Pythagoras Theorem. Pythagoras

Size: px
Start display at page:

Download "Pythagoras Theorem. Pythagoras"

Transcription

1 11 Pythgors Theorem Pythgors Theorem. onverse of Pythgors theorem. Pythgoren triplets Proof of Pythgors theorem nd its converse Problems nd riders bsed on Pythgors theorem. This unit fcilittes you in, stting Pythgors theorem proving Pythgors theorem logiclly. stting converse of Pythgo rs theorem. pro ving converse of Pythgo rs theorem logiclly. explining the mening of Pythgoren triplets. resoning deductively nd prove the riders bsed on Pythgors theorem nd its converse. nlysing nd solving rel life problems bsed on pythgors theorem. Pythgors ( , Greece) Pythgors, pupil of Thles is perhps best known for the theorem on right ngled tringle which bers his nme. He helped to devlop the study of geometry in logicl wy by using undefined terms, definitions, postultes nd logicl deductions. The influence of his school in the fields of mthemtics, science, music, religio n nd philosophy is pprent even tody. There is geometry in the humming of the strings, there is music in the spcing of spheres. -Pythgors

2 70 UNIT-11 Let us recll some of the properties of right ngled tringle which we hve lredy lernt. 1. The side opposite to right ngle is clled hypotenuse.. In right ngled tringle, hypotenuse is the longest side. 3. In n isosceles right ngled tringle, ech cute ngle is 5.. re of right ngled tringle is hlf the product of the sides contining the right ngle. 5. The perpendiculr drwn from the right ngled vertex to the hypotenuse divides the tringle into two similr tringles which re similr to the given right ngled tringle. Now, let us lern one more very interesting property bout right ngled tringles. To understnd the property, do the following ctivity. Hypotenuse onstruct with = cm, = 3cm, = 5cm. Observe tht will be exctly 90. onstruct squres on ll the three sides nd divide them into squres of sides 1cm ech. Now, count the number of smll squres on ll the three sides. They re 9, 16 nd 5. If we dd 9 nd 16, we get 5. Repet this ctivity for right ngled tringles with sides, {6cm, 8cm nd 10cm}, {5cm, 1cm, 13cm} etc. Wht do we infer from this? We cn infer tht, "In right ngled tringle, the squre on the hypotenuse is equl to the sum of the squres on the other two sides". This sttement which gives the reltionship between res of sides of right ngled tringle is clled Pythgors theorem, nmed fter the Greek mthemticin Pythgors, who lived round 500. This theorem which is used in mny brnches of mthemtics hs ttrcted the ttention of mny mthemticins nd tody we hve hundreds of vrieties of proofs for it. The sttement of Pythgors theorem cn be proved prcticlly by nother wy. This ws given by Henry Perigl (1830). Hence, it is clled Perigl dissection. Study the ctivity given below nd do it in groups. onstruct, right ngled t on crd bord s shown in the figure. rw squres on, nd. In these squres, do the constructions s shown in the figure nd steps mentioned below. Mrk the middle point (P) of the squre drwn on the longest side contining the right ngle, i.e.. (This cn be obtined by joining the digonls of the squre) Through P drw E nd FG E. cm cm cm 3 cm cm 5 c 3 cm 3 cm P 5 cm m 3 cm 5 cm 5 cm

3 Pythgors Theorem 71 Mrk the qudrilterls formed s 1,,3 nd, nd the squre on s 5. (Observe the figure) ut the qudrilterls 1,,3,, nd 5. rrnge them on the squre drwn on the hypotenuse. (observe the figure) Wht conclusion we cn drw bout the res of the squres on sides of the right ngled tringle? Pythgors Theorem In right ngled tringle, the squre on the hypotenuse is equl to the sum of the squres on the other two sides. t : In, = 90 To Prove : + = onstruction : rw. Proof : Sttement Reson ompre nd, 90 ( t nd construction) is common. ( Equingulr tringles) = =....(1) ompre nd, ( similrity criteri) 90 ( t nd construction) is common [ Equingulr Tringles] y dding (1) nd () we get + + =....() = (. ) + (. ) = ( + ) [ similrity criteri] + =. = [ + = ) + = QE

4 7 UNIT-11 Know this! udhyn, n ncient Indin mthemticin in his Shulv sutrs composed during 800 sttes tht, "The digonl of rectngle produces both res of which its length nd bredth produce seprtely". d = l + b For this reson, this theorem is lso referred to s the 'udhyn Theorem'. l b d b l lternte proof for Pythgors theorem using re of trpezium t : In, 90 To prove : + c = b onstruction : Extend to such tht, =. t, drw nd mrk point E on it such tht, Join E, nd E,. E =. Proof : Sttement Reson c b c E ompre nd E = ( onstruction) = E 90 ( t nd construction) = E ( onstruction) E ( SS) 1) = E [ PT] ) = E nd 3) = E In, + = 90 [ = E ] E + = 90 [ djcent ngles of liner pir] E = 90

5 Pythgors Theorem 73 re of E = re of + re of E + re of E ½( + c)( + c) = ½c + ½b + ½c ( + c) = c + b [by cncelling 1 throughout] + c + c = c + b + c = b QE Know this To-dy we hve vrieties of proofs for Pythgors Theorem. It is sid tht there re more thn 300 proofs, some of them re proved bsed on trigonometry, co-ordinte geometry, vectors etc. Try to collect some of them nd discuss in groups. ILLUSTRTIVE EXMPLES Numericl problems bsed on Pythgors theorem Exmple 1: In right ngled, = 90, = 17cm nd = 8cm, find. Sol. Given, in, 90 Exmple : In, = + Pythgors theorem] = - = 17-8 = 89-6 = 5 = 5 15cm = 5, M, M = cm nd = 7cm. Find the length of. Sol. In M, M 90, M 5 M 5 8cm 17cm? M is n isosceles right ngled tringle M = M = cm M = M = 7 = 3cm M = 3cm In M, = M + M [ Pythgors theorem] = + 3 = = 5 = 5 5cm

6 7 UNIT-11 Exmple 3 : In the rectngle WXYZ, XY + YZ = 17cm nd XZ + YW = 6 cm, clculte the length nd bredth of the rectngle. Sol. XZ + YW = 6 cm d 1 + d = 6 cm d = 6cm [ d 1 = d ] d XZ = 13 cm = YW = 13cm Let length = XY = x cm bredth = XW = (17 x)cm W X Z Y In WXY, WX + XY = WY [ pythgors theorem] (17 x) + x = 13 (89 3x + x ) + x = 169 (x 3x + 10 = 0) x 17x + 60 = 0 x 1x 5x + 60 = 0 x(x 1) 5(x 1) = 0 (x 1)(x 5) = 0 x 1 = 0 or x 5 = 0 Length x = 1 or x = 5 = 1cm, bredth = 5cm Exmple : In the, the hypotenuse is greter thn one of the other side by units nd it is twice greter thn the nother side by 1 unit. Find the mesure of the sides. Sol. Let = x nd = y = x + or = y + 1 x + = y + 1 x + 1 = y x 1 = y + = Pythgors theorem) x + y = (y + 1) x 1 x = y + y + 1 x x 1 x = x 1 x 1 1 x ( + ) x or ( + 1) y y

