Key. Section I 5. B 6. C. Section II 22. D 23. C 24. A 25. D 26. B 27. D 28. D 29. D 30. C 31. A 32. A 33. A 34. C 35. C PEARSON.
|
|
- Alyson Gilbert
- 5 years ago
- Views:
Transcription
1 K Scion I. D. D. D. 5. B D. Scion II. B. B. D. 5. D B 8.. D.. B. D.. 5. B B. B. B. B Scion Ι Gnrl piu Soluions for qusions n :. D.. 5. D 6. B 7. D 8. D. Probbili (h sum no bing qul o 8 Probbili (h sum bing qul o 8 h numbr of ws of slcing wo ingrs on from ch s is 5. h sum cn b 8 whn h ingrs slc r n, 6 n, 8 n, n 8. Probbili h h sum bing 8 quir probbili Wor: S P I N G Logic: 5 7 o: S W P W Similrl, Wor: L S I Logic: 5 7 o: F O F Z P Soluions for qusions n :. o rimburs is o p bck h mon spn. o inmnif is lso o p bck mon (for som loss or mg. Offs is n moun h iminishs or blncs h ffc of n opposi on. I os no mn gurn, s os inmni.. ucous is hrsh or hors. Ohr snonms r, gring, iscorn, jrring or srin. Soluions for qusion 5: 5. Whn w g ino b compn w g ino ho wr or g ino roubl. Ohr iioms o no work in h con. pic of ck is job/sk h is vr s whil bck o h rwing bor mns fil mp h hs o b sr gin. o b roun h bush is o voi spking opnl/ircl bou n issu. hoic (B Soluions. D B D.... D Soluions for qusions 6 o 8:. B. 5. B B. D B 5. D B 6. HI is prlll o h -is. n lin prlll o h -is mus hv is quion of h form consn. HI cn b n of h lins 8 or 7 or. or or or.. 8. (Q 8 8, 7 5. Suppos HI is h lin 8. hn H cn b n of (8, 7, (8, 8, (8, 5. H hs possibl posiions. For ch of hs possibl posiions I cn hv n of h rmining 8 possibl posiions. HI hs 8 7 possibiliis. s plin bov, i similrl follows h whn HI is h lin 7 or 6 or.. 8, HI hs 7 possibiliis in ch cs. ol numbr of possibiliis for HI (7 (7 h ringl is righ ngl H. h -coorin of G mus b h sm s h of H n is -coorin cn b n possibl vlu ohr hn h of H. h -coorin of G hs 7 6 possibiliis. G hs 6 possibl posiions. From ( n ( h ringl GHI hs 6 58 possibl rrngmns i.., 58 ringls cn b form sisfing h givn coniions. lrn Soluion: Givn 8 8 n 7 5 i.. hr r 7 vricl lins n horizonl lins. h numbr of rcngls form wih hs lins is 7. W know h on rcngl givs righ ngl ringls. ol numbr of righ ngl ringls form is In U n PQ, is common. U PQ h bov conclusions mn h hir pir of ngls of boh s mus b qul. h hir ngl of ch 8 (sum of h ohr wo of is ngls. U PQ. U U ( PQ Q
2 Similrl UQ SQ. U QU ( S Q ( S U ( PQ QU QU 8 U 5 QU U 5 U QU U 5 Q U 5 U Q 5 U From ( 8 U 5 m. 8. W hv o slc h bo h is lbl s miur. Now if w g pn, s h bo cnno hv miur, i hs pns. Now h bo which is lbl s pns cnno hv miur. [ If i hppns hn h bo wih lbl pncil mus conin pncils] h bo wih lbl pns hs pncils n h wih pncils hs miur of hm. Soluions for qusion :. Birh fcs r congnil (prsn from birh n no hrir, compulsiv, or congnil (ffbl; frinl.. Mr. Du hs ci o flo h firs grn pr in Ini fr visiing ngln. I is clr h hr is grn pr in ngln n Mr. Du is imprss wih h pr. ssum h cs whr Mr. Du lrn bou h grn pr whil in ngln bu hr is no grn pr in ngln; in such cs, hr woul no b n rlvnc o h visi o ngln. Hnc Ι follows. ccoring o h smn, Mr. Du wns o flo h firs grn pr. I implis h hr cn b svrl grn pris. hr cnno b mor hn on pr wih h sm nm. Hnc, ΙΙ follows. Mr. Du ss his grn woul rplc h rs in Bngl. From his, i cn b conclu h h grn pr in going o b flo in Bngl s wll. Hnc, ΙΙΙ oo follows. hrfor ll follow. Scion ΙΙ lcronics n ommunicion nginring Soluions for qusions o 55: hoic (B. Givn iffrnil quion is ( whr ( ompring ( wih f(, w hv f(,,, ( n sp siz h. h. B lor s sris scon orr mho, w hv, h h (! f(, f(, f f (f(, ( Hnc Subsiuing hs in (, w g. (. (.!.. hoic (B. Givn z i Now z i ( i i. i i (cos i sin i cos i sin i cos n sin ( Squring n ing, w hv ( cos ( sin (cos sin ln. From (, w hv ln ln cos n sin ln cos n ln sin. Givn curv is h lngh of h curv from (, o (8, cos n sin cos n sin π n π; n, ±, ±,. 8 π n π; n, ±, ±,. Givn im (V 7, S V n L(S V h numbr of vcors in S m. lso, hs m vcors r linrl pnn.
