MEMORANDUM ISEBE LEMFUNDO LEMPUMA KOLONI EASTERN CAPE EDUCATION DEPARTMENT OOS-KAAP ONDERWYSDEPARTEMENT

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1 MLIT MEMANDUM ISEBE LEMFUNDO LEMPUMA KOLONI EASTERN CAPE EDUCATION DEPARTMENT OOS-KAAP ONDERWYSDEPARTEMENT IIMVIWO ZEBANGA LESHUMI ELINANYE GRADE 11 EXAMINATIONS GRAAD 11-EKSAMEN NOVEMBER 008 MATHEMATICAL LITERACY FIRST PAPER This memorandum consists of 11 pages.

2 MATHEMATICAL LITERACY FIRST PAPER (MLIT) (MEMO 11/08) QUESTION cup = 15 g margarine cup = x 15 g = 143,33 g = 143 g Rounding 1 cup = 15 g cup = xg x = x 15 = 143,33 = 143 g kg = g R1, g = R0,0 per gram or cents per gram Rounding (3) () The 5 ml spoon (1) batch = 3,75 units 8 batches = 3,75 x 8 = 30 units Total cost of electricity = 30 units x 59,85 c = 1 795,5 c = R17, batches x 4 cookies 19 cookies cookies 15 = 1,8 boxes They will pack 1 boxes per day ºC = 9 5 (ºF 3) = 9 5 (356 3) = 180º C () () () Rounding (3) Substitution ()

3 (MEMO 11/08) MATHEMATICAL LITERACY FIRST PAPER (MLIT) Total wages per week = 7 hours per day x 3 days = 1 hours = 1 hours x R7,50 = R157,50 per week (3) [0] QUESTION.1 He walks at a speed of 4 km/h Thus he walks 4 km (1)..1 Value of A: Distance = Speed x time = 4 km/h x 0,5 hours = km Substitution Value B: Distance = Speed x time 5 km = 8 km/h x time Time = 5 km 8 km/h = 1,5 hours 1¼ hours 1h15 min Substitution Value of A: Learners can see the pattern 1,, 3 and for giving the answer of km Pattern Value of B: Learners can see the pattern 15 minutes (¼ which is 0,5) and for giving the answer of 1,5 hours.. At 06:15 he was 1 km away from home. 6 km 1 km = 5 km He is thus 5 km away from school. Pattern (4) Time difference ()..3 06: minutes = 06:45 (1)

4 4 MATHEMATICAL LITERACY FIRST PAPER (MLIT) (MEMO 11/08).3.1 Value of C: Distance = Speed x time = 8 km/h x 0,5 hours = km Substitution Value D: Distance = Speed x time 6 km = 8 km/h x time Time = 6 km 8 km/h = 0,75 hours ¾ hours 45 min Substitution Value of C: Learners can see the pattern, 4, 6 and for giving the answer of km Pattern Value of D: Learners can see the pattern 15 minute (¼ which is 0,5) and for giving the answer of 0,75 hours Pattern (4).3. At 06:30 Jason was km away from home; at 06:45 Chanté was km away from home s ().3.3 Jason (1) :00 (1).3.5 points on Chanté s line to be marked points on Jason s line to be marked Jason s line to start from 06:00 Chanté s line to start from 06:30 (6)

5 (MEMO 11/08) MATHEMATICAL LITERACY FIRST PAPER (MLIT) 5 DISTANCE TRAVELLED FROM HOME BY JASON AND CHANTÉ DISTANCE COVERED FROM HOME (KILOMETERS) Chanté Jason Chanté Jason 06:00 06:15 06:30 06:45 07:00 07:15 07:30 TIME

6 6 MATHEMATICAL LITERACY FIRST PAPER (MLIT) (MEMO 11/08).3.6 On graph. One mark is given for drawing in the broken line at 6 km. One mark is given for writing Jason s name under the time of 07: On graph. One mark is given for drawing in the broken line at 6 km. One mark is given for writing Chanté s name under the time of 07: min after 07:15 is 07:30 She would be km past the school. 8 km 6 km = km Broken line at 6 km reading on graph. () Broken line at 6 km reading on graph. () Adding 15 minutes () [8]

