Fast Filling Process Modeling Based on the Real Gas Model with the aim of Simulation of the Compressed Natural Gas Refueling Station

Size: px
Start display at page:

Download "Fast Filling Process Modeling Based on the Real Gas Model with the aim of Simulation of the Compressed Natural Gas Refueling Station"

Transcription

1 3-05! &' 3* 0) '/ % & * -*, * )*( &'% 3*9( 08 '/ /0 -, / /0 - / *8 :30 ;* * 36 3)7 3*/ )'*( 37 G BCD 56 E8? > / 4? :; /7/ 83 56? :; /7/ 3 G J K/? 5H ICCD > / 4? BH L MG ; / IK >? L :H L C / /? - MG :H L 8 4- W / 4 LU M8 ST J OP IK J Q RP / - L 0 / C 5H ICCD W, BCD W 80 K A L L 50 K A / ZR [ C 8 4- W /? K/ AGA8 A : - :; Y7 /D? /6 kwh 7 7/ [ ]/ C 55/ kwh A 7 \ AGA8 A : > / 4? /L :&B &A@) Fast Filling Process Modeling Based on the Real Gas Model with the aim of Simulation of the Compressed atural Gas Refueling Station M Saadat- Targhi J Khadem M Farzaneh-Gord Department of Mechanical Engineering, University of Birjand, Birjand, Iran Department of Mechanical Engineering, University of Birjand, Birjand, Iran Department of Mechanical Engineering, University of Birjand, Birjand, Iran Abstract The main process that occurs in the CG refueling station is filling fast process The main objective of the present study is to apply a more accurate thermodynamic analysis of fast filling process than previous works By using the thermodynamic analysis, a CG refueling station with the cascade system, has been simulated Comparing real and ideal gas models, it can be realized that the temperature profiles are highly different and temperature rise is much more for ideal gas model the lack of Joule-Thompson cooling effect is the most important factor for this different The results indicated that there is a temperature rise in order 50 K for real gas and 80 K for the case of ideal gas The results of the present work have been validated against the experimental data and previous studies The AGA8 Equation of State has been used to calculate the thermodynamic properties of CG The results show that the energy consumed by the compressor for a cycle is equal to 55 kwh and the average energy consumption is equal to 6 kwh for a vehicle Keywords: Modeling, Fast filling, AGA8 Equation of state R8 7/ 4 M8 (3 / ZR [ 83 7f - 7f _/ _/ a d`r:? i j 7f _/ H K/ CCD 4? 7f _/ a J LR: - / I6 :; /7/ 83? 7 > / 4? ]/ > / 4? / 0 ICCD /L ] BCD J / L J / I6 994 L/ [] G / /L / I6 7 4Ge /L 0 /? 7 4Ge ]? 6 n - : Me IC5: ST 008 L/ [] 4R8 7/ 4 7 4Ge 0 ]? [3] 4R8-7f ( - ) 3 BCD JoR8 R / _/ a C 0 L/ 7/ 4P - :; K/ G8 4 E 7 8L/ - J 5P / W 4 7 K/ OG ]D ` _ 4G J ]/ J d`r: ca - RP A ; :; 4?? b :; > / 7/ 4? a J /7/ B ; ( 50 00) 7f 3 4e / ZR QC 7 4Ge 3 /? OG? > / 4? IC5: / ; 8 J _? A :; /7/ 3 ) 0 8G8 M8 E8 4 5RP Q5D * jkhadem49@yahoocom : 95/03/3 :! 95/0/9 :( )!

2 4Ge J L > / 4? BCD ; 8 3 7f 4e 7 Y7 J: 0 / /L :H? K/ AGA8 A : :H L :; W :H L K/ ST 8-0 JoR8 / C [93] 5H ICCD W JoR8, W > / 4? /L W BCD / /7/ 3? K/ / ZR /L R8 / /? - 7f _/ :; &'% 7f _/ :; /7/ 3 R - IC5: 3 /? 4- Q? - - 7f 4e Q 5A / / ZR / Q- 7 4Ge > ; 8 8 Q- > / 4? 7 0\ 08 '/ ') &))7G*8 - F - _8 4e PR, 3 d`r: - 7f _/ /7/ 3 - ]/ _ w / ZR f _/ :;? 3 7f 4e Q P 5e 4 Kx > _3 _3 /? 7 4Ge 4? 3 4e : C 7 4Ge ) J - 4Ge 7 4Ge (0/0 kg/s d`r:) / Priority Panel Dispenser &9H *6I JKL 4P C C \ 8 / ZR /D 0 : 4-0 W 3 /D _C I6 / ZR A - 7f _/ C 8 I6 /L? 0 0 5H ICCD - 7f _/ :H R %55 L 4e I q /L? 7 7 4Ge /L 0 8BCD / 7 5H /? 8L 6 IC5: / 3 S 3 4e ]? K/ JoR8 [54] 4R8 0 8L/ :; /7/ 3 /0 I6 L L 0 /L 7 03 [6] 4R8 ( O7 ]/ G 0- BCD / 4? I6 8/ B; / I6 04 L/ /L R ICCD re- O, 3 4e 7 4Ge J > / / CCD 0 L/ [7] 4R8 R / 7 4Ge 4? ; 3 4e ]? I q /L 5H 8BCD 0 7 C nd6 M OP / 3 4e ; 8 /L \? 0-0 /L ; 8 /L /? 6 4e J 05 L/ [8] 4R8 O7 ]/ Je > / 4? C /D L (G t ; 8 J > / 4? ; L L // 0 0 BCD /? S 3 4e ]? JoR8? K/ C, W W Je BCD J / J 7 /L W :; /7/ 83 /L u 8BCD G 06 L/ [9] 4R8 I:/ 0 /L 7 4 / ZR J 3 JoR8 Q5D bj6 J ; 8 3 7f 4e ]? I q 5H BCD Ev7 W I q J 0 8 S /? 3 R C [83] 5H 8 W JoR8 / ZR [ J: / ZR /L I q 4-0? 5RP ]? 4 8-5RP - C ; (3 7f 8- q JoR8 8 S 4e) ST / ZR 7 / ZR 7 - ST / ZR C ]? / ZR / ZR 7? S C / ZR 5RP ; G C J K/ / :H J 56 : E D > / 4? - :H L 5H W W 0 V/ 0 BCD L L /L > / 4? - 4 ` :H L /L OG L A 06

3 RD O7 H ; I:/ y d( ρvv) dp f ρ V 0 dx dx D R P Zρ T M 4 V Z ρ, V, P, f, D, R, M,T 3\ P / - bj6 0 (8) (9) jh S :_ ; 8 )_ V m A (0) :_ (0) (8) I`: V & & f m mdx & ρ VdV ρ dp 0 A D (}\ R/ L IP) - U IP C () L 3 w [0]? 6 8IP / C 05 & MD(P P ) m A f LRTavg Zavg 7 4Ge 3 4e J ; L; L 4 :_ () [9] > f Z avg T avg /D u ]? K/ 4 ; C ) / R K/ (5) () ] 4 /D () j / 7/ 83 H K/ / ZR / 8/ ZR J d`r:? - a :; 4 4 J ` 8/ ZR a J 8 5A _0 MG 5A / ; - 5/? [ 83 8/ ZR / 4- [9] 4R8 I:/ f C jr8 C (3 7f 4e) / ZR 7 - I q ; C J ST / ZR QA 8- q JoR8 8 S C ]? / ZR 5RP ST / ZR 7 / ZR 7 - S C / ZR 5RP ; G C J /D j / ZR 7? & MWgas mco ρ std Q std ( ) ρ air,std Qstd MWair x V MW air : (3) MW gas ρ air,std Q std 4 4 / ]? 8 3\ / ]? / ZR? :; 4 8 j G Q?? 4-5A / / ZR J: 7/ Q[ ` - 4Ge _,A 3 7f 4e /L 0 / 4 4 Q7 -? 7f 4Ge Q7 _,A O zc : / { 7 I6 dm r m & e dt :? Q? ) L 7 E : V m m & r e 4 Q?? 3 7f 4e 4 O 3 4e Q? ) L _,A L 4H 5 & Vei & Vee QCV m i(h i ) m e(h e ) d Ve m(u ) WCV dt () :? JoR8? E 6 Q M U I q :_ 7 L _,A du r QCV me hr dt ]D 3 4e J LC / / 0 du r dm m r r ur & me hr dt dt () (3) :_ // w? E 6 E ; Z 57 U V hr u r 4 :; Y7 J? 8 3 4e i j : 8Me R /D C J 4 Q- Q K : 3/ 4GR8 QA 87 O C 4 O5: (4) () ] R J: : O u r m r (4) C 4 3 4e - 4 G 7 4Ge /L 0 i? 7 4Ge /L 0 Q6A ] R QRP dm c m & i dt du c dm m c c uc & mi hr dt dt?? 7f :; O V u c m i m c 4 U 7 4Ge 7 4Ge Q7 3/ QA? 7 4Ge :; 57? 3 4e -? Q6A Q K : I6 7 4Ge 3 4e J :; 4 {? /? : 4 / K/ 5e 8 ]? ; 8 Q7 /D 0 d( ρv) 0 dx :? Q? A : _ O zc I`: (5) (6) (7) 07

