CHEM 1001 Problem Set #3: Entropy and Free Energy
|
|
- Maude Francis
- 6 years ago
- Views:
Transcription
1 CHEM 1001 Prblem Set #3: Entry and Free Energy 19.7 (a) Negative; A liquid (mderate entry) cmbines with a slid t frm anther slid. (b)psitive; One mle f high entry gas frms where n gas was resent befre. (c) Psitive; One mle f high entry gas frms where n gas was resent befre. (d) Uncertain; Same number f mles f gaseus rducts as f gaseus reactants. (e) Negative; Tw mles f gas (and a, slid) cmbine t frm just ne mle f gas Trutn's rule is beyed mst clsely by liquids that d nt have a high degree f rder within the liquid. In bth HF and CH3OH, hydrgen bnds create cnsiderable rder within the liquid. In C6H5CH 3, the nly attractive frces are nn-directinal Lndn frces, which cause the mlecules t attract each ther, but have n referred rientatin as hydrgen bnds d. Thus, f the three chices, liquid C H CH wuld mst clsely fllw Trutn's rule First f all, the rcess is clearly sntaneus, and therefre G < 0. In additin, the gases are mre disrdered when they are at a lwer ressure and therefre S>0. We als cnclude that H = 0, because the gases are ideal and thus there are n frces f attractin r reulsin between them, rducing n energy f interactin (a) An exthermic reactin (ne that gives ff heat) may nt ccur sntaneusly if, at the same time, the system becmes mre rdered, that is, S < 0.This is articularly true at a high temerature, where the T S term dminates the G exressin. An examle f such a rcess is freezing water (clearly exthermic because the reverse rcess, melting ice, is endthermic) at temeratures abve 0 C. (b) A reactin in which S > 0 need nt be sntaneus if that rcess als is endthermic. This is articularly true at lw temeratures, where the H term dminates the G exressin. An examle is the varizatin f water (clearly an endthermic rcess, ne that requires heat, and ne that rduces a gas, s S > 0) at lw temeratures, that is, belw 100 C (a) S = 2S [POCl 3(l)] - 2S [PCl 3(g)] - S [O 2(g)] = 2(222.4 J/K) - 2( J/K) J/K = J/K 3 3 G = H - T S = x 10 J - (298 K)( J/K) = -506x10 J = -506 kj (b) The reactin rceeds sntaneusly in the frward directin when reactants and rducts are in their standard states, because the value f G is less than zer.
2 19.27 We cmbine the reactins in the same way as fr Hess's law calculatins. (a) N2O(g) N 2(g) + ½O 2(g) G = -½( kj) = kj N 2(g) + 2O 2(g) 2 NO 2(g) G = kj Net: N2O(g) + 3/2O 2(g) 2NO 2(g) G = = -1.6 kj This reactin reaches an equilibrium cnditin, a cnclusin we reach based n the relatively small abslute value f G. (b) 2N 2(g) + 6H 2(g) 4NH 3(g) G = 2(-33.0 kj) = kj 4NH 3(g) + 5O 2(g) 4NO(g) + 6H2O(l) G = kj 4NO(g) 2N 2(g) + 2O 2(g) G =-2( kj) = kj Net: 6H 2(g) + 3O 2(g) 6H2O(I) G = kj kj kj = kj This reactin is three times the desired reactin, which therefre has G = kj 3 = kj The large negative G value indicates that this reactin wuld tend t g t cmletin at 25 C. (c) 4NH 3(g) + 5O 2(g) 4NO(g) + 6H2O(l) G = kj 4NO(g) 2N 2(g) + 2O 2(g) G = -2( kj) = kj 2N 2(g) + O 2(g) 2N2O(g) G = kj Net: 4NH 3(g) + 4O 2(g) 2N2O(g) + 6H2O(I) G = kj kj kj = kJ This reactin is twice the desired reactin, which, therefre, has G = kj 2 = kj The very large negative value f G fr this reactin indicates that it will g t cmletin.
