Classes at: - Topic: Mole Concept, Volumetric & Redox Titration

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01) To prepare a solution that is 0.0 KCl starting with 100 ml of 0.0 KCl (a) Add 0.7 g KCl (b) Add 0 ml of water Add 0.10 mole KCl (d) Evaporate 10 ml water 0) 10.78 g of H PO in 0 ml solution is 0.

1 01) To prepare a solution that is 0.0 KCl starting with 100 ml of 0.0 KCl (a) Add 0.7 g KCl (b) Add 0 ml of water Add 0.10 mole KCl (d) Evaporate 10 ml water 0) g of H PO in 0 ml solution is 0.0 N. Thus this acid. (a) Has been neutralised to HPO (b) Has been neutralised to PO Has been reduced to HPO (d) Has been neutralised to H PO 0) How many equivalents are there per mole of H S in its oxidation to S? (a) (b) 6 (d) 8 0) In hot alkaline solution, Br disproportionates to Br and BrO Br + 6OH Br + BrO + H O hence equivalent weight of Br is (molecular weight = ) (a) (b) (d) PHYSICAL CHEISTRY by: SHAILENDRA KR. Classes at: eq. Approach SCIENCE TUTORIALS; Opp. Khuda Baksh Library, Ashok Rajpath, Patna PIN POINT STUDY CIRCLE; House No. A/6, Opp. ahual Kothi, Alpana arket, Patna Topic: ole Concept, Volumetric & Redox Titration 6 weight of solute, d = density g/ml) m 1 (a) + = d (b) = 1000 d m Both true (d) None is true 06) aximum no. of mole of PbSO that can be precipitated by mixing 0.00 ml of 0.1 Pb (NO ) and 0.00 ml of 0.1 Na SO will be (a) 0.00 (b) (d) ) [Na+] in a solution prepared by mixing 0.00 ml of 0.1 NaCl with 70 ml of 0.1 Na SO is : (a) 0.1 (b) (d) ) When 80 ml of 0.0 HCl is mixed with 10 ml of 0.1 KOH, the resultant solution is the same as a solution of (a) 0.16 KCl and 0.0 HCl (b) 0.08 KCl 0.08 KCl and 0.01 KOH (d) 0.08 KCl and 0.01 HCl 09) Equal volumes of 0.00 HCl and 0.00 KOH are mixed. The concentration of the principal ions in the resulting solution are : (a) [K + ] = 0.00, [Cl ] = 0.00, [H + ] = ) (molarity) and (molality) are related to (b) [K + ] = 0.00, [Cl ] = 0.100, each other by equation (m = molecular 1. Opp. Khuda Baksh Library, Ashok Rajpath, Patna Page No.: 1

2 [OH ] = [K + ] = 0.100, [Cl ] = 0.100, [OH ] = (d) [K + ] = 0.00, [Cl ] = 0.100, [OH ] = ) ass of KHC O (potassium acid oxalate) required to reduce 100 ml of 0.0 KnO in acidic medium (to n + ) is x g, and to neutralise 100 ml of 0.0 Ca(OH) is y g then, (a) x = Y (b) x = Y x = y (d) None is correct 11) H (l) H O(l) + (g) 100 ml of X molar H gives L of g under the condition when 1 mole occupies L, value of X is (a). (b) (d) 0. 1) If equal volumes of 1 KnO and 1 K solutions are allowed to oxidise Fe(II) to Fe(III), then Fe(II) oxidised will be (a) ore by KnO (b) ore by K Equal in both case (d) Data is incomplete 1) 100 ml of 1 KnO oxidised 100 ml of H in acidic medium (when no is reduced to n + ); volume of same KnO required to oxidise 100 ml of H in basic medium (when no is reduced to no ) will be (a) 100 ml (b) 00 ml 00 ml (d) 100 ml 1) 10 ml of H solution(volume strength= x) required 10 ml of N/0.6 no solution in acidic medium. Hence x is : 1) Aqueous solution of chloride of an element A containing 1 10 mole after complete hydrolysis required 0 ml of 0.1 AgNO solution to form AgCl. Element A is (a) Al (b) P Si (d) S 16) olality of 18 H SO (d = 1.8 g ml 1 ) is : (a) 6 mole kg 1 (b) 00 mole kg 1 00 mole kg 1 (d) 18 mole kg 1 17) 10 L of hard water required 0.6 g of lime(cao) for removing hardness. Hence temporary hardness in ppm of CaCO (parts per million i.e ) is: (a) 100 (b) (d) 0 18) 1 g equiv of a substance is the weight of that amount of a substance which is equivalent to (a) 0. mole of (b) 0.0 mole of 1 mole of (d) 8 mole of 19) In an experiment, 0 ml of 0.1 solution of a metallic salt reacted exactly with ml of 0.1 solution of sodium sulphite. In the reaction SO is oxidised to SO. If the original oxidation number of the metal in the salt was, what would be the new oxidation number of the metal (a) 0 (b) 1 (d) 0) 0 ml pf x HCl neutralises completely 10 ml of 0.1 NaHCO and a further ml of 0. Na CO solution to methyl orange end point. The value of x is (a) (b) (d) ) The density of 1 solution of NaCl is 1.08 g/ml. The molality of the solution is (a) 1.08 (b) (d) 0.08 (a) 0.6 (b).6 ) RH (Ion exchange resin) can replace Ca (d) 10.0 in hard water 1. Opp. Khuda Baksh Library, Ashok Rajpath, Patna Page No.:

