Adaptive Hierarchical Decoupling Sliding-Mode Control of a Electric Unicycle. T. C. Kuo 1/30
|
|
- Carol Tyler
- 5 years ago
- Views:
Transcription
1 Adaptive Hierarchical Decoupling Sliding-Mode Control of a Electric Unicycle T. C. Kuo 1/30
2 Outline Introduction System Modeling Adaptive Hierarchical Decoupling Sliding-Mode Control Simulation Results Conclusions /30
3 Outline Introduction System Modeling Adaptive Hierarchical Decoupling Sliding-Mode Control Simulation Results Conclusions 3/30
4 Introduction (1/) Riding unicycle has been shown to gain many benefits for human health, establishing his or her psychological confidence on learning various sports. In assisting the development of the cerebellum, unicycle exercise also can help people promote their intelligence. Aware of the shortage of the resource of the Earth, more and more technology has been attempted to use unicycles for transportation between short distance and commute. 4/30
5 Introduction (/) Dr. David Vos, 90 s, MIT Trevor Blackwell 007 Twente University 008, MuRuta 5/30
6 Outline Introduction System Modeling Adaptive Hierarchical Decoupling Sliding-Mode Control Simulation Results Conclusions 6/30
7 System Modeling (1/6) Electric unicycle and its components 7/30
8 Fx y FMθφ VM H System Modeling (/6) The simple draw of rider and free-body diagrams θ j θ i j k i 8/30
9 System Modeling (3/6) The kinetic energy and the potential energy of the wheel 1 1 Twheel = mx& + I & mφ, Vwheel = 0 = mr + I & φ ( m ) / I : moment of inertia, m : mass, x& : velocity, & φ : angle velocity m no slip between the wheel and the floor The velocity of the center of gravity (COG) for the body v v v v v = xi & + l & θθ = r & φi + l & θθ G i i l : the distance between COG of the body and the center of the wheel 9/30
10 System Modeling (4/6) The kinetic energy and the potential energy of the body 1 v v 1 T M I & V Mgl body = ( G G ) + Mθ, body = cos( θ ) v = [ r & φ l & v θcos( θ)] i l & v θsin( θ) j G & & & & = IMθ /+ M{[ rφ+ lθcos( θ)] + l θ sin ( θ)}/ I M : moment of inertia, M : mass The total kinetic energy of the electric unicycle with rider T = T + T T wheel body = & φ /+ & θ /+ && θφcos( θ) Iφ Iθ Mrl I = mr + I + Mr, I = I + Ml φ m θ M 10/30
11 System Modeling (5/6) Define the state vector of the electric unicycle as v = [ θ φ] T s Define the viscous and the Coulomb frictions as Dv ( & ) = [ μ ( & θ & φ) + c sgn( & θ & φ) μ & φ+ c sgn( & φ)] T s The Lagrangian function of the electric unicycle with rider L = T V T θ θ φ φ μ and μ are respectively the viscous damping coefficients; θ φ c and c are respectively the coefficients of the Coulomb frictions. θ φ body The Euler-Lagrange equations of motion for electric unicycle d L L T ( ) = D( vs ) dt vs v s T & & T : the torque applied between the body and the wheel 11/30
12 System Modeling (6/6) The equations of motion I && θθ = T Mlr&& φcos( θ) + Mlgsin( θ) μθ( & θ & φ) cθsgn( & θ & φ) (1) I && T Mlr&& Mrl & & c & φφ = θ cos( θ) + θ sin( θ) μφφ φsgn( φ) () The substitution of (1) into () and () into (1) give two second-order dynamic equations of the inclination and rotation angles controlled by torque T && θ = A( θ) T + B( θ, & θ, & φ) && φ = C( θ) T + D( θ, & θ, & φ) where A( θ ) = [ I + Mlrcos( θ )] φ { II θ φ [ Mlrcos( θ)] } B & & 1 I & & c & & Mlg Mlr & c & Mlr & ( θ, θφ, ) = { [ ( ) sgn( ) sin( )] cos( )[ sgn( ) sin( )]} φ μθ θ φ + θ θ φ θ + θ μφ φ + φ φ θ θ { II θ φ [ Mlrcos( θ )] } C( θ) = [ I + Mlrcos( θ)] θ { II θ φ [ Mlrcos( θ)] } D 1 θ & θ & φ = Mrl θ μ & θ & φ + c & θ & φ Mlg θ I μ & φ + c & φ Mrl & θ θ (,, ) { cos( )[ ( ) sgn( ) sin( )] [ sgn( ) sin( )]} θ θ θ φ φ { II θ φ [ Mlrcos( θ )] } 1/30
13 Outline Introduction System Modeling Adaptive Hierarchical Decoupling Sliding-Mode Control Simulation Results Conclusions 13/30
14 Adaptive Hierarchical Decoupling Sliding-Mode Control (1/4) A. Controller Synthesis Only one torque T Two control goals 1. balancing ( θ θ desired ). velocity control ( & & ) φ φ desired Hierarchical Sliding Surface function Two first-layer sliding surface functions S ( θ ) = & θ + k ( θ θ ) = & θ + k θ TH TH desired TH S (& φ) = & φ & φ PH desired The second-layer sliding surface function S = S ( θ ) + αs (& φ) α: real and positive constant T TH PH k TH : real and positive constant 14/30