3 19.31 (a) S rxn = S rducts - S reactants = {1 ml x J K ml + 2 ml x J K ml } - {2 ml x J K ml + 1 ml x J K ml } = J K -1 = kj K -1 (b) H rxn = {bnds brken in reactants (kj/ml)} - {bnds brken in rducts(kj/ ml)} = {4 ml x (389 kj ml ) N-H + 4 ml x (222 kj ml ) O-F} - {4 ml x (301 kj ml ) N-F + 4 ml x (464 kj ml ) O-H} = -616 kj -1 (c) G rxn = H rxn - T S rxn = -616 kj K( kj K ) = -600 kj Since the G rxn is negative, the reactin is sntaneus, and hence feasible (at 25 C). Because bth the entry and enthaly changes are negative, this reactin will be mre highly favred at lw temeratures (i.e. the reactin is enthaly driven) In all three cases, K eq = K because nly gases, slids, and liquids are resent in the chemical equatins. There are n factrs fr slids and liquids in K eq exressins, and gases aear as artial ressures in atmsheres. That makes n K eq the same as K fr these three reactins. We nw recall that K = K c(rt). Hence, in these three cases we have: (a) 2SO 2(g) + O 2(g) 2SO 3(g); n gas = 2 - (2+1) = -1; K eq =K =K c(rt) -1 (b) HI(g) ½H 2(g) + ½I 2(g); n gas = 1 - (½+½) = 0; K eq = K = Kc (c) NH4HCO 3(s) NH 3(g) + CO 2(g) + H2O(I); n gas = 2 - (0) = 2; K eq =K =K c(rt) 2 ngas (a) We knw that K = K c(rt). Fr the reactin 2 SO 2(g) + O 2(g) 2 SO 3(g), n = 2 - (2 + 1) = -1, and therefre a value f K can be btained. gas K = K c(rt) = (2.8 X 10 )( L atm ml K X 1000 K) = 3.41 = Keq We recgnize that K eq = K since all f the substances invlved in the reactin are gases. We can nw evaluate G. G = -RT In K eq = -( J ml K )(1000 K) In (3.41) 4 = x 10 J/ml = kj/ml
4 (b) We can evaluate Q fr this situatin and cmare the value with that f K. c c Since Q c is less than K c, the reactin will shift t the right t rduce mre rducts until the reactin reaches equilibrium and these tw values are equal Since K = K fr this reactin, eq G = -RT In K eq = -RT In K = -( x 10 kj ml K )(298 K)In(6.5x10 ) = kj/ml CO(g) + Cl 2(g) COCl 2(g) G = -67.4kJ/ml C(grahite) + ½O 2(g) CO(g) G f = kj/ml C(grahite) + ½O (g) + CI (g) COCl (g) G = kj/ml f G f f COCI 2(g) given in Aendix D is kj/ml which is in excellent agreement with this calculated value (a) H = H f [CO 2(g)] + H f [H 2(g)] - H f [CO(g)] - H f [H2O(l)] = { ( l) - (-241.8)} kj/ml = kj/ml S = S f [CO 2(g)] + S f [H 2(g)] - S f [CO(g)] - S f [H2O(l)] = { } J ml K = J ml K G = H - T S -3 = kj/ml - ( K)(-42.1 X 10 kj ml K ) = kj/ml (b) G = H - T S -3 = kj/ml - (875 K)(-42.1 X 10 kj ml K ) = -4.4 kj/ml Since K eq = K fr this reactin, G = -RT In K eq = -RT In K 3 In K = - G /RT = (-4.4 X 10 J/ml)/{( J ml K )(875 K)} = 0.60 K = ex(0.60) = 1.8
5 19.67 (a) We cmute G fr the given reactin in the fllwing manner: H = H f [TiCl 4(l)] + H f [O 2(g)] - H f [TiO 2(s)] - 2 H f [Cl 2(g)] = { ( ) - 2(0.00)} kj/ml = kj/ml S = S f [TiCl 4(l)] + S f [O 2(g)] - S f [TiO 2(s)] - 2 S f [Cl 2(g)] = { (50.33) - 2(223.1)} J ml K = J ml K G = H - T S -3 = kj/ml - (298K)(-39.1x10 kj ml K ) = kj/ml kj/ml = kj/ml This reactin is nnsntaneus at 250 C. (We als culd have used values f G t calculate G.) f (b) Fr the cited reactin, G = 2 G f[co 2 (g)]- 2 G f[ CO (g)] - G f [O 2 (g)] G = {2(-394.4) - 2(-137.2) } kj/ml = kj/ml Then we cule the tw reactins. TiO 2 (s) + 2Cl 2 (g) TiCl 4 (l) + O 2(g) 2CO(g) + O (g) 2CO (g) 2 2 G = kj/ml G = kj/ml TiO 2 (s) + 2Cl 2 (g) + 2CO(g) TiCl 4 (l) + 2CO 2(g) G = kj/ml The culed reactin has G < 0, and, therefre, is sntaneus.
CHAPTER 19 SPONTANEOUS CHANGE: ENTROPY AND GIBBS ENERGY
CHAPTER 9 SPONTANEOUS CHANGE: ENTROPY AND GIBBS ENERGY PRACTICE EXAMPLES A (E) In general, S 0 if n gas 0. This is because gases are very disersed cmared t liquids r slids; (gases ssess large entries).
More informationThermodynamics Partial Outline of Topics
Thermdynamics Partial Outline f Tpics I. The secnd law f thermdynamics addresses the issue f spntaneity and invlves a functin called entrpy (S): If a prcess is spntaneus, then Suniverse > 0 (2 nd Law!)