7 Pythgors Theorem 75 1 x x x = ( 1) ( 1) x x x x + x + x + 1 = (x + x + 1) + (x + ) + x + x + x + 1 = x + 8x + + 8x x + x 16x = 0 Exmple 5 : Sol. x 1x 15 = 0 (x 15)(x + 1) = 0 x =15 or x = 1 If x = 15, x + = 17 nd y = x = 15 units, = 8 units, = 17 units. n insect 8 m wy from the foot of lmp post which is 6m tll, crwls towrds it. fter moving through distnce, its distnce from the top of the lmp post is equl to the distnce it hs moved. How fr is the insect wy from the foot of the lmp post? [hskrchry's Leelvthi] istnce between the insect nd the foot of the lmp post = = 8m. The height of the lmp post = = 6m. fter moving distnce, let the insect be t, Let = = x m. = (8 - x) m. In, =x 8-x x = + ( Pythgors theorem) x = 6 + ( 8- x) x = x + x 16x = 100 x = = 8 x = (8 6.5) = 1.75 m The insect is 1.75 m. wy from the foot of the lmp post. Note : We cn lso consider = x, then = = (8 x) =

8 76 UNIT-11 Riders bsed on Pythgors Theorem. Exmple 6 : In the given figure,, Prove tht + = + Sol. In, 90 = + ( Pythgors theorem)...(1) In 90 = + ( Pythgors theorem)...() Subtrcting (1) from (), we get Exmple 7 : In, (i) = = - + = + = 60 (ii). erive n expression for in terms of nd. Sol. onst: rw E such tht E 60 E is n equilterl [ t nd construction] E = = E E is n isosceles E 10 nd E 30 E E = E = E = E [ xiom - 1] = Now in, = + [ pythgors theorem] = ( ) + ( ) [ pythgors theorem] = +. + [ = ] = +. =. + = ( ) + = ( ) + [ = ) =. + or = +. y this we hve expressed interms of nd only. Exmple 8 : erive the formul for height nd re of n equilterl tringle. Sol. In the equilterl, let = = = '' units. rw Let = 'h' units

9 Pythgors Theorem 77 = = = [ RHS theorem] Now there re two right ngled tringles, nd. In, = 90 [ ] = + [ Pythgors theorem] = h + = h + = h 1 = h 3 = h Tke squre root on either sides = h = h h= 3 3 Height of n equilterl tringle of side units, h = Let us now find the re of equilterl. re of = 1 bse height = 1 3 = 3 re of n equilterl tringle, = 3

10 78 UNIT-11 Exmple 9 : Equilterl tringles re drwn on the sides of right ngled tringle. Show tht the re of the tringle on the hypotenuse is equl to sum of the re of tringles on the other two sides. Sol. t : In, 90 To prove : Equilterl les P, Q nd R re drwn on sides, nd respectively. re ( P) + re ( Q) = re ( R) Proof : P Q R [ Equingulr les re similr] P 3x x 3 + y 3 y Q x y x y R onsider re ( P) re ( R) re( Q) re ( R) re( P) re( Q) re( R) = re ( P) re( Q) re( R) = [ Theorem] [ pythgors theorem = + ] re ( P) re( Q) re( R) = 1 re ( P) + re ( Q) = re ( R) lternte Proof : P + Q = x y x y Exmple 10 : 3 3 R = x y x y P + Q = R In, is point on such tht : = 1 : nd is n equilterl tringle Prove tht = 7 Sol. t: In, : = 1 : In, = = To Prove: = 7 onstruction: Proof: rw E In, E = E = nd E = 3 3 re of equilterl le= side 3 E

11 Pythgors Theorem 79 In E, E 90 [ onstruction] = E + E [ Pythgors theorem] = = = = = = 7 = 7 EXERISE 11.1 Numericl problems bsed on Pythgors theorem. 1. The sides of right ngled tringle contining the right ngle re 5cm nd 1cm, find its hypotenuse.. Find the length of the digonl of squre of side 1cm. 3. The length of the digonl of rectngulr plyground is 15m nd the length of one side is 75m. Find the length of the other side. L. In LW, LW 90, LN 90 nd LW = 6cm, LN = 6cm nd N = 8 cm. lculte the length of W. 6 cm N 8cm 6cm 5. door of width 6 meter hs n rch bove it hving height of meter. Find the rdius of the rch. W h = m 6m 6. The sides of right ngled tringle re in n rithmetic progression. Show tht the sides re in the rtio. 3 : : pecock on pillr of 9 feet height on seeing snke coming towrds its hole situted just below the pillr from distnce of 7 feet wy from the pillr will fly to ctch it. If both posess the sme speed, how fr from the pillr they re going to meet?

12 80 UNIT-11 Riders bsed on Pythgors theorem. M 8. In MGN, MP GN. If MG = units, MN = b units, GP = c units nd PN = d units. b Prove tht ( + b)( b) = (c + d)(c d). G c P d N 9. In L, L 90 nd LM L Prove tht L L M M 10. In, = 90 0,. If = 'c' units, = '' units, = 'p' units, = 'b' units Prove tht c p. c p b M Pythgoren triplets You hve lernt tht the mesures of three sides of right ngled tringle re relted in specil wy. If the three numbers, which re the mesures of three sides of right ngled tringle re nturl numbers then they re clled Pythgoren triplets. Some of them re listed in the tble given below. study them. 3,, 5 6, 8, 10 5, 1, 13 15, 36, 39 7,, 5 1, 8, 50 11, 60, 61, 0, ompre ech of the Pythgoren triplets in column with the corresponding triplet in column. We cn conclude tht; if ( x, y, z) is py thgore n triplet, then (kx, ky, kz) is lso Pythgoren triplet where k N. Know this! Pythgoren triplets cn be found using the following generl form. For nturl number: n, (n 1), (n + 1) Here 'n' my be even or odd. 1 For odd nturl numbers: n, ( 1), n 1 ( n 1), Here n is odd where n N. From the bove generl forms ny number of pythgoren triplets cn be generted by giving vlues to 'n'.

13 Pythgors Theorem 81 We hve lernt tht squre number cn be equl to sum of two squre numbers. oes this type of reltionship pply to cubes or other powers? Know this! Fermt's lst theorem [Pierre de Fermt ( ), French mthemticin] "It is impossible to write - cube s the sum of two cubes. - fourth power s the sum of fourth powers" or In generl, "it is impossible to write ny power beyond the second s the sum of two similr powers." There re no, b, c, N for which n + b n = c n where n N nd n > ndrew Wiles (orn in cmbridge, Englnd ) sw this problem, when he ws ten yers old. Thirty yers lter nd with seven yers of intense work ndrew wiles, proved Fermt's lst theorem. onverse of Pythgors Theorem Let us now lern the converse of pythgors theorem. For this, consider the two exmples. Exmple 1 cm 3 cm Exmple cm P.3 cm Let be tring le with = 5cm, = cm nd = 3cm. Imgine squres on ll the three sides nd find their res. Here, the longest side is nd its length is 5cm. The re of the squre on the longest side is 5 sq. cm The sum of the squres on the other two sides nd will be (16 + 9) sq cm which is lso 5 sq. cm. Now mesure which is opposite to the longest side. you will find tht = cm So, is right ngled tringle, right ngled t the vertex. Q 5 cm R Let PQR be nother tringle with QR = 5cm, PQ = cm nd PR =.3 cm. Imgine squres on ll the three sides nd find their res. Here, the longest side is QR nd its length is 5 cm. The re of the squre on the longest side QR is 5 sq. cm. The sum of the squres on the other two sides PQ nd PR will be ( ) sq cm = 3.9 sq. cm which is not equl to the re of the squre on the longest side QR. Now mesure QPR which is opposite to the longest side QR, you will find tht QPR=7 but not 90. So, PQR is not right ngled tringle.