15 Adaptive Hierarchical Decoupling Sliding-Mode Control (/4) Differentiating S T, and using (1) obtain S& = A( θ) T + B( θ, & θ, & φ) + k & θ + αs& (& φ) (3) T TH PH T T eq = T eq β S T A( θ ) (4) B( θθφ, &, &) k & THθ αs& PH (& φ) = A( θ ) Hierarchical Decoupling Sliding-Mode Control β : real and positive constant (5) Adaptive Hierarchical Decoupling Sliding-Mode Control T βs ˆ sat( ) ˆ T + kv ST + kcsgn( S & T φ ) = Teq A( θ ) (6) sat( ): the saturation function : the absolute function kˆ v : estimate of the compensation for the viscous friction kˆ : estimate of the compensation for the Coulomb friction c 15/30
16 Adaptive Hierarchical Decoupling Sliding-Mode Control (3/4) The parameter updating laws ˆ& k = γ S sat( S ) (7) v v T T ˆ& k = γ S sgn( S & φ ) (8) c c T T B. Stability Analysis Lyapunov function Vt () where ST k% v k% c = + + γ γ k% = k kˆ v v v k% = k kˆ c c c v c γ v, γ : two positive and real adaptation gains c 16/30
17 Adaptive Hierarchical Decoupling Sliding-Mode Control (4/4) 1 ˆ 1 V& () t = SS& kk % & & kk % ˆ γ γ T T v v c c v c 1 ˆ 1 = S[ βs ( k k% )sat( S ) ( k k% )sgn( S & φ)] kk % & & kk % ˆ γ γ T T v v T c c T v v c c c 1 ˆ 1 = βs ks sat( S ) + ks % sat( S ) ks sgn( S & φ) + ks % sgn( S & & & φ) kk % kk % ˆ T v T T v T T c T T c T T v v c c γ γc = βs k S sat( S ) k S T v T T c = βs k S sat( S ) k S sgn( S & φ) 0 T v T T c T T Using (3)-(7) obtain 1 ˆ 1 sgn( S & φ) + k% & [ S sat( S ) k ] + k% [ S sgn( S & & φ) kˆ ] γv γc & kˆ v = γ vst sat( ST) & kˆ = γ S sgn( S & φ ) T T v T T v c T T c c c T T Since V& ( t) is negative definite, it is easy to prove via Lyapunov stability theory that the second-layer sliding function, S T ( t) converge to zero as time approaches infinity. 17/30
18 Outline Introduction System Modeling Adaptive Hierarchical Decoupling Sliding-Mode Control Simulation Results Conclusions 009/08/06, 07 18/30
19 Simulation Results (1/9) The first simulation : the electric unicycle for self-balancing Computer simulation parameters: The weights : M = 98, m =. The moments of inertia : I = , I = θ The half diameter of the wheel : r = 0.5. The distance between COG of the body and the center : l = 1. φ The friction coefficients between the body and the wheel : μ = 1, μ = 5, c = 1, c = 10. The initial conditions : θ = (rad) = 10(deg), & φ = 0. θ φ θ φ The parameters of the proposed controller : α = 0.1, β = 1, γ = 1, γ = 1, μ = 1, μ = 5, c = 1, c = 10. θ desired = 0, & φ = 0. desired v c θ φ θ φ 19/30
20 Simulation Results (/9) S T S TH S PH converge to zero time (sec) Time behavior of the sliding functions ST, STH and SPH for self-balancing. 0/30
21 Simulation Results (3/9) theta 1.0 k v k c angle (rad) time (sec) angle velocity (rad/sec) converge to zero d phi/dt time (sec) Simulation results of θ and & φ for self-balancing time (sec) Simulation results of kˆ and kˆ for self-balancing. v c 1/30
22 Simulation Results (4/9) The second simulation : robustness against uncertain frictions Computer simulation parameters: The weights : M = 98, m =. The moments of inertia : I = , I = θ The half diameter of the wheel : r = 0.5. The distance between COG of the body and the center : l = 1. The initial conditions : θ = (rad) = 10(deg), & φ = 0. φ The friction coefficients between the body and the wheel : μ = 1, μ = 5, c = 1, c = 10. θ φ θ φ The parameters of the proposed controller : α = 0.1, β = 1, γ = 1, γ = 1, μ = 0, μ = 0, c = 0, c = 0. θ desired = 0, & φ = 0. desired v c θ φ θ φ /30
23 Simulation Results (5/9) 3 S T.5 S TH S PH converge to zero time (sec) Time behavior of the sliding functions ST, STH and SPH for self-balancing with uncertain frictions. 3/30
24 Simulation Results (6/9) angle (rad) theta k v k c time (sec) angle velocity (rad/sec) converge to zero d phi/dt time (sec) time (sec) Simulation results of θ and & Simulation results of kˆ ˆ v and kc for self-balancing φ for self-balancing with uncertain frictions. with uncertain frictions /30
25 Simulation Results (7/9) The second simulation : angle velocity control with uncertain frictions Computer simulation parameters: The weights : M = 98, m =. The moments of inertia : I = , I = θ The half diameter of the wheel : r = 0.5. The distance between COG of the body and the center : l = 1. The initial conditions : θ = (rad) = 10(deg), & φ = 0. φ The friction coefficients between the body and the wheel : μ = 1, μ = 5, c = 1, c = 10. θ φ θ φ The parameters of the proposed controller : α = 0.1, β = 1, γ = 1, γ = 1, μ = 0, μ = 0, c = 0, c = 0. θ desired = 0, & φ = 5. desired v c θ φ θ φ 5/30