More informationChapters 29 and 35 Thermochemistry and Chemical Thermodynamics
Chapters 9 and 35 Thermchemistry and Chemical Thermdynamics 1 Cpyright (c) 011 by Michael A. Janusa, PhD. All rights reserved. Thermchemistry Thermchemistry is the study f the energy effects that accmpany
More informationChapter 17 Free Energy and Thermodynamics
Chemistry: A Mlecular Apprach, 1 st Ed. Nivald Tr Chapter 17 Free Energy and Thermdynamics Ry Kennedy Massachusetts Bay Cmmunity Cllege Wellesley Hills, MA 2008, Prentice Hall First Law f Thermdynamics
More informationUnit 14 Thermochemistry Notes
Name KEY Perid CRHS Academic Chemistry Unit 14 Thermchemistry Ntes Quiz Date Exam Date Lab Dates Ntes, Hmewrk, Exam Reviews and Their KEYS lcated n CRHS Academic Chemistry Website: https://cincchem.pbwrks.cm
More informationChemical Equilibrium
0.110/5.60 Fall 005 Lecture #10 age 1 Chemical Equilibrium Ideal Gases Questin: What is the cmsitin f a reacting miture f ideal gases? e.g. ½ N (g, T, ) + 3/ H (g, T, ) = NH 3 (g, T, ) What are N,, and
More informationCHEM Thermodynamics. Change in Gibbs Free Energy, G. Review. Gibbs Free Energy, G. Review
Review Accrding t the nd law f Thermdynamics, a prcess is spntaneus if S universe = S system + S surrundings > 0 Even thugh S system
More informationPart One: Heat Changes and Thermochemistry. This aspect of Thermodynamics was dealt with in Chapter 6. (Review)
CHAPTER 18: THERMODYNAMICS AND EQUILIBRIUM Part One: Heat Changes and Thermchemistry This aspect f Thermdynamics was dealt with in Chapter 6. (Review) A. Statement f First Law. (Sectin 18.1) 1. U ttal
More informationCHAPTER Read Chapter 17, sections 1,2,3. End of Chapter problems: 25
CHAPTER 17 1. Read Chapter 17, sectins 1,2,3. End f Chapter prblems: 25 2. Suppse yu are playing a game that uses tw dice. If yu cunt the dts n the dice, yu culd have anywhere frm 2 t 12. The ways f prducing
More informationThermodynamics and Equilibrium
Thermdynamics and Equilibrium Thermdynamics Thermdynamics is the study f the relatinship between heat and ther frms f energy in a chemical r physical prcess. We intrduced the thermdynamic prperty f enthalpy,
More informationEntropy, Free Energy, and Equilibrium
Nv. 26 Chapter 19 Chemical Thermdynamics Entrpy, Free Energy, and Equilibrium Nv. 26 Spntaneus Physical and Chemical Prcesses Thermdynamics: cncerned with the questin: can a reactin ccur? A waterfall runs
More informationALE 21. Gibbs Free Energy. At what temperature does the spontaneity of a reaction change?
Name Chem 163 Sectin: Team Number: ALE 21. Gibbs Free Energy (Reference: 20.3 Silberberg 5 th editin) At what temperature des the spntaneity f a reactin change? The Mdel: The Definitin f Free Energy S
More informationFind this material useful? You can help our team to keep this site up and bring you even more content consider donating via the link on our site.
Find this material useful? Yu can help ur team t keep this site up and bring yu even mre cntent cnsider dnating via the link n ur site. Still having truble understanding the material? Check ut ur Tutring
More informationAP CHEMISTRY CHAPTER 6 NOTES THERMOCHEMISTRY
AP CHEMISTRY CHAPTER 6 NOTES THERMOCHEMISTRY Energy- the capacity t d wrk r t prduce heat 1 st Law f Thermdynamics: Law f Cnservatin f Energy- energy can be cnverted frm ne frm t anther but it can be neither
More informationWhen a substance heats up (absorbs heat) it is an endothermic reaction with a (+)q
Chemistry Ntes Lecture 15 [st] 3/6/09 IMPORTANT NOTES: -( We finished using the lecture slides frm lecture 14) -In class the challenge prblem was passed ut, it is due Tuesday at :00 P.M. SHARP, :01 is
More informationChapter 4 Thermodynamics and Equilibrium
Chapter Thermdynamics and Equilibrium Refer t the fllwing figures fr Exercises 1-6. Each represents the energies f fur mlecules at a given instant, and the dtted lines represent the allwed energies. Assume
More informationSolutions to the Extra Problems for Chapter 14
Slutins t the Extra Prblems r Chapter 1 1. The H -670. T use bnd energies, we have t igure ut what bnds are being brken and what bnds are being made, s we need t make Lewis structures r everything: + +
More informationREVIEW QUESTIONS Chapter 18. H = H (Products) - H (Reactants) H (Products) = (1 x -125) + (3 x -271) = -938 kj
Chemistry 102 ANSWER KEY REVIEW QUESTIONS Chapter 18 1. Calculate the heat reactin ( H ) in kj/ml r the reactin shwn belw, given the H values r each substance: NH (g) + F 2 (g) NF (g) + HF (g) H (kj/ml)
More informationChapter 17: Thermodynamics: Spontaneous and Nonspontaneous Reactions and Processes
Chapter 17: hermdynamics: Spntaneus and Nnspntaneus Reactins and Prcesses Learning Objectives 17.1: Spntaneus Prcesses Cmparing and Cntrasting the hree Laws f hermdynamics (1 st Law: Chap. 5; 2 nd & 3
More informationChem 116 POGIL Worksheet - Week 3 - Solutions Intermolecular Forces, Liquids, Solids, and Solutions