3 RH + Ca + R Ca + H + 1 L of hard water after passing through RH has PH. Hence hardness in ppm of Ca + is (a) 00 (b) (d) 1 ) 1 mole NaF + mole H SO resulting mixture will be neutralised by (a) 1 mole KOH (b) mole Ca(OH) mole NaOH (d) mole KOH ) 10 ml of NaHC O solution is neutralised by 10 ml of 0.1 NaOH solution 10 ml of same NaHC O solution is oxidised by 10 ml of KnO solution is acidic medium. Hence molarity of KnO is (a) 0.1 (b) (d) 0.0 ) For a given mixture of NaHCO and Na CO, volume of a given HCl reauired is x ml of with phenolphthalein indicator and further y ml required with methyl orange indicator. Hence volume of Hcl for complete reaction of NaHCO is (a) x (b) x/ y (d) (y x) 6) 1 mole of ferric oxalate is oxidised by x mole of no and also 1 mole of ferrous oxalate is oxidised by y mole of no in acidic medium.the ratio x/y is (a) : 1 (b) 1 : : 1 (d) 1 : 7) 0 ml of 0.0 solution of sesquicarbonate (Na CO.NaHCO.H O)is titrated against0.0 HCl. x ml of HCl is used when phenolphthalein is the indicator and y ml of HCl is used when methyl orange is the indicator in two separate titrations, hence (y x) is acidic medium. Hence mole fraction of FeSO in the mixture is (a) 80 ml (b) 0 ml AB (d) AB 10 ml (d) None ) The hydrated salt Na SO.nH O, undergoes % loss in weight on heating and becomes 8) mole of a mixture of FeSO and Fe (SO ) anhydrous. The value of n will be : required 100 ml of KnO solution is 1. Opp. Khuda Baksh Library, Ashok Rajpath, Patna Page No.: (a) 1 (b) (d) 9) In the following reaction : 8NO + As S + H O 6AsO +8NO+ 9SO + 8H + equivalent weight of As S (with nolecular weight ) is (a) (b) (d) 8 0) In the following reaction : Cr(OH) + OH + IO CrO + H O + I (a) IO is oxidising agent (b) Cr(OH) is oxidised 6e are being taken per 1 atom (d) All true 1). g of CO is dissolved in 10 ml of 1 N HCl. Unused acid required 100 ml of 0. N NaOH. Hence equivalent weight of is (a) (b) 1 (d) 1 ) Equivalent weight of H P when it disproprotionates into PH and H PO is (mol. wt. = ) (a) (b) (d) ) An element A (at. wt. = 7) and B (at. wt. = ) combine to form a compound. The compound contains 7% A by weight. The formula of the compound will be : (a) A B (b) A B

4 1. Opp. Khuda Baksh Library, Ashok Rajpath, Patna (a) (b) 7 (d) 10 ) 100 ml of PH when decomposed produces phosphorus and hydrogen. The change in volume is : (a) 0 ml increase (b) 00 ml decrease 900 ml decrease (d) None 6) What is the weight of oxygen that is required for the complete combustion of.8 kg of ethylene : (a).8 kg (b) 6. kg 96.0 kg (d) 9.6 kg 7) When 100 g of ethylene polymerizes to polyethylene according to the equation, nch =CH ( CH CH ) n. The weight of polyethylene produced will be : (a) n g (b) 100 g 100 g n (d) 100n g 8) A mixture containing 100 g H and 100 g is ignited so that water is formed according to the reaction, H + H O; How much water will be formed : (a) 11 g (b) 0 g g (d) 00 g 9) ml of N HCl, 0 ml of N/ H SO and 0 ml of N/ HNO are mixed together and volume made one litre. The normality of the resulting solution is : (a) N/ (b) N/10 N/0 (d) N/0 0) 1000 g aqueous solution of CaCO contains 10 g of calcium carbonate. Concentration of solution is : (a) 10 ppm (b) 100 ppm 1000 ppm (d) ppm 1) 1.0 g of pure calcium carbonate was found to require 0 ml of dilute HCl for complete reactions. The strength of the HCl solution is given by : (a) N (b) N 0. N (d) 0. N ) What will be the normality of a solution obtained by mixing 0. N and 0.60 N NaOH in the ratio : 1 by volume : (a) 0. N (b) 0. N 1.0 N (d) 0.1 N ) 100 ml each of 0. N NaOH, N/ HCl and N/10 H SO are mixed together. The resulting solution will be : (a) Acidic (b) Neutral alkaline (d) None of these ) The molarity of pure water is : (a).6 (b) (d) 18 ) H PO is a tribasic acid and one of its salts is NaH PO. What volume of 1 NaOH should be added to 1 g NaH PO (mol.wt. 10) to exactly convert it into Na PO : (a) 100 ml (b) 00 ml 00 ml (d) 80 ml 6) The pair of species having same percentage of carbon is : (a) CH COOH and C 6 H 1 O 6 (b) CH COOH and C H OH HCOOCH and C 1 H O 11 (d) C 6 H 1 O 6 and C 1 H O 11 7) On analysis a certain compound was found to contain iodine and oxygen in the ratio g of iodine and 80 g of oxygen. The atomic mass of iodine is 17 and that of oxygen is 16. Which is the formula of the compound : (a) IO (b) I O I (d) I O 8) The vapour density of pure ozone would be : (a) 8 (b) (d) 16 Page No.:

