Problem Set 3 Solutions
|
|
- Norah Stewart
- 5 years ago
- Views:
Transcription
1 CSE Dsign n Anlysis of Switing Systms Jontn Turnr Prolm St Solutions. Consir t sign of port swit, s on suivi us wit knokout onntrtors t t output. Assum tt t links oprt t G/s n tt t iruit tnology n support mximum lok rt of MHz. Tis mns tt IPP must trnsmit lls on t lst tn prlll signl lins n tt OPP must riv lls on t lst input lins. T tn signl lins lving IPP n us in on of two wys. Eitr, n IPP n sn on ll t tim in prlll form ovr t tn signl lins, or n IPP n sn tn iffrnt lls onurrntly ovr t tn signl lins. In t first s, knokout onntrtor s inputs, wi r tn its wi. In t son s, knokout onntrtor s inputs, wi r on it wi. How mny outputs must t onntrtors v in of t two ss, to prou pkt loss proility of no mor tn wn t input lo is %? In t first s, t proility tt n output rivs i lls in givn yl is just n i n i n n i ( / ) ( / ), wr n=. T proility tt n rriving ll is isr is n n i n i = + ( i k) (/ n) ( / n) if t knokout onntrtor s k output, so w n to fin t i k i smllst vlu of k for wi n n i n ( ) (/ ) ( / ) i i k n n. T smllst su k is i= k + i wn n=. n In t son s, t proility of riving i lls is (/ n) ( / n) i t smllst vlu of k for wi n n i n ( ) (/ ) ( / ) i i k n n i= k + i k is wn n=. i n i, so w n to fin. T smllst su Wt os tis imply out t mmory nwit rquir t t output ports? Compr t ost of implmnting t knokout onntrtors in of t two ss. Wi sign o you tink is t ttr oi? Wy? T son sign rquirs totl of onntrtor outputs, so t nwit ntring t mmory is. G/s n t totl mmory nwit is. G/s. T first sign rquirs totl mmory nwit of G/s, lmost tims s mu. T tpts of t two signs v out t sm omplxity, wit t son ing prps littl lss. Tr is mor ontrol logi n for t son sign, ut t ovrll iffrn twn t two is likly to firly most. T son
2 sign is lrly t ttr oi. T rution in mmory nwit is vry signifint vntg.. Consir uss ll swit wit suivi us wit inputs n outputs. Suppos tt ll tim, ll rrivs on input wit proility p n tt ll is ssign rnomly to iffrnt output. Giv n xprssion for t proility tn givn ll tim, output rivs xtly on ll. ( p /) ( p /) = p( p /) Suppos t OPP t output s knokout onntrtor tt n forwr up to six lls pr ll tim into t OPP s ll uffr. Giv n xprssion proility tn givn ll tim, mor lls rriv t output tn n pl in t uffr. i i ( p /) ( p /) i= i Giv n xprssion for t proility tt n rriving ll is isr. ( / p) i= i ( i ) ( p /) ( p /) i. Consir rings ATM swit wit xtrnl links oprting t G/s. Assum tt t ring is its wi n tt t iruit tnology ing us supports pointtopoint lins oprting t up to MHz. If t swit s svn yts of intrnl r informtion to ll for sning it on t ring, ws t mximum vrg trffi lo tt n support on t outgoing links? Witout ovr, it woul./( ) = %, so wit ovr, is.*/(+)=./) or out.%. Assum t ring uss slott ring protool wit usy/il it, wr ring intrf wit ll to sn uss t first mpty slot tt ss to sn its ll. Suppos trffi is rriving t G/s t of inputs troug n tis rriving trffi is ll going to outputs troug. Wt frtion of its trffi is input tully l to sn? T ring n nl % of t trffi from links, so % of t trffi from. links. So inputs troug will l to forwr ll of tir input trffi, input will l to sn % of its input trffi n inputs n will unl to sn ny of tir trffi.. Consir sr uffr swit wit n inputs n n outputs. Assum tt tr is no limit on t vill uffr sp, tt t pkt lngts r xponntilly istriut, wit mn /µ n tt t tim twn pkt rrivls for outpus xponntilly istriut, wit mn /λ. Giv n xprssion for t proility tt t sr uffr ontins i pkts for prtiulr output. Unr t givn onitions, output n mol y n M/M/ quu, so t proility tt t sr uffr ontins i pkts for givn outpus ( ρ)ρ i wr ρ=λ/µ. i
3 Giv n xprssion for t proility tt t sr uffr ontins totl of i pkts, ssuming tt t numr of pkts going to t iffrnt outputs r inpnnt. In tis s, w v to onsir ll possil wys tt w n g pkts. So, t rquir xprssion is n i n i ( ρ ) ρ = ( ρ) ρ i + i + L+ in = i i + i + L+ in = i wr t summtion is ovr ll nonngtiv intgr vlus for i,...,i n tt up to i. If w ll tis quntity f(i,n), w n o t omputtion itrtivly using t qution wr f(j,)=( ρ)ρ j. f ( i, n) = j i f ( j,) f ( i j, n ) Us tis xprssion to stimt t mount of mmory n to nsur tt t pkt loss proility is no mor tn, wn n= n t input lo is %. Compr tis to t mount of mmory you woul n if t mmory wr not sr. A Visul Bsi progrm to omput f(,n) + + f(i,n) is sown low. Using tis, w fin tt t proility tt t quu ontins mor tn pkts is just unr. For port sr uffr swit, t proility tt t sr uffr s mor tn pkts is just unr. So t sr uffr swit ns storg for pkts, wil swit wit sprt uffrs for output woul n =, wi is out. tims s mny s t sr uffr swit ns. Not tt tis mto for omputing t rquir uffr siz ovrstimts wt s rlly n y smll mount. Funtion suf(ro As Doul, i As Intgr, n As Intgr) As Doul ' Comput t proility tt sr uffr swit wit n ports ' n uniform rnom input lo of ro, s lss tn or qul to ' i pkts in its uffr, ssuming no limit on t numr of pkts ' tt n stor. Dim, j, r As Intgr Dim pi(, ) As Doul Dim s As Doul pi(, ) = ro For j = To i pi(j, ) = ro * pi(j, ) Nxt j For = To n For j = To i pi(j, ) = For r = To j pi(j, ) = pi(j, ) + pi(r, ) * pi(j r, ) Nxt r Nxt j Nxt s = For j = To i s = s + pi(j, n) Nxt j suf = s En Funtion
4 Consir wt ppns wn TCP trffi is ppli to t sr uffr swit. Spifilly, ssum tt n/ of t outputs r riving trffi from lrg numr of TCP strms, wit lrg klog of trffi. Also ssum tt tr is singl quu in t sr uffr for of t outputs, n tt rriving pkts r isr if t quu is full. Qulittivly sri t quuing vior of t sr uffr swit in tis sitution. Estimt t mount of mmory n y t swit to nsur tt non of t usy output links xprins unrflow, ssuming tt t ntwork roun trip tim is ms n tt t output links oprt t G/s. Compr tis to t mount of mmory n in swit tt os not sr t mmory mong t iffrnt outputs. In tis sitution, t iffrnt TCP flows going out on ll t outputs n potntilly om synroniz, sin wn t sr mmory fills up, ll t flows r likly to xprin pkt loss n ru tir winow sizs togtr. To prvnt t sr uffr from unrflowing, w n mmory siz ts omprl to t prout of t output link nwit tims t ntwork rountrip ly. If t roun trip tim is ms n t output links r G/s, tis oms to out Mits for ongst link. If w llow for lfson s wort of uffring, tis numr grows to Mits pr ongst link. Sin lf of t links r ongst, tis rus t mmory usg y just ftor of, n sin mor tn n/ links oul ongst, it s not lr tt w woul vn gt tis rution, in prti. Consquntly for ontinuously klogg TCP flows, tr is littl gin otin from t sr uffr. Bs on ll your nswrs ov, vlut t vntgs n isvntgs of sr uffr swits, rltiv to