Chem 116 POGIL Wrksheet - Week 3 - Slutins Intermlecular Frces, Liquids, Slids, and Slutins Key Questins 1. Is the average kinetic energy f mlecules greater r lesser than the energy f intermlecular frces
More informationChemistry 1A Fall 2000
Chemistry 1A Fall 2000 Midterm Exam III, versin B Nvember 14, 2000 (Clsed bk, 90 minutes, 155 pints) Name: SID: Sectin Number: T.A. Name: Exam infrmatin, extra directins, and useful hints t maximize yur
More informationAdvanced Chemistry Practice Problems
Advanced Chemistry Practice Prblems Thermdynamics: Gibbs Free Energy 1. Questin: Is the reactin spntaneus when ΔG < 0? ΔG > 0? Answer: The reactin is spntaneus when ΔG < 0. 2. Questin: Fr a reactin with
More informationGeneral Chemistry II, Unit II: Study Guide (part 1)
General Chemistry II, Unit II: Study Guide (part 1) CDS Chapter 21: Reactin Equilibrium in the Gas Phase General Chemistry II Unit II Part 1 1 Intrductin Sme chemical reactins have a significant amunt
More informationThermochemistry. Thermochemistry
Thermchemistry Petrucci, Harwd and Herring: Chapter 7 CHEM 1000A 3.0 Thermchemistry 1 Thermchemistry The study energy in chemical reactins A sub-discipline thermdynamics Thermdynamics studies the bulk
More informationLecture 14 Chapter 16, Sections 3-4 Equilibrium. Nifty K eq math Q and K eq Connection with G Le Chatelier
Lecture 14 Chater 16, Sectins 3-4 Equilibrium Nifty K math Q and K Cnnectin with G Le Chatelier Remember In general fr a reactin like aa + bb dd + ee K [ ] d D [ E] e [ ] a A [ ] b B K s can be cmbined
More informationCHEM 116 Electrochemistry at Non-Standard Conditions, and Intro to Thermodynamics
CHEM 116 Electrchemistry at Nn-Standard Cnditins, and Intr t Thermdynamics Imprtant annuncement: If yu brrwed a clicker frm me this semester, return it t me at the end f next lecture r at the final exam
More informationHeat Effects of Chemical Reactions
eat Effects f hemical Reactins Enthalpy change fr reactins invlving cmpunds Enthalpy f frmatin f a cmpund at standard cnditins is btained frm the literature as standard enthalpy f frmatin Δ (O (g = -9690
More informationLecture 16 Thermodynamics II
Lecture 16 Thermdynamics II Calrimetry Hess s Law Enthalpy r Frmatin Cpyright 2013, 2011, 2009, 2008 AP Chem Slutins. All rights reserved. Fur Methds fr Finding H 1) Calculate it using average bnd enthalpies
More informationChemistry 20 Lesson 11 Electronegativity, Polarity and Shapes
Chemistry 20 Lessn 11 Electrnegativity, Plarity and Shapes In ur previus wrk we learned why atms frm cvalent bnds and hw t draw the resulting rganizatin f atms. In this lessn we will learn (a) hw the cmbinatin
More informationSPONTANEITY, ENTROPY, AND FREE ENERGY
CHAER 7 SONANEIY, ENROY, AND FREE ENERGY Questins. Living rganisms need an external surce f energy t carry ut these prcesses. Green plants use the energy frm sunlight t prduce glucse frm carbn dixide and
More information188 CHAPTER 6 THERMOCHEMISTRY
188 CHAPTER 6 THERMOCHEMISTRY 4. a. ΔE = q + w = J + 100. J = 77 J b. w = PΔV = 1.90 atm(.80 L 8.0 L) = 10.5 L atm ΔE = q + w = 50. J + 1060 = 1410 J c. w = PΔV = 1.00 atm(9.1 L11. L) = 17.9 L atm 101.
More informationCHAPTER PRACTICE PROBLEMS CHEMISTRY
Chemical Kinetics Name: Batch: Date: Rate f reactin. 4NH 3 (g) + 5O (g) à 4NO (g) + 6 H O (g) If the rate f frmatin f NO is 3.6 0 3 ml L s, calculate (i) the rate f disappearance f NH 3 (ii) rate f frmatin
More informationLecture 12: Chemical reaction equilibria
3.012 Fundamentals f Materials Science Fall 2005 Lecture 12: 10.19.05 Chemical reactin equilibria Tday: LAST TIME...2 EQUATING CHEMICAL POTENTIALS DURING REACTIONS...3 The extent f reactin...3 The simplest
More informationRecitation 06. n total = P total V/RT = (0.425 atm * 10.5 L) / ( L atm mol -1 K -1 * 338 K) = mol
Recitatin 06 Mixture f Ideal Gases 1. Chapter 5: Exercise: 69 The partial pressure f CH 4 (g) is 0.175 atm and that f O 2 (g) is 0.250 atm in a mixture f the tw gases. a. What is the mle fractin f each
More informationChem 116 POGIL Worksheet - Week 8 Equilibrium Continued - Solutions
Chem 116 POGIL Wrksheet - Week 8 Equilibrium Cntinued - Slutins Key Questins 1. Cnsider the fllwing reatin At 425 C, an equilibrium mixture has the fllwing nentratins What is the value f K? -2 [HI] = 1.01
More informationCHEM 103 Calorimetry and Hess s Law
CHEM 103 Calrimetry and Hess s Law Lecture Ntes March 23, 2006 Prf. Sevian Annuncements Exam #2 is next Thursday, March 30 Study guide, practice exam, and practice exam answer key are already psted n the
More informationLecture 4. The First Law of Thermodynamics
Lecture 4. The First Law f Thermdynamics THERMODYNAMICS: Basic Cncepts Thermdynamics: (frm the Greek therme, meaning "heat" and, dynamis, meaning "pwer") is the study f energy cnversin between heat and
More informationFind this material useful? You can help our team to keep this site up and bring you even more content consider donating via the link on our site.