3 W know h, n subs of n vcors of n n-imnsionl vcor spc V r linrl pnn. Hnc h ls possibl vlu of m is W know h h r of h ringl wih n B s is jcn sis is B. Givn i j k n B i j k r of h ringl OB B ( i B i j k B From (, j k ( 6 r of h ringl OB 6 sq.unis. ωo 6. ( ω Qos ω ωo N I ; N os I Q os 6 ω ; Qos o L Qos 5 ω o L.mH 67µF O Im σ 7. VD ( 7(7 ( ( (7 5V hoic (B 8. F(s L{f(} - s s - h givn funcion is bilrl O in bwn - o. - < σ < K -. N N. F ϑ ϑ From h givn F -ϑ.5v N N hn F -ϑ? -[ F -ϑ ] K -( - K N N N - (I N F ϑ ( F - K ϑ ( -ϑ K - - F. ( V F ϑ.v. ppling KVL o h our loop. VDD D ID VDS S.ID VDS vols IP η.q. sponsivi W Po h.f Whr Ip phoo currn gnr Po incin opicl powr f frqunc of incin phoon h plnk s consn h J/s. from h givn η.7 Po.5 - J q /W hoic (B B o/p Y. b B n b B B b ( B B b ( B.B ( B. B B B Y B.B B B b Y. From h givn p 8ns N N n n o consruc MOD - rippl counr, w rquir flipflops. W know fclk n p 6 Hz 8 fclk.5mhz Bu w rquir h frqunc of h counr MSB (Q I oprs m MOD -. So o/p frqunc f ck.6mhz
4 . ol siz of mmor n.. K in bis Whr n ol no. of mmor chips K no. of rss lins X no. of lins ol siz of mmor KB 5. W know zro inpu rspons X( φ( ( φ( L {(si } Givn h n X( s s j(si si [ si ] [ si ] si (s (s s j(si φ(s s (s (s X(s s (s (s s s s X(s s X( n X( ILF s u( hoic (B 6. Givn G( s s.s zro S n pol S 5 Zro nrb origin, so i rprsns h L compnsor. Im 7. From h givn VPP 5V 8. From h givn 6 n D 6%.6 Fbck fcor β %. D.6 Df β 6..7% hoic (B. h givn circui is invring mplifir V 8 vols. I {IL If} m m 6 6 kω I IL If V kω I 6.5m.66 m 8.66 m hoic (B. W know in Dl moulor slop ovr lo fr coniion, is m s 56 6k { } 8-7 vols hoic (B 6. From h givn N 8 fm.5 khz fs.5 fm.5 khz fs.5 khz L n 56 n 8 rb N. n. fs khz 86 kbps. hoic (B. W know µ ω. µ m µ ωm. µ ( 6 π.5 µ µ (.86 µ µ.5 5 VP Vm 7.5V V Po ( m V m L L L V 56.5 m L 56.5 mw. W know skin ph δ π f µ σ δ wih f. ( ( * [h( * h(] ( * h( Impuls rspons h( h( * h( h - h ( τ.h ( - τ. τ
5 -τ.u - - -τ...u - - -τ...u - - ( - τ τ...u( - τ τ ( τ..u( - τ ( τ.u( - τ τ.u( τ.τ - -τ...τ.u -τ [ -] - -. [ - - ].u( n mho: H(s H(s.H(s h( IL {H(s}.τ τ.τ 5. From h givn H π /m η H µ π η Ω ε εr W εo εr εo εr ( ηh - 6 W mj/m 6. Givn h chrcrisic quion of mri is λ λ λ B l Hmilon horm, w hv I O ( onsir B I ( I ( I. (From ( B Now D(B D( ( ( k k n, whr n orr of 8 ( m m for n posiiv ingr m B 8 ( W know h Prouc of h ign vlus of ( n consn rm in h chrcrisic quion of (whr n orr of ( ( Hnc from (, B 8 7. hoic (B 7. Givn iffrnil quion is ( ( ( pu z (O z ln( ( θ z n ( θ(θ, whr θ z subsiuing hs in (, w g θ(θ θ ( θ - θ - 6 θ ( θ - 5 θ ( lrl ( is homognous linr quion wih consn cofficins. h uilir quion of ( is θ - 5 θ ( θ (θ θ, θ h gnrl soluion of ( is c z/ c z c( z / c( z c( / c( ( z h gnrl soluion of ( is c c(. 8. W hv Y (, O (, B Grn s horm, w know h N M M N ( Hr M n N M n In h rgion, N vris from o M N N M ( ( ] X n vris from o [From (] 8-6.
6 ( ;. Givn fxy(, ; Y, < Ohrwis [ ] P( X< Y P( X< Y ( P X< Y X< Y P(X < Y/X < Y P X< Y P(X < Y/X < Y XY P(X < Y f (, ( ( P(X < Y ( X < Y X > Y O (. ( ( Y P(X < Y ( XY n P(X < Y f (, X Y X Subsiuing ( n ( in (, w hv P(X < Y/X < Y 8.. W hv f( 5 6 W know h h lor s sris pnsion of f( bou is f( f( ( f ( f ( f (!! ( Hr f( 5 6 f(- f ( 6 f (- f ( 6 f (- 6 f ( 6 f (- 6 n f (IV ( f (V (. From (, h lor s sris pnsion of f( bou is f( f(- ( (- f (- ( (! f (-. ( (!.. f(( 8( ( lrniv soluions: ( (! ( 6! f (- 6 W know h h lor s sris pnsion of f( bou is sm s h of h lor s sris pnsion of f( in powrs of. f( 5 6 [( ] 5[( ] 6[( ] [( ( ( ] 5[( ( ] 6( 6 ( 8( (. X < Y X Y. From h givn signl ( -(- I is o signl So o n n bn.sinnωo.sinnωo X > Y ( B(π, O (. X -π (-π,- - π
7 ; π ; - π < < π ls whr π ωo o Bu funmnl prio π ωo bn.sinn..sinn. π π π.sinn π π π.sinn W know u. ϑ. u. ϑ. u. ϑ. π cosn π cos n... π n n π π cosn sinn b n π n n.( π bn π n n n bn (- ; for ll vlus of n. nπ ω h n. -j n H(ω n - H(ω h( h(. -jω h(. -jω h(. -jω. -jω -. -jω -jω ( -jω ( -jω -jω ω ω - j ω j ω - j ω - j ω j - j -. - jθ -jθ Bu sinθ ( - H H j -j.5ω -j.5ω ( ω j..sin.5ω j..sin.5ω -j.5ω ( ω j. { sin.5ω sin.5ω} z n.u n > z. ; z n.u n z z z z ( z. ; < z < X z n.( n - z. Z L (n n-.u[n ] n.u[ n ] (n n.(n z z ( z.z z. X z - z. z z z z { z z z} X z ( z - z{ z } ( z z X( z - z { z - } z -. Unr D. coniions cpcior cs lik opn circui. 5. k 5 I 5 mmp 6k W V Jouls V vols V 5 V - W ( 5.77mJ W 5.5 mj Vh ± 5 m h V V Ω I Ω IN 8 I Vh I 8 I V Ω N Ω i Ω ppling nol nlsis no V n Vh V Vh 8I (i V Bu I V Vh 6 V Vh V Vh ( V Vh 6 (ii From (i n (ii V 6V n Vh 8V Vh N Isc Isc: V V 8I V V V 6 V V V V 8 (i kω kω V I kω kω V Vh Ω IS kω
8 V V - V 8 V V (ii V vols V vols V Isc 8 N 6Ω 7. From h givn ρ.8ω m J 5 /m µn.6 m /V -sc µm ν ν V µ. µ. J. ρ m/sc µsc 7.5V - 5 Ω IN Ω N 6 Ω V H L 6. For < : - swich is clos L S. n O. h givn circui bcoms V -7.5 V V 5 6 V 7 V V 7V 7 V vols Vc( - vols IL( - mp IL( For > : 6 Ω Ω V F F Ω Swich opn, rprsn h givn circui quivln mol { 6 }Ω h chrcrisic quion of h sris L circui is s s L L s s. h roos of h bov quion is s -.5 n s V.. ; V( V n ic( mp (i Vc ic c { ] -(ii From (i n (i V( [ ]u( hoic (B 8. For boh rnsisors VD VG VDS(s VGS V VDS - V VDS > VDS(s So M n M r opring in surion rgion. I I,V V D D GS VGS VGS 5 VGS.5V GS W I µ n o L w [ V - V ] GS H - [.5 - ].75 m n. Jn q.d n. Dn µn V cm /sc.75 Bu givn Jn.5 /cm.65 [ 7 N] N N ( Jn N.6 65 N.76 6 cm. From h givn f(w,, Σm(,,, 5, 7 πm(,, 6. F ( w ( w B D F I I I I I I I I