14 8 UNIT-11 So, wht is the bsic condition for tringle to be right ngled tringle? ompre the res on the sides of two tringles in the bove exmples nd try to figure out the necessry condtion. The condition is: "If the squre on the longest side of tringle is equl to the sum of the squres on the other two sides then those two sides contin right ngle." This is converse of Pythgors theorem. It ws first mentioned nd proved by Euclid. Now let us prove the converse of Pythgors theorem logiclly. onverse of pythgors theorem "If the squre on the longest side of tringle is equl to the sum of the squres on the other two sides, then those two sides contin right ngle." t : In, = + To prove : = 90 onstruction : rw perpendiculr on t. Select point on it such tht, =. Join '' nd ''. Sttement Reson Proof : In, = 90 ( onstruction) = + ( Pythgors theorem) ut in, = + ( t) = = ompre nd = = is common ( Proved) ( onstruction) ( SSS) = ( PT) = = 90 QE

15 Pythgors Theorem 83 omprision of Pythgors theorem nd its converse. Pythgors theorem "In right ngled tringle, the squre on the hypotenuse is equl to the sum of the squres on the other two sides. onverse of Pythgors theorem "If the squre on the longest side of tringle is equl to the sum of the squres on the other two sides, then those two sides contin right ngle." t: In, = 90 To prove: = + t: In, = + To prove: = 90 Now observe the following tble. Study the reltionship between the res of three sides of tringle. c b c b c b In, = 90 = + b = c + * In, < 90 < + b < c + * In, > 90 > + b > c + onverse If b = c + then = 90 If b < c + then < 90 If b > c + then > 90 iscuss The Pythgors theorem hs two fundmentl spects, where one is bout res nd the other is bout lengths. This lndmrk theorem connects two min brnches of mthemtics - Geometry nd lgebr.

16 8 UNIT-11 ILLUSTRTIVE EXMPLES Exmple1 : Verify whether the following mesures represent the sides of right ngled tringle. () 6, 8, 10 Sol. Sides re : 6, 8, 10 onsider the res of squre on the sides : 6, 8, 10 i.e., 36, 6, 100 onsider the sum of res of squres on the two smller sides : = = 10 We observe tht, squre on the longest side of the tringle is equl to the sum of squres on the other two sides. y converse of Pythgors theorem, those two smller sides must contin right ngle. onclusion: The sides 6, 8 nd 10 form the sides of right ngled tringle with hypotenuse 10 units nd 6 nd 8 units s the sides contining the right ngle. Note: Without ctully constructing the tringle for the given mesurements of sides it is now possible to sy whether the sides represent the sides of right ngled tringle using converse of Pythgors theorem. (b) 1,, 3 Sides re : 1, 3, onsider the res of squres on the sides : 1, 3, i.e., : 1, 3, onsider the sum of the res of squres on the two smller sides : = = We observe tht the squre on the longest side ( units) is equl to the sum of the squres on the other two sides. y converse of pythgors Theorem, these two smller sides must contin right ngle. onclusion: 1,, hypotenuse nd 1 nd (c), 5, 6 3 forms the sides of right ngled tringle with units s 3 units s sides contining the right ngle. Sides re :, 5, 6 res of squres on the sides :, 5, 6 i.e., : 16, 5, 36

17 Pythgors Theorem 85 Sum of res of squres on the two smller sides : = We observe tht the squre on the longest side of the tringle is not equl to the sum of the squres on the other two sides. y converse of Pythgors theorem, these two sides cnnot contin right ngle. Hence,, 5, nd 6 cnnot form the sides of right ngled tringle. Exmple : In the qudrilterl, 90 nd = ( + + ). Prove tht : 90 Proof: In, 90 [ t] = + [ Pythgors theorem] ut = ( + )+ [ t] = + [ by dt + = ] = 90 [ converse of Pythgors theorem] EXERISE Verify whether the following mesures represent the sides of right ngled tringle. (), 3, 5 (b) 6 3, 1, 6 (c) n, n 1, n 1 (d) x 1, x, x + 1 (e) x 1 x 1,, x (f) m n, mn, m + n. In, + b = 18 units, b + c = 5 units nd c + = 17 units. Wht type of tringle is? Give reson. c b

18 86 UNIT In,, = nd = 3, Prove tht 90.. The shortest distnce P from point '' to QR is 1 cm. Q nd R re respectively 15 cm nd 0cm from '' nd on opposite sides of P. Prove tht QR cm 1 cm 0 cm 5. In the isosceles, =, = 18 cm,, = 1 cm, is produced to 'E' nd E = 0cm. P 1 cm 0 cm R Prove tht E cm E 6. In the qudrilterl, 90, = 9cm, = = 6cm nd = 3cm, Prove tht cm 6 cm 6 cm 9 cm P 7. is rectngle. 'P' is ny point outside it such tht P + P = +. Prove tht P 90 Pythgors theorem Sttement of Pythgors theorem onverse of Pythgors theorem Pythgoren triplets Logicl proof Riders EXERISE 11.1 NSWERS 1] 13 cm ]1 cm 3] 100m ] cm 5] 3.5m 6] 3: : 5 7] 1 ft

6.2 The Pythagorean Theorems

6.2 The Pythagorean Theorems PythgorenTheorems20052006.nb 1 6.2 The Pythgoren Theorems One of the best known theorems in geometry (nd ll of mthemtics for tht mtter) is the Pythgoren Theorem. You hve probbly lredy worked with this

More information

GEOMETRICAL PROPERTIES OF ANGLES AND CIRCLES, ANGLES PROPERTIES OF TRIANGLES, QUADRILATERALS AND POLYGONS:

GEOMETRICAL PROPERTIES OF ANGLES AND CIRCLES, ANGLES PROPERTIES OF TRIANGLES, QUADRILATERALS AND POLYGONS: GEOMETRICL PROPERTIES OF NGLES ND CIRCLES, NGLES PROPERTIES OF TRINGLES, QUDRILTERLS ND POLYGONS: 1.1 TYPES OF NGLES: CUTE NGLE RIGHT NGLE OTUSE NGLE STRIGHT NGLE REFLEX NGLE 40 0 4 0 90 0 156 0 180 0

More information

3.1 Review of Sine, Cosine and Tangent for Right Angles

3.1 Review of Sine, Cosine and Tangent for Right Angles Foundtions of Mth 11 Section 3.1 Review of Sine, osine nd Tngent for Right Tringles 125 3.1 Review of Sine, osine nd Tngent for Right ngles The word trigonometry is derived from the Greek words trigon,

More information

Is there an easy way to find examples of such triples? Why yes! Just look at an ordinary multiplication table to find them!

Is there an easy way to find examples of such triples? Why yes! Just look at an ordinary multiplication table to find them! PUSHING PYTHAGORAS 009 Jmes Tnton A triple of integers ( bc,, ) is clled Pythgoren triple if exmple, some clssic triples re ( 3,4,5 ), ( 5,1,13 ), ( ) fond of ( 0,1,9 ) nd ( 119,10,169 ). + b = c. For

More information

Similarity and Congruence

Similarity and Congruence Similrity nd ongruence urriculum Redy MMG: 201, 220, 221, 243, 244 www.mthletics.com SIMILRITY N ONGRUN If two shpes re congruent, it mens thy re equl in every wy ll their corresponding sides nd ngles

More information

THE NUMBER CONCEPT IN GREEK MATHEMATICS SPRING 2009

THE NUMBER CONCEPT IN GREEK MATHEMATICS SPRING 2009 THE NUMBER CONCEPT IN GREEK MATHEMATICS SPRING 2009 0.1. VII, Definition 1. A unit is tht by virtue of which ech of the things tht exist is clled one. 0.2. VII, Definition 2. A number is multitude composed

