I I T A C A D E M Y CPT XII-NEW (REG) Batches (Date: ) ANSWERS PHYSICS CHEMISTRY MATHEMATICS 1. (A) 31. (A) 61. (B) 2. (A) 32.

Size: px
Start display at page:

Download "I I T A C A D E M Y CPT XII-NEW (REG) Batches (Date: ) ANSWERS PHYSICS CHEMISTRY MATHEMATICS 1. (A) 31. (A) 61. (B) 2. (A) 32."

Transcription

1 CPT-/XII-S (NEW)/ NARAYANA I I T A C A D E M Y CPT - XII-NEW (REG) Baches (Dae: ) ANSWERS PHYSICS CHEMISTRY MATHEMATICS. (A). (A) 6. (B). (A). (C) 6. (A). (D). (B) 6. (A). (C). (B) 6. (B) 5. (B) 5. (B) 65. (B) 6. (C) 6. (A) 66. (A) 7. (C) 7. (D) 67. (C) 8. (A) 8. (D) 68. (A) 9. (C) 9. (B) 69. (A) 0. (C) 0. (B) 70. (A). (A). (A) 7. (C). (B). (B) 7. (D). (B). (B) 7. (A). (C). (C) 7. (A) 5. (C) 5. (C) 75. (B) 6. (B) 6. (C) 76. (A) 7. (C) 7. (C) 77. (B) 8. (B) 8. (A) 78. (C) 9. (C) 9. (B) 79. (B) 0. (B) 50. (A) 80. (B). (D) 5. (A) 8. (D). (D) 5. (B) 8. (D). (A) 5. (D) 8. (B). (A) 5. (B) 8. (A) 5. (C) 55. (B) 85. (D) 6. (B) 56. (D) 86. (D) 7. (A) 57. (B) 87. (A) 8. (A) 58. (A) 88. (A) 9. (B) 59. (A) 89. (A) 0. (C) 60. (A) 90. (A). (A). (A). (D) Hins & Soluion PART A: PHYSICS

2 . (C) 5. (B) 6. (C) 7. (C) 8. (A) 9. (C) de Bvd CPT-/XII-S (NEW)/ de Bω d l 0 d de Bωd Bωl e M 0. (C) ( l) I A. db 6 (A) e A d dφ db. (B) E dl A d d qe a Direcion of induced field and deermined from Lenz s law m. ( φ φ) ( 0 NBA) (B) e 0.s NBA s e 0.. dφ (C) q id ed d R R d R dφ (aking only magniude of e) Hence, oal charge induced in he conducing loop depends upon he oal change in magneic flu. 5. (C) dφ da d dr e B Bπ R π BR d d d d π B R ( 0 ) ( 0 ) π B R As magneic flu increases in he inward direcion, herefore induced curren will flow in he aniclockwise direcion so as o oppose his increase. 6. (B) 7. (C) 8. (B) 9. (C) L L πr; R ; T sin dθ dθ π 0. (C)

3 . (D). (D). (A). (A) 5. (C) 6. (B) For small angles, sin( d ) θ dθ T( dθ ) I( dl) Bsin 90º; I( Rdθ ) B ILB T IRB ; correc opion is (C) π 7. (A) i ( / 0 / i0 e τ ) CPT-/XII-S (NEW)/ or, e / τ or, ln τ giving τ ln (5 ms) (0.69).5 ms 8. (A) The energy in he magneic field associaed wih he coil is ε / U Li L e....(i) R The ime consan of he circui is τ L.0H 0ms R 00ω Puing he numerical values in (i), he energy a 0 ms is (.0H ) 0.A ( / e ).8 mj 9. (B) Suppose a curren i is esablished in he ouer loop. The magneic field a he cenre will be τ µ 0i B R As he radius R of he inner coil is small compared o R, he flu of magneic field hrough i will be approimaely µ 0i φ π R R So ha he muual inducance is φ µ 0πR M i R 0. (C) The emf induced in he loop is ε vbl v T 0cm. 0

4 The curren in he loop will be i or, v0 T 0.m ε R 0 A Ω ( Ω )( 0 A) giving v0 cms 0.Tm PART B: CHEMISTRY CPT-/XII-S (NEW)/ (A) CF is elecron wihdrawing. So, inermediaes CF C CH will be unsable. H H. (C) Dehydrohalogenaion occurs by E mechanism sayzeff rule is followed and more sable rans--buene is he major produc.. (B) CCl Br CH CH CH HBr CH CH CH Elecrophilic addiion by mark rule CH CH CH Br CH CHBrCH HBr (F. R. subsiuional) hν Alhough propane has si o and only wo o hydrogens ye heir raes of absracion by Br are widely differen, i..e, : 8. Therefore, he major produc is -bromopropane.. (B) In presence of peroides, only he addiion of HBr o unsymmerical alkenes does no occur according o Markovnikov s rule. Since alkene (B) is unsymmerical while alkene (D) is symmerical, herefore, he correc answer is alkene (B). 5. (B) 6. (A) 7. (D)

5 CPT-/XII-S (NEW)/ (D) Ozonolysis sicne all he hree alkenes will give differen producs as shown below: 9. (B) CH CH CH OO CH CH CH CH CH CH CH 0. (B). (A). (B). (B). (C) 5. (C) 6. (C) 7. (C) 8. (A) 9. (B) 50. (A) 5. (A) 5. (B) 5. (D) 5. (B) 55. (B) 56. (D) 57. (B) 58. (A) 59. (A) 60. (A) 6. (B) ( sec an ) I d 6. (A) Pu and use by pars PART C: MATHEMATICS 5

6 6. (A) Pu 6. (B) GI d d d 65. (B) 66. (A) Pu We have, ( ) ( loge ) ( loge ) d c c 6 5 z d 6zdz d 6 z z z z z dz z log C (C) Pu z d dz z n n ( z z ) dz z n n z z c z 68. (A) sec CPT-/XII-S (NEW)/ sine We have, d cos sec e d( sec ) sec e c 69. (A) Pu sin θ sinθ I d cos θ θ cosθdθ ( cosθ sinθ ) ( cosθ sinθ) 70. (A) Pu asinθ dθ sinθ cosθ sinθ cosθ U log sec an, V cos hen use inegraion by pars 7. (C) 6

