Equilibrium and Trusses Trusses
Equilibrium and Trusses ENGR 221 February 17, 2003 Lecture Goals 6-4 Equilibrium in Three Dimensions 7-1 Introduction to Trusses 7-2Plane Trusses 7-3 Space Trusses 7-4 Frames and Machines Equilibrium Problem
More informationBeams. Beams are structural members that offer resistance to bending due to applied load
Beams Beams are structural members that offer resistance to bending due to applied load 1 Beams Long prismatic members Non-prismatic sections also possible Each cross-section dimension Length of member
More informationBeams are bars of material that support. Beams are common structural members. Beams can support both concentrated and distributed loads
Outline: Review External Effects on Beams Beams Internal Effects Sign Convention Shear Force and Bending Moment Diagrams (text method) Relationships between Loading, Shear Force and Bending Moments (faster
More informationTYPES OF STRUCUTRES. HD in Civil Engineering Page 1-1
E2027 Structural nalysis I TYPES OF STRUUTRES H in ivil Engineering Page 1-1 E2027 Structural nalysis I SUPPORTS Pin or Hinge Support pin or hinge support is represented by the symbol H or H V V Prevented:
More informationSLOPE-DEFLECTION METHOD
SLOPE-DEFLECTION ETHOD The slope-deflection method uses displacements as unknowns and is referred to as a displacement method. In the slope-deflection method, the moments at the ends of the members are
More informationUNIT IV FLEXIBILTY AND STIFFNESS METHOD
SIDDHARTH GROUP OF INSTITUTIONS :: PUTTUR Siddharth Nagar, Narayanavanam Road 517583 QUESTION BANK (DESCRIPTIVE) Subject with Code : SA-II (13A01505) Year & Sem: III-B.Tech & I-Sem Course & Branch: B.Tech
More informationChapter 4.1: Shear and Moment Diagram
Chapter 4.1: Shear and Moment Diagram Chapter 5: Stresses in Beams Chapter 6: Classical Methods Beam Types Generally, beams are classified according to how the beam is supported and according to crosssection
More information[8] Bending and Shear Loading of Beams
[8] Bending and Shear Loading of Beams Page 1 of 28 [8] Bending and Shear Loading of Beams [8.1] Bending of Beams (will not be covered in class) [8.2] Bending Strain and Stress [8.3] Shear in Straight
More informationModule 2. Analysis of Statically Indeterminate Structures by the Matrix Force Method
Module 2 Analysis of Statically Indeterminate Structures by the Matrix Force Method Lesson 11 The Force Method of Analysis: Frames Instructional Objectives After reading this chapter the student will be
More informationDeflections. Deflections. Deflections. Deflections. Deflections. Deflections. dx dm V. dx EI. dx EI dx M. dv w
CIVL 311 - Conjugate eam 1/5 Conjugate beam method The development of the conjugate beam method has been atributed to several strucutral engineers. any credit Heinrich üller-reslau (1851-195) with the
More informationChapter 7: Bending and Shear in Simple Beams
Chapter 7: Bending and Shear in Simple Beams Introduction A beam is a long, slender structural member that resists loads that are generally applied transverse (perpendicular) to its longitudinal axis.
More informationShear Force V: Positive shear tends to rotate the segment clockwise.
INTERNL FORCES IN EM efore a structural element can be designed, it is necessary to determine the internal forces that act within the element. The internal forces for a beam section will consist of a shear
More informationBEAM A horizontal or inclined structural member that is designed to resist forces acting to its axis is called a beam
BEM horizontal or inclined structural member that is designed to resist forces acting to its axis is called a beam INTERNL FORCES IN BEM Whether or not a beam will break, depend on the internal resistances
More informationLecture 7: The Beam Element Equations.
4.1 Beam Stiffness. A Beam: A long slender structural component generally subjected to transverse loading that produces significant bending effects as opposed to twisting or axial effects. MECH 40: Finite
More information- Beams are structural member supporting lateral loadings, i.e., these applied perpendicular to the axes.
4. Shear and Moment functions - Beams are structural member supporting lateral loadings, i.e., these applied perpendicular to the aes. - The design of such members requires a detailed knowledge of the
More informationIf the number of unknown reaction components are equal to the number of equations, the structure is known as statically determinate.