4 * g q n n / / B nij (Gij g n ) (QiQ j q n ) (Fi Fj f s w f n n n n ) (SiS j s n ) (Wi Wj w n ) (0) U 8 V G ij E ij t 8 If 0 :H t L O -R8 * / ij ij i j E E (E E ) * G ij (G i G j ) Gij? : ] ]/? V G : T () (9) 8j () () w n u n s n q n g n f n a n i zg x i :; u t [e- A : S 8 u5e :; 8 Q- G F i E i /? [] > 0 C 5e 8A x [e- 8 W i S i Q i K i G i u5e 3 If M_8 5e 8A 7 8 G * E * ij ij? S 0 C i zg Y7 0 :H 8 j i G 8A J C? u5e j? [] > 3 u5e I 5e 8 Q- G V : C * n (6) j /? : j ]/ :; * g q f C n n n n a n (G g n ) (Q q ) (F f n n ) un u U T n u5e 8 U F Q G ~ : (3)? : I6 5 5/ 5 5/ i i i j ij i j i i j i U X E X X (U )(E E ) * G XiGi XiX j(gij )(G i G j) i i j i (4) (5) Q XiQi i (6) F Xi Fi (7) i u5e U M_8 U ij (4) j? : I6 D * n * kn bn kn n n n nρr ρr nρr D (b c k ) exp( c ) (6) j JoR8? Y7 /? [] > ~ : (8) A 4 0 K/ 8 67 re- _/ 4 _8 QC 67 J?? r7 Y7 C re- A? r7 J\ /D J? vp u5e A 4 re- 3 k & k Pdis k W adi (ZsuTsu R) ( ) k P su k k P (Z dis k sutsur) ( ) k Psu k3 k 3 P (Z dis3 k3 su3tsu3 R) ( ) k3 Psu3 K/ j / ZR :H /D d0 & W W adi a η c η m (4) :? (5) 4 _ 4 V η η 4 m c t / ZR / 8? ]/ d`r: BCD H /L / ZR I[e- / [9] > 5e QA :; Y7 J: 0 J K/ /? K/ AGA8 / /L R /D :; 3\ )_ 4 ( 5e 6P ;5e :; /? { ( J? re- u5e zg 8 D t I6 ( J Z )_ u : 8 58 * * * ZBρm - ρ r Cn CnDn n3 n3 ρ r L O B )_ :; I :[] / Z ~ : D * n C * n (6) 8 3\ 58 R?? f 8 C? 8? 8- QH [] > u ` 3\ I6 8 3\ 3 ρ r K ρm : j K/ u5e G/ K ρ r (7) u5e G R? 7/ u 8[e-? 5 5/ 5 5/ K xiki xix j(kij )(K ik j) i i j i K i u5e i zg x i j i G MR8 G/ K ij ~ j :? (8) i zg u G/ 8 5e G V 0 C? [] > u5e :; 8 Q- j I[ L O B (6) j? 8 u n * un 3/ B ant xix jbnije ij (KiK j) n i j? : (9)? : : ]/ ~ : /L > / 4? B * nij :H L (9) 08

5 O7 H ; I:/ y RD zg 6 QC 67 A : K/ 4 ) 87 G u5e [e- ] n - - AGA8 Y7 / u5e 8 Q- G J V / f O` R /D :; BCD H K/ :; [5] > 4 I 6? 4 37 Cj / FG H*( :?7( - F K A MG :H L 8 4- W 4Ge t0-80 K A L L 50 0 O C? 30 d C L 8 7 L K/ A R L L K/ A K/ A 4-7 J Q / :H 4Ge 4 - I q ]D? L L ST u W 4 /? 4-4 Q? 3 7f 4e 7 ;? IK 5e 8 7/ q S 5 7/ 4 Ev7 J / 8, 4 JoR f 4e - / FG H*( -3 i j I`: K/ 0 QA Me J t > / 4? /L d0 QH? O5: 7 4Ge 3 7f 4e - / C 4 Y7 J J 8 O L; R J: () j K/ L O QA /? 0/0 C QA ; 7f 4e u (4) () ] Q K : 3/ re- : O 57 U O C 3 O Y[e _,A 4 O 4 O5: QC 67 J? R J: - 5R Y7 / 4 57 U Y[e _,A? n - - R J: O O` (6) (5) ] : 7 4Ge 0 4 / K/ Y7 5 / f J /D n - QH Me AGA8 S O 5 0/0 R C 4- Q? QA I\5 / I6 MATLAB G O I\5 J /? /,O 9( 3 &)* 0) %H) '/ % MK -3 F 376 :H L MK-4 -*, * H*( &'% MK --4 K/ ST / Me J J /? 7 L L /L u W /L L :H L t 3 Q? 4 ; 7 4Ge - I q 4 /L W u IK J R0 / 0 ; 7 4Ge M / :H L - 38 K d C L L K/ L 7/ 4 4? R V/ J M8 ST J OP IK J Q RP :H / 4 LU 09

6 The on-board GV cylinder pressure (bar) /L > / 4? :H L Ti80 K Ti90 K Ti300 K Ti30 K Ti30 K Ti80 K Ti90 K Ti300 K Ti30 K Ti30 K The reservoir tank pressure (bar) * 3 &)* &*/')) &'% MK -5 F d C 7 4Ge - MG 9 Av J ` - 4Ge 7 4Ge L[ K6 C MG 9 08 '/ &' MK zc H > / 4? /L W Me --3 L J K/ BCD? t L - 4e :; /7/ 3 /7/ 3 u I[e- / H /? :H 3? /? 7 4Ge JoR8? (0- >H 043 R? 3) / t [9] > 3 / ZR I[e- :/? I@ /? W / S ]D 87 4e OR - /? 93 K? Ge - QHA 4Ge 4? w 87, O` 4 / { CH ; 3 > 0? (7 / ZR 7 4e 4? / I6 // 0 { J 9 A 8 J G :H f 4e - /? ]D - 7f 4e - I q u /? W 7 P 34 4 / t 7 Q? 7/ 3? J? / ZR 4 _ 4Ge -? 3 7 J R _ 4Ge - 7 J 4? w / 35-4e 4 L 7 / M8 3/8 - : R 7/ Q[ - - ]/ Time (s) *6I,'O 376,O 9( * R &3 *PQ -4 F? Q6A BCD W,/P I[e- / C [] BCD, W JoR8 / n - [] > 4 ]?, J- BCD W > /D u W / I6 W C [93]? 4-5 Q? 4? 4 ; 4 4?? 0-, W jr8 / H D S 36 w S 4 : > / q 0/0 kg/s 0/9 kg/s C J 4Ge / 0/04 kg/s C J / Q[ ` - 4Ge > ]/ 7 4Ge J ]/ 50 4 S J 4 7 4Ge ) U? 3 7f 4Ge J ]/ wz/ 3 7f BCD W 8 4- W C, C C [93] QH ICCD W 0 D6 7 4Ge - I q u W C 6 Q? BCD /L W 0 W H / 0- W jr8 /? 4-4 5P / 0 [9 3] 5H ICCD C ]? I q J ; 8 /L 4 3 E ; :H L K/ 3 4e I6 L L /L [9 8] ICCD L J K/ ; ` 8-30 i j /L rc 4P 0

