Note: Question number 1 to 8 carries 2 marks each, 9 to 16 carries 4 marks each and 17 to 18 carries 6 marks each.

Transcription

1 IIT-JEE 5-M-1 FIITJEE Slutins t IITJEE 5 Mains aper Time: hurs hemistry te: Questin number 1 t 8 carries marks each, 9 t 16 carries 4 marks each and 17 t 18 carries 6 marks each. Q.1. Mnmer A f a plymer n znlysis yields tw mles f and ne mle f 3. a) Deduce the structure f A. b) Write the structure f all cis frm f plymer f cmpund A. Slutin1. (a) 3 (b) 3 A znlysis all cis frm f plymer f A Q.. Fill in the blanks a) b) U n A B ο Se e... Slutin. (a) 35 U 9 n A 5 97 B 4 n 1 (b) 8 Se 34-1 e 8 Kr 36 Q.3. a) alculate the amunt f alcium xide required when it reacts with 85 gm f 4 1. b) Write the structure f 4 1. Slutin 3. a) 6a 4 1 a 3 ( 4 ) (b) Mles f 4 1 = = Mles f a = 3 6 = 18 Wt. f a = = 18 gm. FIITJEE Ltd. IES use, Sarvapriya Vihar (ear auz Khas Bus Term.), ew Delhi - 16, h : , , , Fax :

2 IIT-JEE 5-M- Q.4. An element crystallizes in fcc lattice having edge length 4 pm. alculate the maximum diameter f atm which can be placed in interstitial site withut distrting the structure. Slutin4. In F, interstitial sites will be ctahedral vids & tetrahedral vids. Fr ctahedral vids Fr tetrahedral vids r1 r1 =.414 =.5 r r Where r 1 = radius f atm in interstitial sites r = radius f atm arranged in F. i.e. 4r = a, Fr maximum diameter f atm in interstitial site, ctahedral vids will be cnsidered. 4 Diameter = r 1 = (.414 r ) =.414 = pm Q.5. % surface sites have adsrbed. n heating gas evlved frm sites and were cllected at.1 atm and 98 K in a cntainer f vlume is.46 cm 3. Density f surface sites is / cm and surface area is 1 cm, find ut the n. f surface sites ccupied per mlecule f. Slutin 5. =.1 atm, T = 98 K, V =.46 cm By ideal gas, V = nrt 3 V n = = = 1. 1 RT w mlecules f = = w ttal surface sites available = = Surface site used t adsrb = = Sites ccupied per mlecule f = = Q.6. redict whether the fllwing mlecules are is structural r nt. Justify yur answer. (i) Me 3 (ii) (SiMe 3 ) 3 Slutin 6. Me &SiMe are nt isstructural. (Me) 3 is trignal pyramidal while trignal planar due t back bnding. Si(Me) 3 SiMe is 3 3 Me Me Me (Me) 3 Si Si(Me) 3 Q.7. Identify X and Y. / 1. 3 a X Y. Zn/3 FIITJEE Ltd. IES use, Sarvapriya Vihar (ear auz Khas Bus Term.), ew Delhi - 16, h : , , , Fax :

3 IIT-JEE 5-M-3 Slutin 7. Å / ring expansin a 3 Zn/3 3 (X) Q.8. Which f the fllwing disaccharide will nt reduce Tllen s reagent? a) b) (Q) () Slutin 8. In structure () bth the rings are present in acetyl frm therefre it will nt hydrlyse in slutin that why Fehling slutin cannt react with this. In structure (Q) ne ring present in the frm f hemiacetal. This will hydrlyse in slutin and it can reduce Fehling slutin. Q.9. Write balanced chemical equatin fr develping a black and white phtgraphic film. Als give reasn why the slutin f sdium thisulphate n acidificatin turns milky white and give balance equatin f this reactin. Slutin 9. a) Reactins used in develping the phtgraphic film AgBr Ag Br sensitive, unexpsed emulsin quinne ydrquinne black silver ( develper particles ) AgBr a S a Ag S abr yp slutin b) 3 3 a S a S S cllidal sulphur Q.1. 3 S (excess) F (excess) Fe bld red(a) clurless(b) Identify A and B. a) Write IUA name f A and B. b) Find ut spin nly magnetic mment f B. Slutin 1. aqueus 3 Fe S Fe S ( excess) 5 ( A)( bld red) FIITJEE Ltd. IES use, Sarvapriya Vihar (ear auz Khas Bus Term.), ew Delhi - 16, h : , , , Fax :