1 of 6 EQUILIBRIUM OF A RIGID BODY AND ANALYSIS OF ETRUCTURAS II 9.1 reactions in supports and joints of a two-dimensional structure and statically indeterminate reactions: Statically indeterminate structures
More informationChapter Objectives. Copyright 2011 Pearson Education South Asia Pte Ltd
Chapter Objectives To generalize the procedure by formulating equations that can be plotted so that they describe the internal shear and moment throughout a member. To use the relations between distributed
More informationMethod of Consistent Deformation
Method of onsistent eformation Structural nalysis y R.. Hibbeler Theory of Structures-II M Shahid Mehmood epartment of ivil Engineering Swedish ollege of Engineering and Technology, Wah antt FRMES Method
More informationDeterminate portal frame
eterminate portal frame onsider the frame shown in the figure below with the aim of calculating the bending moment diagram (M), shear force diagram (SF), and axial force diagram (F). P H y R x x R y L
More informationChapter 7 FORCES IN BEAMS AND CABLES
hapter 7 FORES IN BEAMS AN ABLES onsider a straight two-force member AB subjected at A and B to equal and opposite forces F and -F directed along AB. utting the member AB at and drawing the free-body B
More informationModule 6. Approximate Methods for Indeterminate Structural Analysis. Version 2 CE IIT, Kharagpur
Module 6 Approximate Methods for Indeterminate Structural Analysis Lesson 35 Indeterminate Trusses and Industrial rames Instructional Objectives: After reading this chapter the student will be able to
More informationModule 3. Analysis of Statically Indeterminate Structures by the Displacement Method
odule 3 Analysis of Statically Indeterminate Structures by the Displacement ethod Lesson 21 The oment- Distribution ethod: rames with Sidesway Instructional Objectives After reading this chapter the student
More informationLecture 23 March 12, 2018 Chap 7.3
Statics - TAM 210 & TAM 211 Lecture 23 March 12, 2018 Chap 7.3 Announcements Upcoming deadlines: Monday (3/12) Mastering Engineering Tutorial 9 Tuesday (3/13) PL HW 8 Quiz 5 (3/14-16) Sign up at CBTF Up
More informationENGI 1313 Mechanics I
ENGI 1313 Mechanics I Lecture 25: Equilibrium of a Rigid Body Shawn Kenny, Ph.D., P.Eng. Assistant Professor Faculty of Engineering and Applied Science Memorial University of Newfoundland spkenny@engr.mun.ca
More informationAssumptions: beam is initially straight, is elastically deformed by the loads, such that the slope and deflection of the elastic curve are
*12.4 SLOPE & DISPLACEMENT BY THE MOMENT-AREA METHOD Assumptions: beam is initially straight, is elastically deformed by the loads, such that the slope and deflection of the elastic curve are very small,
More informationStress Analysis Lecture 3 ME 276 Spring Dr./ Ahmed Mohamed Nagib Elmekawy
Stress Analysis Lecture 3 ME 276 Spring 2017-2018 Dr./ Ahmed Mohamed Nagib Elmekawy Axial Stress 2 Beam under the action of two tensile forces 3 Beam under the action of two tensile forces 4 Shear Stress
More informationdv dx Slope of the shear diagram = - Value of applied loading dm dx Slope of the moment curve = Shear Force
Beams SFD and BMD Shear and Moment Relationships w dv dx Slope of the shear diagram = - Value of applied loading V dm dx Slope of the moment curve = Shear Force Both equations not applicable at the point
More informationMethod of Virtual Work Frame Deflection Example Steven Vukazich San Jose State University
Method of Virtual Work Frame Deflection xample Steven Vukazich San Jose State University Frame Deflection xample 9 k k D 4 ft θ " # The statically determinate frame from our previous internal force diagram
More informationMechanics of Materials
Mechanics of Materials 2. Introduction Dr. Rami Zakaria References: 1. Engineering Mechanics: Statics, R.C. Hibbeler, 12 th ed, Pearson 2. Mechanics of Materials: R.C. Hibbeler, 9 th ed, Pearson 3. Mechanics
More informationChapter 5: Equilibrium of a Rigid Body
Chapter 5: Equilibrium of a Rigid Body Chapter Objectives To develop the equations of equilibrium for a rigid body. To introduce the concept of a free-body diagram for a rigid body. To show how to solve
