The equivalent model of a certain op amp is shown in the figure given below, where R 1 = 2.8 MΩ, R 2 = 39 Ω, and A =
|
|
- Beryl Griffith
- 5 years ago
- Views:
Transcription
1 The equivalent model of a certain op amp is shown in the figure given below, where R 1 = 2.8 MΩ, R 2 = 39 Ω, and A = Section Break Difficulty: Easy Learning Objective: Understand how real operational amplifiers (op amps) function. 1/28
2 1. Award: points Calculate the input resistance of the given circuit. The input resistance of the circuit is 2.8 ± 2% MΩ. The input resistance is the Thevenin equivalent resistance seen at the input terminals, that is R in = 2.8 MΩ. The input resistance of the circuit is 2.8 MΩ. Worksheet Difficulty: Easy Learning Objective: Understand how real operational amplifiers (op amps) function. 2/28
3 2. Award: points Calculate the output resistance of the given circuit. The output resistance of the given circuit is 39 ± 2% Ω. The output resistance is the Thevenin equivalent resistance seen at the output terminals, that is R out = 39 Ω. The output resistance of the given circuit is 39 Ω. Worksheet Difficulty: Easy Learning Objective: Understand how real operational amplifiers (op amps) function. 3/28
4 3. Award: points The open-loop gain of an op amp is Calculate the output voltage when there are inputs of +10 μv on the inverting terminal and +20 μv on the noninverting terminal. The output voltage is 750 ± 2% mv. The output voltage is calculated as follows: v o = Av d = A(v 2 v 1 ) = (20 μv 10 μv) = 750 mv The output voltage is 750 mv. Worksheet Difficulty: Medium Learning Objective: Understand how real operational amplifiers (op amps) function. 4/28
5 4. Award: points The output voltage of an op amp is -1 V when the noninverting input is 1 mv. If the open-loop gain of the op amp is , what is the inverting input? The inverting input of the op amp is ± 2% mv. The inverting input of the op amp is calculated as follows: v 0 = Av d = A(v 2 v 1 ) v 2 v 1 = V = mv 1 mv v 1 = mv v 1 = 1 mv ( ) = mv The inverting input of the op amp is mv. Worksheet Difficulty: Medium Learning Objective: Understand how real operational amplifiers (op amps) function. 5/28
6 5. Award: points For the op amp circuit given below, the op amp has an open-loop gain of 90000, an input resistance of 14 kω, and an output resistance of 115 Ω. Find the voltage gain v 0 /v i using the nonideal model of the op amp. The voltage gain v 0 /v i of the op amp is ± 2%. The formula to find the voltage gain is derived as follows: v i + Av d + (R i + R 0 )I = 0 But v d = R i I v i + (R i + R o + R i A) I = 0 Av d R 0 I + v 0 = 0 The voltage gain is calculated as follows: 6/28
7 The voltage gain is Worksheet Difficulty: Medium Learning Objective: Understand how real operational amplifiers (op amps) function. 7/28
8 6. Award: points A 741 op amp shown in the circuit given below has an open-loop voltage gain of 80000, an input resistance of 2 MΩ, and an output resistance of 110 Ω. Calculate the output voltage v 0 in the op amp circuit. The output voltage of the op amp is ± 2% mv. The formula to find the output voltage is derived as follows: (R 0 + R i )I + v i + Av d = 0 But v d = R i I v i + (R o + R i + R i A)I = 0 (1) Av d R 0 I + v o = 0 v o = Av d + R o I = (R o + R i A)I Substituting for I in equation(1), Then, the output voltage is calculated as follows: 8/28
9 v o = mv The output voltage is mv. Worksheet Difficulty: Medium Learning Objective: Understand how real operational amplifiers (op amps) function. The op amp in the circuit given below has R i = 100 kω, R 0 = 100 Ω, v S = 1 mv, and A = 100,000. Section Break Difficulty: Medium Learning Objective: Understand how real operational amplifiers (op amps) function. 9/28
10 7. Award: points Calculate the output voltage v o for the given op amp circuit. The output voltage v o for the given op amp circuit is ± 2% mv. At node V 1, which leads to At node V o, But, V d = V 1 and A = 100,000 so This gives us If V s = 1 mv, then V o = mv The output voltage v o for the given op amp circuit is mv. 10/28
11 Worksheet Difficulty: Medium Learning Objective: Understand how real operational amplifiers (op amps) function. 8. Award: points Calculate the differential voltage v d. The differential voltage v d is 9.90 ± 2% nv. The differential voltage is calculated as follows: v 0 = Av d = 100,000 v d Then,. The differential voltage v d is nv. Worksheet Difficulty: Medium Learning Objective: Understand how real operational amplifiers (op amps) function. 11/28
12 9. Award: points Calculate the output voltage v o for the given op amp circuit. The output voltage v o for the given op amp circuit is ± 2% mv. At node V 1, which leads to At node V o, But, V d = V 1 and A = 100,000 so This gives us If V s = 1 mv, then V o = mv The output voltage v o for the given op amp circuit is mv. 12/28
