AN ANALYSIS OF TWO DIMENSIONAL INTEGRAL EQUATIONS OF THE SECOND KIND

Size: px
Start display at page:

Download "AN ANALYSIS OF TWO DIMENSIONAL INTEGRAL EQUATIONS OF THE SECOND KIND"

Transcription

1 AN ANALYSIS OF TWO DIMENSIONAL INTEGRAL EQUATIONS,... 5 LE MATEMATICHE Vol. LXII (2007) - Fs. I, pp AN ANALYSIS OF TWO DIMENSIONAL INTEGRAL EQUATIONS OF THE SECOND KIND M. M. EL-BORAI - M. A. ABDOU - M. BASSEEM In this rtile, A numeril method is used to solve the two dimensionl Fredholm integrl eqution of the seond kind with wek singulr kernel using the Toeplitz mtrix nd produt Nystrom method. The numeril results given in this pper re omputed using mple 8. The error, in eh se, is omputed.. Introdution. Singulr integrl equtions rise in mny problems of mthemtil physis. Its pplitions re in mny importnt fields like frture mehnis, erodynmis, the theory of porous filtering, ntenn problems in eletromgneti theory nd others. The solutions of their pplitions n be obtined nlytilly, using the theory developed by Muskhelishvili [], but in prtie pproximte methods re needed to solve the Fredholm integrl eqution in one dimensionl problem with different kernels. The diret numeril re preferred, whih ttk the eqution s it is written, without trnsforming it beforehnd into Fredholm eqution. Among Entrto in redzione il 6 Mrzo Key words: Toeplitz mtrix, Nystrom method, logrithmi kernel, Crlemn kernel, liner lgebri system A.M.S.: 45B05, 45E0, 65R.

2 6 M. M. EL-BORAI - M. A. ABDOU - M. BASSEEM these, Glerkin method [2], blok by blok method, Nystrom method [3] nd Toeplitz mtrix method [4]. Afterwrds, mny numeril methods, whih solve problems in one dimensionl integrl equtions, n be found in the books [5], [6] nd [7]. Here, in this work, the existene nd uniqueness solution of the singulr Fredholm integrl eqution in two dimensionl re proved. Also, we use the Toeplitz mtrix nd produt Nystrom method, s fmous methods for solving singulr integrl equtions, to obtin numerilly the solution of the integrl eqution. The error, in eh se, is omputed when the kernel of Fredholm tkes logrithmi nd Crlemn form. 2. Existene nd uniqueness solution. We onsider the two dimensionl Fredholm integrl eqution (2.) µ (x, y) λ b d k(x, u; y,v) (u,v)dvdu = f (x, y), where µ is onstnt defined the kind of the integrl eqution, for µ = 0 nd µ = onstnt 0, we hve, respetively, the Fredholm first nd seond kind, while λ is onstnt, my be omplex, tht hs mny physil mening. The known funtions k(x, u; y, v) nd f (x, y) represent respetively, the disontinuous kernel of the integrl eqution nd its free term. While (x, y) represents the unknown funtion. Assume the following onditions: (i) The generl kernel k(x, u; y, v) stisfies the ondition (2.2) b b d d { k(x, u; y,v) 2 dxdudydv} 2 C, C is smll enough. (ii) The given funtion f (x, y) nd its prtil derivtives with respet to x, y re ontinuous nd its normlity in L 2 [, b] L 2 [, d] is given by (2.3) f (x, y) L2 [,b] L 2 [,d]= [ b d f (x, y) 2 dxdy] 2 = D (iii) The unknown funtion (x, y) stisfies Lipshitz ondition for the rguments x, y, where its norm is onsidered in L 2 [, b] L 2 [, d].

3 AN ANALYSIS OF TWO DIMENSIONAL INTEGRAL EQUATIONS,... 7 Theorem 2. Using the previous onditions, where λ < µ C, the solution of (2.) is exist nd unique. Proof. To prove tht the solution of Eq.(2.) is exist, we use the Pird method, by piking up ny rel ontinuous funtion φ 0 (x, y) in L 2 [, b] L 2 [, d], then onstruting sequene φ n (x, y) to hve µφ n (x, y)= f (x, y)+λ b d (2.4) µφ 0 (x, y) = f (x, y). It is onvenient to introdue: (2.5) then µψ n (x, y) = µ[φ n (x, y) φ n (x, y)] = λ b d (2.6) φ n (x, y) = Using (2.5), we get (2.7) µψ n (x, y) = λ b d k(x, u; y,v)φ n (u,v)dvdu, n =, 2, 3,... k(x, u; y, v)(φ n (u,v) φ n 2 (u,v))dvdu, n ψ i (x, y). i=0 k(x, u; y,v)ψ n (u,v)dvdu, Tking the norm of Eq.(2.7), we obtin (2.8) µ ψ n (x, y) = λ b d µψ 0 = f (x, y). k(x, u; y,v)ψ n (u,v)dvdu. For n =, then using Cuhy-Shwrz inequlity, we hve (2.9) Hene, we get ψ (x, y) λ µ { b b d d (2.0) ψ (x, y) λ µ CD. k(x, u; y,v) 2 dxdudydv} 2 ψ0 (x, y).

4 8 M. M. EL-BORAI - M. A. ABDOU - M. BASSEEM By indution, one hs (2.) ψ n (x, y) α n D, α = λ µ C. This bound under the used ondition λ < µ C ψ n (x, y) uniformly onvergent. Hene, we get (2.2) (x, y) = ψ i (x, y). i=0 mkes the sequene Sine eh of ψ i (x, y) in (2.2) is ontinuous, therefore φ i (x, y) is lso ontinuous, onvergent nd represents the existene of the solution of Eq. (2.). To prove (x, y) is the unique solution of Eq. (2.), ssume (x, y) is nother solution, hene, we get (2.3) (x, y) (x, y) = λ b d k(x, u; y,v)[ (u,v) (u,v)]dvdu. µ Applying Cuhy-Shwrz inequlity nd onditions (i) nd (iii), we get (2.4) (x, y) (x, y) α (x, y) (x, y), α <, whih leds to =. 3. Integrl opertor. The normlity nd ontinuity of the integrl opertor re very importnt to prove the existene nd uniqueness solution of the integrl eqution of the first kind or for homogeneous integrl eqution, where the Pird method fils. For this, ssume the integrl opertor (2.5) W = f µ + K where b d (2.6) K = λ k(x, u; y,v) (u,v)dvdu. µ Hene, the formul (2.), yields (3.7) W =

5 AN ANALYSIS OF TWO DIMENSIONAL INTEGRAL EQUATIONS,... 9 The normlity of K n be showed s follows (3.8) K = λ µ b d k(x, u; y,v) (u,v)dvdu, then, using Cuhy-Shwrz inequlity nd ondition (i), we hve (3.9) K λ µ C = α, α = λ µ C. So by the ondition α<,k is bounded, whih leds to sy tht W is lso bounded opertor. The ontinuity of the integrl opertor W, given by (3.5), n be proved by ssuming n (x, y), m (x, y) stisfy Eq.(3.5) then (3.20) W n W m = K n K m α n m. Therefore, if n m 0, then W n W m 0, whih yields W is ontinuous opertor. Hene, W is ontrtion mpping, then, by Bnh fixed point theorem, the Eq. (2.) hs unique solution. 4. Method of Solution. Here, we disuss the solution of integrl eqution, in two dimensionl problem, using two different methods Toeplitz mtrix method. Toeplitz mtrix method is used to obtin the numeril solution of two dimensionl integrl eqution of the seond kind with singulr kernel. The ide of this method is to obtin, in generl, system of (2N +) (2M+) liner lgebri eqution, where 2N + nd 2M + re the numbers of disretiztion points used in x nd y dimensions respetively. The oeffiients mtrix is expressed s the sum of two mtries, one of them is the Toeplitz mtrix nd the other is mtrix with zero elements exept the first nd lst rows nd olumns.

6 20 M. M. EL-BORAI - M. A. ABDOU - M. BASSEEM (4.2) For this, we ssume = N n= N l= M b d k(x, u; y,v) (u,v)dvdu0 M (n+)h (l+)h =nh =lh k(x, u; y,v) (u,v)dvdu, where h = b nd h = d. The integrl of the right hnd side N M of Eq.(4.2) n be evluted by ssuming x = mh, inresing by rte h, nd y = ph, inresing by rte h. Therefore, (4.22) (n+)h (l+)h k(x, u; y,v) (u,v)dvdu nh lh = A(x, y) (nh, lh ) + B(x, y) (nh,lh + h ) +C(x, y) (nh + h, lh ) + D(x, y) (nh + h, lh + h ) + R. where the weights of the integrtion A, B, C nd D re funtions of x, y will be determined, nd R is the error term. For the prinipl of Toeplitz mtrix method, to solve Eq.(4.22), we ssume (x, y) =, x, y, xy, in this se R = 0, whih led to I = I 2 = nh+h lh +h nh nh+h lh +h nh lh k(x, u; y,v)dvdu = A + B + C + D, lh + C(nh + h) + D(nh + h), uk(x, u; y,v)dvdu = Anh + Bnh (4.23) nh+h lh +h I 3 = vk(x, u; y,v)dvdu = Alh + B(lh + h ) nh lh + Clh + D(lh + h ), nh+h lh +h I 4 = uvk(x, u; y,v)dvdu = Anhlh nh lh + Bnh(lh + h ) + Clh (nh + h) + D(nh + h)(lh + h ).

