Physics 107 HOMEWORK ASSIGNMENT #9
|
|
- Lora Cunningham
- 5 years ago
- Views:
Transcription
1 Physics 07 HOMEORK ASSIGNMENT #9 Cutnell & Johnson, 7 th edition Chapter : Problems 6, 8, 33, 40, 44 *6 A 58-kg skier is going down a slope oriented 35 above the horizontal. The area of each ski in contact with the snow is 0.3 m. Determine the pressure that each ski exerts on the snow. *8 Two identical containers are open at the top and are connected at the bottom via a tube of negligible volume and a valve that is closed. Both containers are filled initially to the same height of.00 m, one with water, the other with mercury, as the drawing indicates. The valve is then opened. ater and mercury are immiscible. Determine the fluid level in the left container when equilibrium is reestablished. 33 Interactive Solution.33 presents a model for solving this problem. Multiple-Concept Example 8 also presents an approach to problems of this kind. The hydraulic oil in a car lift has a density of 830 kg/m 3. The weight of the input piston is negligible. The radii of the input piston and output plunger are and 0.5 m, respectively. hat input force F is needed to support the N combined weight of a car and the output plunger, when (a) the bottom surfaces of the piston and plunger are at the same level, and (b) the bottom surface of the output plunger is.30 m above that of the input piston? 40 The density of ice is 97 kg/m 3, and the density of sea water is 05 kg/m 3. A swimming polar bear climbs onto a piece of floating ice that has a volume of 5. m 3. hat is the weight of the heaviest bear that the ice can support without sinking completely beneath the water? 44 An object is solid throughout. hen the object is completely submerged in ethyl alcohol, its apparent weight is 5. N. hen completely submerged in water, its apparent weight is 3.7 N. hat is the volume of the object?
2 6. REASONING Pressure is defined in Equation.3 as the magnitude of the force acting perpendicular to a surface divided by the area over which the force acts. The force acting perpendicular to the slope is due to the component of the skier s weight that is directed perpendicular to the slope. In the drawing at the right, this component is labeled perpendicular. Note that the fact that the skier is moving is of no importance. perpendicular SOLUTION perpendicular e assume that each ski bears the same amount of force, namely (see the drawing). According to Equation.3, the pressure that each ski applies to the snow is P perpendicular A where A is the area of each ski in contact with the snow. From the drawing, we see that perpendicular cos 35, so that the pressure exerted by each ski on the snow is 58 kg 9.80 m/s cos 35 perpendicular cos35 3 P.8 0 Pa A A 0.3 m where we have used the fact that mg (Equation 4.5). 8. REASONING AND SOLUTION The mercury, being more dense, will flow from the right container into the left container until the pressure is equalized. Then the pressure at the bottom of the left container will be P ρ w gh w + ρ m gh ml and the pressure at the bottom of the right container will be P ρ m gh mr. Equating gives Both liquids are incompressible and immiscible so ρ w gh w + ρ m g(h ml h mr ) 0 () h w.00 m and h ml + h mr.00 m Using these in () and solving for h ml gives, h ml (/)(.00 ρ w /ρ m ) 0.46 m. So the fluid level in the left container is.00 m m.46 m from the bottom.
3 33. REASONING e label the input piston as and the output plunger as. hen the bottom surfaces of the input piston and output plunger are at the same level, Equation.5, F F A / A, applies. However, this equation is not applicable when the bottom surface of the output plunger is h.50 m above the input piston. In this case we must use Equation.4, P P + ρgh, to account for the difference in heights. In either case, we will see that the input force is less than the combined weight of the output plunger and car. SOLUTION a. Using A π r for the circular areas of the piston and plunger, the input force required to support the N weight is 3 ( m) A π F F ( N) 93.0 N A π ( 0.5 m) (.5) b. The pressure P at the input piston is related to the pressure P at the bottom of the output plunger by Equation.4, P P + ρgh, where h is the difference in heights. Setting ( P ) F / A F / π r, ( P ) F / π r, and solving for F, we have F F gh r π r + ρ π r ( N) π π ( π ) 3 ( m) ( 0.5 m) 3 3 π kg/m 9.80 m/s.30 m m 94.9 N (.4) 40. REASONING The ice with the bear on it is floating, so that the upward-acting buoyant force balances the downward-acting weight ice of the ice and weight bear of the bear. The magnitude F B of the buoyant force is the weight of the displaced water, according to Archimedes principle. Thus, we have F +, the expression with which B ice bear we will obtain bear. e can express each of the weights and ice as mass times the magnitude of the acceleration due to gravity (Equation 4.5) and then relate the mass to the density and the displaced volume by using Equation..