9 Givn B slcion lin So B Io I I I From h ruh bl Io D D I D D D I D D I D D. From h givn circui LK -v g Q consir s clk o h n F/F I cs s n up counr Whn vr h NND g o/p X, i clr h circui. X onl whn Q Q Q i.., I is MOD-6 up counr V V b Ι mv k kω k kω kω V V V Vb 8 kω 6 kω 6 k Ι Q f o/p frqunc X clk 6 Q khz. rwing h givn circui mv V 8mV 5 6 mv V b 7.5 mv 8 Q V o 6 V 8 V V I K V b 5.65 mv Vo V Ι 8k Vo.8 mv..8µ. For full wv rcifir wih cpcior filr V VD Vm V VPP.5V.5 VD 8 7.5vols. M. S vlu of rippl volg V vols.5. Vols ippl fcor γ γ.57 Bu γ ( rms V VDc f.. L. 7.5 hoic (B F. µf 5. ppling currn mirror concp Ic Ic Vcc - VB I c c -.7 m.6 m 5 ppling kvl oupu loop. V.7.6 V V V 5. vols hoic (B 6. (s - - s /s (s (s ( s s s /s (s Simplif h givn block igrm ( s G s H s s s
10 Vi s. s ss l S G s.h s ( s s l G( s.h ( s k ϑ s ss.5 k ϑ ( s 7. W know rnsfr funcion G(s ( s 8. from h givn ( ( s - s s s s s ( s ( s s ( s.5s s 8 k B -.5s ( s s ( s.5s s 8 s( s s s s D J I V D ε ε I J. ε. ε W know ε. I I.5 6 π V. V. 5 k - V (s L{(} s sin n. V(m V; V(min.5V 5 I (min m m 5-.5 I( m m.5m IB(min m 5µ IB(m 87.5μ VB - 5 V k V - {- sin } hoic (B IB I IB Vi IB.B VB.7 I m.7m I (.7.5m.5m B min Vi(min V Vi(m IB(m.B VB IB(m (.7.875m Vi..7.V.78V Vi.V 5. W know B.w of SSB signl is fm onl G G G (.5575m B.W of mulipl signl n.fm Gur bn frqunc f 5 f 5 khz 5kHz G G fg f.5khz6khz G B.W ( 5 5 6kHz 6kHz 5. s zs z i.. is no prpniculr o h ircion of wv propgion (z ircion. Hnc i is M mo wih mo numbrs mπ π m nπ 5 π n b M mo 5. In h fr fil of nnn, α r i.. r -6 8k r k.8 µ V/m hoic (B 5. Vb V Vb 8 sin( z V 8 sin( z ρ.m ρb.85m Ponil in clinricl co - orins vris wih V P ln ρ q 8sin( z P ln(. q P ln (.85 q P 8sin( z -.5 sin( - z ln.85 v V â ρ p P â ρ p
11 5...5 ρ Displcmn nsi sin z âp V/m D ε ε r ε.5 sin zâρ ρ X( sin z âp n/m h puls of ( cn b rprsn - ;for < - ; for < h nrg of signl ( cn b clcul s -. - B simplificion w g. 6 - W know h probbili rror of mch filr is givn s P rfc. N..N N o - o o P.rfc rfc( From h givn roo locus, pols iss s - n s -5 Pols ming poin -.5 Zros α ± jβ -.5 ± j k s s.5 G s s s 5 S -.5 lis on h roo locus ( s s.5 k k ( s ( s 5 ( K hoic (B
Fourier Series and Parseval s Relation Çağatay Candan Dec. 22, 2013
Fourir Sris nd Prsvl s Rlion Çğy Cndn Dc., 3 W sudy h m problm EE 3 M, Fll3- in som dil o illusr som conncions bwn Fourir sris, Prsvl s rlion nd RMS vlus. Q. ps h signl sin is h inpu o hlf-wv rcifir circui
More information3.4 Repeated Roots; Reduction of Order
3.4 Rpd Roos; Rducion of Ordr Rcll our nd ordr linr homognous ODE b c 0 whr, b nd c r consns. Assuming n xponnil soluion lds o chrcrisic quion: r r br c 0 Qudric formul or fcoring ilds wo soluions, r &
More informationRelation between Fourier Series and Transform
EE 37-3 8 Ch. II: Inro. o Sinls Lcur 5 Dr. Wih Abu-Al-Su Rlion bwn ourir Sris n Trnsform Th ourir Trnsform T is riv from h finiion of h ourir Sris S. Consir, for xmpl, h prioic complx sinl To wih prio
More informationSingle Correct Type. cos z + k, then the value of k equals. dx = 2 dz. (a) 1 (b) 0 (c)1 (d) 2 (code-v2t3paq10) l (c) ( l ) x.
IIT JEE/AIEEE MATHS y SUHAAG SIR Bhopl, Ph. (755)3 www.kolsss.om Qusion. & Soluion. In. Cl. Pg: of 6 TOPIC = INTEGRAL CALCULUS Singl Corr Typ 3 3 3 Qu.. L f () = sin + sin + + sin + hn h primiiv of f()
More informationRevisiting what you have learned in Advanced Mathematical Analysis
Fourir sris Rvisiing wh you hv lrnd in Advncd Mhmicl Anlysis L f x b priodic funcion of priod nd is ingrbl ovr priod. f x cn b rprsnd by rigonomric sris, f x n cos nx bn sin nx n cos x b sin x cosx b whr
More informationMore on FT. Lecture 10 4CT.5 3CT.3-5,7,8. BME 333 Biomedical Signals and Systems - J.Schesser
Mr n FT Lcur 4CT.5 3CT.3-5,7,8 BME 333 Bimdicl Signls nd Sysms - J.Schssr 43 Highr Ordr Diffrniin d y d x, m b Y b X N n M m N M n n n m m n m n d m d n m Y n d f n [ n ] F d M m bm m X N n n n n n m p
More informationFourier. Continuous time. Review. with period T, x t. Inverse Fourier F Transform. x t. Transform. j t
Coninuous im ourir rnsform Rviw. or coninuous-im priodic signl x h ourir sris rprsnion is x x j, j 2 d wih priod, ourir rnsform Wh bou priodic signls? W willl considr n priodic signl s priodic signl wih
More informationCSE 245: Computer Aided Circuit Simulation and Verification
CSE 45: Compur Aidd Circui Simulaion and Vrificaion Fall 4, Sp 8 Lcur : Dynamic Linar Sysm Oulin Tim Domain Analysis Sa Equaions RLC Nwork Analysis by Taylor Expansion Impuls Rspons in im domain Frquncy
More informationMath 266, Practice Midterm Exam 2
Mh 66, Prcic Midrm Exm Nm: Ground Rul. Clculor i NOT llowd.. Show your work for vry problm unl ohrwi d (pril crdi r vilbl). 3. You my u on 4-by-6 indx crd, boh id. 4. Th bl of Lplc rnform i vilbl h l pg.