7 RD O7 H ; I:/ y * 3 &)* &*/')) &'% MK -6 F \ / R8? Q 7 \ : / ZR 4? (7 J? : _C u 0 8G8 / ZR 4? (7 J? : MG re- 3 /? O, MG G / ZR Q 7 \ / ZR [ C / [ ]/ C JoR8? 55/ kwh A J: /6 kwh 7 7/ / ZR E [ C J - \? _0 W J / / 3 / ZR u 83 U *6I JKL &)* *6I,'O 9( -7 F &9H &9H *6I JKL &)* &' MK - % /? W CH 57 9 P/ I 5 55/ S 47 P/ I 5 /6 /?? : 4? 7 Q/ 4 I? Q/ : Q/ / ZR [ 7 7/ 4 J3 7 / ZR J3 &*/K 7 7/ 4P - :; K/ -4 D :j / H 4 G / I6 :; /7/ 83 BCD? 83 9 J R0 > / 4? 4e 7 4Ge J :H L > / 4? ; 8 7f Y7 J: 0 AGA8 A : / /L /? K/ :H L :; 7 4Ge 0 re- W / w L L W R 30 K A :H L K/ W :H L K/ ST 8-0 JoR8? / C 5H ICCD W JoR8, W 7 L 7 / 4 t - _ 4Ge H 0 / / 00 C - 4\ O0\ 4Ge ]/ O0\ 7?R 7/ QR [e- C 7/ - _ Q[ - ]/ 4Ge / (0/0 kg/s) J QR 4Ge J ]/ 7/ L[ 0 8e H _8G 7 _8G \ 00 - ]/ _ 4e 7 4Ge L[ / / 00 7f 4Ge QR G 7 J 7/ - 4Ge G - 4Ge - : 87 J 4? J? 4 : 87 / f 4e e? / ZR > R3 ]/ 7 4Ge 7/ O, 3-4Ge - (4? 7 4) CH 40 : H 3 3 4e A J / 00 7/ Ge 4 ]/ - _ 4Ge / 8 - J? / ZR 3 4) J 0 O` 4 MG Q 7 \? CH 7 A (4? U? 4 CH 57 A 3 7f 4e 4? e 4 Kx Q 3 _3 B; / / ZR ]/ 3 7f 4e 4? 4Ge d0 - ]/ wz/ - 4Ge _3 J / ZR ]/ - _ 8G8 M8 E8 f C jr8 7/ 4 M8 (3 / ZR [ ) 0 )? i j :; /7/ 83 A ; BCD E8 BH /? 4/ 4/ /? W >R / _0 f jr8 / t L? i j E8 7f 4e 4? 7 Q 7 \ 4 I 9? V J? CH 57 A 3? O, QH Q 7 \

8 (J/mol K) S (K) (s) 4 (kj/kg) 57 U t MR8 (m 3 ) _,A (ms - ) P / (kj/kg) :H (kw) :H 9 i zg [e- (m) ak _ (kgm -3 ) 3\ :H J3 7 7f 4Ge / ZR L _,A 5e 3 7f 4e M / R T t u U V V W W z Z 7 JUV ρ AW7*' a avg c co cv i dis r su std -)* -7 [] Kountz K, Modeling The Fast Fill Process in atural Gas Vehicle Storage Cylinders, American Chemical Society Paper at 07th ational ACS Meeting, March, 994 [] Farzaneh-Gord M, Hashemi S, Farzaneh-Kord A, Thermodynamics Analysis of Cascade Reserviors Filling Process of atural Gas Vehicle Cylinders, World Applied Sciences Journal, Vol 5, o, pp 43-49, 008 [3] Farzaneh-Gord M, Deymi-Dashtebayaz M, Rahbari H R, Studying effects of storage types on performance of CG filling stations, Journal of atural Gas Science and Engineering, Vol 3, o, pp , 0 [4] Farzaneh-Gord M, Deymi-Dashtebayaz M, Rahbari H R, Optimising Compressed atural Gas filling stations reservoir pressure based on thermodynamic analysis, International Journal of Exergy, Vol 0, o 3, pp 99-30, 0 RD 0 {? R : 7 G0 [5] 7 4Ge 4? :; V S / RD /P R5P 8 / 7 / 3 0 ]? J: RCG f 0-03 DK 6 9 R? 3 /0-8ƒ 39 [6] Khamforoush M, Moosavi R, Hatami T, Compressed natural gas behavior in a natural gas vehicle fuel tank during fast filling process: Mathematical modeling, thermodynamic analysis, and optimization, Journal of atural Gas Science and Engineering, Vol 0, o 0, pp -3, 04 [7] Deymi-Dashtebayaz M, Farzaneh-Gord M, Rahbari H R, Studying transmission of fuel storage bank to GV cylinder in CG fast filling station, Journal of the Brazilian Society of BCD /L W 0 A 4? 4? 7 0 O` /?? CH 7 40 A V 3 7f 4e :? O, QH Q 7 \ 9? V J J? : _C u,? Q 7 \ / JoR8? R8 / ZR 4? (7 / ZR [ C re- /? W ]/ C JoR8? 55/ kwh A Q 7 \ J: /6 kwh 7 7/ / ZR [ / &)4T Me 5? - RA C 4 H - ( 4/ 7 4/) 4 K 8 (m ) A L O I 6 (kj/kg K) S - x (kj/kg K) S _,A x (m) jh I 6 j i j i j i G 7 t O i yp [e- t -R8 U O i bj6 yp [e- ` (m/s ) f? :H G 7 t (kj/kg) Z G u P/ I 5 i zg [e- G MR8 G/ (m) L; (kg/s) (kg/kmol) 4 u5e G : (kw) (bar) - LC 8 A3-5 R -6 A B c p c v D f g G h k kwh K l L M /L > / 4? P :H L Q

9 RD O7 H ; I:/ y Mechanical Sciences and Engineering, Vol 34, pp , 0 [8] Khadem J, Saadat-Targhi M, Farzaneh-Gord M, Mathematical modeling of fast filling process at CG refueling stations considering connecting pipes, Journal of atural Gas Science and Engineering, Vol 6, o 0, pp 76-84, 05 [9] Saadat-Targhi M, Khadem J, Farzaneh-Gord M, Thermodynamic analysis of a CG refueling station considering the reciprocating compressor, Journal of atural Gas Science and Engineering, Vol 9, pp , 06 [0] Menon E S, Transmission Pipeline alculations and Simulations Manual: Elsevier Science, 04 [] Starling K E, A G A O S T M Committee, Compressibility and Super compressibility for atural Gas and Other Hydrocarbon Gases: Operating Section, American Gas Association, 986 George D, CG Sampling, atural gas sampling technology conference, ew Orleans, Louisiana, 04, pp

Determining the Optimal Performance of Compressed Natural Gas (CNG) Station Based on PSO Algorithm

Determining the Optimal Performance of Compressed Natural Gas (CNG) Station Based on PSO Algorithm Research Article Journal of Energy Management and Technology (JEMT) Vol. 2, Issue 3 39 Determining the Optimal Performance of Compressed Natural Gas (CNG) Station Based on PSO Algorithm H.YAZDANI 1 AND

More information

P a g e 5 1 of R e p o r t P B 4 / 0 9

P a g e 5 1 of R e p o r t P B 4 / 0 9 P a g e 5 1 of R e p o r t P B 4 / 0 9 J A R T a l s o c o n c l u d e d t h a t a l t h o u g h t h e i n t e n t o f N e l s o n s r e h a b i l i t a t i o n p l a n i s t o e n h a n c e c o n n e

More information

Chapter 5: The First Law of Thermodynamics: Closed Systems

Chapter 5: The First Law of Thermodynamics: Closed Systems Chapter 5: The First Law of Thermodynamics: Closed Systems The first law of thermodynamics can be simply stated as follows: during an interaction between a system and its surroundings, the amount of energy

More information

ENGG 3260: Thermodynamics. Home Assignment 1 (Chapter 1) (Answer)

ENGG 3260: Thermodynamics. Home Assignment 1 (Chapter 1) (Answer) ENGG 360: Thermodynamics Home Assignment 1 (Chapter 1) (Answer) 1. Why does a bicyclist pick up speed on a downhill road even when he is not pedaling? Does this violate the conservation of energy principle?