4 SOLUTION Since the ice with the bear on it is floating, the upward-acting buoyant force F B balances the downward-acting weight ice of the ice and the weight bear of the bear. The buoyant force has a magnitude that equals the weight stated by Archimedes principle. Thus, we have B ice bear bear ice of the displaced water, as F + or () In Equation (), we can use Equation 4.5 to express the weights and ice as mass m times the magnitude g of the acceleration due to gravity. Then, the each mass can be expressed as m ρv (Equation.). ith these substitutions, Equation () becomes ( ρ ) m g m g ( ρ V ) g V g () bear ice ice ice hen the heaviest possible bear is on the ice, the ice is just below the water surface and displaces a volume of water that is V V. Substituting this result into Equation (), we find that ( ρ V ) g ρ V g ( ρ ρ ) V g bear ice ice ice ice ice kg/m 97 kg/m 5. m 9.80 m/s 5500 N ice 44. REASONING hen an object is completely submerged within a fluid, its apparent weight in the fluid is equal to its true weight mg minus the upward-acting buoyant force. According to Archimedes principle, the magnitude of the buoyant force is equal to the weight of the fluid displaced by the object. The weight of the displaced fluid depends on the volume of the object. e will apply this principle twice, once for the object submerged in each fluid, to find the volume of the object. SOLUTION The apparent weights of the object in ethyl alcohol and in water are: Ethyl alcohol 5. N mg ρ gv alcohol eight in True Magnitude of alcohol weight buoyant force () ater 3.7 N mg ρ gv water eight True Magnitude of in water weight buoyant force () These equations contain two unknowns, the volume V of the object and its mass m. By subtracting Equation () from Equation (), we can eliminate the mass algebraically. The result is
5 5. N 3.7 N gv ρ ρ water alcohol Solving this equation for the volume, and using the densities from Table., we have V 5. N 3.7 N.5 N m g ρ ( water ρalcohol ) ( 9.80 m/s )(.00 0 kg/m 806 kg/m ) 4 3
Chapter 15: Fluid Mechanics Dynamics Using Pascal s Law = F 1 = F 2 2 = F 2 A 2
Lecture 24: Archimedes Principle and Bernoulli s Law 1 Chapter 15: Fluid Mechanics Dynamics Using Pascal s Law Example 15.1 The hydraulic lift A hydraulic lift consists of a small diameter piston of radius
More informationm V DEFINITION OF MASS DENSITY The mass density of a substance is the mass of a substance divided by its volume: SI Unit of Mass Density: kg/m 3
Chapter 11 Fluids 11.1 Mass Density DEFINITION OF MASS DENSITY The mass density of a substance is the mass of a substance divided by its volume: ρ m V SI Unit of Mass Density: kg/m 3 11.1 Mass Density
More informationChapter 11. Fluids. continued
Chapter 11 Fluids continued 11.2 Pressure Pressure is the amount of force acting on an area: Example 2 The Force on a Swimmer P = F A SI unit: N/m 2 (1 Pa = 1 N/m 2 ) Suppose the pressure acting on the
More informationChapter 10. Solids & Liquids
Chapter 10 Solids & Liquids Next 6 chapters use all the concepts developed in the first 9 chapters, recasting them into a form ready to apply to specific physical systems. 10.1 Phases of Matter, Mass Density
More informationCh. 11: Some problems on density, pressure, etc.
Q3 A pirate in a movie is carrying a chest (0.30 m 0.30 m 0.20 m) that is supposed to be filled with gold. To see how ridiculous this is, determine the mass (in kg) of the gold. Q15 A solid concrete block
More informationChapter 9: Solids and Fluids
Chapter 9: Solids and Fluids State of matters: Solid, Liquid, Gas and Plasma. Solids Has definite volume and shape Can be crystalline or amorphous Molecules are held in specific locations by electrical
More informationSOLUTION According to Equation 11.3, pressure is defined as P= F/ A; therefore, the magnitude of the force on the lid due to the air pressure is
PHYS 3 Fall 07 Week Recitation: Chapter :, 7, 40, 44, 64, 69.. ssm An airtight box has a remoable lid of area.3 0 m and negligible weight. The box is taken up a mountain where the air pressure outside
More informationChapter 12. Fluid Mechanics. A. The density ρ of a substance of uniform composition is defined as its mass M divided by its volume V.
Chapter 12 Fluid Mechanics 12.1 Density A. The density ρ of a substance of uniform composition is defined as its mass M divided by its volume V. That is,! = M V The density of water at 4 o C is 1000 kg/m
More informationChapter 15. m. The symbolic equation for mass density is: ρ= m V. Table of Densities
Chapter 15 Density Often you will hear that fiberglass is used for racecars because it is lighter than steel. This is only true if we build two identical bodies, one made with steel and one with fiberglass.
