Modeling of Rebound Phenomenon of a Rigid Ball with Friction and Elastic Effects

Size: px
Start display at page:

Download "Modeling of Rebound Phenomenon of a Rigid Ball with Friction and Elastic Effects"

Transcription

1 American Control Conference Marriott Waterfront, Baltimore, MD, USA June -Jul, WeB8. Modeling of Reound Phenomenon of a Rigid Ball with Friction and Elastic Effects Akira Nakashima, Yuki Ogawa, Yosuke Koaashi and Yoshikau Haakawa Astract We derive analtical models of the reound phenomenon etween a ping-pong all and the tale/racket ruer. In the reound model of the tale, the determination of the tpe of the contact during the impact is derived as a generalied condition in the -dimensional space. In the model etween the all and racket ruer, it is assumed that the kinetic energ of the tangent velocit is stored as the potential energ due to the elasticit of the ruer. This assumption leads to that the impulse in the horiontal direction is proportional to the tangent velocit. The models are verified eperimental data. I. INTRODUCTION It is a challenging task for a root to pla tale tennis with a human ecause plaing tale tennis is a deterous task for humans. For simplicit, consider the situation of Fig., where a root tries to hit a fling all. The deterous can e implied the strateg of the root plaing tale tennis, which can e decomposed as the following sutasks: ) To detect the states of the fling all with vision sensors; ) To predict the all trajector; ) To determine the trajector of the racket attached to the root for hitting the all to achieve desired trajector. The numer ) means the image processing algorithm to otain the position, the translational and rotational velocities of the all. The numer ) means the prediction of the position and translational/rotational velocities of the all for the net task of the determination. The numer ) means the determination of the trajectories of the position and orientation of the racket attached to the root for the all to follow desired trajector. In the sutasks ) and ), the all reounds from the tale and the racket ruer. It is therefore necessar to model the reound phenomenon etween the all and the tale/ruer in order to achieve the sutasks ) and ). Fig.. A root tries to hit a fling all. Authors are with Mechanical Science and Engineering, Graduate School of Engineering, Nagoa Universit, Furo-cho, Chikusa-ku, Nagoa, Japan akira@haa.nuem.nagoa-u.ac.jp, and Y. Haakawa is also with RIKEN-TRI Collaoration Center, RIKEN, 7-, Anagahora, Shimoshidami, Moriama-ku, Nagoa, Japan. The reound phenomenon etween a all and a surface has een studied man researchers. Garwin [] proposed the coefficient of restitution (COR) in the direction parallel to the surface. He determined from eperimental data which the contact is the rolling, sliding or oth together during the impact and whether the kinetic energ is stored as elastic one or not. Brod [] considered the effect of friction of the surface with the assumption of no compression of the all. He derived the condition of the rolling contact which is related to the translational and rotational velocities just efore the reound. Shiukawa [] derived the condition which determines whether the rolling contact happens or not during the impact. As specified situations of the reound, Cross [4] considered the effect of friction etween the all and strings of a racket in tennis. He also considered other situations, e.g., the horiontal COR etween alls of various properties and a solid surface []. Furthermore, he investigated the ounce of a spinning all eing incident near the normal to the surface as an eample of situations of hitting a all a racket [6]. For the normal COR, Cross [7] investigated the relation etween the normal COR and the dnamics hsteresis of the impact force. From the reviewed studies, the friction and elastic effects are ver important facts in the reound phenomenon. It is here assumed that a tale tennis all does not deform when reounding. The friction effect is dominative in the case of the reound on the tale and determines the tpe of the contact (sliding/rolling) during the impact, while the elastic effect is dominative in the case of the reound on the racket. As mentioned in the aove reviews, these effects are not considered analticall in the reound. The friction effect was considered in onl the -dimensional case in [] and the elastic effect was considered onl eperimentall in the some previous mentioned studies. We derive analtical models of the reound phenomenon etween a ping-pong all and the tale/racket ruer. In the reound model of the tale, the determination of the tpe of the contact during the impact is derived as a generalied condition in the -dimensional space. In the model etween the all and racket ruer, it is assumed that the kinetic energ of the tangent velocit is stored as the potential energ due to the elasticit of the ruer. This assumption leads to that the impulse in the horiontal direction is proportional to the tangent velocit. The models are verified eperimental data. II. EXPERIMENTAL SYSTEM AND BALL DETECTION Fig. shows the eperimental sstem for detecting the //$6. AACC 4

2 Racket Ball Automatical all catapult rotation ω ais v l [i] j p l j [i] Tale (a) p [i] C () r Vision cameras Fig. 4. Image data and calculation of the rotational velocit. Fig.. Eperimental sstem. all states. The tale is an international standard one with the sie of (W) 76(H) 74(D) [mm]. The all is shot out from the automatical all catapult ROBO-PONG 4 (SAN-EI Co.) which is set at the end of the tale. The fling all is measured the high-speed vision sensors with 9 [fps] (Hamamatsu Photonics K.K.). The arra and piel sies per meter are and α u,α v =. [piel/m]. The sampled data are quantied as D image data with the monochrome rightness of 8it ( ). The focal length of the lens is f = [mm] and the chip sie is. 4. [mm]. is the reference frame. The racket is a standard one (Butterfl K.K.) which is fied with respect to and is mounted such that its contact surface is normal to the -ais. The cameras are calirated with respect to. The translational and rotational velocities are calculated as the constant assuming that there is no effect of the air resistance. Figure shows an eample of the image processing. The figure (a) is the image data where the there are the racket and the all with the lack feature points. The figure () is the inaried one with an appropriate threshold. The white circle represents the all. In the figure (c), the green closed line is the oundar of the all. The four ellow points on the oundar of the all are detected the simple scannings as in the figures (c-) (c-4). In the scanning of (c-), the arrows are scanned in turn from the left and top until the rightness of the scanned image is larger than a specified threshold. The scanning of (c-) (c-4) are similar to the scanning of (c-). The positions of the detected data are recorded as ξ i := (u i,v i ) R (i =,,4). Consider the Racket Ball Feature point (a) () (c) (d) () () () ξ4 () (c-) (c-) (c-) (c-4) Fig.. Image data and detection of the center of the all. () ξ ξc ξ (4) () () ξ mediators of the lines etween ξ i+ and ξ i (i =,,4), ξ := ξ as shown in Fig. (d). Define ξ c as the center of the all. The center ξ c is otained the least squares method with the performance function, which is the sum of the squares of the distances of ξ from the mediators. The center of the all p is calculated ξ c in the left and right images [8]. The translational velocities of the all the mean of all the velocities etween the (i + )th and ith position as v = N i= v [i] N, v [i] := p [i + ] p [i], () t where t = /9 [s] is the sampling time and N is the numer of the frames. Note that [i] denotes the ith frame. Net, consider the detection of the rotational velocit of the all. Figure 4 (a) shows the feature points which are marked on the all as the lack prints. This image can e otained the appropriate gra scale transformation, sharpening and inariation. Figure 4 () shows the all in the ith frame, where ω R is the rotation ais, p lj := p lj p and p lj R is the feature point on the all (j =,,N l ). For the jthe feature point, the following rotational relationship holds [9]: p lj [i + ] = e ω t p lj [i], e ω t I + ω t, () where ω R is the skew-smmetric matri which corresponds to the cross product of ω. Note that the terms of the higher order with respect to t are approimated to ecause of the small t. Sustituting the nd eq. into the st eq. of () leads to p lj [i + ] = p lj [i] + t ωp lj [i], where ωp lj [i] is calculated as ωp lj [i] = ω p lj [i] = p lj [i] ω = p lj [i] ω. Then, we get p lj [i]ω = v lj [i],v lj [i] := p l j [i + ] p lj [i]. () t III. MODELING OF REBOUND A. Reound etween the all and tale Figure shows the reound of the all from the tale, where (v,ω ) and (v,ω ) are the translational and rotational velocities of the all just efore and after the reound and is the reference frame with the -ais normal to the tale. The simplest model of the reound phenomenon is descried the equations of v = e tv, v = v 4