More information

T h e C S E T I P r o j e c t

T h e C S E T I P r o j e c t T h e P r o j e c t T H E P R O J E C T T A B L E O F C O N T E N T S A r t i c l e P a g e C o m p r e h e n s i v e A s s es s m e n t o f t h e U F O / E T I P h e n o m e n o n M a y 1 9 9 1 1 E T

More information

ME Thermodynamics I

ME Thermodynamics I Homework - Week 01 HW-01 (25 points) Given: 5 Schematic of the solar cell/solar panel Find: 5 Identify the system and the heat/work interactions associated with it. Show the direction of the interactions.

More information

Parts Manual. EPIC II Critical Care Bed REF 2031

Parts Manual. EPIC II Critical Care Bed REF 2031 EPIC II Critical Care Bed REF 2031 Parts Manual For parts or technical assistance call: USA: 1-800-327-0770 2013/05 B.0 2031-109-006 REV B www.stryker.com Table of Contents English Product Labels... 4

More information

Dishwasher. Heater. Homework Solutions ME Thermodynamics I Spring HW-1 (25 points)

Dishwasher. Heater. Homework Solutions ME Thermodynamics I Spring HW-1 (25 points) HW-1 (25 points) (a) Given: 1 for writing given, find, EFD, etc., Schematic of a household piping system Find: Identify system and location on the system boundary where the system interacts with the environment

More information

The First Law of Thermodynamics. By: Yidnekachew Messele

The First Law of Thermodynamics. By: Yidnekachew Messele The First Law of Thermodynamics By: Yidnekachew Messele It is the law that relates the various forms of energies for system of different types. It is simply the expression of the conservation of energy

More information

Fuel, Air, and Combustion Thermodynamics

Fuel, Air, and Combustion Thermodynamics Chapter 3 Fuel, Air, and Combustion Thermodynamics 3.1) What is the molecular weight, enthalpy (kj/kg), and entropy (kj/kg K) of a gas mixture at P = 1000 kpa and T = 500 K, if the mixture contains the

More information

THERMODYNAMICS, FLUID AND PLANT PROCESSES. The tutorials are drawn from other subjects so the solutions are identified by the appropriate tutorial.

THERMODYNAMICS, FLUID AND PLANT PROCESSES. The tutorials are drawn from other subjects so the solutions are identified by the appropriate tutorial. THERMODYNAMICS, FLUID AND PLANT PROCESSES The tutorials are drawn from other subjects so the solutions are identified by the appropriate tutorial. THERMODYNAMICS TUTORIAL 2 THERMODYNAMIC PRINCIPLES SAE

More information

176 5 t h Fl oo r. 337 P o ly me r Ma te ri al s

176 5 t h Fl oo r. 337 P o ly me r Ma te ri al s A g la di ou s F. L. 462 E l ec tr on ic D ev el op me nt A i ng er A.W.S. 371 C. A. M. A l ex an de r 236 A d mi ni st ra ti on R. H. (M rs ) A n dr ew s P. V. 326 O p ti ca l Tr an sm is si on A p ps

More information

Common Terms, Definitions and Conversion Factors

Common Terms, Definitions and Conversion Factors 1 Common Terms, Definitions and Conversion Factors 1. Force: A force is a push or pull upon an object resulting from the object s interaction with another object. It is defined as Where F = m a F = Force

More information

THERMODYNAMICS, FLUID AND PLANT PROCESSES. The tutorials are drawn from other subjects so the solutions are identified by the appropriate tutorial.

THERMODYNAMICS, FLUID AND PLANT PROCESSES. The tutorials are drawn from other subjects so the solutions are identified by the appropriate tutorial. THERMODYNAMICS, FLUID AND PLANT PROCESSES The tutorials are drawn from other subjects so the solutions are identified by the appropriate tutorial. THERMODYNAMICS TUTORIAL 1 LIQUIDS VAPOURS - GASES SAE

More information

TankExampleNov2016. Table of contents. Layout

TankExampleNov2016. Table of contents. Layout Table of contents Task... 2 Calculation of heat loss of storage tanks... 3 Properties ambient air Properties of air... 7 Heat transfer outside, roof Heat transfer in flow past a plane wall... 8 Properties

More information

Thermodynamics Introduction and Basic Concepts

Thermodynamics Introduction and Basic Concepts Thermodynamics Introduction and Basic Concepts by Asst. Prof. Channarong Asavatesanupap Mechanical Engineering Department Faculty of Engineering Thammasat University 2 What is Thermodynamics? Thermodynamics

More information

Two mark questions and answers UNIT II SECOND LAW 1. Define Clausius statement. It is impossible for a self-acting machine working in a cyclic process, to transfer heat from a body at lower temperature

More information

Week 5. Energy Analysis of Closed Systems. GENESYS Laboratory

Week 5. Energy Analysis of Closed Systems. GENESYS Laboratory Week 5. Energy Analysis of Closed Systems Objectives 1. Examine the moving boundary work or PdV work commonly encountered in reciprocating devices such as automotive engines and compressors 2. Identify

More information

Dr Ali Jawarneh. Hashemite University

Dr Ali Jawarneh. Hashemite University Dr Ali Jawarneh Department of Mechanical Engineering Hashemite University Examine the moving boundary work or P d work commonly encountered in reciprocating devices such as automotive engines and compressors.

More information

University of Rome Tor Vergata

University of Rome Tor Vergata University of Rome Tor Vergata Faculty of Engineering Department of Industrial Engineering THERMODYNAMIC AND HEAT TRANSFER HEAT TRANSFER dr. G. Bovesecchi gianluigi.bovesecchi@gmail.com 06-7259-727 (7249)

More information

A L A BA M A L A W R E V IE W

A L A BA M A L A W R E V IE W A L A BA M A L A W R E V IE W Volume 52 Fall 2000 Number 1 B E F O R E D I S A B I L I T Y C I V I L R I G HT S : C I V I L W A R P E N S I O N S A N D TH E P O L I T I C S O F D I S A B I L I T Y I N

More information

Trade Patterns, Production networks, and Trade and employment in the Asia-US region

Trade Patterns, Production networks, and Trade and employment in the Asia-US region Trade Patterns, Production networks, and Trade and employment in the Asia-U region atoshi Inomata Institute of Developing Economies ETRO Development of cross-national production linkages, 1985-2005 1985

More information

MAE 11. Homework 8: Solutions 11/30/2018

MAE 11. Homework 8: Solutions 11/30/2018 MAE 11 Homework 8: Solutions 11/30/2018 MAE 11 Fall 2018 HW #8 Due: Friday, November 30 (beginning of class at 12:00p) Requirements:: Include T s diagram for all cycles. Also include p v diagrams for Ch

More information

Answer Key THERMODYNAMICS TEST (a) 33. (d) 17. (c) 1. (a) 25. (a) 2. (b) 10. (d) 34. (b) 26. (c) 18. (d) 11. (c) 3. (d) 35. (c) 4. (d) 19.