5 9) The haemoglobin from the red blood corpuscles of most mammals contains approximately 0.% of iron by weight. The molecular weight of haemoglobin as 67,00. The number of iron atoms in each molecule of haemoglobin is (atomic weight of iron = 6 ) : (a) (b) (d) 0) A person has as many as notes as number of oxygen atoms in.8g Na S O.H O (m.wt. = 8.0). A note counting machine counts 60 million notes per day. How much day would be taken to count these notes : (a) (b) (d) 10 1 Subjective 01.) PenicillinV was treated chemically to convert sulphur to barium sulphute. An 8.19 mg sample of penicillin gave.6 mg BaSO. What is the percentage of sulphur in penicillinv? If there is one sulphur atom in the molecule, what is the molecular weight? 0) Calcium carbide, CaC, used to produce acety lene, C H, is prepared by heating calcium ox ide, CaO and carbon to high temperature. CaO(s) + C(s) CaC (s) + CO(g) If a mixture contains 1.1 kg of each reactant, how many grams of calcium carbide can be prepared? 0) Atoms of the element A (atomic mass = ) are spherical. If each atom is at the corner of a cube in contact (Fig.), calculate length Of the cube (d = 6. g cm ) A 0) A plant virus is found to consist of uniform cylindrical particales of 10 Å in a diameter and 000 Å long. The specific volume of the virus is 0.7 cm / g. If the virus is considered to be a single prticle, find its molecular weight. 0) The reaction C + CO is carried out by taking g of carbon and 96 g. Find out : (a) Which reactant is left in excess? (b) How much of it is left? How many mole of CO are formed? (d) How many g of other reactant should be taken so that nothing is left (as reactant) at B the end of the reactant? 06) What mass of K is required to produce from excess oxalic acid H C O,.00 L C at 7ºC and 1.07 atm pressure? (Cr =, K = 9) + C O + 1H + 6C + Cr + + 7H O 07) Two acids, A and B, are titrated separately. ml of 1N Na CO solution requires 10 ml of A and 0 ml of B for complete neutralisation. What volume of A and B would you mix to produce one litre of 1 N acid solution? 08) What mass of Na SO must have been present in a sample that required 6.0 ml of KnO for its oxidation to Na SO in acidic solution? 09) 0 ml of an acidified solution of 1. N no ions, 1 ml of 0. N oxalic acid and 1 ml of 0. N ferrous salt solution are added together. Find the molarities of no and Fe + ions in the final solution? 10) 0 ml of xhcl neutralises completely 10 ml of 0. NaHCO and further ml of 0. Na CO to phenolphalein end point. What is value of x? NEW APPROACH OF PHYSICAL CHEISTRY BY ILLIEQUIVALENT ETHOD ByShailendra Kumar 1. Opp. Khuda Baksh Library, Ashok Rajpath, Patna Page No.:

6 A n s w e r s Objective: 1. a 1. b 1. c. a,c. a. b. c. b,c. c. c. c. a. c. d. c 6. a 6. a 6. a 7. d 7. a 7. d 8. c 8. a 8. c 9. c 9. d 9. c 10. b 0. d 0. c 11. a 1. a 1. b. d 1. b. d 1. d. d 1. a. a 16. c 6. d 17. b 7. b 18. a 8. a 19. c 9. d 0. c 0. d Subjective: %,9. g mol kg. AB =.7A g mol 1. (a) (B) mol (6g) mol CO(6g) (d) 6 mol C(7g) gm K 7. Volume of acid A = 0. lit. Volume of acid B = 0.8 lit gm 9. [no ] = 0.10,[Fe + ) = X = Opp. Khuda Baksh Library, Ashok Rajpath, Patna Page No.: 6

Topic: Mole Concept. (At. mass, Ba= 137) will be

Topic: Mole Concept. (At. mass, Ba= 137) will be PHYSICAL CHEMISTRY by: SHAILENDRA KR. Meq. Approach Classes at: - SCIENCE TUTORIALS; Opp. Khuda Baksh Library, Ashok Rajpath, Patna PIN POINT STUDY CIRCLE; House No. 5A/65, Opp. Mahual Kothi, Alpana Market,