More informationChapter 14. Lecture 1 Fluid Mechanics. Dr. Armen Kocharian
Chapter 14 Lecture 1 Fluid Mechanics Dr. Armen Kocharian States of Matter Solid Has a definite volume and shape Liquid Has a definite volume but not a definite shape Gas unconfined Has neither a definite
More informationhapter 13 Archimedes Up-thrust
hapter 13 Archimedes Up-thrust In science, buoyancy is an upward force exerted by a fluid that opposes the weight of an immersed object. The buoyant force is also called Archimedes Up-thrust force. Proof
More informationChapter 14 - Fluids. -Archimedes, On Floating Bodies. David J. Starling Penn State Hazleton PHYS 213. Chapter 14 - Fluids. Objectives (Ch 14)
Any solid lighter than a fluid will, if placed in the fluid, be so far immersed that the weight of the solid will be equal to the weight of the fluid displaced. -Archimedes, On Floating Bodies David J.
More informationstorage tank, or the hull of a ship at rest, is subjected to fluid pressure distributed over its surface.
Hydrostatic Forces on Submerged Plane Surfaces Hydrostatic forces mean forces exerted by fluid at rest. - A plate exposed to a liquid, such as a gate valve in a dam, the wall of a liquid storage tank,
More informationPHYSICS HYDROSTATICS FORM 5
Pressure Pressure is defined as force per unit area. Pressure = Force Area Pressure = Newton (metre) 2 1 Pa = 1N/m 2 Which of the following exerts a greater pressure? A woman of mass 70kg stepping on your
More informationNicholas J. Giordano. Chapter 10 Fluids
Nicholas J. Giordano www.cengage.com/physics/giordano Chapter 10 Fluids Fluids A fluid may be either a liquid or a gas Some characteristics of a fluid Flows from one place to another Shape varies according
More informationChapter 15 - Fluid Mechanics Thursday, March 24 th
Chapter 15 - Fluid Mechanics Thursday, March 24 th Fluids Static properties Density and pressure Hydrostatic equilibrium Archimedes principle and buoyancy Fluid Motion The continuity equation Bernoulli
More informationPhy 212: General Physics II. Daniel Bernoulli ( )
Phy 1: General Physics II Chapter 14: Fluids Lecture Notes Daniel Bernoulli (1700-178) Swiss merchant, doctor & mathematician Worked on: Vibrating strings Ocean tides Kinetic theory Demonstrated that as
More informationPhysics - Fluids. Read Page 174 (Density) TQ1. A fluid is what type of matter? TQ2. What is fluid mechanics? TQ3. What is the equation for density?
Homework Procedure: Read pages specified in Honors Physics Essentials by Dan Fullerton. Questions labeled TQ will be questions about the text you read. These TQ s can be answered in one word, one phrase,
More information11.1 Mass Density. Fluids are materials that can flow, and they include both gases and liquids. The mass density of a liquid or gas is an
Chapter 11 Fluids 11.1 Mass Density Fluids are materials that can flow, and they include both gases and liquids. The mass density of a liquid or gas is an important factor that determines its behavior
More informationLiquids CHAPTER 13 FLUIDS FLUIDS. Gases. Density! Bulk modulus! Compressibility. To begin with... some important definitions...
CHAPTER 13 FLUIDS FLUIDS Liquids Gases Density! Bulk modulus! Compressibility Pressure in a fluid! Hydraulic lift! Hydrostatic paradox Measurement of pressure! Manometers and barometers Buoyancy and Archimedes
More informationCHAPTER 13. Liquids FLUIDS FLUIDS. Gases. Density! Bulk modulus! Compressibility. To begin with... some important definitions...
CHAPTER 13 FLUIDS Density! Bulk modulus! Compressibility Pressure in a fluid! Hydraulic lift! Hydrostatic paradox Measurement of pressure! Manometers and barometers Buoyancy and Archimedes Principle! Upthrust!
