Questions. denotes answer available in Student Solutions Manual/Study Guide; O denotes objective question

Size: px
Start display at page:

Download "Questions. denotes answer available in Student Solutions Manual/Study Guide; O denotes objective question"

Transcription

1 Qustions 95 Qustions dnots nswr vill in tudnt olutions Mnul/tudy Guid; O dnots ojctiv qustion. Th currnt in circuit contining coil, rsistor, nd ttry hs rchd constnt vlu. Dos th coil hv n inductnc? Dos th coil ffct th vlu of th currnt? 2. Wht prmtrs ffct th inductnc of coil? Dos th inductnc of coil dpnd on th currnt in th coil? 3. O nitilly, n inductor with no rsistnc crris constnt currnt. Thn th currnt is rought to nw constnt vlu twic s lrg. Aftr this chng, wht hs hppnd to th mf in th inductor? () t is lrgr thn for th chng y fctor of 4. () t is lrgr y fctor of 2. (c) t hs th sm nonzro vlu. (d) t continus to zro. () t hs dcrsd. 4. O A long, fin wir is wound into coil with inductnc 5 mh. Th coil is connctd cross th trminls of ttry, nd th currnt is msurd fw sconds ftr th connction is md. Th wir is unwound nd wound gin into diffrnt coil with 0 mh. This scond coil is connctd cross th sm ttry, nd th currnt is msurd in th sm wy. Comprd with th currnt in th first coil, is th currnt in th scond coil () four tims s lrg, () twic s lrg, (c) unchngd, (d) hlf s lrg, or () on-fourth s lrg? 5. O Two solnoidl coils, A nd B, r wound using qul lngths of th sm kind of wir. Th lngth of th xis of ch coil is lrg comprd with its dimtr. Th xil lngth of coil A is twic s lrg s tht of coil B, nd coil A hs twic s mny turns s coil B. Wht is th rtio of th inductnc of coil A to tht of coil B? () 8 () (c) 2 (d) () (f) (g) 6. A switch controls th currnt in circuit tht hs lrg inductnc. s sprk (Fig. Q32.6) mor likly to producd t th switch whn th switch is ing closd, whn it is ing opnd, or dosn t it mttr? Th lctric rc cn mlt nd oxidiz th contct surfcs, rsulting in high rsistivity of th contcts nd vntul dstruction of th switch. Bfor lctronic ignitions wr invntd, distriutor contct points in utomoils hd to rplcd rgulrly. witchs in powr distriution ntworks nd switchs controlling lrg motors, gnrtors, nd lctromgnts cn suffr from rcing nd cn vry dngrous to oprt. Alxndr Hédr Figur Q O n Figur Q32.7, th switch is lft in position for long tim intrvl nd is thn quickly thrown to position. nk th mgnituds of th voltgs cross th four cir- 8 cuit lmnts short tim thrftr from th lrgst to th smllst. 2.0 V Figur Q H 8. Considr th four circuits shown in Figur Q32.8, ch consisting of ttry, switch, lightul, rsistor, nd ithr cpcitor or n inductor. Assum th cpcitor hs lrg cpcitnc nd th inductor hs lrg inductnc ut no rsistnc. Th lightul hs high fficincy, glowing whnvr it crris lctric currnt. (i) Dscri wht th lightul dos in ch of circuits (), (), (c), nd (d) ftr th switch is thrown closd. (ii) Dscri wht th lightul dos in ch circuit ftr, hving n closd for long tim intrvl, th switch is thrown opn. () (c) Figur Q O Don t do this; it s dngrous nd illgl. uppos criminl wnts to stl nrgy from th lctric compny y plcing flt, rctngulr coil of wir clos to, ut not touching, on long, stright, horizontl wir in trnsmission lin. Th long, stright wir crris sinusoidlly vrying currnt. Which of th following sttmnts is tru? () Th mthod works st if th coil is in vrticl pln surrounding th stright wir. () Th mthod works st if th coil is in vrticl pln with th two long sids of th rctngl prlll to th long wir nd qully fr from it. (c) Th mthod works st if th coil nd th long wir r in th sm horizontl pln with on long sid of th rctngl clos to th wir. (d) Th mthod works for ny orinttion of th coil. () Th mthod cnnot work without contct twn th coil nd th long wir. 0. Considr this thsis: Josph Hnry, Amric s first profssionl physicist, cusd th most rcnt sic chng in () (d)

2 96 Chptr 32 nductnc th humn viw of th Univrs whn h discovrd slfinduction during school vction t th Alny Acdmy out 830. Bfor tht tim, on could think of th Univrs s composd of only on thing: mttr. Th nrgy tht tmporrily mintins th currnt ftr ttry is rmovd from coil, on th othr hnd, is not nrgy tht longs to ny chunk of mttr. t is nrgy in th msslss mgntic fild surrounding th coil. With Hnry s discovry, Ntur forcd us to dmit tht th Univrs consists of filds s wll s mttr. Argu for or ginst th sttmnt. n your viw, wht mks up th Univrs?. O f th currnt in n inductor is dould, y wht fctor is th stord nrgy multiplid? () 4 () 2 (c) (d) 2 () 4 2. O A solnoidl inductor for printd circuit ord is ing rdsignd. To sv wight, th numr of turns is rducd y on-hlf with th gomtric dimnsions kpt th sm. By how much must th currnt chng if th nrgy stord in th inductor is to rmin th sm? () t must four tims lrgr () t must two tims lrgr (c) t must lrgr y fctor of 2. (d) t should lft th sm. () t should on-hlf s lrg. (f) No chng in th currnt cn compnst for th rduction in th numr of turns. 3. Discuss th similritis twn th nrgy stord in th lctric fild of chrgd cpcitor nd th nrgy stord in th mgntic fild of currnt-crrying coil. 4. Th opn switch in Figur Q32.4 is thrown closd t t 0. Bfor th switch is closd, th cpcitor is unchrgd nd ll currnts r zro. Dtrmin th currnts in, C, nd nd th potntil diffrncs cross, C, nd () t th instnt ftr th switch is closd nd () long ftr it is closd. C 5. O Th cntrs of two circulr loops r sprtd y fixd distnc. (i) For wht rltiv orinttion of th loops is thir mutul inductnc mximum? () coxil nd lying in prlll plns () lying in th sm pln (c) lying in prpndiculr plns, with th cntr of on on th xis of th othr (d) Th orinttion mks no diffrnc. (ii) For wht rltiv orinttion is thir mutul inductnc minimum? Choos from th sm possiilitis. 6. n th C circuit shown in Figur 32.0, th chrg on th cpcitor is somtims zro, ut t such instnts th currnt in th circuit is not zro. How is this hvior possil? 7. How cn you tll whthr n C circuit is ovrdmpd or undrdmpd? 8. Cn n ojct xrt forc on itslf? Whn coil inducs n mf in itslf, dos it xrt forc on itslf? Figur Q Prolms Th Prolms from this chptr my ssignd onlin in WAssign. ign in t nd go to ThomsonNOW to ssss your undrstnding of this chptr s topics with dditionl quizzing nd concptul qustions., 2, 3 dnots strightforwrd, intrmdit, chllnging; dnots full solution vill in tudnt olutions Mnul/tudy Guid; dnots cochd solution with hints vill t dnots dvloping symolic rsoning; dnots sking for qulittiv rsoning; dnots computr usful in solving prolm ction 32. lf-nduction nd nductnc. A 2.00-H inductor crris stdy currnt of A. Whn th switch in th circuit is opnd, th currnt is ffctivly zro ftr 0.0 ms. Wht is th vrg inducd mf in th inductor during this tim intrvl? 2. A coild tlphon cord forms spirl hving 70 turns, dimtr of.30 cm nd n unstrtchd lngth of 60.0 cm. Dtrmin th inductnc of on conductor in th unstrtchd cord. 3. A 0.0-mH inductor crris currnt mx sin vt, with mx 5.00 A nd v/2p 60.0 Hz. Wht is th slfinducd mf s function of tim? 4. An mf of 24.0 mv is inducd in 500-turn coil t n instnt whn th currnt is 4.00 A nd is chnging t th rt of 0.0 A/s. Wht is th mgntic flux through ch turn of th coil? 5. An inductor in th form of solnoid contins 420 turns, is 6.0 cm in lngth, nd hs cross-sctionl r of 3.00 cm 2. Wht uniform rt of dcrs of currnt through th inductor inducs n mf of 75 mv? 6. Th currnt in 90.0-mH inductor chngs with tim s.00t t (in units). Find th mgnitud of th inducd mf t () t.00 s nd () t 4.00 s. (c) At wht tim is th mf zro? 7. A 40.0-mA currnt is crrid y uniformly wound ircor solnoid with 450 turns, 5.0-mm dimtr, nd 2.0-cm lngth. Comput () th mgntic fild insid th solnoid, () th mgntic flux through ch turn, nd (c) th inductnc of th solnoid. (d) Wht f? f th currnt wr diffrnt, which of ths quntitis would chng? 8. A toroid hs mjor rdius nd minor rdius r nd is tightly wound with N turns of wir s shown in Figur P32.8. f r, th mgntic fild in th rgion nclosd y th wir of th torus, of cross-sctionl r A pr 2, is ssntilly th sm s th mgntic fild of 2 = intrmdit; 3 = chllnging; = M/G; = ThomsonNOW; = symolic rsoning; = qulittiv rsoning

