# Hydrostatic. Pressure distribution in a static fluid and its effects on solid surfaces and on floating and submerged bodies.

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1 Hydrostatic Pressure distribution in a static fluid and its effects on solid surfaces and on floating and submerged bodies. M. Bahrami ENSC 283 Spring

2 Fluid at rest hydrostatic condition: when a fluid velocity is zero, the pressure variation is due only to the weight of the fluid. There is no pressure change in the horizontal direction. There is a pressure change in the vertical direction proportional to the density, gravity, and depth change. In the limit when the wedge shrinks to a point, M. Bahrami ENSC 283 Spring

3 Pressure forces (pressure gradient) Assume the pressure vary arbitrarily in a fluid, p=p(x,y,z,t). The pressure gradient is a surface force that acts on the sides of the element. Note that the pressure gradient (not pressure) causes a net force that must be balanced by gravity or acceleration. M. Bahrami ENSC 283 Spring

4 Equilibrium The pressure gradient must be balanced by gravity force, or weight of the element, for a fluid at rest. The gravity force is a body force, acting on the entire mass of the element. Magnetic force is another example of body force. M. Bahrami ENSC 283 Spring

5 Gage pressure and vacuum The actual pressure at a given position is called the absolute pressure, and it is measured relative to absolute vacuum. P P gage P vac P abs P atm Absolute (vacuum) = 0 M. Bahrami ENSC 283 Spring

6 Hydrostatic pressure distribution For a fluid at rest, pressure gradient must be balanced by the gravity force Recall: p is perpendicular everywhere to surface of constant pressure p. In our customary coordinate z is upward and the gravity vector is: where g = m/s 2. The pressure gradient vector becomes: M. Bahrami ENSC 283 Spring

7 Hydrostatic pressure distribution Pressure in a continuously distributed uniform static fluid varies only with vertical distance and is independent of the shape of the container. The pressure is the same at all points on a given horizontal plane in a fluid. For liquids, which are incompressible, we have: The quantity, p γ is a length called the pressure head of the fluid. M. Bahrami ENSC 283 Spring

8 The mercury barometer P atm = 761 mmhg Mercury has an extremely small vapor pressure at roomtemperature (almost vacuum), thus p 1 = 0. One can write: M. Bahrami ENSC 283 Spring

9 Hydrostatic pressure in gases Gases are compressible, using the ideal gas equation of state, p=ρrt: For small variations in elevation, isothermal atmosphere can be assumed: In general (for higher altitudes) the atmospheric temperature drops off linearly with z T T 0 Bz where T 0 is the sea level temperature (in Kelvin) and B= K/m. Note that the P atm is nearly zero (vacuum condition) at z = 30 km. M. Bahrami ENSC 283 Spring

10 Manometry A static column of one or multiple fluids can be used to measure pressure difference between 2 points. Such a device is called manometer. Adding/ subtracting γ zas moving down/up in a fluid column. Jumping across U tubes: any two points at the same elevation in a continuous mass of the same static fluid will be at the same pressure. M. Bahrami ENSC 283 Spring

11 Hydrostatic forces on surfaces Consider a plane panel of arbitrary shape completely submerged in a liquid. The total hydrostatic force on one side of the plane is given by: M. Bahrami ENSC 283 Spring

12 Hydrostatic forces on surfaces After integration and simplifications, we find: The force on one side of any plane submerged surface in a uniform fluid equals the pressure at the plate centroid times the plate area, independent of the shape of the plate or angle θ. The resultant force acts not through the centroid but below it toward the high pressure side. Its line of action passes through the centre of pressure CP of the plate (x CP, y CP ). M. Bahrami ENSC 283 Spring

13 Hydrostatic forces on surfaces Centroidal moments of inertia for various cross sections. Note: for symmetrical plates, I xy = 0 and thus x CP = 0. As a result, the center of pressure lies directly below the centroid on the y axis. M. Bahrami ENSC 283 Spring

14 Hydrostatic forces: curved surfaces The easiest way to calculate the pressure forces on a curved surface is to compute the horizontal and vertical forces separately. The horizontal force equals the force on the plane area formed by the projection of the curved surface onto a vertical plane normal to the component. The vertical component equals to the weight of the entire column of fluid, both liquid and atmospheric above the curved surface. F V = W 2 + W 1 + W air M. Bahrami ENSC 283 Spring

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2013 PhysicsBowl Solutions # Ans # Ans # Ans # Ans # Ans 1 C 11 E 21 E 31 D 41 A 2 B 12 C 22 B 32 E 42 C 3 D 13 E 23 D 33 A 43 A 4 E 14 B 24 B 34 A 44 E 5 A 15 D 25 A 35 C 45 C 6 C 16 D 26 B 36 C 46 E