Strength and Stiffness of Engineering Systems

Size: px
Start display at page:

Download "Strength and Stiffness of Engineering Systems"

Transcription

1 Numerical SOLUTIONS to Odd-Numbered roblems* of Chapters 1 10 of: Strength and Stiffness of Engineering Systems by: Frederick A. Leckie Dominic J. Dal Bello Solutions Version: Solutions by: D. J. Dal Bello domdalbello@yahoo.com *Note: Chapters 3 and 8 include several multi-part problems both odd- and even-numbered for which each part repeats the question of art (a), but with different numerical values. For such problems (including even-numbered problems), the numerical solutions are given for arts (a), (c), (e), etc. The problems are: 3.20, 8.1, 8.3, 8.4, and 8.20.

2 .2 Copyright 2009 by Dominic J. Dal Bello Santa Barbara, California All rights reserved. No part of this booklet (numerical solutions) may be reproduced in any form, printed, electronic or otherwise, without the written permission of the author (Dominic J. Dal Bello). These numerical solutions may not be distributed commercially or otherwise sold as a product, or as part of a larger work. However, students, instructors and others using the text, Strength and Stiffness of Engineering Systems (Leckie and Dal Bello, Springer, 2009), for academic and learning purposes may print a copy of these numerical solutions for use in learning the material.

3 .3 Chapter Ultimate, roof, Working kips 1.5 W min = 4710 lb, 3-ton (6000-lb) crane ; 64% lb; 12.8 kips, 11.2 kips, 3200 lb; 18.4 kips; 38.4 kips 1.11 two 8 kn loads, R Ax, R Ay, R By Chapter CD =2.5kips; BC =1.5kips; EF = 3.0 kips; BE =2.50kips 2.3 T 2 :T 1 =2: lb; 2400 lb-ft 2.7 M max = 41.4 kn m for a =4m or 6m lb; 180 lb/ft, 90 lb/ft; 3240 lb-ft 2.11 AB = 3.23 kips; T = kipin. CCW; N = kips up Chapter %, 31.3 ksi; in 2 ; ksi 3.5 lot; S p ~ 225 Ma; E = 200 Ga; S y = 255 Ma; S u = 450 Ma Ma; 1.88; mm; mm in.; in kn m/m 3 ; N m ,000 cycles; 40%; 40.8 kn Ma; 131 Ma ksi kn; 94.3 kn, 3.62 kn m, kn m 3.20 Strain ( 10 3 ) art x y z xy (a) (c) (e) (g) Strain ( 10 6 ) art x y z (a) (b) (c) Chapter Ma; ; 686 m Ma, 40.7 Ma; 1.16 mm, mm = 582 m ksi, 3.00 ksi; in., in.; in. down, in. down psi; in kips left; 8.57 kips left; in. right 4.11 FL 2AE ; plot; FL 3AE ; 34.1 m x Ma, x in meters m right, 582 m up Ma, 56.6 Ma; 4.2; mm, mm; mm right, 0 mm Ma, 80 Ma; 3.0; mm, 2.29 mm; 4.58 mm right 4.21 AB =56.6Ma, BC = 56.6 Ma, BD = 0 Ma; 4.2; AB = mm; BC = mm; BD = 0 mm; mm right 4.23 s = 4.80 ksi; c = ksi; in.; 8330 ksi in 2 ; in Ma ksi, 8.57 ksi; 317 F Ma (matrix), 727 Ma Ma; 5.00 Ma; mm minimum; 18.3 mm lb; ; Ma; 62.8 kn/m kips ave ; 2.67a (n =2.67 radii) N m, 22.9 N m; 8.75 mm down; 2.29 MN/m N m, 22.6 N m; 3.06 mm right; 6.53 MN/m FL AE down; EA 3L ; m = 9K E L ; minimize E or maximize E

4 U AB = U BC = 3EAv 2 16L, U BD = EAv 2 2 3L ; in.; 1195 kips/in N m; mm down lb-in.; in. down 4.57 AD = kn, BD = kn, CD = 28.0 kn; kn right, kn down; kn Chapter in 4 ; 3.98 ksi; 5.0; m 4 ; m 4 ; 1.2% mm; mm, 45.8 mm; 62.0 mm, 6.20 mm; 6.0%, 63.2% savings ksi; ksi, ksi; kip-in.; 2.74 in., 3.0 in.; 63% savings N m; ksi; 1.12 (approx.) in kn m; 73.0 Ma; 3.34 ; 128 mm N m; 32.3 mm; 41.9 mm; 41.9 mm Chapter (a) 0 < x <4 m: V(x) = 6.0 kn, M(x) =6x kn m; 4< x <10 m: V(x) =+4.0 kn; M(x) = 4x+40 kn m; (b) V max =6kN; M max =24kN m at x =4m in.; 2.18% 6.5 S12 31, W14 26; W kip-in.; 6.00 ksi; in Ma ksi at x =21ft psi Ma; w o M = L x ; 29.4 ksi 6L mm Ma; 2.47 mm difference 6.23 v = x ; beam hits structure 6EI 3Lx L=a+b; answers will vary based on length variables (a, b, L) used v 1 v 2 If a < b: 6.31 R A = 3wL 8, R B = 5wL 8, M B = wl 2 8 CW ; w 2x ; 48EI 4 3Lx 3 + L 3 x 6.33 R A = R B = wl 2 up, 6.35 v 1 v 2 bx = L 6EIL 2 b 2 x 2 ; 0 x a = ax 6EIL 3 3aLx 2 + 3a 2 L bl 2 + b 3 x a 3 L ; b L 2 b 2 3/ 2 max = at x = 9 3EIL v 1 v 2 M A = wl 2 12 CCW, M B = wl 2 12 CW ; kn; 59.2 Ma ka; 533 ka; 416 ka a x a+ b = L = x 6EI 3 3Lx 2 ; 0 x L L = x 2L ; L x 3L 2 6EI L b 2 3 = x 6EI 3 3aa + s x ; 0 x a = ax 6EI 2 3a 2a+ s x + a 3 ; a x a+ s v = vl 2 = wl 4 192EI max = wl 4 384EI = 12 Ma at m = 0.3 Ma at m max = 2.00 mm down