3 Prolms 97 solnoid tht hs n nt into lrg circl of rdius. Modling th fild s th uniform fild of long solnoid, show tht th inductnc of such toroid is pproximtly m 0N 2 A 2p (An xct xprssion of th inductnc of toroid with rctngulr cross sction is drivd in Prolm 57.) r 9. A slf-inducd mf in solnoid of inductnc chngs in tim s 0 kt. Find th totl chrg tht psss through th solnoid, ssuming th chrg is finit. ction 32.2 Circuits 0. how tht i t/t is solution of th diffrntil qution d dt 0 whr i is th currnt t t 0 nd t /.. A 2.0-V ttry is connctd into sris circuit contining 0.0- rsistor nd 2.00-H inductor. n wht tim intrvl will th currnt rch () 50.0% nd () 90.0% of its finl vlu? 2. n th circuit digrmmd in Figur P32.2, tk 2.0 V nd Assum th switch is opn for t 0 nd is closd t t 0. On singl st of xs, sktch grphs of th currnt in th circuit s function of tim for t 0, ssuming () th inductnc in th circuit is ssntilly zro, () th inductnc hs n intrmdit vlu, nd (c) th inductnc hs vry lrg vlu. l th initil nd finl vlus of th currnt. Figur P32.8 Ar A 4. n th circuit shown in Figur P32.2, lt 7.00 H, 9.00, nd 20 V. Wht is th slf-inducd mf s ftr th switch is closd? 5. For th circuit shown in Figur P32.2, lt th inductnc 3.00 H, th rsistnc 8.00, nd th ttry mf 36.0 V. () Clcult th rtio of th potntil diffrnc cross th rsistor to th mf cross th inductor whn th currnt is 2.00 A. () Clcult th mf cross th inductor whn th currnt is 4.50 A. 6. A 2.0-V ttry is connctd in sris with rsistor nd n inductor. Th circuit hs tim constnt of 500 ms, nd th mximum currnt is 200 ma. Wht is th vlu of th inductnc of th inductor? 7. An inductor tht hs n inductnc of 5.0 H nd rsistnc of 30.0 is connctd cross 00-V ttry. Wht is th rt of incrs of th currnt () t t 0 nd () t t.50 s? 8. Th switch in Figur P32.8 is opn for t 0 nd is thn thrown closd t tim t 0. Find th currnt in th inductor nd th currnt in th switch s functions of tim thrftr. 0.0 V Figur P32.8 Prolms 8 nd H 9. A sris circuit with 3.00 H nd sris C circuit with C 3.00 mf hv qul tim constnts. f th two circuits contin th sm rsistnc, () wht is th vlu of nd () wht is th tim constnt? 20. A currnt puls is fd to th prtil circuit shown in Figur P Th currnt gins t zro, coms 0.0 A twn t 0 nd t 200 ms, nd thn is zro onc gin. Dtrmin th currnt in th inductor s function of tim. (t ) 0.0 A 200 ms (t ) mh Figur P32.2 Prolms 2, 3, 4, nd 5. Figur P Considr th circuit in Figur P32.2, tking 6.00 V, 8.00 mh, nd () Wht is th inductiv tim constnt of th circuit? () Clcult th currnt in th circuit 250 ms ftr th switch is closd. (c) Wht is th vlu of th finl stdy-stt currnt? (d) Aftr wht tim intrvl dos th currnt rch 80.0% of its mximum vlu? 2. A 40-mH inductor nd rsistor r connctd with switch to 6.00-V ttry s shown in Figur P32.2. () Aftr th switch is thrown to (conncting th ttry), wht tim intrvl lpss for th currnt rchs 220 ma? () Wht is th currnt in th inductor 0.0 s ftr th switch is closd? (c) Now th switch is 2 = intrmdit; 3 = chllnging; = M/G; = ThomsonNOW; = symolic rsoning; = qulittiv rsoning

4 98 Chptr 32 nductnc quickly thrown from to. Wht tim intrvl lpss for th currnt flls to 60 ma? Figur P Two idl inductors, nd 2, hv zro intrnl rsistnc nd r fr prt, so thir mgntic filds do not influnc ch othr. () Assuming ths inductors r connctd in sris, show tht thy r quivlnt to singl idl inductor hving q 2. () Assuming ths sm two inductors r connctd in prlll, show tht thy r quivlnt to singl idl inductor hving / q / / 2. (c) Wht f? Now considr two inductors nd 2 tht hv nonzro intrnl rsistncs nd 2, rspctivly. Assum thy r still fr prt so tht thir mutul inductnc is zro. Assuming ths inductors r connctd in sris, show tht thy r quivlnt to singl inductor hving q 2 nd q 2. (d) f ths sm inductors r now connctd in prlll, is it ncssrily tru tht thy r quivlnt to singl idl inductor hving / q / / 2 nd / q / / 2? Explin your nswr. ction 32.3 Enrgy in Mgntic Fild 23. An ir-cor solnoid with 68 turns is 8.00 cm long nd hs dimtr of.20 cm. How much nrgy is stord in its mgntic fild whn it crris currnt of A? 24. Th mgntic fild insid suprconducting solnoid is 4.50 T. Th solnoid hs n innr dimtr of 6.20 cm nd lngth of 26.0 cm. Dtrmin () th mgntic nrgy dnsity in th fild nd () th nrgy stord in th mgntic fild within th solnoid. 25. On clr dy t crtin loction, 00-V/m vrticl lctric fild xists nr th Erth s surfc. At th sm plc, th Erth s mgntic fild hs mgnitud of T. Comput th nrgy dnsitis of th two filds. 26. Complt th clcultion in Exmpl 32.3 y proving tht 2t> dt A flt coil of wir hs n inductnc of 40.0 mh nd rsistnc of t is connctd to 22.0-V ttry t th instnt t 0. Considr th momnt whn th currnt is 3.00 A. () At wht rt is nrgy ing dlivrd y th ttry? () Wht is th powr ing dlivrd to th rsistor? (c) At wht rt is nrgy ing stord in th mgntic fild of th coil? (d) Wht is th rltionship mong ths thr powr vlus? s this rltionship tru t othr instnts s wll? Explin th rltionship t th momnt immditly ftr t 0 nd t momnt svrl sconds ltr. 28. A 0.0-V ttry, rsistor, nd 0.0-H inductor r connctd in sris. Aftr th currnt in th circuit hs rchd its mximum vlu, clcult () th powr ing supplid y th ttry, () th powr ing dlivrd to th rsistor, (c) th powr ing dlivrd to th inductor, nd (d) th nrgy stord in th mgntic fild of th inductor. 29. Assum th mgnitud of th mgntic fild outsid sphr of rdius is B B 0 (/r) 2, whr B 0 is constnt. Dtrmin th totl nrgy stord in th mgntic fild outsid th sphr nd vlut your rsult for B T nd m, vlus pproprit for th Erth s mgntic fild. ction 32.4 Mutul nductnc 30. Two coils r clos to ch othr. Th first coil crris currnt givn y (t) (5.00 A) t sin (377t). At t s, th mf msurd cross th scond coil is 3.20 V. Wht is th mutul inductnc of th coils? 3. Two coils, hld in fixd positions, hv mutul inductnc of 00 mh. Wht is th pk mf in on coil whn sinusoidl currnt givn y (t) (0.0 A) sin ( 000t) is in th othr coil? 32. On printd circuit ord, rltivly long, stright conductor nd conducting rctngulr loop li in th sm pln s shown in Figur P3.8 in Chptr 3. Tking h mm, w.30 mm, nd 2.70 mm, find thir mutul inductnc. 33. Two solnoids A nd B, spcd clos to ch othr nd shring th sm cylindricl xis, hv 400 nd 700 turns, rspctivly. A currnt of 3.50 A in coil A producs n vrg flux of 300 mw through ch turn of A nd flux of 90.0 mw through ch turn of B. () Clcult th mutul inductnc of th two solnoids. () Wht is th inductnc of A? (c) Wht mf is inducd in B whn th currnt in A incrss t th rt of A/s? 34. A solnoid hs N turns, rdius, nd lngth. t is so long tht its mgntic fild is uniform nrly vrywhr insid it nd is nrly zro outsid. A scond solnoid hs N 2 turns, rdius 2, nd th sm lngth. t lis insid th first solnoid, with thir xs prlll. () Assum solnoid crris vril currnt. Comput th mutul inductnc chrctrizing th mf inducd in solnoid 2. () Now ssum solnoid 2 crris currnt. Comput th mutul inductnc to which th mf in solnoid is proportionl. (c) tt how th rsults of prts () nd () compr with ch othr. 35. A lrg coil of rdius nd hving N turns is coxil with smll coil of rdius 2 nd hving N 2 turns. Th cntrs of th coils r sprtd y distnc x tht is much lrgr thn 2. Wht is th mutul inductnc of th coils? uggstion: John von Numnn provd tht th sm nswr must rsult from considring th flux through th first coil of th mgntic fild producd y th scond coil or from considring th flux through th scond coil of th mgntic fild producd y th first coil. n this prolm, it is sy to clcult th flux through th smll coil, ut it is difficult to clcult th flux through th lrg coil cus to do so, you would hv to know th mgntic fild wy from th xis. 36. Two inductors hving inductncs nd 2 r connctd in prlll s shown in Figur P Th mutul inductnc twn th two inductors is M. Dtr- 2 = intrmdit; 3 = chllnging; = M/G; = ThomsonNOW; = symolic rsoning; = qulittiv rsoning