26 Simulation Results (8/9) S T S TH S PH Can t converge to zero Time(sec) Time behavior of the sliding functions ST, STH and SPH for angle velocity control with uncertain frictions. 6/30
27 Simulation Results (9/9) theta 4 k v angle(rad) k c time(sec) angle velocity (rad/sec) Steady state error d phi/dt time(sec) time(sec) Simulation results of θ and & φ for angle velocity Simulation results of kˆ and kˆ for angle velocity control with uncertain frictions. control with uncertain frictions. v c 7/30
28 Outline Introduction System Modeling Adaptive Hierarchical Decoupling Sliding-Mode Control Simulation Results Conclusions 8/30
29 Conclusions The adaptive hierarchical decoupling sliding mode controller has been proposed to accomplish robust balancing and angle velocity control (0 rad/sec) of the electric unicycle with neglected all of the friction coefficients. The reason for steady state error in final simulation is that θ is not a steady state. desired =0 an d & φ =5 desired 9/30
30 Thanks for your attention 30/30
Lecture 9 Nonlinear Control Design. Course Outline. Exact linearization: example [one-link robot] Exact Feedback Linearization
Lecture 9 Nonlinear Control Design Course Outline Eact-linearization Lyapunov-based design Lab Adaptive control Sliding modes control Literature: [Khalil, ch.s 13, 14.1,14.] and [Glad-Ljung,ch.17] Lecture
More informationLecture 9 Nonlinear Control Design
Lecture 9 Nonlinear Control Design Exact-linearization Lyapunov-based design Lab 2 Adaptive control Sliding modes control Literature: [Khalil, ch.s 13, 14.1,14.2] and [Glad-Ljung,ch.17] Course Outline
More informationIn the presence of viscous damping, a more generalized form of the Lagrange s equation of motion can be written as
2 MODELING Once the control target is identified, which includes the state variable to be controlled (ex. speed, position, temperature, flow rate, etc), and once the system drives are identified (ex. force,
More informationLagrangian Dynamics: Generalized Coordinates and Forces
Lecture Outline 1 2.003J/1.053J Dynamics and Control I, Spring 2007 Professor Sanjay Sarma 4/2/2007 Lecture 13 Lagrangian Dynamics: Generalized Coordinates and Forces Lecture Outline Solve one problem
More informationMCE 366 System Dynamics, Spring Problem Set 2. Solutions to Set 2
MCE 366 System Dynamics, Spring 2012 Problem Set 2 Reading: Chapter 2, Sections 2.3 and 2.4, Chapter 3, Sections 3.1 and 3.2 Problems: 2.22, 2.24, 2.26, 2.31, 3.4(a, b, d), 3.5 Solutions to Set 2 2.22
More informationMAE 142 Homework #2 (Design Project) SOLUTIONS. (a) The main body s kinematic relationship is: φ θ ψ. + C 3 (ψ) 0 + C 3 (ψ)c 1 (θ)
MAE 42 Homework #2 (Design Project) SOLUTIONS. Top Dynamics (a) The main body s kinematic relationship is: ω b/a ω b/a + ω a /a + ω a /a ψâ 3 + θâ + â 3 ψˆb 3 + θâ + â 3 ψˆb 3 + C 3 (ψ) θâ ψ + C 3 (ψ)c
More informationMechatronic System Case Study: Rotary Inverted Pendulum Dynamic System Investigation
Mechatronic System Case Study: Rotary Inverted Pendulum Dynamic System Investigation Dr. Kevin Craig Greenheck Chair in Engineering Design & Professor of Mechanical Engineering Marquette University K.
More informationRotational Motion. Rotational Motion. Rotational Motion
I. Rotational Kinematics II. Rotational Dynamics (Netwton s Law for Rotation) III. Angular Momentum Conservation 1. Remember how Newton s Laws for translational motion were studied: 1. Kinematics (x =
More informationTwo-Dimensional Rotational Kinematics
Two-Dimensional Rotational Kinematics Rigid Bodies A rigid body is an extended object in which the distance between any two points in the object is constant in time. Springs or human bodies are non-rigid
More informationPhysics 106a, Caltech 4 December, Lecture 18: Examples on Rigid Body Dynamics. Rotating rectangle. Heavy symmetric top
Physics 106a, Caltech 4 December, 2018 Lecture 18: Examples on Rigid Body Dynamics I go through a number of examples illustrating the methods of solving rigid body dynamics. In most cases, the problem
More informationCEE 271: Applied Mechanics II, Dynamics Lecture 27: Ch.18, Sec.1 5
1 / 42 CEE 271: Applied Mechanics II, Dynamics Lecture 27: Ch.18, Sec.1 5 Prof. Albert S. Kim Civil and Environmental Engineering, University of Hawaii at Manoa Tuesday, November 27, 2012 2 / 42 KINETIC
More informationTorque/Rotational Energy Mock Exam. Instructions: (105 points) Answer the following questions. SHOW ALL OF YOUR WORK.