5 Ma; 2.39 Ma in in 3 ; 21.3 in 3 ; 6.28 in AD/ mm; S ; 68.6% or 69.4 lb/ft savings lb, deflection 6.55 Silicon Carbide (SiC), but it is brittle; Wood is next best 6.57 m wl = -- 1/ 2 L ; 96 E st = 64.7 ; al = 22.2 Chapter Ma; 2.60 Ma 7.3 at A: = psi; B: = 28.6 psi 7.5 at A: y = 5728 psi; B: y = 5731 psi; C: y = 1.6 Ma, xy = 32. psi Note: a = 1.6 psi (at A, B, C); b = psi (+ at A, atb) 7.7 at A: Ma; B: 1.33 Ma; C: 9.33 Ma; D: 1.33 Ma Ma; 1.90 Ma 7.11 R/ d/(3L 2 ) 7.15 b =82.8Ma (+atb); T =6.90Ma (+ata, B; at C); V =0.28Ma ( ata, C) 7.17 a = /A =67.9psi ( ata, B, C); b,x = FeD/(2I) = 1207 psi (+ at B); b,y = hd/(2i) = 2897 psi (+ at A, atc); T = FhD/(2J) =966psi(+atA, B; atc); V =4F/(3A) = 60.4 psi ( at A, C) 7.19 v wx L3 ; 24EI 1 2L 1 x 2 x 3 wl 2 x = AE max = in. down at x =121.25in. wx 7.21 v = x, 48EI 3 + 3Lx 2 L 3 w v = x ; 48EI 3 + 9Lx 2 L 3 3wL 5wL A y = R = , B ; 8 y = wl M 2 B = CW 8 Chapter (a) Ma, Ma, 32.1 Ma (c) Ma, 55.7 Ma, 3.3 Ma (e) Ma, 76.5 Ma, Ma (g) Ma, 57.7 Ma, 19.6 Ma (i) Ma, Ma, 89.7 Ma 8.3 (a) 17.1 ksi@ 19.3, 2.1 ksi@70.7 (c) 16.4 ksi@12.8, 11.4 ksi@102.8 (e) 19.0 ksi@ 33.7, 6.0 ksi@56.3 (g) 11.7 ksi@ 15.5, 11.7 ksi@ (a) 9.6 ksi@115.7, 9.6 ksi@25.7, 7.5 ksi (c) 13.9 ksi@ 32.3, 13.9 ksi@57.8, 2.5 ksi (e) 6.5 ksi@101.3, 6.5 ksi@11.3, 12.5 ksi (g) 11.7 ksi@119.5, 11.7 ksi@29.5, 0ksi Ma, 26.0 Ma; 30.0 Ma 8.7 = 2.60 Ma, = Ma; I, II = Ma, 90.4 Ma; max = Ma Ma; 0Ma; 0Ma, 42.8Ma t. B; 1.14 t. B (a) 7.7 ksi, 7.70 ksi, ksi (b) 15.4 ksi, 15.4 ksi, 4.74 ksi (c) 15.0 ksi, 15.8 ksi, 0 ksi (d) 16.8 ksi, 17.8 ksi, 0 ksi (normal stresses along y-axis, at points not on x- or z- axes) (e) 3.85 ksi, 8.61 ksi, 7.9 ksi, 8.88 ksi, corresponding to (a)-(d) 8.13 (a) ksi, ksi, 1.61 ksi (c) 3.55 ksi, 1.45 ksi, ksi

6 .6 (e) Ma, 59.0 Ma, 17.8 Ma (g) 70.9 Ma, 30.9 Ma, 94.9 Ma 8.14 Note: s defines plane where max >0. (a) 15 ksi@0, 10 ksi@90 ; max = 2.5 ksi, ave = 12.5 ksi, s = 45 (c) 16.4 ksi@12.8, 11.4 ksi@102.8 ; max =13.9ksi, ave = 2.5 ksi, s = 32.2 (e) Ma@31.7, 55.3 Ma@121.7 ; max =44.7Ma, ave =100Ma, s = 13.3 (g) Ma@ 10.9, 87.7 Ma@79.1 ; max = Ma, ave =20Ma, s = (a) , , (c) , , (a) ; , 7.08 Ma Ga, (a) , , x = A, y = --, 3 A + 2 B + 2 C 2 xy = B C (a) 5.0 ksi; 7.5 ksi; I-III (out-of-plane) (c) 2.5 ksi; 3.5 ksi; I-III (out-of-plane) Chapter Tresca or von Mises; Maximum Normal Stress 9.3 I = 3.1 ksi, does not fail Try: T =120lb and M =160lb-ft ( I = 14.4 ksi) U D = E I II + III 2 I II + II III + III I 1 U D = E I + II III I II + II III + III I I II 2 + II III 2 + III I 2 o = Chapter in. = 11.7 ft kn, AE and CD in. = 8.84 ft 10.7 (a) 708 kips (y-axis buckling); 760 kips (z-axis buckling); buckling about weak-axis; (b) 1390 kips (y-axis buckling); 760 kips (z-axis buckling); buckling about strong-axis K T ; plot Lsin + ecos m m = ; 2 cr -- L E R 2 1st: Ceramic, 2nd: Composite 12 /

Tutorial #1 - CivE. 205 Name: I.D:

Tutorial #1 - CivE. 205 Name: I.D: Tutorial # - CivE. 0 Name: I.D: Eercise : For the Beam below: - Calculate the reactions at the supports and check the equilibrium of point a - Define the points at which there is change in load or beam

More information

PROBLEM 5.1 SOLUTION. Reactions: Pb L Pa L. From A to B: 0 < x < a. Pb L Pb L Pb L Pbx L. From B to C: a < x < L Pa L. Pa L. L Pab At section B: M = L

PROBLEM 5.1 SOLUTION. Reactions: Pb L Pa L. From A to B: 0 < x < a. Pb L Pb L Pb L Pbx L. From B to C: a < x < L Pa L. Pa L. L Pab At section B: M = L PROBEM 5.1 For the beam and loading shown, (a) draw the shear and bending-moment diagrams, (b) determine the equations of the shear and bending-moment curves. SOUTION Reactions: From A to B: 0 < x < a

More information

3.032 Problem Set 1 Fall 2007 Due: Start of Lecture,

3.032 Problem Set 1 Fall 2007 Due: Start of Lecture, 3.032 Problem Set 1 Fall 2007 Due: Start of Lecture, 09.14.07 1. The I35 bridge in Minneapolis collapsed in Summer 2007. The failure apparently occurred at a pin in the gusset plate of the truss supporting

More information

COLUMNS: BUCKLING (DIFFERENT ENDS)

COLUMNS: BUCKLING (DIFFERENT ENDS) COLUMNS: BUCKLING (DIFFERENT ENDS) Buckling of Long Straight Columns Example 4 Slide No. 1 A simple pin-connected truss is loaded and supported as shown in Fig. 1. All members of the truss are WT10 43

More information

Stress Transformation Equations: u = +135 (Fig. a) s x = 80 MPa s y = 0 t xy = 45 MPa. we obtain, cos u + t xy sin 2u. s x = s x + s y.