More informationModule 4 : Deflection of Structures Lecture 4 : Strain Energy Method
Module 4 : Deflection of Structures Lecture 4 : Strain Energy Method Objectives In this course you will learn the following Deflection by strain energy method. Evaluation of strain energy in member under
More informationMECE 3321: Mechanics of Solids Chapter 6
MECE 3321: Mechanics of Solids Chapter 6 Samantha Ramirez Beams Beams are long straight members that carry loads perpendicular to their longitudinal axis Beams are classified by the way they are supported
More informationBending Stress. Sign convention. Centroid of an area
Bending Stress Sign convention The positive shear force and bending moments are as shown in the figure. Centroid of an area Figure 40: Sign convention followed. If the area can be divided into n parts
More informationLecture 4: PRELIMINARY CONCEPTS OF STRUCTURAL ANALYSIS. Introduction
Introduction In this class we will focus on the structural analysis of framed structures. We will learn about the flexibility method first, and then learn how to use the primary analytical tools associated
More informationStrength of Materials Prof. S.K.Bhattacharya Dept. of Civil Engineering, I.I.T., Kharagpur Lecture No.26 Stresses in Beams-I
Strength of Materials Prof. S.K.Bhattacharya Dept. of Civil Engineering, I.I.T., Kharagpur Lecture No.26 Stresses in Beams-I Welcome to the first lesson of the 6th module which is on Stresses in Beams
More informationModule 2. Analysis of Statically Indeterminate Structures by the Matrix Force Method
Module 2 Analysis of Statically Indeterminate Structures by the Matrix Force Method Lesson 8 The Force Method of Analysis: Beams Instructional Objectives After reading this chapter the student will be
More informationShear Force and Bending Moment Diagrams
Shear Force and Bending Moment Diagrams V [ N ] x[m] M [ Nm] x[m] Competencies 1. Draw shear force and bending moment diagrams for point loads and distributed loads 2. Recognize the position of maximum
More informationENGR-1100 Introduction to Engineering Analysis. Lecture 13
ENGR-1100 Introduction to Engineering Analysis Lecture 13 EQUILIBRIUM OF A RIGID BODY & FREE-BODY DIAGRAMS Today s Objectives: Students will be able to: a) Identify support reactions, and, b) Draw a free-body
More informationCIV E 205 Mechanics of Solids II. Course Notes
Department of Civil Engineering CIV E 205 Mechanics of Solids II Instructor: Tarek Hegazi Email: tarek@uwaterloo.ca Course Notes Mechanics of Materials Objectives: - Solve Problems in a structured systematic
More informationEquilibrium of a Particle
ME 108 - Statics Equilibrium of a Particle Chapter 3 Applications For a spool of given weight, what are the forces in cables AB and AC? Applications For a given weight of the lights, what are the forces
More informationBeam Design and Deflections
Beam Design and Deflections tation: a = name for width dimension A = name for area Areq d-adj = area required at allowable stress when shear is adjusted to include self weight Aweb = area of the web of
More informationStatically Indeterminate Beams
Deflection Part Staticall Indeterminate eams We can use the same method that we used for deflection to analze staticall indeterminate beams lessed are the who can laugh at themselves for the shall never
More informationInstitute of Structural Engineering Page 1. Method of Finite Elements I. Chapter 2. The Direct Stiffness Method. Method of Finite Elements I
Institute of Structural Engineering Page 1 Chapter 2 The Direct Stiffness Method Institute of Structural Engineering Page 2 Direct Stiffness Method (DSM) Computational method for structural analysis Matrix
More informationASSOCIATE DEGREE IN ENGINEERING EXAMINATIONS SEMESTER /13
ASSOCIATE DEGREE IN ENGINEERING EXAMINATIONS SEMESTER 2 2012/13 COURSE NAME: ENGINEERING MECHANICS - STATICS CODE: ENG 2008 GROUP: AD ENG II DATE: May 2013 TIME: DURATION: 2 HOURS INSTRUCTIONS: 1. This
More information8.3 Shear and Bending-Moment Diagrams Constructed by Areas
8.3 Shear and ending-moment Diagrams Constructed by reas 8.3 Shear and ending-moment Diagrams Constructed by reas Procedures and Strategies, page 1 of 3 Procedures and Strategies for Solving Problems Involving