13 Worksheet Difficulty: Medium Learning Objective: Understand how real operational amplifiers (op amps) function. 10. Award: points Calculate the differential voltage v d. The differential voltage v d is 9.90 ± 2% nv. The differential voltage is calculated as follows: v 0 = Av d = 100,000 v d Then,. The differential voltage v d is nv. Worksheet Difficulty: Medium Learning Objective: Understand how real operational amplifiers (op amps) function. 13/28
14 11. Award: points Calculate the output voltage v o for the op amp circuit given below, where I = 1 ma and R = 3 kω. (Assume ideal op amp) The output voltage v o for the given op amp circuit is -3.0 ± 2% V. If v a and v b are the voltages at the inverting terminal and noninverting terminals of the op amp, v a = v b = 0 v 0 = V The output voltage v o for the given op amp circuit is V. Worksheet Difficulty: Easy Learning Objective: Understand that ideal op amps function nearly identical to real ones and that they can be used to effectively model them in a variety of circuit applications. 14/28
15 12. Award: points Calculate the output voltage of the op amp circuit given below, where v 1 = 2.3 V and v 2 = 1.5 V. The output voltage of the op amp circuit is -0.8 ± 2% V. The output voltage is calculated as follows: Since v a = v b = 1.5 V and i a = 0, no current flows through the 10-kΩ resistance. Using the compensatory circuit concept, from the given figure we get, v a v o = 0. v o = v a 2.3 = 1.5 V 2.3 V = V The output voltage of the op amp circuit is V. Worksheet Difficulty: Easy Learning Objective: Understand that ideal op amps function nearly identical to real ones and that they can be used to effectively model them in a variety of circuit applications. 15/28
16 16/28
17 13. Award: points Find the output voltage v o for the op amp circuit given below, where V = 11 V. The output voltage v o for the given op amp circuit is 9 ± 2% V. Let v a and v b be respectively the voltages at the inverting and the noninverting terminals of the op amp. v a = v b = 11 V At the inverting terminal, v o = 9 V The output voltage v o for the given op amp circuit is 9 V. Worksheet Difficulty: Easy Learning Objective: Understand that ideal op amps function nearly identical to real ones and that they can be used to effectively model them in a variety of circuit applications. 17/28
18 14. Award: points Find the voltage gain v 0 /v s of the circuit given below, where R 1 = 17 kω and R 2 = 14 kω. The voltage gain v 0 /v s of the circuit is 2.21 ± 2%. Since no current enters the op amp, the voltage at the input of the op amp is v s. Hence, The gain v 0 /v s of the circuit is Worksheet Difficulty: Medium Learning Objective: Understand that ideal op amps function nearly identical to real ones and that they can be used to effectively model them in a variety of circuit applications. 18/28
19 15. Award: points Calculate the voltage ratio v 0 /v s for the op amp circuit given below, where R = 11 kω. Assume that the op amp is ideal. The voltage ratio v 0 /v s for the op amp circuit is ± 2%. Step 1: Label the unknown nodes in the op amp circuit. Next we write the node equations and then apply the constraint v a = v b. Finally, solve for v o in terms of v s. Step 2: Thus, and or v b = 0 = v a or or v 0 /v s = The voltage ratio v 0 /v s is /28
20 Worksheet Difficulty: Medium Learning Objective: Understand that ideal op amps function nearly identical to real ones and that they can be used to effectively model them in a variety of circuit applications. Consider the op amp circuit given below, where R 1 = 19 kω and v s = 1 V. Section Break Difficulty: Medium Learning Objective: Understand that ideal op amps function nearly identical to real ones and that they can be used to effectively model them in a variety of circuit applications. 20/28
21 16. Award: points Calculate the output voltage v 0 for the given circuit. The output voltage v o is 2.48 ± 2% V. By voltage division, But v a = v b v o = 2.48 V The output voltage v o is 2.48 V. Worksheet Difficulty: Medium Learning Objective: Understand that ideal op amps function nearly identical to real ones and that they can be used to effectively model them in a variety of circuit applications. 21/28
22 17. Award: points Calculate the output current in the circuit. The output current in the circuit is ± 2% A. The output current is calculated as follows: The output current in the circuit is A. Worksheet Difficulty: Medium Learning Objective: Understand that ideal op amps function nearly identical to real ones and that they can be used to effectively model them in a variety of circuit applications. 22/28
23 18. Award: points Determine the output voltage v o in the op amp circuit given below, where I = 7 ma. The output voltage v o is ± 2% V. The transformation of a current source to a voltage source is shown below, where v S = 35 V. At node 1, But v 2 = 0. Hence, 140 V 4v 1 = v 1 + 2v 1 2v o 140 V = 7v 1 2v o (1) At node 2,, v 2 = 0 or v 1 = 2v o (2) From (1) and (2), 140 = 14v o 2v o 23/28
24 v o = V The output voltage is V. Worksheet Difficulty: Medium Learning Objective: Understand that ideal op amps function nearly identical to real ones and that they can be used to effectively model them in a variety of circuit applications. 24/28