AP Physics C Spring, 2017 Torque/Rotational Energy Mock Exam Name: Answer Key Mr. Leonard Instructions: (105 points) Answer the following questions. SHOW ALL OF YOUR WORK. (22 pts ) 1. Two masses are attached
More informationThe IDA-PBC Methodology Applied to a Gantry Crane
Outline Methodology Applied to a Gantry Crane Ravi Banavar 1 Faruk Kazi 1 Romeo Ortega 2 N. S. Manjarekar 1 1 Systems and Control Engineering IIT Bombay 2 Supelec Gif-sur-Yvette, France MTNS, Kyoto, 2006
More informationNMT EE 589 & UNM ME 482/582 ROBOT ENGINEERING. Dr. Stephen Bruder NMT EE 589 & UNM ME 482/582
NMT EE 589 & UNM ME 482/582 ROBOT ENGINEERING NMT EE 589 & UNM ME 482/582 Simplified drive train model of a robot joint Inertia seen by the motor Link k 1 I I D ( q) k mk 2 kk Gk Torque amplification G
More informationPhys101 Second Major-173 Zero Version Coordinator: Dr. M. Al-Kuhaili Thursday, August 02, 2018 Page: 1. = 159 kw
Coordinator: Dr. M. Al-Kuhaili Thursday, August 2, 218 Page: 1 Q1. A car, of mass 23 kg, reaches a speed of 29. m/s in 6.1 s starting from rest. What is the average power used by the engine during the
More informationN mg N Mg N Figure : Forces acting on particle m and inclined plane M. (b) The equations of motion are obtained by applying the momentum principles to
.004 MDEING DNMIS ND NTR I I Spring 00 Solutions for Problem Set 5 Problem. Particle slides down movable inclined plane. The inclined plane of mass M is constrained to move parallel to the -axis, and the
More informationModeling and Analysis of Dynamic Systems
Modeling and Analysis of Dynamic Systems by Dr. Guillaume Ducard Fall 2016 Institute for Dynamic Systems and Control ETH Zurich, Switzerland 1/21 Outline 1 Lecture 4: Modeling Tools for Mechanical Systems
More information2.003 Engineering Dynamics Problem Set 4 (Solutions)
.003 Engineering Dynamics Problem Set 4 (Solutions) Problem 1: 1. Determine the velocity of point A on the outer rim of the spool at the instant shown when the cable is pulled to the right with a velocity
More informationET3-7: Modelling I(V) Introduction and Objectives. Electrical, Mechanical and Thermal Systems
ET3-7: Modelling I(V) Introduction and Objectives Electrical, Mechanical and Thermal Systems Objectives analyse and model basic linear dynamic systems -Electrical -Mechanical -Thermal Recognise the analogies
More informationWork and kinetic Energy
Work and kinetic Energy Problem 66. M=4.5kg r = 0.05m I = 0.003kgm 2 Q: What is the velocity of mass m after it dropped a distance h? (No friction) h m=0.6kg mg Work and kinetic Energy Problem 66. M=4.5kg
More informationContents. Dynamics and control of mechanical systems. Focus on
Dynamics and control of mechanical systems Date Day 1 (01/08) Day 2 (03/08) Day 3 (05/08) Day 4 (07/08) Day 5 (09/08) Day 6 (11/08) Content Review of the basics of mechanics. Kinematics of rigid bodies
More informationDynamics and control of mechanical systems
Dynamics and control of mechanical systems Date Day 1 (03/05) - 05/05 Day 2 (07/05) Day 3 (09/05) Day 4 (11/05) Day 5 (14/05) Day 6 (16/05) Content Review of the basics of mechanics. Kinematics of rigid
More informationDYNAMICS OF SERIAL ROBOTIC MANIPULATORS
DYNAMICS OF SERIAL ROBOTIC MANIPULATORS NOMENCLATURE AND BASIC DEFINITION We consider here a mechanical system composed of r rigid bodies and denote: M i 6x6 inertia dyads of the ith body. Wi 6 x 6 angular-velocity
More informationPhysics 200a Finals 18 December minutes Formulas and Figures at the end. Do problems in 6 books as indicated. a = 2 g sin θ.
Physics 200a Finals 8 December 2006 80 minutes Formulas and Figures at the end. Do problems in 6 books as indicated. (I) Book A solid cylinder of mass m and radius r rolls (without slipping) down a slope
More informationAssignment 9. to roll without slipping, how large must F be? Ans: F = R d mgsinθ.
Assignment 9 1. A heavy cylindrical container is being rolled up an incline as shown, by applying a force parallel to the incline. The static friction coefficient is µ s. The cylinder has radius R, mass
More informationLagrangian Dynamics: Derivations of Lagrange s Equations
Constraints and Degrees of Freedom 1.003J/1.053J Dynamics and Control I, Spring 007 Professor Thomas Peacock 4/9/007 Lecture 15 Lagrangian Dynamics: Derivations of Lagrange s Equations Constraints and
More informationChapter 12: Rotation of Rigid Bodies. Center of Mass Moment of Inertia Torque Angular Momentum Rolling Statics
Chapter 1: Rotation of Rigid Bodies Center of Mass Moment of Inertia Torque Angular Momentum Rolling Statics Translational vs Rotational / / 1/ m x v dx dt a dv dt F ma p mv KE mv Work Fd P Fv / / 1/ I
More informationM2A2 Problem Sheet 3 - Hamiltonian Mechanics
MA Problem Sheet 3 - Hamiltonian Mechanics. The particle in a cone. A particle slides under gravity, inside a smooth circular cone with a vertical axis, z = k x + y. Write down its Lagrangian in a) Cartesian,
More informationClassical Mechanics Lecture 15
Classical Mechanics Lecture 5 Today s Concepts: a) Parallel Axis Theorem b) Torque & Angular Acceleration Mechanics Lecture 5, Slide Unit 4 Main Points Mechanics Lecture 4, Slide Unit 4 Main Points Mechanics
More information2.003 Engineering Dynamics Problem Set 6 with solution
.00 Engineering Dynamics Problem Set 6 with solution Problem : A slender uniform rod of mass m is attached to a cart of mass m at a frictionless pivot located at point A. The cart is connected to a fixed
More informationPhysics 201. Professor P. Q. Hung. 311B, Physics Building. Physics 201 p. 1/1
Physics 201 p. 1/1 Physics 201 Professor P. Q. Hung 311B, Physics Building Physics 201 p. 2/1 Rotational Kinematics and Energy Rotational Kinetic Energy, Moment of Inertia All elements inside the rigid
More informationChap. 10: Rotational Motion
Chap. 10: Rotational Motion I. Rotational Kinematics II. Rotational Dynamics - Newton s Law for Rotation III. Angular Momentum Conservation (Chap. 10) 1 Newton s Laws for Rotation n e t I 3 rd part [N
More informationSOLUTION di x = y2 dm. rdv. m = a 2 bdx. = 2 3 rpab2. I x = 1 2 rp L0. b 4 a1 - x2 a 2 b. = 4 15 rpab4. Thus, I x = 2 5 mb2. Ans.
