CPT Day 1. Your Name. Partner s Name

Transcription

1 CPT Day 1 Your Name Partner s Name You will study students solutions to algebra equations. You should: 1. Describe each student s solution to your partner and finish labeling their steps. 2. Talk about the answers to the questions and then write your final answers. 3. Sometimes you will solve a problem using one of the student s ways. Sometimes, you will solve some problems on your own. 1

2 CPT Day 1 2

3 CPT Day 1 Jessica s Solution: 3(t 1) + 3(t 1) = 30 3t 3 + 3t 3 = 30 Distribute 3 s 6t 6 = 30 Combine 3t s and 3 s 6t = 36 Add on Both t = 6 Divide on Both Sammy s Solution: 2(x 3) = 8 2x 6 = 8 Distribute 2 2x = 14 Add on Both x = 7 Divide on Both 1. How do you know if each student solved her problem correctly? 2. Why did Jessica and Sammy both divide as their last step? 3

4 CPT Day 1 Jacob s Solution: 4(x 5) = 12 x 5 = 3 x = 8 Divide 4 on Both Add on Both Kerri s Solution: 4(t 5) + 3(t 5) = 14 7(t 5) = 14 Combine (t 5) s t 5 = 2 Divide on Both t = 7 Add on Both 3. Describe 2 ways that these two students steps solutions are similar. (1) (2) 4. To solve 4(y + 5) + 6(y + 5) = 42, whose first step would work better? Circle one: Jacob s Kerri s Explain your reasoning. GP1. Working with your partner, solve the following equation using Kerri s way. 6(x + 4) + 5(x + 4) = 22 4

5 CPT Day 1 SOLVE THESE PROBLEMS BY YOURSELF. Be sure to show your work. Then, check your answers with a teacher. 4(x 1) = 24 9 = 3(x 4) + 6(x 4) 5(x 3) = = 7(x + 1) + 3(x + 1) 5

6 CPT Day 1 Alexander s Solution: 8 = 2(n 6) 8 = 2n 12 Distribute 20 = 2n Add on Both 10 = n Divide on Both Angela s Solution: 9 = 5(m + 2) + 4(m + 2) 9 = 5m m + 8 Distribute 9 = 9m + 18 Combine -9 = 9m Subtract on Both -1 = m Divide on Both Complete the step labels for each solution in the blank spaces provided above. 5. Describe 2 ways these students solution steps are similar. (1) (2) 6. s problem is easier to solve because: 6

7 CPT Day 1 Colleen s Solution: 6(t + 5) = 18 t + 5 = 3 t = -2 Divide on Both Subtract on Both Sandra s Solution: 2(x + 3) + 6(x + 3) = 40 8(x + 3) = 40 Combine x + 3 = 5 Divide on Both x = 2 Subtract on Both Complete the step labels for each solution in the blank spaces provided above. 7. Could Colleen s first step be the first step on Sandra s problem? Circle one: YES NO Explain your reasoning. 8. If the problem was 8 = 3(j + 6) + 4(j + 2), could you use Sandra s first step? Circle one: YES NO Explain your reasoning. 7

8 CPT Day 2 PLEASE STOP HERE AND WAIT UNTIL WEDNESDAY: DAY 2 Do you have the same partner as yesterday? Please circle one. YES or NO. If not, please write your partner s name here: 7

9 CPT Day 2 Abby s Solution: 3(h 2) + 5(h 2) = 24 8(h 2) = 24 Combine h 2 = 3 Divide on Both h = 5 Add on Both Patrick s Solution: 5(y + 1) = 3(y + 1) + 8 2(y + 1) = 8 Subtract on Both y + 1 = 4 Divide on Both y = 3 Subtract on Both 9. Describe one way the students problems are the same and one way they are different. Same: Different: 10. Patrick s first step is different from Abby s first step because: GP2. Working with your partner, solve the following equation using Patrick s way. 6(x + 2) = 4(x + 2)

10 CPT Day 2 Matt s Solution: 10(x + 3) = 6(x + 3) x + 30 = 6x Distribute 10x + 30 = 6x + 34 Combine 4x + 30 = 34 Subtract on Both 4x = 4 Subtract on Both x = 1 Divide on Both Roger s Solution: 6(w 4) + 7(w 4) = 26 6w w 28 = 26 13w 52 = 26 13w = 78 w = 6 Distribute Combine Add on Both Divide on Both 11. Is Roger s way the same as Matt s way? Circle one: YES NO Explain your reasoning. 12. On a timed test, I would rather solve s problem because: 10