Stress Transformation Equations: u = +135 (Fig. a) s x = 80 MPa s y = 0 t xy = 45 MPa. we obtain, cos u + t xy sin 2u. s x = s x + s y. 014 Pearson Education, Inc., Upper Saddle River, NJ. All rights reserved. This material is protected under all copyright laws as they currently 9 7. Determine the normal stress and shear stress acting

More information

IDE 110 Mechanics of Materials Spring 2006 Final Examination FOR GRADING ONLY

IDE 110 Mechanics of Materials Spring 2006 Final Examination FOR GRADING ONLY Spring 2006 Final Examination STUDENT S NAME (please print) STUDENT S SIGNATURE STUDENT NUMBER IDE 110 CLASS SECTION INSTRUCTOR S NAME Do not turn this page until instructed to start. Write your name on

More information

= 50 ksi. The maximum beam deflection Δ max is not = R B. = 30 kips. Notes for Strength of Materials, ET 200

= 50 ksi. The maximum beam deflection Δ max is not = R B. = 30 kips. Notes for Strength of Materials, ET 200 Notes for Strength of Materials, ET 00 Steel Six Easy Steps Steel beam design is about selecting the lightest steel beam that will support the load without exceeding the bending strength or shear strength

More information

I certify that I have not given unauthorized aid nor have I received aid in the completion of this exam.

I certify that I have not given unauthorized aid nor have I received aid in the completion of this exam. NAME: ME 270 Fall 2012 Examination No. 3 - Makeup Please review the following statement: Group No.: I certify that I have not given unauthorized aid nor have I received aid in the completion of this exam.

More information

A concrete cylinder having a a diameter of of in. mm and elasticity. Stress and Strain: Stress and Strain: 0.

A concrete cylinder having a a diameter of of in. mm and elasticity. Stress and Strain: Stress and Strain: 0. 2011 earson Education, Inc., Upper Saddle River, NJ. ll rights reserved. This material is protected under all copyright laws as they currently 8 1. 3 1. concrete cylinder having a a diameter of of 6.00

More information

[5] Stress and Strain

[5] Stress and Strain [5] Stress and Strain Page 1 of 34 [5] Stress and Strain [5.1] Internal Stress of Solids [5.2] Design of Simple Connections (will not be covered in class) [5.3] Deformation and Strain [5.4] Hooke s Law

More information

CIV 207 Winter For practice

CIV 207 Winter For practice CIV 07 Winter 009 Assignment #10 Friday, March 0 th Complete the first three questions. Submit your work to Box #5 on the th floor of the MacDonald building by 1 noon on Tuesday March 31 st. No late submissions

More information

CHAPTER 2 Failure/Fracture Criterion

CHAPTER 2 Failure/Fracture Criterion (11) CHAPTER 2 Failure/Fracture Criterion (12) Failure (Yield) Criteria for Ductile Materials under Plane Stress Designer engineer: 1- Analysis of loading (for simple geometry using what you learn here

More information

2.0 Introduction. F i. [Eq. 2.1] M i. [Eq. 2.2]

2.0 Introduction. F i. [Eq. 2.1] M i. [Eq. 2.2] Chapter Statics.0 Introduction A Statics analysis is generally the first step in determining how an engineering system deforms under load, and how the system supports the load internally. For equilibrium,

More information

APPENDIX A Thickness of Base Metal

APPENDIX A Thickness of Base Metal APPENDIX A Thickness of Base Metal For uncoated steel sheets, the thickness of the base metal is listed in Table A.1. For galvanized steel sheets, the thickness of the base metal can be obtained by subtracting

More information

3 A y 0.090

3 A y 0.090 ROBLM.1 5.0 in. 5 8 in. diameter A standard tension test is used to determine the properties of an experimental plastic. The test specimen is a 5 -in.-diameter rod and it is subjected to an 800-lb tensile

More information

MECHANICS OF MATERIALS

MECHANICS OF MATERIALS Third E CHAPTER 6 Shearing MECHANCS OF MATERALS Ferdinand P. Beer E. Russell Johnston, Jr. John T. DeWolf Lecture Notes: J. Walt Oler Texas Tech University Stresses in Beams and Thin- Walled Members Shearing

More information

MECHANICS OF MATERIALS

MECHANICS OF MATERIALS CHATR Stress MCHANICS OF MATRIALS and Strain Axial Loading Stress & Strain: Axial Loading Suitability of a structure or machine may depend on the deformations in the structure as well as the stresses induced

More information

Part 1 is to be completed without notes, beam tables or a calculator. DO NOT turn Part 2 over until you have completed and turned in Part 1.