3 ω v ω Assumption : The following simple ounce relationship in the direction holds: v v = e t v () Assumption 4: The impulse in the and directions P := [P P ] T R is given Fig.. Ball velocities just efore and after the reound. and v = v, where e t is the coefficient of restitution of the tale in the direction. In this model, it is assumed that there is no friction on the tale. Therefore, the components and of the velocit v do not change. However, since there actuall eists the friction, the velocit v just after the reound changes due to the friction and the rotational velocit ω as shown in Fig. 6. The red and lue circles represent the cases of the top and ack spins respectivel and the all velocities just efore the reound are the same. It is easil confirmed that the velocit v in the case of the ack spin is greater than in the case of the top spin. In addition, the rotational velocit ω also changes due to the friction. In order to predict the all trajector after the reound from the tale, it is necessar to consider the friction. For integrating the effect of the friction in the reound model, it is ver important to consider the tpe of the contact during the impact, i.e., the sliding and rolling contact. This can e determined using the tangent velocit given v T := [v v ] T + ω r = v rω v + rω, (4) where r := [ r] T R is the contact point of the all from its center and r R + is the all radius. For the modeling, we make the following assumptions: Assumption : During the impact of the reound, the tpe of the contact etween the all and tale is a point contact. This means that an moment does not effect on the all during the impact. Assumption : The differences etween the translational and angular momentums efore and after the reound equal the impulses at the reound. Therefore, the impulse of the rotation is given r P, where P R is the impulse in the translational direction. P = λ v T v T, λ µ P, (6) where µ is the dnamical coefficient of friction etween the all and tale. Assumption : The contact velocities v and v just efore and after the reound are in the same direction. That is, the following relation holds: v T = νv T, ν. (7) If ν, λ = µ P. Assumptions 4 and are necessar to epress the sliding and rolling contacts during the impact. Assumption 4 means that the impulse in the and directions is related to the one in the direction as shown in Fig. 7 (a), where the friction force in the and directions is proportional to f with µ and its direction is the opposite of v T. λ in (6) is the magnitude of P and is equal to or smaller than µ P ecause the contact can e changed from sliding to rolling during the impact as shown in Fig. 7 (). Note that the static friction force does not work on the all when the contact is rolling. Assumption means that the tangent velocit v T after the reound does not ecome negative ecause the rolling starts just after v T =. The condition of ν means that the contact is sliding during the impact. From Assumptions,, the following equations hold: Before Reound µf ω f mv mv = P (8) Iω Iω = r P, (9) v v T After Reound µf ω (a) Case where the contact is sliding during the impact f v T v Before Reound f After Reound ω f v ω µf v v T v T = () Case where the contact is changed from sliding to rolling during the impact Fig. 6. Deference of v when! is the top or ack spin. Fig. 7. Sliding and rolling during the impact. 4

4 where m and I = mr are the mass and moment of inertia. Comining () and (8) ields the relation in the direction: P = m( + e t )v. () For deriving the relation in the and directions, the tangent velocit v after the reound is calculated the definition of (4) with (8), (9) and Assumption 4: ( ) v T = λ m + r vt I v T + v T. () The tangent velocit after the reound, v T, has to satisf (7) of Assumption. Sustituting () into (7) ields ν = λ v T ( m + r I ) +. () It is sufficient to check whether ν of () is positive or not when the contact during the impact is supposed to e sliding, that is, λ = µ P. Comining λ = µ P, (), I = mr and () leads to ν s := µ( + e t) v v T, () which is defined as ν in the case of the sliding. It follows that (i) if ν s >, ν = ν s and λ = µ P (the case of the sliding); (ii) if ν s, ν = (the case of the rolling). Let us consider the sliding case of (i). Sustituting (6) with λ = µ P and () into (8) and (9), we get the translational and rotational velocities after the reound, v and ω, as the functions of those efore the reound: v = A v v + B v ω (4) ω = A ω v + B ω ω, () where α αr A v := α,b v := αr e t A ω := α r α r,b ω := α α α := µ( + e t ) v v T. (6) Net consider the rolling case of (ii). From ν = and (), λ is given λ = m v T. (7) B the similar calculation of the case (i) with (7), we get the coefficient matrices of (4) and () as follows: A v :=,B v := r r e t A ω := r r,b ω :=. (8) Reound Fig. 8. t =. t =. t =. t =. t =. t =. t =. t = 4. Reound of the all from the racket ruer. B. Reound etween the all and racket ruer Figure 8 shows an eample of the reound of the all from the racket ruer. The green circles represent the same point on the all. It is confirmed that the rotational velocit aout the ais normal to the image plane changes to the inverse direction after the reound. This implies that the contact velocities etween the all and the ruer efore and after the reound are opposite to each other. This can not e epressed considering onl the friction and is the specific phenomenon in the case of the ruer due to the storage of its elastic energ. In order to achieve desired all trajector after the reound from the racket, it is necessar to consider this phenomenon. Figure 9 (a) shows the reound of the all from the racket ruer, where the meanings of the variales are the same as in Section. with respect to the racket frame attached to the racket as the -ais normal to the surface. In order to epress the effect of the elasticit parallel to the surface, we model the tangent motion of the racket ruer as the motion of the virtual mass m α with the spring k s and the distance s(t) R as shown in Fig. 9 (). Note that m α is the equivalent mass consisting of the mass of the all and the deformed area of the ruer. For the model, we make the following assumptions: Assumption 6: The reound in the direction does not cause an effect in the and directions. Assumption 7: The impulse in the and directions P R is related to the tangent velocit v T v v ω ω (a) Reound etween the all and the ruer Fig. 9. P = k p v T. (9) Racket vt Ball m Racket m α vt () Virtual spring model parallel to the surface The reound etween the all and the ruer. s s 4