5 Prolms 99 min th quivlnt inductnc q for th systm (Fig. P32.36). (t ) () M 2 Figur P32.36 (t ) q ction 32.5 Oscilltions in n C Circuit 37. A.00-mF cpcitor is chrgd y 40.0-V powr supply. Th fully chrgd cpcitor is thn dischrgd through 0.0-mH inductor. Find th mximum currnt in th rsulting oscilltions. 38. An C circuit consists of 20.0-mH inductor nd mF cpcitor. f th mximum instntnous currnt is 0.00 A, wht is th grtst potntil diffrnc cross th cpcitor? 39. n th circuit of Figur P32.39, th ttry mf is 50.0 V, th rsistnc is 250, nd th cpcitnc is mf. Th switch is closd for long tim intrvl, nd zro potntil diffrnc is msurd cross th cpcitor. Aftr th switch is opnd, th potntil diffrnc cross th cpcitor rchs mximum vlu of 50 V. Wht is th vlu of th inductnc? Figur P An C circuit lik th on in Figur 32.0 contins n 82.0-mH inductor nd 7.0-mF cpcitor tht initilly crris 80-mC chrg. Th switch is opn for t 0 nd thn thrown closd t t 0. () Find th frquncy (in hrtz) of th rsulting oscilltions. At t.00 ms, find () th chrg on th cpcitor nd (c) th currnt in th circuit. 4. A fixd inductnc.05 mh is usd in sris with vril cpcitor in th tuning sction of rdiotlphon on ship. Wht cpcitnc tuns th circuit to th signl from trnsmittr rodcsting t 6.30 MHz? 42. Th switch in Figur P32.42 is connctd to point for long tim intrvl. Aftr th switch is thrown to point, wht r () th frquncy of oscilltion of th C circuit, () th mximum chrg tht pprs on th cpcitor, V Figur P mf C () 0.00 H (c) th mximum currnt in th inductor, nd (d) th totl nrgy th circuit posssss t t 3.00 s? 43. An C circuit lik tht in Figur 32.0 consists of 3.30-H inductor nd n 840-pF cpcitor tht initilly crris 05-mC chrg. Th switch is opn for t 0 nd thn thrown closd t t 0. Comput th following quntitis t t 2.00 ms: () th nrgy stord in th cpcitor, () th nrgy stord in th inductor, nd (c) th totl nrgy in th circuit. ction 32.6 Th C Circuit 44. n Activ Figur 32.5, lt 7.60, 2.20 mh, nd C.80 mf. () Clcult th frquncy of th dmpd oscilltion of th circuit. () Wht is th criticl rsistnc? 45. Considr n C circuit in which 500 mh nd C 0.00 mf. () Wht is th rsonnc frquncy v 0? () f rsistnc of.00 k is introducd into this circuit, wht is th frquncy of th (dmpd) oscilltions? (c) Wht is th prcnt diffrnc twn th two frquncis? 46. how tht Eqution in th txt is Kirchhoff s loop rul s pplid to th circuit in Activ Figur Elctricl oscilltions r inititd in sris circuit contining cpcitnc C, inductnc, nd rsistnc. () f V 4>C (wk dmping), wht tim intrvl lpss for th mplitud of th currnt oscilltion flls to 50.0% of its initil vlu? () Ovr wht tim intrvl dos th nrgy dcrs to 50.0% of its initil vlu? Additionl Prolms 48. viw prolm. This prolm xtnds th rsoning of ction 26.4, Prolm 29 in Chptr 26, Prolm 33 in Chptr 30, nd ction () Considr cpcitor with vcuum twn its lrg, closly spcd, oppositly chrgd prlll plts. how tht th forc on on plt cn ccountd for y thinking of th lctric fild twn th plts s xrting ngtiv prssur qul to th nrgy dnsity of th lctric fild. () Considr two infinit pln shts crrying lctric currnts in opposit dirctions with qul linr currnt dnsitis J s. Clcult th forc pr r cting on on sht du to th mgntic fild, of mgnitud m 0 J s /2, crtd y th othr sht. (c) Clcult th nt mgntic fild twn th shts nd th fild outsid of th volum twn thm. (d) Clcult th nrgy dnsity in th mgntic fild twn th shts. () how tht th forc on on sht cn ccountd for y thinking of th mgntic fild twn th shts s xrting positiv prssur qul to its nrgy dnsity. This rsult for mgntic prssur pplis to ll currnt configurtions, not only to shts of currnt. 49. A.00-mH inductor nd.00-mf cpcitor r connctd in sris. Th currnt in th circuit is dscrid y 20.0t, whr t is in sconds nd is in mprs. Th cpcitor initilly hs no chrg. Dtrmin () th voltg cross th inductor s function of tim, () th voltg cross th cpcitor s function of tim, nd (c) th tim whn th nrgy stord in th cpcitor first xcds tht in th inductor. 50. An inductor hving inductnc nd cpcitor hving cpcitnc C r connctd in sris. Th currnt in th circuit incrss linrly in tim s dscrid y Kt, 2 = intrmdit; 3 = chllnging; = M/G; = ThomsonNOW; = symolic rsoning; = qulittiv rsoning

6 920 Chptr 32 nductnc whr K is constnt. Th cpcitor is initilly unchrgd. Dtrmin () th voltg cross th inductor s function of tim, () th voltg cross th cpcitor s function of tim, nd (c) th tim whn th nrgy stord in th cpcitor first xcds tht in th inductor. 5. A cpcitor in sris C circuit hs n initil chrg Q nd is ing dischrgd. Find, in trms of nd C, th flux through ch of th N turns in th coil whn th chrg on th cpcitor is Q / n th circuit digrmmd in Figur P32.8, ssum tht th switch hs n closd for long tim intrvl nd is opnd t t 0. () Bfor th switch is opnd, dos th inductor hv s n opn circuit, short circuit, rsistor of som prticulr rsistnc, or non of ths choics? Wht currnt dos th inductor crry? () How much nrgy is stord in th inductor for t 0? (c) Aftr th switch is opnd, wht hppns to th nrgy prviously stord in th inductor? (d) ktch grph of th currnt in th inductor for t 0. l th initil nd finl vlus nd th tim constnt. 53. At th momnt t 0, 24.0-V ttry is connctd to 5.00-mH coil nd rsistor. () mmditly thrftr, how dos th potntil diffrnc cross th rsistor compr to th mf cross th coil? () Answr th sm qustion out th circuit svrl sconds ltr. (c) s thr n instnt t which ths two voltgs r qul in mgnitud? f so, whn? s thr mor thn on such instnt? (d) Aftr 4.00-A currnt is stlishd in th rsistor nd coil, th ttry is suddnly rplcd y short circuit. Answr qustions (), (), nd (c) gin with rfrnc to this nw circuit. 54. Whn th currnt in th portion of th circuit shown in Figur P32.54 is 2.00 A nd incrss t rt of A/s, th msurd potntil diffrnc is V 9.00 V. Whn th currnt is 2.00 A nd dcrss t th rt of A/s, th msurd potntil diffrnc is V 5.00 V. Clcult th vlus of nd. Figur P A tim-vrying currnt is snt through 50.0-mH inductor s shown in Figur P Mk grph of th potntil t point rltiv to th potntil t point. lr frquncy to th xprimntlly msurl ngulr frquncy. 57. Th toroid in Figur P32.57 consists of N turns nd hs rctngulr cross sction. ts innr nd outr rdii r nd, rspctivly. () how tht th inductnc of th toroid is m 0N 2 h 2p ln () Using this rsult, comput th inductnc of 500-turn toroid for which 0.0 cm, 2.0 cm, nd h.00 cm. (c) Wht f? n Prolm 8, n pproximt qution for th inductnc of toroid with W r ws drivd. To gt fl for th ccurcy of tht rsult, us th xprssion in Prolm 8 to comput th pproximt inductnc of th toroid dscrid in prt (). How dos tht rsult compr with th nswr to prt ()? Figur P () A flt, circulr coil dos not ctully produc uniform mgntic fild in th r it ncloss. Nvrthlss, stimt th inductnc of flt, compct, circulr coil, with rdius nd N turns, y ssuming th fild t its cntr is uniform ovr its r. () A circuit on lortory tl consists of.5-volt ttry, 270- rsistor, switch, nd thr 30-cm-long ptch cords conncting thm. uppos th circuit is rrngd to circulr. Think of it s flt coil with on turn. Comput th ordr of mgnitud of its inductnc nd (c) of th tim constnt dscriing how fst th currnt incrss whn you clos th switch. 59. At t 0, th opn switch in Figur P32.59 is thrown closd. Using Kirchhoff s ruls for th instntnous currnts nd voltgs in this two-loop circuit, show tht th currnt in th inductor t tim t 0 is t2 3 >2t 4 whr 2 /( 2 ). 56. Considr sris circuit consisting of 500-mF cpcitor, 32.0-mH inductor, nd rsistor. Explin wht you cn sy out th ngulr frquncy of oscilltions for () 0, () 4.00, (c) 5.0, nd (d) 7.0. lt th mthmticl dscription of th nguh (ma) t (ms) Currnt sourc 50.0 mh 2 Figur P32.55 Figur P A wir of nonmgntic mtril, with rdius, crris currnt uniformly distriutd ovr its cross sction. Th totl currnt crrid y th wir is. how tht th mgntic nrgy pr unit lngth insid th wir is m 0 2 /6p. 2 = intrmdit; 3 = chllnging; = M/G; = ThomsonNOW; = symolic rsoning; = qulittiv rsoning