More informationTOPICS. Density. Pressure. Variation of Pressure with Depth. Pressure Measurements. Buoyant Forces-Archimedes Principle
Lecture 6 Fluids TOPICS Density Pressure Variation of Pressure with Depth Pressure Measurements Buoyant Forces-Archimedes Principle Surface Tension ( External source ) Viscosity ( External source ) Equation
More information! =!"#$% exerted by a fluid (liquid or gas) !"#$ =!"# FUNDAMENTAL AND MEASURABLE INTENSIVE PROPERTIES PRESSURE, TEMPERATURE AND SPECIFIC VOLUME
FUNDAMENTAL AND MEASURABLE INTENSIVE PROPERTIES PRESSURE, TEMPERATURE AND SPECIFIC VOLUME PRESSURE, P! =!"#$%!"#! exerted by a fluid (liquid or gas) Thermodynamic importance of pressure One of two independent
More information11/4/2003 PHY Lecture 16 1
Announcements 1. Exams will be returned at the end of class. You may rework the exam for up to 1 extra credit points. Turn in your old exam and your new work (clearly indicated). Due 11/11/3. You may sign
More informationPHYSICS 220 Lecture 16 Fluids Textbook Sections
PHYSICS 220 Lecture 16 Fluids Textbook Sections 10.1-10.4 Lecture 16 Purdue University, Physics 220 1 States of Matter Fluids Solid Hold Volume Hold Shape Liquid Hold Volume Adapt Shape Gas Adapt Volume
More informationStevens High School AP Physics II Work for Not-school
1. (AP SAMPLE QUESTION) An ideal fluid is flowing with a speed of 12 cm/s through a pipe of diameter 5 cm. The pipe splits into three smaller pipes, each with a diameter of 2 cm. What is the speed of the
More informationCHAPTER 10- GRAVITATION
CHAPTER 10- GRAVITATION KEY CONCEPTS [ *rating as per the significance of concept] 1 Gravitation *** 2 Universal Law Of Gravitation **** 3 Free Fall ** 4 To Calculate The Value Of G **** 5 Mass & Weight
More informationHalliday/Resnick/Walker 7e Chapter 14
HRW 7e Chapter 4 Page of 8 Halliday/Resnick/Walker 7e Chapter 4. The air inside pushes outard ith a force given by p i A, here p i is the pressure inside the room and A is the area of the indo. Similarly,
More informationCHAPTER 28 PRESSURE IN FLUIDS
CHAPTER 8 PRESSURE IN FLUIDS EXERCISE 18, Page 81 1. A force of 80 N is applied to a piston of a hydraulic system of cross-sectional area 0.010 m. Determine the pressure produced by the piston in the hydraulic
More informationChapter 14. Fluid Mechanics
Chapter 14 Fluid Mechanics States of Matter Solid Has a definite volume and shape Liquid Has a definite volume but not a definite shape Gas unconfined Has neither a definite volume nor shape All of these
More informationρ mixture = m mixture /V = (SG antifreeze ρ water V antifreeze + SG water ρ water V water )/V, so we get
CHAPTER 10 1. When we use the density of granite, we have m = ρv = (.7 10 3 kg/m 3 )(1 10 8 m 3 ) =.7 10 11 kg.. When we use the density of air, we have m = ρv = ρlwh = (1.9 kg/m 3 )(5.8 m)(3.8 m)(.8 m)
More informationTypes of Forces. Pressure Buoyant Force Friction Normal Force
Types of Forces Pressure Buoyant Force Friction Normal Force Pressure Ratio of Force Per Unit Area p = F A P = N/m 2 = 1 pascal (very small) P= lbs/in 2 = psi = pounds per square inch Example: Snow Shoes
More informationm V DEFINITION OF MASS DENSITY The mass density of a substance is the mass of a substance divided by its volume: SI Unit of Mass Density: kg/m 3
Chapter Fluids . Mass Density DEFINITION OF MASS DENSITY The mass density of a substance is the mass of a substance divided by its volume: m V SI Unit of Mass Density: kg/m 3 . Mass Density . Mass Density
More informationChapter 15: Fluids. Mass Density = Volume. note : Fluids: substances which flow
Fluids: substances which flow Chapter 5: Fluids Liquids: take the shape of their container but have a definite volume Gases: take the shape and volume of their container Density m ρ = V Mass Density =
More informationChapter 9 Solids and Fluids. Elasticity Archimedes Principle Bernoulli s Equation
Chapter 9 Solids and Fluids Elasticity Archimedes Principle Bernoulli s Equation States of Matter Solid Liquid Gas Plasmas Solids: Stress and Strain Stress = Measure of force felt by material Stress= Force
More informationStatic Forces on Surfaces-Buoyancy. Fluid Mechanics. There are two cases: Case I: if the fluid is above the curved surface:
Force on a Curved Surface due to Hydrostatic Pressure If the surface is curved, the forces on each element of the surface will not be parallel (normal to the surface at each point) and must be combined
More informationEQUILIBRIUM OBJECTIVES PRE-LECTURE
27 FE3 EQUILIBRIUM Aims OBJECTIVES In this chapter you will learn the concepts and principles needed to understand mechanical equilibrium. You should be able to demonstrate your understanding by analysing
More informationPhysics 106 Lecture 13. Fluid Mechanics
Physics 106 Lecture 13 Fluid Mechanics SJ 7 th Ed.: Chap 14.1 to 14.5 What is a fluid? Pressure Pressure varies with depth Pascal s principle Methods for measuring pressure Buoyant forces Archimedes principle
More information43. A person sits on a freely spinning lab stool that has no friction in its axle. When this person extends her arms,
43. A person sits on a freely spinning lab stool that has no friction in its axle. When this person extends her arms, A) her moment of inertia increases and her rotational kinetic energy remains the same.
