3.9 Stoichiometric Calcs: Amounts of Reactants and Products
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1 3.9 Stoichiometric Calcs: Amounts of Reactants and Products
2 Law of Conservation of Mass The Law of Conservation of Mass indicates that in an ordinary chemical reaction, Matter cannot be created nor destroyed. No change in total mass occurs in a reaction. Mass of products is equal to mass of reactants. Copyright Houghton Mifflin Company. All rights reserved. 3 2
3 Conservation of Mass 2 moles Ag + 1 moles S = 1 mole Ag 2 S 2 (107.9 g) + 1(32.1 g) = 1 (247.9 g) g reactants = g product Copyright Houghton Mifflin Company. All rights reserved. 3 3
4 Reading Equations In Moles Consider the following equation: 4 Fe(s) + 3 O 2 (g) 2 Fe 2 O 3 (s) This equation can be read in moles by placing the word moles between each coefficient and formula. 4 moles Fe + 3 moles O 2 2 moles Fe 2 O 3 Copyright Houghton Mifflin Company. All rights reserved. 3 4
5 Writing Mole-Mole Factors A mole-mole factor is a ratio of the moles for any two substances in an equation. 4Fe(s) + 3O 2 (g) 2Fe 2 O 3 (s) Fe and O 2 4 moles Fe and 3 moles O 2 3 moles O 2 4 moles Fe Fe and Fe 2 O 3 4 moles Fe and 2 moles Fe 2 O 3 2 moles Fe 2 O 3 4 moles Fe O 2 and Fe 2 O 3 3 moles O 2 and 2 moles Fe 2 O 3 2 moles Fe 2 O 3 3 moles O 2 Copyright Houghton Mifflin Company. All rights reserved. 3 5
6 Learning Check Consider the following equation: 3 H 2 (g) + N 2 (g) 2 NH 3 (g) A. A mole-mole factor for H 2 and N 2 is 1) 3 moles N 2 2) 1 mole N 2 3) 1 mole N 2 1 mole H 2 3 moles H 2 2 moles H 2 B. A mole-mole factor for NH 3 and H 2 is 1) 1 mole H 2 2) 2 moles NH 3 3) 3 moles N 2 2 moles NH 3 3 moles H 2 2 moles NH 3 Copyright Houghton Mifflin Company. All rights reserved. 3 6
7 Solution 3H 2 (g) + N 2 (g) 2NH 3 (g) A. A mole-mole factor for H 2 and N 2 is 2) 1 mole N 2 3 moles H 2 B. A mole-mole factor for NH 3 and H 2 is 2) 2 moles NH 3 3 moles H 2 Copyright Houghton Mifflin Company. All rights reserved. 3 7
8 Calculations with Mole Factors How many moles of Fe 2 O 3 can form from 6.0 mole O 2? 4Fe(s) + 3O 2 (g) 2Fe 2 O 3 (s) Relationship: 3 mole O 2 = 2 mole Fe 2 O 3 Write a mole-mole factor to determine the moles of Fe 2 O mole O 2 x 2 mole Fe 2 O 3 = 4.0 mole Fe 2 O 3 3 mole O 2 Copyright Houghton Mifflin Company. All rights reserved. 3 8
9 Guide to Using Mole Factors Copyright Houghton Mifflin Company. All rights reserved. 3 9
10 Learning Check How many moles of Fe are needed for the reaction of 12.0 moles O 2? 4 Fe(s) + 3 O 2 (g) 2 Fe 2 O 3 (s) 1) 3.00 moles Fe 2) 9.00 moles Fe 3) 16.0 moles Fe Copyright Houghton Mifflin Company. All rights reserved. 3 10
11 Solution 3) 16.0 moles Fe 12.0 moles O 2 x 4 moles Fe = 16.0 moles Fe 3 moles O 2 Copyright Houghton Mifflin Company. All rights reserved. 3 11
12 Steps in Finding the Moles and Masses in a Chemical Reaction Copyright Houghton Mifflin Company. All rights reserved. 3 12
13 Moles to Grams Suppose we want to determine the mass (g) of NH 3 that can form from 2.50 moles N 2. N 2 (g) + 3 H 2 (g) 2 NH 3 (g) The plan needed would be moles N 2 moles NH 3 grams NH 3 The factors needed would be: mole factor NH 3 /N 2 and the molar mass NH 3 Copyright Houghton Mifflin Company. All rights reserved. 3 13