Find this material useful? Yu can help ur team t eep this site up and bring yu even mre cntent cnsider dnating via the lin n ur site. Still having truble understanding the material? Chec ut ur Tutring
More informationHow can standard heats of formation be used to calculate the heat of a reaction?
Answer Key ALE 28. ess s Law and Standard Enthalpies Frmatin (Reerence: Chapter 6 - Silberberg 4 th editin) Imprtant!! Fr answers that invlve a calculatin yu must shw yur wrk neatly using dimensinal analysis
More informationExamples: 1. How much heat is given off by a 50.0 g sample of copper when it cools from 80.0 to 50.0 C?
NOTES: Thermchemistry Part 1 - Heat HEAT- TEMPERATURE - Thermchemistry: the study f energy (in the frm f heat) changes that accmpany physical & chemical changes heat flws frm high t lw (ht cl) endthermic
More informationlecture 5: Nucleophilic Substitution Reactions
lecture 5: Nuclephilic Substitutin Reactins Substitutin unimlecular (SN1): substitutin nuclephilic, unimlecular. It is first rder. The rate is dependent upn ne mlecule, that is the substrate, t frm the
More informationChemistry 114 First Hour Exam
Chemistry 114 First Hur Exam Please shw all wrk fr partial credit Name: (4 pints) 1. (12 pints) Espress is made by frcing very ht water under high pressure thrugh finely grund, cmpacted cffee. (Wikipedia)
More informationSpontaneous Processes, Entropy and the Second Law of Thermodynamics
Chemical Thermdynamics Spntaneus Prcesses, Entrpy and the Secnd Law f Thermdynamics Review Reactin Rates, Energies, and Equilibrium Althugh a reactin may be energetically favrable (i.e. prducts have lwer
More informationFind this material useful? You can help our team to keep this site up and bring you even more content consider donating via the link on our site.
Find this material useful? Yu can help ur team t keep this site up and bring yu even mre cntent cnsider dnating via the link n ur site. Still having truble understanding the material? Check ut ur Tutring
More informationBIT Chapters = =
BIT Chapters 17-0 1. K w = [H + ][OH ] = 9.5 10 14 [H + ] = [OH ] =.1 10 7 ph = 6.51 The slutin is neither acidic nr basic because the cncentratin f the hydrnium in equals the cncentratin f the hydride
More informationGeneral Chemistry II, Unit I: Study Guide (part I)
1 General Chemistry II, Unit I: Study Guide (part I) CDS Chapter 14: Physical Prperties f Gases Observatin 1: Pressure- Vlume Measurements n Gases The spring f air is measured as pressure, defined as the
More informationSemester 2 AP Chemistry Unit 12
Cmmn In Effect and Buffers PwerPint The cmmn in effect The shift in equilibrium caused by the additin f a cmpund having an in in cmmn with the disslved substance The presence f the excess ins frm the disslved
More informationChem 116 POGIL Worksheet - Week 4 Properties of Solutions
Chem 116 POGIL Wrksheet - Week 4 Prperties f Slutins Key Questins 1. Identify the principal type f slute-slvent interactin that is respnsible fr frming the fllwing slutins: (a) KNO 3 in water; (b) Br 2
More informationHow can standard heats of formation be used to calculate the heat of a reaction?
Name Chem 161, Sectin: Grup Number: ALE 28. Hess s Law and Standard Enthalpies Frmatin (Reerence: Chapter 6 - Silberberg 5 th editin) Imprtant!! Fr answers that invlve a calculatin yu must shw yur wrk
More informationMatter Content from State Frameworks and Other State Documents
Atms and Mlecules Mlecules are made f smaller entities (atms) which are bnded tgether. Therefre mlecules are divisible. Miscnceptin: Element and atm are synnyms. Prper cnceptin: Elements are atms with
More informationA Chemical Reaction occurs when the of a substance changes.
Perid: Unit 8 Chemical Reactin- Guided Ntes Chemical Reactins A Chemical Reactin ccurs when the f a substance changes. Chemical Reactin: ne r mre substances are changed int ne r mre new substances by the
More informationFind this material useful? You can help our team to keep this site up and bring you even more content consider donating via the link on our site.
Find this material useful? Yu can help ur team t keep this site up and bring yu even mre cntent cnsider dnating via the link n ur site. Still having truble understanding the material? Check ut ur Tutring
More informationChem 75 February 16, 2017 Exam 2 Solutions
1. (6 + 6 pints) Tw quick questins: (a) The Handbk f Chemistry and Physics tells us, crrectly, that CCl 4 bils nrmally at 76.7 C, but its mlar enthalpy f vaprizatin is listed in ne place as 34.6 kj ml
More informationHess Law - Enthalpy of Formation of Solid NH 4 Cl
Hess Law - Enthalpy f Frmatin f Slid NH 4 l NAME: OURSE: PERIOD: Prelab 1. Write and balance net inic equatins fr Reactin 2 and Reactin 3. Reactin 2: Reactin 3: 2. Shw that the alebraic sum f the balanced
More informationElectrochemistry. Reduction: the gaining of electrons. Reducing agent (reductant): species that donates electrons to reduce another reagent.
