PTT 277/3 APPLIED THERMODYNAMICS SEM 1 (2013/2014)
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1 PTT 77/3 APPLIED THERMODYNAMICS SEM 1 (013/014) 1
2 Energy can exist in numerous forms: Thermal Mechanical Kinetic Potential Electric Magnetic Chemical Nuclear The total energy of a system on a unit mass: E e (kj/kg) m Their sum constitutes the total energy, E of a system Macroscopic forms of energy Related to the motion & the influence of some external effects such as : gravity, magnetion, electricity & surface tension Usually ignored. Kinetic energy, KE The energy that a system possesses as a result of its motion relative to some reference frame. Microscopic forms of energy Those related to the molecular structure of a system and the degree of the molecular activity. Internal energy, U The sum of all the microscopic forms of energy. Potential energy, PE The energy that a system possesses as a result of its elevation in a gravitational field.
3 Kinetic energy, KE Velocity mv KE (kj) Kinetic energy per unit mass: ke V (kj/kg) Potential energy, PE Gravitational acceleration PE mgz (kj) Elevation of the center of gravity of a system relative to some arbitrarily selected reference level Kinetic energy per unit mass: pe gz (kj/kg) Total energy of a system E U KE PE U mv Total energy of a system per unit mass: e u ke pe u V mgz (kj) gz (kj/kg) 3
4 Flow of steam in a pipe m ρv Mass flow rate A V c avg (kg/s) E Energy flow rate m e kw) 4
5 The various forms of microscopic energies that make up sensible energy. The internal energy of a system is the sum of all forms of the microscopic energies Sensible energy The portion of the internal energy of a system associated with the kinetic energies of the molecules. Sensible & latent energy Thermal Energy Latent energy The internal energy associated with the phase of a system. Chemical energy Chemical energy The internal energy associated with the atomic bonds in a molecule. Nuclear energy INTERNAL ENERGY Nuclear energy The tremendous amount of energy associated with the strong bonds within the nucleus of the atom itself. 5
6 Wind Energy A site evaluated for a wind farm is observed to have steady winds at a speed of 8.5 m/s. Determine the wind energy (a) per unit mass, (b) for a mass of 10 kg, and (c) for a flow rate of 1154 kg/s for air. V 8.5 m/s 1J/kg a) e ke 1m /s b) E me (10 kg)(36.1 J/kg) 361J 36.1J/kg 1kW c) E me (1154 kg/s)(36.1 J/kg) 41.7kW 1000 J/s 6
7 The total energy of a system, can be contained or stored in a system, and thus can be viewed as the static forms of energy. The forms of energy not stored in a system can be viewed as: the dynamic forms of energy interactions. are recognized at the system boundary as they cross it Represent the energy gained or lost by a system during a process. The macroscopic kinetic energy is an organized form of energy and is much more useful than the disorganized microscopic kinetic energies of the molecules. The only two forms of energy interactions associated with a closed system are : 1) heat transfer ) work. The difference is An energy interaction is heat transfer if its driving force is a temperature difference. 7 Otherwise it is work.