7 Prolms n Figur P32.6, th switch is closd for t 0 nd stdystt conditions r stlishd. Th switch is opnd t t 0. () Find th initil mf 0 cross immditly ftr t 0. Which nd of th coil, or, is t th highr voltg? () Mk frhnd grphs of th currnts in nd in 2 s function of tim, trting th stdy-stt dirctions s positiv. how vlus for nd ftr t 0. (c) At wht momnt ftr t 0 dos th currnt in 2 hv th vlu 2.00 ma? 2.0 V Armtur mh 0.0 V Figur P k 6.00 k H 8.0 V Figur P Th ld-in wirs from tlvision ntnn r oftn constructd in th form of two prlll wirs (Fig. P32.62). Th two wirs crry currnts of qul mgnitud in opposit dirctions. Assum th wirs crry th currnt uniformly distriutd ovr thir surfcs nd no mgntic fild xists insid th wirs. () Why dos this configurtion of conductors hv n inductnc? () Wht constituts th flux loop for this configurtion? (c) how tht th inductnc of lngth x of this typ of ld-in is m 0x p w ln whr w is th cntr-to-cntr sprtion of th wirs nd is thir rdius. TV ntnn Figur P32.62 TV st viw prolms. Prolms 64 through 67 pply ids from this nd rlir chptrs to som proprtis of suprconductors, which wr introducd in ction Th rsistnc of suprconductor. n n xprimnt crrid out y. C. Collins twn 955 nd 958, currnt ws mintind in suprconducting ld ring for 2.50 yr with no osrvd loss. f th inductnc of th ring wr H nd th snsitivity of th xprimnt wr prt in 0 9, wht ws th mximum rsistnc of th ring? uggstion: Trt th ring s n circuit crrying dcying currnt nd rcll tht x x for smll x. 65. A novl mthod of storing nrgy hs n proposd. A hug undrground suprconducting coil,.00 km in dimtr, would frictd. t would crry mximum currnt of 50.0 ka through ch winding of 50-turn N 3 n solnoid. () f th inductnc of this hug coil wr 50.0 H, wht would th totl nrgy stord? () Wht would th comprssiv forc pr mtr lngth cting twn two djcnt windings m prt? 66. uprconducting powr trnsmission. Th us of suprconductors hs n proposd for powr trnsmission lins. A singl coxil cl (Fig. P32.66) could crry MW (th output of lrg powr plnt) t 200 kv, DC, ovr distnc of 000 km without loss. An innr wir of rdius 2.00 cm, md from th suprconductor N 3 n, crris th currnt in on dirction. A surrounding suprconducting cylindr of rdius 5.00 cm would crry th rturn currnt. n such systm, wht is th mgntic fild () t th surfc of th innr conductor nd () t th innr surfc of th outr conductor? (c) How much nrgy would stord in th spc twn th conductors in 000-km suprconducting lin? (d) Wht is th prssur xrtd on th outr conductor? 63. To prvnt dmg from rcing in n lctric motor, dischrg rsistor is somtims plcd in prlll with th rmtur. f th motor is suddnly unpluggd whil running, this rsistor limits th voltg tht pprs cross th rmtur coils. Considr 2.0-V DC motor with n rmtur tht hs rsistnc of 7.50 nd n inductnc of 450 mh. Assum th mgnitud of th slfinducd mf in th rmtur coils is 0.0 V whn th motor is running t norml spd. (Th quivlnt circuit for th rmtur is shown in Fig. P32.63.) Clcult th mximum rsistnc tht limits th voltg cross th rmtur to 80.0 V whn th motor is unpluggd. Figur P32.66 = 2.00 cm = 5.00 cm 67. Th Missnr ffct. Compr this prolm with Prolm 57 in Chptr 26, prtining to th forc ttrcting prfct dilctric into strong lctric fild. A fundmntl proprty of typ suprconducting mtril is prfct 2 = intrmdit; 3 = chllnging; = M/G; = ThomsonNOW; = symolic rsoning; = qulittiv rsoning

8 922 Chptr 32 nductnc dimgntism, or dmonstrtion of th Missnr ffct, illustrtd in Figur in ction 30.6 nd dscrid s follows. Th suprconducting mtril hs B 0 vrywhr insid it. f smpl of th mtril is plcd into n xtrnlly producd mgntic fild or is coold to com suprconducting whil it is in mgntic fild, lctric currnts ppr on th surfc of th smpl. Th currnts hv prcisly th strngth nd orinttion rquird to mk th totl mgntic fild zro throughout th intrior of th smpl. This prolm will hlp you to undrstnd th mgntic forc tht cn thn ct on th suprconducting smpl. A vrticl solnoid with lngth of 20 cm nd dimtr of 2.50 cm consists of 400 turns of coppr wir crrying countrclockwis currnt of 2.00 A s shown in Figur P () Find th mgntic fild in th vcuum insid th solnoid. () Find th nrgy dnsity of th mgntic fild, noting tht th units J/m 3 of nrgy dnsity r th sm s th units N/m 2 of prssur. (c) Now suprconducting r 2.20 cm in dimtr is insrtd prtwy into th solnoid. ts uppr nd is fr outsid th solnoid, whr th mgntic fild is ngligil. Th lowr nd of th r is dp insid th solnoid. Explin how you idntify th dirction rquird for th currnt on th curvd surfc of th r so tht th totl mgntic fild is zro within th r. Th fild crtd y th suprcurrnts is sktchd in Figur P32.67, nd th totl fild is sktchd in Figur P32.67c. (d) Th fild of th solnoid xrts forc on th currnt in th suprconductor. Explin how you dtrmin th dirction of th forc on th r. () Clcult th mgnitud of th forc y multiplying th nrgy dnsity of th solnoid fild tims th r of th ottom nd of th suprconducting r. B 0 () () (c) Figur P32.67 B tot Answrs to Quick Quizzs 32. (c), (f). For th constnt currnt in sttmnts () nd (), thr is no voltg cross th rsistnclss inductor. n sttmnt (c), if th currnt incrss, th mf inducd in th inductor is in th opposit dirction, from to, mking highr in potntil thn. imilrly, in sttmnt (f), th dcrsing currnt inducs n mf in th sm dirction s th currnt, from to, gin mking th potntil highr t thn t (i), (). As th switch is closd, thr is no currnt, so thr is no voltg cross th rsistor. (ii), (). Aftr long tim, th currnt hs rchd its finl vlu nd th inductor hs no furthr ffct on th circuit (), (d). Bcus th nrgy dnsity dpnds on th mgnitud of th mgntic fild, you must incrs th mgntic fild to incrs th nrgy dnsity. For solnoid, B m 0 n, whr n is th numr of turns pr unit lngth. n choic (), incrsing n incrss th mgntic fild. n choic (), th chng in cross-sctionl r hs no ffct on th mgntic fild. n choic (c), incrsing th lngth ut kping n fixd hs no ffct on th mgntic fild. ncrsing th currnt in choic (d) incrss th mgntic fild in th solnoid (). M incrss cus th mgntic flux through coil 2 incrss (i), (). f th currnt is t its mximum vlu, th chrg on th cpcitor is zro. (ii), (c). f th currnt is zro, this momnt is th instnt t which th cpcitor is fully chrgd nd th currnt is out to rvrs dirction. 2 = intrmdit; 3 = chllnging; = M/G; = ThomsonNOW; = symolic rsoning; = qulittiv rsoning

, between the vertical lines x a and x b. Given a demand curve, having price as a function of quantity, p f (x) at height k is the curve f ( x,

, between the vertical lines x a and x b. Given a demand curve, having price as a function of quantity, p f (x) at height k is the curve f ( x, Clculus for Businss nd Socil Scincs - Prof D Yun Finl Em Rviw vrsion 5/9/7 Chck wbsit for ny postd typos nd updts Pls rport ny typos This rviw sht contins summris of nw topics only (This rviw sht dos hv

More information

Chapter 16. 1) is a particular point on the graph of the function. 1. y, where x y 1

Chapter 16. 1) is a particular point on the graph of the function. 1. y, where x y 1 Prctic qustions W now tht th prmtr p is dirctl rltd to th mplitud; thrfor, w cn find tht p. cos d [ sin ] sin sin Not: Evn though ou might not now how to find th prmtr in prt, it is lws dvisl to procd

More information

Ch 1.2: Solutions of Some Differential Equations

Ch 1.2: Solutions of Some Differential Equations Ch 1.2: Solutions of Som Diffrntil Equtions Rcll th fr fll nd owl/mic diffrntil qutions: v 9.8.2v, p.5 p 45 Ths qutions hv th gnrl form y' = y - b W cn us mthods of clculus to solv diffrntil qutions of

More information

Questions. denotes answer available in Student Solutions Manual/Study Guide; O denotes objective question

Questions. denotes answer available in Student Solutions Manual/Study Guide; O denotes objective question Qustions 799 Qustions dnots nswr vill in tudnt olutions Mnul/tudy Guid; O dnots ojctiv qustion 1. Is th dirction of currnt in ttry lwys from th ngtiv trminl to th positiv trminl? Explin. 2. O crtin ttry

More information

Integration Continued. Integration by Parts Solving Definite Integrals: Area Under a Curve Improper Integrals

Integration Continued. Integration by Parts Solving Definite Integrals: Area Under a Curve Improper Integrals Intgrtion Continud Intgrtion y Prts Solving Dinit Intgrls: Ar Undr Curv Impropr Intgrls Intgrtion y Prts Prticulrly usul whn you r trying to tk th intgrl o som unction tht is th product o n lgric prssion

More information

INTEGRALS. Chapter 7. d dx. 7.1 Overview Let d dx F (x) = f (x). Then, we write f ( x)

INTEGRALS. Chapter 7. d dx. 7.1 Overview Let d dx F (x) = f (x). Then, we write f ( x) Chptr 7 INTEGRALS 7. Ovrviw 7.. Lt d d F () f (). Thn, w writ f ( ) d F () + C. Ths intgrls r clld indfinit intgrls or gnrl intgrls, C is clld constnt of intgrtion. All ths intgrls diffr y constnt. 7..