swits wit sprt mmoris for output. Sr uffring works wll, so long s t trffi going to iffrnt outputs is unorrlt. Sin most TCP flows omplt tir t trnsmission for going troug multipl rouns of ongstion voin, tir vior is mor lik tt prit y t first nlysis, tn y t son. Tis suggsts tt tr is signifint rution in mmory tt n otin using sr uffring. Tis my not lwys l to signifint rution in ost, sin ommril mmory omponnts oftn o not v t il omintion of IO nwit n mmory pity. For ig sp routrs, mmory nwit is oftn t limiting ftor, foring routr signr to us mor mmory omponnts in prlll to gt t rquir nwit, ling to n ovrsupply of mmory pity. In tis sitution, tr is lss to gin from sring t mmory mong iffrnt ports.. Consir rossrs swit wit ports in wi IPP s singl quu n uring ritrtion yl, t IPPs ontn for t output tt t first ll in t quu is rss to. If vry input s ll in its quu n if t outputs ts lls r rss to r slt t rnom, ws t proility tt no lls r irt to prtiulr output? ( / n ) n = ( / ) =. Ws t xpt numr of outputs tt no lls r rss to?.n =. Suppos tt IPP s two quus, on for lls rss to vnnumr outputs n on for lls rss to onumr outputs. Assum tt vry IPP s ll in
5 of its two quus n tt t rsss of lls in t vn quus r rnomly slt from mong t vn outputs n tt t rsss of lls in t o quus r rnomly slt from mong t o outputs. Ws t proility tt givn output s no lls rss to it? ( / ) =. Ws t xpt numr of outputs tt no lls r rss to?.n =. Consir systm in wi IPP s su n ovn quu rrngmnt, n uring ritrtion yl, IPP ttmpts to sn ll from itr of its quus. Estimt t mximum trougput possil in su systm. In singl ll yl, w woul xpt.=. lls to gt troug, unr t givn onitions, ompr to out for t systm in wi IPP s singl quu. In susqunt ll yls, t rsss of lls will not inpnnt, ling to grtion in t trougput, ut t grtion soul lss in t s of n ovn quu systm tn in t s of singl quu systm. T tul mximum trougput soul twn % n % of, or rougly to lls pr yl.
6 . T timslott ritrtion ring, sri on pg, is ttrtiv us is vry simpl to implmnt. It n gnrliz to pply to systms wit VOQs n to llow suling ovr multipl tim stps. In tis gnrliz vrsion, t it z i is rpl y vlu, wi rprsnts t rlist tim stp t wi t output x i is not yt to riv ll. If inpu s n un ll to sn to output x i n s no otr ll to snt t tim, it s t witing ll for trnsmission t tim, n tn inrmnts for pssing its vlu to inpu. T input kps trk of wn witing ll is for trnsmission, n sns it t t pproprit tim. T mtrix sown low rprsnts st of lls witing to troug rossr swit using tis gnrliz timslott ritrtion ring. T ntry in row i, olumn j is t numr of lls npu going to output j. For input, list t output tt sns ll to on sussiv tim stp, until ll t lls r snt. Assum tnitilly, ll t vlus r zro n tt x i =i. T figur low sows wt ppns uring tim. In t firstrtion of t suling lgoritm, noting ppns, sin tr r zros in ll t igonl ntris. T first mtrix in t top row igligts wi VOQs r unr onsirtion uring stp of t lgoritm. T vlu of ftr stp r sown nxt, long wit t prtil onstrut up to tt point. T ntr mtrix in t top row is sows t numr of un pkts in of t VOQs n igligts t VOQs tt r unr onsirtion in t nxt stp. In t prtil s, t unrsor rtr (_) is us to init tim stps uring wi prtiulr inpus not to sn ll. t=,,,,, _,,_,,,,,,,, _,,_,,_,,,,,,_,,,,,, _,,_,,_,,,,
7 T figur low sows wt ppns t tim. Noti tt t initil rmovs tos lls tt wr to go out uring stp. Also not tt ti vlus tt r qul to t t n of tim r inrs to. Tis is nssry to nsur t r mks progrss. t=,_,,_,,,,,,,,,,_,,_, _,, _,,,,,_,,,,,,,,_, _,,,,_,_,,_,,,,,,,,_,,_, _,,,_,_,,,_,_,,,_,,,,,,,,_,,_,,_,_,_, _,,,_,_,,,,_,_,,,_,,,,,,,,_,,_,,_,_,_,,,,_,_,,,,_,_,, Tis figur sows wt ppns t t=. t= _,,,,,,_, _,,_,_,_,,,_,_,,,_,_,, _,,,,,,_,_,_,,_, _,,_,_,_,,,_,_,,,_,_,, _,,,,_,_,_,,,,_,_,_,,_, _,,_,_,_,,,_,_,,,_,_,,,_,,,,,_,_,_,,,,_,_,_,,_,, _,,_,_,_,,,_,_,,,_,_,,,_,,,,,_,_,_,,,,_,_,_,,_,, _,,_,_,_,,_,,,_,_,,,,_,,,_,,,,,,_,_,,,,_,_,_,,_,, _,,_,_,_,,_,,,,_,,,,_,,,_,
8 T figur low sows wt ppns in t nxt fw stps. Svrl mor tim stps r rquir to fully ll t lls. t=,,,,_,_,,,_,_,_, _,,,_,_,_,,_,,,_,,,_,,,_,,,,,_,_,,,_,_,_, _,,,_,_,_,,_,,,_,,,_,,,_,,,,,_,_,,,,_,_,,,,_,_,_,,_,,,_,,,_,,,_,,_,,,,,_,_,,,,_,_,,,,_,_,_,,_,,,_,,,_,,,_,,_,,,,,_,_,,,,_,_,,,,_,_,_,,_,,_,,,_,,,_,,,_,,_,,,,,,_,,,,_,_,,,,_,_,_,,_,,_,,,_,,,,,,_,,_, t=,,,,_,,,_,_,, _,_,_,,_,,_,,_,,,,,,_,,_,,,,,_,,,_,_,, _,_,_,,_,,_,,_,,,,,,_,,_,,,,,_,,,_,_,, _,_,_,,_,,_,,_,,,,,,_,,_,,,,,_,,,_,_,, _,_,_,,_,,_,,_,,,,,,_,,_,,,,,_,,,_,_,, _,_,_,,_,,_,,_,,,,,,_,,_,,,,,_,,,_,_,, _,_,_,,_,,_,,_,,,,,,_,,_, t=,,,_,,_,_, _,_,,_,,_, _,,,,,_,,_,,,,_,,_,_, _,_,,_,,_, _,,,,,_,,_,,,,_,,_,_, _,_,,_,,_, _,,,,,_,,_,,,,_,,_,_, _,_,,_,,_, _,,,,,_,,_,,,,_,,_,_, _,_,,_,,_, _,,,,,_,,_,,,,_,,_,_, _,_,,_,,_, _,,,,,_,,_,
9 . T figur low sows t stt of simpl rossr r t t strt of suling oprtion. Sow t stt of t ontrollr ftr stp of t lgoritm, until ll possil mts v n m. B sur to sow ow t pointrs r upt. Do tis for ot t roun roin lgoritm n t islip lgoritm. T rsult for t roun roin lgoritm is sown low. first roun outputs inputs slnputs slt outputs son roun outputs slnputs inputs slt outputs
10 T rsult for t islip lgoritm is sown low. first roun outputs inputs slnputs slt outputs son roun outputs slnputs inputs slt outputs
11 . Giv n xmpl sowing tslip n rquir up to itrtions to omplt pkt suling oprtion for port rossr. Spifilly, giv n initil stt of t rossr, sowing wi inputs v pkts to sn to wi outputs, n initil vlus of ll t pointrs us y t islip lgoritm. Tn sow wt ppns in of t rmining stps. In prtiulr, sow t stt of t pointrs n wi inputs v n mt to wi outputs, wn t lgoritm trmints. initil onfigurtion first stp son stp tir stp fourt stp fift stp
12 . T figur low sows t stt of rossr wit virtul output quus. In prtiulr, t numr in row i, olumn j nots t numr of lls witing in t VOQ npu going to output j. T numrs in t ottom row rprsnt t numr of lls in t quus t of t outputs. Sow ow t LOOFA lgoritm mts inputs to outputs, ssuming tt t outputs slnputs, s on wi input s t longst VOQ for t output. Us t xtr opis of t figur to sow wt mts r m ftr stp y irling t slt ntris. Mk sur you ll t igrms you r using to init stp. At t n, sow ow t sttus of t VOQs ngs s rsult of t slt ll trnsfrs. first stp son stp tir stp finl stt
13 . T figur low (similr to t figur on pg of t ltur nots) sows t initil stt of CCF rossr r t t strt of suling oprtion. Sow t stt of t ontrollr ftr stp of t lgoritm. nw rrivls following insrtion of rriving lls ftr n stp ftr t stp initil stt ftr st stp ftr r stp ftr t stp T stps r illustrt ov. Following t fift stp, t lgoritm trmints us stl mting s n foun.
