NATIONAL SENIOR CERTIFICATE GRADE 12

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NATIONAL SENI CERTIICATE GRAE 12 ATHEATICAL LITERACY P1 NOVEBER 2017 ARKING GUIELINE ARKS: 150 SYBOL A CA A C S RT/RG S O P R NPR EXPLANATION ethod ethod with accuracy Consistent accuracy Accuracy

1 NATIONAL SENI CERTIICATE GRAE 12 ATHEATICAL LITERACY P1 NOVEBER 2017 ARKING GUIELINE ARKS: 150 SYBOL A CA A C S RT/RG S O P R NPR EXPLANATION ethod ethod with accuracy Consistent accuracy Accuracy Conversion Simplification Reading from a table/graph/diagram Correct substitution in a formula Opinion/Example/efinition/Explanation Penalty, e.g. for no units/incorrect rounding off, etc. Rounding off No penalty rounding or omitting units Answer only, if correct, full marks This marking guideline consists of 16 pages.

2 athematical Literacy/P1 2 BE/November 2017 NSC arking Guideline Question 1 [30 ARKS] RT correct letter G RT 2 RT correct letter C RT 2 RT correct letter Profit = R R = R (a) (b) 10:15 + 5h50 = 16:05 16:05 4:05 pm 5 past 4 in the afternoon Radius = 32,8 mm 2 = 16,4 mm istance = (71,8 mm 32,8 mm) 2 = 19,5 mm 1 subtracting correct values 1A calculating profit 1 adding 1A correct time of sale 1A dividing diameter by 2 1CA radius 1A subtracting and dividing 1CA distance 71,8 mm 2 = 35,9 mm istance = 35,9 mm 16,4 mm = 19,4 mm 1A subtracting and dividing 1CA distance

3 athematical Literacy/P1 3 BE/November 2017 NSC arking Guideline Cost of diluted juice per litre = R 44,95 14 l = R 3, R 3, l : 12 l 1 : 6 1A dividing 1CA cost per litre NPR 1A correct volume of water and order Accept Number of glasses of juice = 14 0,175 1A dividing the correct values = 80 to a whole number RT all values 1A ascending order July 7 th month 2A correct month A correct mode April 4 th month 2A correct month ay and July 5 th month and 7 th month 1A ay 1A July [30]

4 athematical Literacy/P1 4 BE/November 2017 NSC arking Guideline QUESTION 2 [46 ARKS] R465,00 2RT correct bus fare Queenstown and King William's Town 2RT correct cities (a) Port Elizabeth to Bloemfontein = R435,00 1RT R435 Cost = R755,00 R435, (b) = R320,00 King William's Town Cost excluding VAT 100 = R365, CA cost Accept trial and error method CA from Q2.1.3(a) 2RT correct city = R320,175 R320,18 Cost excluding VAT R365 = R320,18 1, : 365 = 100 : x x = price excl. VAT 100 x = R365, = R320,175 R320,18 14 VAT = R365 = R44, Cost excluding VAT = R365 R44,82 R320,18 1 dividing 1A 1,14 1 proportion 1 x as subject of formula 1 multiplying with ratio 1 subtracting VAT NPR

5 athematical Literacy/P1 5 BE/November 2017 NSC arking Guideline rom Queenstown to Bloemfontein return trip 1RT correct fare = R CA for calculating the = R820 return trip Total travelling cost = 12 R820 1 multiplying by 12 = R CA total cost Number of trips = 2 12 = 24 1 multiplying by 12 1CA total trips Total travelling cost = 24 R410 1RT correct fare = R9 840 One way cost for a year = R = R4 920 Total traveling cost = R = R9 840 Traveling cost = R =R CA total cost 1RT correct fare 1 multiplying with 12 1 multiplying with 2 1CA total cost 1RT correct fare 1 multiplying with 2 1 multiplying with 12 1CA cost (4)

6 athematical Literacy/P1 6 BE/November 2017 NSC arking Guideline July / /13 1RT month 1RT year Water and Sewerage Refuse Removal November = 3 days, ecember = 20 days 1RT water and/or sewerage 1RT refuse Penalty for including property rates 1 adding end date 2016/12/20 20 ecember aily average consumption = 12,00 kl 23 days 1A end date 20 ec Accept 19 ec 1RT correct value 1 dividing in correct order 0,522 kl Verifying the consumption rate per day: = 12,00 kl 0,522 kl/day 1RT correct value 1 dividing in correct order 23 days 0,522 kl/day 23 days 12,00kl Water R 1 multiplying 1A volume 1R variable expense The amount of water consumption is not the same every month. O 2O explanation clearly showing change