7 AN ANALYSIS OF TWO DIMENSIONAL INTEGRAL EQUATIONS,... 2 In ft, one n esily evlute weights expliity, but we prefer to evlute suh integrl numerilly, then the vlues of A, B, C nd D re diretly obtined, where (4.24) A = (nl + n + l + )I l + h I 2 n + h I 3 + hh I 4, B = (nl + l)i + l h I 2 + n + h I 3 hh I 4, C = (nl + n)i + l + h D = nl I l h I 2 n h I 3 + hh I 4. Let x = mh, y = ph, so Eq.(4.2) beomes (4.25) b d k(x, u; y,v) (u,v)dvdu = I 2 + n h I 3 hh I 4, N M n= N l= M χ l,p n,m N,M(nh, lh ), where C n,l + D n,l, if n = N B n,l + D n,l, if l = M (4.26) χn,m l,p = A n,l +B n,l +C n,l +D n,l, if M + l M, if N + n N A n,l + B n,l, if n = N A n,l + C n,l, if l = M nd N,M is the numeril pproximte solution, whih stisfy the following formul (4.27) (x, y) N,M 0 s N, M. Hene, Eq.(2.) is pproximtely equivlent to the following (4.28) N M µ N,M (mh, ph ) λ χn,m l,k N,M(nh, lh ) = f (mh, ph ) n= N l= M whih represents system of liner lgebri equtions. The mtrix χ l,p n,m n be written s (4.29) χ l,p n,m = χ l p n m G l,p n,m,

8 22 M. M. EL-BORAI - M. A. ABDOU - M. BASSEEM where (4.30)χn m= l p!a n,l +B n,l +C n,l +D n,l,, M l M,, N n N, whih is the Toeplitz mtrix of order (2N + ) (2M + ) nd A n,l + B n,l + C n,l, n = N, l = M A n,l + C n,l, l = M A n,l + B n,l, n = N (4.3) G l,p n,m = 0, N + n N, M + l M B n,l + D n,l, l = M C n,l + D n,l, C n,l + B n,l + D n,l, n = N l = M, n = N The formul (4.30) represents the elements of Toeplitz mtrix of order (2N + ) (2M + ),while (4.3) is mtrix of order (2N + ) (2M + ) whose elements re zeros exept the first nd lst rows nd olumns. However, the liner lgebri system of (4.28) n be redued to the following mtrix form (4.32) [µi λ(χ G)] = F, µi λ(χ G) = 0. Definition 4.. The estimte lol error R N,M n be determined by the following eqution (x, y) N,M (x, y) = (4.33) N M χn m[ (nh, l p lh ) N,M (nh, lh )] + R N,M, where (4.34) n= N l= M b R N,M = d k(x, u; y,v) (u,v)dvdu N M n= N l= M χ l p n m (nh, lh ). Definition 4.2. The Toeplitz mtrix method is sid to be onvergent of order r + r 2 in the domin [, b] [, d], if nd only if for lrge N, M,

9 AN ANALYSIS OF TWO DIMENSIONAL INTEGRAL EQUATIONS, there exist onstnt D > 0 independent of N, M suh tht (4.35) (x, y) N,M (x, y) DN r M r 2 5. Convergene of lgebri system. Theorem 5.. The liner lgebri system of Eq. (4.28), when N, M is bounded nd hs unique solution under the following onditions (i) f (x, y) = (ii) n= l= l= p= n= l= f 2 (nh, lh ) 2 < H, His onstnt. (5.36) (χ l p n m) 2 2 < Q, Q is onstnt. (5.37) (iii) λ < µ Q. (5.38) Proof. The onvergene of the liner system (4.28) n be proved by onsidering the two bounded sets x, ȳ { s}, where { s} is the fmily set of ll bounded vetors. Here, the metri spe will defined by (5.39) ρ( x, ȳ) = sup x l ȳ l, l nd (5.40) x = (x, x 2 ), ȳ = (y, y 2 ), x i ={x (i) l } l=, y i ={y (i) l } l=, i =, 2. Set the opertor sum L { s} : R 2 R 2 suh tht (5.4) z = L x, z = (z, z 2 ) R 2. Let (5.42) z = n,l= L l,n x + C,

10 24 M. M. EL-BORAI - M. A. ABDOU - M. BASSEEM where (5.43) C = (, 2 ), i ={ (i) l } l= R, i =, 2. The system of Eq.(4.28), when N, M, n be written in the form (5.44) x m,p = µ f m,p l + λ µ l,n= χ l p n mx l,n. From the two liner system of Eq.(5.42) nd (5.44), we tke (5.45) S m,p = λ χ l p n m = λ K l,n. µ µ l,n= l,n= Apply Cuhy-Minkowski inequlity, with the id of ondition (ii) of theorem (5.), we get (5.46) S m,p < λ Q <. µ Therefore, under the ondition λ < µ we hve unique solution of Q (5.44), nd the vlue of x m,p stisfies H (5.47) x m,p <, µ λ. µ λ To prove x m,p is the unique solution of Eq. (5.44), ssume xm,p is nother solution. Hene, we get (5.48) x m,p xm,p = λ χ l p µ n m[x l,n xm,p ]. l,n= Applying Cuhy-Shwrz inequlity nd onditions (i) nd (ii) of theorem (5.), we get (5.49) x m,p x m,p λ µ Q x m,p x m,p. Therefore, we hve x m,p = x m,p. Corollry 5.. then Assume tht, onditions of Theorem (5.) re verified, (5.50) lim N,M R N,M = 0.

11 AN ANALYSIS OF TWO DIMENSIONAL INTEGRAL EQUATIONS, Proof. The formul (4.33), yields (5.5) R N,M = [ (x, y) N,M (x, y)] N M χn m[ (nh, l p lh ) N,M (nh, lh )]. n= N m= M Hene, we hve (5.52) R N,M (x, y) N,M (x, y) therefore + N M n= N m= M χ l p n m[ (nh, lh ) N,M (nh, lh )], (5.54) R N,M < (x, y) N,M (x, y) ( + Q). Sine (x, y) N,M (x, y) 0sN, M, then R n,m The produt Nystrom method. In this setion, we disuss the produt Nystrom method [4] by onsidering the integrl eqution (6.54) b d µ (x, y) λ p(x, u; y,v) k(x, u; y,v) (u,v)dvdu = f (x, y) where p nd k re respetively well behved nd bdly behved funtions of their rguments, nd f (x, y) is given funtion, while (x, y) is the unknown funtion. The formul (6.54) n be written in the form N M µ N,M (x i, y k ) λ w ijkl p(x i, u j ; y k,v l ) N,M (u j,v l ) (6.55) j=0 l=0 = f (x i, y k ), where x i = u i = +ih, nd y k = v k = +kh, i = 0,, 2,..., N with h = b N, Neven, k = 0,, 2,..., M with h = d M, Meven,

12 26 M. M. EL-BORAI - M. A. ABDOU - M. BASSEEM nd the pproximte numeril solution N,M stisfy (6.56) (x, y) N,M (x, y) 0, s N, M. Here, the estimte error R N,M n be defined from the following N M (x, y) N,M (x, y) = w ijkl p(x i, u j ; y k,v l ) (6.57) (6.58) R N,M = b d N j=0 j=0 l=0 [ (u j,v l ) N,M (u j,v l )] + R N,M, k(x, u; y,v) (u,v)dvdu M w ijkl p(x i, u j ; y k,v l ) (u j,v l ). l=0 Therefore, in the light of orollry (5.), we n prove R N,M 0 s N, M. The produt Nystrom method is sid to be onvergent of order r +r 2 in the domin [, b] [, d], if nd only if for lrge N, M, there exist onstnt D > 0 independent of N, M suh tht (6.59) (x, y) N,M (x, y) DN r M r 2 The weights funtions w ijkl re onstruted by insisting tht the rule in (6.55) be ext when p(x i, u; y k,v) (u,v) is polynomil of degree r r 2, sy. Aording to the produt Nystrom method, we pproximte the integrl term in (6.54), when x = x i, y = y k, by produt integrtion form suh s Simpson rule, therefore we write (6.60) = N 2 2 j=0 b d M 2 2 l=0 p(x i, u; y k,v) k(x i, u; y k,v) (u,v)dvdu u2 j+2 v2l+2 u 2 j v 2l p(x i, u; y k,v) k(x i, u; y k,v) (u,v)dvdu.