17 4. Determine the moment of inertia of the semiellipsoid with respect to the x axis and express the result in terms of the mass m of the semiellipsoid. The material has a constant density r. y x y a
More informationVTU-NPTEL-NMEICT Project
MODULE-II --- SINGLE DOF FREE S VTU-NPTEL-NMEICT Project Progress Report The Project on Development of Remaining Three Quadrants to NPTEL Phase-I under grant in aid NMEICT, MHRD, New Delhi SME Name : Course
More informationLecture 9: Eigenvalues and Eigenvectors in Classical Mechanics (See Section 3.12 in Boas)
Lecture 9: Eigenvalues and Eigenvectors in Classical Mechanics (See Section 3 in Boas) As suggested in Lecture 8 the formalism of eigenvalues/eigenvectors has many applications in physics, especially in
More informationState Space Representation
ME Homework #6 State Space Representation Last Updated September 6 6. From the homework problems on the following pages 5. 5. 5.6 5.7. 5.6 Chapter 5 Homework Problems 5.6. Simulation of Linear and Nonlinear
More informationClassical Mechanics Review (Louisiana State University Qualifier Exam)
Review Louisiana State University Qualifier Exam Jeff Kissel October 22, 2006 A particle of mass m. at rest initially, slides without friction on a wedge of angle θ and and mass M that can move without
More informationPLANAR KINETICS OF A RIGID BODY: WORK AND ENERGY Today s Objectives: Students will be able to: 1. Define the various ways a force and couple do work.
PLANAR KINETICS OF A RIGID BODY: WORK AND ENERGY Today s Objectives: Students will be able to: 1. Define the various ways a force and couple do work. In-Class Activities: 2. Apply the principle of work
More informationModelling and Control of Ball-Plate System
Modelling and Control of Ball-Plate System Final Project Report Mohammad Nokhbeh and Daniel Khashabi Under the supervision of Dr.H.A.Talebi Amirkabir University of Technology, 2011 Abstract Abstract In
More informationCP1 REVISION LECTURE 3 INTRODUCTION TO CLASSICAL MECHANICS. Prof. N. Harnew University of Oxford TT 2017
CP1 REVISION LECTURE 3 INTRODUCTION TO CLASSICAL MECHANICS Prof. N. Harnew University of Oxford TT 2017 1 OUTLINE : CP1 REVISION LECTURE 3 : INTRODUCTION TO CLASSICAL MECHANICS 1. Angular velocity and
More informationKINETIC ENERGY SHAPING IN THE INVERTED PENDULUM
KINETIC ENERGY SHAPING IN THE INVERTED PENDULUM J. Aracil J.A. Acosta F. Gordillo Escuela Superior de Ingenieros Universidad de Sevilla Camino de los Descubrimientos s/n 49 - Sevilla, Spain email:{aracil,
More informationDynamics. 1 Copyright c 2015 Roderic Grupen
Dynamics The branch of physics that treats the action of force on bodies in motion or at rest; kinetics, kinematics, and statics, collectively. Websters dictionary Outline Conservation of Momentum Inertia
More informationAssignments VIII and IX, PHYS 301 (Classical Mechanics) Spring 2014 Due 3/21/14 at start of class
Assignments VIII and IX, PHYS 301 (Classical Mechanics) Spring 2014 Due 3/21/14 at start of class Homeworks VIII and IX both center on Lagrangian mechanics and involve many of the same skills. Therefore,
More informationFinal Examination Thursday May Please initial the statement below to show that you have read it
EN40: Dynamics and Vibrations Final Examination Thursday May 0 010 Division of Engineering rown University NME: General Instructions No collaboration of any kind is permitted on this examination. You may
More informationMultiple Choice -- TEST I
Multiple Choice Test I--Classical Mechanics Multiple Choice -- TEST I 1) The position function for an oscillating body is x = 20 sin (6t - /2) At t = 0, the magnitude of the body's acceleration is: a)
More informationCEE 271: Applied Mechanics II, Dynamics Lecture 9: Ch.13, Sec.4-5
1 / 40 CEE 271: Applied Mechanics II, Dynamics Lecture 9: Ch.13, Sec.4-5 Prof. Albert S. Kim Civil and Environmental Engineering, University of Hawaii at Manoa 2 / 40 EQUATIONS OF MOTION:RECTANGULAR COORDINATES
More information13. Rigid Body Dynamics II
University of Rhode Island DigitalCommons@URI Classical Dynamics Physics Course Materials 2015 13. Rigid Body Dynamics II Gerhard Müller University of Rhode Island, gmuller@uri.edu Creative Commons License