5 Assumptions 4 are also assumed to hold here. From Assumption and 6, the equations of (8), (9) and () also hold here. Comining (9), (8), (9) and (), we get the translational and rotational velocities after the reound, (v,ω ), are given the same functional relationships as (4) and () with the coefficient matrices as follows: A v := k pv k pv,b v :=k pv r r e r A ω :=k pω r r,b ω := k pωr k pω r k pv := k p m, k pω := k p I, () where e r is the coefficient of restitution of the ruer. IV. MODEL VERIFICATION The parameters of the all are m =.7 [kg] and r =. [m]. The coefficient of restitution of the tale e t can e calculated as h e t =, () h where h and h are the first and second heights of the dropped all. e t is identified as e t =.9 averaging data points. The dnamical friction coefficient µ is estimated as µ =. measuring the drastic change in the value of the spring alance instrument at the sliding where the weighted all on the tale with the weight.[kg] was pulled. A. The case of the reound on the tale The reound model on the tale is verified the 4 cases of (a) Top spin, () Back spin, (c) Side-top spin and (d) Side-ack spin as illustrated in Fig.. Figure shows the verifications of the cases of the top and ack spins, where the circles and squares represent the top and ack spins. Since the eperimental data of (a) and () is the cases of the pure top spin (ω < ) and pure ack spin (ω > ) with v, ω, ω, (v,v ) [m/s] and Fig.. (a) Top spin () Back spin (c) Side-top spin () Side-ack spin Situations of the verification of the tale v Ep. Value [m/s] Fig v Ep. Value [m/s] ω -4 - Ep. Value [rad/s] Fig ω - Ep. Value [rad/s] Verification of the top and side spins. - v - - Ep. Value [m/s] ω Ep. Value [rad/s] v 4 Ep. Value [m/s] v 4 Ep. Value [m/s] ω - Ep. Value [rad/s] Verification of the side-top and side-ack spins. ω [rad/s] are onl shown. The horiontal and vertical aes are the eperimental values and the calculated values from the model of the translational and rotational velocities after the reound. The solid lines represent the cases where these values are the same. The general situations are represented Fig., which shows the cases with the multi rotational aes where the circles and squares represent the side-top and side-ack spins. Note that the side spin is ω >, the top spin is ω < and the ack spin is ω >. It is confirmed that the almost data in Figs. and are close to the solid lines. It ma e caused the quantiation errors of the image data that a few data is a little far from the solid lines. The image coordinates (u,v) is related to the cartesian ones ( c, c, c ) as u = f c α u c and v = f c α v c, where the parameters f, (α u,α v ) are shown in Section. c =.[m] is in the optic ais and the distance etween the all and the camera. The igger errors of the translational and rotational velocities are aout.[m/s] and [rad/s]. The corresponding distances in ( c, c ) of the errors in a frame are calculated as e v =. t and e ω = r t. From the relationships u = f c α u c and v = f c α v c, the errors in (u,v) are calculated as e v uv =.8 and e ω uv =.64 [piel]. Since e v uv and e ω uv are smaller than [piel], the errors of. [m/s] and [rad/s] ma e caused the quantiation errors. Because all the errors in Figs. and are smaller than these errors, the eperimental data shows the validation 44

6 v 4 v v (a) Top spin Ep. Value [m/s] 4 Ep. Value [m/s] Ep. Value [m/s] () Back spin (c) Side-top spin ( > ) (d) Side-top spin ( < ) v v 6 ω 8 ω 8 ω Fig.. Situations of the verification of the racket. of the reound model on the tale. B. The case of the reound on the racket The reound model on the racket is verified the 4 cases of (a) Top spin, () Back spin, (c) Side-top spin (v > ) and (d) Side-ack spin (v < ) as illustrated in Fig.. The parameters in the reound model are indentified as e r =.8, k p =.9 [/kg]. Figures 4 and show the case of the pure top and ack spins and the case of the sidetop spin of v > and v <. The red data is used for the identification of the parameters and the lue data is used for the verification. The circles and squares represent the top and ack spin in Fig. 4 and the side-top spin of v > and the one of v < in Fig.. It is confirmed that the red and lue data are close to the solid lines with the errors due to the quantiation errors of the image data. Tale I shows some of the eperimental data of the contact velocities efore and after the reound and the ones after the reound which are calculated the model. It is confirmed that the calculated velocities are in the opposite directions of the velocities efore the reound and close to the velocities after the reound. Therefore, the proposed model can represent the specified effect of the ruer. V. CONCLUSIONS We derived analtical models of the reound phenomenon etween a ping-pong all and the tale/racket ruer. In the reound model of the tale, the determination of the tpe of the contact during the impact was derived as a generalied condition in the -dimensional space. In the model etween the all and racket ruer, it was assumed v - Ep. Value [m/s] Fig ω - Ep. Value [rad/s].. v Ep. Value [m/s] Verification of the top spin and ack spin Ep. Value [rad/s] 6 4 Ep. Value [rad/s] 6 4 Ep. Value [rad/s] Fig.. Verification of the side-top spins of v > and v <. TABLE I VERIFICATION OF THE TANGENT VELOCITY No. Before the reound After the reound Calculated Model that the kinetic energ of the tangent velocit was stored as the potential energ due to the elasticit of the ruer. This assumption led to that the impulse in the horiontal direction is proportional to the tangent velocit. The models were verified eperimental data. As future work, it is necessar to reduce the quantiation errors and verif the model in additional reound situations. Furthermore, we would tr to make a method to detect the all state in real-time. REFERENCES [] R. Garwin, Kinematics of an ultraelastic rough all, Am. J. Phs., Vol.7, pp [] H. Brod, That s how the all ounces, Phs. Teach., Vol. pp , 984. [] Kanji Shiukawa, Dnamics of Phsical Eercise, Daishukanshoten, 969 (in japanease). [4] R. Cross, Effects of friction etween the all and strings in tennis, Sports Eng., Vol., pp.8 97,. [] R. Cross, Measurements of the horiontal coefficient of restitution for a superall and a tennis all, Am. J. Phs., Vol.7, No., pp ,. [6] R. Cross, Bounce of a spinning all near normal incidence, Am. J. Phs., Vol.7, No., pp.94 9,. [7] R. Cross, The ounce of a all, Am. J. Phs., Vol.67, No., pp. 7, 999. [8] B. K. Ghosh, N. Xi and T. J. Tarn, Control in Rootics and Automation: Sensor-Based Integration, Academic Press, 999. [9] R. M. Murra, Z. Li and S. S. Sastr, A Mathematical Introduction to ROBOTIC MANIPULATION, CRC Press,

Analysis of Effects of Rebounds and Aerodynamics for Trajectory of Table Tennis Ball

Analysis of Effects of Rebounds and Aerodynamics for Trajectory of Table Tennis Ball SICE Annual Conference 21 August 18-21, 21, The Grand Hotel, Taipei, Taiwan Analsis of Effects of Reounds and Aerodnamics for Trajector of Tale Tennis Junko Nonomura Mechanical Science and Engineering,

More information

Plane Motion of Rigid Bodies: Momentum Methods

Plane Motion of Rigid Bodies: Momentum Methods Plane Motion of Rigid Bodies: Momentum Methods Reference: Beer, Ferdinand P. et al, Vector Mechanics for Engineers : Dynamics, 8 th Edition, Mc GrawHill Hibbeler R.C., Engineering Mechanics: Dynamics,

More information

10. The dimensional formula for c) 6% d) 7%

10. The dimensional formula for c) 6% d) 7% UNIT. One of the combinations from the fundamental phsical constants is hc G. The unit of this epression is a) kg b) m 3 c) s - d) m. If the error in the measurement of radius is %, then the error in the

More information

Chapter 18 KINETICS OF RIGID BODIES IN THREE DIMENSIONS. The two fundamental equations for the motion of a system of particles .

Chapter 18 KINETICS OF RIGID BODIES IN THREE DIMENSIONS. The two fundamental equations for the motion of a system of particles . hapter 18 KINETIS F RIID DIES IN THREE DIMENSINS The to fundamental equations for the motion of a sstem of particles ΣF = ma ΣM = H H provide the foundation for three dimensional analsis, just as the do

More information

INSTRUCTIONS TO CANDIDATES:

INSTRUCTIONS TO CANDIDATES: NATIONAL NIVERSITY OF SINGAPORE FINAL EXAMINATION FOR THE DEGREE OF B.ENG ME 444 - DYNAMICS AND CONTROL OF ROBOTIC SYSTEMS October/November 994 - Time Allowed: 3 Hours INSTRCTIONS TO CANDIDATES:. This

More information

Dynamics and control of mechanical systems

Dynamics and control of mechanical systems JU 18/HL Dnamics and control of mechanical sstems Date Da 1 (3/5) 5/5 Da (7/5) Da 3 (9/5) Da 4 (11/5) Da 5 (14/5) Da 6 (16/5) Content Revie of the basics of mechanics. Kinematics of rigid bodies coordinate

More information

Mechanics II. Which of the following relations among the forces W, k, N, and F must be true?