More information

Section 3: Antiderivatives of Formulas

Section 3: Antiderivatives of Formulas Chptr Th Intgrl Appli Clculus 96 Sction : Antirivtivs of Formuls Now w cn put th is of rs n ntirivtivs togthr to gt wy of vluting finit intgrls tht is ct n oftn sy. To vlut finit intgrl f(t) t, w cn fin

More information

Instructions for Section 1

Instructions for Section 1 Instructions for Sction 1 Choos th rspons tht is corrct for th qustion. A corrct nswr scors 1, n incorrct nswr scors 0. Mrks will not b dductd for incorrct nswrs. You should ttmpt vry qustion. No mrks

More information

MASSACHUSETTS INSTITUTE OF TECHNOLOGY HAYSTACK OBSERVATORY WESTFORD, MASSACHUSETTS

MASSACHUSETTS INSTITUTE OF TECHNOLOGY HAYSTACK OBSERVATORY WESTFORD, MASSACHUSETTS VSRT MEMO #05 MASSACHUSETTS INSTITUTE OF TECHNOLOGY HAYSTACK OBSERVATORY WESTFORD, MASSACHUSETTS 01886 Fbrury 3, 009 Tlphon: 781-981-507 Fx: 781-981-0590 To: VSRT Group From: Aln E.E. Rogrs Subjct: Simplifid

More information

TOPIC 5: INTEGRATION

TOPIC 5: INTEGRATION TOPIC 5: INTEGRATION. Th indfinit intgrl In mny rspcts, th oprtion of intgrtion tht w r studying hr is th invrs oprtion of drivtion. Dfinition.. Th function F is n ntidrivtiv (or primitiv) of th function

More information

UNIT # 08 (PART - I)

UNIT # 08 (PART - I) . r. d[h d[h.5 7.5 mol L S d[o d[so UNIT # 8 (PRT - I CHEMICL INETICS EXERCISE # 6. d[ x [ x [ x. r [X[C ' [X [[B r '[ [B [C. r [NO [Cl. d[so d[h.5 5 mol L S d[nh d[nh. 5. 6. r [ [B r [x [y r' [x [y r'

More information

Lecture 11 Waves in Periodic Potentials Today: Questions you should be able to address after today s lecture:

Lecture 11 Waves in Periodic Potentials Today: Questions you should be able to address after today s lecture: Lctur 11 Wvs in Priodic Potntils Tody: 1. Invrs lttic dfinition in 1D.. rphicl rprsnttion of priodic nd -priodic functions using th -xis nd invrs lttic vctors. 3. Sris solutions to th priodic potntil Hmiltonin

More information

Chem 104A, Fall 2016, Midterm 1 Key

Chem 104A, Fall 2016, Midterm 1 Key hm 104A, ll 2016, Mitrm 1 Ky 1) onstruct microstt tl for p 4 configurtion. Pls numrt th ms n ml for ch lctron in ch microstt in th tl. (Us th formt ml m s. Tht is spin -½ lctron in n s oritl woul writtn

More information

This Week. Computer Graphics. Introduction. Introduction. Graphics Maths by Example. Graphics Maths by Example

This Week. Computer Graphics. Introduction. Introduction. Graphics Maths by Example. Graphics Maths by Example This Wk Computr Grphics Vctors nd Oprtions Vctor Arithmtic Gomtric Concpts Points, Lins nd Plns Eploiting Dot Products CSC 470 Computr Grphics 1 CSC 470 Computr Grphics 2 Introduction Introduction Wh do

More information

Lecture contents. Bloch theorem k-vector Brillouin zone Almost free-electron model Bands Effective mass Holes. NNSE 508 EM Lecture #9

Lecture contents. Bloch theorem k-vector Brillouin zone Almost free-electron model Bands Effective mass Holes. NNSE 508 EM Lecture #9 Lctur contnts Bloch thorm -vctor Brillouin zon Almost fr-lctron modl Bnds ffctiv mss Hols Trnsltionl symmtry: Bloch thorm On-lctron Schrödingr qution ch stt cn ccommo up to lctrons: If Vr is priodic function:

More information

Multi-Section Coupled Line Couplers

Multi-Section Coupled Line Couplers /0/009 MultiSction Coupld Lin Couplrs /8 Multi-Sction Coupld Lin Couplrs W cn dd multipl coupld lins in sris to incrs couplr ndwidth. Figur 7.5 (p. 6) An N-sction coupld lin l W typiclly dsign th couplr

More information

Compact Guide Cylinder with One-way Lock Series MLGP ø40, ø50, ø63. Prevents dropping when air supply pressure falls or residual pressure is exhausted

Compact Guide Cylinder with One-way Lock Series MLGP ø40, ø50, ø63. Prevents dropping when air supply pressure falls or residual pressure is exhausted Compct uid Cylindr with On-wy ock ris MP ø, ø, ø Prvnts dropping whn ir supply prssur flls or rsidul prssur is xhustd Cn lockd t ny position h locking position cn chngd to ccommodt n xtrnl stoppr position

More information

FSA. CmSc 365 Theory of Computation. Finite State Automata and Regular Expressions (Chapter 2, Section 2.3) ALPHABET operations: U, concatenation, *

FSA. CmSc 365 Theory of Computation. Finite State Automata and Regular Expressions (Chapter 2, Section 2.3) ALPHABET operations: U, concatenation, * CmSc 365 Thory of Computtion Finit Stt Automt nd Rgulr Exprssions (Chptr 2, Sction 2.3) ALPHABET oprtions: U, conctntion, * otin otin Strings Form Rgulr xprssions dscri Closd undr U, conctntion nd * (if

More information

CSE 373: More on graphs; DFS and BFS. Michael Lee Wednesday, Feb 14, 2018

CSE 373: More on graphs; DFS and BFS. Michael Lee Wednesday, Feb 14, 2018 CSE 373: Mor on grphs; DFS n BFS Mihl L Wnsy, F 14, 2018 1 Wrmup Wrmup: Disuss with your nighor: Rmin your nighor: wht is simpl grph? Suppos w hv simpl, irt grph with x nos. Wht is th mximum numr of gs

More information

Theoretical Study on the While Drilling Electromagnetic Signal Transmission of Horizontal Well

Theoretical Study on the While Drilling Electromagnetic Signal Transmission of Horizontal Well 7 nd ntrntionl Confrnc on Softwr, Multimdi nd Communiction Enginring (SMCE 7) SBN: 978--6595-458-5 Thorticl Study on th Whil Drilling Elctromgntic Signl Trnsmission of Horizontl Wll Y-huo FAN,,*, Zi-ping

More information

5.4 The Quarter-Wave Transformer

5.4 The Quarter-Wave Transformer 4//9 5_4 Th Qurtr Wv Trnsformr.doc / 5.4 Th Qurtr-Wv Trnsformr Rdg Assignmnt: pp. 73-76, 4-43 By now you v noticd tht qurtr-wv lngth of trnsmission l ( λ 4, β π ) pprs oftn microwv ngrg prolms. Anothr

More information

Oppgavesett kap. 6 (1 av..)

Oppgavesett kap. 6 (1 av..) Oppgvstt kp. 6 (1 v..) hns.brnn@go.uio.no Problm 1 () Wht is homognous nucltion? Why dos Figur 6.2 in th book show tht w won't gt homognous nucltion in th tmosphr? ˆ Homognous nucltion crts cloud droplts

More information

ELECTROMAGNETIC INDUCTION CHAPTER - 38

ELECTROMAGNETIC INDUCTION CHAPTER - 38 . (a) CTOMAGNTIC INDUCTION CHAPT - 38 3 3.dl MT I M I T 3 (b) BI T MI T M I T (c) d / MI T M I T. at + bt + c s / t Volt (a) a t t Sc b t Volt c [] Wbr (b) d [a., b.4, c.6, t s] at + b. +.4. volt 3. (a)

More information

PH427/PH527: Periodic systems Spring Overview of the PH427 website (syllabus, assignments etc.) 2. Coupled oscillations.

PH427/PH527: Periodic systems Spring Overview of the PH427 website (syllabus, assignments etc.) 2. Coupled oscillations. Dy : Mondy 5 inuts. Ovrviw of th PH47 wsit (syllus, ssignnts tc.). Coupld oscilltions W gin with sss coupld y Hook's Lw springs nd find th possil longitudinl) otion of such syst. W ll xtnd this to finit

More information

COMP108 Algorithmic Foundations

COMP108 Algorithmic Foundations Grdy mthods Prudn Wong http://www.s.liv..uk/~pwong/thing/omp108/01617 Coin Chng Prolm Suppos w hv 3 typs of oins 10p 0p 50p Minimum numr of oins to mk 0.8, 1.0, 1.? Grdy mthod Lrning outoms Undrstnd wht

More information

Last time: introduced our first computational model the DFA.

Last time: introduced our first computational model the DFA. Lctur 7 Homwork #7: 2.2.1, 2.2.2, 2.2.3 (hnd in c nd d), Misc: Givn: M, NFA Prov: (q,xy) * (p,y) iff (q,x) * (p,) (follow proof don in clss tody) Lst tim: introducd our first computtionl modl th DFA. Tody

More information

I. The Connection between Spectroscopy and Quantum Mechanics

I. The Connection between Spectroscopy and Quantum Mechanics I. Th Connction twn Spctroscopy nd Quntum Mchnics On of th postults of quntum mchnics: Th stt of systm is fully dscrid y its wvfunction, Ψ( r1, r,..., t) whr r 1, r, tc. r th coordints of th constitunt

More information

Elliptical motion, gravity, etc

Elliptical motion, gravity, etc FW Physics 130 G:\130 lctur\ch 13 Elliticl motion.docx g 1 of 7 11/3/010; 6:40 PM; Lst rintd 11/3/010 6:40:00 PM Fig. 1 Elliticl motion, grvity, tc minor xis mjor xis F 1 =A F =B C - D, mjor nd minor xs

More information

Lecture 4. Conic section

Lecture 4. Conic section Lctur 4 Conic sction Conic sctions r locus of points whr distncs from fixd point nd fixd lin r in constnt rtio. Conic sctions in D r curvs which r locus of points whor position vctor r stisfis r r. whr

More information

SAFE HANDS & IIT-ian's PACE EDT-15 (JEE) SOLUTIONS

SAFE HANDS & IIT-ian's PACE EDT-15 (JEE) SOLUTIONS It is not possibl to find flu through biggr loop dirctly So w will find cofficint of mutual inductanc btwn two loops and thn find th flu through biggr loop Also rmmbr M = M ( ) ( ) EDT- (JEE) SOLUTIONS

More information

Minimum Spanning Trees

Minimum Spanning Trees Minimum Spnning Trs Minimum Spnning Trs Problm A town hs st of houss nd st of rods A rod conncts nd only houss A rod conncting houss u nd v hs rpir cost w(u, v) Gol: Rpir nough (nd no mor) rods such tht:

More information

SOLVED EXAMPLES. be the foci of an ellipse with eccentricity e. For any point P on the ellipse, prove that. tan