25 19. Award: points In the circuit given below, R 1 = 20 kω, R 2 = 66 kω, and R 3 = 2 MΩ. Calculate the gain switch is in position 1, position 2, and position 3. when the The gain at the position 1 is -4.0 ± 2%. The gain at the position 2 is ± 2%. The gain at the position 3 is -400 ± 2%. The gain is calculated as follows: Position 1: Position 2: Position 3: The gain at the position 1 is The gain at the position 2 is The gain at the position 3 is /28
26 Worksheet Difficulty: Medium Learning Objective: Understand how the basic inverting op amp is the workhorse of the op amp family. 26/28
27 20. Award: points In the circuit given below, find k in the voltage transfer function v 0 = kv s. From the figure, v 1 = v 2. Node 1 is the inverting input and node 2 is the non-inverting input. Applying KCL at node 1 gives (1) Applying KCL at node 2 gives Substituting (2) into (1) yields (2) Therefore, The expression for. 27/28
28 Hint #2 Multiple Choice Difficulty: Medium Learning Objective: Understand how the basic noninverting op amp works and how they can be analyzed in electrical circuit applications. 28/28
ECE2262 Electric Circuits. Chapter 4: Operational Amplifier (OP-AMP) Circuits
ECE2262 Electric Circuits Chapter 4: Operational Amplifier (OP-AMP) Circuits 1 4.1 Operational Amplifiers 2 4. Voltages and currents in electrical circuits may represent signals and circuits can perform
More informationE40M. Op Amps. M. Horowitz, J. Plummer, R. Howe 1
E40M Op Amps M. Horowitz, J. Plummer, R. Howe 1 Reading A&L: Chapter 15, pp. 863-866. Reader, Chapter 8 Noninverting Amp http://www.electronics-tutorials.ws/opamp/opamp_3.html Inverting Amp http://www.electronics-tutorials.ws/opamp/opamp_2.html
More informationOperational Amplifiers
Operational Amplifiers A Linear IC circuit Operational Amplifier (op-amp) An op-amp is a high-gain amplifier that has high input impedance and low output impedance. An ideal op-amp has infinite gain and
More informationDesigning Information Devices and Systems I Fall 2018 Lecture Notes Note Introduction: Op-amps in Negative Feedback
EECS 16A Designing Information Devices and Systems I Fall 2018 Lecture Notes Note 18 18.1 Introduction: Op-amps in Negative Feedback In the last note, we saw that can use an op-amp as a comparator. However,
More informationChapter 5. Department of Mechanical Engineering
Source Transformation By KVL: V s =ir s + v By KCL: i s =i + v/r p is=v s /R s R s =R p V s /R s =i + v/r s i s =i + v/r p Two circuits have the same terminal voltage and current Source Transformation
More informationMidterm Exam (closed book/notes) Tuesday, February 23, 2010
University of California, Berkeley Spring 2010 EE 42/100 Prof. A. Niknejad Midterm Exam (closed book/notes) Tuesday, February 23, 2010 Guidelines: Closed book. You may use a calculator. Do not unstaple
More informationEECE 2150 Circuits and Signals, Biomedical Applications Final Exam Section 3
EECE 2150 Circuits and Signals, Biomedical Applications Final Exam Section 3 Instructions: Closed book, closed notes; Computers and cell phones are not allowed You may use the equation sheet provided but
More informationProblem Set 4 Solutions
University of California, Berkeley Spring 212 EE 42/1 Prof. A. Niknejad Problem Set 4 Solutions Please note that these are merely suggested solutions. Many of these problems can be approached in different
More informationEE-201 Review Exam I. 1. The voltage Vx in the circuit below is: (1) 3V (2) 2V (3) -2V (4) 1V (5) -1V (6) None of above
EE-201, Review Probs Test 1 page-1 Spring 98 EE-201 Review Exam I Multiple Choice (5 points each, no partial credit.) 1. The voltage Vx in the circuit below is: (1) 3V (2) 2V (3) -2V (4) 1V (5) -1V (6)
More informationSeries & Parallel Resistors 3/17/2015 1
Series & Parallel Resistors 3/17/2015 1 Series Resistors & Voltage Division Consider the single-loop circuit as shown in figure. The two resistors are in series, since the same current i flows in both
More informationEE 321 Analog Electronics, Fall 2013 Homework #3 solution
EE 32 Analog Electronics, Fall 203 Homework #3 solution 2.47. (a) Use superposition to show that the output of the circuit in Fig. P2.47 is given by + [ Rf v N + R f v N2 +... + R ] f v Nn R N R N2 R [
More informationElectronics II. Final Examination
The University of Toledo f17fs_elct27.fm 1 Electronics II Final Examination Problems Points 1. 11 2. 14 3. 15 Total 40 Was the exam fair? yes no The University of Toledo f17fs_elct27.fm 2 Problem 1 11
More informationSystematic methods for labeling circuits and finding a solvable set of equations, Operational Amplifiers. Kevin D. Donohue, University of Kentucky 1
Systematic methods for labeling circuits and finding a solvable set of equations, Operational Amplifiers Kevin D. Donohue, University of Kentucky Simple circuits with single loops or node-pairs can result
More informationSolved Problems. Electric Circuits & Components. 1-1 Write the KVL equation for the circuit shown.