13 AN ANALYSIS OF TWO DIMENSIONAL INTEGRAL EQUATIONS, Now, if we pproximte the nonsingulr prt of the integrnd over eh intervl [y 2 j, y 2 j+2 ] by the seond degree Lgrnge interpoltion polynomil whih interpoltes it t the points y 2 j, y 2 j+, y 2 j+2, we obtin (6.6) where, b d = p(u i, u; v k,v) k(u i, u; v k,v) (u,v)dvdu N j=0 M w ijkl p(u i, u j ; v k,v l ) (u j,v l ), l=0 w i,k,0,0 = β 2 (i, k,, ), w i,k,2 j+,0 = 2β 3 (i, k, j +, ), w i,k,2 j,0 = β (i, k, j, ) + β 2 (i, k, j +, ), w i,k,n,0 = β (i, k, N/2, ), w i,k,0,2l+ = 2γ 2 (i, k,, l + ), w i,k,2 j+,2l+ = 4γ 3 (i, k, j +, l + ), w i,k,2 j,2l+ = γ (i, k, j, l + ) + γ 2 (i, k, j +, l + ), (6.62) w i,k,n,2l+ = γ (i, k, N/2, l + ), w i,k,0,2l = α 2 (i, k,, l) + β 2 (i, k,, l + ), w i,k,2 j+,2l = 2[α 3 (i, k, j +, l) + β 3 (i, k, j +, l + )], w i,k,2 j,2l = α (i, k, j, l) + β 2 (i, k, j +, l + ), w i,k,n,2l = α (i, k, N/2, l) + β (i, k, N/2, l + ), w i,k,0,m = α 2 (i, k,, M/2), w i,k,2 j+,m = 2α 3 (i, k, j +, M/2), w i,k,2 j,m = α (i, k, j, M/2) + α 2 (i, k, j +, M/2), w i,k,n,m = α (i, k, N/2, M/2),

14 28 M. M. EL-BORAI - M. A. ABDOU - M. BASSEEM suh tht α (i, k, j, l) = v2 l u2 j v 2l 2 4h 2 i, u; v k,v)(u u 2 j 2 ) h 2 u 2 j 2 k(u (u u 2 j )(v v 2l 2 )(v v 2l )dudv, β (i, k, j, l) = v2 l u2 j v 2l 2 i, u; v k,v)(u u 2 j 2 ) 4h 2 h 2 u 2 j 2 k(u (u u 2 j )(v v 2l )(v v 2l )dudv, γ (i, k, j, l) = v2 l u2 j v 2l 2 i, u; v k,v)(u u 2 j 2 ) 4h 2 h 2 u 2 j 2 k(u (u u 2 j )(v v 2l 2 )(v v 2l )dudv, α 2 (i, k, j, l) = v2 l u2 j v 2l 2 4h 2 i, u; v k,v)(u u 2 j ) h 2 u 2 j 2 k(u (u u 2 j )(v v 2l 2 )(v v 2l )dudv, (6.63) β 2 (i, k, j, l) = v2 l u2 j v 2l 2 4h 2 i, u; v k,v)(u u 2 j ) h 2 u 2 j 2 k(u (u u 2 j )(v v 2l )(v v 2l )dudv, γ 2 (i, k, j, l) = v2 l u2 j v 2l 2 4h 2 i, u; v k,v)(u u 2 j ) h 2 u 2 j 2 k(u (u u 2 j )(v v 2l 2 )(v v 2l )dudv, α 3 (i, k, j, l) = v2 l u2 j v 2l 2 i, u; v k,v)(u u 2 j 2 ) 4h 2 h 2 u 2 j 2 k(u (u u 2 j )(v v 2l 2 )(v v 2l )dudv, β 3 (i, k, j, l) = v2 l u2 j v 2l 2 i, u; v k,v)(u u 2 j 2 ) 4h 2 h 2 u 2 j 2 k(u (u u 2 j )(v v 2l )(v v 2l )dudv, γ 3 (i, k, j, l) = v2 l u2 j v 2l 2 4h 2 i, u; v k,v)(u u 2 j 2 ) h 2 u 2 j 2 k(u (u u 2 j )(v v 2l 2 )(v v 2l )dudv.

15 AN ANALYSIS OF TWO DIMENSIONAL INTEGRAL EQUATIONS, Therefore, the integrl eqution (6.54) is redued to the following system of liner lgebri equtions N M µ (6.64) N,M (x i, y k ) λ w ijkl p(x i, u j ; y k,v l ) N,M (u j,v l ) j=0 l=0 = f (x i, y k ), whih n be written in mtrix form. By following the sme wy of Toeplitz mtrix, the existene nd uniqueness solution of the liner lgebri system (6.64) n be proved under the following ondition (6.65) λ < µ P, P > (w ijkl p(x i, u j ; y k,v l )) 2 2. i=0 k=0 j=0 l=0 7. Numeril results. In this setion, we pply the Toeplitz method nd Nystrom method, for different ses. The error, in eh se, is omputed. Exmple : (Logrithmi kernels). Consider the two dimensionl Fredholm integrl eqution (7.66) µ (x, y) λ ln x u ln y v (u,v)dvdu = f (x, y), where the ext solution is (x, y) = 2x 2 y 2 + xy, µ =, λ = 0.0, nd f (x, y) is given by f (x, y) = µ(2x 2 y 2 + xy) 2λ 9 [( x 3 )ln x + ( + x 3 )ln + x 2x ] (7.67) [( y 3 )ln y +( + y 3 )ln + y 2y ] λ 4 [( x 2 )(ln x ln + x ) 2x] [( y 2 )(ln y ln + y ) 2y].

16 30 M. M. EL-BORAI - M. A. ABDOU - M. BASSEEM Disussion (i) For N = M : In Tbles - 3, the numeril solution T nd its error R T for Toeplitz mtrix method, in Eq.(4.28), re obtined for N = M =, 2 nd 3. Also, we lulte N nd evlute R N for the sme orresponding points when N = M = 2, 4 nd 6, in Eq. (6.64). We find tht the error is deresing in the two methods for inresing N = M, see Figures -3. Tble x y φ φ T R T φ N R N R N R T Tble 2 x y φ φ T R T φ N R N R N R T

17 AN ANALYSIS OF TWO DIMENSIONAL INTEGRAL EQUATIONS,... 3 Tble 3 x y φ φ T R T φ N R N R N R T E E E E E E E E E

18 32 M. M. EL-BORAI - M. A. ABDOU - M. BASSEEM (ii) For N M : If N M, for exmple N = 2, M = with respet to Toeplitz mtrix method nd its orresponding vlues of Nystrom method, the error is bigger thn the previous results when N = M (shown by Tble 4 nd Figure 4). Tble 4 x y φ φ T R T φ N R N R N R T E E E Tble 5 x y φ φ T R T φ N R N R N R T E E E E E E E E E E

19 AN ANALYSIS OF TWO DIMENSIONAL INTEGRAL EQUATIONS, Exmple 2: (Crlemn kernels) Consider the two dimensionl Fredholm integrl eqution (7.68) µ (x, y) λ x u ν y v ν 2 (u,v)dvdu = f (x, y), where the ext solution is (x, y) = 2x 2 y 2 + xy nd f (x, y) is given by [ f (x, y) = µ(2x 2 y 2 + xy) 2λ[ ( x ν + x ν ) ν 2 ( ν )(2 ν ) ( x 2 ν + + x 2 ν ) 2 + ( ν )(2 ν )(3 ν ) ( x 3 ν + x 3 ν )] ν 2 ( y ν 2 +y ν 2 ) 2 ( ν 2 )(2 ν 2 ) ( y 2 ν 2 + +y 2 ν 2 ) 2 + ( ν 2 )(2 ν 2 )(3 ν 2 ) ( y 3 ν 2 + y 3 ν 2 )] λ[ ( x ν + + x ν ) ν ( ν )(2 ν ) ( x 2 ν +x 2 ν )][ ν 2 ( y ν 2 + +y ν 2 ) 2 ( ν 2 )(2 ν 2 ) ( y 2 ν y 2 ν 2 )]. Disussion (i) For N = M : Let µ =, λ = 0.0,ν = 0.05,ν 2 = 0.04, then the pproximte solution T nd the error E T of the integrl eqution (7.68), using Toeplitz mtrix method by tking N = M =, 2 nd 3 in Eq.(4.28), is displyed by Tble 4, 5 nd 6 respetively. Also, it displys the vlues of the pproximte solution N nd the error E N t the sme points for the sme integrl eqution but by using the produt Nystrom method with N = M = 2, 4, nd 6 in Eq.(6.64). The errors of Toeplitz mtrix method nd Nystrom method re deresing for inresing M nd N, see Figures 5-7.

