NATIONAL SENIOR CERTIFICATE GRADE 12

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NATIONAL SENIOR CERTIFICATE GRADE 12 MATHEMATICAL LITERACY P1 NOVEMBER 2009 MEMORANDUM MARKS: 150 Symbol M MA CA A C S R/RG SF O P R Explanation Method Method with accuracy Consistent accuracy

1 NATIONAL SENIOR CERTIFICATE GRADE 12 MATHEMATICAL LITERACY P1 NOVEMBER 2009 MEMORANDUM MARKS: 150 Symbol M MA CA A C S R/RG SF O P R Explanation Method Method with accuracy Consistent accuracy Accuracy Conversion Simplification Reading from a table/reading from a graph Correct substitution in a formula Opinion/Example Penalty, e.g. for no units, incorrect rounding off etc. Rounding off This memorandum consists of 12 pages.

2 Mathematical Literacy/P1 2 DoE/November 2009 QUESTION 1 [26] : 128 ( 16) 29 : 8 1A solution = 1, A solution 1,52 1CA rounding off (57) 3 = A square root brackets and dividing = 26 1CA simplification , m l 1M multiplying = m l C 16 16% of kg = kg 100 = 200,8 kg 1C conversion 1M calculating % 1A solution New amount OR = kg + 200,8 kg = 1 455,8 kg 1CA increase in % 16% increase = 1,16 1A total % New amount = 1, kg 1M multiplying = 1 455,8 kg $1 = R10,52 $1 215,00 = R10, ,00 = R12 781,80 1CA solution 1M multiplying 1CA simplification

3 Mathematical Literacy/P1 3 DoE/November MA dividing R 399,00 A 30 1CA simplification = R13, or 100% or certain 2A correct probability SF Temp in o 9 F = 225 o + 32 o 1SF substitution in formula 5 = 405 o F + 32 o F S = 437 o F 435 o F 1S simplification 1CA simplification Cost price of 1 orange = R 9,00 12 = R0, dozen oranges sell for R12,00 Profit = R12,00 R9,00 = R3, Cost = 108 R0,75 = R81,00 1M division by 12 1CA simplification 1M finding profit 1CA solution 1CA cost per orange 1CA cost for 108 oranges OR 12 oranges cost R9, R 9, oranges = 12 = R81,00 1M finding number of dozens 1CA cost for 108 oranges

4 Mathematical Literacy/P1 4 DoE/November 2009 QUESTION 2 [31] Penalty for units in D = 10 cm 1A doubling the radius L = 29,5 cm 2,5 cm 2,5 cm 1M finding length = 24,5 cm A = π r 1CA length of certificate 1SF substitution in formula = 3,14 (5 cm) 2 SF = 78,5 cm P = 2 (29,5 cm + 21 cm) SF 1A unit 1SF substitution in formula = 2 50,5 cm = 101 cm A = 29,5 cm 21 cm SF 1SF substitution in formula = 619,5 cm : A 1MA correct ratio = 3 : guests 7 = 90 guests litre concentrate makes 5 litres of juice A 5 litres concentrate makes 5 5 l = 25 l 1A correct fraction 1MA dilution ratio OR Number of litres of juice = 4 5 l l = 20 l + 5 l = 25 l A 1MA dilution ratio

5 Mathematical Literacy/P1 5 DoE/November Eastern Cape 1CA correct province C = 100% 15% 6% 13% 50% A 1MA setting up model = 16 % Gauteng 1CA correct province A A vehicles OR 0, = ,92 vehicles vehicles R 1MA 18% of vehicles stolen 1MA correct no. of vehicles 1R rounding (4) (a) R750 RG 1 RG reading from graph (b) She will make a loss 1A solution (c) 10 RG 2RG reading from graph Pr ofit Percentage profit = 100% Expenses SF R400 = 100% R850 1SF substitution into formula = 47, S 1S simplification 47,1% R 1R rounding off

6 Mathematical Literacy/P1 6 DoE/November 2009 QUESTION 3 [19] years 1A modal age years 1A median 1SF correct Mean substitution SF = 268 = 15 = 17,8666 = 17,87 years R 15 1MA dividing by size of sample 1R rounding off (a) 20% 1A lowest (b) 100% 1A highest PERFOR- MANCE LEVEL PERCENTAGE RANGE A TALLY FRE- QUENCY 1 0 to 29 //// to 39 //// to 49 //// //// / to 59 //// /// to 69 //// to 79 //// /// to 100 //// //// / 11 1A learners in level 1 1A learners in level 2 1A learners in level 3 1A learners in level 4 1A learners in level 5 1A learners in level 6 1A learners in level 7 (4) learners 1,6 m 2 /learner 1M method (7) = 83,2 m Number of learners = 1,6 = 60 learners 1A simplifying 1M division 1A solution

