PUSH GRAVITY DOES NOT EXIST. Bert Schreiber 4519 Holly St. Bellaire, TX PART 1

Transcription

1 PUSH GRAVITY DOES NOT EXIST Bert Schreiber 4519 Holly St. Bellaire, TX PART 1 There keeps cropping up some persons who believe in PUSH Gravity. Under normal circumstances, this could be so. Unfortunately, it is not; because gravity, or rather its effect, is unique in this Universe. Under the assumption that its effect could be push, it would follow Riemann's postulate that reversing one thing does not change it whatsoever. Simply, it is what he called its Mirror Image. They are one and the same and cannot be distinguished. Reverse the charge of an electron and you would still get the same answers as the positron; then, simply changes its charge sign. Make, and it has been done, positronium which is an antiproton with a positron orbiting it, and it should give off the identical radiation a normal hydrogen atom does and has the same mass, etc. Push Gravity will not stand up to any logic as now follows. The author has to follow current beliefs, so the author will assume that Newton's Equation for gravitational attraction is still true and Einstein's GRT on small masses falling to the Earth, even though they are not. There will be used a simple Thought Experiment. Let there be two small masses placed one on each side of the division line between the Earth's and the Moon's neutral Gravitational Force point, no other masses in space. With pull Gravity, the mass nearest each of the aforesaid masses would then be pushed (attracted) towards it. Now, exchange said masses and the results remain the same. Now using Push Gravity would require intelligence because that force and its effect would have to determine that the mass nearest the Earth must be pushed towards the Earth and the other pushed towards the Moon. That is only half the problem. The force on the Earth's side mass is greater than the force on the Moon's side mass. It has to be, if it is going to move towards the Earth. The force on the Moon's side mass is then zero. How can that be if they are the same size mass? Ditto for the one on the Moon's side. Again, reverse the masses and they each instantly change to their new values as zero became larger, and larger became zero, relative that is. Now change those masses to a one-atom-thick sheet with only one atom diameter length separation. Now explain just how Gravity, either kind, can determine which sheet is on which side so it will move towards its respective attractor? There is an answer as it is just not ever mentioned. The force of the Earth and Moon at the exact point center between those identical sheets is zero and the one nearest the Earth has a small attraction; but the one furthermost is zero and, same for the second in reverse, i.e., the space between those sheets marks the midpoint.

2 This illustration is flawed as they would move toward one another when separated by one-atom thickness. They must be slightly further apart, but not much, so that their mutual attraction is proportionally increased-decreased by the Earth-Moon Forces. Something like 1 or so centimeters should do it. Now do this diametrically opposite, but we will put other masses into our space like it really is. In this case, the direction of push has to reverse from that which it was in the first case or, whatever caused that Gravity push must have intelligence to know where said masses are in relation to the other masses. That is, the push would force the mass nearest the Earth away from the Earth and not towards, as when on the other side. But wait, suppose this push originated from the smaller mass? No problem with that. Then what will be the result for two identical masses as they both would push the same and push apart, not push together? Based on Newton's Equation and Einstein's GRT, for small falling masses, what would be same under the push scenario? The smaller the mass, the greater the push so that an electron would be the smallest and largest source of push in the Universe. The larger the mass, the weaker the push and that is where it completely falls apart. Of course, these believers will say the push comes from outer space pushing all those masses together and not from the masses themselves, i.e., Mach's Postulates or insanity. They only are effected by it. Sort of like a bit of iron is attracted to a magnet. Doesn't compute. The magnetic field of the magnet magnetizes the iron and so would that mysterious Push Gravity source have to gravitize the other masses in the Universe, so that it would have to do the reverse of current pull Gravity; and again, the smaller the mass, the greater the push. That won't work either, as a couple of molecules of any two atoms, would be pushed so hard together that one could never separate them again from the Gravity push alone. Not only that, as that mass became larger, the gravitational force becomes weaker; and if said mass was rotating, would spin off mass with no problem. The Universe would collapse into a speck and disappear. Push Gravity is just not thought out nor are there any equations using more than two masses to support it. At least not any the author has ever seen. It seems to be one of those talked into existence theories ; totally unsupported with the available evidence, which shows just the opposite. Just fanatical beliefs spouted off. PART 2 END OF PUSH GRAVITY IF there were only two masses in the Universe, Push Gravity would work. It will not and cannot work for three or more masses. Many scientific papers use only two masses to prove that shadowing/shielding effect. No one will insert a third mass as that would make their papers worthless and they cannot prove what they are proving. Such papers should not be published and pass the editor s desk in the first place. 2

