MOLE CONCEPT (ADVANCED)

Transcription

1 FOUNDTION BUILDER (OBJECTIVE). (D). (D). (B) 4. () (Most stable isotope of carbo) 5. (D) 6. (C) MOLE CONCEPT (DVNCED) 7. () Moles of gas = Molecular weight of gas = Hece NO. 8. () Molecular weight of C60H Weight of a molecule =.9 g () mole cotais vogadro umber of atoms.. ().4 Moles of N Number of atoms = = (D) () (B) (C) (D).4 N (C) Number of gms of HSO CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE #

2 . (D) Moles of H 0.5 Volume of H i l = l. 4. (D) Moles of u = toms of u = () Mass of oe molecule of 44 CO (C) 0.4 Number of moles of H (B) 8. (B) WH 9g WN 4 4 g 9. (C) I oe HO molecule: proto, 8 eutros, electros 6g Hece i 6 ml, HO mols 8g / mol Protos = N 0 N 0. () atoms w. Hece it should be of same weight W at.wt. (B) N o. of moles = N wt mol.wt M g M mg 0 0. () : g ; B 6 8g ; C : g ; 6 D 8g. (D) :.55N.5 N ; B:N ; C : 4N N ; D.88N 4.4N. 4. (C) 5amu 4amu CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE #

3 5. (B) Oe io cotais: = e totales N 64 N 6. (D) wt = 6 g C 7. (C) 8 : 44 ; 46 B : 46 ; 6 C : 8 ; 54 D : 8 8. (D) 80 HO 8 o. of es N 0 N 9. (C).48 Na SO. 5HO H O molecules 0.05 N 0. (C) 90 g atom N (B) H O 8 54 (96 ) (8 8) = 9.. (C) 0.08 HO. Hece, molecules = N 8. () 4. N 0.. total = 0.8N.4N 4 4. (D).4 C CHO 0. 4 atom = 0. N 5. (B) 8.4 MgCO Each cotai ( ) protos Hece, total 0. 4N.5 4 CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE #

4 6. (B) total 0. molecules = 0.N (D) 4 (i) (ii) 00 8 (iii) 00 (iv) ml g water 8 8. (B) gas w w mol.wt. a 9. () Fe moles I 60 g carbo, C 5 twice = moles 40. (B) Say Mg PO ; the O = (B) w w x : y : : 0 4. (C) X X (C) I : O : : : Hece IO () mol. Wt = VD = 0 7 wchlorie 0 7g 0 9g wmetal CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 4

5 45. (D) CaCO CaO CO Quatity of limes toes = wt. of oe mole mole of CaCO = 0 kg 46. () Moles of HS. Moles of SO SO H S S H O 47. (C) moles give x.5 L.R. Moles of 0 Mg OH H PO Mg OH Mg PO 6H O Moles 4 4 Moles 6 Give Weight of HPO4 98.6g 48. (D) 4 wt 48 7g H O CH OH 49. () W g O 50. () with mole X 5mole'O' with.6 ' 'moles mole'o' gco g.7 Wg 8.g (D) CO CO 5 C H OH W 44 88g 5. (C) KClO KCl O CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 5

6 5. () Hece % loss i wt = 48g Fe H O iro W (B).6 CaCO CaO CaCl % of CaCl 0.% 55. (D) 56. () 57. (B) 58. (D) 59. (D) BaCl Na PO Ba PO 6NaCl 4 4 Moles (L.R.) 4 4 Ca OH H SO CaSO H O 0. LR 0.5 CaSO CaOH 0. 4 B C D 5 8 LR B C 4 B ; D : 4l C l C L.R give 4l 44 w 800g give 50 W B B C C 4D 4 D 4 CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 6

7 60. (C) Mol.wt M VD () D cl wrt air Dcl Mcl 7 D M 9 air 6. (B) Say NO X. The x 4 x 0 Moxide 46 Doxide wrt O.44 M 6. (B) molality 00 urea : NH C NH w solvet O air O 64. (D) Molarity V ml () 66. (D) 0 0. l 0.M 40 mole KMO4 5 moles FeSO4 V V ml 67. (B) 0 H o. of H N. 68. () molal mole NaOH i 00g solvet 00 vol 09mL d. Molarity V ml.009 CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 7