SOLVED EXAMPLES. be the foci of an ellipse with eccentricity e. For any point P on the ellipse, prove that. tan LOCUS 58 SOLVED EXAMPLES Empl Lt F n F th foci of n llips with ccntricit. For n point P on th llips, prov tht tn PF F tn PF F Assum th llips to, n lt P th point (, sin ). P(, sin ) F F F = (-, 0) F = (,

More information

22.615, MHD Theory of Fusion Systems Prof. Freidberg Lecture 8: Effect of a Vertical Field on Tokamak Equilibrium

22.615, MHD Theory of Fusion Systems Prof. Freidberg Lecture 8: Effect of a Vertical Field on Tokamak Equilibrium .65, MHD Thory of usion Systms Prof. ridrg Lctur 8: Effct of Vrticl ild on Tokmk Equilirium Toroidl orc lnc y Mns of Vrticl ild. Lt us riw why th rticl fild is imortnt. 3. or ry short tims, th cuum chmr

More information

( ) Geometric Operations and Morphing. Geometric Transformation. Forward v.s. Inverse Mapping. I (x,y ) Image Processing - Lesson 4 IDC-CG 1

( ) Geometric Operations and Morphing. Geometric Transformation. Forward v.s. Inverse Mapping. I (x,y ) Image Processing - Lesson 4 IDC-CG 1 Img Procssing - Lsson 4 Gomtric Oprtions nd Morphing Gomtric Trnsformtion Oprtions dpnd on Pil s Coordints. Contt fr. Indpndnt of pil vlus. f f (, ) (, ) ( f (, ), f ( ) ) I(, ) I', (,) (, ) I(,) I (,

More information

1.2 Faraday s law A changing magnetic field induces an electric field. Their relation is given by:

1.2 Faraday s law A changing magnetic field induces an electric field. Their relation is given by: Elctromagntic Induction. Lorntz forc on moving charg Point charg moving at vlocity v, F qv B () For a sction of lctric currnt I in a thin wir dl is Idl, th forc is df Idl B () Elctromotiv forc f s any

More information

CSE303 - Introduction to the Theory of Computing Sample Solutions for Exercises on Finite Automata

CSE303 - Introduction to the Theory of Computing Sample Solutions for Exercises on Finite Automata CSE303 - Introduction to th Thory of Computing Smpl Solutions for Exrciss on Finit Automt Exrcis 2.1.1 A dtrministic finit utomton M ccpts th mpty string (i.., L(M)) if nd only if its initil stt is finl

More information

CSE 373: AVL trees. Warmup: Warmup. Interlude: Exploring the balance invariant. AVL Trees: Invariants. AVL tree invariants review

CSE 373: AVL trees. Warmup: Warmup. Interlude: Exploring the balance invariant. AVL Trees: Invariants. AVL tree invariants review rmup CSE 7: AVL trs rmup: ht is n invrint? Mihl L Friy, Jn 9, 0 ht r th AVL tr invrints, xtly? Disuss with your nighor. AVL Trs: Invrints Intrlu: Exploring th ln invrint Cor i: xtr invrint to BSTs tht

More information

CONTINUITY AND DIFFERENTIABILITY

CONTINUITY AND DIFFERENTIABILITY MCD CONTINUITY AND DIFFERENTIABILITY NCERT Solvd mpls upto th sction 5 (Introduction) nd 5 (Continuity) : Empl : Chck th continuity of th function f givn by f() = + t = Empl : Emin whthr th function f

More information

# 1 ' 10 ' 100. Decimal point = 4 hundred. = 6 tens (or sixty) = 5 ones (or five) = 2 tenths. = 7 hundredths.

# 1 ' 10 ' 100. Decimal point = 4 hundred. = 6 tens (or sixty) = 5 ones (or five) = 2 tenths. = 7 hundredths. How os it work? Pl vlu o imls rprsnt prts o whol numr or ojt # 0 000 Tns o thousns # 000 # 00 Thousns Hunrs Tns Ons # 0 Diml point st iml pl: ' 0 # 0 on tnth n iml pl: ' 0 # 00 on hunrth r iml pl: ' 0

More information

CBSE 2015 FOREIGN EXAMINATION

CBSE 2015 FOREIGN EXAMINATION CBSE 05 FOREIGN EXAMINATION (Sris SSO Cod No 65//F, 65//F, 65//F : Forign Rgion) Not tht ll th sts hv sm qustions Onl thir squnc of pprnc is diffrnt M Mrks : 00 Tim Allowd : Hours SECTION A Q0 Find th

More information

Mathematics. Mathematics 3. hsn.uk.net. Higher HSN23000

Mathematics. Mathematics 3. hsn.uk.net. Higher HSN23000 Highr Mthmtics UNIT Mthmtics HSN000 This documnt ws producd spcilly for th HSN.uk.nt wbsit, nd w rquir tht ny copis or drivtiv works ttribut th work to Highr Still Nots. For mor dtils bout th copyright

More information

Continuous Random Variables: Basics

Continuous Random Variables: Basics Continuous Rndom Vrils: Bsics Brlin Chn Dprtmnt o Computr Scinc & Inormtion Enginring Ntionl Tiwn Norml Univrsit Rrnc: - D.. Brtss, J. N. Tsitsilis, Introduction to roilit, Sctions 3.-3.3 Continuous Rndom

More information

CHAPTER 3 MECHANISTIC COMPARISON OF WATER CONING IN OIL AND GAS WELLS

CHAPTER 3 MECHANISTIC COMPARISON OF WATER CONING IN OIL AND GAS WELLS CHAPTER 3 MECHANISTIC COMPARISON OF WATER CONING IN OIL AND GAS WELLS Wtr coning in gs lls hs n undrstood s phnomnon similr to tht in oil ll. In contrst to oil lls, rltivly f studis hv n rportd on spcts

More information

CONIC SECTIONS. MODULE-IV Co-ordinate Geometry OBJECTIVES. Conic Sections

CONIC SECTIONS. MODULE-IV Co-ordinate Geometry OBJECTIVES. Conic Sections Conic Sctions 16 MODULE-IV Co-ordint CONIC SECTIONS Whil cutting crrot ou might hv noticd diffrnt shps shown th dgs of th cut. Anlticll ou m cut it in thr diffrnt ws, nml (i) (ii) (iii) Cut is prlll to

More information

2008 AP Calculus BC Multiple Choice Exam

2008 AP Calculus BC Multiple Choice Exam 008 AP Multipl Choic Eam Nam 008 AP Calculus BC Multipl Choic Eam Sction No Calculator Activ AP Calculus 008 BC Multipl Choic. At tim t 0, a particl moving in th -plan is th acclration vctor of th particl

More information

Errata for Second Edition, First Printing

Errata for Second Edition, First Printing Errt for Scond Edition, First Printing pg 68, lin 1: z=.67 should b z=.44 pg 1: Eqution (.63) should rd B( R) = x= R = θ ( x R) p( x) R 1 x= [1 G( x)] = θp( R) + ( θ R)[1 G( R)] pg 15, problm 6: dmnd of

More information

CIVL 8/ D Boundary Value Problems - Rectangular Elements 1/7

CIVL 8/ D Boundary Value Problems - Rectangular Elements 1/7 CIVL / -D Boundr Vlu Prolms - Rctngulr Elmnts / RECANGULAR ELEMENS - In som pplictions, it m mor dsirl to us n lmntl rprsnttion of th domin tht hs four sids, ithr rctngulr or qudriltrl in shp. Considr

More information

The Theory of Small Reflections

The Theory of Small Reflections Jim Stils Th Univ. of Knss Dt. of EECS 4//9 Th Thory of Smll Rflctions /9 Th Thory of Smll Rflctions Rcll tht w nlyzd qurtr-wv trnsformr usg th multil rflction viw ot. V ( z) = + β ( z + ) V ( z) = = R

More information

The van der Waals interaction 1 D. E. Soper 2 University of Oregon 20 April 2012

The van der Waals interaction 1 D. E. Soper 2 University of Oregon 20 April 2012 Th van dr Waals intraction D. E. Sopr 2 Univrsity of Orgon 20 pril 202 Th van dr Waals intraction is discussd in Chaptr 5 of J. J. Sakurai, Modrn Quantum Mchanics. Hr I tak a look at it in a littl mor

More information

Week 7: Ch. 11 Semiconductor diodes

Week 7: Ch. 11 Semiconductor diodes Wk 7: Ch. 11 Smiconductor diods Principls o Scintilltion Countrs Smiconductor Diods bsics o smiconductors pur lmnts & dopnts 53 Mtrils ion collction, lkg currnt diod structur, pn, np junctions dpltion

More information

b. How many ternary words of length 23 with eight 0 s, nine 1 s and six 2 s?

b. How many ternary words of length 23 with eight 0 s, nine 1 s and six 2 s? MATH 3012 Finl Exm, My 4, 2006, WTT Stunt Nm n ID Numr 1. All our prts o this prolm r onrn with trnry strings o lngth n, i.., wors o lngth n with lttrs rom th lpht {0, 1, 2}.. How mny trnry wors o lngth

More information

Lecture 12 Quantum chromodynamics (QCD) WS2010/11: Introduction to Nuclear and Particle Physics

Lecture 12 Quantum chromodynamics (QCD) WS2010/11: Introduction to Nuclear and Particle Physics Lctur Quntum chromodynmics (QCD) WS/: Introduction to Nuclr nd Prticl Physics QCD Quntum chromodynmics (QCD) is thory of th strong intrction - bsd on color forc, fundmntl forc dscribing th intrctions of

More information

Voltage, Current, Power, Series Resistance, Parallel Resistance, and Diodes

Voltage, Current, Power, Series Resistance, Parallel Resistance, and Diodes Lctur 1. oltag, Currnt, Powr, Sris sistanc, Paralll sistanc, and Diods Whn you start to dal with lctronics thr ar thr main concpts to start with: Nam Symbol Unit oltag volt Currnt ampr Powr W watt oltag

More information

Errata for Second Edition, First Printing

Errata for Second Edition, First Printing Errt for Scond Edition, First Printing pg 68, lin 1: z=.67 should b z=.44 pg 71: Eqution (.3) should rd B( R) = θ R 1 x= [1 G( x)] pg 1: Eqution (.63) should rd B( R) = x= R = θ ( x R) p( x) R 1 x= [1

More information

However, many atoms can combine to form particular molecules, e.g. Chlorine (Cl) and Sodium (Na) atoms form NaCl molecules.