Mechanics II. Which of the following relations among the forces W, k, N, and F must be true? Mechanics II 1. By applying a force F on a block, a person pulls a block along a rough surface at constant velocity v (see Figure below; directions, but not necessarily magnitudes, are indicated). Which

More information

Circular Motion, Pt 2: Angular Dynamics. Mr. Velazquez AP/Honors Physics

Circular Motion, Pt 2: Angular Dynamics. Mr. Velazquez AP/Honors Physics Circular Motion, Pt 2: Angular Dynamics Mr. Velazquez AP/Honors Physics Formulas: Angular Kinematics (θ must be in radians): s = rθ Arc Length 360 = 2π rads = 1 rev ω = θ t = v t r Angular Velocity α av

More information

Solution: (a) (b) (N) F X =0: A X =0 (N) F Y =0: A Y + B Y (54)(9.81) 36(9.81)=0

Solution: (a) (b) (N) F X =0: A X =0 (N) F Y =0: A Y + B Y (54)(9.81) 36(9.81)=0 Prolem 5.6 The masses of the person and the diving oard are 54 kg and 36 kg, respectivel. ssume that the are in equilirium. (a) Draw the free-od diagram of the diving oard. () Determine the reactions at

More information

Solution 11. Kinetics of rigid body(newton s Second Law)

Solution 11. Kinetics of rigid body(newton s Second Law) Solution () urpose and Requirement Solution Kinetics of rigid bod(newton s Second Law) In rob, kinematics stud regarding acceleration of mass center should be done before Newton s second law is used to

More information

Mechanics Departmental Exam Last updated November 2013

Mechanics Departmental Exam Last updated November 2013 Mechanics Departmental Eam Last updated November 213 1. Two satellites are moving about each other in circular orbits under the influence of their mutual gravitational attractions. The satellites have

More information

A Position-Based Visual Impedance Control for Robot Manipulators

A Position-Based Visual Impedance Control for Robot Manipulators 2007 IEEE International Conference on Robotics and Automation Roma, Ital, 10-14 April 2007 ThB21 A Position-Based Visual Impedance Control for Robot Manipulators Vinceno Lippiello, Bruno Siciliano, and

More information

KINEMATIC RELATIONS IN DEFORMATION OF SOLIDS

KINEMATIC RELATIONS IN DEFORMATION OF SOLIDS Chapter 8 KINEMATIC RELATIONS IN DEFORMATION OF SOLIDS Figure 8.1: 195 196 CHAPTER 8. KINEMATIC RELATIONS IN DEFORMATION OF SOLIDS 8.1 Motivation In Chapter 3, the conservation of linear momentum for a

More information

Gravitational potential energy

Gravitational potential energy Gravitational potential energ m1 Consider a rigid bod of arbitrar shape. We want to obtain a value for its gravitational potential energ. O r1 1 x The gravitational potential energ of an assembl of N point-like

More information

Name (please print): UW ID# score last first

Name (please print): UW ID# score last first Name (please print): UW ID# score last first Question I. (20 pts) Projectile motion A ball of mass 0.3 kg is thrown at an angle of 30 o above the horizontal. Ignore air resistance. It hits the ground 100

More information

Number Plane Graphs and Coordinate Geometry

Number Plane Graphs and Coordinate Geometry Numer Plane Graphs and Coordinate Geometr Now this is m kind of paraola! Chapter Contents :0 The paraola PS, PS, PS Investigation: The graphs of paraolas :0 Paraolas of the form = a + + c PS Fun Spot:

More information

we make slices perpendicular to the x-axis. If the slices are thin enough, they resemble x cylinders or discs. The formula for the x

we make slices perpendicular to the x-axis. If the slices are thin enough, they resemble x cylinders or discs. The formula for the x Math Learning Centre Solids of Revolution When we rotate a curve around a defined ais, the -D shape created is called a solid of revolution. In the same wa that we can find the area under a curve calculating

More information

is acting on a body of mass m = 3.0 kg and changes its velocity from an initial

is acting on a body of mass m = 3.0 kg and changes its velocity from an initial PHYS 101 second major Exam Term 102 (Zero Version) Q1. A 15.0-kg block is pulled over a rough, horizontal surface by a constant force of 70.0 N acting at an angle of 20.0 above the horizontal. The block

More information

5. Nonholonomic constraint Mechanics of Manipulation

5. Nonholonomic constraint Mechanics of Manipulation 5. Nonholonomic constraint Mechanics of Manipulation Matt Mason matt.mason@cs.cmu.edu http://www.cs.cmu.edu/~mason Carnegie Mellon Lecture 5. Mechanics of Manipulation p.1 Lecture 5. Nonholonomic constraint.

More information

Chapter 8. Rotational Motion

Chapter 8. Rotational Motion Chapter 8 Rotational Motion Rotational Work and Energy W = Fs = s = rθ Frθ Consider the work done in rotating a wheel with a tangential force, F, by an angle θ. τ = Fr W =τθ Rotational Work and Energy

More information

2007 Problem Topic Comment 1 Kinematics Position-time equation Kinematics 7 2 Kinematics Velocity-time graph Dynamics 6 3 Kinematics Average velocity

2007 Problem Topic Comment 1 Kinematics Position-time equation Kinematics 7 2 Kinematics Velocity-time graph Dynamics 6 3 Kinematics Average velocity 2007 Problem Topic Comment 1 Kinematics Position-time equation Kinematics 7 2 Kinematics Velocity-time graph Dynamics 6 3 Kinematics Average velocity Energy 7 4 Kinematics Free fall Collisions 3 5 Dynamics

More information

Angular velocity and angular acceleration CHAPTER 9 ROTATION. Angular velocity and angular acceleration. ! equations of rotational motion

Angular velocity and angular acceleration CHAPTER 9 ROTATION. Angular velocity and angular acceleration. ! equations of rotational motion Angular velocity and angular acceleration CHAPTER 9 ROTATION! r i ds i dθ θ i Angular velocity and angular acceleration! equations of rotational motion Torque and Moment of Inertia! Newton s nd Law for

More information

On my honor, I have neither given nor received unauthorized aid on this examination.

On my honor, I have neither given nor received unauthorized aid on this examination. Instructor(s): Profs. D. Reitze, H. Chan PHYSICS DEPARTMENT PHY 2053 Exam 2 April 2, 2009 Name (print, last first): Signature: On my honor, I have neither given nor received unauthorized aid on this examination.

More information

MMJ1153 COMPUTATIONAL METHOD IN SOLID MECHANICS PRELIMINARIES TO FEM

MMJ1153 COMPUTATIONAL METHOD IN SOLID MECHANICS PRELIMINARIES TO FEM B Course Content: A INTRODUCTION AND OVERVIEW Numerical method and Computer-Aided Engineering; Phsical problems; Mathematical models; Finite element method;. B Elements and nodes, natural coordinates,

More information

Unless otherwise specified, use g = 9.80 m/s2

Unless otherwise specified, use g = 9.80 m/s2 Phy 111 Exam 2 March 10, 2015 Name Section University ID Please fill in your computer answer sheet as follows: 1) In the NAME grid, fill in your last name, leave one blank space, then your first name.