8 69. (B).6500 Molarity of NOCO 0. M fter dilutio of ml solutio = M () NaCl XNaCl NaCl HO 8 GET EQUIPPED FOR JEE MIN. () KClO KCl O, O l O lo O lo. () Cosider L solutio 9 d 00 HSO d =. g/ml. () : N H NH 5 LR 5 moles N 5 H 0 4. (C) 5. (C) 6. () Fe SO BaCl BaSO FeCl 4 4 :? BaCl FeCl BaCl 0.75 moles CuSO l l SO Cu 4 4 displaces 54g l 9g Cu displaces 7g l 96g CH4 O CO HO 5 8 CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 8

9 5 4 = ; CH 4 (remaiig) = CO 7. (C) X CH X O CO HO X Hece, 4 with X mole CH X moles 4 with.5 moles.5moles x.5 i.e. 4.5 x 4 8. (D) with 0g CaCO mole HCl with 5 L g 0.75M HCl g 9. (B).5 gcl Cl HCl VL Molarity Molarity (D) with X 6g Oxyge with g 0.6 g Oxyge 6 X (D) l O l O : with 7g l mole O with mole 7 8g. (D) (POC o S) BaSO SO S 4 CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 9

10 8 4. (B) NaBr, KBr say 0.97 gbr Br lso, W 9 0. g KBr 4. () 6g. : H 4 4 ; B : H g C : H. ; D : H (C) Total atoms = N N 0.05 N 6. (C) Mol. Wt of B For 5 mol, 46 5g =. kg 7. () 00 :N ; B : 4 D :.5N 7.5N N ; C N 9N 8. (D) (i) 5g (ii) (iii) (iv) () : N B : 6N 4 ; C : 8N 0 ; D : N 6 44 ; 0. (C) wt g 46. (D) CO 8, say. The O 6 4. () CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE #

11 : 0.4g.8g ; B : g 6g ; C : g ; D : 7 g. 6. (D) gram molecule: 44 g molecule of CO = 44 amu 4. () 4 H C : : 5 C H 5. (D) Total charge = N e Ne coulomb 6. (D) Mol.wt mol.wt (D) g H O 45g silica 4g others 8% H O 45g silica 4g others 0gorigial ' w 'grams 8 % of w = water i.e. 9 % of w = silica others Hece, 9 w 88g w % of silica 0 47% (C) MN. 8 % itroge 8 M 8 8 M (D) 0.04% mol.wt at.wt of N 0. () i.e M M 4 verage atomic mass = x = 9% 90 0 x x 0 0. CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE #

12 . (B).. M = Mole fractio of 8 O 8. (C) 6.0 Moles of Ca OH Moles of HCl = HCl Ca OH HCl CaCl H O L.R. Mole fractio of. ().595 Moles of CuSO Weight of solvet = = Volumes of solvet 8 L Molarity 0.M 8 6 O 6 4. (B) () (B) (C) (D) 8 atoms of O 6.0 ~ atoms of Be 6.0 ~ 9 8 atoms of C atoms of F (C) X Y X Y 0 80 : : XY (C) vogadro hypothesis 7. () Moles of magesium = Number of magesium atoms = atoms. 8. (D) CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE #

13 5 Moles of compho Number of atoms ( Molecule has 7 atoms) (D) Moles of e (B) Moles of g = 7. Moles of gs required = 7 7 Mass of gs (D) Mass of ore required = g.4 Moles of l = 7 7 l NaOH HO NalO H Moles Give excess.5 (L.R.) Vol. of H evolved = L. X. y give 0. For B : X X Y 40 0 FOUNDTION BUILDER (SUBJECTIVE) CH 0.moles 6 molecules 4 6 Each molecule has (6 + 4) = es total es 6 H O 8g mole 8g mol molecule has ( + 8) = es mole cotais N electros. O : e, 8protos,8 eutros per io. imole:n e,8 N protos, 8N eutros 5. Gram atomic mass = N mass of oeatom g 40 g CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE #

14 tomic mass = o. of atoms = wt wt of oe atom removed 44amu 7.5 g CO,remaiig mg 6.5 CO mole N 5 charge N e.88 C. 4 O SO moles 64 S Na S O.5H O 5 4 O : S 0.0 O NaNO NO mm N NaNO NO 6 = = t s 6 s t hr t yr.9 years 465. atomic wt = = 40 g/mol 4000 g 00 moles 40g / mol. C 6 g g / mol No. of atoms = C r = 0. ich = 0.54 cm 85.6 Fe ball 0 CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 4

15 V desity ball ball g 85.6 Fe 0.5g 0.455g Fe ad o. of atoms = = wt of atom = g starch starch 6. V.7 L NH NH L 7 7. PV O RT N.69 moleculs O 8. O O 600mL Vml 600 V ml V 600 V 48 g V = 00 ml 9. Elemet % (with i 0 g) o. of (i 0 g) atom ratio 40. K M 6.8 P KM P 0. Say O The H 5 70 d C C.5H5 O or CH0O is empirical formula Mol. Wt C H O weight g CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 5

16 weight 6.0 mol.wt. mol.wt 07.g C C 0.8 H 4.08 H N 7.97 N 0 C H N 5 4. C CO C H HO C H : : CH H 0 cylider r h desity 4. Co cylider Co Co o.of atoms Mol. Wt = wt of mole mix = VD = 76.6 (x mol. NO + ( x) mol. NO 4 ) = 76.6 g x 46 x x NO 46 i mole = mix i0 g 76.6 i0 0.5 NO = 0.47 mix 6. molality 00 solvet C Cosider L of solvet H5OH mol.wt 46 = 8 solvet CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 6

17 8 molality NaHCO Na CO CO H O Na CO oeffect loses 84g NaHCO 6g CO H O loses g g % of NaHCO 6.8% ad Na CO % 8. C H N O C H N O % of C atoms % 9. CHCHO O CHCOOH : 0g g : L.R () 0.45 CHCOOH CHCHO CHCOOH (B) (C) 0. CH 7.7g O left g O O.8 % yeild 0 87.% ad,say CH4 CH4 CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 7

18 ow, 6 8 5g 4.5 also, 0. CO ad CH %CH 4 60%. 5 5 %C H 40% 4. POC o carbo C KCO KZ Fe CN 6 moles of product K CO (POC o Cu Cu NO Cu ).H O product g 4. gno NaCl gcl NaNO L.R gcl gno gcl g 5. CaCO CaO CO MgCO MgO CO %CaCO % Cl KOH KCl KClO H O KCl O KCl KClO Cl KClO 4 Cl Cl Cl g CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 8

19 7. POC o Cl (evetually o completio) Cl KCl KClO4 4 Cl KCl moles 8. g g KClO moles KCl O KClO g g resiude O moles KClO %KClO % KCl 46.8 O CH lcl CH ycl x y 4 Cl gno gcl NO x.. CH4 CH lcl x y x. 6 5x 7 5.5y y.. gcl Cl CH lcl x y y x 7 5.5y x.99 y y i, 6 0y 7 5.5y y ad x 40. KClO KCl O () 6.5g Z HCl ZCl H () H O HO () i (), O KClO i (), 0.5 H O i (), CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 9

20 Z H 0.5 Z g 4. (): B, (B):, 7 7 (C): C B. 4. C O CO, CO POC o C C 0 POC o O : O ad 0.75 : : : CO CO 4. NaOH HSO4 Na SO4 H O NaOH 5 HSO HSO4 stregth 00 V ml HSO4 6.5g / L V ml 0 Molarity 00 0.M i gram / L g / L SO H 4 SO 0.00M o. of io 6 SO CuSO 4.5H O weight 4 Cu mol.wt g 47. MV MV MV Mfial M Molar 48. Molality 00 solvet CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 0