More informationEXERCISE - 01 CHECK YOUR GRASP
DIFFERENTIAL EQUATION EXERCISE - CHECK YOUR GRASP 7. m hn D() m m, D () m m. hn givn D () m m D D D + m m m m m m + m m m m + ( m ) (m ) (m ) (m + ) m,, Hnc numbr of valus of mn will b. n ( ) + c sinc
More informationInstructors Solution for Assignment 3 Chapter 3: Time Domain Analysis of LTIC Systems
Inrucor Soluion for Aignmn Chapr : Tim Domain Anali of LTIC Sm Problm i a 8 x x wih x u,, an Zro-inpu rpon of h m: Th characriic quaion of h LTIC m i i 8, which ha roo a ± j Th zro-inpu rpon i givn b zi
More informationDerivation of the differential equation of motion
Divion of h iffnil quion of oion Fis h noions fin h will us fo h ivion of h iffnil quion of oion. Rollo is hough o -insionl isk. xnl ius of h ll isnc cn of ll (O) - IDU s cn of gviy (M) θ ngl of inclinion
More informationEEE 303: Signals and Linear Systems
33: Sigls d Lir Sysms Orhogoliy bw wo sigls L us pproim fucio f () by fucio () ovr irvl : f ( ) = c( ); h rror i pproimio is, () = f() c () h rgy of rror sigl ovr h irvl [, ] is, { }{ } = f () c () d =
More informationCopyright 2012 Pearson Education, Inc. Publishing as Prentice Hall.
Chapr Rviw 0 6. ( a a ln a. This will qual a if an onl if ln a, or a. + k an (ln + c. Thrfor, a an valu of, whr h wo curvs inrsc, h wo angn lins will b prpnicular. 6. (a Sinc h lin passs hrough h origin
More informationWave Equation (2 Week)
Rfrnc Wav quaion ( Wk 6.5 Tim-armonic filds 7. Ovrviw 7. Plan Wavs in Losslss Mdia 7.3 Plan Wavs in Loss Mdia 7.5 Flow of lcromagnic Powr and h Poning Vcor 7.6 Normal Incidnc of Plan Wavs a Plan Boundaris
More informationChapter 4 Circular and Curvilinear Motions
Chp 4 Cicul n Cuilin Moions H w consi picls moing no long sigh lin h cuilin moion. W fis su h cicul moion, spcil cs of cuilin moion. Anoh mpl w h l sui li is h pojcil..1 Cicul Moion Unifom Cicul Moion
More informationPhysics 160 Lecture 3. R. Johnson April 6, 2015
Physics 6 Lcur 3 R. Johnson April 6, 5 RC Circui (Low-Pass Filr This is h sam RC circui w lookd a arlir h im doma, bu hr w ar rsd h frquncy rspons. So w pu a s wav sad of a sp funcion. whr R C RC Complx
More informationINTERQUARTILE RANGE. I can calculate variabilityinterquartile Range and Mean. Absolute Deviation
INTERQUARTILE RANGE I cn clcul vribiliyinrquril Rng nd Mn Absolu Dviion 1. Wh is h grs common fcor of 27 nd 36?. b. c. d. 9 3 6 4. b. c. d.! 3. Us h grs common fcor o simplify h frcion!".!". b. c. d.
More informationJonathan Turner Exam 2-10/28/03
CS Algorihm n Progrm Prolm Exm Soluion S Soluion Jonhn Turnr Exm //. ( poin) In h Fioni hp ruur, u wn vrx u n i prn v u ing u v i v h lry lo hil in i l m hil o om ohr vrx. Suppo w hng hi, o h ing u i prorm
More informationAR(1) Process. The first-order autoregressive process, AR(1) is. where e t is WN(0, σ 2 )
AR() Procss Th firs-ordr auorgrssiv procss, AR() is whr is WN(0, σ ) Condiional Man and Varianc of AR() Condiional man: Condiional varianc: ) ( ) ( Ω Ω E E ) var( ) ) ( var( ) var( σ Ω Ω Ω Ω E Auocovarianc
More informationInverse Fourier Transform. Properties of Continuous time Fourier Transform. Review. Linearity. Reading Assignment Oppenheim Sec pp.289.
Convrgnc of ourir Trnsform Rding Assignmn Oppnhim Sc 42 pp289 Propris of Coninuous im ourir Trnsform Rviw Rviw or coninuous-im priodic signl x, j x j d Invrs ourir Trnsform 2 j j x d ourir Trnsform Linriy
More informationT h e C S E T I P r o j e c t
T h e P r o j e c t T H E P R O J E C T T A B L E O F C O N T E N T S A r t i c l e P a g e C o m p r e h e n s i v e A s s es s m e n t o f t h e U F O / E T I P h e n o m e n o n M a y 1 9 9 1 1 E T
More information1 Finite Automata and Regular Expressions
1 Fini Auom nd Rgulr Exprion Moivion: Givn prn (rgulr xprion) for ring rching, w migh wn o convr i ino drminiic fini uomon or nondrminiic fini uomon o mk ring rching mor fficin; drminiic uomon only h o
More informationLecture 21 : Graphene Bandstructure
Fundmnls of Nnolcronics Prof. Suprio D C 45 Purdu Univrsi Lcur : Grpn Bndsrucur Rf. Cpr 6. Nwor for Compuionl Nnocnolog Rviw of Rciprocl Lic :5 In ls clss w lrnd ow o consruc rciprocl lic. For D w v: Rl-Spc:
More informationFL/VAL ~RA1::1. Professor INTERVI of. Professor It Fr recru. sor Social,, first of all, was. Sys SDC? Yes, as a. was a. assumee.
B Pror NTERV FL/VAL ~RA1::1 1 21,, 1989 i n or Socil,, fir ll, Pror Fr rcru Sy Ar you lir SDC? Y, om um SM: corr n 'd m vry ummr yr. Now, y n y, f pr my ry for ummr my 1 yr Un So vr ummr cour d rr o l
More informationS.Y. B.Sc. (IT) : Sem. III. Applied Mathematics. Q.1 Attempt the following (any THREE) [15]
S.Y. B.Sc. (IT) : Sm. III Applid Mahmaics Tim : ½ Hrs.] Prlim Qusion Papr Soluion [Marks : 75 Q. Amp h following (an THREE) 3 6 Q.(a) Rduc h mari o normal form and find is rank whr A 3 3 5 3 3 3 6 Ans.:
More informationSystems of First Order Linear Differential Equations
Sysms of Firs Ordr Linr Diffrnil Equions W will now urn our nion o solving sysms of simulnous homognous firs ordr linr diffrnil quions Th soluions of such sysms rquir much linr lgbr (Mh Bu sinc i is no
More informationREPETITION before the exam PART 2, Transform Methods. Laplace transforms: τ dτ. L1. Derive the formulas : L2. Find the Laplace transform F(s) if.