Solved Problems Electric Circuits & Components 1-1 Write the KVL equation for the circuit shown. 1-2 Write the KCL equation for the principal node shown. 1-2A In the DC circuit given in Fig. 1, find (i)
More informationFigure Circuit for Question 1. Figure Circuit for Question 2
Exercises 10.7 Exercises Multiple Choice 1. For the circuit of Figure 10.44 the time constant is A. 0.5 ms 71.43 µs 2, 000 s D. 0.2 ms 4 Ω 2 Ω 12 Ω 1 mh 12u 0 () t V Figure 10.44. Circuit for Question
More informationEECE 2510 Circuits and Signals, Biomedical Applications Final Exam Section 3. Name:
EECE 2510 Circuits and Signals, Biomedical Applications Final Exam Section 3 Instructions: Closed book, closed notes; Computers and cell phones are not allowed Scientific calculators are allowed Complete
More informationECE 212H1F Circuit Analysis October 20, :15-19: Reza Iravani 02 Reza Iravani 03 Ali Nabavi-Niaki. (Non-programmable Calculators Allowed)
Please Print Clearly Last Name: First Name: Student Number: Your Tutorial Section (CIRCLE ONE): 01 Thu 10:00 12:00 HA403 02 Thu 10:00 12:00 GB412 03 Thu 15:00 17:00 GB412 04 Thu 15:00 17:00 SF2202 05 Fri
More informationOne-Port Networks. One-Port. Network
TwoPort s Definitions Impedance Parameters dmittance Parameters Hybrid Parameters Transmission Parameters Cascaded TwoPort s Examples pplications OnePort s v i' 1 OnePort pair of terminals at which a signal
More informationChapter 5 Objectives
Chapter 5 Engr228 Circuit Analysis Dr Curtis Nelson Chapter 5 Objectives State and apply the property of linearity State and apply the property of superposition Investigate source transformations Define
More informationElectronics II. Midterm #2
The University of Toledo EECS:3400 Electronics I su4ms_elct7.fm Section Electronics II Midterm # Problems Points. 8. 7 3. 5 Total 0 Was the exam fair? yes no The University of Toledo su4ms_elct7.fm Problem
More informationE1.1 Analysis of Circuits ( ) Revision Lecture 1 1 / 13
RevisionLecture 1: E1.1 Analysis of Circuits (2014-4530) Revision Lecture 1 1 / 13 Format Question 1 (40%): eight short parts covering the whole syllabus. Questions 2 and 3: single topic questions (answer
More informationUNIT 4 DC EQUIVALENT CIRCUIT AND NETWORK THEOREMS
UNIT 4 DC EQUIVALENT CIRCUIT AND NETWORK THEOREMS 1.0 Kirchoff s Law Kirchoff s Current Law (KCL) states at any junction in an electric circuit the total current flowing towards that junction is equal
More informationLecture 5: Using electronics to make measurements
Lecture 5: Using electronics to make measurements As physicists, we re not really interested in electronics for its own sake We want to use it to measure something often, something too small to be directly
More informationSolution: Based on the slope of q(t): 20 A for 0 t 1 s dt = 0 for 3 t 4 s. 20 A for 4 t 5 s 0 for t 5 s 20 C. t (s) 20 C. i (A) Fig. P1.
Problem 1.24 The plot in Fig. P1.24 displays the cumulative charge q(t) that has entered a certain device up to time t. Sketch a plot of the corresponding current i(t). q 20 C 0 1 2 3 4 5 t (s) 20 C Figure
More informationPOLYTECHNIC UNIVERSITY Electrical Engineering Department. EE SOPHOMORE LABORATORY Experiment 2 DC circuits and network theorems
POLYTECHNIC UNIVERSITY Electrical Engineering Department EE SOPHOMORE LABORATORY Experiment 2 DC circuits and network theorems Modified for Physics 18, Brooklyn College I. Overview of Experiment In this
More informationE40M Review - Part 1
E40M Review Part 1 Topics in Part 1 (Today): KCL, KVL, Power Devices: V and I sources, R Nodal Analysis. Superposition Devices: Diodes, C, L Time Domain Diode, C, L Circuits Topics in Part 2 (Wed): MOSFETs,
More informationMAE140 Linear Circuits Fall 2016 Final, December 6th Instructions
MAE40 Linear Circuits Fall 206 Final, December 6th Instructions. This exam is open book. You may use whatever written materials you choose, including your class notes and textbook. You may use a handheld
More informationor Op Amps for short
or Op Amps for short Objective of Lecture Describe how an ideal operational amplifier (op amp) behaves. Define voltage gain, current gain, transresistance gain, and transconductance gain. Explain the operation
More informationHomework Assignment 08
Homework Assignment 08 Question 1 (Short Takes) Two points each unless otherwise indicated. 1. Give one phrase/sentence that describes the primary advantage of an active load. Answer: Large effective resistance
More informationMAE140 - Linear Circuits - Winter 09 Midterm, February 5
Instructions MAE40 - Linear ircuits - Winter 09 Midterm, February 5 (i) This exam is open book. You may use whatever written materials you choose, including your class notes and textbook. You may use a
More informationVer 6186 E1.1 Analysis of Circuits (2015) E1.1 Circuit Analysis. Problem Sheet 2 - Solutions
Ver 8 E. Analysis of Circuits (0) E. Circuit Analysis Problem Sheet - Solutions Note: In many of the solutions below I have written the voltage at node X as the variable X instead of V X in order to save
More informationMAE140 - Linear Circuits - Fall 14 Midterm, November 6
MAE140 - Linear Circuits - Fall 14 Midterm, November 6 Instructions (i) This exam is open book. You may use whatever written materials you choose, including your class notes and textbook. You may use a
More informationELECTRONIC SYSTEMS. Basic operational amplifier circuits. Electronic Systems - C3 13/05/ DDC Storey 1
Electronic Systems C3 3/05/2009 Politecnico di Torino ICT school Lesson C3 ELECTONIC SYSTEMS C OPEATIONAL AMPLIFIES C.3 Op Amp circuits» Application examples» Analysis of amplifier circuits» Single and
More informationHomework 3 Solution. Due Friday (5pm), Feb. 14, 2013
University of California, Berkeley Spring 2013 EE 42/100 Prof. K. Pister Homework 3 Solution Due Friday (5pm), Feb. 14, 2013 Please turn the homework in to the drop box located next to 125 Cory Hall (labeled
More informationPage 1 of 15 Page 2 of 15 Ohm s Law Basic Electricity Worksheet Topics Question 1 For a given amount of water pressure, which will flow a greater rate of water: a small (restrictive) nozzle or a large
More informationModule 2. DC Circuit. Version 2 EE IIT, Kharagpur
Module 2 DC Circuit Lesson 5 Node-voltage analysis of resistive circuit in the context of dc voltages and currents Objectives To provide a powerful but simple circuit analysis tool based on Kirchhoff s
More informationOperational amplifiers (Op amps)
Operational amplifiers (Op amps) v R o R i v i Av i v View it as an ideal amp. Take the properties to the extreme: R i, R o 0, A.?!?!?!?! v v i Av i v A Consequences: No voltage dividers at input or output.