21 I 49. I C6H molal Say, we have mole mix. The, 0. ad 0.8 I C6H6 C6H6 I molality m Cosider L solutio. t solutio KCl solutio 6g 0 KCl Molailty 00 (ml) Vsolutio M %NH. 70%water. 70 i.e. solutio water 5g 0 0 i.e. solutio 50 50g Vsolutio 66.67mL desity Cosider L of solutio, solutio g M V 8 8moles ethaol ethaol ethaol molality 00 solvet molal 5. SO O SO SO SO SO FeS O FeO 8SO CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE #

22 So moles of FeO NH HCl Wt NH 47 68g 56. H O HO LR wt H O formed g wt H left g w w 6g gcl gbr %g %Cl % % Br % 59. COOH CO H Oubalaced H SO4 POC C CO COOH 90 9 V CO.4L 4.977L acid is H. salt is g moleg mole g g g mol.wt of g mol. wt wt of H CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE #

23 ONE OPTION CORRECT GET EQUIPPED FOR JEE DVNCE. () N H NH say, wt :4x x t o 4x x x 8 t t x x y y y NH was 40% by mol. i.e. X N 40 x x y y y y 0 x x 5y x y y.5 7 y x y x y x y x y (C) () (B) M ().4g ad MB (B) 0.8 MB M.4. (B) with.g metal 0.4g oxyge 64g metal oxyge g. 8g metal with 6g O i.e. MO 4. () with 4M 96g O. si ce X O with 5.7g 4.8g O MX (C) mol.wt 400 g 4 6 CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE #

24 wt mol.wt at.wt. 0 at.wt.g. mass of oe atom 5.5 g (C) PV 0.5. mol.wt RT i.e.. t.wt at.wt 6 wt of oe atom. N N 7. () I Cl ICl, ICl POC o I 5.4 (I) 7 POC o Cl 4. (Cl) 5.5 : : 8. (D) FeSO : SO ad Fe 4 4 Fe SO : SO ad Fe 4 4 give Fe Fe : 9. (D) 0.6M : V say ad 0.5M : Vsay MV MV Mfial 0.4 V V 6V 0.5V 0.4 V V V V or 0.4 V V V V V V V 0.09 V 0. 4 CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 4

25 . (C) t mass. (C) Fe FeCN 6 Fe C N mass of a atom g. (D) (i) g (ii) g (iii) 9 7g (iv) 80 g-molecule = 80 Moles g. (B) 6 : 4 4. () gatom moleof atom 4g. 5. (B) Na CO HCl NaCl H O CO V M HCl Na CO HCl HCl.4 V V 9mL (C) They must have same mol. wt. 7. () 4 6 V V 4 micro sphere sphere 8. (B) KClO KCl O o 0. KClO 0.5 % purity % 9. () V ml m moles BaCl.H O g CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 5

26 4 BaCl g 0. (B).6 V V.94mL. (B).5 0 t MC 6H5CH 9.g M 7 C6H5COOK. (C) CuSO 4.5HO, MgSO 4.7HO total t 5g ad ahydrous g ad 59.5 o solvig, ad CuSO 4.7HO..79g.7 %byt % 5. () C H O C H O C H O C H O : g 4g : L.R theoretical yield M C 9 H 8 O 4.69 %yeild 80.76% (B) XI Cl XCl I XI XCl M 8 M 6.5 M (B) o.of molecules 500cm 0.m VMolarity N 6 5 i.e.v.95 L () i ml CuCl, ad CuBr gbr ad gcl g ad g CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 6

27 7. () the ad cubr 0.5g 5% ad 58% XH 4 ad, say XH6 4 x XH4 XH6 i.e. 5 4 X ad X 4. X i.e. X 4 X X 4X or, X X 7.5 or X (B) M gno 0.05M ml gno gno NaBr NaSO th also, 4 5 t of portio 5 9. () Let acid be H Salt: Ba.HO Ba HSO4 BaSO4 H H 0. (B) total moles = (say) 0.5 moles of CHCOOH () NaOH CHCOOH V 8.5 LB NaOH C H.5O CO H O 6 moles CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 7