More information

SUMMER KNOWHOW STUDY AND LEARNING CENTRE

SUMMER KNOWHOW STUDY AND LEARNING CENTRE SUMMER KNOWHOW STUDY AND LEARNING CENTRE Indices & Logrithms 2 Contents Indices.2 Frctionl Indices.4 Logrithms 6 Exponentil equtions. Simplifying Surds 13 Opertions on Surds..16 Scientific Nottion..18

More information

20 MATHEMATICS POLYNOMIALS

20 MATHEMATICS POLYNOMIALS 0 MATHEMATICS POLYNOMIALS.1 Introduction In Clss IX, you hve studied polynomils in one vrible nd their degrees. Recll tht if p(x) is polynomil in x, the highest power of x in p(x) is clled the degree of

More information

Comparing the Pre-image and Image of a Dilation

Comparing the Pre-image and Image of a Dilation hpter Summry Key Terms Postultes nd Theorems similr tringles (.1) inluded ngle (.2) inluded side (.2) geometri men (.) indiret mesurement (.6) ngle-ngle Similrity Theorem (.2) Side-Side-Side Similrity

More information

THE KENNESAW STATE UNIVERSITY HIGH SCHOOL MATHEMATICS COMPETITION PART I MULTIPLE CHOICE NO CALCULATORS 90 MINUTES

THE KENNESAW STATE UNIVERSITY HIGH SCHOOL MATHEMATICS COMPETITION PART I MULTIPLE CHOICE NO CALCULATORS 90 MINUTES THE 08 09 KENNESW STTE UNIVERSITY HIGH SHOOL MTHEMTIS OMPETITION PRT I MULTIPLE HOIE For ech of the following questions, crefully blcken the pproprite box on the nswer sheet with # pencil. o not fold,

More information

Coimisiún na Scrúduithe Stáit State Examinations Commission

Coimisiún na Scrúduithe Stáit State Examinations Commission M 30 Coimisiún n Scrúduithe Stáit Stte Exmintions Commission LEAVING CERTIFICATE EXAMINATION, 005 MATHEMATICS HIGHER LEVEL PAPER ( 300 mrks ) MONDAY, 3 JUNE MORNING, 9:30 to :00 Attempt FIVE questions

More information

a < a+ x < a+2 x < < a+n x = b, n A i n f(x i ) x. i=1 i=1

a < a+ x < a+2 x < < a+n x = b, n A i n f(x i ) x. i=1 i=1 Mth 33 Volume Stewrt 5.2 Geometry of integrls. In this section, we will lern how to compute volumes using integrls defined by slice nlysis. First, we recll from Clculus I how to compute res. Given the

More information

Intermediate Math Circles Wednesday 17 October 2012 Geometry II: Side Lengths

Intermediate Math Circles Wednesday 17 October 2012 Geometry II: Side Lengths Intermedite Mth Cirles Wednesdy 17 Otoer 01 Geometry II: Side Lengths Lst week we disussed vrious ngle properties. As we progressed through the evening, we proved mny results. This week, we will look t

More information

STRAND J: TRANSFORMATIONS, VECTORS and MATRICES

STRAND J: TRANSFORMATIONS, VECTORS and MATRICES Mthemtics SKE: STRN J STRN J: TRNSFORMTIONS, VETORS nd MTRIES J3 Vectors Text ontents Section J3.1 Vectors nd Sclrs * J3. Vectors nd Geometry Mthemtics SKE: STRN J J3 Vectors J3.1 Vectors nd Sclrs Vectors

More information

MTH 4-16a Trigonometry

MTH 4-16a Trigonometry MTH 4-16 Trigonometry Level 4 [UNIT 5 REVISION SECTION ] I cn identify the opposite, djcent nd hypotenuse sides on right-ngled tringle. Identify the opposite, djcent nd hypotenuse in the following right-ngled

More information

The Fundamental Theorem of Calculus. The Total Change Theorem and the Area Under a Curve.

The Fundamental Theorem of Calculus. The Total Change Theorem and the Area Under a Curve. Clculus Li Vs The Fundmentl Theorem of Clculus. The Totl Chnge Theorem nd the Are Under Curve. Recll the following fct from Clculus course. If continuous function f(x) represents the rte of chnge of F

More information

Goals: Determine how to calculate the area described by a function. Define the definite integral. Explore the relationship between the definite

Goals: Determine how to calculate the area described by a function. Define the definite integral. Explore the relationship between the definite Unit #8 : The Integrl Gols: Determine how to clculte the re described by function. Define the definite integrl. Eplore the reltionship between the definite integrl nd re. Eplore wys to estimte the definite

More information

MATH STUDENT BOOK. 10th Grade Unit 5

MATH STUDENT BOOK. 10th Grade Unit 5 MATH STUDENT BOOK 10th Grde Unit 5 Unit 5 Similr Polygons MATH 1005 Similr Polygons INTRODUCTION 3 1. PRINCIPLES OF ALGEBRA 5 RATIOS AND PROPORTIONS 5 PROPERTIES OF PROPORTIONS 11 SELF TEST 1 16 2. SIMILARITY

More information

Shape and measurement

Shape and measurement C H A P T E R 5 Shpe nd mesurement Wht is Pythgors theorem? How do we use Pythgors theorem? How do we find the perimeter of shpe? How do we find the re of shpe? How do we find the volume of shpe? How do

More information

GEOMETRY OF THE CIRCLE TANGENTS & SECANTS

GEOMETRY OF THE CIRCLE TANGENTS & SECANTS Geometry Of The ircle Tngents & Secnts GEOMETRY OF THE IRLE TNGENTS & SENTS www.mthletics.com.u Tngents TNGENTS nd N Secnts SENTS Tngents nd secnts re lines tht strt outside circle. Tngent touches the

More information

青藜苑教育 The digrm shows the position of ferry siling between Folkestone nd lis. The ferry is t X. X 4km The pos

青藜苑教育 The digrm shows the position of ferry siling between Folkestone nd lis. The ferry is t X. X 4km The pos 青藜苑教育 www.thetopedu.com 010-6895997 1301951457 Revision Topic 9: Pythgors Theorem Pythgors Theorem Pythgors Theorem llows you to work out the length of sides in right-ngled tringle. c The side opposite

More information

MORE FUNCTION GRAPHING; OPTIMIZATION. (Last edited October 28, 2013 at 11:09pm.)

MORE FUNCTION GRAPHING; OPTIMIZATION. (Last edited October 28, 2013 at 11:09pm.) MORE FUNCTION GRAPHING; OPTIMIZATION FRI, OCT 25, 203 (Lst edited October 28, 203 t :09pm.) Exercise. Let n be n rbitrry positive integer. Give n exmple of function with exctly n verticl symptotes. Give

More information

Sect 10.2 Trigonometric Ratios

Sect 10.2 Trigonometric Ratios 86 Sect 0. Trigonometric Rtios Objective : Understnding djcent, Hypotenuse, nd Opposite sides of n cute ngle in right tringle. In right tringle, the otenuse is lwys the longest side; it is the side opposite

More information

Answers: ( HKMO Heat Events) Created by: Mr. Francis Hung Last updated: 15 December 2017

Answers: ( HKMO Heat Events) Created by: Mr. Francis Hung Last updated: 15 December 2017 Answers: (0- HKMO Het Events) reted y: Mr. Frncis Hung Lst updted: 5 Decemer 07 - Individul - Group Individul Events 6 80 0 4 5 5 0 6 4 7 8 5 9 9 0 9 609 4 808 5 0 6 6 7 6 8 0 9 67 0 0 I Simplify 94 0.