7 7. (D) ( e sin sin sin 8cos ) d e ( sin sin ) e ( sin cos ) e ( sin sin ) c 7. (A) ( ) I e d ( ) and using he formula e f f d 7. (A) ( ) and ( ) e e c 75. (B) Pu log e ( ) d sin cos 76. (A) I d sin sin α e d e sec an d e an c ( α α) sin sin cos cos sin ( α α ) sin cos sin co cosec ( cosα sinα co) Pu cosα sinα co, d 0 sinα cosec d d c sinα sinα ( cosα sinα co) c sinα 77. (B) Pu anθ 78. (C) Pu d d d CPT-/XII-S (NEW)/

8 6 d (B) Le d (B) e ( ) d d u d du du an u c u an e e c d ( )( ) ( ) ( ) ( )( ) d d d an an c 6 8. (D) ( ) ( ) ( )( ) 8. (D) Pu y 8. (B) I d d d I d CPT-/XII-S (NEW)/

9 8. (A) Pu CPT-/XII-S (NEW)/ (D) ( 5) ( )( ) (D) I ln ( ) c c 87. (A) d cos sin d π cos π loge an c sec π d 88. (A) Pu a cos b sin 89. (A) Pu U, V a sec 90. (A) e d / ( ) ******************************************************************************** NEXT CPT(XII-NEW): TEST DATE & SYLLABUS CPT JEE ADVANCED MODEL Syllabus for all Advance Model CPTs: Syllabus covering from Previous Advance model CPT o previous week. PHY Elecric dipole, Capacior, Curren Elecriciy, Magneic field & Magneism Complee, Elecromagneic Inducion, Alernaing Curren (.05.6 o -07-6) CHEM- Elecrochemisry, Chemical Kineics, Surface Chemisry, Chemisry in EveryDay life, GOC, Aromaiciy, EAS, Alkane, Alkene, Alkyne (.05.6 o ) MATH Coninuiy & differeniabiliy, Applicaion of Derivaive, Indefinie inegraion. (.05.6 o ) 9

3. Alternating Current

3. Alternating Current 3. Alernaing Curren TOPCS Definiion and nroducion AC Generaor Componens of AC Circuis Series LRC Circuis Power in AC Circuis Transformers & AC Transmission nroducion o AC The elecric power ou of a home

More information

Name: Total Points: Multiple choice questions [120 points]

Name: Total Points: Multiple choice questions [120 points] Name: Toal Poins: (Las) (Firs) Muliple choice quesions [1 poins] Answer all of he following quesions. Read each quesion carefully. Fill he correc bubble on your scanron shee. Each correc answer is worh

More information

Chapter 10 INDUCTANCE Recommended Problems:

Chapter 10 INDUCTANCE Recommended Problems: Chaper 0 NDUCTANCE Recommended Problems: 3,5,7,9,5,6,7,8,9,,,3,6,7,9,3,35,47,48,5,5,69, 7,7. Self nducance Consider he circui shown in he Figure. When he swich is closed, he curren, and so he magneic field,

More information

8.022 (E&M) Lecture 16

8.022 (E&M) Lecture 16 8. (E&M) ecure 16 Topics: Inducors in circuis circuis circuis circuis as ime Our second lecure on elecromagneic inducance 3 ways of creaing emf using Faraday s law: hange area of circui S() hange angle

More information

Physics 111. Exam #1. January 24, 2011

Physics 111. Exam #1. January 24, 2011 Physics 111 Exam #1 January 4, 011 Name Muliple hoice /16 Problem #1 /8 Problem # /8 Problem #3 /8 Toal /100 ParI:Muliple hoice:irclehebesansweroeachquesion.nyohermarks willnobegivencredi.eachmuliple choicequesionisworh4poinsoraoalo

More information

Physics 1402: Lecture 22 Today s Agenda

Physics 1402: Lecture 22 Today s Agenda Physics 142: ecure 22 Today s Agenda Announcemens: R - RV - R circuis Homework 6: due nex Wednesday Inducion / A curren Inducion Self-Inducance, R ircuis X X X X X X X X X long solenoid Energy and energy

More information

Reading from Young & Freedman: For this topic, read sections 25.4 & 25.5, the introduction to chapter 26 and sections 26.1 to 26.2 & 26.4.

Reading from Young & Freedman: For this topic, read sections 25.4 & 25.5, the introduction to chapter 26 and sections 26.1 to 26.2 & 26.4. PHY1 Elecriciy Topic 7 (Lecures 1 & 11) Elecric Circuis n his opic, we will cover: 1) Elecromoive Force (EMF) ) Series and parallel resisor combinaions 3) Kirchhoff s rules for circuis 4) Time dependence

More information

THE SINE INTEGRAL. x dt t

THE SINE INTEGRAL. x dt t THE SINE INTEGRAL As one learns in elemenary calculus, he limi of sin(/ as vanishes is uniy. Furhermore he funcion is even and has an infinie number of zeros locaed a ±n for n1,,3 Is plo looks like his-

More information

copper ring magnetic field

copper ring magnetic field IB PHYSICS: Magneic Fields, lecromagneic Inducion, Alernaing Curren 1. This quesion is abou elecromagneic inducion. In 1831 Michael Faraday demonsraed hree ways of inducing an elecric curren in a ring

More information

- If one knows that a magnetic field has a symmetry, one may calculate the magnitude of B by use of Ampere s law: The integral of scalar product

- If one knows that a magnetic field has a symmetry, one may calculate the magnitude of B by use of Ampere s law: The integral of scalar product 11.1 APPCATON OF AMPEE S AW N SYMMETC MAGNETC FEDS - f one knows ha a magneic field has a symmery, one may calculae he magniude of by use of Ampere s law: The inegral of scalar produc Closed _ pah * d

More information

Physics 1502: Lecture 20 Today s Agenda

Physics 1502: Lecture 20 Today s Agenda Physics 152: Lecure 2 Today s Agenda Announcemens: Chap.27 & 28 Homework 6: Friday nducion Faraday's Law ds N S v S N v 1 A Loop Moving Through a Magneic Field ε() =? F() =? Φ() =? Schemaic Diagram of