14 . In on vrint of t LOOFA rossr suling lgoritm, outputs tt riv multipl is from inputs, slnputs s on t timstmps of t ontning lls (lls wit smll timstmps r prfrr ovr lls wit lrgr timstmps). Also, lls r forwr from t outputsi quus in timstmp orr. Fin trffi pttrn tt monstrts tt vn wit spup of, tis vrsion of t LOOFA suling lgoritm os not lwys forwr lls in FIFO orr. T figur low illustrts snrio in wi t olst lls first vrsion of t LOOFA lgoritm fils to prsrv FIFO orring. Tis is for six port swit. following rrivl stp stintion & timstmp stp,,, following trnsfr,,, following prtur,, following trnsfr timstmp of quu lls,, stp,,,,,,,,,,,,,,,,,,, stp,,,,,,,,,,,,,,,,, stp,,,,,,,,,,,, stp,,,,, Now, output must sn ll wit timstmp, wil input still s ll wit timstmp.
15 . Sow tt t stl mting lgoritm sri on pg os in ft prou stl mting. Assum, to t ontrry, tt t onstrut mting is not stl. Tis mns tt tr r two pirs (, ) n (, ) su tt prfrs to n prfrs to. If tis wr t s, tn must v m i for for it i for. Sin t mmrs of B only ng prtnrs to improv tir prfrn, t t tim tt i for, itr ws unmt or it ws mt wit prtnr tt rnk no igr tn. In tis s, must v swit prtnrs, mting it wit. But tis yils ontrition, sin woul not v swit from to, ftr oming mt wit.. On wy to implmnt multisn rossr swit wit VOQs is for t IPPs to opy rriving multist ll to t VOQs for ll outputs tt r to riv opis. Wit tis ppro, t multist lls ppr no iffrnt tn unist lls to t rossr. Sow tt rossr n forwr multist lls wit fnout of F in workonsrving fsion, using t LOOFA lgoritm n spup of F+. W strt y ssuming tt t swit oprts in yls of F+ pss. T first ps of yl is t rrivl ps, uring wi n rriving ll my pl in up to F iffrnt VOQs. T nxt F pss r trnsfr pss, uring wi lls r trnsfrr from inputs to outputs troug t rossr. T nxt ps is t prtur ps, uring wi lls r trnsmitt on t output links. T lst ps is n itionl trnsfr ps. W fin t slknss of ll just s on pg of t nots. W not tt t lmm on pg gnrlizs t multist s. As wit t unist s, trnsfr yl, t minimum slknss t n inpunrss y t lst on (unlss it s no lls). During t rrivl ps, ll s slknss n rs y t most F n uring t prtur ps its slknss n rs y t most. Sin tr r F+ trnsfr pss, tr n no nt rs in ll s slknss uring n F+ ps yl. W n lso giv vrsion of lmm on. In prtiulr, w n sow tt following t rrivl ps of ny stp, t slknss of ll is t lst (F). For lls tt rriv uring t first tim stp, tis is lrly tru, sin t outputs v no lls t tis point, n t most F lls gt insrt into VOQs uring t first stp. So, t ll wi is lsn t orring s slknss of (F). As on, w pro y inution. Lt ll tt ws pl in VOQ uring t rrivl stp of ps t. If tr r no lls tt pr n wr prsnt t t input for stp t, tn t rsult lrly ols, sin only t lls tt rriv uring stp t oul pr n tr r t most F of ts, xluing. So, suppos is ll tt ws prsnt for stp t n tt prs. Assum lso, tt ll otr lls prsnt for stp t tt pr lso pr. By t inution ypotsis, following t rrivl ps of stp t, t slknss of ws t lst (F). So, just for t rrivl ps of stp t, t slknss of must t lst. Now, onsir t lls pl in VOQs uring stp t. L t numr of ts lls tt pr. Tis mns tt ftr t rrivl ps of stp t, t slknss of is t ls. Sin tr t most (F)i otr lls tt rriv uring stp t tt pr n o not pr, t slknss of is t lst (i)((f)i)=(f). To omplt t proof tt t systm is workonsrving, suppos tt ftr t rrivl ps of som stp, tr is som output wit no lls in its output quu n tr r lls witing in VOQs for tt output. Lt ny su ll. Sin tr r no lls in t output quu, n sin t slknss of is t lst (F), tr n t most F lls tt pr ts input. Tis mns tt uring of t F trnsfr pss twn t rrivl ps n t prtur ps,
16 itr som ll in front of gts trnsfrr, or t input ttmpts to sn. Sin tr only F lls in front of, tr must t lst on trnsfr ps uring wi t input ttmpts to sn. If os not gt snt uring su trnsfr ps, tn t output must v gottn ll from som otr input. So, t output s ll to sn, uring t prtur ps.