More information

PYTHAGORAS THEOREM WHAT S IN CHAPTER 1? IN THIS CHAPTER YOU WILL:

PYTHAGORAS THEOREM WHAT S IN CHAPTER 1? IN THIS CHAPTER YOU WILL: PYTHAGORAS THEOREM 1 WHAT S IN CHAPTER 1? 1 01 Squres, squre roots nd surds 1 02 Pythgors theorem 1 03 Finding the hypotenuse 1 04 Finding shorter side 1 05 Mixed prolems 1 06 Testing for right-ngled tringles

More information

1 cos. cos cos cos cos MAT 126H Solutions Take-Home Exam 4. Problem 1

1 cos. cos cos cos cos MAT 126H Solutions Take-Home Exam 4. Problem 1 MAT 16H Solutions Tke-Home Exm 4 Problem 1 ) & b) Using the hlf-ngle formul for cosine, we get: 1 cos 1 4 4 cos cos 8 4 nd 1 8 cos cos 16 4 c) Using the hlf-ngle formul for tngent, we get: cot ( 3π 1 )

More information

Part I: Study the theorem statement.

Part I: Study the theorem statement. Nme 1 Nme 2 Nme 3 A STUDY OF PYTHAGORAS THEOREM Instrutions: Together in groups of 2 or 3, fill out the following worksheet. You my lift nswers from the reding, or nswer on your own. Turn in one pket for

More information

Properties of Integrals, Indefinite Integrals. Goals: Definition of the Definite Integral Integral Calculations using Antiderivatives

Properties of Integrals, Indefinite Integrals. Goals: Definition of the Definite Integral Integral Calculations using Antiderivatives Block #6: Properties of Integrls, Indefinite Integrls Gols: Definition of the Definite Integrl Integrl Clcultions using Antiderivtives Properties of Integrls The Indefinite Integrl 1 Riemnn Sums - 1 Riemnn

More information

Triangles The following examples explore aspects of triangles:

Triangles The following examples explore aspects of triangles: Tringles The following exmples explore spects of tringles: xmple 1: ltitude of right ngled tringle + xmple : tringle ltitude of the symmetricl ltitude of n isosceles x x - 4 +x xmple 3: ltitude of the

More information

I1.1 Pythagoras' Theorem. I1.2 Further Work With Pythagoras' Theorem. I1.3 Sine, Cosine and Tangent. I1.4 Finding Lengths in Right Angled Triangles

I1.1 Pythagoras' Theorem. I1.2 Further Work With Pythagoras' Theorem. I1.3 Sine, Cosine and Tangent. I1.4 Finding Lengths in Right Angled Triangles UNIT I1 Pythgors' Theorem nd Trigonometric Rtios: Tet STRAND I: Geometry nd Trigonometry I1 Pythgors' Theorem nd Trigonometric Rtios Tet Contents Section I1.1 Pythgors' Theorem I1. Further Work With Pythgors'

More information

1 PYTHAGORAS THEOREM 1. Given a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

1 PYTHAGORAS THEOREM 1. Given a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. 1 PYTHAGORAS THEOREM 1 1 Pythgors Theorem In this setion we will present geometri proof of the fmous theorem of Pythgors. Given right ngled tringle, the squre of the hypotenuse is equl to the sum of the

More information

15 - TRIGONOMETRY Page 1 ( Answers at the end of all questions )

15 - TRIGONOMETRY Page 1 ( Answers at the end of all questions ) - TRIGONOMETRY Pge P ( ) In tringle PQR, R =. If tn b c = 0, 0, then Q nd tn re the roots of the eqution = b c c = b b = c b = c [ AIEEE 00 ] ( ) In tringle ABC, let C =. If r is the inrdius nd R is the

More information

Definite integral. Mathematics FRDIS MENDELU

Definite integral. Mathematics FRDIS MENDELU Definite integrl Mthemtics FRDIS MENDELU Simon Fišnrová Brno 1 Motivtion - re under curve Suppose, for simplicity, tht y = f(x) is nonnegtive nd continuous function defined on [, b]. Wht is the re of the

More information

Problem Set 9. Figure 1: Diagram. This picture is a rough sketch of the 4 parabolas that give us the area that we need to find. The equations are:

Problem Set 9. Figure 1: Diagram. This picture is a rough sketch of the 4 parabolas that give us the area that we need to find. The equations are: (x + y ) = y + (x + y ) = x + Problem Set 9 Discussion: Nov., Nov. 8, Nov. (on probbility nd binomil coefficients) The nme fter the problem is the designted writer of the solution of tht problem. (No one

More information

8Similarity UNCORRECTED PAGE PROOFS. 8.1 Kick off with CAS 8.2 Similar objects 8.3 Linear scale factors. 8.4 Area and volume scale factors 8.

8Similarity UNCORRECTED PAGE PROOFS. 8.1 Kick off with CAS 8.2 Similar objects 8.3 Linear scale factors. 8.4 Area and volume scale factors 8. 8.1 Kick off with S 8. Similr ojects 8. Liner scle fctors 8Similrity 8. re nd volume scle fctors 8. Review U N O R R E TE D P G E PR O O FS 8.1 Kick off with S Plese refer to the Resources t in the Prelims

More information

Operations with Polynomials

Operations with Polynomials 38 Chpter P Prerequisites P.4 Opertions with Polynomils Wht you should lern: How to identify the leding coefficients nd degrees of polynomils How to dd nd subtrct polynomils How to multiply polynomils

More information

Section 1.3 Triangles

Section 1.3 Triangles Se 1.3 Tringles 21 Setion 1.3 Tringles LELING TRINGLE The line segments tht form tringle re lled the sides of the tringle. Eh pir of sides forms n ngle, lled n interior ngle, nd eh tringle hs three interior

More information

Definite integral. Mathematics FRDIS MENDELU. Simona Fišnarová (Mendel University) Definite integral MENDELU 1 / 30

Definite integral. Mathematics FRDIS MENDELU. Simona Fišnarová (Mendel University) Definite integral MENDELU 1 / 30 Definite integrl Mthemtics FRDIS MENDELU Simon Fišnrová (Mendel University) Definite integrl MENDELU / Motivtion - re under curve Suppose, for simplicity, tht y = f(x) is nonnegtive nd continuous function

More information

+ R 2 where R 1. MULTIPLE CHOICE QUESTIONS (MCQ's) (Each question carries one mark)

+ R 2 where R 1. MULTIPLE CHOICE QUESTIONS (MCQ's) (Each question carries one mark) 2. C h p t e r t G l n c e is the set of ll points in plne which re t constnt distnce from fixed point clled centre nd constnt distnce is known s rdius of circle. A tngent t ny point of circle is perpendiculr

More information

13.3 CLASSICAL STRAIGHTEDGE AND COMPASS CONSTRUCTIONS

13.3 CLASSICAL STRAIGHTEDGE AND COMPASS CONSTRUCTIONS 33 CLASSICAL STRAIGHTEDGE AND COMPASS CONSTRUCTIONS As simple ppliction of the results we hve obtined on lgebric extensions, nd in prticulr on the multiplictivity of extension degrees, we cn nswer (in

More information

Consolidation Worksheet

Consolidation Worksheet Cmbridge Essentils Mthemtics Core 8 NConsolidtion Worksheet N Consolidtion Worksheet Work these out. 8 b 7 + 0 c 6 + 7 5 Use the number line to help. 2 Remember + 2 2 +2 2 2 + 2 Adding negtive number is

More information

ARITHMETIC OPERATIONS. The real numbers have the following properties: a b c ab ac

ARITHMETIC OPERATIONS. The real numbers have the following properties: a b c ab ac REVIEW OF ALGEBRA Here we review the bsic rules nd procedures of lgebr tht you need to know in order to be successful in clculus. ARITHMETIC OPERATIONS The rel numbers hve the following properties: b b