20 34 M. M. EL-BORAI - M. A. ABDOU - M. BASSEEM Figure Figure 2 Figure 3 Figure 4

21 AN ANALYSIS OF TWO DIMENSIONAL INTEGRAL EQUATIONS, Figure 5 Figure 6 Figure 7 Figure 8

22 36 M. M. EL-BORAI - M. A. ABDOU - M. BASSEEM Tble 6 x y φ φ T R T φ N R N R N R T Tble 7 x y φ φ T R T φ N R N R N R T E E E E E E E E E E E

23 AN ANALYSIS OF TWO DIMENSIONAL INTEGRAL EQUATIONS, segue: Tble 7 x y φ φ T R T φ N R N R N R T E E E E E E E E E E E E

24 38 M. M. EL-BORAI - M. A. ABDOU - M. BASSEEM (ii) For N M : When N M, for exmple N = 2, M = with respet to Toeplitz mtrix method nd its orresponding vlues, N = 4, M = 2, of Nystrom method, the error is bigger thn the previous results in whih N = M (see Tble 8 nd Figure 8). Tble 8 x y φ φ T R T φ N R N R N R T Conlusion: - The error funtion of Toeplitz mtrix method is smller thn the orresponding error of Nystrom method in the most ses of logrithmi kernel form exept for the first vlues of N, M, see Tbles In Crlemn kernels form (ν = 0.05, ν 2 = 0.04), Nystrom method is better thn Toeplitz mtrix method. 3 - In the following Tble, we tke different vlues of λ = {0., 0.0, 0.00}, where N = M = 2 (with respet to Toeplitz mtrix method). The error, in both methods, is deresing whenever λ dereses. 4 - In Crlemn kernel form, when ν or ν 2 pprohes, for exmple ν 2 = 0.04 nd ν ={0.05, 0.5, 0.8}, the error is inresing in two methods (see Tble 0).

25 AN ANALYSIS OF TWO DIMENSIONAL INTEGRAL EQUATIONS, Tble 9 Tble 0 λ mx R T mx R N mx R T mx R N λ mx R T mx R N E Aknowledgment We thnks the referee for his effetive omments. REFERENCES [] N. I. Muskhelishvili, Singulr Integrl Equtions, Noordhoff, Groningen, The Netherlnds, 953. [2] E. Venturino, The Glerkin method for singulr integrl equtions revisited, J. Comp. Appl. Mth. 40 (992) [3] Youngmok Jeon, A qudrture method for the Cuhy singulr integrl equtions, J. Integrl equtions nd pplitions, V. 7 N0o. 2 (995) [4] M. A. Abdou, K. I. Mhmed, A. S. Isml, Toeplitz mtrix nd produt Nystrom methods for solving the singulr integrl eqution, Le Mtemtihe, Vol. LVII (2002) - Fs. I, pp [5] L. M. Delves, Mohmed J. L., Computtionl Methods for Integrl Equtions, New York. London, 985. [6] E. K. Atkinson, A Survey of Numeril Method for the Solution of Fredholm Integrl Eqution of the Seond Kind, Phildelphi, 976. [7] M. A. Golberg, ed., Numeril Solution of Integrl Equtions, Nelsson, New York, 990. M. M. El-Bori M. A. Abdou Alexndri University Alexndri University Fulty of Siene Fulty of Edution Deprtment of Mthemtis Deprtment of Mthemtis Egypt Egypt E-mil: m m elbori@ yhoo.om E-mil: bdell 77@ yhoo.om M. Bsseem Alexndri Thrwt 9 Mohmmed Eqbl St. Egypt E-mil: bsseem777@ yhoo.om

MA10207B: ANALYSIS SECOND SEMESTER OUTLINE NOTES

MA10207B: ANALYSIS SECOND SEMESTER OUTLINE NOTES MA10207B: ANALYSIS SECOND SEMESTER OUTLINE NOTES CHARLIE COLLIER UNIVERSITY OF BATH These notes hve been typeset by Chrlie Collier nd re bsed on the leture notes by Adrin Hill nd Thoms Cottrell. These

More information

Part 4. Integration (with Proofs)

Part 4. Integration (with Proofs) Prt 4. Integrtion (with Proofs) 4.1 Definition Definition A prtition P of [, b] is finite set of points {x 0, x 1,..., x n } with = x 0 < x 1

More information

Solutions to Assignment 1

Solutions to Assignment 1 MTHE 237 Fll 2015 Solutions to Assignment 1 Problem 1 Find the order of the differentil eqution: t d3 y dt 3 +t2 y = os(t. Is the differentil eqution liner? Is the eqution homogeneous? b Repet the bove

More information

Tutorial Worksheet. 1. Find all solutions to the linear system by following the given steps. x + 2y + 3z = 2 2x + 3y + z = 4.

Tutorial Worksheet. 1. Find all solutions to the linear system by following the given steps. x + 2y + 3z = 2 2x + 3y + z = 4. Mth 5 Tutoril Week 1 - Jnury 1 1 Nme Setion Tutoril Worksheet 1. Find ll solutions to the liner system by following the given steps x + y + z = x + y + z = 4. y + z = Step 1. Write down the rgumented mtrix

More information

Hyers-Ulam stability of Pielou logistic difference equation

Hyers-Ulam stability of Pielou logistic difference equation vilble online t wwwisr-publitionsom/jns J Nonliner Si ppl, 0 (207, 35 322 Reserh rtile Journl Homepge: wwwtjnsom - wwwisr-publitionsom/jns Hyers-Ulm stbility of Pielou logisti differene eqution Soon-Mo

More information

Final Exam Review. [Top Bottom]dx =

Final Exam Review. [Top Bottom]dx = Finl Exm Review Are Between Curves See 7.1 exmples 1, 2, 4, 5 nd exerises 1-33 (odd) The re of the region bounded by the urves y = f(x), y = g(x), nd the lines x = nd x = b, where f nd g re ontinuous nd

More information

arxiv: v1 [math.ca] 21 Aug 2018

arxiv: v1 [math.ca] 21 Aug 2018 rxiv:1808.07159v1 [mth.ca] 1 Aug 018 Clulus on Dul Rel Numbers Keqin Liu Deprtment of Mthemtis The University of British Columbi Vnouver, BC Cnd, V6T 1Z Augest, 018 Abstrt We present the bsi theory of

More information

Co-ordinated s-convex Function in the First Sense with Some Hadamard-Type Inequalities

Co-ordinated s-convex Function in the First Sense with Some Hadamard-Type Inequalities Int. J. Contemp. Mth. Sienes, Vol. 3, 008, no. 3, 557-567 Co-ordinted s-convex Funtion in the First Sense with Some Hdmrd-Type Inequlities Mohmmd Alomri nd Mslin Drus Shool o Mthemtil Sienes Fulty o Siene

More information

More Properties of the Riemann Integral

More Properties of the Riemann Integral More Properties of the Riemnn Integrl Jmes K. Peterson Deprtment of Biologil Sienes nd Deprtment of Mthemtil Sienes Clemson University Februry 15, 2018 Outline More Riemnn Integrl Properties The Fundmentl

More information

INTEGRATION. 1 Integrals of Complex Valued functions of a REAL variable

INTEGRATION. 1 Integrals of Complex Valued functions of a REAL variable INTEGRATION NOTE: These notes re supposed to supplement Chpter 4 of the online textbook. 1 Integrls of Complex Vlued funtions of REAL vrible If I is n intervl in R (for exmple I = [, b] or I = (, b)) nd

More information

Lecture 1 - Introduction and Basic Facts about PDEs

Lecture 1 - Introduction and Basic Facts about PDEs * 18.15 - Introdution to PDEs, Fll 004 Prof. Gigliol Stffilni Leture 1 - Introdution nd Bsi Fts bout PDEs The Content of the Course Definition of Prtil Differentil Eqution (PDE) Liner PDEs VVVVVVVVVVVVVVVVVVVV

More information

RIEMANN INTEGRATION. Throughout our discussion of Riemann integration. B = B [a; b] = B ([a; b] ; R)

RIEMANN INTEGRATION. Throughout our discussion of Riemann integration. B = B [a; b] = B ([a; b] ; R) RIEMANN INTEGRATION Throughout our disussion of Riemnn integrtion B = B [; b] = B ([; b] ; R) is the set of ll bounded rel-vlued funtons on lose, bounded, nondegenerte intervl [; b] : 1. DEF. A nite set

More information

Learning Objectives of Module 2 (Algebra and Calculus) Notes:

Learning Objectives of Module 2 (Algebra and Calculus) Notes: 67 Lerning Ojetives of Module (Alger nd Clulus) Notes:. Lerning units re grouped under three res ( Foundtion Knowledge, Alger nd Clulus ) nd Further Lerning Unit.. Relted lerning ojetives re grouped under

More information

The study of dual integral equations with generalized Legendre functions

The study of dual integral equations with generalized Legendre functions J. Mth. Anl. Appl. 34 (5) 75 733 www.elsevier.om/lote/jm The study of dul integrl equtions with generlized Legendre funtions B.M. Singh, J. Rokne,R.S.Dhliwl Deprtment of Mthemtis, The University of Clgry,

More information

T b a(f) [f ] +. P b a(f) = Conclude that if f is in AC then it is the difference of two monotone absolutely continuous functions.