More information

4. Electric field lines with respect to equipotential surfaces are

4. Electric field lines with respect to equipotential surfaces are Pre-es Quasi-saic elecromagneism. The field produced by primary charge Q and by an uncharged conducing plane disanced from Q by disance d is equal o he field produced wihou conducing plane by wo following

More information

Chapter 4 AC Network Analysis

Chapter 4 AC Network Analysis haper 4 A Nework Analysis Jaesung Jang apaciance Inducance and Inducion Time-Varying Signals Sinusoidal Signals Reference: David K. heng, Field and Wave Elecromagneics. Energy Sorage ircui Elemens Energy

More information

Basic Circuit Elements Professor J R Lucas November 2001

Basic Circuit Elements Professor J R Lucas November 2001 Basic Circui Elemens - J ucas An elecrical circui is an inerconnecion of circui elemens. These circui elemens can be caegorised ino wo ypes, namely acive and passive elemens. Some Definiions/explanaions

More information

Direct Current Circuits. February 19, 2014 Physics for Scientists & Engineers 2, Chapter 26 1

Direct Current Circuits. February 19, 2014 Physics for Scientists & Engineers 2, Chapter 26 1 Direc Curren Circuis February 19, 2014 Physics for Scieniss & Engineers 2, Chaper 26 1 Ammeers and Volmeers! A device used o measure curren is called an ammeer! A device used o measure poenial difference

More information

Homework: See website. Table of Contents

Homework: See website. Table of Contents Dr. Friz Wilhelm page of 4 C:\physics\3 lecure\ch3 Inducance C circuis.docx; P /5/8 S: 5/4/9 9:39: AM Homework: See websie. Table of Conens: 3. Self-inducance in a circui, 3. -Circuis, 4 3.a Charging he

More information

Solutions to JEE Mains/Test Series - 9/IITJEE

Solutions to JEE Mains/Test Series - 9/IITJEE Soluions o JEE Mains/Tes Series - 9/IITJEE - [CHEMISTRY].(C).(C).(A).(D) 5.(D) By conservaion of moles PV P V P V + RT RT R T P + P am. Saemen-II violaes he iner pair effec. Hence i is false. KMnO will

More information

MEMS 0031 Electric Circuits

MEMS 0031 Electric Circuits MEMS 0031 Elecric Circuis Chaper 1 Circui variables Chaper/Lecure Learning Objecives A he end of his lecure and chaper, you should able o: Represen he curren and volage of an elecric circui elemen, paying

More information

University of Cyprus Biomedical Imaging and Applied Optics. Appendix. DC Circuits Capacitors and Inductors AC Circuits Operational Amplifiers

University of Cyprus Biomedical Imaging and Applied Optics. Appendix. DC Circuits Capacitors and Inductors AC Circuits Operational Amplifiers Universiy of Cyprus Biomedical Imaging and Applied Opics Appendix DC Circuis Capaciors and Inducors AC Circuis Operaional Amplifiers Circui Elemens An elecrical circui consiss of circui elemens such as

More information

Maxwell s Equations and Electromagnetic Waves

Maxwell s Equations and Electromagnetic Waves Phsics 36: Waves Lecure 3 /9/8 Maxwell s quaions and lecromagneic Waves Four Laws of lecromagneism. Gauss Law qenc all da ρdv Inegral From From he vecor ideni da dv Therefore, we ma wrie Gauss Law as ρ

More information

Voltage/current relationship Stored Energy. RL / RC circuits Steady State / Transient response Natural / Step response

Voltage/current relationship Stored Energy. RL / RC circuits Steady State / Transient response Natural / Step response Review Capaciors/Inducors Volage/curren relaionship Sored Energy s Order Circuis RL / RC circuis Seady Sae / Transien response Naural / Sep response EE4 Summer 5: Lecure 5 Insrucor: Ocavian Florescu Lecure

More information

Electromagnetic Induction: The creation of an electric current by a changing magnetic field.

Electromagnetic Induction: The creation of an electric current by a changing magnetic field. Inducion 1. Inducion 1. Observaions 2. Flux 1. Inducion Elecromagneic Inducion: The creaion of an elecric curren by a changing magneic field. M. Faraday was he firs o really invesigae his phenomenon o

More information

Chapter 16: Summary. Instructor: Jean-François MILLITHALER.

Chapter 16: Summary. Instructor: Jean-François MILLITHALER. Chaper 16: Summary Insrucor: Jean-François MILLITHALER hp://faculy.uml.edu/jeanfrancois_millihaler/funelec/spring2017 Slide 1 Curren & Charge Elecric curren is he ime rae of change of charge, measured

More information

Lecture 13 RC/RL Circuits, Time Dependent Op Amp Circuits

Lecture 13 RC/RL Circuits, Time Dependent Op Amp Circuits Lecure 13 RC/RL Circuis, Time Dependen Op Amp Circuis RL Circuis The seps involved in solving simple circuis conaining dc sources, resisances, and one energy-sorage elemen (inducance or capaciance) are:

More information

8. Basic RL and RC Circuits

8. Basic RL and RC Circuits 8. Basic L and C Circuis This chaper deals wih he soluions of he responses of L and C circuis The analysis of C and L circuis leads o a linear differenial equaion This chaper covers he following opics

More information

Chapter 8 The Complete Response of RL and RC Circuits

Chapter 8 The Complete Response of RL and RC Circuits Chaper 8 The Complee Response of RL and RC Circuis Seoul Naional Universiy Deparmen of Elecrical and Compuer Engineering Wha is Firs Order Circuis? Circuis ha conain only one inducor or only one capacior

More information

Hall effect. Formulae :- 1) Hall coefficient RH = cm / Coulumb. 2) Magnetic induction BY 2

Hall effect. Formulae :- 1) Hall coefficient RH = cm / Coulumb. 2) Magnetic induction BY 2 Page of 6 all effec Aim :- ) To deermine he all coefficien (R ) ) To measure he unknown magneic field (B ) and o compare i wih ha measured by he Gaussmeer (B ). Apparaus :- ) Gauss meer wih probe ) Elecromagne

More information

CHAPTER 55 DIFFERENTIATION OF PARAMETRIC EQUATIONS

CHAPTER 55 DIFFERENTIATION OF PARAMETRIC EQUATIONS CHAPTER 55 DIFFERENTIATION OF PARAMETRIC EQUATIONS EXERCISE 7 Page. Given an ( ), deermine in erms of. If, hen If ( ), hen ( ). A parabola has parameric equaions:,. Evaluae d d when 0.5 If, hen If, hen

More information

Phys1112: DC and RC circuits

Phys1112: DC and RC circuits Name: Group Members: Dae: TA s Name: Phys1112: DC and RC circuis Objecives: 1. To undersand curren and volage characerisics of a DC RC discharging circui. 2. To undersand he effec of he RC ime consan.