More informationPressure in a fluid P P P P
Fluids Gases (compressible) and liquids (incompressible) density of gases can change dramatically, while that of liquids much less so Gels, colloids, liquid crystals are all odd-ball states of matter We
More informationWRITE ALL YOUR CALCULATIONS IN THE BLUEBOOK PUT YOUR NAME AND THE TEST IN THE BLUEBOOK AND HAND IN
Physics 6B - MWF - Midterm 1 Test #: A Name: Perm #: Section (10-11 or 12-1): You MUST put the TEST # in the first answer bubble. The TA will explain. YOU MUST do this or the test will not be graded. WRITE
More informationEric G. Paterson. Spring 2005
Eric G. Paterson Department of Mechanical and Nuclear Engineering Pennsylvania State University Spring 2005 Reading and Homework Read Chapter 3. Homework Set #2 has been posted. Due date: Friday 21 January.
More informationPhysics 201 Chapter 13 Lecture 1
Physics 201 Chapter 13 Lecture 1 Fluid Statics Pascal s Principle Archimedes Principle (Buoyancy) Fluid Dynamics Continuity Equation Bernoulli Equation 11/30/2009 Physics 201, UW-Madison 1 Fluids Density
More informationMomentum Circular Motion and Gravitation Rotational Motion Fluid Mechanics
Momentum Circular Motion and Gravitation Rotational Motion Fluid Mechanics Momentum Momentum Collisions between objects can be evaluated using the laws of conservation of energy and of momentum. Momentum
More informationStates of matter. Density high > high >> low (pressure dependent)
Fluids States of matter Solids Fluids crystalline amorphous liquids gasses Inter-atomic forces strong > strong >> very weak Density high > high >> low (pressure dependent) Density is an important material
More informationME 262 BASIC FLUID MECHANICS Assistant Professor Neslihan Semerci Lecture 4. (Buoyancy and Viscosity of water)
ME 262 BASIC FLUID MECHANICS Assistant Professor Neslihan Semerci Lecture 4 (Buoyancy and Viscosity of water) 16. BUOYANCY Whenever an object is floating in a fluid or when it is completely submerged in
More informationFluids. Fluid = Gas or Liquid. Density Pressure in a Fluid Buoyancy and Archimedes Principle Fluids in Motion
Chapter 14 Fluids Fluids Density Pressure in a Fluid Buoyancy and Archimedes Principle Fluids in Motion Fluid = Gas or Liquid MFMcGraw-PHY45 Chap_14Ha-Fluids-Revised 10/13/01 Densities MFMcGraw-PHY45 Chap_14Ha-Fluids-Revised
More informationAnswers to test yourself questions
Answers to test yourself questions Option B B Rotational dynamics ( ω + ω )t Use 0 ( +.).0 θ to get θ 46. 46 rad. Use ω ω0 + αθ to get ω.0 +. 4 and so ω 7.8 7 rad s. Use ω ω0 + αθ to get.4. + α 0 π. Hence
More informationPage 1. Physics 131: Lecture 23. Today s Agenda. Announcements. States of Matter
Physics 131: Lecture 3 Today s Agenda Description of Fluids at Rest Pressure vs Depth Pascal s Principle: hydraulic forces Archimedes Principle: objects in a fluid Bernoulli s equation Physics 01: Lecture
More informationMULTIPLE-CHOICE PROBLEMS:(Two marks per answer) (Circle the Letter Beside the Most Correct Answer in the Questions Below.)
MULTIPLE-CHOICE PROLEMS:(Two marks per answer) (Circle the Letter eside the Most Correct Answer in the Questions elow.) 1. The absolute viscosity µ of a fluid is primarily a function of: a. Density. b.
More informationPhysics 220: Classical Mechanics
Lecture /33 Phys 0 Physics 0: Classical Mechanics Lecture: MWF 8:40 am 9:40 am (Phys 4) Michael Meier mdmeier@purdue.edu Office: Phys Room 38 Help Room: Phys Room schedule on course webpage Office Hours:
More information5. is made of a different material than bar two
Example Problems: Bar one has a Young s modulus that is bigger than that of bar Two. This means that bar one: 1. is longer than bar two 2. is shorter than bar two 3. has a greater cross-sectional area
More informationPhysics 207 Lecture 18
Physics 07, Lecture 8, Nov. 6 MidTerm Mean 58.4 (64.6) Median 58 St. Dev. 6 (9) High 94 Low 9 Nominal curve: (conservative) 80-00 A 6-79 B or A/B 34-6 C or B/C 9-33 marginal 9-8 D Physics 07: Lecture 8,
More information. According to the workenergy theorem (Equation 6.3), the work done by the net external force W catapult
1. REASONING The work done by the catapult catapult is one contribution to the work done by the net external force that changes the kinetic energy of the plane. The other contribution is the work done
More informationFluidi. Copyright 2015 John Wiley & Sons, Inc. All rights reserved.