Answer Key THERMODYNAMICS TEST (a) 33. (d) 17. (c) 1. (a) 25. (a) 2. (b) 10. (d) 34. (b) 26. (c) 18. (d) 11. (c) 3. (d) 35. (c) 4. (d) 19. HERMODYNAMICS ES Answer Key. (a) 9. (a) 7. (c) 5. (a). (d). (b) 0. (d) 8. (d) 6. (c) 4. (b). (d). (c) 9. (b) 7. (c) 5. (c) 4. (d). (a) 0. (b) 8. (b) 6. (b) 5. (b). (d). (a) 9. (a) 7. (b) 6. (a) 4. (d).

More information

AME 436. Energy and Propulsion. Lecture 11 Propulsion 1: Thrust and aircraft range

AME 436. Energy and Propulsion. Lecture 11 Propulsion 1: Thrust and aircraft range AME 436 Energy and Propulsion Lecture 11 Propulsion 1: Thrust and aircraft range Outline!!!!! Why gas turbines? Computation of thrust Propulsive, thermal and overall efficiency Specific thrust, thrust

More information

Massachusetts Institute of Technology Physics Department

Massachusetts Institute of Technology Physics Department Massachusetts Institute of Technology Physics Department Physics 8.21 Fall 2011 Physics of Energy October 4, 2011 Quiz 1 Instructions Problem Points 1 30 2 45 3 25 4 (+ 20) Total 100 You must do problems

More information

First Law of Thermodynamics

First Law of Thermodynamics First Law of Thermodynamics During an interaction between a system and its surroundings, the amount of energy gained by the system must be exactly equal to the amount of energy lost by the surroundings.

More information

Readings for this homework assignment and upcoming lectures

Readings for this homework assignment and upcoming lectures Homework #3 (group) Tuesday, February 13 by 4:00 pm 5290 exercises (individual) Thursday, February 15 by 4:00 pm extra credit (individual) Thursday, February 15 by 4:00 pm Readings for this homework assignment

More information

P a g e 3 6 of R e p o r t P B 4 / 0 9

P a g e 3 6 of R e p o r t P B 4 / 0 9 P a g e 3 6 of R e p o r t P B 4 / 0 9 p r o t e c t h um a n h e a l t h a n d p r o p e r t y fr om t h e d a n g e rs i n h e r e n t i n m i n i n g o p e r a t i o n s s u c h a s a q u a r r y. J

More information

PTT 277/3 APPLIED THERMODYNAMICS SEM 1 (2013/2014)

PTT 277/3 APPLIED THERMODYNAMICS SEM 1 (2013/2014) PTT 77/3 APPLIED THERMODYNAMICS SEM 1 (013/014) 1 Energy can exist in numerous forms: Thermal Mechanical Kinetic Potential Electric Magnetic Chemical Nuclear The total energy of a system on a unit mass:

More information

Two mark questions and answers UNIT I BASIC CONCEPT AND FIRST LAW SVCET

Two mark questions and answers UNIT I BASIC CONCEPT AND FIRST LAW SVCET Two mark questions and answers UNIT I BASIC CONCEPT AND FIRST LAW 1. What do you understand by pure substance? A pure substance is defined as one that is homogeneous and invariable in chemical composition

More information

Isentropic Efficiency in Engineering Thermodynamics

Isentropic Efficiency in Engineering Thermodynamics June 21, 2010 Isentropic Efficiency in Engineering Thermodynamics Introduction This article is a summary of selected parts of chapters 4, 5 and 6 in the textbook by Moran and Shapiro (2008. The intent

More information

Why do we need to study thermodynamics? Examples of practical thermodynamic devices:

Why do we need to study thermodynamics? Examples of practical thermodynamic devices: Why do we need to study thermodynamics? Knowledge of thermodynamics is required to design any device involving the interchange between heat and work, or the conversion of material to produce heat (combustion).

More information

T098. c Dr. Md. Zahurul Haq (BUET) First Law of Thermodynamics ME 201 (2012) 2 / 26

T098. c Dr. Md. Zahurul Haq (BUET) First Law of Thermodynamics ME 201 (2012) 2 / 26 Conservation of Energy for a Closed System Dr. Md. Zahurul Haq Professor Department of Mechanical Engineering Bangladesh University of Engineering & Technology (BUET Dhaka-, Bangladesh zahurul@me.buet.ac.bd

More information

c Dr. Md. Zahurul Haq (BUET) Thermodynamic Processes & Efficiency ME 6101 (2017) 2 / 25 T145 = Q + W cv + i h 2 = h (V2 1 V 2 2)

c Dr. Md. Zahurul Haq (BUET) Thermodynamic Processes & Efficiency ME 6101 (2017) 2 / 25 T145 = Q + W cv + i h 2 = h (V2 1 V 2 2) Thermodynamic Processes & Isentropic Efficiency Dr. Md. Zahurul Haq Professor Department of Mechanical Engineering Bangladesh University of Engineering & Technology (BUET Dhaka-1000, Bangladesh zahurul@me.buet.ac.bd

More information

Software Process Models there are many process model s in th e li t e ra t u re, s om e a r e prescriptions and some are descriptions you need to mode

Software Process Models there are many process model s in th e li t e ra t u re, s om e a r e prescriptions and some are descriptions you need to mode Unit 2 : Software Process O b j ec t i ve This unit introduces software systems engineering through a discussion of software processes and their principal characteristics. In order to achieve the desireable

More information

MODULE CODE: ENGG08021 INTRODUCTION TO THERMOFLUIDS. Date: 15 January 2016 Time: 10:00 12:00

MODULE CODE: ENGG08021 INTRODUCTION TO THERMOFLUIDS. Date: 15 January 2016 Time: 10:00 12:00 School of Engineering & Computing Session 2015-16 Paisley Campus Trimester 1 MODULE CODE: ENGG08021 INTRODUCTION TO THERMOFLUIDS Date: 15 January 2016 Time: 10:00 12:00 Attempt FOUR QUESTIONS IN TOTAL

More information

MAE 320 THERODYNAMICS FINAL EXAM - Practice. Name: You are allowed three sheets of notes.

MAE 320 THERODYNAMICS FINAL EXAM - Practice. Name: You are allowed three sheets of notes. 50 MAE 320 THERODYNAMICS FINAL EXAM - Practice Name: You are allowed three sheets of notes. 1. Fill in the blanks for each of the two (Carnot) cycles below. (a) 5 a) Heat engine or Heat pump/refrigerator

More information

1. (10) Calorically perfect ideal air at 300 K, 100 kpa, 1000 m/s, is brought to rest isentropically. Determine its final temperature.

1. (10) Calorically perfect ideal air at 300 K, 100 kpa, 1000 m/s, is brought to rest isentropically. Determine its final temperature. AME 5053 Intermediate Thermodynamics Examination Prof J M Powers 30 September 0 0 Calorically perfect ideal air at 300 K, 00 kpa, 000 m/s, is brought to rest isentropically Determine its final temperature

More information

Section 2. Energy Fundamentals

Section 2. Energy Fundamentals Section 2 Energy Fundamentals 1 Energy Fundamentals Open and Closed Systems First Law of Thermodynamics Second Law of Thermodynamics Examples of heat engines and efficiency Heat Transfer Conduction, Convection,

More information

I. (20%) Answer the following True (T) or False (F). If false, explain why for full credit.

I. (20%) Answer the following True (T) or False (F). If false, explain why for full credit. I. (20%) Answer the following True (T) or False (F). If false, explain why for full credit. Both the Kelvin and Fahrenheit scales are absolute temperature scales. Specific volume, v, is an intensive property,

More information

PROPERTIES OF FLUIDS

PROPERTIES OF FLUIDS Unit - I Chapter - PROPERTIES OF FLUIDS Solutions of Examples for Practice Example.9 : Given data : u = y y, = 8 Poise = 0.8 Pa-s To find : Shear stress. Step - : Calculate the shear stress at various

More information

THE METHOD OF THE WORKING FLUID SELECTION FOR ORGANIC RANKINE CYCLE (ORC) SYSTEM WITH VOLUMETRIC EXPANDER. * Corresponding Author ABSTRACT