More information

5/2/2015 7:42 AM. Chapter 17. Plane Motion of Rigid Bodies: Energy and Momentum Methods. Mohammad Suliman Abuhaiba, Ph.D., PE

5/2/2015 7:42 AM. Chapter 17. Plane Motion of Rigid Bodies: Energy and Momentum Methods. Mohammad Suliman Abuhaiba, Ph.D., PE 5//05 7:4 AM Chapter 7 Plane Motion of Rigid Bodies: Energy and Momentum Methods 5//05 7:4 AM Chapter Outline Principle of Work and Energy for a Rigid Body Work of Forces Acting on a Rigid Body Kinetic

More information

Rolling, Torque & Angular Momentum

Rolling, Torque & Angular Momentum PHYS 101 Previous Exam Problems CHAPTER 11 Rolling, Torque & Angular Momentum Rolling motion Torque Angular momentum Conservation of angular momentum 1. A uniform hoop (ring) is rolling smoothly from the

More information

Final Exam. June 10, 2008, 1:00pm

Final Exam. June 10, 2008, 1:00pm PHYSICS 101: Fundamentals of Physics Final Exam Final Exam Name TA/ Section # June 10, 2008, 1:00pm Recitation Time You have 2 hour to complete the exam. Please answer all questions clearly and completely,

More information

Physics 201. Professor P. Q. Hung. 311B, Physics Building. Physics 201 p. 1/1

Physics 201. Professor P. Q. Hung. 311B, Physics Building. Physics 201 p. 1/1 Physics 201 p. 1/1 Physics 201 Professor P. Q. Hung 311B, Physics Building Physics 201 p. 2/1 Rotational Kinematics and Energy Rotational Kinetic Energy, Moment of Inertia All elements inside the rigid

More information

6-1. Conservation law of mechanical energy

6-1. Conservation law of mechanical energy 6-1. Conservation law of mechanical energy 1. Purpose Investigate the mechanical energy conservation law and energy loss, by studying the kinetic and rotational energy of a marble wheel that is moving

More information

Exam II. Spring 2004 Serway & Jewett, Chapters Fill in the bubble for the correct answer on the answer sheet. next to the number.

Exam II. Spring 2004 Serway & Jewett, Chapters Fill in the bubble for the correct answer on the answer sheet. next to the number. Agin/Meyer PART I: QUALITATIVE Exam II Spring 2004 Serway & Jewett, Chapters 6-10 Assigned Seat Number Fill in the bubble for the correct answer on the answer sheet. next to the number. NO PARTIAL CREDIT:

More information

Second-Order Linear Differential Equations C 2

Second-Order Linear Differential Equations C 2 C8 APPENDIX C Additional Topics in Differential Equations APPENDIX C. Second-Order Homogeneous Linear Equations Second-Order Linear Differential Equations Higher-Order Linear Differential Equations Application

More information

( ) ( ) A i ˆj. What is the unit vector  that points in the direction of A? 1) The vector A is given by = ( 6.0m ) ˆ ( 8.0m ) Solution A D) 6 E) 6

( ) ( ) A i ˆj. What is the unit vector  that points in the direction of A? 1) The vector A is given by = ( 6.0m ) ˆ ( 8.0m ) Solution A D) 6 E) 6 A i ˆj. What is the unit vector  that points in the direction of A? 1) The vector A is given b ( 6.m ) ˆ ( 8.m ) A ˆ i ˆ ˆ j A ˆ i ˆ ˆ j C) A ˆ ( 1 ) ( i ˆ ˆ j) D) Aˆ.6 iˆ+.8 ˆj E) Aˆ.6 iˆ.8 ˆj A) (.6m

More information

King Fahd University of Petroleum and Minerals Physics Department Physics 101 Recitation Term 131 Fall 013 Quiz # 4 Section 10 A 1.50-kg block slides down a frictionless 30.0 incline, starting from rest.

More information

PLANAR KINETIC EQUATIONS OF MOTION (Section 17.2)

PLANAR KINETIC EQUATIONS OF MOTION (Section 17.2) PLANAR KINETIC EQUATIONS OF MOTION (Section 17.2) We will limit our study of planar kinetics to rigid bodies that are symmetric with respect to a fixed reference plane. As discussed in Chapter 16, when

More information

Simultaneous Orthogonal Rotations Angle

Simultaneous Orthogonal Rotations Angle ELEKTROTEHNIŠKI VESTNIK 8(1-2): -11, 2011 ENGLISH EDITION Simultaneous Orthogonal Rotations Angle Sašo Tomažič 1, Sara Stančin 2 Facult of Electrical Engineering, Universit of Ljubljana 1 E-mail: saso.tomaic@fe.uni-lj.si

More information

Additional Topics in Differential Equations

Additional Topics in Differential Equations 6 Additional Topics in Differential Equations 6. Eact First-Order Equations 6. Second-Order Homogeneous Linear Equations 6.3 Second-Order Nonhomogeneous Linear Equations 6.4 Series Solutions of Differential

More information

Problem 3 Solution Page 1. 1A. Assuming as outlined in the text that the orbit is circular, and relating the radial acceleration

Problem 3 Solution Page 1. 1A. Assuming as outlined in the text that the orbit is circular, and relating the radial acceleration Prolem 3 Solution Page Solution A. Assug as outlined in the text that the orit is circular, and relating the radial acceleration V GM S to the graitational field (where MS is the solar mass we otain Jupiter's

More information

Ch. 2 The Laws of Motion

Ch. 2 The Laws of Motion Ch. 2 The Laws of Motion Lesson 1 Gravity and Friction Force - A push or pull we pull on a locker handle push a soccer ball or on the computer keys Contact force - push or pull on one object by another

More information

DYNAMICS VECTOR MECHANICS FOR ENGINEERS: Plane Motion of Rigid Bodies: Energy and Momentum Methods. Seventh Edition CHAPTER

DYNAMICS VECTOR MECHANICS FOR ENGINEERS: Plane Motion of Rigid Bodies: Energy and Momentum Methods. Seventh Edition CHAPTER CHAPTER 7 VECTOR MECHANICS FOR ENGINEERS: DYNAMICS Ferdinand P. Beer E. Russell Johnston, Jr. Lecture Notes: J. Walt Oler Texas Tech University Plane Motion of Rigid Bodies: Energy and Momentum Methods

More information

Graphs and polynomials

Graphs and polynomials 1 1A The inomial theorem 1B Polnomials 1C Division of polnomials 1D Linear graphs 1E Quadratic graphs 1F Cuic graphs 1G Quartic graphs Graphs and polnomials AreAS of STud Graphs of polnomial functions

More information

Forces of Rolling. 1) Ifobjectisrollingwith a com =0 (i.e.no netforces), then v com =ωr = constant (smooth roll)

Forces of Rolling. 1) Ifobjectisrollingwith a com =0 (i.e.no netforces), then v com =ωr = constant (smooth roll) Physics 2101 Section 3 March 12 rd : Ch. 10 Announcements: Mid-grades posted in PAW Quiz today I will be at the March APS meeting the week of 15-19 th. Prof. Rich Kurtz will help me. Class Website: http://www.phys.lsu.edu/classes/spring2010/phys2101-3/

More information

EF 151 Final Exam, Fall, 2011 Page 1 of 11

EF 151 Final Exam, Fall, 2011 Page 1 of 11 EF 5 Final Exam, Fall, 0 Page of Instructions Do not open or turn over the exam until instructed to do so. Name, and section will be written on the st page of the exam after time starts. Do not leave your