Part 1 is to be completed without notes, beam tables or a calculator. DO NOT turn Part 2 over until you have completed and turned in Part 1. NAME CM 3505 Fall 06 Test 2 Part 1 is to be completed without notes, beam tables or a calculator. Part 2 is to be completed after turning in Part 1. DO NOT turn Part 2 over until you have completed and

More information

DL CMU wall = 51.0 (lb/ft 2 ) 0.7 (ft) DL beam = 2.5 (lb/ft 2 ) 18.0 (ft) 5

DL CMU wall = 51.0 (lb/ft 2 ) 0.7 (ft) DL beam = 2.5 (lb/ft 2 ) 18.0 (ft) 5 SUJECT: HEADER EAM SELECTION SHEET 108 of 131 INTERIOR HEADER EAM SELECTION - ay length = 36 ft. (stairwell) INTERIOR HEADER EAM Header eam 1 2 Total ay Length = 36 (ft) Total ay Width = 10 (ft) 20.5 Fill

More information

MECHANICS OF MATERIALS

MECHANICS OF MATERIALS CHTER MECHNICS OF MTERILS 10 Ferdinand. Beer E. Russell Johnston, Jr. Columns John T. DeWolf cture Notes: J. Walt Oler Texas Tech University 006 The McGraw-Hill Companies, Inc. ll rights reserved. Columns

More information

Mechanics of Materials II. Chapter III. A review of the fundamental formulation of stress, strain, and deflection

Mechanics of Materials II. Chapter III. A review of the fundamental formulation of stress, strain, and deflection Mechanics of Materials II Chapter III A review of the fundamental formulation of stress, strain, and deflection Outline Introduction Assumtions and limitations Axial loading Torsion of circular shafts

More information

P.E. Civil Exam Review:

P.E. Civil Exam Review: P.E. Civil Exam Review: Structural Analysis J.P. Mohsen Email: jpm@louisville.edu Structures Determinate Indeterminate STATICALLY DETERMINATE STATICALLY INDETERMINATE Stability and Determinacy of Trusses

More information

Introduction to Structural Member Properties

Introduction to Structural Member Properties Introduction to Structural Member Properties Structural Member Properties Moment of Inertia (I): a mathematical property of a cross-section (measured in inches 4 or in 4 ) that gives important information

More information

Solid Mechanics Homework Answers

Solid Mechanics Homework Answers Name: Date: Solid Mechanics Homework nswers Please show all of your work, including which equations you are using, and circle your final answer. Be sure to include the units in your answers. 1. The yield

More information

Towards The. Design of Super Columns. Prof. AbdulQader Najmi

Towards The. Design of Super Columns. Prof. AbdulQader Najmi Towards The Design of Super Columns Prof. AbdulQader Najmi Description: Tubular Column Square or Round Filled with Concrete Provided with U-Links welded to its Walls as shown in Figure 1 Compression Specimen

More information

Homework No. 1 MAE/CE 459/559 John A. Gilbert, Ph.D. Fall 2004

Homework No. 1 MAE/CE 459/559 John A. Gilbert, Ph.D. Fall 2004 Homework No. 1 MAE/CE 459/559 John A. Gilbert, Ph.D. 1. A beam is loaded as shown. The dimensions of the cross section appear in the insert. the figure. Draw a complete free body diagram showing an equivalent

More information

5. What is the moment of inertia about the x - x axis of the rectangular beam shown?

5. What is the moment of inertia about the x - x axis of the rectangular beam shown? 1 of 5 Continuing Education Course #274 What Every Engineer Should Know About Structures Part D - Bending Strength Of Materials NOTE: The following question was revised on 15 August 2018 1. The moment

More information

D : SOLID MECHANICS. Q. 1 Q. 9 carry one mark each.

D : SOLID MECHANICS. Q. 1 Q. 9 carry one mark each. GTE 2016 Q. 1 Q. 9 carry one mark each. D : SOLID MECHNICS Q.1 single degree of freedom vibrating system has mass of 5 kg, stiffness of 500 N/m and damping coefficient of 100 N-s/m. To make the system

More information

Review Lecture. AE1108-II: Aerospace Mechanics of Materials. Dr. Calvin Rans Dr. Sofia Teixeira De Freitas

Review Lecture. AE1108-II: Aerospace Mechanics of Materials. Dr. Calvin Rans Dr. Sofia Teixeira De Freitas Review Lecture AE1108-II: Aerospace Mechanics of Materials Dr. Calvin Rans Dr. Sofia Teixeira De Freitas Aerospace Structures & Materials Faculty of Aerospace Engineering Analysis of an Engineering System

More information

Stress Analysis Lecture 3 ME 276 Spring Dr./ Ahmed Mohamed Nagib Elmekawy

Stress Analysis Lecture 3 ME 276 Spring Dr./ Ahmed Mohamed Nagib Elmekawy Stress Analysis Lecture 3 ME 276 Spring 2017-2018 Dr./ Ahmed Mohamed Nagib Elmekawy Axial Stress 2 Beam under the action of two tensile forces 3 Beam under the action of two tensile forces 4 Shear Stress

More information

ME Final Exam. PROBLEM NO. 4 Part A (2 points max.) M (x) y. z (neutral axis) beam cross-sec+on. 20 kip ft. 0.2 ft. 10 ft. 0.1 ft.

ME Final Exam. PROBLEM NO. 4 Part A (2 points max.) M (x) y. z (neutral axis) beam cross-sec+on. 20 kip ft. 0.2 ft. 10 ft. 0.1 ft. ME 323 - Final Exam Name December 15, 2015 Instructor (circle) PROEM NO. 4 Part A (2 points max.) Krousgrill 11:30AM-12:20PM Ghosh 2:30-3:20PM Gonzalez 12:30-1:20PM Zhao 4:30-5:20PM M (x) y 20 kip ft 0.2

More information

GATE SOLUTIONS E N G I N E E R I N G

GATE SOLUTIONS E N G I N E E R I N G GATE SOLUTIONS C I V I L E N G I N E E R I N G From (1987-018) Office : F-16, (Lower Basement), Katwaria Sarai, New Delhi-110016 Phone : 011-65064 Mobile : 81309090, 9711853908 E-mail: info@iesmasterpublications.com,

More information

ES230 STRENGTH OF MATERIALS

ES230 STRENGTH OF MATERIALS ES230 STRENGTH OF MATERIALS Exam 1 Study Guide. Exam 1: Wednesday, February 8 th, in-class Updated 2/5/17 Purpose of this Guide: To thoroughly prepare students for the exact types of problems that will

More information

Level 7 Postgraduate Diploma in Engineering Computational mechanics using finite element method

Level 7 Postgraduate Diploma in Engineering Computational mechanics using finite element method 9210-203 Level 7 Postgraduate Diploma in Engineering Computational mechanics using finite element method You should have the following for this examination one answer book No additional data is attached

More information

This procedure covers the determination of the moment of inertia about the neutral axis.