More information8.1 Internal Forces in Structural Members
8.1 Internal Forces in Structural Members 8.1 Internal Forces in Structural Members xample 1, page 1 of 4 1. etermine the normal force, shear force, and moment at sections passing through a) and b). 4
More informationEngineering Mechanics: Statics in SI Units, 12e
Engineering Mechanics: Statics in SI Units, 12e 5 Equilibrium of a Rigid Body Chapter Objectives Develop the equations of equilibrium for a rigid body Concept of the free-body diagram for a rigid body
More informationSTATICS. Bodies. Vector Mechanics for Engineers: Statics VECTOR MECHANICS FOR ENGINEERS: Design of a support
4 Equilibrium CHAPTER VECTOR MECHANICS FOR ENGINEERS: STATICS Ferdinand P. Beer E. Russell Johnston, Jr. Lecture Notes: J. Walt Oler Texas Tech University of Rigid Bodies 2010 The McGraw-Hill Companies,
More informationEQUIVALENT FORCE-COUPLE SYSTEMS
EQUIVALENT FORCE-COUPLE SYSTEMS Today s Objectives: Students will be able to: 1) Determine the effect of moving a force. 2) Find an equivalent force-couple system for a system of forces and couples. APPLICATIONS
More informationFINAL EXAMINATION. (CE130-2 Mechanics of Materials)
UNIVERSITY OF CLIFORNI, ERKELEY FLL SEMESTER 001 FINL EXMINTION (CE130- Mechanics of Materials) Problem 1: (15 points) pinned -bar structure is shown in Figure 1. There is an external force, W = 5000N,
More informationChapter 2. Shear Force and Bending Moment. After successfully completing this chapter the students should be able to:
Chapter Shear Force and Bending Moment This chapter begins with a discussion of beam types. It is also important for students to know and understand the reaction from the types of supports holding the
More informationEquilibrium of a Rigid Body. Engineering Mechanics: Statics
Equilibrium of a Rigid Body Engineering Mechanics: Statics Chapter Objectives Revising equations of equilibrium of a rigid body in 2D and 3D for the general case. To introduce the concept of the free-body
More information3.1 CONDITIONS FOR RIGID-BODY EQUILIBRIUM
3.1 CONDITIONS FOR RIGID-BODY EQUILIBRIUM Consider rigid body fixed in the x, y and z reference and is either at rest or moves with reference at constant velocity Two types of forces that act on it, the
More informationT2. VIERENDEEL STRUCTURES
T2. VIERENDEEL STRUCTURES AND FRAMES 1/11 T2. VIERENDEEL STRUCTURES NOTE: The Picture Window House can be designed using a Vierendeel structure, but now we consider a simpler problem to discuss the calculation
More informationEQUATIONS OF EQUILIBRIUM & TWO- AND THREE-FORCE MEMEBERS
EQUATIONS OF EQUILIBRIUM & TWO- AND THREE-FORCE MEMEBERS Today s Objectives: Students will be able to: a) Apply equations of equilibrium to solve for unknowns, and, b) Recognize two-force members. In-Class
More informationLecture 0. Statics. Module 1. Overview of Mechanics Analysis. IDeALab. Prof. Y.Y.KIM. Solid Mechanics
Lecture 0. Statics Module 1. Overview of Mechanics Analysis Overview of Mechanics Analysis Procedure of Solving Mechanics Problems Objective : Estimate the force required in the flexor muscle Crandall,
More informationQuizzam Module 1 : Statics
Structural Steel Design Quizzam odule : Statics NAE Draw shear and moment diagrams for the following loading conditions. Note the reactions. Calculate the maximum amount of internal bending moment. 0 500
More informationReview of Strain Energy Methods and Introduction to Stiffness Matrix Methods of Structural Analysis
uke University epartment of Civil and Environmental Engineering CEE 42L. Matrix Structural Analysis Henri P. Gavin Fall, 22 Review of Strain Energy Methods and Introduction to Stiffness Matrix Methods
More informationCHAPTER The linear arch
CHAPTER 6 The Romans were the first to use arches as major structural elements, employing them, mainly in semicircular form, in bridge and aqueduct construction and for roof supports, particularly the
More informationDeflection of Flexural Members - Macaulay s Method 3rd Year Structural Engineering
Deflection of Flexural Members - Macaulay s Method 3rd Year Structural Engineering 008/9 Dr. Colin Caprani 1 Contents 1. Introduction... 3 1.1 General... 3 1. Background... 4 1.3 Discontinuity Functions...