CSE 373: More on graphs; DFS and BFS. Michael Lee Wednesday, Feb 14, 2018
CSE 373: Mor on grphs; DFS n BFS Mihl L Wnsy, F 14, 2018 1 Wrmup Wrmup: Disuss with your nighor: Rmin your nighor: wht is simpl grph? Suppos w hv simpl, irt grph with x nos. Wht is th mximum numr of gs
More informationCSC Design and Analysis of Algorithms. Example: Change-Making Problem
CSC 801- Dsign n Anlysis of Algorithms Ltur 11 Gry Thniqu Exmpl: Chng-Mking Prolm Givn unlimit mounts of oins of nomintions 1 > > m, giv hng for mount n with th lst numr of oins Exmpl: 1 = 25, 2 =10, =
More informationTangram Fractions Overview: Students will analyze standard and nonstandard
ACTIVITY 1 Mtrils: Stunt opis o tnrm mstrs trnsprnis o tnrm mstrs sissors PROCEDURE Skills: Dsriin n nmin polyons Stuyin onrun Comprin rtions Tnrm Frtions Ovrviw: Stunts will nlyz stnr n nonstnr tnrms
More information16.unified Introduction to Computers and Programming. SOLUTIONS to Examination 4/30/04 9:05am - 10:00am
16.unii Introution to Computrs n Prormmin SOLUTIONS to Exmintion /30/0 9:05m - 10:00m Pro. I. Kristin Lunqvist Sprin 00 Grin Stion: Qustion 1 (5) Qustion (15) Qustion 3 (10) Qustion (35) Qustion 5 (10)
More informationMAT3707. Tutorial letter 201/1/2017 DISCRETE MATHEMATICS: COMBINATORICS. Semester 1. Department of Mathematical Sciences MAT3707/201/1/2017
MAT3707/201/1/2017 Tutoril lttr 201/1/2017 DISCRETE MATHEMATICS: COMBINATORICS MAT3707 Smstr 1 Dprtmnt o Mtmtil Sins SOLUTIONS TO ASSIGNMENT 01 BARCODE Din tomorrow. univrsity o sout ri SOLUTIONS TO ASSIGNMENT
More informationPresent state Next state Q + M N
Qustion 1. An M-N lip-lop works s ollows: I MN=00, th nxt stt o th lip lop is 0. I MN=01, th nxt stt o th lip-lop is th sm s th prsnt stt I MN=10, th nxt stt o th lip-lop is th omplmnt o th prsnt stt I
More information12. Traffic engineering
lt2.ppt S-38. Introution to Tltrffi Thory Spring 200 2 Topology Pths A tlommunition ntwork onsists of nos n links Lt N not th st of nos in with n Lt J not th st of nos in with j N = {,,,,} J = {,2,3,,2}
More informationExam 1 Solution. CS 542 Advanced Data Structures and Algorithms 2/14/2013
CS Avn Dt Struturs n Algorithms Exm Solution Jon Turnr //. ( points) Suppos you r givn grph G=(V,E) with g wights w() n minimum spnning tr T o G. Now, suppos nw g {u,v} is to G. Dsri (in wors) mtho or
More informationCSE 373: AVL trees. Warmup: Warmup. Interlude: Exploring the balance invariant. AVL Trees: Invariants. AVL tree invariants review
rmup CSE 7: AVL trs rmup: ht is n invrint? Mihl L Friy, Jn 9, 0 ht r th AVL tr invrints, xtly? Disuss with your nighor. AVL Trs: Invrints Intrlu: Exploring th ln invrint Cor i: xtr invrint to BSTs tht
More informationd e c b a d c b a d e c b a a c a d c c e b
FLAT PEYOTE STITCH Bin y mkin stoppr -- sw trou n pull it lon t tr until it is out 6 rom t n. Sw trou t in witout splittin t tr. You soul l to sli it up n own t tr ut it will sty in pl wn lt lon. Evn-Count
More informationOutline. 1 Introduction. 2 Min-Cost Spanning Trees. 4 Example
Outlin Computr Sin 33 Computtion o Minimum-Cost Spnnin Trs Prim's Alorithm Introution Mik Joson Dprtmnt o Computr Sin Univrsity o Clry Ltur #33 3 Alorithm Gnrl Constrution Mik Joson (Univrsity o Clry)
More informationModule graph.py. 1 Introduction. 2 Graph basics. 3 Module graph.py. 3.1 Objects. CS 231 Naomi Nishimura
Moul grph.py CS 231 Nomi Nishimur 1 Introution Just lik th Python list n th Python itionry provi wys of storing, ssing, n moifying t, grph n viw s wy of storing, ssing, n moifying t. Bus Python os not
More information(2) If we multiplied a row of B by λ, then the value is also multiplied by λ(here lambda could be 0). namely
. DETERMINANT.. Dtrminnt. Introution:I you think row vtor o mtrix s oorint o vtors in sp, thn th gomtri mning o th rnk o th mtrix is th imnsion o th prlllppi spnn y thm. But w r not only r out th imnsion,
More informationWhy the Junction Tree Algorithm? The Junction Tree Algorithm. Clique Potential Representation. Overview. Chris Williams 1.
Why th Juntion Tr lgorithm? Th Juntion Tr lgorithm hris Willims 1 Shool of Informtis, Univrsity of Einurgh Otor 2009 Th JT is gnrl-purpos lgorithm for omputing (onitionl) mrginls on grphs. It os this y
More informationOpenMx Matrices and Operators
OpnMx Mtris n Oprtors Sr Mln Mtris: t uilin loks Mny typs? Dnots r lmnt mxmtrix( typ= Zro", nrow=, nol=, nm="" ) mxmtrix( typ= Unit", nrow=, nol=, nm="" ) mxmtrix( typ= Int", nrow=, nol=, nm="" ) mxmtrix(
More informationConstructive Geometric Constraint Solving
Construtiv Gomtri Constrint Solving Antoni Soto i Rir Dprtmnt Llngutgs i Sistms Inormàtis Univrsitt Politèni Ctluny Brlon, Sptmr 2002 CGCS p.1/37 Prliminris CGCS p.2/37 Gomtri onstrint prolm C 2 D L BC
More informationA Simple Code Generator. Code generation Algorithm. Register and Address Descriptors. Example 3/31/2008. Code Generation
A Simpl Co Gnrtor Co Gnrtion Chptr 8 II Gnrt o for singl si lok How to us rgistrs? In most mhin rhitturs, som or ll of th oprnsmust in rgistrs Rgistrs mk goo tmporris Hol vlus tht r omput in on si lok
More informationWeighted Graphs. Weighted graphs may be either directed or undirected.
1 In mny ppltons, o rp s n ssot numrl vlu, ll wt. Usully, t wts r nonntv ntrs. Wt rps my tr rt or unrt. T wt o n s otn rrr to s t "ost" o t. In ppltons, t wt my msur o t lnt o rout, t pty o ln, t nry rqur
More information1 Introduction to Modulo 7 Arithmetic
1 Introution to Moulo 7 Arithmti Bor w try our hn t solvin som hr Moulr KnKns, lt s tk los look t on moulr rithmti, mo 7 rithmti. You ll s in this sminr tht rithmti moulo prim is quit irnt rom th ons w
More informationThe University of Sydney MATH 2009
T Unvrsty o Syny MATH 2009 APH THEOY Tutorl 7 Solutons 2004 1. Lt t sonnt plnr rp sown. Drw ts ul, n t ul o t ul ( ). Sow tt s sonnt plnr rp, tn s onnt. Du tt ( ) s not somorp to. ( ) A onnt rp s on n
More informationV={A,B,C,D,E} E={ (A,D),(A,E),(B,D), (B,E),(C,D),(C,E)}
Introution Computr Sin & Enginring 423/823 Dsign n Anlysis of Algorithms Ltur 03 Elmntry Grph Algorithms (Chptr 22) Stphn Sott (Apt from Vinohnrn N. Vriym) I Grphs r strt t typs tht r pplil to numrous
More informationECE COMBINATIONAL BUILDING BLOCKS - INVEST 13 DECODERS AND ENCODERS
C 24 - COMBINATIONAL BUILDING BLOCKS - INVST 3 DCODS AND NCODS FALL 23 AP FLZ To o "wll" on this invstition you must not only t th riht nswrs ut must lso o nt, omplt n onis writups tht mk ovious wht h
More information# 1 ' 10 ' 100. Decimal point = 4 hundred. = 6 tens (or sixty) = 5 ones (or five) = 2 tenths. = 7 hundredths.