Fluidi 11.1 Mass Density DEFINITION OF MASS DENSITY The mass density of a substance is the mass of a substance divided by its volume: m V SI Unit of Mass Density: kg/m3 11.1 Mass Density 11.1 Mass Density
More informationM o d u l e B a s i c A e r o d y n a m i c s
Category A B1 B2 B3 Level 1 2 3 M o d u l e 0 8-0 1 B a s i c A e r o d y n a m i c s P h y s i c s o f t h e A t m o s p h e r e 08-01- 1 Category A B1 B2 B3 Level 1 2 3 T a b l e o f c o n t e n t s
More informationSample paper 10. Question 1. Which of the following is correct in respect to acceleration?
Sample paper 10 Question 1 Which of the following is correct in respect to acceleration? A. Body does not require any force to accelerate B. Body s velocity should be zero C. Body should be at rest D.
More informationPhysics 111. Thursday, November 11, 2004
ics Thursday, ember 11, 2004 Ch 15: Fluids Pascal s Principle Archimede s Principle Fluid Flows Continuity Equation Bernoulli s Equation Toricelli s Theorem Announcements Wednesday, 8-9 pm in NSC 118/119
More informationWinter 2017 PHYSICS 115 MIDTERM EXAM 1 Section X PRACTICE EXAM SOLUTION Seat No
Winter 2017 PHYSICS 115 MIDTERM EXAM 1 Section X PRACTICE EXAM SOLUTION Seat No Name (Print): Name (Print): Honor Pledge: All work presented here is my own. Signature: Student ID: READ THIS ENTIRE PAGE
More informationFluid Mechanics. Forces on Fluid Elements. Fluid Elements - Definition:
Fluid Mechanics Chapter 2: Fluid Statics Lecture 3 Forces on Fluid Elements Fluid Elements - Definition: Fluid element can be defined as an infinitesimal region of the fluid continuum in isolation from
More informationPhysics 220: Classical Mechanics
Lecture 10 1/34 Phys 220 Physics 220: Classical Mechanics Lecture: MWF 8:40 am 9:40 am (Phys 114) Michael Meier mdmeier@purdue.edu Office: Phys Room 381 Help Room: Phys Room 11 schedule on course webpage
More informationChapter 9. Solids and Fluids. 1. Introduction. 2. Fluids at Rest. 3. Fluid Motion
Chapter 9 Solids and Fluids 1. Introduction 2. Fluids at Rest 3. Fluid Motion 1 States of Matter Solid Liquid Gas Plasma 2 Density and Specific Gravity What is Density? How do I calculate it? What are
More informationFs (30.0 N)(50.0 m) The magnitude of the force that the shopper exerts is f 48.0 N cos 29.0 cos 29.0 b. The work done by the pushing force F is
Chapter 6: Problems 5, 6, 8, 38, 43, 49 & 53 5. ssm Suppose in Figure 6. that +1.1 1 3 J o work is done by the orce F (magnitude 3. N) in moving the suitcase a distance o 5. m. At what angle θ is the orce
More informationSolution to phys101-t112-final Exam
Solution to phys101-t112-final Exam Q1. An 800-N man stands halfway up a 5.0-m long ladder of negligible weight. The base of the ladder is.0m from the wall as shown in Figure 1. Assuming that the wall-ladder
More informationExam 4--PHYS 101--Fall 2016
Name: Exam 4--PHYS 101--Fall 2016 Multiple Choice Identify the choice that best completes the statement or answers the question. 1. A bus contains a 2000 kg flywheel (a disk that has a 0.500 m radius)
More informationFluid Mechanics. If deformation is small, the stress in a body is proportional to the corresponding
Fluid Mechanics HOOKE'S LAW If deformation is small, the stress in a body is proportional to the corresponding strain. In the elasticity limit stress and strain Stress/strain = Const. = Modulus of elasticity.
More informationYou are responsible for recording your 9 digit PSU Student ID on your scantron form
Tuesday, July 28; 9:35AM 10:50AM in 273 Willard 20 Mul=ple Choice Ques=ons See Folder in Exam Resources Midterm 2 Informa=on You are responsible for recording your 9 digit PSU Student ID on your scantron
More informationCh 6 Using Newton s Laws. Applications to mass, weight, friction, air resistance, and periodic motion
Ch 6 Using Newton s Laws Applications to mass, weight, friction, air resistance, and periodic motion Newton s 2 nd Law Applied Galileo hypothesized that all objects gain speed at the same rate (have the
More informationUNIVERSITY OF SASKATCHEWAN Department of Physics and Engineering Physics
UNIVERSITY OF SASKATCHEWAN Department of Physics and Engineering Physics Physics 117.3 MIDTERM TEST February 11, 009 Time: 90 minutes NAME: (Last) Please Print (Given) STUDENT NO.: LECTURE SECTION (please
More informationMECHANICAL PROPERTIES OF FLUIDS
CHAPTER-10 MECHANICAL PROPERTIES OF FLUIDS QUESTIONS 1 marks questions 1. What are fluids? 2. How are fluids different from solids? 3. Define thrust of a liquid. 4. Define liquid pressure. 5. Is pressure
More informationChapter 9. Solids and Fluids 9.3 DENSITY AND PRESSURE
9.3 DENSITY AND PRESSURE Chapter 9 Solids and Fluids The density of an object having uniform composition is defined as its mass M divided by its volume V: M V [9.6] SI unit: kilogram per meter cubed (kg/m
More informationChapter 1 INTRODUCTION
Chapter 1 INTRODUCTION 1-1 The Fluid. 1-2 Dimensions. 1-3 Units. 1-4 Fluid Properties. 1 1-1 The Fluid: It is the substance that deforms continuously when subjected to a shear stress. Matter Solid Fluid
More information5 In a factory, regular stacks, each containing 150 pieces of paper, are measured using a pair of vernier calipers. The reading of one stack is shown.
