File:Psych1HeatCoil.EES 10/21/2003 3:41:38 PM Page 1 EES Ver : #317: CEAE University of Colorado, Boulder
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1 File:Psych1HeatCoil.EES 10/21/2003 3:41:38 PM Page 1 "AREN 3010 In-Class Psychrometric Problem #1" " Moist air enters a heating coil at 40 F dry-bulb temperature and 36 F wet-bulb temperature at a rate of 2000 cfm. Barometric pressure is psia. The air leaves the coil at a dry-bulb temperature of 140 F. " "Given information" P_atm = T_sa = 140 T_ma = 40 TWB_ma = 36 CFM_ma = 2000 TW_ent = 180 TW_lvg = 160 T_steam = 250 "Calculate properties of mixed air" W_ma = HUMRAT(AIRH2O,t=T_ma, b=twb_ma,p=p_atm) h_ma = ENTHALPY(AIRH2O,t=T_ma, w=w_ma,p=p_atm) v_ma = VOLUME(AIRH2O,t=T_ma, w=w_ma,p=p_atm) c_p = SPECHEAT(AIRH2O,t=T_ma,w=W_ma,p=P_atm) "a) How much heat is added to the air?" m_sa = CFM_ma/v_ma*CONVERT(hr,min) h_sa = ENTHALPY(AIRH2O,t=T_sa, w=w_ma,p=p_atm) Q_air = m_sa*(h_sa-h_ma) Q_airT = m_sa*c_p*(t_sa-t_ma) "b) If the heat is provided by hot water that enters the coil at 180 F and leaves at 160 F, what is the water flow rate?" c_water = SPECHEAT(WATER,t=TW_ent,p=P_atm) m_w = Q_air/(c_WATER*(TW_ent-TW_lvg)) "c) If the heat is provided by a steam coil with saturated steam at 250 F, what steam flow rate is required?
2 File:Psych1HeatCoil.EES 10/21/2003 3:41:39 PM Page 2 Assume that the steam leaves the coil as a saturated liquid?" hfg_steam = ENTHALPY(STEAM,t=T_steam,x=1)-ENTHALPY(STEAM,t=T_steam,x=0) m_steam = Q_air/hfg_steam AREN 3010 In-Class Psychrometric Problem #1 Moist air enters a heating coil at 40 F dry-bulb temperature and 36 F wet-bulb temperature at a rate of 2000 cfm. Barometric pressure is psia. The air leaves the coil at a dry-bulb temperature of 140 F. Given information P atm = T sa = 140 T ma = 40 TWB ma = 36 CFM ma = 2000 TW ent = 180 TW lvg = 160 T steam = 250 Calculate properties of mixed air W ma = ω 'AirH2O', T = T ma, B = TWB ma, P = P atm h ma = h 'AirH2O', T = T ma, w = W ma, P = P atm v ma = v 'AirH2O', T = T ma, w = W ma, P = P atm c p = Cp 'AirH2O', T = T ma, w = W ma, P = P atm a) How much heat is added to the air? m sa = CFM ma 60 min v ma hr h sa = h 'AirH2O', T = T sa, w = W ma, P = P atm Q air = m sa h sa h ma Q airt = m sa c p T sa T ma b) If the heat is provided by hot water that enters the coil at 180 F and leaves at 160 F, what is the water flow rate? c WATER = Cp 'Water', T = TW ent, P = P atm
3 File:Psych1HeatCoil.EES 10/21/2003 3:41:39 PM Page 3 m w = Q air c WATER TW ent TW lvg c) If the heat is provided by a steam coil with saturated steam at 250 F, what steam flow rate is required? Assume that the steam leaves the coil as a saturated liquid? hfg steam = h 'Steam', T = T steam, x = 1 h 'Steam', T = T steam, x = 0 m steam = Q air hfg steam Unit Settings: [F]/[psia]/[lbm]/[degrees] CFM ma = 2000 [cfm] c p = [Btu/lb m -R] c WATER = [Btu/lb m -R] hfg steam = [Btu/lbm] h ma = [Btu/lb m ] h sa = [Btu/lb m ] m sa = 9473 [lb m /hr] m steam = [lb m /hr] m w = [lb m /hr] P atm = 14.7 [psia] Q air = [Btu/hr] Q airt = [Btu/hr] TWB ma = 36 [F] TW ent = 180 [F] TW lvg = 160 [F] T ma = 40 [F] T sa = 140 [F] T steam = 250 [F] v ma = [ft 3 /lb m ] W ma = No unit consistency or conversion problems were detected.