More information

SMT 2014 Calculus Test Solutions February 15, 2014 = 3 5 = 15.

SMT 2014 Calculus Test Solutions February 15, 2014 = 3 5 = 15. SMT Calculus Tes Soluions February 5,. Le f() = and le g() =. Compue f ()g (). Answer: 5 Soluion: We noe ha f () = and g () = 6. Then f ()g () =. Plugging in = we ge f ()g () = 6 = 3 5 = 5.. There is a

More information

MEI STRUCTURED MATHEMATICS 4758

MEI STRUCTURED MATHEMATICS 4758 OXFORD CAMBRIDGE AND RSA EXAMINATIONS Advanced Subsidiary General Cerificae of Educaion Advanced General Cerificae of Educaion MEI STRUCTURED MATHEMATICS 4758 Differenial Equaions Thursday 5 JUNE 006 Afernoon

More information

Challenge Problems. DIS 203 and 210. March 6, (e 2) k. k(k + 2). k=1. f(x) = k(k + 2) = 1 x k

Challenge Problems. DIS 203 and 210. March 6, (e 2) k. k(k + 2). k=1. f(x) = k(k + 2) = 1 x k Challenge Problems DIS 03 and 0 March 6, 05 Choose one of he following problems, and work on i in your group. Your goal is o convince me ha your answer is correc. Even if your answer isn compleely correc,

More information

CHAPTER 12 DIRECT CURRENT CIRCUITS

CHAPTER 12 DIRECT CURRENT CIRCUITS CHAPTER 12 DIRECT CURRENT CIUITS DIRECT CURRENT CIUITS 257 12.1 RESISTORS IN SERIES AND IN PARALLEL When wo resisors are conneced ogeher as shown in Figure 12.1 we said ha hey are conneced in series. As

More information

Chapter 28 - Circuits

Chapter 28 - Circuits Physics 4B Lecure Noes Chaper 28 - Circuis Problem Se #7 - due: Ch 28 -, 9, 4, 7, 23, 38, 47, 53, 57, 66, 70, 75 Lecure Ouline. Kirchoff's ules 2. esisors in Series 3. esisors in Parallel 4. More Complex

More information

Inductor Energy Storage

Inductor Energy Storage School of Compuer Science and Elecrical Engineering 5/5/ nducor Energy Sorage Boh capaciors and inducors are energy sorage devices They do no dissipae energy like a resisor, bu sore and reurn i o he circui

More information

C3 Exam Workshop 2. Workbook. 1. (a) Express 7 cos x 24 sin x in the form R cos (x + α) where R > 0 and 0 < α < 2

C3 Exam Workshop 2. Workbook. 1. (a) Express 7 cos x 24 sin x in the form R cos (x + α) where R > 0 and 0 < α < 2 C3 Exam Workshop 2 Workbook 1. (a) Express 7 cos x 24 sin x in the form R cos (x + α) where R > 0 and 0 < α < 2 π. Give the value of α to 3 decimal places. (b) Hence write down the minimum value of 7 cos

More information

RC, RL and RLC circuits

RC, RL and RLC circuits Name Dae Time o Complee h m Parner Course/ Secion / Grade RC, RL and RLC circuis Inroducion In his experimen we will invesigae he behavior of circuis conaining combinaions of resisors, capaciors, and inducors.

More information

MASSACHUSETTS INSTITUTE OF TECHNOLOGY Department of Physics Spring Experiment 9: Faraday s Law of Induction

MASSACHUSETTS INSTITUTE OF TECHNOLOGY Department of Physics Spring Experiment 9: Faraday s Law of Induction MASSACHUSETTS INSTITUTE OF TECHNOLOY Deparmen of Physics 8.02 Spring 2005 OBJECTIVES Experimen 9: Faraday s Law of Inducion 1. To become familiar wih he conceps of changing magneic flux and induced curren

More information

9. Alternating currents

9. Alternating currents WS 9. Alernaing currens 9.1 nroducion Besides ohmic resisors, capaciors and inducions play an imporan role in alernaing curren (AC circuis as well. n his experimen, one shall invesigae heir behaviour in

More information

WEEK-3 Recitation PHYS 131. of the projectile s velocity remains constant throughout the motion, since the acceleration a x

WEEK-3 Recitation PHYS 131. of the projectile s velocity remains constant throughout the motion, since the acceleration a x WEEK-3 Reciaion PHYS 131 Ch. 3: FOC 1, 3, 4, 6, 14. Problems 9, 37, 41 & 71 and Ch. 4: FOC 1, 3, 5, 8. Problems 3, 5 & 16. Feb 8, 018 Ch. 3: FOC 1, 3, 4, 6, 14. 1. (a) The horizonal componen of he projecile

More information

Lab 10: RC, RL, and RLC Circuits

Lab 10: RC, RL, and RLC Circuits Lab 10: RC, RL, and RLC Circuis In his experimen, we will invesigae he behavior of circuis conaining combinaions of resisors, capaciors, and inducors. We will sudy he way volages and currens change in

More information

!!"#"$%&#'()!"#&'(*%)+,&',-)./0)1-*23)