How os it work? Pl vlu o imls rprsnt prts o whol numr or ojt # 0 000 Tns o thousns # 000 # 00 Thousns Hunrs Tns Ons # 0 Diml point st iml pl: ' 0 # 0 on tnth n iml pl: ' 0 # 00 on hunrth r iml pl: ' 0
More informationV={A,B,C,D,E} E={ (A,D),(A,E),(B,D), (B,E),(C,D),(C,E)}
s s of s Computr Sin & Enginring 423/823 Dsign n Anlysis of Ltur 03 (Chptr 22) Stphn Sott (Apt from Vinohnrn N. Vriym) s of s s r strt t typs tht r pplil to numrous prolms Cn ptur ntitis, rltionships twn
More informationGraph Isomorphism. Graphs - II. Cayley s Formula. Planar Graphs. Outline. Is K 5 planar? The number of labeled trees on n nodes is n n-2
Grt Thortil Is In Computr Sin Vitor Amhik CS 15-251 Ltur 9 Grphs - II Crngi Mllon Univrsity Grph Isomorphism finition. Two simpl grphs G n H r isomorphi G H if thr is vrtx ijtion V H ->V G tht prsrvs jny
More informationlearning objectives learn what graphs are in mathematical terms learn how to represent graphs in computers learn about typical graph algorithms
rp loritms lrnin ojtivs loritms your sotwr systm sotwr rwr lrn wt rps r in mtmtil trms lrn ow to rprsnt rps in omputrs lrn out typil rp loritms wy rps? intuitivly, rp is orm y vrtis n s twn vrtis rps r
More informationLecture 20: Minimum Spanning Trees (CLRS 23)
Ltur 0: Mnmum Spnnn Trs (CLRS 3) Jun, 00 Grps Lst tm w n (wt) rps (unrt/rt) n ntrou s rp voulry (vrtx,, r, pt, onnt omponnts,... ) W lso suss jny lst n jny mtrx rprsntton W wll us jny lst rprsntton unlss
More informationCSE 373. Graphs 1: Concepts, Depth/Breadth-First Search reading: Weiss Ch. 9. slides created by Marty Stepp
CSE 373 Grphs 1: Conpts, Dpth/Brth-First Srh ring: Wiss Ch. 9 slis rt y Mrty Stpp http://www.s.wshington.u/373/ Univrsity o Wshington, ll rights rsrv. 1 Wht is grph? 56 Tokyo Sttl Soul 128 16 30 181 140
More information5/1/2018. Huffman Coding Trees. Huffman Coding Trees. Huffman Coding Trees. Huffman Coding Trees. Huffman Coding Trees. Huffman Coding Trees
/1/018 W usully no strns y ssnn -lnt os to ll rtrs n t lpt (or mpl, 8-t on n ASCII). Howvr, rnt rtrs our wt rnt rquns, w n sv mmory n ru trnsmttl tm y usn vrl-lnt non. T s to ssn sortr os to rtrs tt our
More informationCOMP108 Algorithmic Foundations
Grdy mthods Prudn Wong http://www.s.liv..uk/~pwong/thing/omp108/01617 Coin Chng Prolm Suppos w hv 3 typs of oins 10p 0p 50p Minimum numr of oins to mk 0.8, 1.0, 1.? Grdy mthod Lrning outoms Undrstnd wht
More informationGrade 7/8 Math Circles March 4/5, Graph Theory I- Solutions
ulty o Mtmtis Wtrloo, Ontrio N ntr or ution in Mtmtis n omputin r / Mt irls Mr /, 0 rp Tory - Solutions * inits lln qustion. Tr t ollowin wlks on t rp low. or on, stt wtr it is pt? ow o you know? () n
More information, each of which is a tree, and whose roots r 1. , respectively, are children of r. Data Structures & File Management
nrl tr T is init st o on or mor nos suh tht thr is on sint no r, ll th root o T, n th rminin nos r prtition into n isjoint susts T, T,, T n, h o whih is tr, n whos roots r, r,, r n, rsptivly, r hilrn o
More informationOutline. Computer Science 331. Computation of Min-Cost Spanning Trees. Costs of Spanning Trees in Weighted Graphs
Outlin Computr Sin 33 Computtion o Minimum-Cost Spnnin Trs Prim s Mik Joson Dprtmnt o Computr Sin Univrsity o Clry Ltur #34 Introution Min-Cost Spnnin Trs 3 Gnrl Constrution 4 5 Trmintion n Eiiny 6 Aitionl
More informationProblem 1. Solution: = show that for a constant number of particles: c and V. a) Using the definitions of P
rol. Using t dfinitions of nd nd t first lw of trodynis nd t driv t gnrl rltion: wr nd r t sifi t itis t onstnt rssur nd volu rstivly nd nd r t intrnl nrgy nd volu of ol. first lw rlts d dq d t onstnt
More informationCS 461, Lecture 17. Today s Outline. Example Run
Prim s Algorithm CS 461, Ltur 17 Jr Si Univrsity o Nw Mxio In Prim s lgorithm, th st A mintin y th lgorithm orms singl tr. Th tr strts rom n ritrry root vrtx n grows until it spns ll th vrtis in V At h
More informationb. How many ternary words of length 23 with eight 0 s, nine 1 s and six 2 s?
MATH 3012 Finl Exm, My 4, 2006, WTT Stunt Nm n ID Numr 1. All our prts o this prolm r onrn with trnry strings o lngth n, i.., wors o lngth n with lttrs rom th lpht {0, 1, 2}.. How mny trnry wors o lngth
More informationMultipoint Alternate Marking method for passive and hybrid performance monitoring
Multipoint Altrnt Mrkin mtho or pssiv n hyri prormn monitorin rt-iool-ippm-multipoint-lt-mrk-00 Pru, Jul 2017, IETF 99 Giuspp Fiool (Tlom Itli) Muro Coilio (Tlom Itli) Amo Spio (Politnio i Torino) Riro
More informationAn undirected graph G = (V, E) V a set of vertices E a set of unordered edges (v,w) where v, w in V
Unirt Grphs An unirt grph G = (V, E) V st o vrtis E st o unorr gs (v,w) whr v, w in V USE: to mol symmtri rltionships twn ntitis vrtis v n w r jnt i thr is n g (v,w) [or (w,v)] th g (v,w) is inint upon
More informationPlanar Upward Drawings
C.S. 252 Pro. Rorto Tmssi Computtionl Gomtry Sm. II, 1992 1993 Dt: My 3, 1993 Sri: Shmsi Moussvi Plnr Upwr Drwings 1 Thorm: G is yli i n only i it hs upwr rwing. Proo: 1. An upwr rwing is yli. Follow th
More informationMath 61 : Discrete Structures Final Exam Instructor: Ciprian Manolescu. You have 180 minutes.
Nm: UCA ID Numr: Stion lttr: th 61 : Disrt Struturs Finl Exm Instrutor: Ciprin nolsu You hv 180 minuts. No ooks, nots or lultors r llow. Do not us your own srth ppr. 1. (2 points h) Tru/Fls: Cirl th right
More informationBASIC CAGE DETAILS D C SHOWN CLOSED TOP SPRING FINGERS INNER WALL TABS ARE COINED OVER BASE AND COVER FOR RIGIDITY
SI TIS SOWN OS TOP SPRIN INRS INNR W TS R OIN OVR S N OVR OR RIIITY. R IMNSIONS O INNR SIN TO UNTION WIT QU SM ORM-TOR (zqsp+) TRNSIVR. R. RR S OPTION (S T ON ST ) TURS US WIT OPTION T SINS. R (INSI TO
More informationCS September 2018
Loil los Distriut Systms 06. Loil los Assin squn numrs to msss All ooprtin prosss n r on orr o vnts vs. physil los: rport tim o y Assum no ntrl tim sour Eh systm mintins its own lol lo No totl orrin o
More informationAlgorithmic and NP-Completeness Aspects of a Total Lict Domination Number of a Graph
Intrntionl J.Mth. Comin. Vol.1(2014), 80-86 Algorithmi n NP-Compltnss Aspts of Totl Lit Domintion Numr of Grph Girish.V.R. (PES Institut of Thnology(South Cmpus), Bnglor, Krntk Stt, Ini) P.Ush (Dprtmnt
More informationGarnir Polynomial and their Properties
Univrsity of Cliforni, Dvis Dprtmnt of Mthmtis Grnir Polynomil n thir Proprtis Author: Yu Wng Suprvisor: Prof. Gorsky Eugny My 8, 07 Grnir Polynomil n thir Proprtis Yu Wng mil: uywng@uvis.u. In this ppr,
More informationPaths. Connectivity. Euler and Hamilton Paths. Planar graphs.