More information

Physics UCSB TR 2:00-3:15 lecture Final Exam Wednesday 3/17/2010

Physics UCSB TR 2:00-3:15 lecture Final Exam Wednesday 3/17/2010 Physics @ UCSB TR :00-3:5 lecture Final Eam Wednesday 3/7/00 Print your last name: Print your first name: Print your perm no.: INSTRUCTIONS: DO NOT START THE EXAM until you are given instructions to do

More information

Translational vs Rotational. m x. Connection Δ = = = = = = Δ = = = = = = Δ =Δ = = = = = 2 / 1/2. Work

Translational vs Rotational. m x. Connection Δ = = = = = = Δ = = = = = = Δ =Δ = = = = = 2 / 1/2. Work Translational vs Rotational / / 1/ Δ m x v dx dt a dv dt F ma p mv KE mv Work Fd / / 1/ θ ω θ α ω τ α ω ω τθ Δ I d dt d dt I L I KE I Work / θ ω α τ Δ Δ c t s r v r a v r a r Fr L pr Connection Translational

More information

= o + t = ot + ½ t 2 = o + 2

= o + t = ot + ½ t 2 = o + 2 Chapters 8-9 Rotational Kinematics and Dynamics Rotational motion Rotational motion refers to the motion of an object or system that spins about an axis. The axis of rotation is the line about which the

More information

Transformation of kinematical quantities from rotating into static coordinate system

Transformation of kinematical quantities from rotating into static coordinate system Transformation of kinematical quantities from rotating into static coordinate sstem Dimitar G Stoanov Facult of Engineering and Pedagog in Sliven, Technical Universit of Sofia 59, Bourgasko Shaussee Blvd,

More information

Date Period Name. Write the term that correctly completes the statement. Use each term once. elastic collision

Date Period Name. Write the term that correctly completes the statement. Use each term once. elastic collision Date Period Name CHAPTER 11 Conservation of Energy Vocabulary Review Write the term that correctly completes the statement. Use each term once. elastic collision law of conservation of energy elastic potential

More information

CH. 1 FUNDAMENTAL PRINCIPLES OF MECHANICS

CH. 1 FUNDAMENTAL PRINCIPLES OF MECHANICS 446.201 (Solid echanics) Professor Youn, eng Dong CH. 1 FUNDENTL PRINCIPLES OF ECHNICS Ch. 1 Fundamental Principles of echanics 1 / 14 446.201 (Solid echanics) Professor Youn, eng Dong 1.2 Generalied Procedure

More information

Optimal Motion Planning for Free-Flying Robots

Optimal Motion Planning for Free-Flying Robots Optimal Motion Planning for Free-Fling Robots R. Lampariello, S. Agrawal, G. Hiringer Institute of Robotics and Mechatronics Department of Mechanical Engineering German Aerospace Center (DLR) Universit

More information

Cartesian coordinates in space (Sect. 12.1).

Cartesian coordinates in space (Sect. 12.1). Cartesian coordinates in space (Sect..). Overview of Multivariable Calculus. Cartesian coordinates in space. Right-handed, left-handed Cartesian coordinates. Distance formula between two points in space.

More information

SOLUTION. will destroy the integrity of the work and Anis not permitted

SOLUTION. will destroy the integrity of the work and Anis not permitted 15 42. The block has a mass of 50 kg and rests on the surface of the cart having a mass of 75 kg. If the spring which is attached to the cart and not the block is compressed 0.2 m and the system is released

More information

Handout 7: Torque, angular momentum, rotational kinetic energy and rolling motion. Torque and angular momentum

Handout 7: Torque, angular momentum, rotational kinetic energy and rolling motion. Torque and angular momentum Handout 7: Torque, angular momentum, rotational kinetic energy and rolling motion Torque and angular momentum In Figure, in order to turn a rod about a fixed hinge at one end, a force F is applied at a

More information

Three-dimensional free vibration analysis of functionally graded rectangular plates using the B-spline Ritz method

Three-dimensional free vibration analysis of functionally graded rectangular plates using the B-spline Ritz method The 01 World Congress on Advances in Civil, Environmental, and Materials Research (ACEM 1) Seoul, Korea, August 6-30, 01 Three-dimensional free viration analsis of functionall graded rectangular plates

More information

11. (7 points: Choose up to 3 answers) What is the tension,!, in the string? a.! = 0.10 N b.! = 0.21 N c.! = 0.29 N d.! = N e.! = 0.

11. (7 points: Choose up to 3 answers) What is the tension,!, in the string? a.! = 0.10 N b.! = 0.21 N c.! = 0.29 N d.! = N e.! = 0. A harmonic wave propagates horizontally along a taut string of length! = 8.0 m and mass! = 0.23 kg. The vertical displacement of the string along its length is given by!!,! = 0.1!m cos 1.5!!! +!0.8!!,

More information

PARAMETER IDENTIFICATION, MODELING, AND SIMULATION OF A CART AND PENDULUM

PARAMETER IDENTIFICATION, MODELING, AND SIMULATION OF A CART AND PENDULUM PARAMETER IDENTIFICATION, MODELING, AND SIMULATION OF A CART AND PENDULUM Erin Bender Mechanical Engineering Erin.N.Bender@Rose-Hulman.edu ABSTRACT In this paper a freely rotating pendulum suspended from

More information

Polynomial Degree and Finite Differences

Polynomial Degree and Finite Differences CONDENSED LESSON 7.1 Polynomial Degree and Finite Differences In this lesson, you Learn the terminology associated with polynomials Use the finite differences method to determine the degree of a polynomial

More information

PHYSICS 221, FALL 2010 EXAM #1 Solutions WEDNESDAY, SEPTEMBER 29, 2010

PHYSICS 221, FALL 2010 EXAM #1 Solutions WEDNESDAY, SEPTEMBER 29, 2010 PHYSICS 1, FALL 010 EXAM 1 Solutions WEDNESDAY, SEPTEMBER 9, 010 Note: The unit vectors in the +x, +y, and +z directions of a right-handed Cartesian coordinate system are î, ĵ, and ˆk, respectively. In

More information

THE KINETICS OF PHASE TRANSITIONS: I. THE ROLE OF HETEROGENEITY. F. Paladi* and V. Gamurari

THE KINETICS OF PHASE TRANSITIONS: I. THE ROLE OF HETEROGENEITY. F. Paladi* and V. Gamurari THE KINETICS OF PHASE TRANSITIONS: I. THE ROLE OF HETEROGENEITY F. Paladi* and V. Gamurari Department of Theoretical Phsics Moldova State Universit 60 A. Mateevici str. MD-009 Chisinau Repulic of Moldova

More information

We define angular displacement, θ, and angular velocity, ω. What's a radian?

We define angular displacement, θ, and angular velocity, ω. What's a radian? We define angular displacement, θ, and angular velocity, ω Units: θ = rad ω = rad/s What's a radian? Radian is the ratio between the length of an arc and its radius note: counterclockwise is + clockwise

More information

UNIVERSITY OF SASKATCHEWAN Department of Physics and Engineering Physics

UNIVERSITY OF SASKATCHEWAN Department of Physics and Engineering Physics UNIVERSITY OF SASKATCHEWAN Department of Physics and Engineering Physics Physics 111.6 MIDTERM TEST #2 November 15, 2001 Time: 90 minutes NAME: STUDENT NO.: (Last) Please Print (Given) LECTURE SECTION

More information

Solution Only gravity is doing work. Since gravity is a conservative force mechanical energy is conserved:

Solution Only gravity is doing work. Since gravity is a conservative force mechanical energy is conserved: 8) roller coaster starts with a speed of 8.0 m/s at a point 45 m above the bottom of a dip (see figure). Neglecting friction, what will be the speed of the roller coaster at the top of the next slope,

More information

16. Rotational Dynamics

16. Rotational Dynamics 6. Rotational Dynamics A Overview In this unit we will address examples that combine both translational and rotational motion. We will find that we will need both Newton s second law and the rotational

More information

Graphs and polynomials

Graphs and polynomials 5_6_56_MQVMM - _t Page Frida, Novemer 8, 5 :5 AM MQ Maths Methods / Final Pages / 8//5 Graphs and polnomials VCEcoverage Areas of stud Units & Functions and graphs Algera In this chapter A The inomial

More information

Magnetic field generated by current filaments

Magnetic field generated by current filaments Journal of Phsics: Conference Series OPEN ACCESS Magnetic fiel generate b current filaments To cite this article: Y Kimura 2014 J. Phs.: Conf. Ser. 544 012004 View the article online for upates an enhancements.