8 Heat The form of energy that is transferred between two systems (or a system and its surroundings) by virtue of a temperature difference. Temperature difference is the driving force for heat transfer. The larger the temperature difference, the higher is the rate of heat transfer. Energy is recognized as heat transfer only as it crosses the system boundary. Energy can cross the boundaries of a closed system in the form of heat and work. 8
9 Heat transfer per unit mass Q q (kj/kg) m Amount of heat transfer when heat transfer rate changes with time t Q Q dt t 1 (kj) The system is well insulated so that only a negligible amount of heat can pass through the boundary Adiabatic process A process during which there is no heat transfer Both the system and surroundings are at the same temperature and therefore there is no driving force (temp diff) for heat transfer Amount of heat transfer when heat transfer rate is constant Q Q Δt (kj) During an adiabatic process, a system exchanges no heat with its surroundings. 9
10 Kinetic theory: Treats molecules as tiny balls that are in motion and thus possess kinetic energy. Heat: The energy associated with the random motion of atoms and molecules. Heat Transfer Mechanisms Conduction: The transfer of energy from the more energetic particles of a substance to the adjacent less energetic ones as a result of interaction between particles. Convection: The transfer of energy between a solid surface and the adjacent fluid that is in motion, and it involves the combined effects of conduction and fluid motion. Radiation: The transfer of energy due to the emission of electromagnetic waves (or photons). 10
11 Work: The energy transfer associated with a force acting through a distance. A rising piston, a rotating shaft, and an electric wire crossing the system boundaries are all associated with work interactions Work done per unit mass Power is the work done per unit time (kw) Specifying the directions of heat and work. 11
12 The first law of thermodynamics (the conservation of energy principle) provides a sound basis for studying the relationships among the various forms of energy and energy interactions. The first law states that energy can be neither created nor destroyed during a process; it can only change forms. Energy cannot be created or destroyed; it can only change forms. 1
13 13
14 The net change (increase or decrease) in the total energy of the system during a process is equal to the difference between the total energy entering and the total energy leaving the system during that process. (Q in Q out ) + W sh = E system 14
15 E system (Q in Q out ) + W sh = U + KE + PE (Energy Balance for Closed Systems) Internal, kinetic, and potential energy changes 15
16 Energy Balance for Closed Systems Water flows over a waterfall 100 m in height. Take 1 kg of the water as the system, and assume that it does not change energy with its surroundings. (a) What is the potential energy of the water at the top of the falls with respect to the base of the falls? (b) What is the kinetic energy of the water just before it strikes bottom? 16 16
17 The 1 kg of water exchanges no energy with the surroundings. Thus, for each part of the process E system = U + KE + PE = 0 a) Determine the potential energy, PE PE = mg (z z 1 ) = = 1 kg 9.81 m (100-0) m s 981 kg m /s = 981 N.m = 981 J b) Determine the kinetic energy, KE U + KE + PE = 0 During the free fall of the water no mechanism exists for conversion of potential or kinetic energy into internal energy. Thus, U must be zero. = 0 + KE + PE = 0 = 0 + (KE KE 1 ) + (PE PE 1 ) = 0 Let KE 1 and PE = 0 Thus, we get KE = 981 J 17 17
18 Cooling of a Hot Fluid in a Tank A rigid tank contains a hot fluid that is cooled while being stirred by a paddle wheel. Initially, the internal energy of the fluid is 800 kj. During the cooling process, the fluid loses 500 kj of heat, and the paddle wheel does 100 kj of work on the fluid. Determine the final internal energy of the fluid. Neglect the energy stored in the paddle wheel. Ans: U =400 kj 18
19 E in and E out Heat transfer Work transfer Mass flow Energy Balanced for Open Systems: SI unit: (Q in Q out ) + W sh = H + u + g z (kj/kg) English system unit: (Q in Q out ) + W sh = H + u + g z (Btu/Ibm) g c g c The energy content of a control volume can be changed by mass flow as well as heat and work interactions. Energy balance for cycle When E =0, Q net =W net W net,out = Q net,in 19
20 Energy Balance for Open Systems Air at 1 bar and 5 C enters a compressor at low velocity, discharges at 3 bar, and enters a nozzle in which it expands to a final velocity of 600 m/s at the initial conditions of pressure and temperature. If the work of compression is 40 kj per kilogram of air, how much heat must be removed during compression? Write energy balance for open system: Q + W sh = H + u + g z (kj/kg) Assumptions: 1. No enthalpy change, H, of air due to the air returns to its initial temperature and pressure.. The potential energy, PE, is presumed negligible due to no change in elevation involved 3. Neglecting the initial kinetic energy; u 1 Ans: Q= -60 kj/kg 0 0
21 EXAMPLE -11 EXAMPLE
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