4 IIT-JEE 5-M-4 3 [ ] Fe S 6 5 6F FeF S 5 ( excess) ( A)( bld red) ( B)( clurless) a) entaaquathicyanat irn (III) in hexaflur ferrate (III) b) Magnetic mment = n( n ) = 35 = 5.9 B.M., where n = number f unpaired electrns Q.11. X( g) 3Y( g) Z( g) Time (in Min) 1 artial pressure f X (in mm f g) 8 4 Assuming ideal gas cnditin. alculate a) rder f reactin b) Rate cnstant. c) Time taken fr 75% cmpletin f reactin. d) Ttal pressure when x = 7 mm. Slutin 11. X(g) 3Y(g) Z(g) a) By the given data, we can bserved that t 1/ f the X is cnstant i.e. 1 min. therefre rder f reactin is ne..693 b) Rate cnstant K = t1/ = = min 1 c) Time taken fr 75% cmpletin f reactin = t 1/ d) X 3Y Z Initial pressure 8 At any time 8 x 3/ x x Given 8 x = 7 mm x = 1 mm Ttal pressure = = 95 mm Q.1. a) alculate velcity f electrn in first Bhr rbit f hydrgen atm (Given r = a ). b) Find de-brglie wavelength f the electrn in first Bhr rbit. c) Find the rbital angular mmentum f p rbital in terms f h/π units. nh Slutin 1. a) mvr = r = a =.59 A π nh 6 v = =.18 1 m/sec (n = 1) πmr 34 h b) λ= = =.33 1 m = 3.3 A mv c) Fr p value f = 1 h rbital angular mmentum = ( 1) π h = π Q.13. a,l 5 13 Y(Tertiary alchl ther prducts) (X) (ptically active) Find X and Y. Is Y ptically active? Write the intermediate steps. FIITJEE Ltd. IES use, Sarvapriya Vihar (ear auz Khas Bus Term.), ew Delhi - 16, h : , , , Fax :

5 IIT-JEE 5-M-5 Slutin13. 3 X is r 3 3 (X) a l (X) shift (Y) (ptically inacticv Q.14. Give reasns: a) i) 3 Br 3 (aq) 5 acidic slutin ii) Br 3 (aq) 5 neutral 3 b) i) F a(aq) - F (liberated) ii) 3 F a(aq) - F is nt liberated 3 c) i) nc. 3 nc. S4 ii) nc. 3 nc. S4 d) d / 3mlef is frmed but nt FIITJEE Ltd. IES use, Sarvapriya Vihar (ear auz Khas Bus Term.), ew Delhi - 16, h : , , , Fax :

6 IIT-JEE 5-M-6 Slutin14. (a) (i) aq 5 Br Br (acid) (ii) a( aq) reactin (b) (i) Br F a( aq) F is liberated 3 This is a bimlecular reactin. Rate f this reactin is being enhanced by presence f electrn withdrawing grups at rth and para psitins. F (ii) is nt liberated. a( aq) F 3 Bimlecular mechanism is nt pssible is this case. (c) (i) Due t presence f lne pair n nitrgen atm grup is electrn dnating and rth, para directing. (ii) grup is electrn withdrawing and meta directing. (d) Due t reductin f central ring, three fur membered antiarmatic rings becme stable while n reductin f terminal ring nly ne antiarmatic ring can be stabilized. Q Brwn fumes and abrmn cnc. B A 3 intermediate D Explsive prduct pungent smell Find A, B, and D. Als write equatins A t B and A t. Slutin15. (A) S 4 (B) Br () (D) 3 Reactins invlved are: S4 abr Mn Br as4 MnS4 ( A) ( B)( Brwn fumes) S4 3 S 4 ( A) ( ) FIITJEE Ltd. IES use, Sarvapriya Vihar (ear auz Khas Bus Term.), ew Delhi - 16, h : , , , Fax :