More informationNonholonomic Constraints Examples
Nonholonomic Constraints Examples Basilio Bona DAUIN Politecnico di Torino July 2009 B. Bona (DAUIN) Examples July 2009 1 / 34 Example 1 Given q T = [ x y ] T check that the constraint φ(q) = (2x + siny
More informationQuiz Number 4 PHYSICS April 17, 2009
Instructions Write your name, student ID and name of your TA instructor clearly on all sheets and fill your name and student ID on the bubble sheet. Solve all multiple choice questions. No penalty is given
More informationWebreview Torque and Rotation Practice Test
Please do not write on test. ID A Webreview - 8.2 Torque and Rotation Practice Test Multiple Choice Identify the choice that best completes the statement or answers the question. 1. A 0.30-m-radius automobile
More information4) Vector = and vector = What is vector = +? A) B) C) D) E)
1) Suppose that an object is moving with constant nonzero acceleration. Which of the following is an accurate statement concerning its motion? A) In equal times its speed changes by equal amounts. B) In
More informationPLANAR KINETIC EQUATIONS OF MOTION: TRANSLATION
PLANAR KINETIC EQUATIONS OF MOTION: TRANSLATION Today s Objectives: Students will be able to: 1. Apply the three equations of motion for a rigid body in planar motion. 2. Analyze problems involving translational
More informationMechatronics. MANE 4490 Fall 2002 Assignment # 1
Mechatronics MANE 4490 Fall 2002 Assignment # 1 1. For each of the physical models shown in Figure 1, derive the mathematical model (equation of motion). All displacements are measured from the static
More informationExam 3 Practice Solutions
Exam 3 Practice Solutions Multiple Choice 1. A thin hoop, a solid disk, and a solid sphere, each with the same mass and radius, are at rest at the top of an inclined plane. If all three are released at
More informationCEE 271: Applied Mechanics II, Dynamics Lecture 28: Ch.17, Sec.2 3
1 / 20 CEE 271: Applied Mechanics II, Dynamics Lecture 28: Ch.17, Sec.2 3 Prof. Albert S. Kim Civil and Environmental Engineering, University of Hawaii at Manoa Monday, November 1, 2011 2 / 20 PLANAR KINETIC
More informationReview for 3 rd Midterm
Review for 3 rd Midterm Midterm is on 4/19 at 7:30pm in the same rooms as before You are allowed one double sided sheet of paper with any handwritten notes you like. The moment-of-inertia about the center-of-mass
More informationPhys101 Third Major-161 Zero Version Coordinator: Dr. Ayman S. El-Said Monday, December 19, 2016 Page: 1
Coordinator: Dr. Ayman S. El-Said Monday, December 19, 2016 Page: 1 Q1. A water molecule (H 2O) consists of an oxygen (O) atom of mass 16m and two hydrogen (H) atoms, each of mass m, bound to it (see Figure
More informationarxiv:physics/ v3 [physics.ed-ph] 24 Jun 2003
ERAU-PHY-0201c The driven pendulum at arbitrary drive angles Gordon J. VanDalen Department of Physics, University of California, Riverside, California 92521 and arxiv:physics/0211047v3 [physics.ed-ph]
More informationVariable Structure Control of Pendulum-driven Spherical Mobile Robots
rd International Conerence on Computer and Electrical Engineering (ICCEE ) IPCSIT vol. 5 () () IACSIT Press, Singapore DOI:.776/IPCSIT..V5.No..6 Variable Structure Control o Pendulum-driven Spherical Mobile
More informationSelected Topics in Physics a lecture course for 1st year students by W.B. von Schlippe Spring Semester 2007
Selected Topics in Physics a lecture course for st year students by W.B. von Schlippe Spring Semester 7 Lecture : Oscillations simple harmonic oscillations; coupled oscillations; beats; damped oscillations;
More informationRigid Body Kinetics :: Force/Mass/Acc
Rigid Body Kinetics :: Force/Mass/Acc General Equations of Motion G is the mass center of the body Action Dynamic Response 1 Rigid Body Kinetics :: Force/Mass/Acc Fixed Axis Rotation All points in body
More informationOrdinary Differential Equations
Ordinary Differential Equations In this lecture, we will look at different options for coding simple differential equations. Start by considering bicycle riding as an example. Why does a bicycle move forward?