More information

STRAND F: ALGEBRA. UNIT F4 Solving Quadratic Equations: Text * * Contents. Section. F4.1 Factorisation. F4.2 Using the Formula

STRAND F: ALGEBRA. UNIT F4 Solving Quadratic Equations: Text * * Contents. Section. F4.1 Factorisation. F4.2 Using the Formula UNIT F4 Solving Quadratic Equations: Tet STRAND F: ALGEBRA Unit F4 Solving Quadratic Equations Tet Contents * * Section F4. Factorisation F4. Using the Formula F4. Completing the Square UNIT F4 Solving

More information

I xx + I yy + I zz = (y 2 + z 2 )dm + (x 2 + y 2 )dm. (x 2 + z 2 )dm + (x 2 + y 2 + z 2 )dm = 2

I xx + I yy + I zz = (y 2 + z 2 )dm + (x 2 + y 2 )dm. (x 2 + z 2 )dm + (x 2 + y 2 + z 2 )dm = 2 9196_1_s1_p095-0987 6/8/09 1:09 PM Page 95 010 Pearson Education, Inc., Upper Saddle River, NJ. ll rights reserved. This material is protected under all copright laws as the currentl 1 1. Show that the

More information

Review before final exam. Guide how to identify type of the problem

Review before final exam. Guide how to identify type of the problem Review before final eam. Guide how to identif tpe of the problem Guide how to identif tpe of the problem The question is about? sas average acceleration or if the acceleration is constant a=dv/dt ma be

More information

Your Name: PHYSICS 101 MIDTERM. Please circle your section 1 9 am Galbiati 2 10 am Kwon 3 11 am McDonald 4 12:30 pm McDonald 5 12:30 pm Kwon

Your Name: PHYSICS 101 MIDTERM. Please circle your section 1 9 am Galbiati 2 10 am Kwon 3 11 am McDonald 4 12:30 pm McDonald 5 12:30 pm Kwon 1 Your Name: PHYSICS 101 MIDTERM October 26, 2006 2 hours Please circle your section 1 9 am Galbiati 2 10 am Kwon 3 11 am McDonald 4 12:30 pm McDonald 5 12:30 pm Kwon Problem Score 1 /13 2 /20 3 /20 4

More information

Chapter 8- Rotational Kinematics Angular Variables Kinematic Equations

Chapter 8- Rotational Kinematics Angular Variables Kinematic Equations Chapter 8- Rotational Kinematics Angular Variables Kinematic Equations Chapter 9- Rotational Dynamics Torque Center of Gravity Newton s 2 nd Law- Angular Rotational Work & Energy Angular Momentum Angular

More information

Infinitesimal Rotations

Infinitesimal Rotations Universit of Connecticut DigitalCommons@UConn Chemistr Education Materials Department of Chemistr Januar 007 Infinitesimal Rotations Carl W. David Universit of Connecticut, Carl.David@uconn.edu Follow

More information

Part Two: Earlier Material

Part Two: Earlier Material Part Two: Earlier Material Problem 1: (Momentum and Impulse) A superball of m 1 = 0.08kg, starting at rest, is dropped from a height falls h 0 = 3.0m above the ground and bounces back up to a height of

More information

Exam II Difficult Problems

Exam II Difficult Problems Exam II Difficult Problems Exam II Difficult Problems 90 80 70 60 50 40 30 20 10 0 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 Two boxes are connected to each other as shown. The system is released

More information

Distance travelled time taken and if the particle is a distance s(t) along the x-axis, then its instantaneous speed is:

Distance travelled time taken and if the particle is a distance s(t) along the x-axis, then its instantaneous speed is: Chapter 1 Kinematics 1.1 Basic ideas r(t) is the position of a particle; r = r is the distance to the origin. If r = x i + y j + z k = (x, y, z), then r = r = x 2 + y 2 + z 2. v(t) is the velocity; v =

More information

Q2. A machine carries a 4.0 kg package from an initial position of d ˆ. = (2.0 m)j at t = 0 to a final position of d ˆ ˆ

Q2. A machine carries a 4.0 kg package from an initial position of d ˆ. = (2.0 m)j at t = 0 to a final position of d ˆ ˆ Coordinator: Dr. S. Kunwar Monday, March 25, 2019 Page: 1 Q1. An object moves in a horizontal circle at constant speed. The work done by the centripetal force is zero because: A) the centripetal force

More information

FALL TERM EXAM, PHYS 1211, INTRODUCTORY PHYSICS I Thursday, 11 December 2014, 6 PM to 9 PM, Field House Gym

FALL TERM EXAM, PHYS 1211, INTRODUCTORY PHYSICS I Thursday, 11 December 2014, 6 PM to 9 PM, Field House Gym FALL TERM EXAM, PHYS 1211, INTRODUCTORY PHYSICS I Thursday, 11 December 2014, 6 PM to 9 PM, Field House Gym NAME: STUDENT ID: INSTRUCTION 1. This exam booklet has 13 pages. Make sure none are missing 2.

More information

Lab 9 - Rotational Dynamics

Lab 9 - Rotational Dynamics 145 Name Date Partners Lab 9 - Rotational Dynamics OBJECTIVES To study angular motion including angular velocity and angular acceleration. To relate rotational inertia to angular motion. To determine kinetic

More information

Review questions. Before the collision, 70 kg ball is stationary. Afterward, the 30 kg ball is stationary and 70 kg ball is moving to the right.

Review questions. Before the collision, 70 kg ball is stationary. Afterward, the 30 kg ball is stationary and 70 kg ball is moving to the right. Review questions Before the collision, 70 kg ball is stationary. Afterward, the 30 kg ball is stationary and 70 kg ball is moving to the right. 30 kg 70 kg v (a) Is this collision elastic? (b) Find the

More information

Lecture 13 REVIEW. Physics 106 Spring What should we know? What should we know? Newton s Laws

Lecture 13 REVIEW. Physics 106 Spring What should we know? What should we know? Newton s Laws Lecture 13 REVIEW Physics 106 Spring 2006 http://web.njit.edu/~sirenko/ What should we know? Vectors addition, subtraction, scalar and vector multiplication Trigonometric functions sinθ, cos θ, tan θ,

More information

Exact Free Vibration of Webs Moving Axially at High Speed

Exact Free Vibration of Webs Moving Axially at High Speed Eact Free Viration of Wes Moving Aially at High Speed S. HATAMI *, M. AZHARI, MM. SAADATPOUR, P. MEMARZADEH *Department of Engineering, Yasouj University, Yasouj Department of Civil Engineering, Isfahan