However, many atoms can combine to form particular molecules, e.g. Chlorine (Cl) and Sodium (Na) atoms form NaCl molecules. Lctur 6 Titl: Fundmntls of th Quntum Thory of molcul formtion Pg- In th lst modul, w hv discussd out th tomic structur nd tomic physics to undrstnd th spctrum of toms. Howvr, mny toms cn comin to form

More information

Winter 2016 COMP-250: Introduction to Computer Science. Lecture 23, April 5, 2016

Winter 2016 COMP-250: Introduction to Computer Science. Lecture 23, April 5, 2016 Wintr 2016 COMP-250: Introduction to Computr Scinc Lctur 23, April 5, 2016 Commnt out input siz 2) Writ ny lgorithm tht runs in tim Θ(n 2 log 2 n) in wors cs. Explin why this is its running tim. I don

More information

Case Study VI Answers PHA 5127 Fall 2006

Case Study VI Answers PHA 5127 Fall 2006 Qustion. A ptint is givn 250 mg immit-rls thophyllin tblt (Tblt A). A wk ltr, th sm ptint is givn 250 mg sustin-rls thophyllin tblt (Tblt B). Th tblts follow on-comprtmntl mol n hv first-orr bsorption

More information

Walk Like a Mathematician Learning Task:

Walk Like a Mathematician Learning Task: Gori Dprtmnt of Euction Wlk Lik Mthmticin Lrnin Tsk: Mtrics llow us to prform mny usful mthmticl tsks which orinrily rquir lr numbr of computtions. Som typs of problms which cn b on fficintly with mtrics

More information

Chapter 7 Steady Magnetic Field. september 2016 Microwave Laboratory Sogang University

Chapter 7 Steady Magnetic Field. september 2016 Microwave Laboratory Sogang University Chpter 7 Stedy Mgnetic Field september 2016 Microwve Lbortory Sogng University Teching point Wht is the mgnetic field? Biot-Svrt s lw: Coulomb s lw of Mgnetic field Stedy current: current flow is independent

More information

Notes on Finite Automata Department of Computer Science Professor Goldberg Textbooks: Introduction to the Theory of Computation by Michael Sipser

Notes on Finite Automata Department of Computer Science Professor Goldberg Textbooks: Introduction to the Theory of Computation by Michael Sipser Nots on Finit Automt Dprtmnt of Computr Scinc Profssor Goldrg Txtooks: Introduction to th Thory of Computtion y Michl Sipsr Elmnts of th Thory of Computtion y H. Lwis nd C. Ppdimitriou Ths nots contin

More information

CAPACITORS AND DIELECTRICS

CAPACITORS AND DIELECTRICS Importnt Definitions nd Units Cpcitnce: CAPACITORS AND DIELECTRICS The property of system of electricl conductors nd insultors which enbles it to store electric chrge when potentil difference exists between

More information

General Notes About 2007 AP Physics Scoring Guidelines

General Notes About 2007 AP Physics Scoring Guidelines AP PHYSICS C: ELECTRICITY AND MAGNETISM 2007 SCORING GUIDELINES Gnral Nots About 2007 AP Physics Scoring Guidlins 1. Th solutions contain th most common mthod of solving th fr-rspons qustions and th allocation

More information

MASTER CLASS PROGRAM UNIT 4 SPECIALIST MATHEMATICS SEMESTER TWO 2014 WEEK 11 WRITTEN EXAMINATION 1 SOLUTIONS

MASTER CLASS PROGRAM UNIT 4 SPECIALIST MATHEMATICS SEMESTER TWO 2014 WEEK 11 WRITTEN EXAMINATION 1 SOLUTIONS MASTER CLASS PROGRAM UNIT SPECIALIST MATHEMATICS SEMESTER TWO WEEK WRITTEN EXAMINATION SOLUTIONS FOR ERRORS AND UPDATES, PLEASE VISIT WWW.TSFX.COM.AU/MC-UPDATES QUESTION () Lt p ( z) z z z If z i z ( is

More information

Problem Solving 7: Faraday s Law Solution

Problem Solving 7: Faraday s Law Solution MASSACHUSETTS NSTTUTE OF TECHNOLOGY Deprtment of Physics: 8.02 Prolem Solving 7: Frdy s Lw Solution Ojectives 1. To explore prticulr sitution tht cn led to chnging mgnetic flux through the open surfce

More information

GUC (Dr. Hany Hammad) 9/28/2016

GUC (Dr. Hany Hammad) 9/28/2016 U (r. Hny Hd) 9/8/06 ctur # 3 ignl flow grphs (cont.): ignl-flow grph rprsnttion of : ssiv sgl-port dvic. owr g qutions rnsducr powr g. Oprtg powr g. vill powr g. ppliction to Ntwork nlyzr lirtion. Nois

More information

ELEG 413 Lecture #6. Mark Mirotznik, Ph.D. Professor The University of Delaware

ELEG 413 Lecture #6. Mark Mirotznik, Ph.D. Professor The University of Delaware LG 43 Lctur #6 Mrk Mirtnik, Ph.D. Prfssr Th Univrsity f Dlwr mil: mirtni@c.udl.du Wv Prpgtin nd Plritin TM: Trnsvrs lctrmgntic Wvs A md is prticulr fild cnfigurtin. Fr givn lctrmgntic bundry vlu prblm,

More information

The Angular Momenta Dipole Moments and Gyromagnetic Ratios of the Electron and the Proton

The Angular Momenta Dipole Moments and Gyromagnetic Ratios of the Electron and the Proton Journl of Modrn hysics, 014, 5, 154-157 ublishd Onlin August 014 in SciRs. htt://www.scir.org/journl/jm htt://dx.doi.org/.436/jm.014.51415 Th Angulr Momnt Diol Momnts nd Gyromgntic Rtios of th Elctron

More information

IMPORTANT. Read these directions carefully:

IMPORTANT. Read these directions carefully: Physics 208: Electricity nd Mgnetism Finl Exm, Secs. 506 510. 7 My. 2004 Instructor: Dr. George R. Welch, 415 Engineering-Physics, 845-7737 Print your nme netly: Lst nme: First nme: Sign your nme: Plese

More information

PHYS ,Fall 05, Term Exam #1, Oct., 12, 2005

PHYS ,Fall 05, Term Exam #1, Oct., 12, 2005 PHYS1444-,Fall 5, Trm Exam #1, Oct., 1, 5 Nam: Kys 1. circular ring of charg of raius an a total charg Q lis in th x-y plan with its cntr at th origin. small positiv tst charg q is plac at th origin. What

More information

Paths. Connectivity. Euler and Hamilton Paths. Planar graphs.

Paths. Connectivity. Euler and Hamilton Paths. Planar graphs. Pths.. Eulr n Hmilton Pths.. Pth D. A pth rom s to t is squn o gs {x 0, x 1 }, {x 1, x 2 },... {x n 1, x n }, whr x 0 = s, n x n = t. D. Th lngth o pth is th numr o gs in it. {, } {, } {, } {, } {, } {,

More information

A 1 A 2. a) Find the wavelength of the radio waves. Since c = f, then = c/f = (3x10 8 m/s) / (30x10 6 Hz) = 10m.

A 1 A 2. a) Find the wavelength of the radio waves. Since c = f, then = c/f = (3x10 8 m/s) / (30x10 6 Hz) = 10m. 1. Young s doubl-slit xprint undrlis th instrunt landing syst at ost airports and is usd to guid aircraft to saf landings whn th visibility is poor. Suppos that a pilot is trying to align hr plan with

More information

CSC Design and Analysis of Algorithms. Example: Change-Making Problem

CSC Design and Analysis of Algorithms. Example: Change-Making Problem CSC 801- Dsign n Anlysis of Algorithms Ltur 11 Gry Thniqu Exmpl: Chng-Mking Prolm Givn unlimit mounts of oins of nomintions 1 > > m, giv hng for mount n with th lst numr of oins Exmpl: 1 = 25, 2 =10, =

More information

#6A&B Magnetic Field Mapping

#6A&B Magnetic Field Mapping #6A& Mgnetic Field Mpping Gol y performing this lb experiment, you will: 1. use mgnetic field mesurement technique bsed on Frdy s Lw (see the previous experiment),. study the mgnetic fields generted by

More information

EAcos θ, where θ is the angle between the electric field and

EAcos θ, where θ is the angle between the electric field and 8.4. Modl: Th lctric flux flows out of a closd surfac around a rgion of spac containing a nt positiv charg and into a closd surfac surrounding a nt ngativ charg. Visualiz: Plas rfr to Figur EX8.4. Lt A

More information

ME 522 PRINCIPLES OF ROBOTICS. FIRST MIDTERM EXAMINATION April 19, M. Kemal Özgören

ME 522 PRINCIPLES OF ROBOTICS. FIRST MIDTERM EXAMINATION April 19, M. Kemal Özgören ME 522 PINCIPLES OF OBOTICS FIST MIDTEM EXAMINATION April 9, 202 Nm Lst Nm M. Kml Özgörn 2 4 60 40 40 0 80 250 USEFUL FOMULAS cos( ) cos cos sin sin sin( ) sin cos cos sin sin y/ r, cos x/ r, r 0 tn 2(

More information

DIRECT CURRENT CIRCUITS

DIRECT CURRENT CIRCUITS DRECT CURRENT CUTS ELECTRC POWER Consider the circuit shown in the Figure where bttery is connected to resistor R. A positive chrge dq will gin potentil energy s it moves from point to point b through

More information

UNCORRECTED SAMPLE PAGES 4-1. Naming fractions KEY IDEAS. 1 Each shape represents ONE whole. a i ii. b i ii

UNCORRECTED SAMPLE PAGES 4-1. Naming fractions KEY IDEAS. 1 Each shape represents ONE whole. a i ii. b i ii - Nming frtions Chptr Frtions Eh shp rprsnts ONE whol. i ii Wht frtion is shdd? Writ s frtion nd in words. Wht frtion is not shdd? Writ s frtion nd in words. i ii i ii Writ s mny diffrnt frtions s you

More information

Weighted Matching and Linear Programming

Weighted Matching and Linear Programming Wightd Mtching nd Linr Progrmming Jonthn Turnr Mrch 19, 01 W v sn tht mximum siz mtchings cn b found in gnrl grphs using ugmnting pths. In principl, this sm pproch cn b pplid to mximum wight mtchings.