4 File:Psych2ZoneHeat.EES 10/21/2003 3:50:04 PM Page 1 "AREN 3010 In-Class Psychrometric Problem #2" "A building space is to be maintained at 70 F dry-bulb and 30% RH when the barometric pressure is psia. The total heating load on the space has been calculated to be 60,000 Btu/hr. Supply air is delivered to the space at a temperature of 120 F " "Given information" P_atm = T_sa = 120 T_ra = 70 RH_ra =.3 Q_heat = Q_fan = 400*CONVERT(W,Btu/hr) "Calculate properties of outdoor and return air" W_ra = HUMRAT(AIRH2O,t=T_ra, r=rh_ra,p=p_atm) v_ra = VOLUME(AIRH2O,t=T_ra, w=w_ra,p=p_atm) v_sa = VOLUME(AIRH2O,t=T_sa, w=w_ra,p=p_atm) c_p = SPECHEAT(AIRH2O,t=T_ra,w=W_ra,p=P_atm) "a) What is the volumetric airflow required for the space?" m_sa=q_heat /(c_p*(t_sa-t_ra)) CFM_sa = m_sa*v_sa/convert(hr,min) CFM_ra = m_sa*v_ra/convert(hr,min) "b) What is the discharge air temperature?" T_da = T_sa-Q_fan/(m_sa*c_p) AREN 3010 In-Class Psychrometric Problem #2 A building space is to be maintained at 70 F dry-bulb and 30% RH when the barometric pressure is psia. The total heating load on the space has been calculated to be 60,000 Btu/hr. Supply air is delivered to the space at a temperature of 120 F
5 File:Psych2ZoneHeat.EES 10/21/2003 3:50:05 PM Page 2 Given information P atm = T sa = 120 T ra = 70 RH ra = 0.3 Q heat = Q fan = Btu/hr W Calculate properties of outdoor and return air W ra = ω 'AirH2O', T = T ra, R = RH ra, P = P atm v ra = v 'AirH2O', T = T ra, w = W ra, P = P atm v sa = v 'AirH2O', T = T sa, w = W ra, P = P atm c p = Cp 'AirH2O', T = T ra, w = W ra, P = P atm a) What is the volumetric airflow required for the space? m sa = Q heat c p T sa T ra CFM sa = m sa v sa 60 min hr CFM ra = m sa v ra 60 min hr b) What is the discharge air temperature? T da = T sa Q fan m sa c p Unit Settings: [F]/[psia]/[lbm]/[degrees] CFM ra = 1110 [cfm] CFM sa = 1214 [cfm] c p = [Btu/lb m -R] m sa = 4949 [lb m /hr] P atm = 14.7 [psia] Q fan = 1365 [Btu/hr] Q heat = [Btu/hr] RH ra = 0.3 T da = [F] T ra = 70 [F] T sa = 120 [F] v ra = [ft 3 /lb m ] v sa = [ft 3 /lb m ] W ra = No unit consistency or conversion problems were detected.
