Numbering Systems. Contents: Binary & Decimal. Converting From: B D, D B. Arithmetic operation on Binary.
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1 Numbering Systems Contents: Binary & Decimal. Converting From: B D, D B. Arithmetic operation on Binary. Addition & Subtraction using Octal & Hexadecimal 2 s Complement, Subtraction Using 2 s Complement.
2 Objectives Understand the binary number system and decimal number system Be able to convert from binary to decimal Be able to convert from decimal to binary Be able to make binary addition Understand 2 s complement and Subtraction using 2 s complement
3 Binary & Decimal Systems
4 Bits & Bytes Bits are binary digits; they are either 0s or 1s. Bit (b) Binary digit, a 1 or 0 Computers operate with electronic switches that are either "on" or "off", corresponding to 1 or 0. A byte is a group of eight bits Byte (B) 8 bits
5 Decimal System Since we use only 10 digits in our daily calculations, our system of representing numbers is called Decimal System. So the numerical value Eight thousands nine hundred fifty four is represented as: = 8* * * *10 0
6 Decimal number system Base 10 because it uses ten symbols 0,1,2,3,4,5,6,7,8, could also be written as: (2x10 3 ) + (1x10 2 ) + (3x10 1 ) + (4x10 0 )
7 Binary System Since a computer is a machine that can only work on two states: ON or OFF or two electrical pulse states High or Low, or two logical states True or False or simply 1 or 0 So the alphabet in computers is only formed of two entities (rather than 10 in the decimal system). That is why it is called Binary System.
8 Binary number system Base 2 because it uses 2 symbols 0 & 1 Computers recognize and process data using the binary (Base 2) numbering system The position, or place, of each digit represents the number 2 the base number raised to a power (exponent), based on its position (2 0, 2 1, 2 2, etc.) = (1 x 2 4 = 16) + (0 x 2 3 = 0) + (1 x 2 2 =4) + (1 x 2 1 = 2) + (0 x 2 0 = 0) = 22
9 Binary System Numerical Values in Binary System are represented as a combination of 1 s and 0 s, For example Decimal Binary etc..
10 Binary System Notice the Following: Decimal Binary 3 = 3* = 1* * = 1* * = 1*2 3 +0*2 2 +1*2 1 +0*2 0 So what is the decimal value of this binary number: ?
11 Converting From Binary Decimal Decimal Binary
12 Converting from binary to decimal Multiply the binary digits by the base number (2), raised to the exponent of its position starting at 0. Binary no Position ^posn. 2^6 2^5 2^4 2^3 2^2 2^1 2^0 Answer: 1*2^6+0*2^5+0*2^4+1*2^3+0*2^2+1*2^1+0*2^0 = = 74
13 Binary Fractions The decimal value is calculated in the same way as for non-fractional numbers, the exponents are now negative.
14 Example: (binary) =1* * * * * x 2-3 = = = (decimal) Note: = = = = = 8 = = = etc. 16
15 Try these Binary Decimal equivalent 0011? ? 1111? ? 11.11? ?
16 Converting from decimal to binary Divide the decimal number by two. Note the result & remainder. Repeat the process until the result is zero. The binary number equivalent is got reading all the remainders in the reverse order to which they were got.
17 Converting from decimal to binary E.g. decimal 46 46/2 = 23 rem 0 23/2 = 11 rem 1 11/2 = 5 rem 1 5/2 = 2 rem 1 2/2 = 1 rem 0 1/2 = 0 rem 1 Binary number is:
18 converting decimal to binary fractions Consider left and right of the decimal point separately. The stuff to the left can be converted to binary as before. _
19 Example: Give (base 10) in base 2 27 (base 10) to binary (base 2): 27/2 = 13 rem 1 13/2 = 6 rem 1 6/2 = 3 rem 0 3/2 = 1 rem 1 1/2 = 0 rem 1 27 (base 10) = (base 2)
20 Cont. Example.6875 (base 10) to binary (base 2): Integer Fraction Coefficient *2 = *2 = *2 = *2 = (base 10) =.1011 (base 2) So, (base 10) = (base 2)
21 Try these: Decimal Binary equivalent 34? 67.44? 234? ? 25? ?
22 Binary Addition& Subtraction
23 Binary addition The binary addition table: = = = = 0 (carry 1) Overflow: If there is not enough room to hold the result correctly.