11 CPT Day 2 SOLVE THESE PROBLEMS BY YOURSELF. Be sure to show your work. Then, check your answers with a teacher (x + 1) = 8(x + 1) 2(y + 6) + 3(y + 6) = (x 2) = 7(x 2) 5(b 3) + 2(b 3) = 35 11

12 CPT Day 2 Elizabeth s Solution: 5(m + 4) = 2(m + 4) (m + 4) = 15 Subtract on Both m + 4 = 5 Divide on Both m = 1 Subtract on Both Jason s Solution: 21 = 7(x 2) 3 = x 2 Divide on Both 5 = x Add on Both 13. To solve 6(y + 3) = 4(y + 3) + 18, whose first step would work better? Circle one: Elizabeth s Jason s Explain your reasoning. 14. Describe 2 ways that these two students solution steps are similar. (1) (2) 12

13 CPT Day 2 Tia s Solution: 8 + 2(x + 5) = 6(x + 5) 8 + 2x + 10 = 6x + 30 Distribute 2x + 18 = 6x + 30 Combine 18 = 4x + 30 Subtract on Both -12 = 4x Subtract on Both -3 = x Divide on Both Peter s Solution: 3(w + 4) = 24 3w + 12 = 24 Distribute 3w = 12 Subtract w = 4 Divide on Both 15. Why did Tia and Peter both distribute as their first step? 16. How do you know if each student solved his problem correctly? 13

14 CPT Day 3 PLEASE STOP HERE AND WAIT UNTIL THURSDAY: DAY 3 Do you have the same partner as yesterday? Please circle one. YES or NO. If not, please write your partner s name here: 13

15 CPT Day 3 Brianna s Solution: 3(n 2) + 12 = 6(n 2) 12 = 3(n 2) Subtract on Both 4 = n 2 Divide on Both 6 = n Add on Both Matthew s Solution: 1 (x + 8) = 5 4 x + 8 = 20 x = 12 Divide on Both Subtract on Both 17. Could Brianna s first step be the first step on Matthew s problem? Circle one: YES NO Explain your reasoning. 18. If the problem was 8(j + 2) = 4(j + 8) + 12, could you use Brianna s first step? Circle one: YES NO Explain your reasoning. GP3. Working with your partner, solve the following equation using Matthew s way. 1 5 (x 4) = 2 15

16 CPT Day 3 Scott s Solution: 2(y 4) + 36 = 8(y 4) 2y = 8y 32 Distribute 2y + 28 = 8y 32 Combine 28 = 6y 32 Subtract on Both 60 = 6y Add on Both 10 = y Divide on Both Stacy s Solution: 1 (x + 2) = x + 2 = 4 Distribute x = 10 Subtract on Both 3 x = 10 Divide on Both 19. Describe 2 ways these students solution steps are similar: (1) (2) 20. s problem is easier to solve because: 16

17 CPT Day 3 SOLVE THESE PROBLEMS BY YOURSELF. Be sure to show your work. Then, check your answers with a teacher. 1 6 (x + 1) = 1 4(x 3) = 2(x 3) (x + 3) = 1 4(f + 5) + 18 = 10(f + 5) 17

18 CPT Day 3 Jarrod s Solution: 9 = 3(y + 5) + 6(y + 5) 9 = 9(y + 5) Combine 1 = y + 5 Divide on Both -4 = y Subtract on Both Peter s Solution: 2(t 1) + 20 = 7(t 1) 20 = 5(t 1) Subtract 4 = t 1 Divide on Both 5 = t Add on Both 21. Describe one way the students problems are the same and one way they are different. Same: Different: 22. Jarrod s first step is different from Peter s first step because: 18

19 CPT Day 3 Danielle s Solution: 18 = 4(r 1) + 2(r 1) 18 = 4r 4 + 2r 2 Distribute 18 = 6r 6 Combine 24 = 6r Add on Both 4 = r Divide on Both Johan s Solution: 9(w + 2) = 3(w + 2) w + 18 = 3w w + 18 = 3w w + 18 = 30 6w = 12 w = 2 Distribute Combine Subtract on Both Subtract on Both Divide on Both 23. Is Danielle s way the same as Johan s way? Circle one: YES NO Explain your reasoning. 24. On a timed test, I would rather solve s problem because: 19