3 Due to vagueness (lots of verbiage) of those who profess to Push Gravity, it is going to be necessary to discuss what the words they use mean. The semantics of the English language leave a lot of room for maneuvering. Push and pull are relative, so there can be a push or pull with no opposite effect or action. A pitcher can throw a ball (push), but the catcher is surely not pulling the ball into his glove. As to Push Gravity effect, the usage of push will mean that there is some force coming in from outside the system which results in its loss [shielding/shadowing] causing the mass in question to be pushed away from the direction of the source. This loss of force is then assumed to be some value less than the original force impinging on the mass so that the net difference, in vs. out, is called push, which is in the direction of the incoming force. There is no problem with a two-mass system. There is a problem when there are more than two masses, especially when their masses are different. In fact, it results in impossibilities. To keep the calculations simple, the common center of mass rotation is ignored (can't happen anyway with Push Gravity) and the specific lengths the masses are apart, likewise. The entire concept is there is no opposite effect in either the push or pull effect for gravity. Either system gives gravity effect a one way ticket and there is no anti-gravity in either system. A simple observation and actual measurements easily demolishes the whole verbiage concept of Push Gravity on the Earth. Any mass sitting on the surface moves up and down to the surface (solid) tides of the Earth. Depending on the parameters, about 18 or so inches up and down, maximum, once a Lunar Month; less daily. This slight movement away from the exact center of the Earth, causes its weight to be less, also g n, and that is due to the effect of gravity varying as to the inverse square of the length from the center of the Earth, etc. This weight loss is about 2 x 10-6 parts. It is, therefore, impossible for such a slight movement to have any measurable effect if and when the force comes from outside and from shielding. The amount of mass being moved does not change, only its relative density. Ergo, no change in shielding. To mathematically (it has been done by models, but models are not reality) explain the Earth - Moon - Sun tides using Push Gravity, has never been done. A mechanical model was constructed by one such person which apparently showed that Push Gravity existed and used the tides as his proof. The author destroyed this poor soul s proof (and informed him and heard nothing thereafter) by a simple experiment. To a strip of wood with a hole in the center, affix on each end a rubber band with a small weight attached using different weights on each. Staple the free end of the band onto the stick at a short length away from the hole. Insert stick via the hole in a variable speed electric drill. Perform this experiment in the open and drill in a horizontal position, i.e., plane of rotation vertical to experimenter. If the bands break, the weights fly off with a high speed and can cause damage. Start rotation slowly and drill will vibrate. As the speed is increased the vibrations cease as the weights will self-position themselves to self-balance said rotation. Why the water on the Earth bulges out on the opposite side of the Earth when the Earth-Moon-Sun are aligned in said order, is explained by some very complicated, and not really believed, theory. 3

4 The gravitational pull has nothing to do with it. The water simply balances out the vibrations exactly as those two weights did. It is a proven rotational mechanical causation of self-balancing and no theory is required. End of any tide theories. Lastly, it would require the Push Gravity to then act as the inverse square of the length, etc., or that once it passes through a mass, it mysteriously creates a new force acting as same. That, too, is impossible as it could somehow focus through a spherical mass, but would not focus going through a pancake galaxy, i.e., and a ball of mass vs. a disk of mass. This is the same as the Ptolemaic System, From Ptolemy (ca ), Solar-Planet system using epicycles which over time, required more and more minor epicycles to explain new observations/discoveries made to the Solar System. It finally got so complicated {Schreiber s axiom} that it was apparently a worthless theory and N. Copernicus ( ), with his new one, the heliocentric system (Sun as center), then solved the problem. The author is now (no more verbiage including above, since the Push Gravity believers have never done so) going to do the mathematics and prove, once and for all time, hopefully, there is NO SUCH THING AS PUSH GRAVITY EFFECT. The author is going to have to assume some rules that the author believes they mean, but never specifically spell out (i.e., what are their postulates, another flaw in their papers) can be used to show why shadowing does not compute. The first is that it will be assumed that the external source has some unit value of 100 units of force coming from outer space, equally in, and from, all directions. The next is that such a shadowing is based upon the amount of mass in the bodies in question such that there is a 10% drop per 100 mass units. This differential, or shadowing, is then the source of that push if understand correctly. It is easily understood that one considers these forces as projectiles which pass through the mass; and those which are stopped (absorbed), then push the mass inwards. 1. There is then shown that this shadowing effect does not follow known visual observations of/in the Solar System, nor matches the known force equations and experimental results for all the known forces, electric, magnetic, and gravity. 2. There is chosen a special Solar System using three masses in such. One, a large Sun of 100 mass units (m) and two others whose units are 2 and 1 units of mass. What then happens is that the force coming in through the Sun is decreased before it hits the other two masses. The force coming in from the other direction does not change until the vector effective force exists. For simplicity, only the in-line values used. Due to others wanting minutiae, there will be a slight increase of the remaining force when the angular values are such that they intercept the other masses. That requires inserting lengths they are away from one another, etc. All the masses in question are assumed to lie in the same plane. Since this force originates at near infinity, then the force lines must be parallel or the effect is identical to parallel lines. Therefore, when absorbed, the remaining force decreases in strength only. It is an impossibility for said force to vary as the inverse square of the length since it does not originate at the masses themselves. Consider same as nothing more than a perfectly collimated light beam with varying density filters inserted in it. It is going to be difficult to follow what is relative to what. The Sun will be used as the point frame of reference. The arrows show the direction of the original, and then the remaining force. To prevent confusion, the < and > are used to show the net result(s) and its direction of action. > is in towards Sun and < away from Sun. The arrows are in plane as shown in FIGURE 1 view looking down on this system. 4