Pths.. Eulr n Hmilton Pths.. Pth D. A pth rom s to t is squn o gs {x 0, x 1 }, {x 1, x 2 },... {x n 1, x n }, whr x 0 = s, n x n = t. D. Th lngth o pth is th numr o gs in it. {, } {, } {, } {, } {, } {,
More information0.1. Exercise 1: the distances between four points in a graph
Mth 707 Spring 2017 (Drij Grinrg): mitrm 3 pg 1 Mth 707 Spring 2017 (Drij Grinrg): mitrm 3 u: W, 3 My 2017, in lss or y mil (grinr@umn.u) or lss S th wsit or rlvnt mtril. Rsults provn in th nots, or in
More informationThe University of Sydney MATH2969/2069. Graph Theory Tutorial 5 (Week 12) Solutions 2008
Th Univrsity o Syny MATH2969/2069 Grph Thory Tutoril 5 (Wk 12) Solutions 2008 1. (i) Lt G th isonnt plnr grph shown. Drw its ul G, n th ul o th ul (G ). (ii) Show tht i G is isonnt plnr grph, thn G is
More informationBASIC CAGE DETAILS SHOWN 3D MODEL: PSM ASY INNER WALL TABS ARE COINED OVER BASE AND COVER FOR RIGIDITY SPRING FINGERS CLOSED TOP
MO: PSM SY SI TIS SOWN SPRIN INRS OS TOP INNR W TS R OIN OVR S N OVR OR RIIITY. R TURS US WIT OPTION T SINS. R (UNOMPRSS) RR S OPTION (S T ON ST ) IMNSIONS O INNR SIN TO UNTION WIT QU SM ORM-TOR (zqsp+)
More informationNumbering Boundary Nodes
Numring Bounry Nos Lh MBri Empori Stt Univrsity August 10, 2001 1 Introution Th purpos of this ppr is to xplor how numring ltril rsistor ntworks ffts thir rspons mtrix, Λ. Morovr, wht n lrn from Λ out
More informationSolutions for HW11. Exercise 34. (a) Use the recurrence relation t(g) = t(g e) + t(g/e) to count the number of spanning trees of v 1
Solutions for HW Exris. () Us th rurrn rltion t(g) = t(g ) + t(g/) to ount th numr of spnning trs of v v v u u u Rmmr to kp multipl gs!! First rrw G so tht non of th gs ross: v u v Rursing on = (v, u ):
More informationUsing the Printable Sticker Function. Using the Edit Screen. Computer. Tablet. ScanNCutCanvas
SnNCutCnvs Using th Printl Stikr Funtion On-o--kin stikrs n sily rt y using your inkjt printr n th Dirt Cut untion o th SnNCut mhin. For inormtion on si oprtions o th SnNCutCnvs, rr to th Hlp. To viw th
More informationDUET WITH DIAMONDS COLOR SHIFTING BRACELET By Leslie Rogalski
Dut with Dimons Brlt DUET WITH DIAMONDS COLOR SHIFTING BRACELET By Lsli Roglski Photo y Anrw Wirth Supruo DUETS TM from BSmith rt olor shifting fft tht mks your work tk on lif of its own s you mov! This
More informationComplete Solutions for MATH 3012 Quiz 2, October 25, 2011, WTT
Complt Solutions or MATH 012 Quiz 2, Otor 25, 2011, WTT Not. T nswrs ivn r r mor omplt tn is xpt on n tul xm. It is intn tt t mor omprnsiv solutions prsnt r will vlul to stunts in stuyin or t inl xm. In
More information4.1 Interval Scheduling. Chapter 4. Greedy Algorithms. Interval Scheduling: Greedy Algorithms. Interval Scheduling. Interval scheduling.
Cptr 4 4 Intrvl Suln Gry Alortms Sls y Kvn Wyn Copyrt 005 Prson-Ason Wsly All rts rsrv Intrvl Suln Intrvl Suln: Gry Alortms Intrvl suln! Jo strts t s n nss t! Two os omptl ty on't ovrlp! Gol: n mxmum sust
More informationIn which direction do compass needles always align? Why?
AQA Trloy Unt 6.7 Mntsm n Eltromntsm - Hr 1 Complt t p ll: Mnt or s typ o or n t s stronst t t o t mnt. Tr r two typs o mnt pol: n. Wrt wt woul ppn twn t pols n o t mnt ntrtons low: Drw t mnt l lns on
More informationNefertiti. Echoes of. Regal components evoke visions of the past MULTIPLE STITCHES. designed by Helena Tang-Lim
MULTIPLE STITCHES Nrtiti Ehos o Rgl omponnts vok visions o th pst sign y Hln Tng-Lim Us vrity o stiths to rt this rgl yt wrl sign. Prt sping llows squr s to mk roun omponnts tht rp utiully. FCT-SC-030617-07
More informationImproving Union. Implementation. Union-by-size Code. Union-by-Size Find Analysis. Path Compression! Improving Find find(e)
POW CSE 36: Dt Struturs Top #10 T Dynm (Equvln) Duo: Unon-y-Sz & Pt Comprsson Wk!! Luk MDowll Summr Qurtr 003 M! ZING Wt s Goo Mz? Mz Construton lortm Gvn: ollton o rooms V Conntons twn t rooms (ntlly
More informationCS 103 BFS Alorithm. Mark Redekopp
CS 3 BFS Aloritm Mrk Rkopp Brt-First Sr (BFS) HIGHLIGHTED ALGORITHM 3 Pt Plnnin W'v sn BFS in t ontxt o inin t sortst pt trou mz? S?? 4 Pt Plnnin W xplor t 4 niors s on irtion 3 3 3 S 3 3 3 3 3 F I you
More informationCS61B Lecture #33. Administrivia: Autograder will run this evening. Today s Readings: Graph Structures: DSIJ, Chapter 12
Aministrivi: CS61B Ltur #33 Autogrr will run this vning. Toy s Rings: Grph Struturs: DSIJ, Chptr 12 Lst moifi: W Nov 8 00:39:28 2017 CS61B: Ltur #33 1 Why Grphs? For xprssing non-hirrhilly rlt itms Exmpls:
More informationAnnouncements. Not graphs. These are Graphs. Applications of Graphs. Graph Definitions. Graphs & Graph Algorithms. A6 released today: Risk
Grphs & Grph Algorithms Ltur CS Spring 6 Announmnts A6 rls toy: Risk Strt signing with your prtnr sp Prlim usy Not grphs hs r Grphs K 5 K, =...not th kin w mn, nywy Applitions o Grphs Communition ntworks
More informationCycles and Simple Cycles. Paths and Simple Paths. Trees. Problem: There is No Completely Standard Terminology!
Outlin Computr Sin 331, Spnnin, n Surphs Mik Joson Dprtmnt o Computr Sin Univrsity o Clry Ltur #30 1 Introution 2 3 Dinition 4 Spnnin 5 6 Mik Joson (Univrsity o Clry) Computr Sin 331 Ltur #30 1 / 20 Mik
More informationSimilarity Search. The Binary Branch Distance. Nikolaus Augsten.