This procedure covers the determination of the moment of inertia about the neutral axis. 327 Sample Problems Problem 16.1 The moment of inertia about the neutral axis for the T-beam shown is most nearly (A) 36 in 4 (C) 236 in 4 (B) 136 in 4 (D) 736 in 4 This procedure covers the determination

More information

CIV E 205 Mechanics of Solids II. Course Notes

CIV E 205 Mechanics of Solids II. Course Notes Department of Civil Engineering CIV E 205 Mechanics of Solids II Instructor: Tarek Hegazi Email: tarek@uwaterloo.ca Course Notes Mechanics of Materials Objectives: - Solve Problems in a structured systematic

More information

ME 202 STRENGTH OF MATERIALS SPRING 2014 HOMEWORK 4 SOLUTIONS

ME 202 STRENGTH OF MATERIALS SPRING 2014 HOMEWORK 4 SOLUTIONS ÇANKAYA UNIVERSITY MECHANICAL ENGINEERING DEPARTMENT ME 202 STRENGTH OF MATERIALS SPRING 2014 Due Date: 1 ST Lecture Hour of Week 12 (02 May 2014) Quiz Date: 3 rd Lecture Hour of Week 12 (08 May 2014)

More information

1.1 To observe, evaluate and report on the load deflection relationship of a simply supported beam and a cantilever beam.

1.1 To observe, evaluate and report on the load deflection relationship of a simply supported beam and a cantilever beam. I. OBJECTIVES 1.1 To observe, evaluate and report on the load deflection relationship of a simply supported beam and a cantilever beam. 1.2 To determine the modulus of elasticity of the beam and what the

More information

Problem 7.1 Determine the soil pressure distribution under the footing. Elevation. Plan. M 180 e 1.5 ft P 120. (a) B= L= 8 ft L e 1.5 ft 1.

Problem 7.1 Determine the soil pressure distribution under the footing. Elevation. Plan. M 180 e 1.5 ft P 120. (a) B= L= 8 ft L e 1.5 ft 1. Problem 7.1 Determine the soil pressure distribution under the footing. Elevation Plan M 180 e 1.5 ft P 10 (a) B= L= 8 ft L e 1.5 ft 1.33 ft 6 1 q q P 6 (P e) 180 6 (180) 4.9 kip/ft B L B L 8(8) 8 3 P

More information

CITY AND GUILDS 9210 UNIT 135 MECHANICS OF SOLIDS Level 6 TUTORIAL 5A - MOMENT DISTRIBUTION METHOD

CITY AND GUILDS 9210 UNIT 135 MECHANICS OF SOLIDS Level 6 TUTORIAL 5A - MOMENT DISTRIBUTION METHOD Outcome 1 The learner can: CITY AND GUIDS 910 UNIT 15 ECHANICS OF SOIDS evel 6 TUTORIA 5A - OENT DISTRIBUTION ETHOD Calculate stresses, strain and deflections in a range of components under various load

More information

EMA 3702 Mechanics & Materials Science (Mechanics of Materials) Chapter 2 Stress & Strain - Axial Loading

EMA 3702 Mechanics & Materials Science (Mechanics of Materials) Chapter 2 Stress & Strain - Axial Loading MA 3702 Mechanics & Materials Science (Mechanics of Materials) Chapter 2 Stress & Strain - Axial Loading MA 3702 Mechanics & Materials Science Zhe Cheng (2018) 2 Stress & Strain - Axial Loading Statics

More information

Danger of Snow in the Sunshine State

Danger of Snow in the Sunshine State Undergraduate Journal of Mathematical Modeling: One + Two Volume 7 2017 Spring 2017 Issue 2 Article 2 Danger of Snow in the Sunshine State Dmitrii Karpenko University of South Florida Advisors: Arcadii

More information

host structure (S.F.D.)

host structure (S.F.D.) TABLE 00.4 FBC Typical Mansard Beam [AAF] Allowable Span of Mansard Screen Enclosure Self-Mating Beams in accordance with requirements of Table 00.4 (and the 005 Aluminum Design Manual) using 6005T5 alloy:

More information

Three torques act on the shaft. Determine the internal torque at points A, B, C, and D.

Three torques act on the shaft. Determine the internal torque at points A, B, C, and D. ... 7. Three torques act on the shaft. Determine the internal torque at points,, C, and D. Given: M 1 M M 3 300 Nm 400 Nm 00 Nm Solution: Section : x = 0; T M 1 M M 3 0 T M 1 M M 3 T 100.00 Nm Section

More information

Properties of Sections

Properties of Sections ARCH 314 Structures I Test Primer Questions Dr.-Ing. Peter von Buelow Properties of Sections 1. Select all that apply to the characteristics of the Center of Gravity: A) 1. The point about which the body

More information

ME 323 FINAL EXAM FALL SEMESTER :00 PM 9:00 PM Dec. 16, 2010

ME 323 FINAL EXAM FALL SEMESTER :00 PM 9:00 PM Dec. 16, 2010 ME 33 FINA EXAM FA SEMESTER 1 7: PM 9: PM Dec. 16, 1 Instructions 1. Begin each problem in the space provided on the eamination sheets. If additional space is required, use the paper provided. Work on

More information

Use Hooke s Law (as it applies in the uniaxial direction),

Use Hooke s Law (as it applies in the uniaxial direction), 0.6 STRSS-STRAIN RLATIONSHIP Use the principle of superposition Use Poisson s ratio, v lateral longitudinal Use Hooke s Law (as it applies in the uniaxial direction), x x v y z, y y vx z, z z vx y Copyright

More information

Discontinuous Distributions in Mechanics of Materials

Discontinuous Distributions in Mechanics of Materials Discontinuous Distributions in Mechanics of Materials J.E. Akin, Rice University 1. Introduction The study of the mechanics of materials continues to change slowly. The student needs to learn about software

More information

Seismic Pushover Analysis Using AASHTO Guide Specifications for LRFD Seismic Bridge Design

Seismic Pushover Analysis Using AASHTO Guide Specifications for LRFD Seismic Bridge Design Seismic Pushover Analysis Using AASHTO Guide Specifications for LRFD Seismic Bridge Design Elmer E. Marx, Alaska Department of Transportation and Public Facilities Michael Keever, California Department