7 IIT-JEE 5-M (D) (Explsive) Q.16. (B) Mist air Ml 4 Zn (A) white fumes having (M = transitinelement (purple clr) pungent smell clurless) Identify the metal M and hence Ml 4. Explain the difference in clurs f Ml 4 and A. Slutin 16. M = Ti 3 6 A = Ti B = Ti Ti(IV) in cntains n d-electrns, while d d transitin f single electrn f Ti(III) will cause clur change. Q.17. µ bs = µ ixi Where µ i is the diple mment f stable cnfrmer and x i is the mle fractin f that cnfrmer. a) Write stable cnfrmer fr Z Z in ewman s prjectin. If µ slutin = 1. D and mle fractin f anti frm =.8, find µ Guche. b) Write mst stable mes cnfrmer f DY DY If (i) Y = 3 abut 3 rtatin and (ii) Y = abut 1 rtatin. Slutin17. a) Z Z Z Z (Anti) (Gauche) Mle fractin f anti frm =.8 Mle fractin f Gauche frm =.18 µ b. = 1 1 =µ (anti).8 µ (Gauce).18 µ (anti) = 1= µ (Gauche).18 1 µ Gauche = = 5.55 D.18 FIITJEE Ltd. IES use, Sarvapriya Vihar (ear auz Khas Bus Term.), ew Delhi - 16, h : , , , Fax :

8 IIT-JEE 5-M-8 b) i) D 3 ii) D D D 3 Q.18. a) alculate G r f the fllwing reactin Ag( aq) l( aq. ) Agl( s) Given G f ( Agl ) 19KJ / mle G l - 19 kj/mle f f G Ag 77 kj/mle Represent the abve reactin in frm f a cell. alculate E f the cell. Find lg 1 K sp f Agl. b) g f metallic Zn (amu = 65.39) was added t 1 ml f saturated slutin f Agl. Zn alculate lg1. Given that Ag Ag e Ag E =.8 V Zn e Zn E =.76 V Als find hw many mles f Ag will be frmed? Slutin18. ell reactins are 1 Ag l Agl Ag Ag e - (ii).(i) 1 l - e l (iii) - Ag l Agl (i ii iii) - hence cell representatin is Ag Ag Agl l l,t Ag (aq) l (aq) Agl(s); G G i) G = 19 ( 19 77) = = 77 = -57 = -1 F E -57 = E 57 E = =.59 Vlts 965 ii) -57 = -.33 RT lg K 57 1 lg K = lg K = K = 1 1 R FIITJEE Ltd. IES use, Sarvapriya Vihar (ear auz Khas Bus Term.), ew Delhi - 16, h : , , , Fax :

9 IIT-JEE 5-M-9 K sp = 1/K K sp = 1-1 lg K sp = -1 iii) 1 Agl(s) Ag (aq) l (aq) S S 1-1 = S S = 1-5 m / L b) When = 1 3 mles f Zn has been added, Ag e Ag; E =.8V Zn Zn e; E =.77V Ag( aq) Zn( s) Zn( aq) Ag( S ); E = 1.57V 1-6 mle 1-3 mles lg1k ( eq) = 5.8 Therefre, this reactin will mve in frward directin cmpletely. ence mles f Ag frmed will be 1-6 At equilibrium, (E cell = ).591 Zn Eell = lg1 Ag 1.56 Zn = lg = Ag te: FIITJEE slutins t IITJEE, 5 Mains apers created using memry retentin f select FIITJEE students appeared in this test and hence may nt exactly be the same as the riginal paper. wever, every effrt has been made t reprduce the riginal paper in the interest f the aspiring students. FIITJEE Ltd. IES use, Sarvapriya Vihar (ear auz Khas Bus Term.), ew Delhi - 16, h : , , , Fax :