Tranform Mhod and Calculu of Svral Variabl H7, p Lcurr: Armin Halilovic KTH, Campu Haning E-mail: armin@dkh, wwwdkh/armin REPETITION bfor h am PART, Tranform Mhod Laplac ranform: L Driv h formula : a L[
More informationBoyce/DiPrima 9 th ed, Ch 2.1: Linear Equations; Method of Integrating Factors
Boc/DiPrima 9 h d, Ch.: Linar Equaions; Mhod of Ingraing Facors Elmnar Diffrnial Equaions and Boundar Valu Problms, 9 h diion, b William E. Boc and Richard C. DiPrima, 009 b John Wil & Sons, Inc. A linar
More informationEE Control Systems LECTURE 11
Up: Moy, Ocor 5, 7 EE 434 - Corol Sy LECTUE Copyrigh FL Lwi 999 All righ rrv POLE PLACEMET A STEA-STATE EO Uig fc, o c ov h clo-loop pol o h h y prforc iprov O c lo lc uil copor o oi goo y- rcig y uyig
More informationElementary Differential Equations and Boundary Value Problems
Elmnar Diffrnial Equaions and Boundar Valu Problms Boc. & DiPrima 9 h Ediion Chapr : Firs Ordr Diffrnial Equaions 00600 คณ ตศาสตร ว ศวกรรม สาขาว ชาว ศวกรรมคอมพ วเตอร ป การศ กษา /55 ผศ.ดร.อร ญญา ผศ.ดร.สมศ
More informationSection 2: The Z-Transform
Scion : h -rnsform Digil Conrol Scion : h -rnsform In linr discr-im conrol sysm linr diffrnc quion chrcriss h dynmics of h sysm. In ordr o drmin h sysm s rspons o givn inpu, such diffrnc quion mus b solvd.
More information0# E % D 0 D - C AB
5-70,- 393 %& 44 03& / / %0& / / 405 4 90//7-90/8/3 ) /7 0% 0 - @AB 5? 07 5 >0< 98 % =< < ; 98 07 &? % B % - G %0A 0@ % F0 % 08 403 08 M3 @ K0 J? F0 4< - G @ I 0 QR 4 @ 8 >5 5 % 08 OF0 80P 0O 0N 0@ 80SP
More informationSystems of First Order Linear Differential Equations
Sysms of Firs Ordr Linr Diffrnil Equions W will now urn our nion o solving sysms of simulnous homognous firs ordr linr diffrnil quions Th soluions of such sysms rquir much linr lgbr (Mh Bu sinc i is no
More informationWeek 06 Discussion Suppose a discrete random variable X has the following probability distribution: f ( 0 ) = 8
STAT W 6 Discussion Fll 7..-.- If h momn-gnring funcion of X is M X ( ), Find h mn, vrinc, nd pmf of X.. Suppos discr rndom vribl X hs h following probbiliy disribuion: f ( ) 8 7, f ( ),,, 6, 8,. ( possibl
More informationP a g e 5 1 of R e p o r t P B 4 / 0 9
P a g e 5 1 of R e p o r t P B 4 / 0 9 J A R T a l s o c o n c l u d e d t h a t a l t h o u g h t h e i n t e n t o f N e l s o n s r e h a b i l i t a t i o n p l a n i s t o e n h a n c e c o n n e
More informationImproved Computation of Electric Field in. Rectangular Waveguide. Based Microwave Components Using. Modal Expansion
Journl of Innoviv Tchnolog n Eucion, Vol. 3, 6, no., 3 - HIKARI L, www.-hikri.co hp://.oi.org/.988/ji.6.59 Iprov Copuion of Elcric Fil in Rcngulr Wvgui Bs icrowv Coponns Ug ol Epnsion Rj Ro Dprn of lcronics
More informationReview Lecture 5. The source-free R-C/R-L circuit Step response of an RC/RL circuit. The time constant = RC The final capacitor voltage v( )
Rviw Lcur 5 Firs-ordr circui Th sourc-fr R-C/R-L circui Sp rspons of an RC/RL circui v( ) v( ) [ v( 0) v( )] 0 Th i consan = RC Th final capacior volag v() Th iniial capacior volag v( 0 ) Volag/currn-division
More informationLaplace Transform. National Chiao Tung University Chun-Jen Tsai 10/19/2011
plc Trnorm Nionl Chio Tung Univriy Chun-Jn Ti /9/ Trnorm o Funcion Som opror rnorm uncion ino nohr uncion: d Dirniion: x x, or Dx x dx x Indini Ingrion: x dx c Dini Ingrion: x dx 9 A uncion my hv nicr
More informationSOLVED EXAMPLES. be the foci of an ellipse with eccentricity e. For any point P on the ellipse, prove that. tan
LOCUS 58 SOLVED EXAMPLES Empl Lt F n F th foci of n llips with ccntricit. For n point P on th llips, prov tht tn PF F tn PF F Assum th llips to, n lt P th point (, sin ). P(, sin ) F F F = (-, 0) F = (,
More informationChapter 5 The Laplace Transform. x(t) input y(t) output Dynamic System
EE 422G No: Chapr 5 Inrucor: Chung Chapr 5 Th Laplac Tranform 5- Inroducion () Sym analyi inpu oupu Dynamic Sym Linar Dynamic ym: A procor which proc h inpu ignal o produc h oupu dy ( n) ( n dy ( n) +
More informationLecture 2: Current in RC circuit D.K.Pandey
Lcur 2: urrn in circui harging of apacior hrough Rsisr L us considr a capacior of capacianc is conncd o a D sourc of.m.f. E hrough a rsisr of rsisanc R and a ky K in sris. Whn h ky K is swichd on, h charging
More informationErlkönig. t t.! t t. t t t tj "tt. tj t tj ttt!t t. e t Jt e t t t e t Jt
Gsng Po 1 Agio " " lkö (Compl by Rhol Bckr, s Moifi by Mrk S. Zimmr)!! J "! J # " c c " Luwig vn Bhovn WoO 131 (177) I Wr Who!! " J J! 5 ri ris hro' h spä h, I urch J J Nch rk un W Es n wil A J J is f
More informationControl Systems. Modelling Physical Systems. Assoc.Prof. Haluk Görgün. Gears DC Motors. Lecture #5. Control Systems. 10 March 2013
Lcur #5 Conrol Sy Modlling Phyicl Sy Gr DC Moor Aoc.Prof. Hluk Görgün 0 Mrch 03 Conrol Sy Aoc. Prof. Hluk Görgün rnfr Funcion for Sy wih Gr Gr provid chnicl dvng o roionl y. Anyon who h riddn 0-pd bicycl
More information16.512, Rocket Propulsion Prof. Manuel Martinez-Sanchez Lecture 3: Ideal Nozzle Fluid Mechanics
6.5, Rok ropulsion rof. nul rinz-snhz Lur 3: Idl Nozzl luid hnis Idl Nozzl low wih No Sprion (-D) - Qusi -D (slndr) pproximion - Idl gs ssumd ( ) mu + Opimum xpnsion: - or lss, >, ould driv mor forwrd
More informationEngine Thrust. From momentum conservation
Airbrhing Propulsion -1 Airbrhing School o Arospc Enginring Propulsion Ovrviw w will b xmining numbr o irbrhing propulsion sysms rmjs, urbojs, urbons, urboprops Prormnc prmrs o compr hm, usul o din som
