GRADE 11 NATIONAL SENIOR CERTIFICATE

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1 GRADE 11 NATIONAL SENIOR CERTIFICATE MATHEMATICAL LITERACY P NOVEMBER 007 MARKING MEMORANDUM This memorandum consists of 8 pages.

2 Mathematical Literacy/P QUESTION 1 [1] R50 (1) 1.1. R15 per person (1) people (1) As more people travel in the car the cost per person decreases. A solution 1..1 Turn right down Bumba Lane, cross over Main Road and continue until Thato s house. Turn left into Zwemba Drive, take first left into Second Avenue and carry on until Joe s house. Pick up Joe. Turn around and continue along Second Avenue. Turn left into Main Road and take the first Right into First Avenue. Stop at the Office Block. Scale measurements 1.. width = 1mm = 0,01 m length = 35mm = 0,035 m Accept any logical route 3A solution (3) 1M converting to m 1A correct values Actual measurements width = 0,01 x = 40 m length = 0,035 m x = 700m 1M multiplying 1A correct values (4) :15 07:50 = 9 hours 5 minutes She would be charged the rate for More than 9 hours which is R1, :45 08:01 = 44 minutes. This is less than 1 hour, so she would not be charged anything. 17: 1:15 = 5 hours and 15 minutes. She would be charged the rate for From 5 to 7 hours which is R8, Period Parked : 8h45 to 13h5 = 4hrs 40min cost for parking : She would be charged the rate for parking for 4-5 hours, which is R6,00. A charge of R8,00 is incorrect. R She is being over charged by R. 1A hours parked 1CA cost of parking 1A hours parked 1 CA cost of parking 1A hours parked 1CA cost of parking 1R explanation (3) [19]

3 Mathematical Literacy/P 3.1 QUESTION [3] 9 i = = 0, A calculating i A = P (1 + i) n = R ( 1 + 0,09) 8 = R39 107,5..1 Area of walls = (l x b) + (l x b) = (4 x 3) + (5 x 3) = 4m + m = 54m Surface area to be painted = 54m 15m [,04m x 0,8m] = 54m 15m 1,63m = 37,37m.. Area to be painted = x 43,368 m = 74,74m 86,736 m No. of 5 litre can = 36 m =,409 need 3 x 5 litre cans because x 5 litres cans will not be sufficient to give the walls two coats of paint..3a Area of kitchen floor = 4m x 3m = 1m Cost of tiling kitchen = 1 x R1,50 = R150..3b Area of a service room floor = l x b = (5 x 4)m = 0m Cost of tiling front of shop = 16 x R1,50 = R50 Total cost = R150 + R50 = R910 1M substitution 1A correct values 1CA solution (4) 1A area of door 1CA solution (5) 1M double area 1M dividing 1CA Solution 1CA decision (4) 1M multiplication 1CA solution (3) 1CA multiplication 1CA solution (4)

4 Mathematical Literacy/P 4.3 Height of the decoration =,4 m + 10 cm =,4 m + 0,1 m =,5 m 1A change measurement to metres Width of the decoration = 0,8 m + 0,1 m + 0,1 m = 1,0 m Length of decoration =,5 m + 1,0 m +,5 m = 6 m.4.1 V = π r h = 3,14 (1,5) (3) cm 3 = cm 3 = ml = 6,8 l of water.4. Volme of water + volume of rice = 65 ml + 50 ml = 875 ml 3 4 of 6,8 l = 47,1l ml Number of cups of rice = = 53, ml C The maximum number of cups she can cook is cups would be too much 1CA solution (4) 1M substitution 1A correct value 1A answer in ml 1CA conversion to l (4) 1 M adding M finding fraction 1 A solution CA final answer (5) [34]

5 Mathematical Literacy/P 5 QUESTION 3 [4] For 11A : median = = 58 For 11B : median = = 59,5 = 60 (4) 3.1. For 11A: Mean mark = 17 = = 57,66 = 57,7 For 11B: Mean mark = = 163 = 54,1 (4) For 11A: Range = 9 18 = 74 For 11B: Range = = 87 11A has the smaller range 1 CA conclusion (3) No of learners in Grade 11A who got a mark of 50 or less = 10 x 100% = 33,33% 1M finding percentage No of learners in Grade 11B who got a mark of 50 or less = 13 x 100% = 43,33% 11A performed better than 11 B. Their mean is higher and their range is smaller. R R Also, fewer of them got a mark of 50 or less. 1M finding percentage (4) R valid reason (3)

6 Mathematical Literacy/P P = 1 = 10 = 0,1 P = = 1 1CA decimal soln. (3) 0 P = = 0 P = 60 = 1M correct totals for 0, both classes = 3,33% as % (4) [9]

7 Mathematical Literacy/P 7 QUESTION 4 [3] 4.1 The basic cost is R190 (constant) and the cost of each minute (t) is R1, C =,50t Minutes and 1 seconds 73 minutes Cost = R,50 x 73 = R18, COST OF CELL PHONE CALLS Cost in Rand Time in minutes B A 1A R80 constant 1A each minute 1M form of eq. 1A correct equation 1M substitution 1A rounding up 1CA solution (3) Graph A for plotting correctly Graph B for getting the cut on the vertical axis correct for plotting correctly (5) R500 (accept between R480 R50) A solution

8 Mathematical Literacy/P After using the cell phone for 00 minutes A solution 4.6 Rafique s total sales = R R R5 000 = R1 000 James s total sales = R R R4 000 = R9 000 Rafique s sales were higher. 1A addition 1A final answer [18] TOTAL: [100]

9 ASSESSMENT FRAMEWORK Mathematical Literacy Grade 11 November 007 P Q 1 Context detail Work Colleagues Mrs Madondo's Take-Away shop Item Learning Outcomes LO 1 LO LO 3 LO 4 Taxonomy Level L1 L 0% L3 40% L4 40% Subtot a b Total Class Marks Travelling Salesman

NATIONAL SENIOR CERTIFICATE GRADE 12

NATIONAL SENIOR CERTIFICATE GRADE 12 MATHEMATICAL LITERACY P1 NOVEMBER 2009 MEMORANDUM MARKS: 150 Symbol M MA CA A C S R/RG SF O P R Explanation Method Method with accuracy Consistent accuracy Accuracy