T b a(f) [f ] +. P b a(f) = Conclude that if f is in AC then it is the difference of two monotone absolutely continuous functions. Rel Vribles, Fll 2014 Problem set 5 Solution suggestions Exerise 1. Let f be bsolutely ontinuous on [, b] Show tht nd T b (f) P b (f) f (x) dx [f ] +. Conlude tht if f is in AC then it is the differene

More information

ON THE INEQUALITY OF THE DIFFERENCE OF TWO INTEGRAL MEANS AND APPLICATIONS FOR PDFs

ON THE INEQUALITY OF THE DIFFERENCE OF TWO INTEGRAL MEANS AND APPLICATIONS FOR PDFs ON THE INEQUALITY OF THE DIFFERENCE OF TWO INTEGRAL MEANS AND APPLICATIONS FOR PDFs A.I. KECHRINIOTIS AND N.D. ASSIMAKIS Deprtment of Eletronis Tehnologil Edutionl Institute of Lmi, Greee EMil: {kehrin,

More information

(a) A partition P of [a, b] is a finite subset of [a, b] containing a and b. If Q is another partition and P Q, then Q is a refinement of P.

(a) A partition P of [a, b] is a finite subset of [a, b] containing a and b. If Q is another partition and P Q, then Q is a refinement of P. Chpter 7: The Riemnn Integrl When the derivtive is introdued, it is not hrd to see tht the it of the differene quotient should be equl to the slope of the tngent line, or when the horizontl xis is time

More information

University of Sioux Falls. MAT204/205 Calculus I/II

University of Sioux Falls. MAT204/205 Calculus I/II University of Sioux Flls MAT204/205 Clulus I/II Conepts ddressed: Clulus Textook: Thoms Clulus, 11 th ed., Weir, Hss, Giordno 1. Use stndrd differentition nd integrtion tehniques. Differentition tehniques

More information

The Riemann-Stieltjes Integral

The Riemann-Stieltjes Integral Chpter 6 The Riemnn-Stieltjes Integrl 6.1. Definition nd Eistene of the Integrl Definition 6.1. Let, b R nd < b. ( A prtition P of intervl [, b] is finite set of points P = { 0, 1,..., n } suh tht = 0

More information

Lecture 14: Quadrature

Lecture 14: Quadrature Lecture 14: Qudrture This lecture is concerned with the evlution of integrls fx)dx 1) over finite intervl [, b] The integrnd fx) is ssumed to be rel-vlues nd smooth The pproximtion of n integrl by numericl

More information

DIFFERENCE BETWEEN TWO RIEMANN-STIELTJES INTEGRAL MEANS

DIFFERENCE BETWEEN TWO RIEMANN-STIELTJES INTEGRAL MEANS Krgujev Journl of Mthemtis Volume 38() (204), Pges 35 49. DIFFERENCE BETWEEN TWO RIEMANN-STIELTJES INTEGRAL MEANS MOHAMMAD W. ALOMARI Abstrt. In this pper, severl bouns for the ifferene between two Riemn-

More information

Exam 2, Mathematics 4701, Section ETY6 6:05 pm 7:40 pm, March 31, 2016, IH-1105 Instructor: Attila Máté 1

Exam 2, Mathematics 4701, Section ETY6 6:05 pm 7:40 pm, March 31, 2016, IH-1105 Instructor: Attila Máté 1 Exm, Mthemtics 471, Section ETY6 6:5 pm 7:4 pm, Mrch 1, 16, IH-115 Instructor: Attil Máté 1 17 copies 1. ) Stte the usul sufficient condition for the fixed-point itertion to converge when solving the eqution

More information

The Riemann and the Generalised Riemann Integral

The Riemann and the Generalised Riemann Integral The Riemnn nd the Generlised Riemnn Integrl Clvin 17 July 14 Contents 1 The Riemnn Integrl 1.1 Riemnn Integrl............................................ 1. Properties o Riemnn Integrble Funtions.............................

More information

Numerical Integration

Numerical Integration Chpter 5 Numericl Integrtion Numericl integrtion is the study of how the numericl vlue of n integrl cn be found. Methods of function pproximtion discussed in Chpter??, i.e., function pproximtion vi the

More information

SECTION A STUDENT MATERIAL. Part 1. What and Why.?

SECTION A STUDENT MATERIAL. Part 1. What and Why.? SECTION A STUDENT MATERIAL Prt Wht nd Wh.? Student Mteril Prt Prolem n > 0 n > 0 Is the onverse true? Prolem If n is even then n is even. If n is even then n is even. Wht nd Wh? Eploring Pure Mths Are

More information

AP Calculus BC Chapter 8: Integration Techniques, L Hopital s Rule and Improper Integrals

AP Calculus BC Chapter 8: Integration Techniques, L Hopital s Rule and Improper Integrals AP Clulus BC Chpter 8: Integrtion Tehniques, L Hopitl s Rule nd Improper Integrls 8. Bsi Integrtion Rules In this setion we will review vrious integrtion strtegies. Strtegies: I. Seprte the integrnd into

More information

Introduction to Olympiad Inequalities

Introduction to Olympiad Inequalities Introdution to Olympid Inequlities Edutionl Studies Progrm HSSP Msshusetts Institute of Tehnology Snj Simonovikj Spring 207 Contents Wrm up nd Am-Gm inequlity 2. Elementry inequlities......................

More information

The Regulated and Riemann Integrals

The Regulated and Riemann Integrals Chpter 1 The Regulted nd Riemnn Integrls 1.1 Introduction We will consider severl different pproches to defining the definite integrl f(x) dx of function f(x). These definitions will ll ssign the sme vlue

More information

Theoretical foundations of Gaussian quadrature

Theoretical foundations of Gaussian quadrature Theoreticl foundtions of Gussin qudrture 1 Inner product vector spce Definition 1. A vector spce (or liner spce) is set V = {u, v, w,...} in which the following two opertions re defined: (A) Addition of

More information

The Riemann Integral

The Riemann Integral Deprtment of Mthemtics King Sud University 2017-2018 Tble of contents 1 Anti-derivtive Function nd Indefinite Integrls 2 3 4 5 Indefinite Integrls & Anti-derivtive Function Definition Let f : I R be function

More information

CHAPTER 4: DETERMINANTS

CHAPTER 4: DETERMINANTS CHAPTER 4: DETERMINANTS MARKS WEIGHTAGE 0 mrks NCERT Importnt Questions & Answers 6. If, then find the vlue of. 8 8 6 6 Given tht 8 8 6 On epnding both determinnts, we get 8 = 6 6 8 36 = 36 36 36 = 0 =

More information

Electromagnetism Notes, NYU Spring 2018

Electromagnetism Notes, NYU Spring 2018 Eletromgnetism Notes, NYU Spring 208 April 2, 208 Ation formultion of EM. Free field desription Let us first onsider the free EM field, i.e. in the bsene of ny hrges or urrents. To tret this s mehnil system

More information

Physics 116C Solution of inhomogeneous ordinary differential equations using Green s functions

Physics 116C Solution of inhomogeneous ordinary differential equations using Green s functions Physics 6C Solution of inhomogeneous ordinry differentil equtions using Green s functions Peter Young November 5, 29 Homogeneous Equtions We hve studied, especilly in long HW problem, second order liner

More information

MATH 409 Advanced Calculus I Lecture 22: Improper Riemann integrals.

MATH 409 Advanced Calculus I Lecture 22: Improper Riemann integrals. MATH 409 Advned Clulus I Leture 22: Improper Riemnn integrls. Improper Riemnn integrl If funtion f : [,b] R is integrble on [,b], then the funtion F(x) = x f(t)dt is well defined nd ontinuous on [,b].