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7 File:Psych3CoolCoil.EES 10/21/ :01:00 PM Page 1 "AREN 3010 In-Class Psychrometric Problem #3" " Moist air enters a cooling coil at 78 F dry-bulb temperature and 50% RH at a rate of 2400 cfm. Barometric pressure is psia. The air leaves the coil at a dry-bulb temperature of 55 F and a dew-point temperature of 53 F. The condensate leaves at a temperature of 52 F. " "Given information" P_atm = T_da = 55 TDP_da = 53 T_ma = 78 RH_ma =.5 CFM_ma = 2400 T_cond = 52 "Calculate properties of mixed and supply air" W_ma = HUMRAT(AIRH2O,t=T_ma, r=rh_ma,p=p_atm) h_ma = ENTHALPY(AIRH2O,t=T_ma, w=w_ma,p=p_atm) v_ma = VOLUME(AIRH2O,t=T_ma, w=w_ma,p=p_atm) W_da = HUMRAT(AIRH2O,t=T_da, d=tdp_da,p=p_atm) h_da = ENTHALPY(AIRH2O,t=T_da, w=w_da,p=p_atm) c_p = SPECHEAT(AIRH2O,t=T_ma,w=W_ma,p=P_atm) "a) What is the total load on the coil?" m_sa = CFM_ma/v_ma*CONVERT(hr,min) h_cond = ENTHALPY(WATER,t=T_cond,p=P_atm) m_cond = m_sa*(w_ma-w_da) Q_totExact = m_sa*(h_ma-h_da)-m_cond*h_cond Q_tot=m_sa*(h_ma-h_da) Error_Q = (Q_tot-Q_totExact)/Q_totExact "b) What is the sensible heat ratio?" Q_sen = m_sa*c_p*(t_ma-t_da) SHR = Q_sen/Q_tot "c) What are the supply air conditions?" Q_fan = 1200*CONVERT(W,Btu/hr)
8 File:Psych3CoolCoil.EES 10/21/ :01:00 PM Page 2 T_sa = T_da+Q_fan/(m_sa*c_p) W_sa = W_da AREN 3010 In-Class Psychrometric Problem #3 Moist air enters a cooling coil at 78 F dry-bulb temperature and 50% RH at a rate of 2400 cfm. Barometric pressure is psia. The air leaves the coil at a dry-bulb temperature of 55 F and a dew-point temperature of 53 F. The condensate leaves at a temperature of 52 F. Given information P atm = T da = 55 TDP da = 53 T ma = 78 RH ma = 0.5 CFM ma = 2400 T cond = 52 Calculate properties of mixed and supply air W ma = ω 'AirH2O', T = T ma, R = RH ma, P = P atm h ma = h 'AirH2O', T = T ma, w = W ma, P = P atm v ma = v 'AirH2O', T = T ma, w = W ma, P = P atm W da = ω 'AirH2O', T = T da, D = TDP da, P = P atm h da = h 'AirH2O', T = T da, w = W da, P = P atm c p = Cp 'AirH2O', T = T ma, w = W ma, P = P atm a) What is the total load on the coil? m sa = CFM ma 60 min v ma hr h cond = h 'Water', T = T cond, P = P atm m cond = m sa W ma W da Q totexact = m sa h ma h da m cond h cond Q tot = m sa h ma h da
9 File:Psych3CoolCoil.EES 10/21/ :01:00 PM Page 3 Error Q = Q tot Q totexact Q totexact b) What is the sensible heat ratio? Q sen = m sa c p T ma T da SHR = Q sen Q tot c) What are the supply air conditions? Q fan = Btu/hr W T sa = T da + Q fan m sa c p W sa = W da Unit Settings: [F]/[psia]/[lbm]/[degrees] CFM ma = 2400 [cfm] c p = [Btu/lb m -R] Error Q = h cond = [Btu/lb m ] h da = [Btu/lb m ] h ma = [Btu/lb m ] m cond = [lb m /hr] m sa = [lb m /hr] P atm = 14.7 [psia] Q fan = 4095 [Btu/hr] Q sen = [Btu/hr] Q tot = [Btu/hr] Q totexact = [Btu/hr] RH ma = 0.5 SHR = TDP da = 53 [F] T cond = 52 T da = 55 [F] T ma = 78 [F] T sa = 56.6 [F] v ma = [ft 3 /lb m ] W da = W ma = W sa = No unit consistency or conversion problems were detected.
