NATIONAL SENIOR CERTIFICATE GRADE 10
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1 NATIONAL SENIOR CERTIFICATE GRADE 10 MATHEMATICAL LITERACY P EXEMPLAR 01 MEMORANDUM MARKS: 75 Symbol M MA CA A C S RT/RG SF O P R Explanation Method Method with accuracy Consistent accuracy Accuracy Conversion Simplification Reading from a table/reading from a graph Correct substitution in a formula Opinion/Example Penalty, e.g. for no units, incorrect rounding off, etc. Rounding off/reason This memorandum consists of 7 pages.
2 Mathematical Literacy/P DBE/01 QUESTION 1 [13] Base = 6 15 cm = 90 cm Height = 3 15 cm = 45 cm 1A length Area of a triangle = 1 base height 1 = 90 cm 45 cm = 05 cm 1SF substituting 1 CA answer 1.1. Diameter = 4 15 cm = 60 cm Radius = 30 cm Area of a circle = (radius) = 3,14 (30 cm) = 87,8 cm 1A diameter 1CA radius 1SF substituting (4) L Length of tape = Perimeter of rectangle + Perimeter of square = 60 cm + 30 cm cm = 10 cm + 60 cm + 10 cm S = 300 cm cm = 3 m C 1SF substituting into perimeter of rectangle 1SF substituting into perimeter of square 1S simplification 1C converting cm to m (4) L3 Cost = R19,50 3 = R58,50 () L3
3 Mathematical Literacy/P 3 DBE/01 QUESTION [6].1.1 Tariff = R5,994 RT RT reading values from table () L.1. A = 40 R5,994 = R39,76 M OR R73,33 A = M 1,14 = R39,76 1M multiplying/dividing () L. 114% amount excluding VAT = C 116, 8 M C = 114% 116, 8 = 114, = R10,00 1M concept excluding VAT 1A dividing by 114% 1A simplification.3.1 The total due includes values, like rates, on which no VAT is charged (zero rated). R R.3. VAT at B = R73,33 R39,76 = R33,57 VAT at D = R116,8 R10,00 = R14,8 Total VAT M = R33,57 + R,7 + R55,76 + R9,4 + R14,8 + R5,84 = R140,96 R answer 1CA VAT at B 1CA VAT at D 1M adding all the values () L4
4 Mathematical Literacy/P 4 DBE/01.4 Monthly rates = Residential rate rateable value 1 rateable value R73,38 = 1,89% 1 1 R73,38 Rateable value = 0,0189 M/A = R ,17 1SF substitution into formula 1M/A rearranging the formula.5.1 Amount in rand = 6,0 5,4 + (amount used 6,0 ) 10,94 1A multiplying by 5,4 1M subtracting 6,0 1A multiplying by 10,94.5. Graph A The graph shows that the tariff increases when more water is used. R (Any other suitable explanation).6.1 Mean M = = 1 = 765,50 kwh.6. During the school holidays in June, more people could be at home using electricity O June is a winter month, and the family could be using more electricity to keep themselves warm. O A choice R reason 1M finding mean 1A simplifying O own opinion (4) L4.6.3 (Any other opinion/reason) P(less than 710) = 1 1 1A numerator 1A denominator () L4 () L3
5 Mathematical Literacy/P 5 DBE/01 QUESTION 3 [14] 3.1 Number of screws = 6 4 = 4 A answer 3. Chair seat and stretcher 1A chair seat A stretcher () L4 3.3 Assemble the chair's side rails (C) to the front leg frame (B) using the wood dowel (J) and the JCBC screw (G) and the spring washer (H). Tighten in a clockwise direction using the Allen key (K). 1A side rails and front leg frame 1A wood dowel, JCBC screw and spring washer 1A direction for tightening 1A Allen key (4) L4 3.4 Area = 4 cm 41 cm 1SF substitution into formula = 1 7 cm 1A correct unit cm Scale height = 3,5 = 4 cm 1A using the scale (3) L () L3
6 Mathematical Literacy/P 6 DBE/01 QUESTION 4 [19] ; 9; 30; 30; 3; 35; 35; 38; 56; 56; 58; 58; 58; 67; 67; 70; 74; 76; 84; 85 M 1M arranging data Mode = 58% A A mode () L (1) L3 (1) 4.1. Range = 85% 5% M = 60% Median = M 1M subtracting min and max values 1CA solution () L 1A correct central values 1M dividing = 57% 1CA conclusion 4..1 P = 0 Q = 6 1A solution A solution (3) L P = M 0 = 0,35 1A denominator 1M writing probability (3) L
7 Mathematical Literacy/P 7 DBE/ NUMBER OF LEARNERS PER LEVEL 7 FREQUENCY Level 1 Level Level 3 Level 4 Level 5 Level 6 Level 7 1CA correct plotting of L 1CA correct plotting of L3 1A correct plotting of L6 LEVEL Share = of R600 5 = R360 R360 Each learner s share = = R180 1A using ratio 1A simplifying TOTAL: 75
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