More informationNotes for course EE1.1 Circuit Analysis TOPIC 10 2-PORT CIRCUITS
Objectives: Introduction Notes for course EE1.1 Circuit Analysis 4-5 Re-examination of 1-port sub-circuits Admittance parameters for -port circuits TOPIC 1 -PORT CIRCUITS Gain and port impedance from -port
More informationChapter 10 Sinusoidal Steady State Analysis Chapter Objectives:
Chapter 10 Sinusoidal Steady State Analysis Chapter Objectives: Apply previously learn circuit techniques to sinusoidal steady-state analysis. Learn how to apply nodal and mesh analysis in the frequency
More informationD is the voltage difference = (V + - V - ).
1 Operational amplifier is one of the most common electronic building blocks used by engineers. It has two input terminals: V + and V -, and one output terminal Y. It provides a gain A, which is usually
More informationFundamentals of Electric Circuits, Second Edition - Alexander/Sadiku
Chapter 3, Problem 9(8). Find V x in the network shown in Fig. 3.78. Figure 3.78 Chapter 3, Solution 9(8). Consider the circuit below. 2 Ω 2 Ω -j 8 30 o I j 4 j 4 I 2 -j2v For loop, 8 30 = (2 j4)i ji 2
More informationDesigning Information Devices and Systems II Fall 2016 Murat Arcak and Michel Maharbiz Homework 0. This homework is due August 29th, 2016, at Noon.
EECS 16B Designing Information Devices and Systems II Fall 2016 Murat Arcak and Michel Maharbiz Homework 0 This homework is due August 29th, 2016, at Noon. 1. Homework process and study group (a) Who else
More informationFinal Exam. 55:041 Electronic Circuits. The University of Iowa. Fall 2013.
Final Exam Name: Max: 130 Points Question 1 In the circuit shown, the op-amp is ideal, except for an input bias current I b = 1 na. Further, R F = 10K, R 1 = 100 Ω and C = 1 μf. The switch is opened at
More informationDesigning Information Devices and Systems I Spring 2019 Midterm 2
1 EECS 16A Designing Information Devices and Systems I Spring 2019 Midterm 2 1. How is your semester so far? (1 point) 2. Do you have any summer plans? (1 point) Do not turn this page until the proctor
More informationECE2262 Electric Circuits
ECE2262 Electric Circuits Equivalence Chapter 5: Circuit Theorems Linearity Superposition Thevenin s and Norton s Theorems Maximum Power Transfer Analysis of Circuits Using Circuit Theorems 1 5. 1 Equivalence
More informationElectric Circuits II Sinusoidal Steady State Analysis. Dr. Firas Obeidat
Electric Circuits II Sinusoidal Steady State Analysis Dr. Firas Obeidat 1 Table of Contents 1 2 3 4 5 Nodal Analysis Mesh Analysis Superposition Theorem Source Transformation Thevenin and Norton Equivalent
More informationChapter 10 AC Analysis Using Phasors
Chapter 10 AC Analysis Using Phasors 10.1 Introduction We would like to use our linear circuit theorems (Nodal analysis, Mesh analysis, Thevenin and Norton equivalent circuits, Superposition, etc.) to
More informationDesigning Information Devices and Systems I Spring 2018 Lecture Notes Note 20
EECS 16A Designing Information Devices and Systems I Spring 2018 Lecture Notes Note 20 Design Example Continued Continuing our analysis for countdown timer circuit. We know for a capacitor C: I = C dv
More informationENGG 1203 Tutorial. Solution. Op Amps 7 Mar Learning Objectives. Determine V o in the following circuit. Assume that the op-amp is ideal.
ENGG 03 Tutorial Q Op Amps 7 Mar Learning Objectives Analyze circuits with ideal operational amplifiers News HW Mid term Revision tutorial ( Mar :30-6:0, CBA) Ack.: MIT OCW 6.0 Determine V o in the following
More informationChapter 2. Engr228 Circuit Analysis. Dr Curtis Nelson
Chapter 2 Engr228 Circuit Analysis Dr Curtis Nelson Chapter 2 Objectives Understand symbols and behavior of the following circuit elements: Independent voltage and current sources; Dependent voltage and
More informationECE Analog Integrated Circuit Design - II P.E. Allen
Lecture 290 Feedback Analysis using Return Ratio (3/20/02) Page 2901 LECTURE 290 FEEDBACK CIRCUIT ANALYSIS USING RETURN RATIO (READING: GHLM 599613) Objective The objective of this presentation is: 1.)