7 (MEMO 11/08) MATHEMATICAL LITERACY FIRST PAPER (MLIT) 7 QUESTION ; 9 ; 10 ; 10 ; / 10 ; 18 / ; 1 ; 30 ; 43 ; Median = = ; 6 ; 6 ; 8 ; / 1 ; 3 / ; 9 ; 31 ; 50 ; Median = = 17,5 3.3 Team A s mode = 10 Team B s mode = Team A s mean = 10 0 = 10 = 0, 3.5 Team B s mean = 10 0 = 10 = Team B has a better batting average than Team A 3.6 Range of Team A = 51 0 = 51 Arranging from small to large numbers middle numbers Dividing by (4) Arranging from small to large numbers middle numbers Dividing by (4) () Adding Dividing by 10 (3) Adding Dividing by 10 Justification (4) Subtract small from big () 3.7 Range of Team B = 51 4 = 47 Subtract small from big () batsmen (1) []

8 8 MATHEMATICAL LITERACY FIRST PAPER (MLIT) (MEMO 11/08) QUESTION m x 56 m = 40 m Area of Farm = 40 m x = m π r 4. Area of Pond = 8 = 7 = 1 3 m Doubling (3) Sub. of π Sub. or r For π = 3,14 π r Area of Pond = 3,14 8 = = 1 30,88 m Sub. of π Sub. or r if learners used π on calculator = 1 31,50 m (3) 4.3 No. of goats per m is = () 4.4 Rectangular side is ( ) = 16 m Pond side (arc) is π r = x 8 = 88 m 7 Total length is 16 m + 88 m = 304 m Addition Rectangular side is ( ) = 16 m Pond side = π r = 3,14 x 8 = 87,9 m Total length = 16 m + 87,9 m = 303,9 m Addition Rectangular side is ( ) = 16 m Pond side = π r = π x 8 = 87,96 m Total length = 16 m + 87,9 m = 303,96 m 4.5 Cost of fence is R45,00 x 304 = R13 680,00 Addition (3) ()

9 (MEMO 11/08) MATHEMATICAL LITERACY FIRST PAPER (MLIT) R10,00 x 5 = R600,00 Total labour charge is R600,00 x = R1 00, R R1 00 R14 880,00 Multiplying by 5 Multiplying by (3) Method () [18] QUESTION Volume = 3,5 m x 1,5 m x 0,5 m =,65 m 3 5. Volume in cm 3 =,65 m 3 x = cm 3 Volume in litres = cm cm 3 = 65 litres 350 cm x 150 cm x 50 cm = cm 3 Volume in Litres = cm cm 3 = 65 litres. 5.3 Volume of the bucket = π r h Volume of the bucket = x 14 x 40 cm 7 = cm 3 = 4,64 litres Volume = π r h = 3,14 x 14 x 40 = 4 617,6 cm 3 = 4,6 litres Volume = π r h = πx 14 x 40 = 4 630,09 = 4,63 litres () (4) Sub. of Sub. Of r in litres Sub. of Sub. Of r in litres Using Sub. Of r in litres (4)

10 10 MATHEMATICAL LITERACY FIRST PAPER (MLIT) (MEMO 11/08) 5.4 No. Of buckets = 65 4,64 = 106,53 No. Of buckets = 65 4,6 = 106,6 No. Of buckets = 65 4,63 = 106,58 () [1] TOTAL: 100

11 (MEMO 11/08) MATHEMATICAL LITERACY FIRST PAPER (MLIT) 11 MATHEMATICAL LITERACY GRADE 11 NOVEMBER 008 FIRST PAPER Taxonomy Learning Outcomes Level L 1 L Q Context Detail Item LO1 LO LO3 LO4 60% 40% Sub-tot Total Mrs. Pelser and the Sugar Biscuits Chanté and.3. Jason going to School Batting Averages Farming Enclosure Dairy Farming Percentage

ISEBE LEMFUNDO LEMPUMA KOLONI EASTERN CAPE EDUCATION DEPARTMENT OOS-KAAP ONDERWYSDEPARTEMENT

MATH ISEBE LEMFUNDO LEMPUMA KOLONI EASTERN CAPE EDUCATION DEPARTMENT OOS-KAAP ONDERWYSDEPARTEMENT IIMVIWO ZEBANGA LESHUMI ELINANYE GRADE 11 EXAMINATIONS GRAAD 11-EKSAMEN NOVEMBER 2008 MATHEMATICS FIRST