28 C H O CO H O 4 moles PV 40.8 RT also.5 O % % C H ad C H %. () % o. of atom ratio l K S O (B) Vmolecule mol. Wt N Vmol desity More tha oe correct. (BD) moles i L 50 g kg m 99kg (B) w Na S O 474 () % by weight 0 7.9% 50 (B) x (C) molality of Na 00 wsolvet (B) mol. wt = wt of.4 L=8.896 g mol. wt VD (BD) CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 8

29 4. (CD) [] : g [ B] 64 g [ D] : g Ca NO Na C O CaC O NaNO 4 4 millimoles : LR 6 5. (C). CaO CaCO w 0.00 g w CaCO CaCl 0.0. g w. g NaCl 6. (C) 0 m moles ; HCl 00m moles NaCl 00 m moles 00 Ca, 400Cl CaCl catio 600 aios Cl M (BD) Obvious,B,D 8. (BCD) mole NH wh W N 4 4 g 4 4 g molecule atoms 9. (B) Obvious : H 4 N 8 a 4 7 N. (BC) obvious others deped o volume. (CD) HCl NaOH NaCl H O Fial coc. Of NaCl M Solutios is eural so CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 9

30 H 7. (BC) MM Mass of oe molecule N No of molecules NO of Mole N. (D) (CD) Hece Mol. Wt Match the followig. I P, II, III - C, IV E (I) wt % of C 0 8.% 407 (P) 6 (II) wt % of H 0.47% 407 () (III) wt of H: wt of Cl 6 : (C) (IV) mo. of C: O =: (E). a S, b S, c- Q, d R wso (a) s W o (b) d 5 g ccsp. gr s (c) M VD Q (d) molecular at aos = 9(R) 44. a PS, b S, c PQ, d R 0 (a) l 0.04 M H Total =0. M Cl 0. M 500 (P), (S) 0 (b) K 0.M 0 0 Cl 0.M 0 (S) CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 0

31 (c) K 0.M 0 [ P], [Q] 6 SO M (d) wh SO H 4 SO4 0 H 00 5 M 00 SO M 00 [R] 4. - p,r,s B-p, C- p,q,r, D-s () VSO. L wso g total atoms N (B) H V H. L g,, total atoms N P wh (C) o. of atoms 0.5 N.5 N [P], [Q], [R] (D) moleo V.4 L toms wt g [S] COMPREHENSION TYPE Passage. (C) wt of atom 4 amu.66 g.. () 0 wt 00g. S HSO4. (B).4 M s M (B) C O Passage C C O 0 VO V air.4c Vair L 0 CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE #

32 . () Cosider L. KOH 6.9 KOH solu 86.4 solu 88g 0 d.889g / ml.. (C) 4 PV 0. MHSO 4 NH 00 RT M 0.06 HSO4. () V 40mL 600 V 4. () HS HSO 54 4 HSO V 0. 5 V 5L Passage. (D) 8g 6 mho g. () vogadro s law.. (C) obvious Mass is 6amu. 4. () obvious Passage 4. () gno NaCl gcl NaNO : gcl wt 4.88g. () H SO g INTEGER 4. (5) 0.5 mole N.N has e. CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE #

33 5moles.. () CO 44 C. () MCl : say. mol.wt M 6.5 Cl X X MCl X 0.5 Cl g 70 0.x M 6.5x 6.4 M s (Dulog petite s law) x x 6.5x 4. (4) Fe (5) x x 40.6x 5 x 0 6. () CH O CO HO or 4 7. () 440 mol.wt (6) 5 solu 0.g solu 6g 0 9. (4) Fe 0. (8) CO C6HO5 g algae g algae gstrach CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE #

34 gstrach POC o carbo 6 CO (C6HO 5 ) time g,(.7 g) POC o Co Co O 4 Co PPt Co ppt ppt Co mol.wt.5g EXPERTISE TTINERS Co Co g. a) (0.7), 90 (a) 0.5g Fe FeO 0 0.5gFe FeO wt of mix= g b) (0.74) (b) 0.5g Fe FeO O 0.74g Fe. (5.5) (i) gno gcl NaCl HCl (ii) NaClis ot affected.4 Cl gcl Now, 58.5 M gram CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 4