More information

Problem d d d B C E D. 0.8d. Additional lecturebook examples 29 ME 323

Problem d d d B C E D. 0.8d. Additional lecturebook examples 29 ME 323 Problem 9.1 Two beam segments, AC and CD, are connected together at C by a frictionless pin. Segment CD is cantilevered from a rigid support at D, and segment AC has a roller support at A. a) Determine

More information

MECHANICS OF MATERIALS

MECHANICS OF MATERIALS Third CHTR Stress MCHNICS OF MTRIS Ferdinand. Beer. Russell Johnston, Jr. John T. DeWolf ecture Notes: J. Walt Oler Texas Tech University and Strain xial oading Contents Stress & Strain: xial oading Normal

More information

MECHANICS OF MATERIALS. Prepared by Engr. John Paul Timola

MECHANICS OF MATERIALS. Prepared by Engr. John Paul Timola MECHANICS OF MATERIALS Prepared by Engr. John Paul Timola Mechanics of materials branch of mechanics that studies the internal effects of stress and strain in a solid body. stress is associated with the

More information

CIV E 205 Mechanics of Solids II. Course Notes

CIV E 205 Mechanics of Solids II. Course Notes University of Waterloo Department of Civil Engineering CIV E 205 Mechanics of Solids II Instructor: Tarek Hegazi Room: CPH 2373 G, Ext. 2174 Email: tarek@uwaterloo.ca Course Web: www.civil.uwaterloo.ca/tarek/hegazy205.html

More information

Errata (Includes critical corrections only for the 1 st, 2 nd & 3 rd reprints)

Errata (Includes critical corrections only for the 1 st, 2 nd & 3 rd reprints) Page Number Errata (Includes critical corrections only for the 1 st, 2 nd & 3 rd reprints) Description of Correction Mechanics of Materials, 8e James M. Gere & Barry J. Goodno ISBN: 9781111577735 11 Figure

More information

Karbala University College of Engineering Department of Civil Eng. Lecturer: Dr. Jawad T. Abodi

Karbala University College of Engineering Department of Civil Eng. Lecturer: Dr. Jawad T. Abodi Chapter 04 Structural Steel Design According to the AISC Manual 13 th Edition Analysis and Design of Compression Members By Dr. Jawad Talib Al-Nasrawi University of Karbala Department of Civil Engineering

More information

REDUCTION OF A SIMPLE DISTRIBUTED LOADING. Today s Objectives: Students will be able to determine an equivalent force for a distributed load.

REDUCTION OF A SIMPLE DISTRIBUTED LOADING. Today s Objectives: Students will be able to determine an equivalent force for a distributed load. REDUCTION OF A SIMPLE DISTRIBUTED LOADING Today s Objectives: Students will be able to determine an equivalent force for a distributed load. = READING QUIZ 1. The resultant force (F R ) due to a distributed

More information

POE Practice Test - Materials

POE Practice Test - Materials Class: Date: POE Practice Test - Materials Multiple Choice Identify the choice that best completes the statement or answers the question. 1. A student weighs 150 lbs and is standing on a beam which spans

More information

Physics 8 Monday, November 23, 2015

Physics 8 Monday, November 23, 2015 Physics 8 Monday, November 23, 2015 Handing out HW11, due Friday, December 4. One or two more beam-related examples, then we ll move on to oscillations ( periodic motion ). This week s reading is Mazur

More information

Free Body Diagram: Solution: The maximum load which can be safely supported by EACH of the support members is: ANS: A =0.217 in 2

Free Body Diagram: Solution: The maximum load which can be safely supported by EACH of the support members is: ANS: A =0.217 in 2 Problem 10.9 The angle β of the system in Problem 10.8 is 60. The bars are made of a material that will safely support a tensile normal stress of 8 ksi. Based on this criterion, if you want to design the

More information

REVIEW FOR EXAM II. Dr. Ibrahim A. Assakkaf SPRING 2002

REVIEW FOR EXAM II. Dr. Ibrahim A. Assakkaf SPRING 2002 REVIEW FOR EXM II. J. Clark School of Engineering Department of Civil and Environmental Engineering b Dr. Ibrahim. ssakkaf SPRING 00 ENES 0 Mechanics of Materials Department of Civil and Environmental

More information

General Comparison between AISC LRFD and ASD

General Comparison between AISC LRFD and ASD General Comparison between AISC LRFD and ASD 1 General Comparison between AISC LRFD and ASD 2 AISC ASD and LRFD AISC ASD = American Institute of Steel Construction = Allowable Stress Design AISC Ninth

More information

Solution: The moment of inertia for the cross-section is: ANS: ANS: Problem 15.6 The material of the beam in Problem

Solution: The moment of inertia for the cross-section is: ANS: ANS: Problem 15.6 The material of the beam in Problem Problem 15.4 The beam consists of material with modulus of elasticity E 14x10 6 psi and is subjected to couples M 150, 000 in lb at its ends. (a) What is the resulting radius of curvature of the neutral

More information

Bracing for Earthquake Resistant Design

Bracing for Earthquake Resistant Design h z (Draft, 010) Bracing for Earthquae Resistant Design 1 September 18, 00 (010 update) Rigid Roof Idealization and Column Stiffness Relative to the columns, the roof structural system might be quite rigid,

More information

1.105 Solid Mechanics Laboratory Fall 2003

1.105 Solid Mechanics Laboratory Fall 2003 1.105 Solid Mechanics Laboratory Fall 200 Experiment 7 Elastic Buckling. The objectives of this experiment are To study the failure of a truss structure due to local buckling of a compression member. To

More information

1 of 12. Given: Law of Cosines: C. Law of Sines: Stress = E = G

1 of 12. Given: Law of Cosines: C. Law of Sines: Stress = E = G ES230 STRENGTH OF MATERIALS FINAL EXAM: WEDNESDAY, MAY 15 TH, 4PM TO 7PM, AEC200 Closed book. Calculator and writing supplies allowed. Protractor and compass required. 180 Minute Time Limit You must have

More information

MECHANICS OF MATERIALS

MECHANICS OF MATERIALS Third CHTR Stress MCHNICS OF MTRIS Ferdinand. Beer. Russell Johnston, Jr. John T. DeWolf ecture Notes: J. Walt Oler Texas Tech University and Strain xial oading Contents Stress & Strain: xial oading Normal