THE METHOD OF THE WORKING FLUID SELECTION FOR ORGANIC RANKINE CYCLE (ORC) SYSTEM WITH VOLUMETRIC EXPANDER. * Corresponding Author ABSTRACT Paper ID: 79, Page 1 THE METHOD OF THE WORKING FLUID SELECTION FOR ORGANIC RANKINE CYCLE (ORC) SYSTEM WITH VOLUMETRIC EXPANDER Piotr Kolasiński* 1 1 Wrocław University of Technology, Department of Thermodynamics,

More information

CNG measuring systems for vehicles

CNG measuring systems for vehicles CNG measuring systems for vehicles Sistemas de medición de GNC de uso vehicular Part 3 Review (1) METROLOGY - Accuracy - Trueness - Precision - Error - Uncertainty, Type A and Type B - Standard deviation

More information

EXAM # 1 CIRCLE YOUR LECTURE BELOW: 8:30 am 11:30 am 2:30 pm Prof. Memon Prof. Naik Prof. Lucht INSTRUCTIONS

EXAM # 1 CIRCLE YOUR LECTURE BELOW: 8:30 am 11:30 am 2:30 pm Prof. Memon Prof. Naik Prof. Lucht INSTRUCTIONS Last Name First Name CIRCLE YOUR LECTURE BELOW: 8: am : am : pm Prof. Memon Prof. Naik Prof. Lucht EXAM # INSTRUCTIONS. This is a closed book examination. An equation sheet and all needed property tables

More information

Chapter 5. Mass and Energy Analysis of Control Volumes

Chapter 5. Mass and Energy Analysis of Control Volumes Chapter 5 Mass and Energy Analysis of Control Volumes Conservation Principles for Control volumes The conservation of mass and the conservation of energy principles for open systems (or control volumes)

More information

ERRATA SHEET Thermodynamics: An Engineering Approach 8th Edition Yunus A. Çengel, Michael A. Boles McGraw-Hill, 2015

ERRATA SHEET Thermodynamics: An Engineering Approach 8th Edition Yunus A. Çengel, Michael A. Boles McGraw-Hill, 2015 ERRATA SHEET Thermodynamics: An Engineering Approach 8th Edition Yunus A. Çengel, Michael A. Boles McGraw-Hill, 2015 December 2015 This errata includes all corrections since the first printing of the book.

More information

Teaching schedule *15 18

Teaching schedule *15 18 Teaching schedule Session *15 18 19 21 22 24 Topics 5. Gas power cycles Basic considerations in the analysis of power cycle; Carnot cycle; Air standard cycle; Reciprocating engines; Otto cycle; Diesel

More information

ME Thermodynamics I. Lecture Notes and Example Problems

ME Thermodynamics I. Lecture Notes and Example Problems ME 227.3 Thermodynamics I Lecture Notes and Example Problems James D. Bugg September 2018 Department of Mechanical Engineering Introduction Part I: Lecture Notes This part contains handout versions of

More information

Fundamentals of Thermodynamics. Chapter 8. Exergy

Fundamentals of Thermodynamics. Chapter 8. Exergy Fundamentals of Thermodynamics Chapter 8 Exergy Exergy Availability, available energy Anergy Unavailable energy Irreversible energy, reversible work, and irreversibility Exergy analysis : Pure Thermodynamics

More information

(Refer Slide Time: 0:15)

(Refer Slide Time: 0:15) (Refer Slide Time: 0:15) Engineering Thermodynamics Professor Jayant K Singh Department of Chemical Engineering Indian Institute of Technology Kanpur Lecture 18 Internal energy, enthalpy, and specific

More information

ME Thermodynamics I

ME Thermodynamics I HW-03 (25 points) i) Given: for writing Given, Find, Basic equations Rigid tank containing nitrogen gas in two sections initially separated by a membrane. Find: Initial density (kg/m3) of nitrogen gas

More information

Honors Physics. Notes Nov 16, 20 Heat. Persans 1

Honors Physics. Notes Nov 16, 20 Heat. Persans 1 Honors Physics Notes Nov 16, 20 Heat Persans 1 Properties of solids Persans 2 Persans 3 Vibrations of atoms in crystalline solids Assuming only nearest neighbor interactions (+Hooke's law) F = C( u! u

More information

ENT 254: Applied Thermodynamics

ENT 254: Applied Thermodynamics ENT 54: Applied Thermodynamics Mr. Azizul bin Mohamad Mechanical Engineering Program School of Mechatronic Engineering Universiti Malaysia Perlis (UniMAP) azizul@unimap.edu.my 019-4747351 04-9798679 Chapter

More information

Executive Committee and Officers ( )

Executive Committee and Officers ( ) Gifted and Talented International V o l u m e 2 4, N u m b e r 2, D e c e m b e r, 2 0 0 9. G i f t e d a n d T a l e n t e d I n t e r n a t i o n a2 l 4 ( 2), D e c e m b e r, 2 0 0 9. 1 T h e W o r

More information

CHAPTER. The First Law of Thermodynamics: Closed Systems

CHAPTER. The First Law of Thermodynamics: Closed Systems CHAPTER 3 The First Law of Thermodynamics: Closed Systems Closed system Energy can cross the boundary of a closed system in two forms: Heat and work FIGURE 3-1 Specifying the directions of heat and work.

More information

0 o C. H vap. H evap

0 o C. H vap. H evap Solution. Energy P (00 ) Pν x 0 5 ρ 850,4 J kg - J kg Power kg s 000,4 600 70 W Solution. 00 o C H evap H vap 0 o C H liq 00 t H liq (4. x0 t ) dt 4.t x0 0 40 0 40 kj kg - H evap 40,68 J mol - (From Appendix

More information

Chapter 7. Entropy. by Asst.Prof. Dr.Woranee Paengjuntuek and Asst. Prof. Dr.Worarattana Pattaraprakorn

Chapter 7. Entropy. by Asst.Prof. Dr.Woranee Paengjuntuek and Asst. Prof. Dr.Worarattana Pattaraprakorn Chapter 7 Entropy by Asst.Prof. Dr.Woranee Paengjuntuek and Asst. Prof. Dr.Worarattana Pattaraprakorn Reference: Cengel, Yunus A. and Michael A. Boles, Thermodynamics: An Engineering Approach, 5th ed.,

More information

Thermodynamics I Spring 1432/1433H (2011/2012H) Saturday, Wednesday 8:00am - 10:00am & Monday 8:00am - 9:00am MEP 261 Class ZA

Thermodynamics I Spring 1432/1433H (2011/2012H) Saturday, Wednesday 8:00am - 10:00am & Monday 8:00am - 9:00am MEP 261 Class ZA Thermodynamics I Spring 1432/1433H (2011/2012H) Saturday, Wednesday 8:00am - 10:00am & Monday 8:00am - 9:00am MEP 261 Class ZA Dr. Walid A. Aissa Associate Professor, Mech. Engg. Dept. Faculty of Engineering

More information

Workshop Paris, November 2006

Workshop Paris, November 2006 SAFe and Efficient hydrocarbon oxidation processes by KINetics and Explosion expertise and development of computational process engineering tools Project No. EVG1-CT-2002-00072 Workshop Paris, November

More information

1. Basic state values of matter

1. Basic state values of matter 1. Basic state values of matter Example 1.1 The pressure inside a boiler is p p = 115.10 5 Pa and p v = 9.44.10 4 Pa inside a condenser. Calculate the absolute pressure inside the boiler and condenser

More information

CHAPTER 8 ENTROPY. Blank

CHAPTER 8 ENTROPY. Blank CHAPER 8 ENROPY Blank SONNAG/BORGNAKKE SUDY PROBLEM 8-8. A heat engine efficiency from the inequality of Clausius Consider an actual heat engine with efficiency of η working between reservoirs at and L.