More information

7.1 Integral as Net Change and 7.2 Areas in the Plane Calculus

7.1 Integral as Net Change and 7.2 Areas in the Plane Calculus 7.1 Integrl s Net Chnge nd 7. Ares in the Plne Clculus 7.1 INTEGRAL AS NET CHANGE Notecrds from 7.1: Displcement vs Totl Distnce, Integrl s Net Chnge We hve lredy seen how the position of n oject cn e

More information

MEP Practice Book ES3. 1. Calculate the size of the angles marked with a letter in each diagram. None to scale

MEP Practice Book ES3. 1. Calculate the size of the angles marked with a letter in each diagram. None to scale ME rctice ook ES3 3 ngle Geometr 3.3 ngle Geometr 1. lculte the size of the ngles mrked with letter in ech digrm. None to scle () 70 () 20 54 65 25 c 36 (d) (e) (f) 56 62 d e 60 40 70 70 f 30 g (g) (h)

More information

We divide the interval [a, b] into subintervals of equal length x = b a n

We divide the interval [a, b] into subintervals of equal length x = b a n Arc Length Given curve C defined by function f(x), we wnt to find the length of this curve between nd b. We do this by using process similr to wht we did in defining the Riemnn Sum of definite integrl:

More information

7.2 The Definite Integral

7.2 The Definite Integral 7.2 The Definite Integrl the definite integrl In the previous section, it ws found tht if function f is continuous nd nonnegtive, then the re under the grph of f on [, b] is given by F (b) F (), where

More information

SOLUTIONS FOR ADMISSIONS TEST IN MATHEMATICS, COMPUTER SCIENCE AND JOINT SCHOOLS WEDNESDAY 5 NOVEMBER 2014

SOLUTIONS FOR ADMISSIONS TEST IN MATHEMATICS, COMPUTER SCIENCE AND JOINT SCHOOLS WEDNESDAY 5 NOVEMBER 2014 SOLUTIONS FOR ADMISSIONS TEST IN MATHEMATICS, COMPUTER SCIENCE AND JOINT SCHOOLS WEDNESDAY 5 NOVEMBER 014 Mrk Scheme: Ech prt of Question 1 is worth four mrks which re wrded solely for the correct nswer.

More information

Chapter 1: Fundamentals

Chapter 1: Fundamentals Chpter 1: Fundmentls 1.1 Rel Numbers Types of Rel Numbers: Nturl Numbers: {1, 2, 3,...}; These re the counting numbers. Integers: {... 3, 2, 1, 0, 1, 2, 3,...}; These re ll the nturl numbers, their negtives,

More information

ICSE Board Class IX Mathematics Paper 4 Solution

ICSE Board Class IX Mathematics Paper 4 Solution ICSE Bord Clss IX Mthemtics Pper Solution SECTION A (0 Mrks) Q.. () Consider x y 6 5 5 x y 6 5 5 0 6 0 6 x y 6 50 8 5 6 7 6 x y 6 7 6 x y 6 x 7,y (b) Dimensions of the brick: Length (l) = 0 cm, bredth

More information

1 ELEMENTARY ALGEBRA and GEOMETRY READINESS DIAGNOSTIC TEST PRACTICE

1 ELEMENTARY ALGEBRA and GEOMETRY READINESS DIAGNOSTIC TEST PRACTICE ELEMENTARY ALGEBRA nd GEOMETRY READINESS DIAGNOSTIC TEST PRACTICE Directions: Study the exmples, work the prolems, then check your nswers t the end of ech topic. If you don t get the nswer given, check

More information

Find the value of x. Give answers as simplified radicals.

Find the value of x. Give answers as simplified radicals. 9.2 Dy 1 Wrm Up Find the vlue of. Give nswers s simplified rdicls. 1. 2. 3 3 3. 4. 10 Mrch 2, 2017 Geometry 9.2 Specil Right Tringles 1 Geometry 9.2 Specil Right Tringles 9.2 Essentil Question Wht is the

More information

The Algebra (al-jabr) of Matrices

The Algebra (al-jabr) of Matrices Section : Mtri lgebr nd Clculus Wshkewicz College of Engineering he lgebr (l-jbr) of Mtrices lgebr s brnch of mthemtics is much broder thn elementry lgebr ll of us studied in our high school dys. In sense

More information

Maintaining Mathematical Proficiency

Maintaining Mathematical Proficiency Nme Dte hpter 9 Mintining Mthemtil Profiieny Simplify the epression. 1. 500. 189 3. 5 4. 4 3 5. 11 5 6. 8 Solve the proportion. 9 3 14 7. = 8. = 9. 1 7 5 4 = 4 10. 0 6 = 11. 7 4 10 = 1. 5 9 15 3 = 5 +

More information

AQA Further Pure 1. Complex Numbers. Section 1: Introduction to Complex Numbers. The number system

AQA Further Pure 1. Complex Numbers. Section 1: Introduction to Complex Numbers. The number system Complex Numbers Section 1: Introduction to Complex Numbers Notes nd Exmples These notes contin subsections on The number system Adding nd subtrcting complex numbers Multiplying complex numbers Complex

More information

List all of the possible rational roots of each equation. Then find all solutions (both real and imaginary) of the equation. 1.

List all of the possible rational roots of each equation. Then find all solutions (both real and imaginary) of the equation. 1. Mth Anlysis CP WS 4.X- Section 4.-4.4 Review Complete ech question without the use of grphing clcultor.. Compre the mening of the words: roots, zeros nd fctors.. Determine whether - is root of 0. Show

More information

Geometry AP Book 8, Part 2: Unit 3

Geometry AP Book 8, Part 2: Unit 3 Geometry ook 8, rt 2: Unit 3 IMRTNT NTE: For mny questions in this unit, there re multiple correct nswers, e.g. line segment cn e written s, RST is the sme s TSR, etc. Where pproprite, techers should e

More information

x means to use x as a factor five times, or x x x x x (2 c ) means to use 2c as a factor four times, or

x means to use x as a factor five times, or x x x x x (2 c ) means to use 2c as a factor four times, or 14 DAY 1 CHAPTER FIVE Wht fscinting mthemtics is now on our gend? We will review the pst four chpters little bit ech dy becuse mthemtics builds. Ech concept is foundtion for nother ide. We will hve grph

More information

APPROXIMATE INTEGRATION

APPROXIMATE INTEGRATION APPROXIMATE INTEGRATION. Introduction We hve seen tht there re functions whose nti-derivtives cnnot be expressed in closed form. For these resons ny definite integrl involving these integrnds cnnot be

More information

A study of Pythagoras Theorem

A study of Pythagoras Theorem CHAPTER 19 A study of Pythgors Theorem Reson is immortl, ll else mortl. Pythgors, Diogenes Lertius (Lives of Eminent Philosophers) Pythgors Theorem is proly the est-known mthemticl theorem. Even most nonmthemticins

More information

Math 1102: Calculus I (Math/Sci majors) MWF 3pm, Fulton Hall 230 Homework 2 solutions

Math 1102: Calculus I (Math/Sci majors) MWF 3pm, Fulton Hall 230 Homework 2 solutions Mth 1102: Clculus I (Mth/Sci mjors) MWF 3pm, Fulton Hll 230 Homework 2 solutions Plese write netly, nd show ll work. Cution: An nswer with no work is wrong! Do the following problems from Chpter III: 6,

More information

Trigonometry. VCEcoverage. Area of study. Units 3 & 4 Geometry and trigonometry

Trigonometry. VCEcoverage. Area of study. Units 3 & 4 Geometry and trigonometry Trigonometry 9 VEcoverge re of study Units & Geometry nd trigonometry In this ch chpter 9 Pythgors theorem 9 Pythgoren trids 9 Three-dimensionl Pythgors theorem 9D Trigonometric rtios 9E The sine rule

More information

Log1 Contest Round 3 Theta Individual. 4 points each 1 What is the sum of the first 5 Fibonacci numbers if the first two are 1, 1?