!!#$%&#'()!#&'(*%)+,&',-)./0)1-*23) "#"$%&#'()"#&'(*%)+,&',-)./)1-*) #$%&'()*+,&',-.%,/)*+,-&1*#$)()5*6$+$%*,7&*-'-&1*(,-&*6&,7.$%$+*&%'(*8$&',-,%'-&1*(,-&*6&,79*(&,%: ;..,*&1$&$.$%&'()*1$$.,'&',-9*(&,%)?%*,('&5

More information

3, so θ = arccos

3, so θ = arccos Mahemaics 210 Professor Alan H Sein Monday, Ocober 1, 2007 SOLUTIONS This problem se is worh 50 poins 1 Find he angle beween he vecors (2, 7, 3) and (5, 2, 4) Soluion: Le θ be he angle (2, 7, 3) (5, 2,

More information

Comparative study between two models of a linear oscillating tubular motor

Comparative study between two models of a linear oscillating tubular motor IOSR Journal of Elecrical and Elecronics Engineering (IOSR-JEEE) e-issn: 78-676,p-ISSN: 3-333, Volume 9, Issue Ver. IV (Feb. 4), PP 77-83 Comparaive sudy beween wo models of a linear oscillaing ubular

More information

Math 2142 Exam 1 Review Problems. x 2 + f (0) 3! for the 3rd Taylor polynomial at x = 0. To calculate the various quantities:

Math 2142 Exam 1 Review Problems. x 2 + f (0) 3! for the 3rd Taylor polynomial at x = 0. To calculate the various quantities: Mah 4 Eam Review Problems Problem. Calculae he 3rd Taylor polynomial for arcsin a =. Soluion. Le f() = arcsin. For his problem, we use he formula f() + f () + f ()! + f () 3! for he 3rd Taylor polynomial

More information

Wave Motion Sections 1,2,4,5, I. Outlook II. What is wave? III.Kinematics & Examples IV. Equation of motion Wave equations V.

Wave Motion Sections 1,2,4,5, I. Outlook II. What is wave? III.Kinematics & Examples IV. Equation of motion Wave equations V. Secions 1,,4,5, I. Oulook II. Wha is wave? III.Kinemaics & Eamples IV. Equaion of moion Wave equaions V. Eamples Oulook Translaional and Roaional Moions wih Several phsics quaniies Energ (E) Momenum (p)

More information

6.01: Introduction to EECS I Lecture 8 March 29, 2011

6.01: Introduction to EECS I Lecture 8 March 29, 2011 6.01: Inroducion o EES I Lecure 8 March 29, 2011 6.01: Inroducion o EES I Op-Amps Las Time: The ircui Absracion ircuis represen sysems as connecions of elemens hrough which currens (hrough variables) flow

More information

SINUSOIDAL WAVEFORMS

SINUSOIDAL WAVEFORMS SINUSOIDAL WAVEFORMS The sinusoidal waveform is he only waveform whose shape is no affeced by he response characerisics of R, L, and C elemens. Enzo Paerno CIRCUIT ELEMENTS R [ Ω ] Resisance: Ω: Ohms Georg

More information

ENGI 9420 Engineering Analysis Assignment 2 Solutions

ENGI 9420 Engineering Analysis Assignment 2 Solutions ENGI 940 Engineering Analysis Assignmen Soluions 0 Fall [Second order ODEs, Laplace ransforms; Secions.0-.09]. Use Laplace ransforms o solve he iniial value problem [0] dy y, y( 0) 4 d + [This was Quesion

More information

INDEX. Transient analysis 1 Initial Conditions 1

INDEX. Transient analysis 1 Initial Conditions 1 INDEX Secion Page Transien analysis 1 Iniial Condiions 1 Please inform me of your opinion of he relaive emphasis of he review maerial by simply making commens on his page and sending i o me a: Frank Mera

More information

t + t sin t t cos t sin t. t cos t sin t dt t 2 = exp 2 log t log(t cos t sin t) = Multiplying by this factor and then integrating, we conclude that

t + t sin t t cos t sin t. t cos t sin t dt t 2 = exp 2 log t log(t cos t sin t) = Multiplying by this factor and then integrating, we conclude that ODEs, Homework #4 Soluions. Check ha y ( = is a soluion of he second-order ODE ( cos sin y + y sin y sin = 0 and hen use his fac o find all soluions of he ODE. When y =, we have y = and also y = 0, so

More information

( ) = Q 0. ( ) R = R dq. ( t) = I t

( ) = Q 0. ( ) R = R dq. ( t) = I t ircuis onceps The addiion of a simple capacior o a circui of resisors allows wo relaed phenomena o occur The observaion ha he ime-dependence of a complex waveform is alered by he circui is referred o as

More information

AC Circuits AC Circuit with only R AC circuit with only L AC circuit with only C AC circuit with LRC phasors Resonance Transformers

AC Circuits AC Circuit with only R AC circuit with only L AC circuit with only C AC circuit with LRC phasors Resonance Transformers A ircuis A ircui wih only A circui wih only A circui wih only A circui wih phasors esonance Transformers Phys 435: hap 31, Pg 1 A ircuis New Topic Phys : hap. 6, Pg Physics Moivaion as ime we discovered

More information

Week #13 - Integration by Parts & Numerical Integration Section 7.2

Week #13 - Integration by Parts & Numerical Integration Section 7.2 Week #3 - Inegraion by Pars & Numerical Inegraion Secion 7. From Calculus, Single Variable by Hughes-Halle, Gleason, McCallum e. al. Copyrigh 5 by John Wiley & Sons, Inc. This maerial is used by permission

More information

Section 2.2 Charge and Current 2.6 b) The current direction is designated as the direction of the movement of positive charges.

Section 2.2 Charge and Current 2.6 b) The current direction is designated as the direction of the movement of positive charges. Chaper Soluions Secion. Inroducion. Curren source. Volage source. esisor.4 Capacior.5 Inducor Secion. Charge and Curren.6 b) The curren direcion is designaed as he direcion of he movemen of posiive charges..7

More information

Physics for Scientists & Engineers 2

Physics for Scientists & Engineers 2 Direc Curren Physics for Scieniss & Engineers 2 Spring Semeser 2005 Lecure 16 This week we will sudy charges in moion Elecric charge moving from one region o anoher is called elecric curren Curren is all

More information

Biot-Savart. The equation is this:

Biot-Savart. The equation is this: Biot-Savart When a wire carries a current, this current produces a magnetic field in the vicinity of the wire. One way of determining the strength and direction of this field is with the Law of Biot-Savart.