14 Moles to Grams The setup for the solution would be: 2.50 mole N 2 x 2 moles NH 3 x 17.0 g NH 3 1 mole N 2 1 mole NH 3 given mole-mole factor molar mass = 85.0 g NH 3 Copyright Houghton Mifflin Company. All rights reserved. 3 14
15 Learning Check How many grams of O 2 are needed to produce mole Fe 2 O 3 in the following reaction? 4 Fe(s) + 3 O 2 (g) 2 Fe 2 O 3 (s) 1) 38.4 g O 2 2) 19.2 g O 2 3) 1.90 g O 2 Copyright Houghton Mifflin Company. All rights reserved. 3 15
16 Solution 2) 19.2 g O mole Fe 2 O 3 x 3 mole O 2 x 32.0 g O 2 = 19.2 g O 2 2 mole Fe 2 O 3 1 mole O 2 mole factor molar mass Copyright Houghton Mifflin Company. All rights reserved. 3 16
17 Calculating the Mass of a Reactant The reaction between H 2 and O 2 produces 13.1 g water. How many grams of O 2 reacted? 2 H 2 (g) + O 2 (g) 2 H 2 O(g) The plan and factors would be? g 13.1 g g H 2 O mole H 2 O mole O 2 g O 2 molar mole-mole molar mass H 2 O factor mass O 2 Copyright Houghton Mifflin Company. All rights reserved. 3 17
18 Calculating the Mass of a Reactant The setup would be: 13.1 g H 2 O x 1 mole H 2 O x 1 mole O 2 x 32.0 g O g H 2 O 2 moles H 2 O 1 mole O 2 molar mole-mole molar mass H 2 O factor mass O 2 = 11.6 g O 2 Copyright Houghton Mifflin Company. All rights reserved. 3 18
19 Learning Check Acetylene gas C 2 H 2 burns in the oxyacetylene torch for welding. How many grams of C 2 H 2 are burned if the reaction produces 75.0 g CO 2? 2 C 2 H 2 (g) + 5 O 2 (g) 4 CO 2 (g) + 2 H 2 O(g) 1) 88.6 g C 2 H 2 2) 44.3 g C 2 H 2 3) 22.2 g C 2 H 2 Copyright Houghton Mifflin Company. All rights reserved. 3 19
20 Solution 3) 22.2 g C 2 H 2 2 C 2 H 2 (g) + 5 O 2 (g) 4 CO 2 (g) + 2 H 2 O(g) 75.0 g CO 2 x 1 mole CO 2 x 2 moles C 2 H 2 x 26.0 g C 2 H g CO 4 moles CO mole C 2 H 2 molar mole-mole molar mass CO 2 factor mass C 2 H 2 = 22.2 g C 2 H 2 Copyright Houghton Mifflin Company. All rights reserved. 3 20
21 Calculating the Mass of Product When 18.6 g ethane gas C 2 H 6 burns in oxygen, how many grams of CO 2 are produced? 2 C 2 H 6 (g) + 7 O 2 (g) 4 CO 2 (g) + 6 H 2 O(g) 18.6 g? g The plan and factors would be g C 2 H 6 mole C 2 H 6 mole CO 2 g CO 2 molar mole-mole molar mass C 2 H 6 factor mass CO 2 Copyright Houghton Mifflin Company. All rights reserved. 3 21
22 Calculating the Mass of Product 2 C 2 H 6 (g) + 7 O 2 (g) 4 CO 2 (g) + 6 H 2 O(g) The setup would be 18.6 g C 2 H 6 x 1 mole C 2 H 6 x 4 moles CO 2 x 44.0 g CO g C 2 H 6 2 moles C 2 H 1 mole CO 6 2 molar mole-mole molar mass C 2 H 6 factor mass CO 2 = 54.4 g CO 2 Copyright Houghton Mifflin Company. All rights reserved. 3 22
23 Learning Check How many grams H 2 O are produced when 35.8 g C 3 H 8 react by the following equation? C 3 H 8 (g) + 5 O 2 (g) 3 CO 2 (g) + 4 H 2 O(g) 1) 14.6 g H 2 O 2) 58.4 g H 2 O 3) 117 g H 2 O Copyright Houghton Mifflin Company. All rights reserved. 3 23
24 Solution 2) 58.4 g H 2 O C 3 H 8 (g) + 5 O 2 (g) 3 CO 2 (g) + 4 H 2 O(g) 35.8 g C 3 H 8 x 1 mole C 3 H 8 x 4 mole H 2 O x 18.0 g H 2 O = 58.4 g H 2 O 44.1 g C 3 H 8 1 mole C 3 H 8 1 mole H 2 O molar mole-mole molar mass C 3 H 8 factor mass H 2 O Copyright Houghton Mifflin Company. All rights reserved. 3 24
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