More information

Steel Cross Sections. Structural Steel Design

Steel Cross Sections. Structural Steel Design Steel Cross Sections Structural Steel Design PROPERTIES OF SECTIONS Perhaps the most important properties of a beam are the depth and shape of its cross section. There are many to choose from, and there

More information

EMA 3702 Mechanics & Materials Science (Mechanics of Materials) Chapter 5 Beams for Bending

EMA 3702 Mechanics & Materials Science (Mechanics of Materials) Chapter 5 Beams for Bending MA 3702 Mechanics & Materials Science (Mechanics of Materials) Chapter 5 Beams for Bending Introduction esign of beams for mechanical or civil/structural applications Transverse loading in most cases for

More information

By Dr. Mohammed Ramidh

By Dr. Mohammed Ramidh Engineering Materials Design Lecture.6 the design of beams By Dr. Mohammed Ramidh 6.1 INTRODUCTION Finding the shear forces and bending moments is an essential step in the design of any beam. we usually

More information

MECE 3321 MECHANICS OF SOLIDS CHAPTER 3

MECE 3321 MECHANICS OF SOLIDS CHAPTER 3 MECE 3321 MECHANICS OF SOLIDS CHAPTER 3 Samantha Ramirez TENSION AND COMPRESSION TESTS Tension and compression tests are used primarily to determine the relationship between σ avg and ε avg in any material.

More information

EMA 3702 Mechanics & Materials Science (Mechanics of Materials) Chapter 3 Torsion

EMA 3702 Mechanics & Materials Science (Mechanics of Materials) Chapter 3 Torsion EMA 3702 Mechanics & Materials Science (Mechanics of Materials) Chapter 3 Torsion Introduction Stress and strain in components subjected to torque T Circular Cross-section shape Material Shaft design Non-circular

More information

CIV E 205 Mechanics of Solids II. Course Notes

CIV E 205 Mechanics of Solids II. Course Notes University of Waterloo Department of Civil Engineering CIV E 205 Mechanics of Solids II Instructor: Tarek Hegazi Room: CPH 2373 G, Ext. 2174 Email: tarek@uwaterloo.ca Course Web: www.civil.uwaterloo.ca/tarek/205-2005.html

More information

APRIL Conquering the FE & PE exams Formulas, Examples & Applications. Topics covered in this month s column:

APRIL Conquering the FE & PE exams Formulas, Examples & Applications. Topics covered in this month s column: APRIL 2015 DR. Z s CORNER Conquering the FE & PE exams Formulas, Examples & Applications Topics covered in this month s column: PE Exam Specifications (Geotechnical) Transportation (Horizontal Curves)

More information

4.MECHANICAL PROPERTIES OF MATERIALS

4.MECHANICAL PROPERTIES OF MATERIALS 4.MECHANICAL PROPERTIES OF MATERIALS The diagram representing the relation between stress and strain in a given material is an important characteristic of the material. To obtain the stress-strain diagram

More information

Module 4 : Deflection of Structures Lecture 4 : Strain Energy Method

Module 4 : Deflection of Structures Lecture 4 : Strain Energy Method Module 4 : Deflection of Structures Lecture 4 : Strain Energy Method Objectives In this course you will learn the following Deflection by strain energy method. Evaluation of strain energy in member under

More information

PROBLEM 7.37 SOLUTION

PROBLEM 7.37 SOLUTION PROLEM 7.37 For the beam and loading shown, (a) draw the shear and bending-moment diagrams, (b) determine the maimum absolute values of the shear and bending moment. Free bod: Entire beam Σ M = 0: E(6

More information

Q. 1 Q. 5 carry one mark each.

Q. 1 Q. 5 carry one mark each. General ptitude G Set-8 Q. 1 Q. 5 carry one mark each. Q.1 The chairman requested the aggrieved shareholders to him. () bare with () bore with (C) bear with (D) bare Q.2 Identify the correct spelling out

More information

Physics 8 Monday, November 20, 2017

Physics 8 Monday, November 20, 2017 Physics 8 Monday, November 20, 2017 Pick up HW11 handout, due Dec 1 (Friday next week). This week, you re skimming/reading O/K ch8, which goes into more detail on beams. Since many people will be traveling

More information

2. Rigid bar ABC supports a weight of W = 50 kn. Bar ABC is pinned at A and supported at B by rod (1). What is the axial force in rod (1)?

2. Rigid bar ABC supports a weight of W = 50 kn. Bar ABC is pinned at A and supported at B by rod (1). What is the axial force in rod (1)? IDE 110 S08 Test 1 Name: 1. Determine the internal axial forces in segments (1), (2) and (3). (a) N 1 = kn (b) N 2 = kn (c) N 3 = kn 2. Rigid bar ABC supports a weight of W = 50 kn. Bar ABC is pinned at

More information

UNIT-V MOMENT DISTRIBUTION METHOD

UNIT-V MOMENT DISTRIBUTION METHOD UNIT-V MOMENT DISTRIBUTION METHOD Distribution and carryover of moments Stiffness and carry over factors Analysis of continuous beams Plane rigid frames with and without sway Neylor s simplification. Hardy

More information

RSTAB. Structural Analysis and Design Dynamic Analysis. Verification Manual. Ing. Software Dlubal Am Zellweg 2 D Tiefenbach

RSTAB. Structural Analysis and Design Dynamic Analysis. Verification Manual. Ing. Software Dlubal Am Zellweg 2 D Tiefenbach Version July 2011 Program RSTAB Structural Analysis and Design Dynamic Analysis Verification Manual All rights, including those of translation, are reserved. portion of this book may be reproduced mechanically,

More information

MAAE 2202 A. Come to the PASS workshop with your mock exam complete. During the workshop you can work with other students to review your work.