More information

3. Kinetics of Particles

3. Kinetics of Particles 3. Kinetics of Particles 3.1 Force, Mass and Acceleration 3.3 Impulse and Momentum 3.4 Impact 1 3.1 Force, Mass and Acceleration We draw two important conclusions from the results of the experiments. First,

More information

Survey of Wave Types and Characteristics

Survey of Wave Types and Characteristics Seminar: Vibrations and Structure-Borne Sound in Civil Engineering Theor and Applications Surve of Wave Tpes and Characteristics Xiuu Gao April 1 st, 2006 Abstract Mechanical waves are waves which propagate

More information

Quiz Samples for Chapter 7 Kinetic Energy and Work

Quiz Samples for Chapter 7 Kinetic Energy and Work Name: Department: Student ID #: Notice ˆ + ( 1) points per correct (incorrect) answer ˆ No penalty for an unanswered question ˆ Fill the lank ( ) with ( ) if the statement is correct (incorrect) ˆ : corrections

More information

THE DIRIHLET PROBLEM FOR THE FRACTIONAL POISSON S EQUATION WITH CAPUTO DERIVATIVES A Finite Difference Approximation and a Numerical Solution

THE DIRIHLET PROBLEM FOR THE FRACTIONAL POISSON S EQUATION WITH CAPUTO DERIVATIVES A Finite Difference Approximation and a Numerical Solution Beialaev, V. B., et al: The Dirihlet Prolem for the Fractional Poisson's Equation... THERMAL SIENE: Year, Vol. 6, No., pp. 385-394 385 THE DIRIHLET PROBLEM FOR THE FRATIONAL POISSON S EQUATION WITH APUTO

More information

Chapter 9. Rotational Dynamics

Chapter 9. Rotational Dynamics Chapter 9 Rotational Dynamics In pure translational motion, all points on an object travel on parallel paths. The most general motion is a combination of translation and rotation. 1) Torque Produces angular

More information

LAB 05 Projectile Motion

LAB 05 Projectile Motion LAB 5 Projectile Motion CONTENT: 1. Introduction. Projectile motion A. Setup B. Various characteristics 3. Pre-lab: A. Activities B. Preliminar info C. Quiz 1. Introduction After introducing one-dimensional

More information

ON THE INTERPRETATION OF THE LAGRANGE MULTIPLIERS IN THE CONSTRAINT FORMULATION OF CONTACT PROBLEMS; OR WHY ARE SOME MULTIPLIERS ALWAYS ZERO?

ON THE INTERPRETATION OF THE LAGRANGE MULTIPLIERS IN THE CONSTRAINT FORMULATION OF CONTACT PROBLEMS; OR WHY ARE SOME MULTIPLIERS ALWAYS ZERO? Proceedings of the ASME 214 International Design Engineering Technical Conferences & Computers and Information in Engineering Conference IDETC/CIE 214 August 17-2, 214, Buffalo, New York, USA DETC214-3479

More information

Physics Final Exam Formulas

Physics Final Exam Formulas INSTRUCTIONS: Write your NAME on the front of the blue exam booklet. The exam is closed book, and you may have only pens/pencils and a calculator (no stored equations or programs and no graphing). Show

More information

Chapters 10 & 11: Rotational Dynamics Thursday March 8 th

Chapters 10 & 11: Rotational Dynamics Thursday March 8 th Chapters 10 & 11: Rotational Dynamics Thursday March 8 th Review of rotational kinematics equations Review and more on rotational inertia Rolling motion as rotation and translation Rotational kinetic energy

More information

Elementary Mechanics Using Matlab

Elementary Mechanics Using Matlab Anders Malthe-S0renssen Elementary Mechanics Using Matlab A Modern Course Combining Analytical and Numerical Techniques ^ Springer Contents 1 Introduction 1 1.1 Physics 1 1.2 Mechanics 2 1.3 Integrating

More information

PHYSICS PART II SECTION- I. Straight objective Type

PHYSICS PART II SECTION- I. Straight objective Type PHYSICS PAT II SECTION- I Straight objective Tpe This section contains 9 multiple choice questions numbered to 1. Each question has choices,, (C) and, out of which ONLY ONE is correct.. A parallel plate

More information

Review of Linear Momentum And Rotational Motion

Review of Linear Momentum And Rotational Motion Physics 7B-1 (C/D) Professor Cebra (Guest Lecturer) Winter 2010 Lecture 7 Review of Linear Momentum And Rotational Motion Slide 1 of 36 Slides 3-19 were discussed in the 7:30 Lecture Slides 6-27 were discussed

More information

= y(x, t) =A cos (!t + kx)

= y(x, t) =A cos (!t + kx) A harmonic wave propagates horizontally along a taut string of length L = 8.0 m and mass M = 0.23 kg. The vertical displacement of the string along its length is given by y(x, t) = 0. m cos(.5 t + 0.8

More information

Strain Transformation and Rosette Gage Theory

Strain Transformation and Rosette Gage Theory Strain Transformation and Rosette Gage Theor It is often desired to measure the full state of strain on the surface of a part, that is to measure not onl the two etensional strains, and, but also the shear

More information

Phys101 Second Major-173 Zero Version Coordinator: Dr. M. Al-Kuhaili Thursday, August 02, 2018 Page: 1. = 159 kw

Phys101 Second Major-173 Zero Version Coordinator: Dr. M. Al-Kuhaili Thursday, August 02, 2018 Page: 1. = 159 kw Coordinator: Dr. M. Al-Kuhaili Thursday, August 2, 218 Page: 1 Q1. A car, of mass 23 kg, reaches a speed of 29. m/s in 6.1 s starting from rest. What is the average power used by the engine during the

More information

STRAND: ALGEBRA Unit 2 Solving Quadratic Equations

STRAND: ALGEBRA Unit 2 Solving Quadratic Equations CMM Suject Support Strand: ALGEBRA Unit Solving Quadratic Equations: Tet STRAND: ALGEBRA Unit Solving Quadratic Equations TEXT Contents Section. Factorisation. Using the Formula. Completing the Square

More information

nm nm

nm nm The Quantum Mechanical Model of the Atom You have seen how Bohr s model of the atom eplains the emission spectrum of hdrogen. The emission spectra of other atoms, however, posed a problem. A mercur atom,

More information

particle p = m v F ext = d P = M d v cm dt

particle p = m v F ext = d P = M d v cm dt Lecture 11: Momentum and Collisions; Introduction to Rotation 1 REVIEW: (Chapter 8) LINEAR MOMENTUM and COLLISIONS The first new physical quantity introduced in Chapter 8 is Linear Momentum Linear Momentum

More information

LATERAL BUCKLING ANALYSIS OF ANGLED FRAMES WITH THIN-WALLED I-BEAMS

LATERAL BUCKLING ANALYSIS OF ANGLED FRAMES WITH THIN-WALLED I-BEAMS Journal of arine Science and J.-D. Technolog, Yau: ateral Vol. Buckling 17, No. Analsis 1, pp. 9-33 of Angled (009) Frames with Thin-Walled I-Beams 9 ATERA BUCKING ANAYSIS OF ANGED FRAES WITH THIN-WAED

More information

AE/ME 339. K. M. Isaac Professor of Aerospace Engineering. December 21, 2001 topic13_grid_generation 1

AE/ME 339. K. M. Isaac Professor of Aerospace Engineering. December 21, 2001 topic13_grid_generation 1 AE/ME 339 Professor of Aerospace Engineering December 21, 2001 topic13_grid_generation 1 The basic idea behind grid generation is the creation of the transformation laws between the phsical space and the

More information