35 0.5 M ( C H Cl ) 4 y z CxHyClz O xco HO Cl 0. x CO 0.95 () x y 5.5Z y HO x y 5.5 z..() PV x y 5.5z RT Solvig, x ; y 4 ad z CH4Cl..() 5. Cosider mole mix t 55.4 N, NO, N O 4 Now, after heatig, NO 4 NO N O o. of moles = New verage mol. Wt Now, () also 0.6.() Solvig () ad (), 0.5,ad 0. 5 :: 4 6. IO HSO 5.8 HSO 7 48 w 9.9 g NaHSO I st 5.8 i IO 98 IO I IO M NaIO CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 5

36 IO V 0.L 00 ml M IO 7. gno KI KNO gi KI KIO 6HCl ICl KCl H O 0 MKI VKI KIO MKI 0 M 0.M KI KI, excess KIO Now, KI, excess m mole Origial KI m mole KIused 5m mole gno KI used 5mmole w (gno ) 0.85g purity 85% 8. Let % of boro will at. Wt..0 = x Let % of boro will at. Wt..0 = (0 x) x.0 0 x x = 0% 9. Let NaCl = w gms kcl = (8 w) gms POC o Cl w 0.8 w 0.45 M M M Nacl kcl gcl w 0.8 w w = 0.08 gm Nacl = 0.08 gm kcl = gm acl kcl. C x H y. POC o Na; moles of Na O = moles of NaCl Na O ; ko Weight of Na O 6 0.0gm. Weight of ko % Na O =.58%. % k o =.6 % CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 6

37 y C H x y xo xco H O x y POC o carbo 5x vol.of CO Now vol. of CO = ml (that obtaied by koh) x = Vol. of O reactioary = 5 ml Vol. of O reacted = 5 ml ml of C x H y react with ( + y/x) ml O 5 ml of C x H y react with ( + y/x) = ml 5 (give) y = 4 formula = C H 4. (a) CO C CO POC o carbo Let CO = x l CO = ( x) l x x.6 x =.6 = x = 0.4 l & ( x)0.6 L (b) The molecular formula = M N 4 % Nitroge = 0 8 x 4 Where x = atomic wt of metal 0 8 x 4 moobromiatio. CH5 pat 85%yeildC 90%yield 4H 55gm POC o carbo x x = 74.7 gms 74.7 V.4L 55.5L 0. (.7 g) Heatig below C coverts PbNO ito PbO but to NaNOito NaNO as: PbNO PbOs NO O MW: 0 NaNO NaNO s O CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 7

38 MW: Weight loss 5.4g 0 Weight of residue left 5.4.6g Now, let the origial mixture cotai x g of Pb NO 0g PbNO gives g PbO x g Pb NO will give x g PbO 0 Similarly, 85g NaNOgives 69g NaNO 5 xg NaNO will give Residue : x 69 5 x.6g x g NaNO 85 Solvig for x gives, x.g Pb NO NaNO. 7g. 4. Molarity of solutio = 0.5 M molality = 0.4 m Mole fractio of Na SO 4 = Molar mass of Glauber salt Na SO.H O g mole of Na SO 4.H O i.0 L solutio molarity of solutio 0.5M lso, weight of.0 L solutio 77.g Weight of NaSO4i.0 L solutio g weight of water i.0 L solutio molality m g m Iitial millimol of CHCOOH Millimol of CHCOOH remaiig after adsorptio millimol of CHCOOH adsorbed umber of molecules of CHCOOH adsorbed CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 8

39 area covered up by oe molecule m 6. () Partial pressure of N 0.00 atm, T 98K, V.46 dm From ideal gas law: pv RT pv N RT No. of molecules of N 6.0. () Now, total surface sites available Surface sites used i adsorptio Number of sites Sites occupied per molecules Number of molecules Molarity V solutio solute Lt V solutio is affected by Temperatuere CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 9 6 WINDOW TO JEE MIN. (C) 560 Fe 56 No. of atoms = N 70 I 70 g of N o. of atoms = N 5 N 4 0 I 0 g of H o. of atoms = N 0 N. () Mole ratio of C : H : N 9.5 : : 4 : : 4 4 : 4 : Empirical formula CH4N Empirical formula mass