More informationrad/sec Example 2.13: Find out the equation of motion for the vibratory system shown in fig Sample copy
Natural frequency, ω = rad/sec So, ω = rad/sec Example 2.13: Find out the equation of motion for the vibratory system shown in fig 2.26. Fig 2.26 Solution: The equation of motion can be written as (ka)aθ
More informationName: Fall 2014 CLOSED BOOK
Name: Fall 2014 1. Rod AB with weight W = 40 lb is pinned at A to a vertical axle which rotates with constant angular velocity ω =15 rad/s. The rod position is maintained by a horizontal wire BC. Determine
More informationMath Review Night: Work and the Dot Product
Math Review Night: Work and the Dot Product Dot Product A scalar quantity Magnitude: A B = A B cosθ The dot product can be positive, zero, or negative Two types of projections: the dot product is the parallel
More information2.003 Quiz #1 Review
2.003J Spring 2011: Dynamics and Control I Quiz #1 Review Massachusetts Institute of Technology March 5th, 2011 Department of Mechanical Engineering March 6th, 2011 1 Reference Frames 2.003 Quiz #1 Review
More informationPhysics 2210 Homework 18 Spring 2015
Physics 2210 Homework 18 Spring 2015 Charles Jui April 12, 2015 IE Sphere Incline Wording A solid sphere of uniform density starts from rest and rolls without slipping down an inclined plane with angle
More informationPerformance of Feedback Control Systems
Performance of Feedback Control Systems Design of a PID Controller Transient Response of a Closed Loop System Damping Coefficient, Natural frequency, Settling time and Steady-state Error and Type 0, Type
More informationClassical Mechanics Comprehensive Exam Solution
Classical Mechanics Comprehensive Exam Solution January 31, 011, 1:00 pm 5:pm Solve the following six problems. In the following problems, e x, e y, and e z are unit vectors in the x, y, and z directions,
More informationRigid Manipulator Control
Rigid Manipulator Control The control problem consists in the design of control algorithms for the robot motors, such that the TCP motion follows a specified task in the cartesian space Two types of task
More informationTHE REACTION WHEEL PENDULUM
THE REACTION WHEEL PENDULUM By Ana Navarro Yu-Han Sun Final Report for ECE 486, Control Systems, Fall 2013 TA: Dan Soberal 16 December 2013 Thursday 3-6pm Contents 1. Introduction... 1 1.1 Sensors (Encoders)...
More informationRotational motion problems
Rotational motion problems. (Massive pulley) Masses m and m 2 are connected by a string that runs over a pulley of radius R and moment of inertia I. Find the acceleration of the two masses, as well as
More informationLecture 31. EXAMPLES: EQUATIONS OF MOTION USING NEWTON AND ENERGY APPROACHES
Lecture 31. EXAMPLES: EQUATIONS OF MOTION USING NEWTON AND ENERGY APPROACHES Figure 5.29 (a) Uniform beam moving in frictionless slots and attached to ground via springs at A and B. The vertical force
More informationA Model-Free Control System Based on the Sliding Mode Control Method with Applications to Multi-Input-Multi-Output Systems
Proceedings of the 4 th International Conference of Control, Dynamic Systems, and Robotics (CDSR'17) Toronto, Canada August 21 23, 2017 Paper No. 119 DOI: 10.11159/cdsr17.119 A Model-Free Control System
More informationPhysics 312, Winter 2007, Practice Final
Physics 312, Winter 2007, Practice Final Time: Two hours Answer one of Question 1 or Question 2 plus one of Question 3 or Question 4 plus one of Question 5 or Question 6. Each question carries equal weight.
More informationQ1. For a completely inelastic two-body collision the kinetic energy of the objects after the collision is the same as:
Coordinator: Dr.. Naqvi Monday, January 05, 015 Page: 1 Q1. For a completely inelastic two-body collision the kinetic energy of the objects after the collision is the same as: ) (1/) MV, where M is the
More information1. Which of the following is the unit for angular displacement? A. Meters B. Seconds C. Radians D. Radian per second E. Inches
AP Physics B Practice Questions: Rotational Motion Multiple-Choice Questions 1. Which of the following is the unit for angular displacement? A. Meters B. Seconds C. Radians D. Radian per second E. Inches
More informationEE Homework 3 Due Date: 03 / 30 / Spring 2015
EE 476 - Homework 3 Due Date: 03 / 30 / 2015 Spring 2015 Exercise 1 (10 points). Consider the problem of two pulleys and a mass discussed in class. We solved a version of the problem where the mass was
More informationRobotics & Automation. Lecture 25. Dynamics of Constrained Systems, Dynamic Control. John T. Wen. April 26, 2007
Robotics & Automation Lecture 25 Dynamics of Constrained Systems, Dynamic Control John T. Wen April 26, 2007 Last Time Order N Forward Dynamics (3-sweep algorithm) Factorization perspective: causal-anticausal
More informationd. Determine the power output of the boy required to sustain this velocity.
AP Physics C Dynamics Free Response Problems 1. A 45 kg boy stands on 30 kg platform suspended by a rope passing over a stationary pulley that is free to rotate. The other end of the rope is held by the
More informationThe basic principle to be used in mechanical systems to derive a mathematical model is Newton s law,
Chapter. DYNAMIC MODELING Understanding the nature of the process to be controlled is a central issue for a control engineer. Thus the engineer must construct a model of the process with whatever information
More informationRotational Kinematics and Dynamics. UCVTS AIT Physics
Rotational Kinematics and Dynamics UCVTS AIT Physics Angular Position Axis of rotation is the center of the disc Choose a fixed reference line Point P is at a fixed distance r from the origin Angular Position,
More informationForces of Rolling. 1) Ifobjectisrollingwith a com =0 (i.e.no netforces), then v com =ωr = constant (smooth roll)
Physics 2101 Section 3 March 12 rd : Ch. 10 Announcements: Mid-grades posted in PAW Quiz today I will be at the March APS meeting the week of 15-19 th. Prof. Rich Kurtz will help me. Class Website: http://www.phys.lsu.edu/classes/spring2010/phys2101-3/
More informationPHYSICS 311: Classical Mechanics Final Exam Solution Key (2017)
PHYSICS 311: Classical Mechanics Final Exam Solution Key (017) 1. [5 points] Short Answers (5 points each) (a) In a sentence or two, explain why bicycle wheels are large, with all of the mass at the edge,
More informationPhysics 2210 Fall smartphysics Conservation of Angular Momentum 11/20/2015
Physics 2210 Fall 2015 smartphysics 19-20 Conservation of Angular Momentum 11/20/2015 Poll 11-18-03 In the two cases shown above identical ladders are leaning against frictionless walls and are not sliding.