24 Binary subtraction The binary subtraction table: 0-0 = = = = 1 (borrow 1)
25 Binary Addition Add Two binary numbers 0101 (5 base 10) and 0011 (3 base 10)
26 Binary Addition Verification = = 83 10
27 Binary Addition ex Verification = =
28 Binary Addition & Subtraction Accomplished exactly the same as decimal Only two values per position (0 or 1) Examples: Addition Subtraction Carry Borrow
29 Binary Addition & Subtraction Exercise Add the following two binary numbers Subtract the following two numbers
30 Binary Multiplication& Division
31 Binary Multiplication Each bit from 2 nd number is multiplied by each bit in first number, then the result is added in order after shifting 1position each time. 0*0=0 0*1=0 1*0=0 1*1=1
32 Binary Multiplication Example (38) 1110 (14) (532)
33 Binary Division Using long division like decimal division
34 Octal Addition& Subtraction
35 Octal Addition Just as with decimal addition, octal uses carry when the sum of the values of a position exceeds 7 10 [or 7 8 ] Carry
36 Octal Addition (subtract Base (8))
37 Octal Addition ex (subtract Base (8))
38 Octal Subtraction Just as with decimal subtraction, Octal uses borrow when the difference between the values of a position requires it Borrow
39 Octal Subtraction
40 Octal Subtraction ex
41 Hexadecimal Addition& Subtraction
42 Hexadecimal Addition Just as with decimal addition, hexadecimal uses carry when the sum of the values of a position exceeds [or F 16 ] Carry A 1 1 D E F 0 E F H Note that FFFFH may be treated as -1 depending on whether we are dealing with signed or unsigned values
43 Hexadecimal Addition C F (subtract Base (16)) B 4 2 B 16
44 Hexadecimal Addition 8 A D D (subtract Base (16)) 16
45 Hexadecimal Subtraction Just as with decimal subtraction, hexadecimal uses borrow when the difference between the values of a position requires it Borrow A 1 1 D E F C C B 4 H
46 Hexadecimal Subtraction B 16 7 C F
47 Hexadecimal Subtraction 8 A D D
48 2 s Complement & Subtraction using 2 s Complement
49 How To Represent Signed Numbers Plus and minus sign used for decimal numbers: 25 (or +25), -16, etc. For computers, desirable to represent everything as bits. Three types of signed binary number representations: signed magnitude, 1 s complement, 2 s complement. In each case: left-most bit indicates sign: positive (0) or negative (1). Consider signed magnitude: = = Sign bit Magnitude Sign bit Magnitude
50 One s Complement Representation The one s complement of a binary number involves inverting all bits. 1 s comp of is s comp of is = = Sign bit Magnitude Sign bit Magnitude
51 Two s Complement Representation The two s complement of a binary number involves inverting all bits and adding 1. 2 s comp of is s comp of is To find negative of 2 s complement number take the 2 s complement = = Sign bit Magnitude Sign bit Magnitude
52 Two s Complement Shortcuts Algorithm Simply complement each bit and then add 1 to the result. Finding the 2 s complement of ( ) 2 and of its 2 s complement N = [N] =
53 1 s Complement Addition Using 1 s complement numbers, adding numbers is easy. For example, suppose we wish to add +(1100) 2 and +(0001) 2. Let s compute (12) 10 + (1) 10. (12) 10 = +(1100) 2 = in 1 s comp. (1) 10 = +(0001) 2 = in 1 s comp. Step 1: Add binary numbers Step 2: Add carry to low-order bit Add Add carry Final Result
54 1 s Complement Subtraction Using 1 s complement numbers, subtracting numbers is also easy. For example, suppose we wish to subtract +(0001) 2 from +(1100) 2. Let s compute (12) 10 - (1) 10. (12) 10 = +(1100) 2 = in 1 s comp. (-1) 10 = -(0001) 2 = in 1 s comp. 1 s comp Step 1: Take 1 s complement of 2 nd operand Step 2: Add binary numbers Step 3: Add carry to low order bit Add Add carry Final Result
55 2 s Complement Addition Using 2 s complement numbers, adding numbers is easy. For example, suppose we wish to add +(1100) 2 and +(0001) 2. Let s compute (12) 10 + (1) 10. (12) 10 = +(1100) 2 = in 2 s comp. (1) 10 = +(0001) 2 = in 2 s comp. Step 1: Add binary numbers Step 2: Ignore carry bit Add Final Result Ignore
56 2 s Complement Subtraction Using 2 s complement numbers, follow steps for subtraction For example, suppose we wish to subtract +(0001) 2 from +(1100) 2. Let s compute (12) 10 - (1) 10. (12) 10 = +(1100) 2 = in 2 s comp. (-1) 10 = -(0001) 2 = in 2 s comp. 2 s comp Step 1: Take 2 s complement of 2 nd operand Step 2: Add binary numbers Step 3: Ignore carry bit Add Final Result Ignore Carry
57 2 s Complement Subtraction: Example #2 Let s compute (13) 10 (5) 10. (13) 10 = +(1101) 2 = (01101) 2 (-5) 10 = -(0101) 2 = (11011) 2 Adding these two 5-bit codes carry Discarding the carry bit, the sign bit is seen to be zero, indicating a correct result. Indeed, (01000) 2 = +(1000) 2 = +(8)
58 2 s Complement Subtraction: Example #3 Let s compute (5) 10 (12) 10. (-12) 10 = -(1100) 2 = (10100) 2 (5) 10 = +(0101) 2 = (00101) 2 Adding these two 5-bit codes Here, there is no carry bit and the sign bit is 1. This indicates a negative result, which is what we expect. (11001) 2 = -(7) 10.
59 Thank You
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