More informationA L A BA M A L A W R E V IE W
A L A BA M A L A W R E V IE W Volume 52 Fall 2000 Number 1 B E F O R E D I S A B I L I T Y C I V I L R I G HT S : C I V I L W A R P E N S I O N S A N D TH E P O L I T I C S O F D I S A B I L I T Y I N
More informationControl System Engineering (EE301T) Assignment: 2
Conrol Sysm Enginring (EE0T) Assignmn: PART-A (Tim Domain Analysis: Transin Rspons Analysis). Oain h rspons of a uniy fdack sysm whos opn-loop ransfr funcion is (s) s ( s 4) for a uni sp inpu and also
More informationStatistics Assessing Normality Gary W. Oehlert School of Statistics 313B Ford Hall
Siic 504 0. Aing Normliy Gry W. Ohlr School of Siic 33B For Hll 6-65-557 gry@.umn.u Mny procur um normliy. Som procur fll pr if h rn norml, whr ohr cn k lo of bu n kp going. In ihr c, i nic o know how
More informationThe Mathematics of Harmonic Oscillators
Th Mhcs of Hronc Oscllors Spl Hronc Moon In h cs of on-nsonl spl hronc oon (SHM nvolvng sprng wh sprng consn n wh no frcon, you rv h quon of oon usng Nwon's scon lw: con wh gvs: 0 Ths s sos wrn usng h
More informationWave Phenomena Physics 15c
Wv hnon hyscs 5c cur 4 Coupl Oscllors! H& con 4. Wh W D s T " u forc oscllon " olv h quon of oon wh frcon n foun h sy-s soluon " Oscllon bcos lr nr h rsonnc frquncy " hs chns fro 0 π/ π s h frquncy ncrss
More informationH is equal to the surface current J S
Chapr 6 Rflcion and Transmission of Wavs 6.1 Boundary Condiions A h boundary of wo diffrn mdium, lcromagnic fild hav o saisfy physical condiion, which is drmind by Maxwll s quaion. This is h boundary condiion
More informationCharging of capacitor through inductor and resistor
cur 4&: R circui harging of capacior hrough inducor and rsisor us considr a capacior of capacianc is conncd o a D sourc of.m.f. E hrough a rsisr of rsisanc R, an inducor of inducanc and a y K in sris.
More informationChapter4 Time Domain Analysis of Control System
Chpr4 im Domi Alyi of Corol Sym Rouh biliy cririo Sdy rror ri rpo of h fir-ordr ym ri rpo of h cod-ordr ym im domi prformc pcificio h rliohip bw h prformc pcificio d ym prmr ri rpo of highr-ordr ym Dfiiio
More informationDigital Signal Processing. Digital Signal Processing READING ASSIGNMENTS. License Info for SPFirst Slides. Fourier Transform LECTURE OBJECTIVES
Digil Signl Procssing Digil Signl Procssing Prof. Nizmin AYDIN nydin@yildiz.du.r hp:www.yildiz.du.r~nydin Lcur Fourir rnsform Propris Licns Info for SPFirs Slids READING ASSIGNMENS his work rlsd undr Criv
More information2 T. or T. DSP First, 2/e. This Lecture: Lecture 7C Fourier Series Examples: Appendix C, Section C-2 Various Fourier Series
DSP Firs, Lcur 7C Fourir Sris Empls: Common Priodic Signls READIG ASSIGMES his Lcur: Appndi C, Scion C- Vrious Fourir Sris Puls Wvs ringulr Wv Rcifid Sinusoids lso in Ch. 3, Sc. 3-5 Aug 6 3-6, JH McCllln
More informationOn the Derivatives of Bessel and Modified Bessel Functions with Respect to the Order and the Argument
Inrnaional Rsarch Journal of Applid Basic Scincs 03 Aailabl onlin a wwwirjabscom ISSN 5-838X / Vol 4 (): 47-433 Scinc Eplorr Publicaions On h Driais of Bssl Modifid Bssl Funcions wih Rspc o h Ordr h Argumn
More informationA Study of the Solutions of the Lotka Volterra. Prey Predator System Using Perturbation. Technique
Inrnionl hmil orum no. 667-67 Sud of h Soluions of h o Volrr r rdor Ssm Using rurion Thniqu D.Vnu ol Ro * D. of lid hmis IT Collg of Sin IT Univrsi Vishnm.. Indi Y... Thorni D. of lid hmis IT Collg of
More informationChapter 5 Transient Analysis
hpr 5 rs Alyss Jsug Jg ompl rspos rs rspos y-s rspos m os rs orr co orr Dffrl Equo. rs Alyss h ffrc of lyss of crcus wh rgy sorg lms (ucors or cpcors) & m-ryg sgls wh rss crcus s h h quos rsulg from r
More informationMathcad Lecture #4 In-class Worksheet Vectors and Matrices 1 (Basics)
Mh Lr # In-l Workh Vor n Mri (Bi) h n o hi lr, o hol l o: r mri n or in Mh i mri prorm i mri mh oprion ol m o linr qion ing mri mh. Cring Mri Thr r rl o r mri. Th "Inr Mri" Wino (M) B K Poin Rr o
More informationChapter 3: Fourier Representation of Signals and LTI Systems. Chih-Wei Liu
Chapr 3: Fourir Rprsnaion of Signals and LTI Sysms Chih-Wi Liu Oulin Inroducion Complx Sinusoids and Frquncy Rspons Fourir Rprsnaions for Four Classs of Signals Discr-im Priodic Signals Fourir Sris Coninuous-im
More informationA Kalman filtering simulation
A Klmn filering simulion The performnce of Klmn filering hs been esed on he bsis of wo differen dynmicl models, ssuming eiher moion wih consn elociy or wih consn ccelerion. The former is epeced o beer
More informationME 522 PRINCIPLES OF ROBOTICS. FIRST MIDTERM EXAMINATION April 19, M. Kemal Özgören
ME 522 PINCIPLES OF OBOTICS FIST MIDTEM EXAMINATION April 9, 202 Nm Lst Nm M. Kml Özgörn 2 4 60 40 40 0 80 250 USEFUL FOMULAS cos( ) cos cos sin sin sin( ) sin cos cos sin sin y/ r, cos x/ r, r 0 tn 2(
More information2. The Laplace Transform
Th aac Tranorm Inroucion Th aac ranorm i a unamna an vry uu oo or uying many nginring robm To in h aac ranorm w conir a comx variab σ, whr σ i h ra ar an i h imaginary ar or ix vau o σ an w viw a a oin
More informationThe Procedure Abstraction Part II: Symbol Tables and Activation Records
Th Produr Absrion Pr II: Symbol Tbls nd Aivion Rords Th Produr s Nm Sp Why inrodu lxil soping? Provids ompil-im mhnism for binding vribls Ls h progrmmr inrodu lol nms How n h ompilr kp rk of ll hos nms?