More information

UNIT I Basic concepts and Work & Heat Transfer

UNIT I Basic concepts and Work & Heat Transfer SIDDHARTH GROUP OF INSTITUTIONS :: PUTTUR Siddharth Nagar, Narayanavanam Road 517583 QUESTION BANK (DESCRIPTIVE) Subject with Code: Engineering Thermodynamics (16ME307) Year & Sem: II-B. Tech & II-Sem

More information

Thermodynamics is the Science of Energy and Entropy

Thermodynamics is the Science of Energy and Entropy Definition of Thermodynamics: Thermodynamics is the Science of Energy and Entropy - Some definitions. - The zeroth law. - Properties of pure substances. - Ideal gas law. - Entropy and the second law. Some

More information

Chapter 1: 20, 23, 35, 41, 68, 71, 76, 77, 80, 85, 90, 101, 103 and 104.

Chapter 1: 20, 23, 35, 41, 68, 71, 76, 77, 80, 85, 90, 101, 103 and 104. Chapter 1: 0, 3, 35, 1, 68, 71, 76, 77, 80, 85, 90, 101, 103 and 10. 1-0 The filament of a 150 W incandescent lamp is 5 cm long and has a diameter of 0.5 mm. The heat flux on the surface of the filament,

More information

Today lecture. 1. Entropy change in an isolated system 2. Exergy

Today lecture. 1. Entropy change in an isolated system 2. Exergy Today lecture 1. Entropy change in an isolated system. Exergy - What is exergy? - Reversible Work & Irreversibility - Second-Law Efficiency - Exergy change of a system For a fixed mass For a flow stream

More information

The simplified model now consists only of Eq. 5. Degrees of freedom for the simplified model: 2-1

The simplified model now consists only of Eq. 5. Degrees of freedom for the simplified model: 2-1 . a) Overall mass balance: d( ρv ) Energy balance: = w + w w () d V T Tref C = wc ( T Tref ) + wc( T Tref ) w C T Because ρ = constant and ( Tref ) V = V = constant, Eq. becomes: () w = + () w w b) From

More information

SHRI RAMSWAROOP MEMORIAL COLLEGE OF ENGG. & MANAGEMENT

SHRI RAMSWAROOP MEMORIAL COLLEGE OF ENGG. & MANAGEMENT B.Tech. [SEM III (ME-31, 32, 33,34,35 & 36)] QUIZ TEST-1 Time: 1 Hour THERMODYNAMICS Max. Marks: 30 (EME-303) Note: Attempt All Questions. Q1) 2 kg of an ideal gas is compressed adiabatically from pressure

More information

Mechanics 4. Work, Power, Energy Linear Momentum Conservation Laws. Work W

Mechanics 4. Work, Power, Energy Linear Momentum Conservation Laws. Work W Mechanics 4 Work, Power, Energy Linear Momentum Conservation Laws Work W If a force F acts on a body and the body moves a distance s in the direction of the force, the work W done by the force F is defined

More information

To receive full credit all work must be clearly provided. Please use units in all answers.

To receive full credit all work must be clearly provided. Please use units in all answers. Exam is Open Textbook, Open Class Notes, Computers can be used (Computer limited to class notes, lectures, homework, book material, calculator, conversion utilities, etc. No searching for similar problems

More information

Name: I have observed the honor code and have neither given nor received aid on this exam.

Name: I have observed the honor code and have neither given nor received aid on this exam. ME 235 FINAL EXAM, ecember 16, 2011 K. Kurabayashi and. Siegel, ME ept. Exam Rules: Open Book and one page of notes allowed. There are 4 problems. Solve each problem on a separate page. Name: I have observed

More information

Chapter 8. Conservation of Energy

Chapter 8. Conservation of Energy Chapter 8 Conservation of Energy Energy Review Kinetic Energy Associated with movement of members of a system Potential Energy Determined by the configuration of the system Gravitational and Elastic Potential

More information

7. Development of the 2nd Law

7. Development of the 2nd Law 7-1 7. Development of the 2nd Law 7.1 1st Law Limitations The 1 st Law describes energy accounting. Once we have a process (or string of processes) we can calculate the relevant energy interactions. The

More information

MAE 110A. Homework 3: Solutions 10/20/2017

MAE 110A. Homework 3: Solutions 10/20/2017 MAE 110A Homework 3: Solutions 10/20/2017 3.10: For H 2O, determine the specified property at the indicated state. Locate the state on a sketch of the T-v diagram. Given a) T 140 C, v 0.5 m 3 kg b) p 30MPa,

More information

CHAPTER 4 The Integral Forms of the Fundamental Laws

CHAPTER 4 The Integral Forms of the Fundamental Laws CHAPTER 4 The Integral Forms of the Fundamental Laws FE-type Exam Review Problems: Problems 4- to 4-5 4 (B) 4 (D) 4 (A) 44 (D) p m ρa A π 4 7 87 kg/s RT 87 9 Refer to the circle of Problem 47: 757 Q A

More information

ECE309 INTRODUCTION TO THERMODYNAMICS & HEAT TRANSFER. 20 June 2005

ECE309 INTRODUCTION TO THERMODYNAMICS & HEAT TRANSFER. 20 June 2005 ECE309 INTRODUCTION TO THERMODYNAMICS & HEAT TRANSFER 20 June 2005 Midterm Examination R. Culham & M. Bahrami This is a 90 minute, closed-book examination. You are permitted to use one 8.5 in. 11 in. crib

More information

Thermodynamics I Spring 1432/1433H (2011/2012H) Saturday, Wednesday 8:00am - 10:00am & Monday 8:00am - 9:00am MEP 261 Class ZA

Thermodynamics I Spring 1432/1433H (2011/2012H) Saturday, Wednesday 8:00am - 10:00am & Monday 8:00am - 9:00am MEP 261 Class ZA Thermodynamics I Spring 1432/1433H (2011/2012H) Saturday, Wednesday 8:00am - 10:00am & Monday 8:00am - 9:00am MEP 261 Class ZA Dr. Walid A. Aissa Associate Professor, Mech. Engg. Dept. Faculty of Engineering

More information

CHAPTER 5 MASS AND ENERGY ANALYSIS OF CONTROL VOLUMES

CHAPTER 5 MASS AND ENERGY ANALYSIS OF CONTROL VOLUMES Thermodynamics: An Engineering Approach 8th Edition in SI Units Yunus A. Çengel, Michael A. Boles McGraw-Hill, 2015 CHAPTER 5 MASS AND ENERGY ANALYSIS OF CONTROL VOLUMES Lecture slides by Dr. Fawzi Elfghi

More information

ENERGY ANALYSIS OF CLOSED SYSTEMS

ENERGY ANALYSIS OF CLOSED SYSTEMS Thermodynamics: An Engineering Approach Seventh Edition in SI Units Yunus A. Cengel, Michael A. Boles McGraw-Hill, 2011 Chapter 4 ENERGY ANALYSIS OF CLOSED SYSTEMS Mehmet Kanoglu University of Gaziantep

More information

Where F1 is the force and dl1 is the infinitesimal displacement, but F1 = p1a1

Where F1 is the force and dl1 is the infinitesimal displacement, but F1 = p1a1 In order to force the fluid to flow across the boundary of the system against a pressure p1, work is done on the boundary of the system. The amount of work done is dw = - F1.dl1, Where F1 is the force

More information

Introduction CHAPTER Prime Movers. 1.2 Sources of Energy

Introduction CHAPTER Prime Movers. 1.2 Sources of Energy Introduction CHAPTER 1 1.1 Prime Movers Prime mover is a device which converts natural source of energy into mechanical work to drive machines for various applications. In olden days, man had to depend

More information

I M P O R T A N T S A F E T Y I N S T R U C T I O N S W h e n u s i n g t h i s e l e c t r o n i c d e v i c e, b a s i c p r e c a u t i o n s s h o

I M P O R T A N T S A F E T Y I N S T R U C T I O N S W h e n u s i n g t h i s e l e c t r o n i c d e v i c e, b a s i c p r e c a u t i o n s s h o I M P O R T A N T S A F E T Y I N S T R U C T I O N S W h e n u s i n g t h i s e l e c t r o n i c d e v i c e, b a s i c p r e c a u t i o n s s h o u l d a l w a y s b e t a k e n, i n c l u d f o l