More information55:041 Electronic Circuits The University of Iowa Fall Final Exam
Final Exam Name: Score Max: 135 Question 1 (1 point unless otherwise noted) a. What is the maximum theoretical efficiency for a class-b amplifier? Answer: 78% b. The abbreviation/term ESR is often encountered
More informationEIT Review. Electrical Circuits DC Circuits. Lecturer: Russ Tatro. Presented by Tau Beta Pi The Engineering Honor Society 10/3/2006 1
EIT Review Electrical Circuits DC Circuits Lecturer: Russ Tatro Presented by Tau Beta Pi The Engineering Honor Society 10/3/2006 1 Session Outline Basic Concepts Basic Laws Methods of Analysis Circuit
More informationKirchhoff's Laws and Circuit Analysis (EC 2)
Kirchhoff's Laws and Circuit Analysis (EC ) Circuit analysis: solving for I and V at each element Linear circuits: involve resistors, capacitors, inductors Initial analysis uses only resistors Power sources,
More informationElectronics II. Midterm #1
The University of Toledo EECS:3400 Electronics I su3ms_elct7.fm Section Electronics II Midterm # Problems Points. 5. 6 3. 9 Total 0 Was the exam fair? yes no The University of Toledo su3ms_elct7.fm Problem
More informationENGG 1203 Tutorial. Op Amps 10 Oct Learning Objectives. News. Ack.: MIT OCW Analyze circuits with ideal operational amplifiers
ENGG 1203 Tutorial Op Amps 10 Oct Learning Objectives Analyze circuits with ideal operational amplifiers News Mid term Revision tutorial Ack.: MIT OCW 6.01 1 Q1 This circuit is controlled by the charge
More informationNotes on Electricity (Circuits)
A circuit is defined to be a collection of energy-givers (batteries) and energy-takers (resistors, light bulbs, radios, etc.) that form a closed path (or complete path) through which electrical current
More informationKirchhoff's Laws and Maximum Power Transfer
German Jordanian University (GJU) Electrical Circuits Laboratory Section Experiment Kirchhoff's Laws and Maximum Power Transfer Post lab Report Mahmood Hisham Shubbak / / 8 Objectives: To learn KVL and
More informationChapter 5 Solution P5.2-2, 3, 6 P5.3-3, 5, 8, 15 P5.4-3, 6, 8, 16 P5.5-2, 4, 6, 11 P5.6-2, 4, 9
Chapter 5 Solution P5.2-2, 3, 6 P5.3-3, 5, 8, 15 P5.4-3, 6, 8, 16 P5.5-2, 4, 6, 11 P5.6-2, 4, 9 P 5.2-2 Consider the circuit of Figure P 5.2-2. Find i a by simplifying the circuit (using source transformations)
More informationSimultaneous equations for circuit analysis
Simultaneous equations for circuit analysis This worksheet and all related files are licensed under the Creative Commons Attribution License, version 1.0. To view a copy of this license, visit http://creativecommons.org/licenses/by/1.0/,
More informationEIT Quick-Review Electrical Prof. Frank Merat
CIRCUITS 4 The power supplied by the 0 volt source is (a) 2 watts (b) 0 watts (c) 2 watts (d) 6 watts (e) 6 watts 4Ω 2Ω 0V i i 2 2Ω 20V Call the clockwise loop currents i and i 2 as shown in the drawing
More informationOperational amplifiers (Op amps)
Operational amplifiers (Op amps) Recall the basic two-port model for an amplifier. It has three components: input resistance, Ri, output resistance, Ro, and the voltage gain, A. v R o R i v d Av d v Also
More informationA two-port network is an electrical network with two separate ports
5.1 Introduction A two-port network is an electrical network with two separate ports for input and output. Fig(a) Single Port Network Fig(b) Two Port Network There are several reasons why we should study
More informationECE2262 Electric Circuits. Chapter 5: Circuit Theorems
ECE2262 Electric Circuits Chapter 5: Circuit Theorems 1 Equivalence Linearity Superposition Thevenin s and Norton s Theorems Maximum Power Transfer Analysis of Circuits Using Circuit Theorems 2 5. 1 Equivalence
More informationU1 is zero based because its noninverting terminal is connected to circuit common. Therefore, the circuit reference voltage is 0 V.