MAAE 2202 A. Come to the PASS workshop with your mock exam complete. During the workshop you can work with other students to review your work. It is most beneficial to you to write this mock final exam UNDER EXAM CONDITIONS. This means: Complete the exam in 3 hours. Work on your own. Keep your textbook closed. Attempt every question. After the

More information

Chapter 1 Introduction- Concept of Stress

Chapter 1 Introduction- Concept of Stress hapter 1 Introduction- oncept of Stress INTRODUTION Review of Statics xial Stress earing Stress Torsional Stress 14 6 ending Stress W W L Introduction 1-1 Shear Stress W W Stress and Strain L y y τ xy

More information

Singly Symmetric Combination Section Crane Girder Design Aids. Patrick C. Johnson

Singly Symmetric Combination Section Crane Girder Design Aids. Patrick C. Johnson Singly Symmetric Combination Section Crane Girder Design Aids by Patrick C. Johnson PCJohnson@psu.edu The Pennsylvania State University Department of Civil and Environmental Engineering University Park,

More information

Serviceability Deflection calculation

Serviceability Deflection calculation Chp-6:Lecture Goals Serviceability Deflection calculation Deflection example Structural Design Profession is concerned with: Limit States Philosophy: Strength Limit State (safety-fracture, fatigue, overturning

More information

MECHANICS OF MATERIALS Sample Problem 4.2

MECHANICS OF MATERIALS Sample Problem 4.2 Sample Problem 4. SOLUTON: Based on the cross section geometry, calculate the location of the section centroid and moment of inertia. ya ( + Y Ad ) A A cast-iron machine part is acted upon by a kn-m couple.

More information

2 marks Questions and Answers

2 marks Questions and Answers 1. Define the term strain energy. A: Strain Energy of the elastic body is defined as the internal work done by the external load in deforming or straining the body. 2. Define the terms: Resilience and

More information

ME 323 Examination #2 April 11, 2018

ME 323 Examination #2 April 11, 2018 ME 2 Eamination #2 April, 2 PROBLEM NO. 25 points ma. A thin-walled pressure vessel is fabricated b welding together two, open-ended stainless-steel vessels along a 6 weld line. The welded vessel has an

More information

Due Monday, September 14 th, 12:00 midnight

Due Monday, September 14 th, 12:00 midnight Due Monday, September 14 th, 1: midnight This homework is considering the analysis of plane and space (3D) trusses as discussed in class. A list of MatLab programs that were discussed in class is provided

More information

Symmetric Bending of Beams

Symmetric Bending of Beams Symmetric Bending of Beams beam is any long structural member on which loads act perpendicular to the longitudinal axis. Learning objectives Understand the theory, its limitations and its applications

More information

Lecture 4 Honeycombs Notes, 3.054

Lecture 4 Honeycombs Notes, 3.054 Honeycombs-In-plane behavior Lecture 4 Honeycombs Notes, 3.054 Prismatic cells Polymer, metal, ceramic honeycombs widely available Used for sandwich structure cores, energy absorption, carriers for catalysts

More information

If the solution does not follow a logical thought process, it will be assumed in error.

If the solution does not follow a logical thought process, it will be assumed in error. Please indicate your group number (If applicable) Circle Your Instructor s Name and Section: MWF 8:30-9:20 AM Prof. Kai Ming Li MWF 2:30-3:20 PM Prof. Fabio Semperlotti MWF 9:30-10:20 AM Prof. Jim Jones

More information

Part IB Paper 2: Structures. Examples Paper 2/3 Elastic structural analysis

Part IB Paper 2: Structures. Examples Paper 2/3 Elastic structural analysis ISSUEB 011 15 NOV 2013 1 Engineering Tripos Part IB SECOND YEAR Part IB Paper 2: Structures Examples Paper 2/3 Elastic structural analysis Straightforward questions are marked by t; Tripos standard questions

More information

Chapter 8. Shear and Diagonal Tension

Chapter 8. Shear and Diagonal Tension Chapter 8. and Diagonal Tension 8.1. READING ASSIGNMENT Text Chapter 4; Sections 4.1-4.5 Code Chapter 11; Sections 11.1.1, 11.3, 11.5.1, 11.5.3, 11.5.4, 11.5.5.1, and 11.5.6 8.2. INTRODUCTION OF SHEAR

More information

MATERIALS FOR CIVIL AND CONSTRUCTION ENGINEERS

MATERIALS FOR CIVIL AND CONSTRUCTION ENGINEERS MATERIALS FOR CIVIL AND CONSTRUCTION ENGINEERS 3 rd Edition Michael S. Mamlouk Arizona State University John P. Zaniewski West Virginia University Solution Manual FOREWORD This solution manual includes

More information

Chapter 8: Bending and Shear Stresses in Beams

Chapter 8: Bending and Shear Stresses in Beams Chapter 8: Bending and Shear Stresses in Beams Introduction One of the earliest studies concerned with the strength and deflection of beams was conducted by Galileo Galilei. Galileo was the first to discuss

More information

Lecture 8: Flexibility Method. Example

Lecture 8: Flexibility Method. Example ecture 8: lexibility Method Example The plane frame shown at the left has fixed supports at A and C. The frame is acted upon by the vertical load P as shown. In the analysis account for both flexural and

More information

Problem 1: Calculating deflection by integration uniform load. Problem 2: Calculating deflection by integration - triangular load pattern

Problem 1: Calculating deflection by integration uniform load. Problem 2: Calculating deflection by integration - triangular load pattern Problem 1: Calculating deflection by integration uniform load Problem 2: Calculating deflection by integration - triangular load pattern Problem 3: Deflections - by differential equations, concentrated

More information

Companion. Jeffrey E. Jones

Companion. Jeffrey E. Jones MATLAB7 Companion 1O11OO1O1O1OOOO1O1OO1111O1O1OO 1O1O1OO1OO1O11OOO1O111O1O1O1O1 O11O1O1O11O1O1O1O1OO1O11O1O1O1 O1O1O1111O11O1O1OO1O1O1O1OOOOO O1111O1O1O1O1O1O1OO1OO1OO1OOO1 O1O11111O1O1O1O1O Jeffrey E.

More information

The Finite Element Method for the Analysis of Non-Linear and Dynamic Systems

The Finite Element Method for the Analysis of Non-Linear and Dynamic Systems The Finite Element Method for the Analysis of Non-Linear and Dynamic Systems Prof. Dr. Eleni Chatzi Dr. Giuseppe Abbiati, Dr. Konstantinos Agathos Lecture 1-21 September, 2017 Institute of Structural Engineering

More information