More information

MATH Final Review

MATH Final Review MATH 1591 - Finl Review November 20, 2005 1 Evlution of Limits 1. the ε δ definition of limit. 2. properties of limits. 3. how to use the diret substitution to find limit. 4. how to use the dividing out

More information

Line Integrals and Entire Functions

Line Integrals and Entire Functions Line Integrls nd Entire Funtions Defining n Integrl for omplex Vlued Funtions In the following setions, our min gol is to show tht every entire funtion n be represented s n everywhere onvergent power series

More information

TOPIC: LINEAR ALGEBRA MATRICES

TOPIC: LINEAR ALGEBRA MATRICES Interntionl Blurete LECTUE NOTES for FUTHE MATHEMATICS Dr TOPIC: LINEA ALGEBA MATICES. DEFINITION OF A MATIX MATIX OPEATIONS.. THE DETEMINANT deta THE INVESE A -... SYSTEMS OF LINEA EQUATIONS. 8. THE AUGMENTED

More information

ODE: Existence and Uniqueness of a Solution

ODE: Existence and Uniqueness of a Solution Mth 22 Fll 213 Jerry Kzdn ODE: Existence nd Uniqueness of Solution The Fundmentl Theorem of Clculus tells us how to solve the ordinry differentil eqution (ODE) du = f(t) dt with initil condition u() =

More information

Numerical Analysis: Trapezoidal and Simpson s Rule

Numerical Analysis: Trapezoidal and Simpson s Rule nd Simpson s Mthemticl question we re interested in numericlly nswering How to we evlute I = f (x) dx? Clculus tells us tht if F(x) is the ntiderivtive of function f (x) on the intervl [, b], then I =

More information

Hermite-Hadamard inequality for geometrically quasiconvex functions on co-ordinates

Hermite-Hadamard inequality for geometrically quasiconvex functions on co-ordinates Int. J. Nonliner Anl. Appl. 8 27 No. 47-6 ISSN: 28-6822 eletroni http://dx.doi.org/.2275/ijn.26.483 Hermite-Hdmrd ineulity for geometrilly usionvex funtions on o-ordintes Ali Brni Ftemeh Mlmir Deprtment

More information

Lecture 19: Continuous Least Squares Approximation

Lecture 19: Continuous Least Squares Approximation Lecture 19: Continuous Lest Squres Approximtion 33 Continuous lest squres pproximtion We begn 31 with the problem of pproximting some f C[, b] with polynomil p P n t the discrete points x, x 1,, x m for

More information

16z z q. q( B) Max{2 z z z z B} r z r z r z r z B. John Riley 19 October Econ 401A: Microeconomic Theory. Homework 2 Answers

16z z q. q( B) Max{2 z z z z B} r z r z r z r z B. John Riley 19 October Econ 401A: Microeconomic Theory. Homework 2 Answers John Riley 9 Otober 6 Eon 4A: Miroeonomi Theory Homework Answers Constnt returns to sle prodution funtion () If (,, q) S then 6 q () 4 We need to show tht (,, q) S 6( ) ( ) ( q) q [ q ] 4 4 4 4 4 4 Appeling

More information

QUADRATIC EQUATION. Contents

QUADRATIC EQUATION. Contents QUADRATIC EQUATION Contents Topi Pge No. Theory 0-04 Exerise - 05-09 Exerise - 09-3 Exerise - 3 4-5 Exerise - 4 6 Answer Key 7-8 Syllus Qudrti equtions with rel oeffiients, reltions etween roots nd oeffiients,

More information

Advanced Calculus: MATH 410 Notes on Integrals and Integrability Professor David Levermore 17 October 2004

Advanced Calculus: MATH 410 Notes on Integrals and Integrability Professor David Levermore 17 October 2004 Advnced Clculus: MATH 410 Notes on Integrls nd Integrbility Professor Dvid Levermore 17 October 2004 1. Definite Integrls In this section we revisit the definite integrl tht you were introduced to when

More information

MAT 403 NOTES 4. f + f =

MAT 403 NOTES 4. f + f = MAT 403 NOTES 4 1. Fundmentl Theorem o Clulus We will proo more generl version o the FTC thn the textook. But just like the textook, we strt with the ollowing proposition. Let R[, ] e the set o Riemnn

More information

(4.1) D r v(t) ω(t, v(t))

(4.1) D r v(t) ω(t, v(t)) 1.4. Differentil inequlities. Let D r denote the right hnd derivtive of function. If ω(t, u) is sclr function of the sclrs t, u in some open connected set Ω, we sy tht function v(t), t < b, is solution

More information

Linear Algebra Introduction

Linear Algebra Introduction Introdution Wht is Liner Alger out? Liner Alger is rnh of mthemtis whih emerged yers k nd ws one of the pioneer rnhes of mthemtis Though, initilly it strted with solving of the simple liner eqution x +

More information

1. Gauss-Jacobi quadrature and Legendre polynomials. p(t)w(t)dt, p {p(x 0 ),...p(x n )} p(t)w(t)dt = w k p(x k ),

1. Gauss-Jacobi quadrature and Legendre polynomials. p(t)w(t)dt, p {p(x 0 ),...p(x n )} p(t)w(t)dt = w k p(x k ), 1. Guss-Jcobi qudrture nd Legendre polynomils Simpson s rule for evluting n integrl f(t)dt gives the correct nswer with error of bout O(n 4 ) (with constnt tht depends on f, in prticulr, it depends on

More information

INTRODUCTION TO INTEGRATION

INTRODUCTION TO INTEGRATION INTRODUCTION TO INTEGRATION 5.1 Ares nd Distnces Assume f(x) 0 on the intervl [, b]. Let A be the re under the grph of f(x). b We will obtin n pproximtion of A in the following three steps. STEP 1: Divide

More information

Section 4.4. Green s Theorem

Section 4.4. Green s Theorem The Clulus of Funtions of Severl Vriles Setion 4.4 Green s Theorem Green s theorem is n exmple from fmily of theorems whih onnet line integrls (nd their higher-dimensionl nlogues) with the definite integrls

More information

SOLUTIONS FOR ANALYSIS QUALIFYING EXAM, FALL (1 + µ(f n )) f(x) =. But we don t need the exact bound.) Set

SOLUTIONS FOR ANALYSIS QUALIFYING EXAM, FALL (1 + µ(f n )) f(x) =. But we don t need the exact bound.) Set SOLUTIONS FOR ANALYSIS QUALIFYING EXAM, FALL 28 Nottion: N {, 2, 3,...}. (Tht is, N.. Let (X, M be mesurble spce with σ-finite positive mesure µ. Prove tht there is finite positive mesure ν on (X, M such

More information

f (x)dx = f(b) f(a). a b f (x)dx is the limit of sums

f (x)dx = f(b) f(a). a b f (x)dx is the limit of sums Green s Theorem If f is funtion of one vrible x with derivtive f x) or df dx to the Fundmentl Theorem of lulus, nd [, b] is given intervl then, ording This is not trivil result, onsidering tht b b f x)dx

More information

Lecture Summaries for Multivariable Integral Calculus M52B

Lecture Summaries for Multivariable Integral Calculus M52B These leture summries my lso be viewed online by liking the L ion t the top right of ny leture sreen. Leture Summries for Multivrible Integrl Clulus M52B Chpter nd setion numbers refer to the 6th edition.

More information

MATH34032: Green s Functions, Integral Equations and the Calculus of Variations 1

MATH34032: Green s Functions, Integral Equations and the Calculus of Variations 1 MATH34032: Green s Functions, Integrl Equtions nd the Clculus of Vritions 1 Section 1 Function spces nd opertors Here we gives some brief detils nd definitions, prticulrly relting to opertors. For further

More information

1 PYTHAGORAS THEOREM 1. Given a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.

1 PYTHAGORAS THEOREM 1. Given a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides. 1 PYTHAGORAS THEOREM 1 1 Pythgors Theorem In this setion we will present geometri proof of the fmous theorem of Pythgors. Given right ngled tringle, the squre of the hypotenuse is equl to the sum of the

More information

6.1 Definition of the Riemann Integral

6.1 Definition of the Riemann Integral 6 The Riemnn Integrl 6. Deinition o the Riemnn Integrl Deinition 6.. Given n intervl [, b] with < b, prtition P o [, b] is inite set o points {x, x,..., x n } [, b], lled grid points, suh tht x =, x n

More information

Chapter Gauss Quadrature Rule of Integration

Chapter Gauss Quadrature Rule of Integration Chpter 7. Guss Qudrture Rule o Integrtion Ater reding this hpter, you should e le to:. derive the Guss qudrture method or integrtion nd e le to use it to solve prolems, nd. use Guss qudrture method to

More information

WHEN IS A FUNCTION NOT FLAT? 1. Introduction. {e 1 0, x = 0. f(x) =

WHEN IS A FUNCTION NOT FLAT? 1. Introduction. {e 1 0, x = 0. f(x) = WHEN IS A FUNCTION NOT FLAT? YIFEI PAN AND MEI WANG Abstrct. In this pper we prove unique continution property for vector vlued functions of one vrible stisfying certin differentil inequlity. Key words:

More information

Section 3.6. Definite Integrals

Section 3.6. Definite Integrals The Clulus of Funtions of Severl Vribles Setion.6 efinite Integrls We will first define the definite integrl for funtion f : R R nd lter indite how the definition my be extended to funtions of three or

More information

Dong-Myung Lee, Jeong-Gon Lee, and Ming-Gen Cui. 1. introduction

Dong-Myung Lee, Jeong-Gon Lee, and Ming-Gen Cui. 1. introduction J. Kore So. Mth. Edu. Ser. B: Pure Appl. Mth. ISSN 16-0657 Volume 11, Number My 004), Pges 133 138 REPRESENTATION OF SOLUTIONS OF FREDHOLM EQUATIONS IN W Ω) OF REPRODUCING KERNELS Dong-Myung Lee, Jeong-Gon

More information

On the Co-Ordinated Convex Functions

On the Co-Ordinated Convex Functions Appl. Mth. In. Si. 8, No. 3, 085-0 0 085 Applied Mthemtis & Inormtion Sienes An Interntionl Journl http://.doi.org/0.785/mis/08038 On the Co-Ordinted Convex Funtions M. Emin Özdemir, Çetin Yıldız, nd Ahmet

More information

NUMERICAL INTEGRATION. The inverse process to differentiation in calculus is integration. Mathematically, integration is represented by.