More information

MATH 31B: MIDTERM 2 REVIEW. x 2 e x2 2x dx = 1. ue u du 2. x 2 e x2 e x2] + C 2. dx = x ln(x) 2 2. ln x dx = x ln x x + C. 2, or dx = 2u du.

MATH 31B: MIDTERM 2 REVIEW. x 2 e x2 2x dx = 1. ue u du 2. x 2 e x2 e x2] + C 2. dx = x ln(x) 2 2. ln x dx = x ln x x + C. 2, or dx = 2u du. MATH 3B: MIDTERM REVIEW JOE HUGHES. Inegraion by Pars. Evaluae 3 e. Soluion: Firs make he subsiuion u =. Then =, hence 3 e = e = ue u Now inegrae by pars o ge ue u = ue u e u + C and subsiue he definiion

More information

2.4 Cuk converter example

2.4 Cuk converter example 2.4 Cuk converer example C 1 Cuk converer, wih ideal swich i 1 i v 1 2 1 2 C 2 v 2 Cuk converer: pracical realizaion using MOSFET and diode C 1 i 1 i v 1 2 Q 1 D 1 C 2 v 2 28 Analysis sraegy This converer

More information

Section 3.8, Mechanical and Electrical Vibrations

Section 3.8, Mechanical and Electrical Vibrations Secion 3.8, Mechanical and Elecrical Vibraions Mechanical Unis in he U.S. Cusomary and Meric Sysems Disance Mass Time Force g (Earh) Uni U.S. Cusomary MKS Sysem CGS Sysem fee f slugs seconds sec pounds

More information

Complete solutions to Exercise 14(b) 1. Very similar to EXAMPLE 4. We have same characteristic equation:

Complete solutions to Exercise 14(b) 1. Very similar to EXAMPLE 4. We have same characteristic equation: Soluions 4(b) Complee soluions o Exercise 4(b). Very similar o EXAMPE 4. We have same characerisic equaion: 5 i Ae = + Be By using he given iniial condiions we obain he simulaneous equaions A+ B= 0 5A

More information

where k=constant of proportionality , are two point charges (C) r = distance between the charges (m)

where k=constant of proportionality , are two point charges (C) r = distance between the charges (m) DMI COLLEGE OF ENGINEERING, CHENNAI DEPARTMENT OF ELECTRONICS AND COMMUNICATION ENGINNERING EC6403 ELECTRO MAGNETIC FIELDS UNIT-I: STATIC ELECTRIC FIELD PART-A (2 Marks) 1. Conver he given recangular coordinae

More information

UCLA: Math 3B Problem set 3 (solutions) Fall, 2018

UCLA: Math 3B Problem set 3 (solutions) Fall, 2018 UCLA: Mah 3B Problem se 3 (soluions) Fall, 28 This problem se concenraes on pracice wih aniderivaives. You will ge los of pracice finding simple aniderivaives as well as finding aniderivaives graphically

More information

Math 23 Spring Differential Equations. Final Exam Due Date: Tuesday, June 6, 5pm

Math 23 Spring Differential Equations. Final Exam Due Date: Tuesday, June 6, 5pm Mah Spring 6 Differenial Equaions Final Exam Due Dae: Tuesday, June 6, 5pm Your name (please prin): Insrucions: This is an open book, open noes exam. You are free o use a calculaor or compuer o check your

More information

IE1206 Embedded Electronics

IE1206 Embedded Electronics E06 Embedded Elecronics Le Le3 Le4 Le Ex Ex P-block Documenaion, Seriecom Pulse sensors,, R, P, serial and parallel K LAB Pulse sensors, Menu program Sar of programing ask Kirchhoffs laws Node analysis

More information

( ) 2. Review Exercise 2. cos θ 2 3 = = 2 tan. cos. 2 x = = x a. Since π π, = 2. sin = = 2+ = = cotx. 2 sin θ 2+

( ) 2. Review Exercise 2. cos θ 2 3 = = 2 tan. cos. 2 x = = x a. Since π π, = 2. sin = = 2+ = = cotx. 2 sin θ 2+ Review Eercise sin 5 cos sin an cos 5 5 an 5 9 co 0 a sinθ 6 + 4 6 + sin θ 4 6+ + 6 + 4 cos θ sin θ + 4 4 sin θ + an θ cos θ ( ) + + + + Since π π, < θ < anθ should be negaive. anθ ( + ) Pearson Educaion

More information

Problem Set #1. i z. the complex propagation constant. For the characteristic impedance:

Problem Set #1. i z. the complex propagation constant. For the characteristic impedance: Problem Se # Problem : a) Using phasor noaion, calculae he volage and curren waves on a ransmission line by solving he wave equaion Assume ha R, L,, G are all non-zero and independen of frequency From

More information

5.2. The Natural Logarithm. Solution

5.2. The Natural Logarithm. Solution 5.2 The Naural Logarihm The number e is an irraional number, similar in naure o π. Is non-erminaing, non-repeaing value is e 2.718 281 828 59. Like π, e also occurs frequenly in naural phenomena. In fac,

More information

Selective peracetic acid determination in the presence of hydrogen peroxide using the molecular absorption properties of catalase

Selective peracetic acid determination in the presence of hydrogen peroxide using the molecular absorption properties of catalase Analyical and Bioanalyical Chemisry Elecronic Supplemenary Maerial Selecive peraceic acid deerminaion in he presence of hydrogen peroxide using he molecular absorpion properies of caalase Javier Galbán,

More information

(π 3)k. f(t) = 1 π 3 sin(t)

(π 3)k. f(t) = 1 π 3 sin(t) Mah 6 Fall 6 Dr. Lil Yen Tes Show all our work Name: Score: /6 No Calculaor permied in his par. Read he quesions carefull. Show all our work and clearl indicae our final answer. Use proper noaion. Problem