More informationPlane Trusses Trusses
TRUSSES Plane Trusses Trusses- It is a system of uniform bars or members (of various circular section, angle section, channel section etc.) joined together at their ends by riveting or welding and constructed
More informationENR202 Mechanics of Materials Lecture 4A Notes and Slides
Slide 1 Copyright Notice Do not remove this notice. COMMMONWEALTH OF AUSTRALIA Copyright Regulations 1969 WARNING This material has been produced and communicated to you by or on behalf of the University
More informationDeflection of Flexural Members - Macaulay s Method 3rd Year Structural Engineering
Deflection of Flexural Members - Macaulay s Method 3rd Year Structural Engineering 009/10 Dr. Colin Caprani 1 Contents 1. Introduction... 4 1.1 General... 4 1. Background... 5 1.3 Discontinuity Functions...
More information2. Determine the deflection at C of the beam given in fig below. Use principal of virtual work. W L/2 B A L C
CE-1259, Strength of Materials UNIT I STRESS, STRAIN DEFORMATION OF SOLIDS Part -A 1. Define strain energy density. 2. State Maxwell s reciprocal theorem. 3. Define proof resilience. 4. State Castigliano
More informationBOOK OF COURSE WORKS ON STRENGTH OF MATERIALS FOR THE 2 ND YEAR STUDENTS OF THE UACEG
BOOK OF COURSE WORKS ON STRENGTH OF MATERIALS FOR THE ND YEAR STUDENTS OF THE UACEG Assoc.Prof. Dr. Svetlana Lilkova-Markova, Chief. Assist. Prof. Dimitar Lolov Sofia, 011 STRENGTH OF MATERIALS GENERAL
More informationModule 3. Analysis of Statically Indeterminate Structures by the Displacement Method. Version 2 CE IIT, Kharagpur
odule 3 Analysis of Statically Indeterminate Structures by the Displacement ethod Version CE IIT, Kharagpur Lesson The ultistory Frames with Sidesway Version CE IIT, Kharagpur Instructional Objectives
More informationTutorial #1 - CivE. 205 Name: I.D:
Tutorial # - CivE. 0 Name: I.D: Eercise : For the Beam below: - Calculate the reactions at the supports and check the equilibrium of point a - Define the points at which there is change in load or beam
More informationFIXED BEAMS CONTINUOUS BEAMS
FIXED BEAMS CONTINUOUS BEAMS INTRODUCTION A beam carried over more than two supports is known as a continuous beam. Railway bridges are common examples of continuous beams. But the beams in railway bridges
More information7 STATICALLY DETERMINATE PLANE TRUSSES
7 STATICALLY DETERMINATE PLANE TRUSSES OBJECTIVES: This chapter starts with the definition of a truss and briefly explains various types of plane truss. The determinancy and stability of a truss also will
More informationThree torques act on the shaft. Determine the internal torque at points A, B, C, and D.
... 7. Three torques act on the shaft. Determine the internal torque at points,, C, and D. Given: M 1 M M 3 300 Nm 400 Nm 00 Nm Solution: Section : x = 0; T M 1 M M 3 0 T M 1 M M 3 T 100.00 Nm Section
More informationOutline: Centres of Mass and Centroids. Beams External Effects Beams Internal Effects
Outline: Centres of Mass and Centroids Centre of Mass Centroids of Lines, Areas and Volumes Composite Bodies Beams External Effects Beams Internal Effects 1 Up to now all forces have been concentrated
More informationCalculating Truss Forces. Method of Joints
Calculating Truss Forces Method of Joints Forces Compression body being squeezed Tension body being stretched Truss truss is composed of slender members joined together at their end points. They are usually
More informationChapter 7. ELASTIC INSTABILITY Dr Rendy Thamrin; Zalipah Jamellodin
Chapter 7 ESTIC INSTIITY Dr Rendy Thamrin; Zalipah Jamellodin 7. INTRODUCTION TO ESTIC INSTIITY OF COUN ND FRE In structural analysis problem, the aim is to determine a configuration of loaded system,
More informationCIV E 205 Mechanics of Solids II. Course Notes
University of Waterloo Department of Civil Engineering CIV E 205 Mechanics of Solids II Instructor: Tarek Hegazi Room: CPH 2373 G, Ext. 2174 Email: tarek@uwaterloo.ca Course Web: www.civil.uwaterloo.ca/tarek/205-2005.html
More informationThe case where there is no net effect of the forces acting on a rigid body
The case where there is no net effect of the forces acting on a rigid body Outline: Introduction and Definition of Equilibrium Equilibrium in Two-Dimensions Special cases Equilibrium in Three-Dimensions
More informationSub. Code:
Important Instructions to examiners: ) The answers should be examined by key words and not as word-to-word as given in the model answer scheme. ) The model answer and the answer written by candidate may
More informationCIV E 205 Mechanics of Solids II. Course Notes
University of Waterloo Department of Civil Engineering CIV E 205 Mechanics of Solids II Instructor: Tarek Hegazi Room: CPH 2373 G, Ext. 2174 Email: tarek@uwaterloo.ca Course Web: www.civil.uwaterloo.ca/tarek/hegazy205.html
More informationUNIT-V MOMENT DISTRIBUTION METHOD
UNIT-V MOMENT DISTRIBUTION METHOD Distribution and carryover of moments Stiffness and carry over factors Analysis of continuous beams Plane rigid frames with and without sway Neylor s simplification. Hardy
More informationDeflection of Beams. Equation of the Elastic Curve. Boundary Conditions
Deflection of Beams Equation of the Elastic Curve The governing second order differential equation for the elastic curve of a beam deflection is EI d d = where EI is the fleural rigidit, is the bending
More informationPurpose of this Guide: To thoroughly prepare students for the exact types of problems that will be on Exam 3.