Electrchemistry Review: Reductin: the gaining f electrns Oxidatin: the lss f electrns Reducing agent (reductant): species that dnates electrns t reduce anther reagent. Oxidizing agent (xidant): species
More informationGOAL... ability to predict
THERMODYNAMICS Chapter 18, 11.5 Study f changes in energy and transfers f energy (system < = > surrundings) that accmpany chemical and physical prcesses. GOAL............................. ability t predict
More informationUniversity Chemistry Quiz /04/21 1. (10%) Consider the oxidation of ammonia:
University Chemistry Quiz 3 2015/04/21 1. (10%) Cnsider the xidatin f ammnia: 4NH 3 (g) + 3O 2 (g) 2N 2 (g) + 6H 2 O(l) (a) Calculate the ΔG fr the reactin. (b) If this reactin were used in a fuel cell,
More informationChem 112, Fall 05 (Weis/Garman) Exam 4A, December 14, 2005 (Print Clearly) +2 points
+2 pints Befre yu begin, make sure that yur exam has all 7 pages. There are 14 required prblems (7 pints each) and tw extra credit prblems (5 pints each). Stay fcused, stay calm. Wrk steadily thrugh yur
More informationTypes of Energy COMMON MISCONCEPTIONS CHEMICAL REACTIONS INVOLVE ENERGY
CHEMICAL REACTIONS INVOLVE ENERGY The study energy and its transrmatins is knwn as thermdynamics. The discussin thermdynamics invlve the cncepts energy, wrk, and heat. Types Energy Ptential energy is stred
More informationAP Chemistry Assessment 2
AP Chemistry Assessment 2 DATE OF ADMINISTRATION: January 8 January 12 TOPICS COVERED: Fundatinal Tpics, Reactins, Gases, Thermchemistry, Atmic Structure, Peridicity, and Bnding. MULTIPLE CHOICE KEY AND
More informationName: Period: Date: BONDING NOTES HONORS CHEMISTRY
Name: Perid: Date: BONDING NOTES HONORS CHEMISTRY Directins: This packet will serve as yur ntes fr this chapter. Fllw alng with the PwerPint presentatin and fill in the missing infrmatin. Imprtant terms
More informationChem 111 Summer 2013 Key III Whelan
Chem 111 Summer 2013 Key III Whelan Questin 1 6 Pints Classify each f the fllwing mlecules as plar r nnplar? a) NO + : c) CH 2 Cl 2 : b) XeF 4 : Questin 2 The hypthetical mlecule PY 3 Z 2 has the general
More informationChem 115 POGIL Worksheet - Week 8 Thermochemistry (Continued), Electromagnetic Radiation, and Line Spectra
Chem 115 POGIL Wrksheet - Week 8 Thermchemistry (Cntinued), Electrmagnetic Radiatin, and Line Spectra Why? As we saw last week, enthalpy and internal energy are state functins, which means that the sum
More informationCHM 152 Practice Final
CM 152 Practice Final 1. Of the fllwing, the ne that wuld have the greatest entrpy (if cmpared at the same temperature) is, [a] 2 O (s) [b] 2 O (l) [c] 2 O (g) [d] All wuld have the same entrpy at the
More informationCHE 105 EXAMINATION III November 11, 2010
CHE 105 EXAMINATION III Nvember 11, 2010 University f Kentucky Department f Chemistry READ THESE DIRECTIONS CAREFULLY BEFORE STARTING THE EXAMINATION! It is extremely imprtant that yu fill in the answer
More informationChemical Thermodynamics
Chemical Thermdynamics Objectives 1. Be capable f stating the First, Secnd, and Third Laws f Thermdynamics and als be capable f applying them t slve prblems. 2. Understand what the parameter entrpy means.
More informationCHEM 1032 FALL 2017 Practice Exam 4 1. Which of the following reactions is spontaneous under normal and standard conditions?
1 CHEM 1032 FALL 2017 Practice Exam 4 1. Which f the fllwing reactins is spntaneus under nrmal and standard cnditins? A. 2 NaCl(aq) 2 Na(s) + Cl2(g) B. CaBr2(aq) + 2 H2O(aq) Ca(OH)2(aq) + 2 HBr(aq) C.
More informationA.P. CHEMISTRY. SOLUTIONS AND ACID BASE CHEMISTRY. p 1
A.P. CHEMISTRY. SOLUTIONS AND ACID BASE CHEMISTRY. p 1 (Nte: questins 1 t 14 are meant t be dne WITHOUT calculatrs!) 1.Which f the fllwing is prbably true fr a slid slute with a highly endthermic heat
More informationCHAPTER 6 / HARVEY A. CHEMICAL EQUILIBRIUM B. THERMODYNAMICS AND EQUILIBRIUM C. MANUPULATING EQUILIBRIUM CONSTANTS
CHPTER 6 / HRVEY. CHEMICL B. THERMODYNMICS ND C. MNUPULTING CONSTNTS D. CONSTNTS FOR CHEMICL RECTIONS 1. Precipitatin Reactins 2. cid-base Reactins 3. Cmplexatin Reactins 4. Oxidatin-Reductin Reactins
More informationMaterials Engineering 272-C Fall 2001, Lecture 7 & 8 Fundamentals of Diffusion
Materials Engineering 272-C Fall 2001, Lecture 7 & 8 Fundamentals f Diffusin Diffusin: Transprt in a slid, liquid, r gas driven by a cncentratin gradient (r, in the case f mass transprt, a chemical ptential
More information4 electron domains: 3 bonding and 1 non-bonding. 2 electron domains: 2 bonding and 0 non-bonding. 3 electron domains: 2 bonding and 1 non-bonding
[4.3D VSEPR] pg. 1 f 7 Curriculum The use f VSEPR thery t predict the electrn dmain gemetry and the mlecular gemetry fr species with tw, three and fur electrn dmains. Shapes f species are determined by
More informationFind this material useful? You can help our team to keep this site up and bring you even more content consider donating via the link on our site.