More information

a b c cat CAT A B C Aa Bb Cc cat cat Lesson 1 (Part 1) Verbal lesson: Capital Letters Make The Same Sound Lesson 1 (Part 1) continued...

a b c cat CAT A B C Aa Bb Cc cat cat Lesson 1 (Part 1) Verbal lesson: Capital Letters Make The Same Sound Lesson 1 (Part 1) continued... Progrssiv Printing T.M. CPITLS g 4½+ Th sy, fun (n FR!) wy to tch cpitl lttrs. ook : C o - For Kinrgrtn or First Gr (not for pr-school). - Tchs tht cpitl lttrs mk th sm souns s th littl lttrs. - Tchs th

More information

Physics 2135 Exam 1 February 14, 2017

Physics 2135 Exam 1 February 14, 2017 Exm Totl / 200 Physics 215 Exm 1 Ferury 14, 2017 Printed Nme: Rec. Sec. Letter: Five multiple choice questions, 8 points ech. Choose the est or most nerly correct nswer. 1. Two chrges 1 nd 2 re seprted

More information

(2) If we multiplied a row of B by λ, then the value is also multiplied by λ(here lambda could be 0). namely

(2) If we multiplied a row of B by λ, then the value is also multiplied by λ(here lambda could be 0). namely . DETERMINANT.. Dtrminnt. Introution:I you think row vtor o mtrix s oorint o vtors in sp, thn th gomtri mning o th rnk o th mtrix is th imnsion o th prlllppi spnn y thm. But w r not only r out th imnsion,

More information

Formal Concept Analysis

Formal Concept Analysis Forml Conpt Anlysis Conpt intnts s losd sts Closur Systms nd Implitions 4 Closur Systms 0.06.005 Nxt-Closur ws dvlopd y B. Gntr (984). Lt M = {,..., n}. A M is ltilly smllr thn B M, if B A if th smllst

More information

this is called an indeterninateformof-oior.fi?afleleitns derivatives can now differentiable and give 0 on on open interval containing I agree to.

this is called an indeterninateformof-oior.fi?afleleitns derivatives can now differentiable and give 0 on on open interval containing I agree to. hl sidd r L Hospitl s Rul 11/7/18 Pronouncd Loh mtims splld Non p t mtims w wnt vlut limit ii m itn ) but irst indtrnintmori?lltns indtrmint t inn gl in which cs th clld n i 9kt ti not ncssrily snsign

More information

PH2200 Practice Final Exam Spring 2004

PH2200 Practice Final Exam Spring 2004 PH2200 Practic Final Exam Spring 2004 Instructions 1. Writ your nam and studnt idntification numbr on th answr sht. 2. This a two-hour xam. 3. Plas covr your answr sht at all tims. 4. This is a closd book

More information

12. Traffic engineering

12. Traffic engineering lt2.ppt S-38. Introution to Tltrffi Thory Spring 200 2 Topology Pths A tlommunition ntwork onsists of nos n links Lt N not th st of nos in with n Lt J not th st of nos in with j N = {,,,,} J = {,2,3,,2}

More information

The pn junction: 2 Current vs Voltage (IV) characteristics

The pn junction: 2 Current vs Voltage (IV) characteristics Th pn junction: Currnt vs Voltag (V) charactristics Considr a pn junction in quilibrium with no applid xtrnal voltag: o th V E F E F V p-typ Dpltion rgion n-typ Elctron movmnt across th junction: 1. n

More information

THE DETERMINATION of the signal magnitude at the

THE DETERMINATION of the signal magnitude at the IEEE TANSACTIONS ON ELECTOMAGNETIC COMPATIBILITY, VOL 50, NO 3, AUGUST 2008 Clcultion of Elctricl Prmtrs of Two-Wir Lins in Multiconductor Cbls Boris M Lvin Abstrct A rigorous mthod for th clcultions of

More information

Electromagnetism Physics 15b

Electromagnetism Physics 15b lctromagntism Physics 15b Lctur #8 lctric Currnts Purcll 4.1 4.3 Today s Goals Dfin lctric currnt I Rat of lctric charg flow Also dfin lctric currnt dnsity J Charg consrvation in a formula Ohm s Law vryon

More information

Exam 1. It is important that you clearly show your work and mark the final answer clearly, closed book, closed notes, no calculator.

Exam 1. It is important that you clearly show your work and mark the final answer clearly, closed book, closed notes, no calculator. Exam N a m : _ S O L U T I O N P U I D : I n s t r u c t i o n s : It is important that you clarly show your work and mark th final answr clarly, closd book, closd nots, no calculator. T i m : h o u r

More information

Part 7: Capacitance And Capacitors

Part 7: Capacitance And Capacitors Part 7: apacitanc And apacitors 7. Elctric harg And Elctric Filds onsidr a pair of flat, conducting plats, arrangd paralll to ach othr (as in figur 7.) and sparatd by an insulator, which may simply b air.

More information

The Z transform techniques

The Z transform techniques h Z trnfor tchniqu h Z trnfor h th rol in dicrt yt tht th Lplc trnfor h in nlyi of continuou yt. h Z trnfor i th principl nlyticl tool for ingl-loop dicrt-ti yt. h Z trnfor h Z trnfor i to dicrt-ti yt

More information

S i m p l i f y i n g A l g e b r a SIMPLIFYING ALGEBRA.

S i m p l i f y i n g A l g e b r a SIMPLIFYING ALGEBRA. S i m p l i y i n g A l g r SIMPLIFYING ALGEBRA www.mthltis.o.nz Simpliying SIMPLIFYING Algr ALGEBRA Algr is mthmtis with mor thn just numrs. Numrs hv ix vlu, ut lgr introus vrils whos vlus n hng. Ths

More information

Limits Indeterminate Forms and L Hospital s Rule

Limits Indeterminate Forms and L Hospital s Rule Limits Indtrmint Forms nd L Hospitl s Rul I Indtrmint Form o th Tp W hv prviousl studid its with th indtrmint orm s shown in th ollowin mpls: Empl : Empl : tn [Not: W us th ivn it ] Empl : 8 h 8 [Not:

More information

ECE COMBINATIONAL BUILDING BLOCKS - INVEST 13 DECODERS AND ENCODERS

ECE COMBINATIONAL BUILDING BLOCKS - INVEST 13 DECODERS AND ENCODERS C 24 - COMBINATIONAL BUILDING BLOCKS - INVST 3 DCODS AND NCODS FALL 23 AP FLZ To o "wll" on this invstition you must not only t th riht nswrs ut must lso o nt, omplt n onis writups tht mk ovious wht h

More information

Exam 2 Thursday (7:30-9pm) It will cover material through HW 7, but no material that was on the 1 st exam.

Exam 2 Thursday (7:30-9pm) It will cover material through HW 7, but no material that was on the 1 st exam. Exam 2 Thursday (7:30-9pm) It will covr matrial through HW 7, but no matrial that was on th 1 st xam. What happns if w bash atoms with lctrons? In atomic discharg lamps, lots of lctrons ar givn kintic

More information

Module 2 Motion Instructions

Module 2 Motion Instructions Moul 2 Motion Instrutions CAUTION: Bor you strt this xprimnt, unrstn tht you r xpt to ollow irtions EXPLICITLY! Tk your tim n r th irtions or h stp n or h prt o th xprimnt. You will rquir to ntr t in prtiulr

More information

IVE(TY) Department of Engineering E&T2520 Electrical Machines 1 Miscellaneous Exercises

IVE(TY) Department of Engineering E&T2520 Electrical Machines 1 Miscellaneous Exercises TRANSFORMER Q1 IE(TY) Dpartmnt of Enginring E&T50 Elctrical Machins 1 Miscllanous Exrciss Q Q3 A singl phas, 5 ka, 0/440, 60 Hz transformr gav th following tst rsults. Opn circuit tst (440 sid opn): 0

More information

Engineering 323 Beautiful HW #13 Page 1 of 6 Brown Problem 5-12

Engineering 323 Beautiful HW #13 Page 1 of 6 Brown Problem 5-12 Enginring Bautiful HW #1 Pag 1 of 6 5.1 Two componnts of a minicomputr hav th following joint pdf for thir usful liftims X and Y: = x(1+ x and y othrwis a. What is th probability that th liftim X of th

More information

Math 34A. Final Review

Math 34A. Final Review Math A Final Rviw 1) Us th graph of y10 to find approimat valus: a) 50 0. b) y (0.65) solution for part a) first writ an quation: 50 0. now tak th logarithm of both sids: log() log(50 0. ) pand th right

More information

Page 1. Question 19.1b Electric Charge II Question 19.2a Conductors I. ConcepTest Clicker Questions Chapter 19. Physics, 4 th Edition James S.

Page 1. Question 19.1b Electric Charge II Question 19.2a Conductors I. ConcepTest Clicker Questions Chapter 19. Physics, 4 th Edition James S. ConTst Clikr ustions Chtr 19 Physis, 4 th Eition Jms S. Wlkr ustion 19.1 Two hrg blls r rlling h othr s thy hng from th iling. Wht n you sy bout thir hrgs? Eltri Chrg I on is ositiv, th othr is ngtiv both

More information