More information

CHAPTER 53 METHODS OF DIFFERENTIATION

CHAPTER 53 METHODS OF DIFFERENTIATION CHAPTER 5 METHODS OF DIFFERENTIATION EXERCISE 5 Page 67. Differeniae wih respec o : (a 5 5 (b.4.5 (c 5 4 (a If 5 5 hen (5 4 ( 5 8.4.5 (b If.4.5 hen (.4.5 (.5 (c If hen. Differeniae wih respec o : (a 4

More information

2 int T. is the Fourier transform of f(t) which is the inverse Fourier transform of f. i t e

2 int T. is the Fourier transform of f(t) which is the inverse Fourier transform of f. i t e PHYS67 Class 3 ourier Transforms In he limi T, he ourier series becomes an inegral ( nt f in T ce f n f f e d, has been replaced by ) where i f e d is he ourier ransform of f() which is he inverse ourier

More information

21.9 Magnetic Materials

21.9 Magnetic Materials 21.9 Magneic Maerials The inrinsic spin and rbial min f elecrns gives rise he magneic prperies f maerials è elecrn spin and rbis ac as iny curren lps. In ferrmagneic maerials grups f 10 16-10 19 neighbring

More information

Let ( α, β be the eigenvector associated with the eigenvalue λ i

Let ( α, β be the eigenvector associated with the eigenvalue λ i ENGI 940 4.05 - Sabiliy Analysis (Linear) Page 4.5 Le ( α, be he eigenvecor associaed wih he eigenvalue λ i of he coefficien i i) marix A Le c, c be arbirary consans. a b c d Case of real, disinc, negaive

More information

LECTURE 17. Reminder Magnetic Flux

LECTURE 17. Reminder Magnetic Flux LECTURE 17 Motional EMF Eddy Currents Self Inductance Reminder Magnetic Flux Faraday s Law ε = dφ B Flux through one loop Φ B = BAcosθ da Flux through N loops Φ B = NBAcosθ 1 Reminder How to Change Magnetic

More information

a. Show that these lines intersect by finding the point of intersection. b. Find an equation for the plane containing these lines.

a. Show that these lines intersect by finding the point of intersection. b. Find an equation for the plane containing these lines. Mah A Final Eam Problems for onsideraion. Show all work for credi. Be sure o show wha you know. Given poins A(,,, B(,,, (,, 4 and (,,, find he volume of he parallelepiped wih adjacen edges AB, A, and A.

More information

Today in Physics 218: radiation reaction

Today in Physics 218: radiation reaction Today in Physics 18: radiaion reacion Radiaion reacion The Abraham-Lorenz formula; radiaion reacion force The pah of he elecron in oday s firs example (radial decay grealy exaggeraed) 6 March 004 Physics

More information

Solutions of Sample Problems for Third In-Class Exam Math 246, Spring 2011, Professor David Levermore

Solutions of Sample Problems for Third In-Class Exam Math 246, Spring 2011, Professor David Levermore Soluions of Sample Problems for Third In-Class Exam Mah 6, Spring, Professor David Levermore Compue he Laplace ransform of f e from is definiion Soluion The definiion of he Laplace ransform gives L[f]s

More information

( ) ( ) if t = t. It must satisfy the identity. So, bulkiness of the unit impulse (hyper)function is equal to 1. The defining characteristic is

( ) ( ) if t = t. It must satisfy the identity. So, bulkiness of the unit impulse (hyper)function is equal to 1. The defining characteristic is UNIT IMPULSE RESPONSE, UNIT STEP RESPONSE, STABILITY. Uni impulse funcion (Dirac dela funcion, dela funcion) rigorously defined is no sricly a funcion, bu disribuion (or measure), precise reamen requires

More information

R.#W.#Erickson# Department#of#Electrical,#Computer,#and#Energy#Engineering# University#of#Colorado,#Boulder#

R.#W.#Erickson# Department#of#Electrical,#Computer,#and#Energy#Engineering# University#of#Colorado,#Boulder# .#W.#Erickson# Deparmen#of#Elecrical,#Compuer,#and#Energy#Engineering# Universiy#of#Colorado,#Boulder# Chaper 2 Principles of Seady-Sae Converer Analysis 2.1. Inroducion 2.2. Inducor vol-second balance,

More information

MATH 122B AND 125 FINAL EXAM REVIEW PACKET ANSWERS (Fall 2016) t f () t 1/2 3/4 5/4 7/4 2

MATH 122B AND 125 FINAL EXAM REVIEW PACKET ANSWERS (Fall 2016) t f () t 1/2 3/4 5/4 7/4 2 MATH B AND FINAL EXAM REVIEW PACKET ANSWERS (Fall 6).....6.8 f () / / / 7/ f( + h) f(). lim h h The slope of f a = f (6) The average rae of change of f from = o = dy = 8. a) f ( a) b) f ( a) + f( a). a)

More information

Math 2214 Solution Test 1B Fall 2017

Math 2214 Solution Test 1B Fall 2017 Mah 14 Soluion Tes 1B Fall 017 Problem 1: A ank has a capaci for 500 gallons and conains 0 gallons of waer wih lbs of sal iniiall. A soluion conaining of 8 lbsgal of sal is pumped ino he ank a 10 galsmin.

More information

Introduction to AC Power, RMS RMS. ECE 2210 AC Power p1. Use RMS in power calculations. AC Power P =? DC Power P =. V I = R =. I 2 R. V p.