Log1 Contest Round 3 Theta Individual. 4 points each 1 What is the sum of the first 5 Fibonacci numbers if the first two are 1, 1? 008 009 Log1 Contest Round Thet Individul Nme: points ech 1 Wht is the sum of the first Fiboncci numbers if the first two re 1, 1? If two crds re drwn from stndrd crd deck, wht is the probbility of drwing

More information

Introduction To Matrices MCV 4UI Assignment #1

Introduction To Matrices MCV 4UI Assignment #1 Introduction To Mtrices MCV UI Assignment # INTRODUCTION: A mtrix plurl: mtrices) is rectngulr rry of numbers rrnged in rows nd columns Exmples: ) b) c) [ ] d) Ech number ppering in the rry is sid to be

More information

Section 14.3 Arc Length and Curvature

Section 14.3 Arc Length and Curvature Section 4.3 Arc Length nd Curvture Clculus on Curves in Spce In this section, we ly the foundtions for describing the movement of n object in spce.. Vector Function Bsics In Clc, formul for rc length in

More information

Week 10: Line Integrals

Week 10: Line Integrals Week 10: Line Integrls Introduction In this finl week we return to prmetrised curves nd consider integrtion long such curves. We lredy sw this in Week 2 when we integrted long curve to find its length.

More information

2 Calculate the size of each angle marked by a letter in these triangles.

2 Calculate the size of each angle marked by a letter in these triangles. Cmridge Essentils Mthemtics Support 8 GM1.1 GM1.1 1 Clculte the size of ech ngle mrked y letter. c 2 Clculte the size of ech ngle mrked y letter in these tringles. c d 3 Clculte the size of ech ngle mrked

More information

Lecture 2 : Propositions DRAFT

Lecture 2 : Propositions DRAFT CS/Mth 240: Introduction to Discrete Mthemtics 1/20/2010 Lecture 2 : Propositions Instructor: Dieter vn Melkeeek Scrie: Dlior Zelený DRAFT Lst time we nlyzed vrious mze solving lgorithms in order to illustrte

More information

Each term is formed by adding a constant to the previous term. Geometric progression

Each term is formed by adding a constant to the previous term. Geometric progression Chpter 4 Mthemticl Progressions PROGRESSION AND SEQUENCE Sequence A sequence is succession of numbers ech of which is formed ccording to definite lw tht is the sme throughout the sequence. Arithmetic Progression

More information

MATH 115 FINAL EXAM. April 25, 2005

MATH 115 FINAL EXAM. April 25, 2005 MATH 115 FINAL EXAM April 25, 2005 NAME: Solution Key INSTRUCTOR: SECTION NO: 1. Do not open this exm until you re told to begin. 2. This exm hs 9 pges including this cover. There re 9 questions. 3. Do

More information

Minnesota State University, Mankato 44 th Annual High School Mathematics Contest April 12, 2017

Minnesota State University, Mankato 44 th Annual High School Mathematics Contest April 12, 2017 Minnesot Stte University, Mnkto 44 th Annul High School Mthemtics Contest April, 07. A 5 ft. ldder is plced ginst verticl wll of uilding. The foot of the ldder rests on the floor nd is 7 ft. from the wll.

More information

Definition :- A shape has a line of symmetry if, when folded over the line. 1 line of symmetry 2 lines of symmetry

Definition :- A shape has a line of symmetry if, when folded over the line. 1 line of symmetry 2 lines of symmetry Symmetry Lines of Symmetry Definition :- A shpe hs line of symmetry if, when folded over the line the hlves of the shpe mtch up exctly. Some shpes hve more thn one line of symmetry : line of symmetry lines

More information

Chapter 4 Contravariance, Covariance, and Spacetime Diagrams

Chapter 4 Contravariance, Covariance, and Spacetime Diagrams Chpter 4 Contrvrince, Covrince, nd Spcetime Digrms 4. The Components of Vector in Skewed Coordintes We hve seen in Chpter 3; figure 3.9, tht in order to show inertil motion tht is consistent with the Lorentz

More information

1. Gauss-Jacobi quadrature and Legendre polynomials. p(t)w(t)dt, p {p(x 0 ),...p(x n )} p(t)w(t)dt = w k p(x k ),

1. Gauss-Jacobi quadrature and Legendre polynomials. p(t)w(t)dt, p {p(x 0 ),...p(x n )} p(t)w(t)dt = w k p(x k ), 1. Guss-Jcobi qudrture nd Legendre polynomils Simpson s rule for evluting n integrl f(t)dt gives the correct nswer with error of bout O(n 4 ) (with constnt tht depends on f, in prticulr, it depends on

More information

Before we can begin Ch. 3 on Radicals, we need to be familiar with perfect squares, cubes, etc. Try and do as many as you can without a calculator!!!

Before we can begin Ch. 3 on Radicals, we need to be familiar with perfect squares, cubes, etc. Try and do as many as you can without a calculator!!! Nme: Algebr II Honors Pre-Chpter Homework Before we cn begin Ch on Rdicls, we need to be fmilir with perfect squres, cubes, etc Try nd do s mny s you cn without clcultor!!! n The nth root of n n Be ble

More information

Exponentials - Grade 10 [CAPS] *

Exponentials - Grade 10 [CAPS] * OpenStx-CNX module: m859 Exponentils - Grde 0 [CAPS] * Free High School Science Texts Project Bsed on Exponentils by Rory Adms Free High School Science Texts Project Mrk Horner Hether Willims This work

More information

Andrew Ryba Math Intel Research Final Paper 6/7/09 (revision 6/17/09)

Andrew Ryba Math Intel Research Final Paper 6/7/09 (revision 6/17/09) Andrew Ryb Mth ntel Reserch Finl Pper 6/7/09 (revision 6/17/09) Euler's formul tells us tht for every tringle, the squre of the distnce between its circumcenter nd incenter is R 2-2rR, where R is the circumrdius

More information

6.2 CONCEPTS FOR ADVANCED MATHEMATICS, C2 (4752) AS

6.2 CONCEPTS FOR ADVANCED MATHEMATICS, C2 (4752) AS 6. CONCEPTS FOR ADVANCED MATHEMATICS, C (475) AS Objectives To introduce students to number of topics which re fundmentl to the dvnced study of mthemtics. Assessment Emintion (7 mrks) 1 hour 30 minutes.

More information

Date Lesson Text TOPIC Homework. Solving for Obtuse Angles QUIZ ( ) More Trig Word Problems QUIZ ( )

Date Lesson Text TOPIC Homework. Solving for Obtuse Angles QUIZ ( ) More Trig Word Problems QUIZ ( ) UNIT 5 TRIGONOMETRI RTIOS Dte Lesson Text TOPI Homework pr. 4 5.1 (48) Trigonometry Review WS 5.1 # 3 5, 9 11, (1, 13)doso pr. 6 5. (49) Relted ngles omplete lesson shell & WS 5. pr. 30 5.3 (50) 5.3 5.4

More information

Objective: Use the Pythagorean Theorem and its converse to solve right triangle problems. CA Geometry Standard: 12, 14, 15

Objective: Use the Pythagorean Theorem and its converse to solve right triangle problems. CA Geometry Standard: 12, 14, 15 Geometry CP Lesson 8.2 Pythgoren Theorem nd its Converse Pge 1 of 2 Ojective: Use the Pythgoren Theorem nd its converse to solve right tringle prolems. CA Geometry Stndrd: 12, 14, 15 Historicl Bckground

More information

Similar Right Triangles

Similar Right Triangles Geometry V1.noteook Ferury 09, 2012 Similr Right Tringles Cn I identify similr tringles in right tringle with the ltitude? Cn I identify the proportions in right tringles? Cn I use the geometri mens theorems

More information

How do we solve these things, especially when they get complicated? How do we know when a system has a solution, and when is it unique?