Similrity Srh Th Binry Brnh Distn Nikolus Augstn nikolus.ugstn@sg..t Dpt. of Computr Sins Univrsity of Slzurg http://rsrh.uni-slzurg.t Vrsion Jnury 11, 2017 Wintrsmstr 2016/2017 Augstn (Univ. Slzurg) Similrity
More informationDesigning A Concrete Arch Bridge
This is th mous Shwnh ri in Switzrln, sin y Rort Millrt in 1933. It spns 37.4 mtrs (122 t) n ws sin usin th sm rphil mths tht will monstrt in this lsson. To pro with this lsson, lik on th Nxt utton hr
More informationDivided. diamonds. Mimic the look of facets in a bracelet that s deceptively deep RIGHT-ANGLE WEAVE. designed by Peggy Brinkman Matteliano
RIGHT-ANGLE WEAVE Dv mons Mm t look o ts n rlt tt s ptvly p sn y Py Brnkmn Mttlno Dv your mons nto trnls o two or our olors. FCT-SCON0216_BNB66 2012 Klm Pulsn Co. Ts mtrl my not rprou n ny orm wtout prmsson
More informationWeighted graphs -- reminder. Data Structures LECTURE 15. Shortest paths algorithms. Example: weighted graph. Two basic properties of shortest paths
Dt Strutur LECTURE Shortt pth lgorithm Proprti of hortt pth Bllmn-For lgorithm Dijktr lgorithm Chptr in th txtook (pp ). Wight grph -- rminr A wight grph i grph in whih g hv wight (ot) w(v i, v j ) >.
More informationMath 166 Week in Review 2 Sections 1.1b, 1.2, 1.3, & 1.4
Mt 166 WIR, Sprin 2012, Bnjmin urisp Mt 166 Wk in Rviw 2 Stions 1.1, 1.2, 1.3, & 1.4 1. S t pproprit rions in Vnn irm tt orrspon to o t ollowin sts. () (B ) B () ( ) B B () (B ) B 1 Mt 166 WIR, Sprin 2012,
More informationEE1000 Project 4 Digital Volt Meter
Ovrviw EE1000 Projt 4 Diitl Volt Mtr In this projt, w mk vi tht n msur volts in th rn o 0 to 4 Volts with on iit o ury. Th input is n nlo volt n th output is sinl 7-smnt iit tht tlls us wht tht input s
More informationCMPS 2200 Fall Graphs. Carola Wenk. Slides courtesy of Charles Leiserson with changes and additions by Carola Wenk
CMPS 2200 Fll 2017 Grps Crol Wnk Sls ourtsy o Crls Lsrson wt ns n tons y Crol Wnk 10/23/17 CMPS 2200 Intro. to Alortms 1 Grps Dnton. A rt rp (rp) G = (V, E) s n orr pr onsstn o st V o vrts (snulr: vrtx),
More informationCS200: Graphs. Graphs. Directed Graphs. Graphs/Networks Around Us. What can this represent? Sometimes we want to represent directionality:
CS2: Grphs Prihr Ch. 4 Rosn Ch. Grphs A olltion of nos n gs Wht n this rprsnt? n A omputr ntwork n Astrtion of mp n Soil ntwork CS2 - Hsh Tls 2 Dirt Grphs Grphs/Ntworks Aroun Us A olltion of nos n irt
More informationCS 241 Analysis of Algorithms
CS 241 Anlysis o Algorithms Prossor Eri Aron Ltur T Th 9:00m Ltur Mting Lotion: OLB 205 Businss HW6 u lry HW7 out tr Thnksgiving Ring: Ch. 22.1-22.3 1 Grphs (S S. B.4) Grphs ommonly rprsnt onntions mong
More informationSection 10.4 Connectivity (up to paths and isomorphism, not including)
Toy w will isuss two stions: Stion 10.3 Rprsnting Grphs n Grph Isomorphism Stion 10.4 Conntivity (up to pths n isomorphism, not inluing) 1 10.3 Rprsnting Grphs n Grph Isomorphism Whn w r working on n lgorithm
More information(Minimum) Spanning Trees
(Mnmum) Spnnn Trs Spnnn trs Kruskl's lortm Novmr 23, 2017 Cn Hrn / Gory Tn 1 Spnnn trs Gvn G = V, E, spnnn tr o G s onnt surp o G wt xtly V 1 s mnml sust o s tt onnts ll t vrts o G G = Spnnn trs Novmr
More informationSEE PAGE 2 FOR BRUSH MOTOR WIRING SEE PAGE 3 FOR MANUFACTURER SPECIFIC BLDC MOTOR WIRING EXAMPLES EZ SERVO EZSV17 WIRING DIAGRAM FOR BLDC MOTOR
0V TO 0V SUPPLY GROUN +0V TO +0V RS85 ONVRTR 9 TO OM PORT ON P TO P OM PORT US 9600 U 8IT, NO PRITY, STOP, NO FLOW TRL. OPTO SNSOR # GROUN +0V TO +0V GROUN RS85 RS85 OPTO SNSOR # PHOTO TRNSISTOR TO OTHR
More informationQUESTIONS BEGIN HERE!
Points miss: Stunt's Nm: Totl sor: /100 points Est Tnnss Stt Univrsity Dprtmnt of Computr n Informtion Sins CSCI 710 (Trnoff) Disrt Struturs TEST for Fll Smstr, 00 R this for strtin! This tst is los ook
More information12/3/12. Outline. Part 10. Graphs. Circuits. Euler paths/circuits. Euler s bridge problem (Bridges of Konigsberg Problem)
12/3/12 Outlin Prt 10. Grphs CS 200 Algorithms n Dt Struturs Introution Trminology Implmnting Grphs Grph Trvrsls Topologil Sorting Shortst Pths Spnning Trs Minimum Spnning Trs Ciruits 1 Ciruits Cyl 2 Eulr
More information5/9/13. Part 10. Graphs. Outline. Circuits. Introduction Terminology Implementing Graphs
Prt 10. Grphs CS 200 Algorithms n Dt Struturs 1 Introution Trminology Implmnting Grphs Outlin Grph Trvrsls Topologil Sorting Shortst Pths Spnning Trs Minimum Spnning Trs Ciruits 2 Ciruits Cyl A spil yl
More informationCOMPLEXITY OF COUNTING PLANAR TILINGS BY TWO BARS
OMPLXITY O OUNTING PLNR TILINGS Y TWO RS KYL MYR strt. W show tht th prolm o trmining th numr o wys o tiling plnr igur with horizontl n vrtil r is #P-omplt. W uil o o th rsults o uquir, Nivt, Rmil, n Roson
More informationSpanning Trees. BFS, DFS spanning tree Minimum spanning tree. March 28, 2018 Cinda Heeren / Geoffrey Tien 1
Spnnn Trs BFS, DFS spnnn tr Mnmum spnnn tr Mr 28, 2018 Cn Hrn / Gory Tn 1 Dpt-rst sr Vsts vrts lon snl pt s r s t n o, n tn ktrks to t rst junton n rsums own notr pt Mr 28, 2018 Cn Hrn / Gory Tn 2 Dpt-rst
More informationHaving a glimpse of some of the possibilities for solutions of linear systems, we move to methods of finding these solutions. The basic idea we shall
Hvn lps o so o t posslts or solutons o lnr systs, w ov to tos o nn ts solutons. T s w sll us s to try to sply t syst y lntn so o t vrls n so ts qutons. Tus, w rr to t to s lnton. T prry oprton nvolv s
More informationPhysics 222 Midterm, Form: A
Pysis 222 Mitrm, Form: A Nm: Dt: Hr r som usul onstnts. 1 4πɛ 0 = 9 10 9 Nm 2 /C 2 µ0 4π = 1 10 7 tsl s/c = 1.6 10 19 C Qustions 1 5: A ipol onsistin o two r point-lik prtils wit q = 1 µc, sprt y istn
More informationEdge-Triggered D Flip-flop. Formal Analysis. Fundamental-Mode Sequential Circuits. D latch: How do flip-flops work?