ES230 STRENGTH OF MTERILS Exam 3 Study Guide Exam 3: Wednesday, March 8 th in-class Updated 3/3/17 Purpose of this Guide: To thoroughly prepare students for the exact types of problems that will be on
More informationFIXED BEAMS IN BENDING
FIXED BEAMS IN BENDING INTRODUCTION Fixed or built-in beams are commonly used in building construction because they possess high rigidity in comparison to simply supported beams. When a simply supported
More informationSTATICALLY INDETERMINATE STRUCTURES
STATICALLY INDETERMINATE STRUCTURES INTRODUCTION Generally the trusses are supported on (i) a hinged support and (ii) a roller support. The reaction components of a hinged support are two (in horizontal
More informationDue Tuesday, September 21 st, 12:00 midnight
Due Tuesday, September 21 st, 12:00 midnight The first problem discusses a plane truss with inclined supports. You will need to modify the MatLab software from homework 1. The next 4 problems consider
More informationUnit II Shear and Bending in Beams
Unit II Shear and Bending in Beams Syllabus: Beams and Bending- Types of loads, supports - Shear Force and Bending Moment Diagrams for statically determinate beam with concentrated load, UDL, uniformly
More informationEQUATIONS OF EQUILIBRIUM & TWO- AND THREE-FORCE MEMEBERS
EQUATIONS OF EQUILIBRIUM & TWO- AND THREE-FORCE MEMEBERS Today s Objectives: Students will be able to: a) Apply equations of equilibrium to solve for unknowns, and b) Recognize two-force members. In-Class
More informationMECHANICS OF MATERIALS Design of a Transmission Shaft
Design of a Transmission Shaft If power is transferred to and from the shaft by gears or sprocket wheels, the shaft is subjected to transverse loading as well as shear loading. Normal stresses due to transverse
More informationStructural Analysis III Compatibility of Displacements & Principle of Superposition
Structural Analysis III Compatibility of Displacements & Principle of Superposition 2007/8 Dr. Colin Caprani, Chartered Engineer 1 1. Introduction 1.1 Background In the case of 2-dimensional structures
More informationUNIT I ENERGY PRINCIPLES
UNIT I ENERGY PRINCIPLES Strain energy and strain energy density- strain energy in traction, shear in flexure and torsion- Castigliano s theorem Principle of virtual work application of energy theorems
More informationInstitute of Structural Engineering Page 1. Method of Finite Elements I. Chapter 2. The Direct Stiffness Method. Method of Finite Elements I
Institute of Structural Engineering Page 1 Chapter 2 The Direct Stiffness Method Institute of Structural Engineering Page 2 Direct Stiffness Method (DSM) Computational method for structural analysis Matrix
More informationEQUATIONS OF EQUILIBRIUM & TWO-AND THREE-FORCE MEMEBERS
EQUATIONS OF EQUILIBRIUM & TWO-AND THREE-FORCE MEMEBERS Today s Objectives: Students will be able to: a) Apply equations of equilibrium to solve for unknowns, and, b) Recognize two-force members. READING
More informationStructures. Shainal Sutaria
Structures ST Shainal Sutaria Student Number: 1059965 Wednesday, 14 th Jan, 011 Abstract An experiment to find the characteristics of flow under a sluice gate with a hydraulic jump, also known as a standing
More information