Introduction to AC Power, RMS RMS. ECE 2210 AC Power p1. Use RMS in power calculations. AC Power P =? DC Power P =. V I = R =. I 2 R. V p. ECE MS I DC Power P I = Inroducion o AC Power, MS I AC Power P =? A Solp //9, // // correced p4 '4 v( ) = p cos( ω ) v( ) p( ) Couldn' we define an "effecive" volage ha would allow us o use he same relaionships

More information

EE650R: Reliability Physics of Nanoelectronic Devices Lecture 9:

EE650R: Reliability Physics of Nanoelectronic Devices Lecture 9: EE65R: Reliabiliy Physics of anoelecronic Devices Lecure 9: Feaures of Time-Dependen BTI Degradaion Dae: Sep. 9, 6 Classnoe Lufe Siddique Review Animesh Daa 9. Background/Review: BTI is observed when he

More information

BEng (Hons) Telecommunications. Examinations for / Semester 2

BEng (Hons) Telecommunications. Examinations for / Semester 2 BEng (Hons) Telecommunicaions Cohor: BTEL/14/FT Examinaions for 2015-2016 / Semeser 2 MODULE: ELECTROMAGNETIC THEORY MODULE CODE: ASE2103 Duraion: 2 ½ Hours Insrucions o Candidaes: 1. Answer ALL 4 (FOUR)

More information

Physics Notes for Class 12 chapter 6 ELECTROMAGNETIC I NDUCTION

Physics Notes for Class 12 chapter 6 ELECTROMAGNETIC I NDUCTION 1 P a g e Physics Notes for Class 12 chapter 6 ELECTROMAGNETIC I NDUCTION Whenever the magnetic flux linked with an electric circuit changes, an emf is induced in the circuit. This phenomenon is called

More information

ME 391 Mechanical Engineering Analysis

ME 391 Mechanical Engineering Analysis Fall 04 ME 39 Mechanical Engineering Analsis Eam # Soluions Direcions: Open noes (including course web posings). No books, compuers, or phones. An calculaor is fair game. Problem Deermine he posiion of

More information

Review of EM and Introduction to FDTD

Review of EM and Introduction to FDTD 1/13/016 5303 lecromagneic Analsis Using Finie Difference Time Domain Lecure #4 Review of M and Inroducion o FDTD Lecure 4These noes ma conain coprighed maerial obained under fair use rules. Disribuion

More information

QUANTUM MANIPULATIONS OF TRAPPED ELECTRONS ON LIQUID HELIUM

QUANTUM MANIPULATIONS OF TRAPPED ELECTRONS ON LIQUID HELIUM QUANTUM MANIPULATIONS OF TRAPPED ELECTRONS ON LIQUID HELIUM L. F. Wei Quanum Opoelecronics Laboraory QOL, Sowhwes Jiaoong Universiy, Chengdu, China & Sae Key of Opoelecric Maerials and echnolies, Sun Ya-sen

More information

Figure 1: Alternator front view.

Figure 1: Alternator front view. Robson 1 Hand Turned Electric Generator Ethan Robson & Professor Leon Cole Abstract The purpose of this project was to design and build a hand turned alternator to demonstrate electromagnetic induction

More information

Module 2 F c i k c s la l w a s o s f dif di fusi s o i n

Module 2 F c i k c s la l w a s o s f dif di fusi s o i n Module Fick s laws of diffusion Fick s laws of diffusion and hin film soluion Adolf Fick (1855) proposed: d J α d d d J (mole/m s) flu (m /s) diffusion coefficien and (mole/m 3 ) concenraion of ions, aoms

More information

Numerical Dispersion

Numerical Dispersion eview of Linear Numerical Sabiliy Numerical Dispersion n he previous lecure, we considered he linear numerical sabiliy of boh advecion and diffusion erms when approimaed wih several spaial and emporal

More information

Electrical and current self-induction

Electrical and current self-induction Elecrical and curren self-inducion F. F. Mende hp://fmnauka.narod.ru/works.hml mende_fedor@mail.ru Absrac The aricle considers he self-inducance of reacive elemens. Elecrical self-inducion To he laws of

More information

( ) = 0.43 kj = 430 J. Solutions 9 1. Solutions to Miscellaneous Exercise 9 1. Let W = work done then 0.

( ) = 0.43 kj = 430 J. Solutions 9 1. Solutions to Miscellaneous Exercise 9 1. Let W = work done then 0. Soluions 9 Soluions o Miscellaneous Exercise 9. Le W work done hen.9 W PdV Using Simpson's rule (9.) we have. W { 96 + [ 58 + 6 + 77 + 5 ] + [ + 99 + 6 ]+ }. kj. Using Simpson's rule (9.) again: W.5.6

More information

2. The following diagram shows a circular loop of wire in a uniform magnetic field that points out of the page.

2. The following diagram shows a circular loop of wire in a uniform magnetic field that points out of the page. 1. Two elecromagneic waves ravel hrough emp space. Wave A as a wavelengh of 700 nm (red ligh), while Wave B has a wavelengh of 400 nm (blue ligh). Which saemen is rue? A) Wave A ravels faser because i

More information

4.6 One Dimensional Kinematics and Integration

4.6 One Dimensional Kinematics and Integration 4.6 One Dimensional Kinemaics and Inegraion When he acceleraion a( of an objec is a non-consan funcion of ime, we would like o deermine he ime dependence of he posiion funcion x( and he x -componen of

More information

(1) (2) Differentiation of (1) and then substitution of (3) leads to. Therefore, we will simply consider the second-order linear system given by (4)

(1) (2) Differentiation of (1) and then substitution of (3) leads to. Therefore, we will simply consider the second-order linear system given by (4) Phase Plane Analysis of Linear Sysems Adaped from Applied Nonlinear Conrol by Sloine and Li The general form of a linear second-order sysem is a c b d From and b bc d a Differeniaion of and hen subsiuion

More information

Suggested Problem Solutions Associated with Homework #5

Suggested Problem Solutions Associated with Homework #5 Suggesed Problem Soluions Associaed wih Homework #5 431 (a) 8 Si has proons and neurons (b) 85 3 Rb has 3 proons and 48 neurons (c) 5 Tl 81 has 81 proons and neurons 43 IDENTIFY and SET UP: The ex calculaes

More information

CHAPTER 2 Signals And Spectra

CHAPTER 2 Signals And Spectra CHAPER Signals And Specra Properies of Signals and Noise In communicaion sysems he received waveform is usually caegorized ino he desired par conaining he informaion, and he undesired par. he desired par

More information

Math 2214 Solution Test 1A Spring 2016

Math 2214 Solution Test 1A Spring 2016 Mah 14 Soluion Tes 1A Spring 016 sec Problem 1: Wha is he larges -inerval for which ( 4) = has a guaraneed + unique soluion for iniial value (-1) = 3 according o he Exisence Uniqueness Theorem? Soluion

More information