7 athematical Literacy/P1 7 BE/November 2017 NSC arking Guideline 1RT all values from bill A = R R0, (a) (b) = R397,67 B = R397,67 R115,27 = R282, 40 Note value for B can be used to calculate A 1 subtracting correct values B = R880,10 R167,58 R430,12 = R282,40 Sewerage rate per m 2 = R298, subtracting correct values 1RT correct values = R0, A simplification 463m 2 : R 298,36 1RT Correct values 1m 2 : R0, A simplification NPR R919,33 2RT unpaid amount Rounding up Rounding (off) to the nearest R10,00 Rounding (off) to the nearest R100, Commission = 1,95% 360,00 = 7,02 2A Rounding up 1A rounding 1A nearest 10 rand 1A rounding 1A nearest 100 rand 1A calculating % 1A commission in pound

8 athematical Literacy/P1 8 BE/November 2017 NSC arking Guideline A conversion 360,00 = /A 0,05773 = R6 235, R6 235,93 or R6 235 or R6 236 R1,00 1 = 0,05773 = R17, = R17, A simplification 1CA rounding 1A conversion = R62 35, A simplification R6 235,93 R1,00 = 0,05773 x = 360,00 x =R ,05773 = R6 235,93 Interest after 1 year = R ,3% = R315 1CA rounding 1A multiplying with 360 1A conversion 1CA rounding NPR 1 calculate interest for first year Amount after year 1 = R R315 = R5 315,00 1A simplification Interest for full 2 nd year = R ,3% R334,845 1CA 2 nd year amount 1 Interest for 2 year = R334,845 2 = R167,42 Value of the fixed deposit = R R167,42 = R5 482,42 1 half year interest

9 athematical Literacy/P1 9 BE/November 2017 NSC arking Guideline Interest after 1 year = R ,3% = R315 Amount after year 1 = R R315 = R5 315,00 1 calculate interest for first year 1A simplification Second year interest rate = 6,3% nd year rate = 3,15% Interest for 1 year = R ,15% 2 R167,42 Value of the fixed deposit = R R167,42 = R5 482,42 Amount after year 1 = R5 000 (1 + 0,063) = R5 315,00 Value of fixed deposit after 1 21 years = 0,063 R R5 482,42 1CA half year interest 1 calculate amount for first year 1A simplification 1CA 2 nd year amount 1 half year (5) [46]

10 athematical Literacy/P1 10 BE/November 2017 NSC arking Guideline QUESTION 3 [21 ARKS] Number of tables = = 30 1A correct number of tables Number of balloons = 4 30 = Length of decorative ribbon in cm = 2 (length + width) + 1 S = 2 (10 + 6) + 1 = Volume = π (radius) 2 height S = 3,142 (6 cm) 2 28 cm 1CA minimum number of balloons 2S substituting correct values into the formula 1A minimum length 1A radius 1S correct height and 3,142 = 3 167,136 cm Volume = cm 3 45% = 756 cm 3 NPR 1A calculating 45% ass of sand = 756 cm 3 1,53g/cm 3 = 1 156,68 g multiply by rate 1CA mass in grams 1,16 kg C 1,53 g/cm 3 = 0,00153 kg/cm 3 C Volume = cm 3 45% = 756 cm 3 ass of the sand = 0,00153 kg/cm cm 3 1C converting to kg to 2decimal places 1C converting to kg 1A calculating 45% 1 multiplying with the rate = 1,15668 kg 1,16 kg 1 CA mass in kg to 2 dec. places

11 athematical Literacy/P1 11 BE/November 2017 NSC arking Guideline ass of sand in a full vase = cm 3 1,53g/cm 3 = 2 570,4 g = 2,5704 kg C ass of sand if filled to 45% 1 multiplying with the rate 1A mass 1C conversion = 2,5704 kg 45% = 1,16 kg 1 Area of triangle = 4 cm 3,464 cm 2 = 6,928 cm Total surface Area of a triangular prism S = 2 6, cm 4cm = 13,856 cm cm 2 = 85,856 cm minutes = seconds C Average time to cover 1 box = seconds 20 = 90 seconds 1CA mass of sand to two decimal places (4) 1A substituting correct values in formula 1RT height NPR CA from Q CA substituting area of triangle 1S substituting correct values in formula 1CA total surface area 1 C conversion to seconds (4) L3 Average time to cover 1 box 30 min = = 1,5 min 20 = 1,5 min 60 sec/min = 90 seconds C 1 time per box 1C conversion [21]