NUMERICAL INTEGRATION. The inverse process to differentiation in calculus is integration. Mathematically, integration is represented by. NUMERICAL INTEGRATION 1 Introduction The inverse process to differentition in clculus is integrtion. Mthemticlly, integrtion is represented by f(x) dx which stnds for the integrl of the function f(x) with

More information

Type 2: Improper Integrals with Infinite Discontinuities

Type 2: Improper Integrals with Infinite Discontinuities mth imroer integrls: tye 6 Tye : Imroer Integrls with Infinite Disontinuities A seond wy tht funtion n fil to be integrble in the ordinry sense is tht it my hve n infinite disontinuity (vertil symtote)

More information

where the box contains a finite number of gates from the given collection. Examples of gates that are commonly used are the following: a b

where the box contains a finite number of gates from the given collection. Examples of gates that are commonly used are the following: a b CS 294-2 9/11/04 Quntum Ciruit Model, Solovy-Kitev Theorem, BQP Fll 2004 Leture 4 1 Quntum Ciruit Model 1.1 Clssil Ciruits - Universl Gte Sets A lssil iruit implements multi-output oolen funtion f : {0,1}

More information

f (z) dz = 0 f(z) dz = 2πj f(z 0 ) Generalized Cauchy Integral Formula (For pole with any order) (n 1)! f (n 1) (z 0 ) f (n) (z 0 ) M n!

f (z) dz = 0 f(z) dz = 2πj f(z 0 ) Generalized Cauchy Integral Formula (For pole with any order) (n 1)! f (n 1) (z 0 ) f (n) (z 0 ) M n! uhy s Theorems I Ang M.S. Otober 26, 212 Augustin-Louis uhy 1789 1857 Referenes Murry R. Spiegel omplex V ribles with introdution to onf orml mpping nd its pplitions Dennis G. Zill, P. D. Shnhn A F irst

More information

Discrete Structures Lecture 11

Discrete Structures Lecture 11 Introdution Good morning. In this setion we study funtions. A funtion is mpping from one set to nother set or, perhps, from one set to itself. We study the properties of funtions. A mpping my not e funtion.

More information

A Mathematical Model for Unemployment-Taking an Action without Delay

A Mathematical Model for Unemployment-Taking an Action without Delay Advnes in Dynmil Systems nd Applitions. ISSN 973-53 Volume Number (7) pp. -8 Reserh Indi Publitions http://www.ripublition.om A Mthemtil Model for Unemployment-Tking n Ation without Dely Gulbnu Pthn Diretorte

More information

Euler, Ioachimescu and the trapezium rule. G.J.O. Jameson (Math. Gazette 96 (2012), )

Euler, Ioachimescu and the trapezium rule. G.J.O. Jameson (Math. Gazette 96 (2012), ) Euler, Iochimescu nd the trpezium rule G.J.O. Jmeson (Mth. Gzette 96 (0), 36 4) The following results were estblished in recent Gzette rticle [, Theorems, 3, 4]. Given > 0 nd 0 < s

More information

Solution 4. hence the Cauchy problem has a differentiable solution for all positive time y ą 0. b) Let hpsq ups, 0q, since hpsq is decreasing in r π

Solution 4. hence the Cauchy problem has a differentiable solution for all positive time y ą 0. b) Let hpsq ups, 0q, since hpsq is decreasing in r π Solution 4 1. ) Let hpsq ups, 0q, sine the initil ondition hpxq is differentile nd nonderesing, i.e. h 1 pxq ě 0, we hve the formul for the ritil time (see eqution (2.47) on p.4 in [PR]), y 1 h 1 ă 0 @x

More information

AN INTEGRAL INEQUALITY FOR CONVEX FUNCTIONS AND APPLICATIONS IN NUMERICAL INTEGRATION

AN INTEGRAL INEQUALITY FOR CONVEX FUNCTIONS AND APPLICATIONS IN NUMERICAL INTEGRATION Applied Mthemtics E-Notes, 5(005), 53-60 c ISSN 1607-510 Avilble free t mirror sites of http://www.mth.nthu.edu.tw/ men/ AN INTEGRAL INEQUALITY FOR CONVEX FUNCTIONS AND APPLICATIONS IN NUMERICAL INTEGRATION

More information

Integration Techniques

Integration Techniques Integrtion Techniques. Integrtion of Trigonometric Functions Exmple. Evlute cos x. Recll tht cos x = cos x. Hence, cos x Exmple. Evlute = ( + cos x) = (x + sin x) + C = x + 4 sin x + C. cos 3 x. Let u

More information

SOLUTIONS TO MATH38181 EXTREME VALUES EXAM

SOLUTIONS TO MATH38181 EXTREME VALUES EXAM SOLUTIONS TO MATH388 EXTREME VALUES EXAM Solutions to Question If there re norming onstnts n >, b n nd nondegenerte G suh tht the df of normlized version of M n onverges to G, i.e. ( ) Mn b n Pr x F n

More information

AN INEQUALITY OF OSTROWSKI TYPE AND ITS APPLICATIONS FOR SIMPSON S RULE AND SPECIAL MEANS. I. Fedotov and S. S. Dragomir

AN INEQUALITY OF OSTROWSKI TYPE AND ITS APPLICATIONS FOR SIMPSON S RULE AND SPECIAL MEANS. I. Fedotov and S. S. Dragomir RGMIA Reserch Report Collection, Vol., No., 999 http://sci.vu.edu.u/ rgmi AN INEQUALITY OF OSTROWSKI TYPE AND ITS APPLICATIONS FOR SIMPSON S RULE AND SPECIAL MEANS I. Fedotov nd S. S. Drgomir Astrct. An

More information

For a, b, c, d positive if a b and. ac bd. Reciprocal relations for a and b positive. If a > b then a ab > b. then

For a, b, c, d positive if a b and. ac bd. Reciprocal relations for a and b positive. If a > b then a ab > b. then Slrs-7.2-ADV-.7 Improper Definite Integrls 27.. D.dox Pge of Improper Definite Integrls Before we strt the min topi we present relevnt lger nd it review. See Appendix J for more lger review. Inequlities:

More information

Convex Sets and Functions

Convex Sets and Functions B Convex Sets nd Functions Definition B1 Let L, +, ) be rel liner spce nd let C be subset of L The set C is convex if, for ll x,y C nd ll [, 1], we hve 1 )x+y C In other words, every point on the line

More information

Math& 152 Section Integration by Parts

Math& 152 Section Integration by Parts Mth& 5 Section 7. - Integrtion by Prts Integrtion by prts is rule tht trnsforms the integrl of the product of two functions into other (idelly simpler) integrls. Recll from Clculus I tht given two differentible

More information

Can one hear the shape of a drum?

Can one hear the shape of a drum? Cn one her the shpe of drum? After M. K, C. Gordon, D. We, nd S. Wolpert Corentin Lén Università Degli Studi di Torino Diprtimento di Mtemti Giuseppe Peno UNITO Mthemtis Ph.D Seminrs Mondy 23 My 2016 Motivtion:

More information

Numerical Integration. 1 Introduction. 2 Midpoint Rule, Trapezoid Rule, Simpson Rule. AMSC/CMSC 460/466 T. von Petersdorff 1

Numerical Integration. 1 Introduction. 2 Midpoint Rule, Trapezoid Rule, Simpson Rule. AMSC/CMSC 460/466 T. von Petersdorff 1 AMSC/CMSC 46/466 T. von Petersdorff 1 umericl Integrtion 1 Introduction We wnt to pproximte the integrl I := f xdx where we re given, b nd the function f s subroutine. We evlute f t points x 1,...,x n

More information

Czechoslovak Mathematical Journal, 55 (130) (2005), , Abbotsford. 1. Introduction

Czechoslovak Mathematical Journal, 55 (130) (2005), , Abbotsford. 1. Introduction Czechoslovk Mthemticl Journl, 55 (130) (2005), 933 940 ESTIMATES OF THE REMAINDER IN TAYLOR S THEOREM USING THE HENSTOCK-KURZWEIL INTEGRAL, Abbotsford (Received Jnury 22, 2003) Abstrct. When rel-vlued