How do we solve these things, especially when they get complicated? How do we know when a system has a solution, and when is it unique? XII. LINEAR ALGEBRA: SOLVING SYSTEMS OF EQUATIONS Tody we re going to tlk bout solving systems of liner equtions. These re problems tht give couple of equtions with couple of unknowns, like: 6 2 3 7 4

More information

MATHEMATICS AND STATISTICS 1.2

MATHEMATICS AND STATISTICS 1.2 MATHEMATICS AND STATISTICS. Apply lgebric procedures in solving problems Eternlly ssessed 4 credits Electronic technology, such s clcultors or computers, re not permitted in the ssessment of this stndr

More information

Sample Problems for the Final of Math 121, Fall, 2005

Sample Problems for the Final of Math 121, Fall, 2005 Smple Problems for the Finl of Mth, Fll, 5 The following is collection of vrious types of smple problems covering sections.8,.,.5, nd.8 6.5 of the text which constitute only prt of the common Mth Finl.

More information

4.4 Areas, Integrals and Antiderivatives

4.4 Areas, Integrals and Antiderivatives . res, integrls nd ntiderivtives 333. Ares, Integrls nd Antiderivtives This section explores properties of functions defined s res nd exmines some connections mong res, integrls nd ntiderivtives. In order

More information

What else can you do?

What else can you do? Wht else cn you do? ngle sums The size of specil ngle types lernt erlier cn e used to find unknown ngles. tht form stright line dd to 180c. lculte the size of + M, if L is stright line M + L = 180c( stright

More information

The Regulated and Riemann Integrals

The Regulated and Riemann Integrals Chpter 1 The Regulted nd Riemnn Integrls 1.1 Introduction We will consider severl different pproches to defining the definite integrl f(x) dx of function f(x). These definitions will ll ssign the sme vlue

More information

Invention of the plane geometrical formulae - Part II

Invention of the plane geometrical formulae - Part II IOSR Journl of Mthemtics (IOSR-JM) e-issn: 78-578,p-ISSN: 319-765X, Volume 6, Issue 3 (My. - Jun. 013), PP 10-15 Invention of the plne geometricl formule - Prt II Mr. Stish M. Kple sst. Techer Mhtm Phule

More information

Intermediate Math Circles Wednesday, November 14, 2018 Finite Automata II. Nickolas Rollick a b b. a b 4

Intermediate Math Circles Wednesday, November 14, 2018 Finite Automata II. Nickolas Rollick a b b. a b 4 Intermedite Mth Circles Wednesdy, Novemer 14, 2018 Finite Automt II Nickols Rollick nrollick@uwterloo.c Regulr Lnguges Lst time, we were introduced to the ide of DFA (deterministic finite utomton), one

More information

5.2 Volumes: Disks and Washers

5.2 Volumes: Disks and Washers 4 pplictions of definite integrls 5. Volumes: Disks nd Wshers In the previous section, we computed volumes of solids for which we could determine the re of cross-section or slice. In this section, we restrict

More information

Geometry of the Circle - Chords and Angles. Geometry of the Circle. Chord and Angles. Curriculum Ready ACMMG: 272.

Geometry of the Circle - Chords and Angles. Geometry of the Circle. Chord and Angles. Curriculum Ready ACMMG: 272. Geometry of the irle - hords nd ngles Geometry of the irle hord nd ngles urriulum Redy MMG: 272 www.mthletis.om hords nd ngles HRS N NGLES The irle is si shpe nd so it n e found lmost nywhere. This setion

More information

n f(x i ) x. i=1 In section 4.2, we defined the definite integral of f from x = a to x = b as n f(x i ) x; f(x) dx = lim i=1

n f(x i ) x. i=1 In section 4.2, we defined the definite integral of f from x = a to x = b as n f(x i ) x; f(x) dx = lim i=1 The Fundmentl Theorem of Clculus As we continue to study the re problem, let s think bck to wht we know bout computing res of regions enclosed by curves. If we wnt to find the re of the region below the

More information

APPLICATIONS OF THE DEFINITE INTEGRAL

APPLICATIONS OF THE DEFINITE INTEGRAL APPLICATIONS OF THE DEFINITE INTEGRAL. Volume: Slicing, disks nd wshers.. Volumes by Slicing. Suppose solid object hs boundries extending from x =, to x = b, nd tht its cross-section in plne pssing through

More information

Bases for Vector Spaces

Bases for Vector Spaces Bses for Vector Spces 2-26-25 A set is independent if, roughly speking, there is no redundncy in the set: You cn t uild ny vector in the set s liner comintion of the others A set spns if you cn uild everything

More information

4 VECTORS. 4.0 Introduction. Objectives. Activity 1

4 VECTORS. 4.0 Introduction. Objectives. Activity 1 4 VECTRS Chpter 4 Vectors jectives fter studying this chpter you should understnd the difference etween vectors nd sclrs; e le to find the mgnitude nd direction of vector; e le to dd vectors, nd multiply

More information

Answers for Lesson 3-1, pp Exercises

Answers for Lesson 3-1, pp Exercises Answers for Lesson -, pp. Eercises * ) PQ * ) PS * ) PS * ) PS * ) SR * ) QR * ) QR * ) QR. nd with trnsversl ; lt. int. '. nd with trnsversl ; lt. int. '. nd with trnsversl ; sme-side int. '. nd with

More information

Review of Calculus, cont d

Review of Calculus, cont d Jim Lmbers MAT 460 Fll Semester 2009-10 Lecture 3 Notes These notes correspond to Section 1.1 in the text. Review of Clculus, cont d Riemnn Sums nd the Definite Integrl There re mny cses in which some

More information

Math 154B Elementary Algebra-2 nd Half Spring 2015

Math 154B Elementary Algebra-2 nd Half Spring 2015 Mth 154B Elementry Alger- nd Hlf Spring 015 Study Guide for Exm 4, Chpter 9 Exm 4 is scheduled for Thursdy, April rd. You my use " x 5" note crd (oth sides) nd scientific clcultor. You re expected to know

More information

UNCORRECTED. 9Geometry in the plane and proof

UNCORRECTED. 9Geometry in the plane and proof 9Geometry in the plne nd proof Ojectives To consider necessry nd sufficient conditions for two lines to e prllel. To determine the ngle sum of polygon. To define congruence of two figures. To determine

More information

Written as per the revised syllabus prescribed by the Maharashtra State Board of Secondary and Higher Secondary Education, Pune.

Written as per the revised syllabus prescribed by the Maharashtra State Board of Secondary and Higher Secondary Education, Pune. Written s per the revised syllbus prescribed by the Mhrshtr Stte Bord of Secondry nd Higher Secondry Eduction, Pune. Slient Fetures Written s per the new textbook. Exhustive coverge of entire syllbus.

More information

Loudoun Valley High School Calculus Summertime Fun Packet

Loudoun Valley High School Calculus Summertime Fun Packet Loudoun Vlley High School Clculus Summertime Fun Pcket We HIGHLY recommend tht you go through this pcket nd mke sure tht you know how to do everything in it. Prctice the problems tht you do NOT remember!

More information