40 8 54 Molecular formula CH 4N C6H8N 4. (D) BCl H B 6HCl o.of moles of H o. of moles of B.6 No. of moles of H.8 Volume of H.4 L 67.L (Molar volume of ay gas at N.T.P =.4 L) 5. (B) 6.0 N 0. Molarity (C) mole is defied as umber of atoms preset i g C ad i.e Sice this umber remais uchaged, mass of mole substace will remai uchaged. 7. (C) V = L Wtotal g N solute =.05 W SOLUTE = W = 0 = 897 g solvet.05 molality (B) o. of moles of oxyge atom 8 o. of moles of Mg PO 4 No. of moles of Mg PO 4 9. () V = L N solute =.6 W solute = w total g desity 00 =. g/ml (C) l s 6HCl aq l aq 6Cl aq H g Per mole of HCl, o. of moles of CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 40

41 H formed Volume of H at STP. (B) Molality 5. m. i.e. if wt. of HO 00gm the o. of moles of CHOH XCHOH (Old data NTP).L. (C) 00 Volume of solutio m.5 m Molarity.05M 60. (C) Molarity M 4. () weight Number of atoms N species atomic weight I 4 g of hydroge Number of atoms 4 N 4N [Here species = because hydroge is preset as H ] I 70 g of chlorie = N Number of atoms = 70 N N 7 [Here chlorie is take as Cl ] I 7 g of iodie, 7 Number of atoms = N N 54 [Here iodie is take as I ] I 48 g of magesium, 48 Number of atoms = N N 4 [Here Mg is preset as Mg so species = ] Thus, the umber of atoms are largest i 4 g of hydroge. 5. (B) Heavy water is D O I it, Number of p 8 CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 4

42 Number of e 8 0 Number of 8 (D has 0 because it is actually, H ) 6. (D) 8 g H O cotais g H 0.7 g H O cotais 0.08 g H. 44 g CO cotais g C.08 g CO cotais 0.84 g C C : H : 0.07 : :8 Empirical formula = C 7 H 8 7. (C) M solutio meas moles of solute (NaCl) are preset i 00 L of solutio. Mass of solutio = volume of solutio desity 00.5 = 5 g Mass of solute = No. of mole molar mass of NaCl 58.5g = 75.5 g Mass of solvet = (5 75.5)g = 76.5 g =.076 kg moles of solute Molality mass of solvet i kg.79m () MV MV Fial cocetratio, M V V M 9. (B) NO O W O M O W O M N 8 N W M W M 4 N N N N N O 7 0. (B) BaCl HSO4 BaSO4 HCl 0.8gm 4.9gm 0.05mole mole mole 0.05 gm mole 0.05mole.65gm CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 4

43 . (B) 00 Volume of solutio ml. 00ml 00 Molarity M (D) Molecular mass of compoud 6 gm 4 % of H i NH4 0.5%. () No. of moles of acetic acid adsorbed by gm charcoal (C) Wt. adsorbed by gm 4 9 mole gm 0.054gm Wt. adsorbed per gram gm 8mg B C BC = 6 mole 60 mole 0.06 mole 0.mole C is limitig reaget No. of moles of BC formed 0.0 Wt. of BC formed 4.8gm 4.8 Molecular wt. of BC x x (B) BaCl.xHO 8x x x x x 6. (B) 8 0 x x (B) CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 4

44 y y CxHy x O xco HO y x y x 5 4 C H 8. (C) Weight of a compoud i gram w Molar mass M WINDOW TO JEE DVNCED Number of molecules N vogadro umber N N O w O.. (i) d N N N w N. (ii) 8 N Dividig Eq. (i) by Eq. (ii) gives N O w O N N w N 4 CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 44 Number of moles. () I a eutral atom, atomic umber represets the umber of protos iside the ucleus ad equal umber of electros aroud it. Therefore, the umber of total electros i molecule of CO, electros preset i oe carbo atom electros preset i oe oxyge atom () Number of molecules preset i 6g of water 6 N N 8 Number of molecules preset i 8g of CO 8 N N 8 Number of molecules preset i 46g of CH5OH 46 N N 46 Number of molecules preset i 54g of NO 5 54 N 0.5N 8