When you have completed this exercise, you will be able to operate a zener-clamped op amp comparator circuit using dc and ac voltages. You will verify your results with an oscilloscope. U1 is zero based
More informationNotes for course EE1.1 Circuit Analysis TOPIC 3 CIRCUIT ANALYSIS USING SUB-CIRCUITS
Notes for course EE1.1 Circuit Analysis 2004-05 TOPIC 3 CIRCUIT ANALYSIS USING SUB-CIRCUITS OBJECTIVES 1) To introduce the Source Transformation 2) To consider the concepts of Linearity and Superposition
More informationEE105 Fall 2014 Microelectronic Devices and Circuits
EE05 Fall 204 Microelectronic Devices and Circuits Prof. Ming C. Wu wu@eecs.berkeley.edu 5 Sutardja Dai Hall (SDH) Terminal Gain and I/O Resistances of BJT Amplifiers Emitter (CE) Collector (CC) Base (CB)
More informationEE 230 Lecture 21. Nonlinear Op Amp Applications. Nonlinear analysis methods Comparators with Hysteresis
EE 230 Lecture 2 Nonlinear Op Amp Applications Nonlinear analysis methods Comparators with Hysteresis Quiz 5 Plot the transfer charactristics of the following circuit. Assume the op amp has =2 and SATL
More informationECE 201 Fall 2009 Final Exam
ECE 01 Fall 009 Final Exam December 16, 009 Division 0101: Tan (11:30am) Division 001: Clark (7:30 am) Division 0301: Elliott (1:30 pm) Instructions 1. DO NOT START UNTIL TOLD TO DO SO.. Write your Name,
More informationProblem Set 5 Solutions
University of California, Berkeley Spring 01 EE /0 Prof. A. Niknejad Problem Set 5 Solutions Please note that these are merely suggested solutions. Many of these problems can be approached in different
More informationECE Circuit Theory. Final Examination. December 5, 2008
ECE 212 H1F Pg 1 of 12 ECE 212 - Circuit Theory Final Examination December 5, 2008 1. Policy: closed book, calculators allowed. Show all work. 2. Work in the provided space. 3. The exam has 3 problems
More informationECE-343 Test 2: Mar 21, :00-8:00, Closed Book. Name : SOLUTION
ECE-343 Test 2: Mar 21, 2012 6:00-8:00, Closed Book Name : SOLUTION 1. (25 pts) (a) Draw a circuit diagram for a differential amplifier designed under the following constraints: Use only BJTs. (You may
More informationECE 220 Laboratory 4 Volt Meter, Comparators, and Timer
ECE 220 Laboratory 4 Volt Meter, Comparators, and Timer Michael W. Marcellin Please follow all rules, procedures and report requirements as described at the beginning of the document entitled ECE 220 Laboratory
More informationECE 212H1F Circuit Analysis October 30, :10-19: Reza Iravani 02 Reza Iravani 03 Piero Triverio. (Non-programmable Calculators Allowed)
Please Print Clearly Last Name: First Name: Student Number: Your Tutorial Section (CIRCLE ONE): 01 Thu. 9-11 RS211 02 Thu. 9-11 GB119 03 Tue. 10-12 SF2202 04 Tue. 10-12 SF3201 05 Tue. 13-15 GB304 06 Tue.
More informationEE100Su08 Lecture #9 (July 16 th 2008)
EE100Su08 Lecture #9 (July 16 th 2008) Outline HW #1s and Midterm #1 returned today Midterm #1 notes HW #1 and Midterm #1 regrade deadline: Wednesday, July 23 rd 2008, 5:00 pm PST. Procedure: HW #1: Bart
More informationElectric Circuits Fall 2015 Solution #5
RULES: Please try to work on your own. Discussion is permissible, but identical submissions are unacceptable! Please show all intermeate steps: a correct solution without an explanation will get zero cret.
More informationCURRENT SOURCES EXAMPLE 1 Find the source voltage Vs and the current I1 for the circuit shown below SOURCE CONVERSIONS
CURRENT SOURCES EXAMPLE 1 Find the source voltage Vs and the current I1 for the circuit shown below EXAMPLE 2 Find the source voltage Vs and the current I1 for the circuit shown below SOURCE CONVERSIONS
More informationOperational Amplifier (Op-Amp) Operational Amplifiers. OP-Amp: Components. Internal Design of LM741
(Op-Amp) s Prof. Dr. M. Zahurul Haq zahurul@me.buet.ac.bd http://teacher.buet.ac.bd/zahurul/ Department of Mechanical Engineering Bangladesh University of Engineering & Technology ME 475: Mechatronics
More informationDC CIRCUIT ANALYSIS. Loop Equations
All of the rules governing DC circuits that have been discussed so far can now be applied to analyze complex DC circuits. To apply these rules effectively, loop equations, node equations, and equivalent
More informationDesign Engineering MEng EXAMINATIONS 2016
IMPERIAL COLLEGE LONDON Design Engineering MEng EXAMINATIONS 2016 For Internal Students of the Imperial College of Science, Technology and Medicine This paper is also taken for the relevant examination
More informationINTRODUCTION TO ELECTRONICS
INTRODUCTION TO ELECTRONICS Basic Quantities Voltage (symbol V) is the measure of electrical potential difference. It is measured in units of Volts, abbreviated V. The example below shows several ways
More informationENGG 1203 Tutorial_9 - Review. Boolean Algebra. Simplifying Logic Circuits. Combinational Logic. 1. Combinational & Sequential Logic
ENGG 1203 Tutorial_9 - Review Boolean Algebra 1. Combinational & Sequential Logic 2. Computer Systems 3. Electronic Circuits 4. Signals, Systems, and Control Remark : Multiple Choice Questions : ** Check
More informationHomework Assignment 11
Homework Assignment Question State and then explain in 2 3 sentences, the advantage of switched capacitor filters compared to continuous-time active filters. (3 points) Continuous time filters use resistors
More informationDelhi Noida Bhopal Hyderabad Jaipur Lucknow Indore Pune Bhubaneswar Kolkata Patna Web: Ph:
Serial : ND_EE_NW_Analog Electronics_05088 Delhi Noida Bhopal Hyderabad Jaipur Lucknow ndore Pune Bhubaneswar Kolkata Patna Web: E-mail: info@madeeasy.in Ph: 0-4546 CLASS TEST 08-9 ELECTCAL ENGNEENG Subject
More informationVer 3537 E1.1 Analysis of Circuits (2014) E1.1 Circuit Analysis. Problem Sheet 1 (Lectures 1 & 2)
Ver 3537 E. Analysis of Circuits () Key: [A]= easy... [E]=hard E. Circuit Analysis Problem Sheet (Lectures & ). [A] One of the following circuits is a series circuit and the other is a parallel circuit.