Find this material useful? Yu can help ur team t keep this site up and bring yu even mre cntent cnsider dnating via the link n ur site. Still having truble understanding the material? Check ut ur Tutring
More informationThermochemistry. The study of energy changes that occur during chemical : at constant volume ΔU = q V. no at constant pressure ΔH = q P
Thermchemistry The study energy changes that ccur during chemical : at cnstant vlume ΔU = q V n at cnstant pressure = q P nly wrk Fr practical reasns mst measurements are made at cnstant, s thermchemistry
More information15.0 g Cr = 21.9 g Cr O g Cr 4 mol Cr mol Cr O
WYSE Academic Challenge Sectinal Chemistry Exam 2008 SOLUTION SET 1. Crrect answer: B. Use PV = nrt t get: PV = nrt 2. Crrect answer: A. (2.18 atm)(25.0 L) = n(0.08206 L atm/ml K)(23+273) n = 2.24 ml Assume
More informationGASES. PV = nrt N 2 CH 4 CO 2 O 2 HCN N 2 O NO 2. Pressure & Boyle s Law Temperature & Charles s Law Avogadro s Law IDEAL GAS LAW
GASES Pressure & Byle s Law Temperature & Charles s Law Avgadr s Law IDEAL GAS LAW PV = nrt N 2 CH 4 CO 2 O 2 HCN N 2 O NO 2 Earth s atmsphere: 78% N 2 21% O 2 sme Ar, CO 2 Sme Cmmn Gasses Frmula Name
More informationO C S polar - greater force. H polar greater force. H polar. polar H-bond
hapter 10 : 29, 30, 31, 33, 36, 40, 46, 48, 50, 72, 87, 91, 93, 110 29. a. Lndn e. Lndn b. diple-diple f. diple-diple c. -bnding g. in-in d. in-in 30. a. in-in e. -bnding b. Lndn f. diple-diple c. Lndn
More informationN 2 (g) + 3H 2 (g) 2NH 3 (g) o Three mole ratios can be derived from the balanced equation above: Example: Li(s) + O 2 (g) Li 2 O(s)
Chapter 9 - Stichimetry Sectin 9.1 Intrductin t Stichimetry Types f Stichimetry Prblems Given is in mles and unknwn is in mles. Given is in mles and unknwn is in mass (grams). Given is in mass and unknwn
More informationBootstrap Method > # Purpose: understand how bootstrap method works > obs=c(11.96, 5.03, 67.40, 16.07, 31.50, 7.73, 11.10, 22.38) > n=length(obs) >
Btstrap Methd > # Purpse: understand hw btstrap methd wrks > bs=c(11.96, 5.03, 67.40, 16.07, 31.50, 7.73, 11.10, 22.38) > n=length(bs) > mean(bs) [1] 21.64625 > # estimate f lambda > lambda = 1/mean(bs);
More informationChapter 8 Reduction and oxidation
Chapter 8 Reductin and xidatin Redx reactins and xidatin states Reductin ptentials and Gibbs energy Nernst equatin Disprprtinatin Ptential diagrams Frst-Ebswrth diagrams Ellingham diagrams Oxidatin refers
More informationLecture 17: Free Energy of Multi-phase Solutions at Equilibrium
Lecture 17: 11.07.05 Free Energy f Multi-phase Slutins at Equilibrium Tday: LAST TIME...2 FREE ENERGY DIAGRAMS OF MULTI-PHASE SOLUTIONS 1...3 The cmmn tangent cnstructin and the lever rule...3 Practical
More informationHeat Effects of Chemical Reactions
* eat Effect f hemical Reactin Enthalpy change fr reactin invlving cmpund Enthalpy f frmatin f a cmpund at tandard cnditin i btained frm the literature a tandard enthalpy f frmatin Δ O g = -9690 J/mle
More informationenthalpies of formation for a few thousand compounds can be used for thermochemical calculations for millions of different chemical reactions
hater 4. hermchemistry Summary thermchemistry: branch f thermdynamics dealing with energy changes f chemical reactins, w, U, and are calculated fr chemical reactin rcesses enthalies f frmatin are intrduced
More informationA. Lattice Enthalpies Combining equations for the first ionization energy and first electron affinity:
[15.1B Energy Cycles Lattice Enthalpy] pg. 1 f 5 CURRICULUM Representative equatins (eg M+(g) M+(aq)) can be used fr enthalpy/energy f hydratin, inizatin, atmizatin, electrn affinity, lattice, cvalent
More informationChE 471: LECTURE 4 Fall 2003
ChE 47: LECTURE 4 Fall 003 IDEL RECTORS One f the key gals f chemical reactin engineering is t quantify the relatinship between prductin rate, reactr size, reactin kinetics and selected perating cnditins.