More informationPage 2. Q1.A satellite X is in a circular orbit of radius r about the centre of a spherical planet of mass
Q1. satellite X is in a circular orbit of radius r about the centre of a spherical planet of mass M. Which line, to, in the table gives correct expressions for the centripetal acceleration a and the speed
More informationSRV02-Series Rotary Experiment # 7. Rotary Inverted Pendulum. Student Handout
SRV02-Series Rotary Experiment # 7 Rotary Inverted Pendulum Student Handout SRV02-Series Rotary Experiment # 7 Rotary Inverted Pendulum Student Handout 1. Objectives The objective in this experiment is
More informationRotational Motion. Every quantity that we have studied with translational motion has a rotational counterpart
Rotational Motion & Angular Momentum Rotational Motion Every quantity that we have studied with translational motion has a rotational counterpart TRANSLATIONAL ROTATIONAL Displacement x Angular Displacement
More information9.3 Worked Examples Circular Motion
9.3 Worked Examples Circular Motion Example 9.1 Geosynchronous Orbit A geostationary satellite goes around the earth once every 3 hours 56 minutes and 4 seconds, (a sidereal day, shorter than the noon-to-noon
More informationb) 2/3 MR 2 c) 3/4MR 2 d) 2/5MR 2
Rotational Motion 1) The diameter of a flywheel increases by 1%. What will be percentage increase in moment of inertia about axis of symmetry a) 2% b) 4% c) 1% d) 0.5% 2) Two rings of the same radius and
More informationChapter 21 Rigid Body Dynamics: Rotation and Translation about a Fixed Axis
Chapter 21 Rigid Body Dynamics: Rotation and Translation about a Fixed Axis Chapter 21 Rigid Body Dynamics: Rotation and Translation about a Fixed Axis... 2 21.1 Introduction... 2 21.2 Translational Equation
More informationIntroduction to Robotics
J. Zhang, L. Einig 277 / 307 MIN Faculty Department of Informatics Lecture 8 Jianwei Zhang, Lasse Einig [zhang, einig]@informatik.uni-hamburg.de University of Hamburg Faculty of Mathematics, Informatics
More informationCEE 271: Applied Mechanics II, Dynamics Lecture 25: Ch.17, Sec.4-5
1 / 36 CEE 271: Applied Mechanics II, Dynamics Lecture 25: Ch.17, Sec.4-5 Prof. Albert S. Kim Civil and Environmental Engineering, University of Hawaii at Manoa Date: 2 / 36 EQUATIONS OF MOTION: ROTATION
More informationRotation. Kinematics Rigid Bodies Kinetic Energy. Torque Rolling. featuring moments of Inertia
Rotation Kinematics Rigid Bodies Kinetic Energy featuring moments of Inertia Torque Rolling Angular Motion We think about rotation in the same basic way we do about linear motion How far does it go? How
More informationChapter 9- Static Equilibrium
Chapter 9- Static Equilibrium Changes in Office-hours The following changes will take place until the end of the semester Office-hours: - Monday, 12:00-13:00h - Wednesday, 14:00-15:00h - Friday, 13:00-14:00h
More informationRotational Dynamics. Slide 2 / 34. Slide 1 / 34. Slide 4 / 34. Slide 3 / 34. Slide 6 / 34. Slide 5 / 34. Moment of Inertia. Parallel Axis Theorem
Slide 1 / 34 Rotational ynamics l Slide 2 / 34 Moment of Inertia To determine the moment of inertia we divide the object into tiny masses of m i a distance r i from the center. is the sum of all the tiny
More informationControl of Mobile Robots
Control of Mobile Robots Regulation and trajectory tracking Prof. Luca Bascetta (luca.bascetta@polimi.it) Politecnico di Milano Dipartimento di Elettronica, Informazione e Bioingegneria Organization and
More informationPHY6426/Fall 07: CLASSICAL MECHANICS HOMEWORK ASSIGNMENT #1 due by 9:35 a.m. Wed 09/05 Instructor: D. L. Maslov Rm.
PHY646/Fall 07: CLASSICAL MECHANICS HOMEWORK ASSIGNMENT # due by 9:35 a.m. Wed 09/05 Instructor: D. L. Maslov maslov@phys.ufl.edu 39-053 Rm. 4 Please help your instructor by doing your work neatly.. Goldstein,
More informationMULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.
Exam Name MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question. 1) Two men, Joel and Jerry, push against a wall. Jerry stops after 10 min, while Joel is
More informationNon-textbook problem #I: Let s start with a schematic side view of the drawbridge and the forces acting on it: F axle θ
PHY 309 K. Solutions for Problem set # 10. Non-textbook problem #I: Let s start with a schematic side view of the drawbridge and the forces acting on it: F axle θ T mg The bridgeis shown just asit begins
More information