PURE PHYSICS MECHANICS (PART I) 1 State the symbol of the SI unit for the following physical quantities. (a) Temperature (b) Density (c) Weight (d) Acceleration 2 For each of the following formula, derive
More informationEXAM 1 PHYS 103 FALL 2011 A NAME: SECTION
EXAM 1 PHYS 103 FALL 2011 A NAME: SECTION As a student at NJIT I, will conduct myself in a professional manner and will comply with the provisions of the NJIT Academic Honor Code. I also understand that
More informationPYP 001 SECOND MAJOR EXAM CODE TERM 161 THURSDAY, DECEMBER 15, 2016 PAGE 1
TERM 161 THURSDAY, DECEMBER 15, 2016 PAGE 1 *Read the following (20) questions and choose the best answer: (The Periodic Table is attached) 1 Car P has twice the speed of car Q but car Q has four times
More informationMULTIPLE-CHOICE PROBLEMS :(Two marks per answer) (Circle the Letter Beside the Most Correct Answer in the Questions Below.)
Test Midterm 1 F2013 MULTIPLE-CHOICE PROBLEMS :(Two marks per answer) (Circle the Letter Beside the Most Correct nswer in the Questions Below.) 1. The absolute viscosity µ of a fluid is primarily a function
More information(A) I only (B) III only (C) I and II only (D) II and III only (E) I, II, and III
1. A solid metal ball and a hollow plastic ball of the same external radius are released from rest in a large vacuum chamber. When each has fallen 1m, they both have the same (A) inertia (B) speed (C)
More informationPhysics 201 Chapter 13 Lecture 1
Physics 201 Chapter 13 Lecture 1 Fluid Statics Pascal s Principle Archimedes Principle (Buoyancy) Fluid Dynamics Continuity Equation Bernoulli Equation 11/30/2009 Physics 201, UW-Madison 1 Fluids Density
More informationBarometer Fluid rises until pressure at A, due its weight, equals atmospheric pressure at B. Unit: mm Hg (millimeters that mercury rises)
FLUID MECHANICS The study of the properties of fluids resulting from the action forces. Fluid a liquid, gas, or plasma We will only consider incompressible fluids i.e. liquids Pressure P F A (normal force)
More informationCH 10: PRESSURE, GRAVITY AND MOMENTS
CH 10: PRESSURE, GRAVITY AND MOMENTS Exercise 10.1: Page 104 1. Convert each of the following to kg: (i) 200 g (ii) 4 g (iii) 2 x 10 5 g (iv) 24 mg 2. Convert each of the following to m 3 : (i) 1 cm 3
More informationStates of Matter. Chapter 9 Solids and Fluids. Solids: Stress and Strain. Solids: Stress and Strain. Stress = Force Area. Strain =!L L. Example 9.
Elasticity Chapter 9 Solids and Fluids Archimedes Principle Bernoulli s Equation Solid Liquid Gas Plasmas States of Matter Solids: Stress and Strain Solids: Stress and Strain Stress = Measure of force
More informationStates of Matter. Chapter 9 Solids and Fluids. Solids: Stress and Strain. Solids: Stress and Strain. Stress = Force Area. Strain =!