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11 File:Psych4Mix.EES 10/21/2003 9:26:57 AM Page 1 "AREN 3010 In-Class Psychrometric Problem #4" " Outdoor air is mixed with building return air in a mixing chamber prior to conditioning. The outdoor air is at 90 F and 40% RH with an airflow of 1000 cfm. The return air is 80 F and 67 F wet-bulb with an airflow rate of 3000 cfm. " "Given information" P_atm = T_ra = 80 TWB_ra = 65 cfm_ra = 3000 T_oa = 90 RH_oa =.4 cfm_oa = 1000 "Calculate properties of outdoor and return air" h_ra = ENTHALPY(AIRH2O,t=T_ra, b=twb_ra,p=p_atm) W_ra = HUMRAT(AIRH2O,t=T_ra, b=twb_ra,p=p_atm) v_ra = VOLUME(AIRH2O,t=T_ra, b=twb_ra,p=p_atm) h_oa = ENTHALPY(AIRH2O,t=T_oa, r=rh_oa,p=p_atm) W_oa = HUMRAT(AIRH2O,t=T_oa, r=rh_oa,p=p_atm) v_oa = VOLUME(AIRH2O,t=T_oa, r=rh_oa,p=p_atm) "What is the mixed air condition?" m_oa = cfm_oa/v_oa*convert(hr,min) m_ra = cfm_ra/v_ra*convert(hr,min) m_ma = m_oa+m_ra OA_frac = m_oa/m_ma h_ma = OA_frac*h_oa + (1-OA_frac)*h_ra W_ma = OA_frac*W_oa + (1-OA_frac)*W_ra T_ma = TEMPERATURE(AIRH2O,h=h_ma,w=W_ma,p=P_atm) v_ma = VOLUME(AIRH2O,T=T_ma,w=W_ma,p=P_atm) cfm_ma = m_ma*v_ma/convert(hr,min) AREN 3010 In-Class Psychrometric Problem #4
12 File:Psych4Mix.EES 10/21/2003 9:26:57 AM Page 2 Outdoor air is mixed with building return air in a mixing chamber prior to conditioning. The outdoor air is at 90 F and 40% RH with an airflow of 1000 cfm. The return air is 80 F and 67 F wet-bulb with an airflow rate of 3000 cfm. Given information P atm = T ra = 80 TWB ra = 65 cfm ra = 3000 T oa = 90 RH oa = 0.4 cfm oa = 1000 Calculate properties of outdoor and return air h ra = h 'AirH2O', T = T ra, B = TWB ra, P = P atm W ra = ω 'AirH2O', T = T ra, B = TWB ra, P = P atm v ra = v 'AirH2O', T = T ra, B = TWB ra, P = P atm h oa = h 'AirH2O', T = T oa, R = RH oa, P = P atm W oa = ω 'AirH2O', T = T oa, R = RH oa, P = P atm v oa = v 'AirH2O', T = T oa, R = RH oa, P = P atm What is the mixed air condition? m oa = m ra = cfm oa 60 min v oa hr cfm ra 60 min v ra hr m ma = m oa + m ra OA frac = m oa m ma h ma = OA frac h oa + 1 OA frac h ra W ma = OA frac W oa + 1 OA frac W ra T ma = T 'AirH2O', h = h ma, w = W ma, P = P atm
13 File:Psych4Mix.EES 10/21/2003 9:26:57 AM Page 3 v ma = v 'AirH2O', T = T ma, w = W ma, P = P atm cfm ma = m ma v ma 60 min hr Unit Settings: [F]/[psia]/[lbm]/[degrees] cfm ma = [cfm] cfm oa = 1000 [cfm] cfm ra = 3000 [cfm] h ma = [Btu/lb m ] h oa = [Btu/lb m ] h ra = [Btu/lb m ] m ma = [lb m /hr] m oa = 4248 [lb m /hr] m ra = [lb m /hr] OA frac = P atm = 14.7 [psia] RH oa = 0.4 TWB ra = 65 [F] T ma = [F] T oa = 90 [F] T ra = 80 [F] v ma = [ft 3 /lb m ] v oa = [ft 3 /lb m ] v ra = [ft 3 /lb m ] W ma = W oa = W ra = No unit consistency or conversion problems were detected.