More information

Classification following properties of the system in Intensive and Extensive

Classification following properties of the system in Intensive and Extensive Unit I Classification following properties of the system in Intensive and Extensive Extensive : mass, weight, volume, potential energy, Kinetic energy, Internal energy, entropy, exergy, energy, magnetization

More information

Homework 6 Solar PV Energy MAE 119 W2017 Professor G.R. Tynan

Homework 6 Solar PV Energy MAE 119 W2017 Professor G.R. Tynan Homework 6 Solar PV Energy MAE 119 W2017 Professor G.R. Tynan 1. What is the most likely wavelength and frequency of light emitted from the sun which has a black body temperature of about 6600 deg K? What

More information

Chapter 3 PROPERTIES OF PURE SUBSTANCES. Thermodynamics: An Engineering Approach, 6 th Edition Yunus A. Cengel, Michael A. Boles McGraw-Hill, 2008

Chapter 3 PROPERTIES OF PURE SUBSTANCES. Thermodynamics: An Engineering Approach, 6 th Edition Yunus A. Cengel, Michael A. Boles McGraw-Hill, 2008 Chapter 3 PROPERTIES OF PURE SUBSTANCES Thermodynamics: An Engineering Approach, 6 th Edition Yunus A. Cengel, Michael A. Boles McGraw-Hill, 2008 Objectives Introduce the concept of a pure substance. Discuss

More information

Chapter 1: Basic Definitions, Terminologies and Concepts

Chapter 1: Basic Definitions, Terminologies and Concepts Chapter : Basic Definitions, Terminologies and Concepts ---------------------------------------. UThermodynamics:U It is a basic science that deals with: -. Energy transformation from one form to another..

More information

OH BOY! Story. N a r r a t iv e a n d o bj e c t s th ea t e r Fo r a l l a g e s, fr o m th e a ge of 9

OH BOY! Story. N a r r a t iv e a n d o bj e c t s th ea t e r Fo r a l l a g e s, fr o m th e a ge of 9 OH BOY! O h Boy!, was or igin a lly cr eat ed in F r en ch an d was a m a jor s u cc ess on t h e Fr en ch st a ge f or young au di enc es. It h a s b een s een by ap pr ox i ma t ely 175,000 sp ect at

More information

R13. II B. Tech I Semester Regular Examinations, Jan THERMODYNAMICS (Com. to ME, AE, AME) PART- A

R13. II B. Tech I Semester Regular Examinations, Jan THERMODYNAMICS (Com. to ME, AE, AME) PART- A SET - 1 II B. Tech I Semester Regular Examinations, Jan - 2015 THERMODYNAMICS (Com. to ME, AE, AME) Time: 3 hours Max. Marks: 70 Note 1. Question Paper consists of two parts (Part-A and Part-B) 2. Answer

More information

Dynamic simulation and Control of a CO 2 Compression and Purification Unit for Oxy-Coal-Fired Power Plants

Dynamic simulation and Control of a CO 2 Compression and Purification Unit for Oxy-Coal-Fired Power Plants Dynamic simulation and Control of a CO 2 Compression and Purification Unit for Oxy-Coal-Fired Power Plants Authors A. Chansomwong, K.E. Zanganeh, A. Shafeen, P.L. Douglas,E. Croiset, L.A. Ricardez-Sandoval,

More information

Chapter 4 ENERGY ANALYSIS OF CLOSED SYSTEMS

Chapter 4 ENERGY ANALYSIS OF CLOSED SYSTEMS Thermodynamics: An Engineering Approach Seventh Edition in SI Units Yunus A. Cengel, Michael A. Boles McGraw-Hill, 2011 Chapter 4 ENERGY ANALYSIS OF CLOSED SYSTEMS Copyright The McGraw-Hill Companies,

More information

Answers to Selected Problems

Answers to Selected Problems Answers to Selected Problems 3. (a 68.8 K and 4.65 0 5 Pa; (b at 90 o (horizontal 8.6 K and 4.863 0 5 Pa; (c at 80 o (vertical downward 96.4 K and 5. 0 5 Pa. 3. (a δ Q/ δ t = 3.5 0 8 J/hr [contractor pays]

More information

Compression and Expansion of Fluids

Compression and Expansion of Fluids CH2303 Chemical Engineering Thermodynamics I Unit V Compression and Expansion of Fluids Dr. M. Subramanian 26-Sep-2011 Associate Professor Department of Chemical Engineering Sri Sivasubramaniya Nadar College

More information

Downloaded from

Downloaded from Chapter 12 (Thermodynamics) Multiple Choice Questions Single Correct Answer Type Q1. An ideal gas undergoes four different processes from the same initial state (figure). Four processes are adiabatic,

More information

Consequences of Second Law of Thermodynamics. Entropy. Clausius Inequity

Consequences of Second Law of Thermodynamics. Entropy. Clausius Inequity onsequences of Second Law of hermodynamics Dr. Md. Zahurul Haq Professor Department of Mechanical Engineering Bangladesh University of Engineering & echnology BUE Dhaka-000, Bangladesh zahurul@me.buet.ac.bd

More information

ME 300 Thermodynamics II Exam 1 September 27, :00 p.m. 9:00 p.m.

ME 300 Thermodynamics II Exam 1 September 27, :00 p.m. 9:00 p.m. ME 00 Thermodynamics II Exam 1 September 7, 01 8:00 p.m. 9:00 p.m. Name: Solution Section (Circle One): Sojka Naik 11:0 a.m. 1:0 p.m. Instructions: This is a closed book/notes exam. You may use a calculator.

More information

CHEM 4641 Fall questions worth a total of 32 points. Show your work, except on multiple-choice questions. 1 V α=

CHEM 4641 Fall questions worth a total of 32 points. Show your work, except on multiple-choice questions. 1 V α= Physical Chemistry I Final Exam Name: KEY CHEM 4641 Fall 017 15 questions worth a total of 3 points. Show your work, except on multiple-choice questions. 1 V 1 V α= κt = V T P V P T Gas constant R = 8.314

More information

12/21/2014 7:39 PM. Chapter 2. Energy and the 1st Law of Thermodynamics. Dr. Mohammad Suliman Abuhaiba, PE

12/21/2014 7:39 PM. Chapter 2. Energy and the 1st Law of Thermodynamics. Dr. Mohammad Suliman Abuhaiba, PE Chapter 2 Energy and the 1st Law of Thermodynamics 1 2 Homework Assignment # 2 Problems: 1, 7, 14, 20, 30, 36, 42, 49, 56 Design and open end problem: 2.1D Due Monday 22/12/2014 3 Work and Kinetic Energy

More information

Gestão de Sistemas Energéticos 2017/2018

Gestão de Sistemas Energéticos 2017/2018 Gestão de Sistemas Energéticos 2017/2018 Exergy Analysis Prof. Tânia Sousa taniasousa@tecnico.ulisboa.pt Conceptualizing Chemical Exergy C a H b O c enters the control volume at T 0, p 0. O 2 and CO 2,

More information

In the next lecture...

In the next lecture... 16 1 In the next lecture... Solve problems from Entropy Carnot cycle Exergy Second law efficiency 2 Problem 1 A heat engine receives reversibly 420 kj/cycle of heat from a source at 327 o C and rejects

More information

Discovery Guide. Beautiful, mysterious woman pursued by gunmen. Sounds like a spy story...

Discovery Guide. Beautiful, mysterious woman pursued by gunmen. Sounds like a spy story... Dv G W C T Gp, A T Af Hk T 39 Sp. M Mx Hk p j p v, f M P v...(!) Af Hk T 39 Sp, B,,, UNMISSABLE! T - f 4 p v 150 f-p f x v. Bf, k 4 p v 150. H k f f x? D,,,, v? W k, pf p f p? W f f f? W k k p? T p xp

More information