Elasticity Chapter 9 Solids and Fluids Archimedes Principle Bernoulli s Equation Solid Liquid Gas Plasmas States of Matter 1 2 Solids: Stress and Strain Solids: Stress and Strain Stress = Measure of force
More informationThere are three phases of matter: Solid, liquid and gas
FLUIDS: Gases and Liquids Chapter 4 of text There are three phases of matter: Solid, liquid and gas Solids: Have form, constituents ( atoms and molecules) are in fixed positions (though they can vibrate
More informationQ1. A) 46 m/s B) 21 m/s C) 17 m/s D) 52 m/s E) 82 m/s. Ans: v = ( ( 9 8) ( 98)
Coordinator: Dr. Kunwar S. Wednesday, May 24, 207 Page: Q. A hot-air balloon is ascending (going up) at the rate of 4 m/s and when the balloon is 98 m above the ground a package is dropped from it, vertically
More informationFluid Mechanics-61341
An-Najah National University College of Engineering Fluid Mechanics-61341 Chapter [2] Fluid Statics 1 Fluid Mechanics-2nd Semester 2010- [2] Fluid Statics Fluid Statics Problems Fluid statics refers to
More informationTemperature Thermal Expansion Ideal Gas Law Kinetic Theory Heat Heat Transfer Phase Changes Specific Heat Calorimetry
Temperature Thermal Expansion Ideal Gas Law Kinetic Theory Heat Heat Transfer Phase Changes Specific Heat Calorimetry Zeroeth Law Two systems individually in thermal equilibrium with a third system (such
More informationPrince Sultan University Deanship of Educational Services Department of Mathematics and General Sciences
Prince Sultan University Deanship of Educational Services Department of Mathematics and General Sciences COURSE DETAILS: Introduction to Physical Science SCI101 MAJOR EXAM II Semester: First Semester --
More informationFluid Statics. Pressure. Pressure
Pressure Fluid Statics Variation of Pressure with Position in a Fluid Measurement of Pressure Hydrostatic Thrusts on Submerged Surfaces Plane Surfaces Curved Surfaces ddendum First and Second Moment of
More informationFluids. Fluids in Motion or Fluid Dynamics
Fluids Fluids in Motion or Fluid Dynamics Resources: Serway - Chapter 9: 9.7-9.8 Physics B Lesson 3: Fluid Flow Continuity Physics B Lesson 4: Bernoulli's Equation MIT - 8: Hydrostatics, Archimedes' Principle,
More informationKing Fahd University of Petroleum and Minerals Department of Physics. Final Exam 041. Answer key - First choice is the correct answer
King Fahd University of Petroleum and Minerals Department of Physics MSK Final Exam 041 Answer key - First choice is the correct answer Q1 A 20 kg uniform ladder is leaning against a frictionless wall
More informationObjective: To enable the students to describe, state and derive the terms and expressions relevant in carrying out experiment 5 meaningfully.
Pre-Lab Questions 5 Topic: Archimedes Principle Objective: To enable the students to describe, state and derive the terms and expressions relevant in carrying out experiment 5 meaningfully. After successfully
More informationQuestion Mark Max
PHYS 1021: FINAL EXAM Page 1 of 11 PHYS 1021: FINAL EXAM 12 December, 2013 Instructor: Ania Harlick Student Name: Total: / 100 ID Number: INSTRUCTIONS 1. There are nine questions each worth 12.5 marks.
More information1 atm = 1.01x10 Pa = 760 Torr = 14.7 lb / in
Last class we began discussion of ressure in fluids, with ressure defined as, F = ; units N 1 Pa = 1 m 2 There are a number of other ressure units in common use having the following equivalence, 5 2 1
More informationFluid Mechanics. The atmosphere is a fluid!
Fluid Mechanics The atmosphere is a fluid! Some definitions A fluid is any substance which can flow Liquids, gases, and plasmas Fluid statics studies fluids in equilibrium Density, pressure, buoyancy Fluid
More informationMass per unit volume Mass of 1 m 3. Units of density = kg m 3 Density is a scalar. mass volume. density = m V. rho. 1m x 1m x 1m
1 Mass per unit volume Mass of 1 m 3 density = mass volume rho ρ = m V 1m x 1m x 1m Units of density = kg m 3 Density is a scalar 2 1000 kg 5100 kg 8900 kg Each has a volume of 1 m 3. Which has the greatest
More informationPhysics 201, Lecture 26
Physics 201, Lecture 26 Today s Topics n Fluid Mechanics (chapter 14) n Review: Pressure n Buoyancy, Archimedes s Principle (14.4) n Fluid Dynamics, Bernoulli s Equation (14.5,14.6) n Applications of Fluid
More information*************************************************************************
Your Name: TEST #3 Print clearly. There are 20 equally-weighted questions on this test (two-part problems count as two separate questions). There is only one correct answer per question. Clearly circle
More informationFinal Mock Exam PH 221-1D
Final Mock Exam PH 221-1D April 18, 2015 You will have 2 hours to complete this exam. You must answer 8 questions to make a perfect score of 80. 1 Chapter Concept Summary Equations: Cutnell & Johnson
More informationTest 3 Preparation Questions
Test 3 Preparation Questions A1. Which statement is true concerning an object executing simple harmonic motion? (A) Its velocity is never zero. (B) Its acceleration is never zero. (C) Its velocity and
More informationLecture Notes Chapter 5 Friction
Lecture Notes Chapter 5 Friction NORMAL FORCES When an object rests on a surface, the surface exerts a normal force on the object, keeping it from accelerating downward. A normal force is perpendicular
More information