More informationES 250 Practice Final Exam
ES 50 Pracice Final Exam. Given ha v 8 V, a Deermine he values of v o : 0 Ω, v o. V 0 Firs, v o 8. V 0 + 0 Nex, 8 40 40 0 40 0 400 400 ib i 0 40 + 40 + 40 40 40 + + ( ) 480 + 5 + 40 + 8 400 400( 0) 000
More informationMidterm exam 2, April 7, 2009 (solutions)
Univrsiy of Pnnsylvania Dparmn of Mahmaics Mah 26 Honors Calculus II Spring Smsr 29 Prof Grassi, TA Ashr Aul Midrm xam 2, April 7, 29 (soluions) 1 Wri a basis for h spac of pairs (u, v) of smooh funcions
More informationChapter 8: Propagating Quantum States of Radiation
Quum Opcs f hcs Oplccs h R Cll Us Chp 8: p Quum Ss f R 8. lcmc Ms Wu I hs chp w wll cs pp quum ss f wus fs f spc. Cs h u shw lw f lcc wu. W ssum h h wu hs l lh qul h -c wll ssum l. Th lcc cs s fuc f l
More informationPupil / Class Record We can assume a word has been learned when it has been either tested or used correctly at least three times.
2 Pupi / Css Rr W ssum wr hs b r wh i hs b ihr s r us rry s hr ims. Nm: D Bu: fr i bus brhr u firs hf hp hm s uh i iv iv my my mr muh m w ih w Tik r pp push pu sh shu sisr s sm h h hir hr hs im k w vry
More informationSOME USEFUL MATHEMATICS
SOME USEFU MAHEMAICS SOME USEFU MAHEMAICS I is esy o mesure n preic he behvior of n elecricl circui h conins only c volges n currens. However, mos useful elecricl signls h crry informion vry wih ime. Since
More informationThe model proposed by Vasicek in 1977 is a yield-based one-factor equilibrium model given by the dynamic
h Vsick modl h modl roosd by Vsick in 977 is yild-bsd on-fcor quilibrium modl givn by h dynmic dr = b r d + dw his modl ssums h h shor r is norml nd hs so-clld "mn rvring rocss" (undr Q. If w u r = b/,
More information(A) 1 (B) 1 + (sin 1) (C) 1 (sin 1) (D) (sin 1) 1 (C) and g be the inverse of f. Then the value of g'(0) is. (C) a. dx (a > 0) is
[STRAIGHT OBJECTIVE TYPE] l Q. Th vlu of h dfii igrl, cos d is + (si ) (si ) (si ) Q. Th vlu of h dfii igrl si d whr [, ] cos cos Q. Vlu of h dfii igrl ( si Q. L f () = d ( ) cos 7 ( ) )d d g b h ivrs
More informationDouble Slits in Space and Time
Doubl Slis in Sac an Tim Gorg Jons As has bn ror rcnly in h mia, a am l by Grhar Paulus has monsra an inrsing chniqu for ionizing argon aoms by using ulra-shor lasr ulss. Each lasr uls is ffcivly on an
More informationTransfer function and the Laplace transformation
Lab No PH-35 Porland Sa Univriy A. La Roa Tranfr funcion and h Laplac ranformaion. INTRODUTION. THE LAPLAE TRANSFORMATION L 3. TRANSFER FUNTIONS 4. ELETRIAL SYSTEMS Analyi of h hr baic paiv lmn R, and
More information10. If p and q are the lengths of the perpendiculars from the origin on the tangent and the normal to the curve
0. If p and q ar h lnghs of h prpndiculars from h origin on h angn and h normal o h curv + Mahmaics y = a, hn 4p + q = a a (C) a (D) 5a 6. Wha is h diffrnial quaion of h family of circls having hir cnrs
More informationELECTRIC VELOCITY SERVO REGULATION
ELECIC VELOCIY SEVO EGULAION Gorg W. Younkin, P.E. Lif FELLOW IEEE Indusril Conrols Consuling, Di. Bulls Ey Mrking, Inc. Fond du Lc, Wisconsin h prformnc of n lcricl lociy sro is msur of how wll h sro
More informationUNIT #5 EXPONENTIAL AND LOGARITHMIC FUNCTIONS
Answr Ky Nam: Da: UNIT # EXPONENTIAL AND LOGARITHMIC FUNCTIONS Par I Qusions. Th prssion is quivaln o () () 6 6 6. Th ponnial funcion y 6 could rwrin as y () y y 6 () y y (). Th prssion a is quivaln o
More informationP441 Analytical Mechanics - I. Coupled Oscillators. c Alex R. Dzierba
Lecure 3 Mondy - Deceber 5, 005 Wrien or ls upded: Deceber 3, 005 P44 Anlyicl Mechnics - I oupled Oscillors c Alex R. Dzierb oupled oscillors - rix echnique In Figure we show n exple of wo coupled oscillors,
More informationREADING ASSIGNMENTS. Signal Processing First. Fourier Transform LECTURE OBJECTIVES. This Lecture: Lecture 23 Fourier Transform Properties
Signl Procssing Firs Lcur 3 Fourir rnsform Propris READING ASSIGNMENS his Lcur: Chpr, Scs. -5 o -9 ls in Scion -9 Ohr Rding: Rciion: Chpr, Scs. - o -9 N Lcurs: Chpr Applicions 3/7/4 3, JH McCllln & RW
More informationPhysics 2A HW #3 Solutions
Chper 3 Focus on Conceps: 3, 4, 6, 9 Problems: 9, 9, 3, 41, 66, 7, 75, 77 Phsics A HW #3 Soluions Focus On Conceps 3-3 (c) The ccelerion due o grvi is he sme for boh blls, despie he fc h he hve differen
More informationSE1CY15 Differentiation and Integration Part B
SECY5 Diffrniion nd Ingrion Pr B Diffrniion nd Ingrion 6 Prof Richrd Michll Tody w will sr o look mor ypicl signls including ponnils, logrihms nd hyprbolics Som of his cn b found in h rcommndd books Crof
More information1 Introduction to Modulo 7 Arithmetic
1 Introution to Moulo 7 Arithmti Bor w try our hn t solvin som hr Moulr KnKns, lt s tk los look t on moulr rithmti, mo 7 rithmti. You ll s in this sminr tht rithmti moulo prim is quit irnt rom th ons w
More informationHandout on. Crystal Symmetries and Energy Bands