More informationCHEM 1413 Chapter 6 Homework Questions TEXTBOOK HOMEWORK
CHEM 1413 Chapter 6 Hmewrk Questins TEXTBOOK HOMEWORK 6.25 A 27.7-g sample f the radiatr clant ethylene glycl releases 688 J f heat. What was the initial temperature f the sample if the final temperature
More informationThermochemistry Heats of Reaction
hermchemistry Heats f Reactin aa + bb cc + dd hermchemical Semantics q V = Heat f Rxn at [V] = U = Energy (change) f Rxn q P = Heat f Rxn at [P] = H = Enthalpy (change) f Rxn Exthermic rxns: q < 0 Endthermic
More informationIn the half reaction I 2 2 I the iodine is (a) reduced (b) oxidized (c) neither of the above
6.3-110 In the half reactin I 2 2 I the idine is (a) reduced (b) xidized (c) neither f the abve 6.3-120 Vitamin C is an "antixidant". This is because it (a) xidizes readily (b) is an xidizing agent (c)
More informationSupporting information
Electrnic Supplementary Material (ESI) fr Physical Chemistry Chemical Physics This jurnal is The wner Scieties 01 ydrgen perxide electrchemistry n platinum: twards understanding the xygen reductin reactin
More informationChapter 19. Electrochemistry. Dr. Al Saadi. Electrochemistry
Chapter 19 lectrchemistry Part I Dr. Al Saadi 1 lectrchemistry What is electrchemistry? It is a branch f chemistry that studies chemical reactins called redx reactins which invlve electrn transfer. 19.1
More informationDispersion Ref Feynman Vol-I, Ch-31
Dispersin Ref Feynman Vl-I, Ch-31 n () = 1 + q N q /m 2 2 2 0 i ( b/m) We have learned that the index f refractin is nt just a simple number, but a quantity that varies with the frequency f the light.
More informationEdexcel IGCSE Chemistry. Topic 1: Principles of chemistry. Chemical formulae, equations and calculations. Notes.
Edexcel IGCSE Chemistry Tpic 1: Principles f chemistry Chemical frmulae, equatins and calculatins Ntes 1.25 write wrd equatins and balanced chemical equatins (including state symbls): fr reactins studied
More informationUnit 10: Kinetics And Equilibrium
Name Unit 10: Kinetics And Equilibrium Skills 1. Understand thery f reactin kinetics 2. Understand factrs affecting reactin rate 3. Drawing and interpreting ptential energy diagrams 4. Distinguish between
More informationFind this material useful? You can help our team to keep this site up and bring you even more content consider donating via the link on our site.
Find this material useful? Yu can help ur team t keep this site up and bring yu even mre cntent cnsider dnating via the link n ur site. Still having truble understanding the material? Check ut ur Tutring
More informationMidterm Review Notes - Unit 1 Intro
Midterm Review Ntes - Unit 1 Intr 3 States f Matter Slid definite shape, definite vlume, very little mlecular mvement Liquid definite vlume, takes shape f cntainer, mlecules mve faster Gas des nt have
More information**DO NOT ONLY RELY ON THIS STUDY GUIDE!!!**
Tpics lists: UV-Vis Absrbance Spectrscpy Lab & ChemActivity 3-6 (nly thrugh 4) I. UV-Vis Absrbance Spectrscpy Lab Beer s law Relates cncentratin f a chemical species in a slutin and the absrbance f that
More informationChem 163 Section: Team Number: ALE 24. Voltaic Cells and Standard Cell Potentials. (Reference: 21.2 and 21.3 Silberberg 5 th edition)
Name Chem 163 Sectin: Team Number: ALE 24. Vltaic Cells and Standard Cell Ptentials (Reference: 21.2 and 21.3 Silberberg 5 th editin) What des a vltmeter reading tell us? The Mdel: Standard Reductin and
More informationCHEMICAL EQUILIBRIUM
14 CHAPTER CHEMICAL EQUILIBRIUM 14.1 The Nature f Chemical Equilibrium 14. The Empirical Law f Mass Actin 14.3 Thermdynamic Descriptin f the Equilibrium State 14.4 The Law f Mass Actin fr Related and Simultaneus
More informationUniversity of Waterloo DEPARTMENT OF CHEMISTRY CHEM 123 Test #2 Wednesday, March 11, 2009
University f Waterl DEPARTMENT OF CHEMISTRY CHEM 13 Test # Wednesday, March 11, 009 This is test versin 001. Fill in vals 001 fr the Card Number (r Test Master) n yur cmputer answer card. Name (Print in
More informationNUPOC STUDY GUIDE ANSWER KEY. Navy Recruiting Command
NUPOC SUDY GUIDE ANSWER KEY Navy Recruiting Cmmand CHEMISRY. ph represents the cncentratin f H ins in a slutin, [H ]. ph is a lg scale base and equal t lg[h ]. A ph f 7 is a neutral slutin. PH < 7 is acidic
More information( ) kt. Solution. From kinetic theory (visualized in Figure 1Q9-1), 1 2 rms = 2. = 1368 m/s
.9 Kinetic Mlecular Thery Calculate the effective (rms) speeds f the He and Ne atms in the He-Ne gas laser tube at rm temperature (300 K). Slutin T find the rt mean square velcity (v rms ) f He atms at
More information