12 athematical Literacy/P1 12 BE/November 2017 NSC arking Guideline QUESTION 4 [27 ARKS] NOTE :PU & NC maximum [23 ARKS] to be scaled to 27 ARKS &P Bar scale Scaled bar Linear scale 2A identifying type of Graphical scale scale Top view Aerial view Bird s eye view Satelite view 2A correct view of the map South East SE East of South 2A identifying correct direction A exact number of medical points Accept owbray and Observatory 2A identifying correct suburbs Accept aitland and Saltriver Castle e Goede Hoop, Old Biscuit ill, Planetarium 4, 5 and 6 3A identifying correct tourist attractions &P &P &P &P &P

13 athematical Literacy/P1 13 BE/November 2017 NSC arking Guideline ; B; E; A; C NOTE: &P [PU & NC not to be marked] E B 1A order BEA 1A end with C NOTE: [PU & NC not to be marked] &P (a) (b) 2A correct letter 0 2A probability 0 % Impossible 0 None 130 Total blocks = = 130 Probability of taking out a blue block 1A total 130 P P 25 = ,23% 0,19 1A numerator 1A denominator (a) (b) Number of layers = 35 cm 16, = 2,12 2 Number of cans which can be packed lengthwise = 56 cm 12,6 cm = 4, A dividing correct values 1CA exact number of layers 1A dividing the width or length by 2,6 &P &P L3 Number of cans which can be packed width-wise = 41 cm 12,6 cm = 3, A rounding both down to whole numbers aximum number of cans = = 24 1CA for max number of cans [27]

14 athematical Literacy/P1 14 BE/November 2017 NSC arking Guideline QUESTION 5 [26 ARKS] Ques Solution Explanation T/L Broken line graph line graph 2A correct type of graph Number of candidates = adding ath and ath Lit = CA max number of candidates % 1 certain definite 2A correct probability Accounting, Business Studies, Economics and athematical Literacy 1RT 1 st subject 1RT 2 nd subject 1RT last two subjects P athematics 2RT correct subject The data of one variable is grouped into subjects The data of one variable is not numerical 2A explanation Business Studies 2RT correct subject

15 athematical Literacy/P1 15 BE/November 2017 NSC arking Guideline Ques Solution Explanation T/L O Copyright payments, advertising costs, bursary, grants etc. 2O an example of other type of expenditure ( any other valid expenditure) onations = [R63 (R27,09 + R21,02 + R3,78)] billion 1 subtracting from R63 billion = R11,11 billion in billions 11,11 Percentage donations = 100% 63 17,6% 1CA donations as a % R27, ,02 + 3,78 = R51,89 billion Percentage income shown = R51,89 R63 100% 82,4% Percentage donations =100% 82,4% =17,6% Percentage = R27,09 R63 100% = 43% 1 percentage income shown 1 subtracting from 100% 1 percentage calculation R21,02 R63 100% 33,365% R3,78 R63 100% = 6% Percentage donations = 100% (43% + 33,4% + 6%) 1 subtracting from 100% = 17,6% NPR

16 athematical Literacy/P1 16 BE/November 2017 NSC arking Guideline Ques Solution Explanation T/L Interest in Rand = ,7% 1RT correct amount 1 multiplying with 0,7% = ,7 million 1CA interest amount Interest in rand = 54,1 billion 0,7% = 0,3787 billion 1RT correct amount 1 multiplying with 0,7% 1CA interest amount = ,7 million ifference = income expenditure = R63 billion R54,1 billion 1 subtracting = R8,9 billion C = R8 900 million R in billions 1C for difference in millions ifference = income expenditure C = R million R million = R8 900 million R subtracting 1C converting to millions 1CA difference in millions [26] TOTAL: 150

NATIONAL SENIOR CERTIFICATE GRADE 12

NATIONAL SENIOR CERTIFICATE GRADE 12 NATIONAL SENI CERTIICATE GRADE 12 MATHEMATICAL LITERACY P1 NOVEMBER 2014 MEMANDUM MARKS: 150 SYMBOL EXPLANATION M Method MA Method with accuracy CA Consistent accuracy A Accuracy C Conversion S Simplification