dou o Csl s d g Bds I hs lu ou wll l: Th loshp bw ss d g bds h bs of sp-ob ouplg Th loshp bw ss d g bds h ps of sp-ob ouplg C 7 pg 9 Fh Coll Uvs d g Bds gll hs oh Th sl pol ss ddo o h l slo s: Fo pl h
More informatione t dt e t dt = lim e t dt T (1 e T ) = 1
Improper Inegrls There re wo ypes of improper inegrls - hose wih infinie limis of inegrion, nd hose wih inegrnds h pproch some poin wihin he limis of inegrion. Firs we will consider inegrls wih infinie
More information(2) If we multiplied a row of B by λ, then the value is also multiplied by λ(here lambda could be 0). namely
. DETERMINANT.. Dtrminnt. Introution:I you think row vtor o mtrix s oorint o vtors in sp, thn th gomtri mning o th rnk o th mtrix is th imnsion o th prlllppi spnn y thm. But w r not only r out th imnsion,
More informationLecture 1: Numerical Integration The Trapezoidal and Simpson s Rule
Lcur : Numrical ngraion Th Trapzoidal and Simpson s Rul A problm Th probabiliy of a normally disribud (man µ and sandard dviaion σ ) vn occurring bwn h valus a and b is B A P( a x b) d () π whr a µ b -
More information2.1. Differential Equations and Solutions #3, 4, 17, 20, 24, 35
MATH 5 PS # Summr 00.. Diffrnial Equaions and Soluions PS.# Show ha ()C #, 4, 7, 0, 4, 5 ( / ) is a gnral soluion of h diffrnial quaion. Us a compur or calculaor o skch h soluions for h givn valus of h
More informationCS 541 Algorithms and Programs. Exam 2 Solutions. Jonathan Turner 11/8/01
CS 1 Algorim nd Progrm Exm Soluion Jonn Turnr 11/8/01 B n nd oni, u ompl. 1. (10 poin). Conidr vrion of or p prolm wi mulipliiv o. In i form of prolm, lng of p i produ of dg lng, rr n um. Explin ow or
More informationPHYS ,Fall 05, Term Exam #1, Oct., 12, 2005
PHYS1444-,Fall 5, Trm Exam #1, Oct., 1, 5 Nam: Kys 1. circular ring of charg of raius an a total charg Q lis in th x-y plan with its cntr at th origin. small positiv tst charg q is plac at th origin. What
More informationADORO TE DEVOTE (Godhead Here in Hiding) te, stus bat mas, la te. in so non mor Je nunc. la in. tis. ne, su a. tum. tas: tur: tas: or: ni, ne, o:
R TE EVTE (dhd H Hdg) L / Mld Kbrd gú s v l m sl c m qu gs v nns V n P P rs l mul m d lud 7 súb Fí cón ví f f dó, cru gs,, j l f c r s m l qum t pr qud ct, us: ns,,,, cs, cut r l sns m / m fí hó sn sí
More informationName:... Batch:... TOPIC: II (C) 1 sec 3 2x - 3 sec 2x. 6 é ë. logtan x (A) log (tan x) (B) cot (log x) (C) log log (tan x) (D) tan (log x) cos x (C)
Nm:... Bch:... TOPIC: II. ( + ) d cos ( ) co( ) n( ) ( ) n (D) non of hs. n sc d sc + sc é ësc sc ù û sc sc é ë ù û (D) non of hs. sc cosc d logn log (n ) co (log ) log log (n ) (D) n (log ). cos log(
More informationPHA Final Exam Fall On my honor, I have neither given nor received unauthorized aid in doing this assignment.
Nm: UFI#: PHA 527 Finl Exm Fll 2008 On my honor, I hv nihr givn nor rcivd unuhorizd id in doing his ssignmn. Nm Pls rnsfr h nswrs ono h bubbl sh. Pls fill in ll h informion ncssry o idnify yourslf. h procors
More informationAdrian Sfarti University of California, 387 Soda Hall, UC Berkeley, California, USA
Innionl Jonl of Phoonis n Oil Thnolo Vol. 3 Iss. : 36-4 Jn 7 Rliisi Dnis n lonis in Unifol l n in Unifol Roin s-th Gnl ssions fo h loni 4-Vo Ponil in Sfi Unisi of Clifoni 387 So Hll UC Bkl Clifoni US s@ll.n
More informationEXERCISE - 01 CHECK YOUR GRASP
DEFNTE NTEGRATON EXERCSE - CHECK YOUR GRASP. ( ) d [ ] d [ ] d d ƒ( ) ƒ '( ) [ ] [ ] 8 5. ( cos )( c)d 8 ( cos )( c)d + 8 ( cos )( c) d 8 ( cos )( c) d sic + cos 8 is lwys posiiv f() d ( > ) ms f() is
More informationDEPARTMENT OF ELECTRICAL &ELECTRONICS ENGINEERING SIGNALS AND SYSTEMS. Assoc. Prof. Dr. Burak Kelleci. Spring 2018
DEPARTMENT OF ELECTRICAL &ELECTRONICS ENGINEERING SIGNALS AND SYSTEMS Aoc. Prof. Dr. Burak Kllci Spring 08 OUTLINE Th Laplac Tranform Rgion of convrgnc for Laplac ranform Invr Laplac ranform Gomric valuaion
More informationEE415/515 Fundamentals of Semiconductor Devices Fall 2012
3 EE4555 Fudmls of Smicoducor vics Fll cur 8: PN ucio iod hr 8 Forwrd & rvrs bis Moriy crrir diffusio Brrir lowrd blcd by iffusio rducd iffusio icrsd mioriy crrir drif rif hcd 3 EE 4555. E. Morris 3 3
More informationRight Angle Trigonometry
Righ gl Trigoomry I. si Fs d Dfiiios. Righ gl gl msurig 90. Srigh gl gl msurig 80. u gl gl msurig w 0 d 90 4. omplmry gls wo gls whos sum is 90 5. Supplmry gls wo gls whos sum is 80 6. Righ rigl rigl wih
More information2. Transfer function. Kanazawa University Microelectronics Research Lab. Akio Kitagawa
. ransfr funion Kanazawa Univrsiy Mirolronis Rsarh Lab. Akio Kiagawa . Wavforms in mix-signal iruis Configuraion of mix-signal sysm x Digial o Analog Analog o Digial Anialiasing Digial moohing Filr Prossor
More informationy cos x = cos xdx = sin x + c y = tan x + c sec x But, y = 1 when x = 0 giving c = 1. y = tan x + sec x (A1) (C4) OR y cos x = sin x + 1 [8]
DIFF EQ - OPTION. Sol th iffrntial quation tan +, 0
More information