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15 File:Psych5OneZone.EES 10/21/2003 9:28:52 AM Page 1 "AREN 3010 In-Class Psychrometric Problem #5" " A building space is to be maintained at 78 F dry-bulb and 65 F wet-bulb. The total cooling load on the space has been calculated to be 60,000 Btu/hr of which 42,000 Btu/hr is sensible heat gain. Supply air is delivered to the space at a temperature of 58 F. For acceptable air quality, 500 cfm of outside air is required. Outdoor conditions are 90 F and 50% RH. " "Given information" P_atm = T_sa = 58 T_ra = 78 TWB_ra = 65 T_oa = 90 RH_oa =.5 cfm_oa = 500 Q_sen = Q_tot = "Calculate properties of outdoor and return air" h_ra = ENTHALPY(AIRH2O,t=T_ra, b=twb_ra,p=p_atm) W_ra = HUMRAT(AIRH2O,t=T_ra, b=twb_ra,p=p_atm) h_oa = ENTHALPY(AIRH2O,t=T_oa, r=rh_oa,p=p_atm) W_oa = HUMRAT(AIRH2O,t=T_oa, r=rh_oa,p=p_atm) v_oa = VOLUME(AIRH2O,t=T_oa, r=rh_oa,p=p_atm) c_p = SPECHEAT(AIRH2O,t=T_ra,b=TWB_ra,p=P_atm) "a) What is the airflow required for the space?" m_sa=q_sen /(c_p*(t_ra-t_sa)) "b)what is the supply air humidity ratio?" h_sa = h_ra - Q_tot / m_sa W_sa = HUMRAT(AIRH2O,t=T_sa, h=h_sa,p=p_atm)
16 File:Psych5OneZone.EES 10/21/2003 9:28:53 AM Page 2 "c) What is the capacity of the cooling coil?" m_oa = cfm_oa/v_oa*convert(hr,min) OA_frac = m_oa/m_sa h_ma = OA_frac*h_oa + (1-OA_frac)*h_ra W_ma = OA_frac*W_oa + (1-OA_frac)*W_ra Q_coil = m_sa*(h_ma - h_sa) "d) What is the sensible heat ratio of the cooling coil?" T_ma = TEMPERATURE(AIRH2O,h=h_ma,w=W_ma,p=P_atm) Q_scoil = m_sa*c_p*(t_ma - T_sa) SHR_coil = Q_scoil/Q_coil AREN 3010 In-Class Psychrometric Problem #5 A building space is to be maintained at 78 F dry-bulb and 65 F wet-bulb. The total cooling load on the space has been calculated to be 60,000 Btu/hr of which 42,000 Btu/hr is sensible heat gain. Supply air is delivered to the space at a temperature of 58 F. For acceptable air quality, 500 cfm of outside air is required. Outdoor conditions are 90 F and 50% RH. Given information P atm = T sa = 58 T ra = 78 TWB ra = 65 T oa = 90 RH oa = 0.5 cfm oa = 500 Q sen = Q tot = Calculate properties of outdoor and return air h ra = h 'AirH2O', T = T ra, B = TWB ra, P = P atm W ra = ω 'AirH2O', T = T ra, B = TWB ra, P = P atm h oa = h 'AirH2O', T = T oa, R = RH oa, P = P atm W oa = ω 'AirH2O', T = T oa, R = RH oa, P = P atm v oa = v 'AirH2O', T = T oa, R = RH oa, P = P atm c p = Cp 'AirH2O', T = T ra, B = TWB ra, P = P atm
17 File:Psych5OneZone.EES 10/21/2003 9:28:53 AM Page 3 a) What is the airflow required for the space? m sa = Q sen c p T ra T sa b)what is the supply air humidity ratio? h sa = h ra Q tot m sa W sa = ω 'AirH2O', T = T sa, h = h sa, P = P atm c) What is the capacity of the cooling coil? m oa = cfm oa 60 min v oa hr OA frac = m oa m sa h ma = OA frac h oa + 1 OA frac h ra W ma = OA frac W oa + 1 OA frac W ra Q coil = m sa h ma h sa d) What is the sensible heat ratio of the cooling coil? T ma = T 'AirH2O', h = h ma, w = W ma, P = P atm Q scoil = m sa c p T ma T sa SHR coil = Q scoil Q coil Unit Settings: [F]/[psia]/[lbm]/[degrees] cfm oa = 500 [cfm] c p = [Btu/lb m -R] h ma = [Btu/lb m ] h oa = [Btu/lb m ] h ra = [Btu/lb m ] h sa = [Btu/lb m ] m oa = 2114 [lb m /hr] m sa = 8576 [lb m /hr] OA frac = P atm = 14.7 [psia] Q coil = [Btu/hr] Q scoil = [Btu/hr] Q sen = [Btu/hr] Q tot = [Btu/hr] RH oa = 0.5 SHR coil = TWB ra = 65 [F] T ma = [F] T oa = 90 [F] T ra = 78 [F] T sa = 58 [F] v oa = [ft 3 /lb m ] W ma = W oa = W ra = W sa = No unit consistency or conversion problems were detected.