More informationTwo-Port Networks Admittance Parameters CHAPTER16 THE LEARNING GOALS FOR THIS CHAPTER ARE THAT STUDENTS SHOULD BE ABLE TO:
CHAPTER16 Two-Port Networks THE LEARNING GOALS FOR THIS CHAPTER ARE THAT STUDENTS SHOULD BE ABLE TO: Calculate the admittance, impedance, hybrid, and transmission parameter for two-port networks. Convert
More informationThe Common-Emitter Amplifier
c Copyright 2009. W. Marshall Leach, Jr., Professor, Georgia Institute of Technology, School of Electrical and Computer Engineering. The Common-Emitter Amplifier Basic Circuit Fig. shows the circuit diagram
More informationIn this lecture, we will consider how to analyse an electrical circuit by applying KVL and KCL. As a result, we can predict the voltages and currents
In this lecture, we will consider how to analyse an electrical circuit by applying KVL and KCL. As a result, we can predict the voltages and currents around an electrical circuit. This is a short lecture,
More information4/27 Friday. I have all the old homework if you need to collect them.
4/27 Friday Last HW: do not need to turn it. Solution will be posted on the web. I have all the old homework if you need to collect them. Final exam: 7-9pm, Monday, 4/30 at Lambert Fieldhouse F101 Calculator
More informationModule 2. DC Circuit. Version 2 EE IIT, Kharagpur
Module DC Circuit Lesson 4 Loop Analysis of resistive circuit in the context of dc voltages and currents Objectives Meaning of circuit analysis; distinguish between the terms mesh and loop. To provide
More informationEE292: Fundamentals of ECE
EE292: Fundamentals of ECE Fall 2012 TTh 10:00-11:15 SEB 1242 Lecture 4 120906 http://www.ee.unlv.edu/~b1morris/ee292/ 2 Outline Review Voltage Divider Current Divider Node-Voltage Analysis 3 Network Analysis
More informationmywbut.com Mesh Analysis
Mesh Analysis 1 Objectives Meaning of circuit analysis; distinguish between the terms mesh and loop. To provide more general and powerful circuit analysis tool based on Kirchhoff s voltage law (KVL) only.
More informationChapter 4 Circuit Theorems
Chapter 4 Circuit Theorems 1. Linearity and Proportionality. Source Transformation 3. Superposition Theorem 4. Thevenin s Theorem and Norton s Theorem 5. Maximum Power Transfer Theorem Mazita Sem 1 111
More informationAlgebraic equation manipulation for electric circuits
Algebraic equation manipulation for electric circuits This worksheet and all related files are licensed under the Creative Commons Attribution License, version.0. To view a copy of this license, visit
More informationSinusoidal Steady State Analysis (AC Analysis) Part II
Sinusoidal Steady State Analysis (AC Analysis) Part II Amin Electronics and Electrical Communications Engineering Department (EECE) Cairo University elc.n102.eng@gmail.com http://scholar.cu.edu.eg/refky/
More informationDesigning Information Devices and Systems I Fall 2017 Midterm 2. Exam Location: 150 Wheeler, Last Name: Nguyen - ZZZ
EECS 16A Designing Information Devices and Systems I Fall 2017 Midterm 2 Exam Location: 150 Wheeler, Last Name: Nguyen - ZZZ PINT your student ID: PINT AND SIGN your name:, (last name) (first name) (signature)
More informationES250: Electrical Science. HW1: Electric Circuit Variables, Elements and Kirchhoff s Laws
ES250: Electrical Science HW1: Electric Circuit Variables, Elements and Kirchhoff s Laws Introduction Engineers use electric circuits to solve problems that are important to modern society, such as: 1.
More informationECE 523/421 - Analog Electronics University of New Mexico Solutions Homework 3
ECE 523/42 - Analog Electronics University of New Mexico Solutions Homework 3 Problem 7.90 Show that when ro is taken into account, the voltage gain of the source follower becomes G v v o v sig R L r o
More informationELEC 250: LINEAR CIRCUITS I COURSE OVERHEADS. These overheads are adapted from the Elec 250 Course Pack developed by Dr. Fayez Guibaly.
Elec 250: Linear Circuits I 5/4/08 ELEC 250: LINEAR CIRCUITS I COURSE OVERHEADS These overheads are adapted from the Elec 250 Course Pack developed by Dr. Fayez Guibaly. S.W. Neville Elec 250: Linear Circuits
More informationMassachusetts Institute of Technology Department of Electrical Engineering and Computer Science : Circuits & Electronics Problem Set #1 Solution
Massachusetts Institute of Technology Department of Electrical Engineering and Computer Science 6.2: Circuits & Electronics Problem Set # Solution Exercise. The three resistors form a series connection.
More information