5 Understanding this is very mind boggling and not simple. Specifically, keeping all of the relative directions and effects in mind at once. Essentially, what is going in, what is happening, and what is the relative effect; push, in, effect in, out, etc. F = 100 m B 1M C A F = 100 m 1M 2M 1M F = 90 m 100M F = 100 m >Sun 1M D F = 100 m FIGURE 1 When the 1M mass is at point B or D, the Force coming in through the Sun is then: 99 1M 100 so that the net result is then 1 < for either. The force acting on 2M after passing through 1 M is then: 100 1M.99 2M The net result is then: = = 1.98 = 2.98 The force acting on 1M after passing through 2M is then: 100 2M 98 1M The net result is then: = =.98 = 2.98 The end result is zero effect for these, leaving only the Sun's effect of 1<. When 1M is at position A, the forces are then, when going through the Sun first: M M M 100 When going through 2M first, the forces are then: 100 2M 98 1M The net result is then : =.9< = < and = 2 > =.98> = 2.98> The net result is: =.218 > and =.08 > =.298 > When 1M is at position C, the forces then, when going through the Sun first: M M M 100 When going through 1M then: 100 1M 99 2M The net result is then: = 1.8 < =.882 < = < = 1 > = 1.98 > = 2.98 > The net result is then: 2.98 > < =.298 > FIGURE 2 then shows each of these in turn for one orbit of 1M. Value/direction of Forces: For B and D position, a is from Sun through 1M,and for position A, from Sun then through 1M, then through 2M. 5

6 b is from outside through 2M,then through 1M. For C position, c is from Sun through 2M,then through 1M and d is from outside through 1M, then through 2M. a1 1M = 0 47 b-a =.218 > a1.782 b 2 d-c =.118 > b-a =.08 > c.882 1M d 1 2M a.9 1M b.98 c 1.8 d 1.98 d-c =.18 > = 0 a1 1M FIGURE 2 A mere glance at the FIGURE 2 shows the impossibility of Push Gravity. That is, provided one looked closely at the results of the calculations for position A and C which show that the effective net forces are both inwards towards the Sun, which is correct. However, at position B and D, there are no inward Forces, but only the outward one away from Sun and that destroys the equilibrium of the system. The total force for position A and C is correct; but the individual contribution is not balanced whatsoever. To follow through, there is then: When position is A, the 2M mass is going the difference of.218 > [ ] and the 1M mass.08 > [ ]. The acceleration of 2M is then about 1.3+ greater than 1M's acceleration. When, if it could, 1M moves to position B, the acceleration is outward, then moves to position C and moves in slow,.118; then at position D, it once more again moves outward very fast, 1. Simply going from A through D positions, its net force = acceleration since M = 1, is then: or 1 greater than.118 or 8.5 times larger; so it would not slow down any great amount, but keep on going outward (vector value) and ditto for 1 greater than.08 or about 12.5 times larger, so it would go still faster outward into space. In fact, they could never be in such a position, to even start with, or rotating around one other's center Of mass rotation. mv 2 /r = constant (1) so all Forces must not vary to start with. Simply, gravity effect must originate with/at the source's center and vary as the inverse square of the length from the mass s centers, etc. The Push Gravity system is totally unstable/unbalanced and 1M would go flying off into space or be thrown outward. All three of these results, so set forth, should end the theory of Push Gravity once and for all. It never could exist in the first place as per the opening statements. And so much for E. Mach and his postulate #1 and his meaningless postulate #2. Reformatted January