7 Mathematical Literacy/P1 7 DoE/November 2009 QUESTION 4 [23] km C RG 1C conversion to hrs 1RG reading from graph :45 R 2RG reading from graph (a) km Speed = SF 1SF substitution into formula 2h = 60 km/h 1CA solution (b) 72 minutes = 1,2 hours 1A conversion to hours Distance = 80 km/h SF 1,2h Distance = 80 1,2 km = 96 km DISTANCE TRAVELLED AGAINST TIME TAKEN 1SF substitution into formula 1CA solution Mr Lebelo Mr Goldman Distance in km :00 07:15 07:30 07:45 08:00 08:15 08:30 08:45 09:00 Ti m e 1A line 7:00 to 7:15 1A plot other 3 points 1A joining the 3 points 1A shape of graph (4)

8 Mathematical Literacy/P1 8 DoE/November (a) 1 hour RG 1RG Reading from the graph (b) 60 km RG RG 2RG Reading from the graph (c) Dist (Mr Lebelo) Dist (Mr Goldman) 1M method RG RG 1RG reading from graph or table = 100 km 90 km 1RG reading from graph or table = 10 km 4.2 Cost of petrol = 10 journeys 8 l R8,23 per l = R658,40 1A Number of journeys 1M multiplication (4)

9 Mathematical Literacy/P1 9 DoE/November 2009 Question 5 [18] ,51 ; 7,51 ; 7,64 ; 7,71 ; 7,81 ; 7,91 ; 8,05 ; 8,22 2A ascending order ,51 metres 1A mode Range = 8,02 m 7,23 m 1M largest smallest = 0,79 m Lowest jump = 7,23 m 1CA solution 1A lowest jump ,23 m = 7, cm = 723 cm 1C conversion 1CA answer in cm 1M method 1A solution Charles 2A solution 5.2 V = 9 m 2,75 m 0,07 m = 1,7325 m 3 C 7,64+ 7,82 Median = m 2 = 7,73 m SF 1SF substitution 1CA simplification ,733m August 1991 October 1968 A 1CA rounding off 1MA method = 22 years 10 months 1CA solution 23 years 1CA rounding off

10 Mathematical Literacy/P1 10 DoE/November 2009 QUESTION 6 [18] ,2% RG 1RG reading from table Difference = A correct values = (a) A = 100% 22,3% 60,2% 3,6% A 1CA difference 1MA correct values = 13,9% OR 1CA value of A A = 100% A = 13,9 % (b) B = A = MA adding correct values 1CA value of B

11 Mathematical Literacy/P1 11 DoE/November GRANT TYPES AS A PERCENTAGE OF TOTAL GRANTS RECEIVED 1A Old-age A Child support in A Disability in A Other Percentage Old-age Child support Disability Other = 32 RT S Types of grants (4) 1RT reading correct value for burial policy 1M dividing value by total 1S simplifying RT R960 R15,45 R24,50 R60,00 R30,00 R40,00 R86,40 = R703,65 ANSWER ONLY FULL MARKS 1RT correct values 1M method ANSWER ONLY FULL MARKS

12 Mathematical Literacy/P1 12 DoE/November 2009 QUESTION 7 [15] (a) A = SF 1 SF substitution into formula = 7 1CA value of A (b) 10 = 3 B + 1 SF 1 SF substitution into formula 3B = 9 S 1S simplifying equation B = 3 1CA value of B St Patrick s College RT RT 2RT reading from the table C2 RG 1RG reading from the map From Kokstad College travel in a NE direction along Brownlee Rd to Elliot St. Travel in a SE direction along Elliot St and turn right into Barclay Rd. Kokstad Rugby Club will be on the left. 2A correct directions South-east/North-west 1A correct direction cm represents cm Therefore, 5 cm would represent cm S = cm 1A scale interpretation 1M multiplication 1S simplification = m C 1C conversion (4) TOTAL: 150

NATIONAL SENIOR CERTIFICATE GRADE 12

NATIONAL SENIOR CERTIFICATE GRADE 12 NATIONAL SENI CERTIFICATE GRADE 12 MATHEMATICAL LITERACY P1 NOVEMBER 2009 MEMANDUM MARKS: 150 Symbol M MA CA A C S RT/RG SF O P R Explanation Method Method with accuracy Consistent accuracy Accuracy Conversion