E-Trir D Flip-Flop Funamntal-Mo Squntial Ciruits PR A How o lip-lops work? How to analys aviour o lip-lops? R How to sin unamntal-mo iruits? Funamntal mo rstrition - only on input an an at a tim; iruit
More informationAquauno Video 6 Plus Page 1
Connt th timr to th tp. Aquuno Vio 6 Plus Pg 1 Usr mnul 3 lik! For Aquuno Vio 6 (p/n): 8456 For Aquuno Vio 6 Plus (p/n): 8413 Opn th timr unit y prssing th two uttons on th sis, n fit 9V lklin ttry. Whn
More informationProblem solving by search
Prolm solving y srh Tomáš voo Dprtmnt o Cyrntis, Vision or Roots n Autonomous ystms Mrh 5, 208 / 3 Outlin rh prolm. tt sp grphs. rh trs. trtgis, whih tr rnhs to hoos? trtgy/algorithm proprtis? Progrmming
More information12 - M G P L Z - M9BW. Port type. Bore size ø12, ø16 20/25/32/40/50/ MPa 10 C to 60 C (With no condensation) 50 to 400 mm/s +1.
ris - MP - Compt gui ylinr ø, ø, ø, ø, ø, ø, ø, ø ow to Orr Cln sris lif typ (with spilly trt sliing prts) Vuum sution typ (with spilly trt sliing prts) ir ylinr otry tutor - M P - - MW ll ushing ring
More informationFunctions and Graphs 1. (a) (b) (c) (f) (e) (d) 2. (a) (b) (c) (d)
Functions nd Grps. () () (c) - - - O - - - O - - - O - - - - (d) () (f) - - O - 7 6 - - O - -7-6 - - - - - O. () () (c) (d) - - - O - O - O - - O - -. () G() f() + f( ), G(-) f( ) + f(), G() G( ) nd G()
More informationChem 104A, Fall 2016, Midterm 1 Key
hm 104A, ll 2016, Mitrm 1 Ky 1) onstruct microstt tl for p 4 configurtion. Pls numrt th ms n ml for ch lctron in ch microstt in th tl. (Us th formt ml m s. Tht is spin -½ lctron in n s oritl woul writtn
More informationRegister Allocation. Register Allocation. Principle Phases. Principle Phases. Example: Build. Spills 11/14/2012
Rgistr Allotion W now r l to o rgistr llotion on our intrfrn grph. W wnt to l with two typs of onstrints: 1. Two vlus r liv t ovrlpping points (intrfrn grph) 2. A vlu must or must not in prtiulr rhitturl
More informationThe Plan. Honey, I Shrunk the Data. Why Compress. Data Compression Concepts. Braille Example. Braille. x y xˆ
h ln ony, hrunk th t ihr nr omputr in n nginring nivrsity of shington t omprssion onpts ossy t omprssion osslss t omprssion rfix os uffmn os th y 24 2 t omprssion onpts originl omprss o x y xˆ nor or omprss
More informationSeven-Segment Display Driver
7-Smnt Disply Drivr, Ron s in 7-Smnt Disply Drivr, Ron s in Prolm 62. 00 0 0 00 0000 000 00 000 0 000 00 0 00 00 0 0 0 000 00 0 00 BCD Diits in inry Dsin Drivr Loi 4 inputs, 7 outputs 7 mps, h with 6 on
More informationMULTIPLE-LEVEL LOGIC OPTIMIZATION II
MUTIPE-EVE OGIC OPTIMIZATION II Booln mthos Eploit Booln proprtis Giovnni D Mihli Don t r onitions Stnfor Univrsit Minimition of th lol funtions Slowr lgorithms, ttr qulit rsults Etrnl on t r onitions
More informationDepth First Search. Yufei Tao. Department of Computer Science and Engineering Chinese University of Hong Kong
Dprtmnt o Computr Sn n Ennrn Cns Unvrsty o Hon Kon W v lry lrn rt rst sr (BFS). Toy, w wll suss ts sstr vrson : t pt rst sr (DFS) lortm. Our susson wll on n ous on rt rps, us t xtnson to unrt rps s strtorwr.
More informationCS553 Lecture Register Allocation I 3
Low-Lvl Issus Last ltur Intrproural analysis Toay Start low-lvl issus Rgistr alloation Latr Mor rgistr alloation Instrution shuling CS553 Ltur Rgistr Alloation I 2 Rgistr Alloation Prolm Assign an unoun
More informationGraphs. CSC 1300 Discrete Structures Villanova University. Villanova CSC Dr Papalaskari
Grphs CSC 1300 Disrt Struturs Villnov Univrsity Grphs Grphs r isrt struturs onsis?ng of vr?s n gs tht onnt ths vr?s. Grphs n us to mol: omputr systms/ntworks mthm?l rl?ons logi iruit lyout jos/prosss f
More information10/5/2012 S. THAI SUBHA CHAPTER-V
/5/ /5/ S. THAI SUBHA CHAPTER-V FIR is finit impuls rspons. FIR systm s n impuls rspons tt is ro outsi of sm finit tim intrvl. FIR systm s finit mmory of lngt M smpls. /5/ S. THAI SUBHA CHAPTER-V /5/ IIR
More informationA Low Noise and Reliable CMOS I/O Buffer for Mixed Low Voltage Applications
Proings of th 6th WSEAS Intrntionl Confrn on Miroltronis, Nnoltronis, Optoltronis, Istnul, Turky, My 27-29, 27 32 A Low Nois n Rlil CMOS I/O Buffr for Mix Low Voltg Applitions HWANG-CHERNG CHOW n YOU-GANG
More informationDecimals DECIMALS.
Dimls DECIMALS www.mthltis.o.uk ow os it work? Solutions Dimls P qustions Pl vlu o imls 0 000 00 000 0 000 00 0 000 00 0 000 00 0 000 tnths or 0 thousnths or 000 hunrths or 00 hunrths or 00 0 tn thousnths
More informationJonathan Turner Exam 2-10/28/03
CS Algorihm n Progrm Prolm Exm Soluion S Soluion Jonhn Turnr Exm //. ( poin) In h Fioni hp ruur, u wn vrx u n i prn v u ing u v i v h lry lo hil in i l m hil o om ohr vrx. Suppo w hng hi, o h ing u i prorm
More informationTheorem 1. An undirected graph is a tree if and only if there is a unique simple path between any two of its vertices.
Cptr 11: Trs 11.1 - Introuton to Trs Dnton 1 (Tr). A tr s onnt unrt rp wt no sp ruts. Tor 1. An unrt rp s tr n ony tr s unqu sp pt twn ny two o ts vrts. Dnton 2. A root tr s tr n w on vrtx s n snt s t
More informationVLSI Testing Assignment 2
1. 5-vlu D-clculus trut tbl or t XOR unction: XOR 0 1 X D ~D 0 0 1 X D ~D 1 1 0 X ~D D X X X X X X D D ~D X 0 1 ~D ~D D X 1 0 Tbl 1: 5-vlu D-clculus Trut Tbl or t XOR Function Sinc 2-input XOR t wors s
More informationFormal Concept Analysis
Forml Conpt Anlysis Conpt intnts s losd sts Closur Systms nd Implitions 4 Closur Systms 0.06.005 Nxt-Closur ws dvlopd y B. Gntr (984). Lt M = {,..., n}. A M is ltilly smllr thn B M, if B A if th smllst
More information