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19 File:Psych6OneZoneOffDesign.EES 10/21/2003 9:29:37 AM Page 1 "AREN 3010 In-Class Psychrometric Problem #6" " A building space is to be maintained at 78 F dry-bulb temperature. The total cooling load on the space has been calculated to be 30,000 Btu/hr of which 27,000 Btu/hr is sensible heat gain. Supply air is delivered to the space at 58 F and 90% RH. The outdoor air mass flow rate is 25% of the total supply mass flow rate. Outdoor conditions are 80 F and 55% RH. " "Given information" P_atm = T_sa = 58 RH_sa =.90 T_ra = 78 T_oa = 80 RH_oa =.55 OA_frac =.25 Q_sen = Q_tot = "Calculate properties of outdoor and return air" W_sa = HUMRAT(AIRH2O,t=T_sa, r=rh_sa,p=p_atm) h_sa = ENTHALPY(AIRH2O,t=T_sa, w=w_sa,p=p_atm) h_oa = ENTHALPY(AIRH2O,t=T_oa, r=rh_oa,p=p_atm) W_oa = HUMRAT(AIRH2O,t=T_oa, r=rh_oa,p=p_atm) v_oa = VOLUME(AIRH2O,t=T_oa, r=rh_oa,p=p_atm) c_p = SPECHEAT(AIRH2O,t=T_ra,r=.5,p=P_atm) "a) What is the airflow required for the space?" m_sa=q_sen /(c_p*(t_ra-t_sa)) "b)what is the zone air humidity ratio?" h_sa = h_ra - Q_tot / m_sa W_ra = HUMRAT(AIRH2O,t=T_ra, h=h_ra,p=p_atm)
20 File:Psych6OneZoneOffDesign.EES 10/21/2003 9:29:37 AM Page 2 "c) What is the capacity of the cooling coil?" OA_frac = m_oa/m_sa h_ma = OA_frac*h_oa + (1-OA_frac)*h_ra W_ma = OA_frac*W_oa + (1-OA_frac)*W_ra Q_coil = m_sa*(h_ma - h_sa) "d) What is the sensible heat ratio of the cooling coil?" T_ma = TEMPERATURE(AIRH2O,h=h_ma,w=W_ma,p=P_atm) Q_scoil = m_sa*c_p*(t_ma - T_sa) SHR_coil = Q_scoil/Q_coil AREN 3010 In-Class Psychrometric Problem #6 A building space is to be maintained at 78 F dry-bulb temperature. The total cooling load on the space has been calculated to be 30,000 Btu/hr of which 27,000 Btu/hr is sensible heat gain. Supply air is delivered to the space at 58 F and 90% RH. The outdoor air mass flow rate is 25% of the total supply mass flow rate. Outdoor conditions are 80 F and 55% RH. Given information P atm = T sa = 58 RH sa = 0.9 T ra = 78 T oa = 80 RH oa = 0.55 OA frac = 0.25 Q sen = Q tot = Calculate properties of outdoor and return air W sa = ω 'AirH2O', T = T sa, R = RH sa, P = P atm h sa = h 'AirH2O', T = T sa, w = W sa, P = P atm h oa = h 'AirH2O', T = T oa, R = RH oa, P = P atm W oa = ω 'AirH2O', T = T oa, R = RH oa, P = P atm v oa = v 'AirH2O', T = T oa, R = RH oa, P = P atm c p = Cp 'AirH2O', T = T ra, R = 0.5, P = P atm a) What is the airflow required for the space?
21 File:Psych6OneZoneOffDesign.EES 10/21/2003 9:29:38 AM Page 3 m sa = Q sen c p T ra T sa b)what is the zone air humidity ratio? h sa = h ra Q tot m sa W ra = ω 'AirH2O', T = T ra, h = h ra, P = P atm c) What is the capacity of the cooling coil? OA frac = m oa m sa h ma = OA frac h oa + 1 OA frac h ra W ma = OA frac W oa + 1 OA frac W ra Q coil = m sa h ma h sa d) What is the sensible heat ratio of the cooling coil? T ma = T 'AirH2O', h = h ma, w = W ma, P = P atm Q scoil = m sa c p T ma T sa SHR coil = Q scoil Q coil Unit Settings: [F]/[psia]/[lbm]/[degrees] c p = [Btu/lb m -R] h ma = [Btu/lb m ] h oa = [Btu/lb m ] h ra = 29.4 [Btu/lb m ] h sa = [Btu/lb m ] m oa = 1378 [lb m /hr] m sa = 5513 [lb m /hr] OA frac = 0.25 P atm = 14.7 [psia] Q coil = [Btu/hr] Q scoil = [Btu/hr] Q sen = [Btu/hr] Q tot = [Btu/hr] RH oa = 0.55 RH sa = 0.9 SHR coil = T ma = 78.5 [F] T oa = 80 [F] T ra = 78 [F] T sa = 58 [F] v oa = [ft 3 /lb m ] W ma = W oa = W ra = W sa = No unit consistency or conversion problems were detected.
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