45 Here N is vogadro s umber. Hece, 6 g of water cotai the largest N molecules. 4. () The balaced chemical reactio of zic with sulphuric acid ad NaOH are Z H SO ZSO H g 4 4 Z NaOH HO Na Z OH H 4 g Sice oe mole of H umber of g is produced per mole of zic with both sulphuric acid ad NaOH respectively, hydroge gas is produced i the molar ratio of : i the above reactios. 5. () Ulike other metal carboates that usually decomposes ito metal oxides liberatig carbo dioxide, silver carboate o heatig decomposes ito elemetal silver liberatig mixture of carbo dioxide ad oxyge gas as Heat g CO s g s CO g O g MW 76g 8 6g Hece,.76g of gco o heatig will give g g as residue (D) The balaced chemical reactio is BaCl Na PO Ba PO 6NaCl 4 4 I this reactio, moles of BaCl combies with moles of NaPO 4. Hece, 0.5 mole of BaCl require mole of Na PO 4 Sice available Na PO 4 0. mole is less tha required mole (0.), it is the limitig reactat ad would determie the amout of product Ba PO 4 Na PO gives mole Ba PO moles of 4 0. mole of NaPO4 would give 0. 0.mole Ba PO () Molality of a solutio is defied as umber of moles of solute preset i.0kg (00 g) of solvet. 8. (D) Molality is defied i terms of weight, hece idepedet of temperature. Remaiig three cocetratio uits are defied i terms of volume of solutio, they depeds o temperature. 9. (D) Mass of a electro 9.8 kg kg electro CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 45

46 kg 9.8 electros mole of electros () Number of atoms = umber of moles vogadro s umber Number of atoms i 4 g C 4 N N Number of atoms i 56 g of Fe 56 N N 56 Number of atoms i 7 g of l 7 N N 7. (B) From the give relative abudace, the average atomic weight of Fe ca be calculated as (C) Moles of solute M 00 Vol of solutio m Moles of solute 60 mass of solutio Vol. of solutio desity M (C) WO W 4 N O O N N w w N : N : 7 : O N O N N CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 46

47 FILL IN THE BLNKS. (C- isotope) Carbo - isotope. ccordig to moder atomic mass uit, oe atomic mass uit (amu) is defied as oe twelfth of mass of a atom of C isotope, ie, amu u weight of a atom of C isotope.. (6.0 4 ) Cosiderig desity of water to be.0g ml, 8mL of water is 8 g (.0 mol) of water ad it cotai vogadro umber of molecules. lso oe molecule of water cotai (oe from each H atom) + 8 (from oxyge atom) electros..0mole of HO cotai 6.0. (0.4 m) Molarity Number of moles of solute Volume of solutio i litre Weight of solute 00 Molar mass Volume i ml M electros. 4. (4.4g) Molar mass of CuSO 4.5HO g lso, molar mass represets mass of vogadro umber of molecules i gram uit, therefore, 6.0 molecules of CuSO 4.5H O weigh 49.5 g molecules will weigh INTEGER TYPE. (8) % by mass 9. Moles of solute M 00 Vol. of solutio m. (4) MV M V V V 8m. Boltzma costat, 4.4g 6.0 R k or R k N N = 8.74 J K 8. Hece, o. of sigificat figures is 4 CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 47

48 . (8) Mass of L solvet = 0.4gmL ml = 400 g = 0.4 kg Mole of solute. So molality (m) Mass of solvet (kg) 0.4 = 8 m 4. (9) m molality M molarity Msolvet 0.M solute 0.9Msolvet M M 9M M M solvet solute solvet solute solvet 9 CENTERS: MUMBI / DELHI / KOL / KOLKT / LUCKNOW / NSHIK / GO / PUNE # 48