More information

Definite integral. Mathematics FRDIS MENDELU

Definite integral. Mathematics FRDIS MENDELU Definite integrl Mthemtics FRDIS MENDELU Simon Fišnrová Brno 1 Motivtion - re under curve Suppose, for simplicity, tht y = f(x) is nonnegtive nd continuous function defined on [, b]. Wht is the re of the

More information

Definite integral. Mathematics FRDIS MENDELU. Simona Fišnarová (Mendel University) Definite integral MENDELU 1 / 30

Definite integral. Mathematics FRDIS MENDELU. Simona Fišnarová (Mendel University) Definite integral MENDELU 1 / 30 Definite integrl Mthemtics FRDIS MENDELU Simon Fišnrová (Mendel University) Definite integrl MENDELU / Motivtion - re under curve Suppose, for simplicity, tht y = f(x) is nonnegtive nd continuous function

More information

AP Calculus AB Unit 4 Assessment

AP Calculus AB Unit 4 Assessment Clss: Dte: 0-04 AP Clulus AB Unit 4 Assessment Multiple Choie Identify the hoie tht best ompletes the sttement or nswers the question. A lultor my NOT be used on this prt of the exm. (6 minutes). The slope

More information

Math 32B Discussion Session Week 8 Notes February 28 and March 2, f(b) f(a) = f (t)dt (1)

Math 32B Discussion Session Week 8 Notes February 28 and March 2, f(b) f(a) = f (t)dt (1) Green s Theorem Mth 3B isussion Session Week 8 Notes Februry 8 nd Mrh, 7 Very shortly fter you lerned how to integrte single-vrible funtions, you lerned the Fundmentl Theorem of lulus the wy most integrtion

More information

f(x)dx . Show that there 1, 0 < x 1 does not exist a differentiable function g : [ 1, 1] R such that g (x) = f(x) for all

f(x)dx . Show that there 1, 0 < x 1 does not exist a differentiable function g : [ 1, 1] R such that g (x) = f(x) for all 3 Definite Integrl 3.1 Introduction In school one comes cross the definition of the integrl of rel vlued function defined on closed nd bounded intervl [, b] between the limits nd b, i.e., f(x)dx s the

More information

Inequalities of Olympiad Caliber. RSME Olympiad Committee BARCELONA TECH

Inequalities of Olympiad Caliber. RSME Olympiad Committee BARCELONA TECH Ineulities of Olymid Clier José Luis Díz-Brrero RSME Olymid Committee BARCELONA TECH José Luis Díz-Brrero RSME Olymi Committee UPC BARCELONA TECH jose.luis.diz@u.edu Bsi fts to rove ineulities Herefter,

More information

A REVIEW OF CALCULUS CONCEPTS FOR JDEP 384H. Thomas Shores Department of Mathematics University of Nebraska Spring 2007

A REVIEW OF CALCULUS CONCEPTS FOR JDEP 384H. Thomas Shores Department of Mathematics University of Nebraska Spring 2007 A REVIEW OF CALCULUS CONCEPTS FOR JDEP 384H Thoms Shores Deprtment of Mthemtics University of Nebrsk Spring 2007 Contents Rtes of Chnge nd Derivtives 1 Dierentils 4 Are nd Integrls 5 Multivrite Clculus

More information

Advanced Computational Fluid Dynamics AA215A Lecture 3 Polynomial Interpolation: Numerical Differentiation and Integration.

Advanced Computational Fluid Dynamics AA215A Lecture 3 Polynomial Interpolation: Numerical Differentiation and Integration. Advnced Computtionl Fluid Dynmics AA215A Lecture 3 Polynomil Interpoltion: Numericl Differentition nd Integrtion Antony Jmeson Winter Qurter, 2016, Stnford, CA Lst revised on Jnury 7, 2016 Contents 3 Polynomil

More information

6.5 Improper integrals

6.5 Improper integrals Eerpt from "Clulus" 3 AoPS In. www.rtofprolemsolving.om 6.5. IMPROPER INTEGRALS 6.5 Improper integrls As we ve seen, we use the definite integrl R f to ompute the re of the region under the grph of y =

More information

Main topics for the First Midterm

Main topics for the First Midterm Min topics for the First Midterm The Midterm will cover Section 1.8, Chpters 2-3, Sections 4.1-4.8, nd Sections 5.1-5.3 (essentilly ll of the mteril covered in clss). Be sure to know the results of the

More information

Best Approximation. Chapter The General Case

Best Approximation. Chapter The General Case Chpter 4 Best Approximtion 4.1 The Generl Cse In the previous chpter, we hve seen how n interpolting polynomil cn be used s n pproximtion to given function. We now wnt to find the best pproximtion to given

More information

A Lower Bound for the Length of a Partial Transversal in a Latin Square, Revised Version

A Lower Bound for the Length of a Partial Transversal in a Latin Square, Revised Version A Lower Bound for the Length of Prtil Trnsversl in Ltin Squre, Revised Version Pooy Htmi nd Peter W. Shor Deprtment of Mthemtil Sienes, Shrif University of Tehnology, P.O.Bo 11365-9415, Tehrn, Irn Deprtment

More information

Matrices SCHOOL OF ENGINEERING & BUILT ENVIRONMENT. Mathematics (c) 1. Definition of a Matrix

Matrices SCHOOL OF ENGINEERING & BUILT ENVIRONMENT. Mathematics (c) 1. Definition of a Matrix tries Definition of tri mtri is regulr rry of numers enlosed inside rkets SCHOOL OF ENGINEERING & UIL ENVIRONEN Emple he following re ll mtries: ), ) 9, themtis ), d) tries Definition of tri Size of tri

More information

New Expansion and Infinite Series

New Expansion and Infinite Series Interntionl Mthemticl Forum, Vol. 9, 204, no. 22, 06-073 HIKARI Ltd, www.m-hikri.com http://dx.doi.org/0.2988/imf.204.4502 New Expnsion nd Infinite Series Diyun Zhng College of Computer Nnjing University

More information

QUADRATURE is an old-fashioned word that refers to

QUADRATURE is an old-fashioned word that refers to World Acdemy of Science Engineering nd Technology Interntionl Journl of Mthemticl nd Computtionl Sciences Vol:5 No:7 011 A New Qudrture Rule Derived from Spline Interpoltion with Error Anlysis Hdi Tghvfrd

More information

Best Approximation in the 2-norm

Best Approximation in the 2-norm Jim Lmbers MAT 77 Fll Semester 1-11 Lecture 1 Notes These notes correspond to Sections 9. nd 9.3 in the text. Best Approximtion in the -norm Suppose tht we wish to obtin function f n (x) tht is liner combintion

More information

STEP FUNCTIONS, DELTA FUNCTIONS, AND THE VARIATION OF PARAMETERS FORMULA. 0 if t < 0, 1 if t > 0.

STEP FUNCTIONS, DELTA FUNCTIONS, AND THE VARIATION OF PARAMETERS FORMULA. 0 if t < 0, 1 if t > 0. STEP FUNCTIONS, DELTA FUNCTIONS, AND THE VARIATION OF PARAMETERS FORMULA STEPHEN SCHECTER. The unit step function nd piecewise continuous functions The Heviside unit step function u(t) is given by if t

More information

1. On some properties of definite integrals. We prove

1. On some properties of definite integrals. We prove This short collection of notes is intended to complement the textbook Anlisi Mtemtic 2 by Crl Mdern, published by Città Studi Editore, [M]. We refer to [M] for nottion nd the logicl stremline of the rguments.

More information

FUNCTIONS OF α-slow INCREASE

FUNCTIONS OF α-slow INCREASE Bulletin of Mthemticl Anlysis nd Applictions ISSN: 1821-1291, URL: http://www.bmth.org Volume 4 Issue 1 (2012), Pges 226-230. FUNCTIONS OF α-slow INCREASE (COMMUNICATED BY HÜSEYIN BOR) YILUN SHANG Abstrct.

More information

Properties of Integrals, Indefinite Integrals. Goals: Definition of the Definite Integral Integral Calculations using Antiderivatives

Properties of Integrals, Indefinite Integrals. Goals: Definition of the Definite Integral Integral Calculations using Antiderivatives Block #6: Properties of Integrls, Indefinite Integrls Gols: Definition of the Definite Integrl Integrl Clcultions using Antiderivtives Properties of Integrls The Indefinite Integrl 1 Riemnn Sums - 1 Riemnn

More information

The Double Integral. The Riemann sum of a function f (x; y) over this partition of [a; b] [c; d] is. f (r j ; t k ) x j y k

The Double Integral. The Riemann sum of a function f (x; y) over this partition of [a; b] [c; d] is. f (r j ; t k ) x j y k The Double Integrl De nition of the Integrl Iterted integrls re used primrily s tool for omputing double integrls, where double integrl is n integrl of f (; y) over region : In this setion, we de ne double

More information