9.1 Information Given by Chemical Equations 9.2 Mole Mole Relationships 9.3 Mass Calculations 9.4 The Concept of Limiting Reactants 9.
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2 9.1 Information Given by Chemical Equations 9.2 Mole Mole Relationships 9.3 Mass Calculations 9.4 The Concept of Limiting Reactants 9.5 Calculations Involving a Limiting Reactant 9.6 Percent Yield
3 mole-to-mole ratio substances coefficients of any two
4 Fe and O 2 Fe and Fe 2 O 3
5 O2 and Fe2O3
6 1) 3 mol N 2 2) 1 mol N 2 3) 1 mol N 2 1 mol H 2 3 mol H 2 2 mol H 2 1) 1 mol H 2 2) 2 mol NH 3 3) 3 mol N 2 2 mol NH 3 3 mol H 2 2 mol NH 3
7 2) 1 mol N 2 3 mol H 2 2) 2 mol NH 3 3 mol H 2
8 3 O 2 2 Fe 2 O 3 moles of Fe 2 O 3 moles O 2 mol O 2 mol Fe 2 O 3 mol O 2
9 Learning Check 2 1) 3.00 mol Fe 2) 9.00 mol Fe 3) 16.0 mol Fe
10 4 3
11 Learning Check S3 1) 38.4 g O 2 2) 19.2 g O 2 3) 1.90 g O 2
12 19.2 g O2
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14 Write the equation Balance the equation
15 Organize data mol bridge? g 13.1 g Plan g H 2 O mol H 2 O mol O 2 O 2 Setup 11.6 g O 2
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17 4 Na + O 2 2 Na 2 O
18 4 Na + O 2 2 Na 2 O 3.30 x molelcules
19 2 C 2 H O 2 4 CO H 2 O
20 2 C 2 H O 2 4 CO H 2 O 22.2 g C 2 H 2
21 Pathways for Problems Using Equations Given (A) Find (B)
22 Pathways for Problems Using Equations Given (A) molar mass (A) coefficients Avogadro's number Find (B) molar mass (B) Avogradro s number
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26 slices of bread slices of cheese sandwiches
27 slices of bread slices of cheese sandwiches 2 slices of bread cheese
28 Limiting Reactants Method 1 1. Write a balanced equation. 2. For each reactant, calculate the amount of product formed. 3. Smaller answer indicates: limiting reactant amount of product Courtesy Christy Johannesson
29 Limiting Reactants Method 2 Begin by writing a correctly balanced chemical equation Write down all quantitative values under equation (include units) Convert ALL reactants to units of moles Divide by the coefficient in front of each reactant The smallest value is the limiting reactant!
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34 CH 4 + H 2 O 3H 2 + CO
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37 You know that chemical A reacts with chemical B. You react 10.0 g of A with 10.0 g of B.
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39 You react 10.0 g of A with 10.0 g of B. What mass of product will be produced given that the molar mass of A is 10.0 g/mol, B is 20.0 g/mol, and C is 25.0 g/mol? They react according to the equation: A + 3B 2C
40 You react 10.0 g of A with 10.0 g of B. What mass of product will be produced given that the molar mass of A is 10.0 g/mol, B is 20.0 g/mol, and C is 25.0 g/mol? They react according to the equation: A + 3B 2C 1 mol A 10.0 g A = 1.00 mol A 10.0 g A 1 mol B 10.0 g B = mol B 20.0 g B
41 You react 10.0 g of A with 10.0 g of B. What mass of product will be produced given that the molar mass of A is 10.0 g/mol, B is 20.0 g/mol, and C is 25.0 g/mol? They react according to the equation: A + 3B 2C 1.00 mol A 3 mol B 1 mol A = 3.00 mol B required to
42 You react 10.0 g of A with 10.0 g of B. What mass of product will be produced given that the molar mass of A is 10.0 g/mol, B is 20.0 g/mol, and C is 25.0 g/mol? They react according to the equation: A + 3B 2C 2 mol C mol B = mol C produced 3 mol B
43 You react 10.0 g of A with 10.0 g of B. What mass of product will be produced given that the molar mass of A is 10.0 g/mol, B is 20.0 g/mol, and C is 25.0 g/mol? They react according to the equation: A + 3B 2C 25.0 g C mol C = 8.33 g C 1 mol C
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45 greatest
46 true
47 grams of NH g N 2 (1mole/28g N 2 )(2 moles NH 3 /1 moles N 2 ) (17 g NH 3 /1 mole NH 3 ) = 3.64 g NH g H 2 (1mole/2g H 2 )(2 moles NH 3 /3 moles H 2 ) (17 g NH 3 /1 mole NH 3 ) = 17.0 g NH 3
48 2 Do a standard mass to mass problem starting with each reactant 50.0 gmg 1mol Mg 1mol H L 24.31g Mg 1mol Mg 1mol H 2 = 46.1 L H g HCl 1mol HCl 1 mole H L g HCl 2mol HCl 1mol H 2 HCl is the limiting reactant!! = 23.0 L H 2
49 = 25.0 grams Mg needed for the reaction Thus, 50.0 grams 25.0 grams = 25.0 grams Mg leftover!
50 g Ca 3 (PO 4 ) 2 1mol Ca 3 (PO 4 ) 2 3mol CaSO g CaSO g 1 mol Ca 3 (PO 4 ) 2 1mol CaSO 4 = 1317 g 980 g H 2 SO 4 1mol H 2 SO 4 3mol CaSO g CaSO g H 2 SO 4 3mol H 2 SO 4 1mol CaSO 4 = 1360 g Calcium phosphate is the limiting reactant. Starting with calcium phosphate, a mass to mass problem gives 632 grams phosphoric acid will form!
51 limiting reactant. ALL
52 yield) (theoretical (Actual yield)
53 Actual yield Theoretical (possible) yield Percent Yield
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55 Actual yield Theoretical yield 100% = percent yield
56 You react 10.0 g of A with 10.0 g of B. What mass of product will be produced given that the molar mass of A is 10.0 g/mol, B is 20.0 g/mol, and C is 25.0 g/mol? They react according to the equation: A + 3B 2C We determined that 8.33 g C should be produced g of C is what was actually made in the lab. What is the percent yield of the reaction? Where are we going? We want to determine the percent yield of the reaction.
57 You react 10.0 g of A with 10.0 g of B. What mass of product will be produced given that the molar mass of A is 10.0 g/mol, B is 20.0 g/mol, and C is 25.0 g/mol? They react according to the equation: A + 3B 2C We determined that 8.33 g C should be produced g of C is what was actually made in the lab. What is the percent yield of the reaction? What do we know? We know the actual and theoretical yields.
58 You react 10.0 g of A with 10.0 g of B. What mass of product will be produced given that the molar mass of A is 10.0 g/mol, B is 20.0 g/mol, and C is 25.0 g/mol? They react according to the equation: A + 3B 2C We determined that 8.33 g C should be produced g of C is what was actually made in the lab. What is the percent yield of the reaction? How do we get there? 7.23 g C 8.33 g C 100% = 86.8%
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61 Write balanced reaction 2 Cu + S Cu 2 S Determine theoretical yield doing a mass to mass problem 1.50g Cu 1 mol Cu 1mol Cu 2 S g Cu 2 S 63.55g Cu 2 mol Cu 1mol Cu 2 S = 1.88 g Cu 2 S Percent Yield = 1.76 g x 100 = 93.6 % 1.88g
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