Scattering matrix of the interface
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1 Scattering matrix of the interface Let us consider a generalied version of the roblem: when waves are incident on the interface from both media scattering: 0 E A ex j B ex j y 0, 0, 1, 1, 0 E C ex j D ex j y D ex j 1, 0, B ex j0, Aex j C ex j 1, 1, 0, Scattering from layered media 3
2 Scattering matrix of the interface Matching the solutions results in the scattering matrix of the interface: matrix relating the amlitudes of the reflected waves to those of the incident waves at the interface B T A C T D S 0 D ex j 1, 0, B ex j0, Aex j C ex j 1, 1, 0, 0 0 T 1 T 1 1 1, 1, 0, Scattering from layered media 4
3 Scattering matrix of the interface For the TM case: 0 H Aex j B ex j y 1, 1,,, 0 H C ex j D ex j y B TM T TM A C TTM TM D T TM TM TM 1 S TM TM 0 0, B ex j0, Aex j T TM 1 TM 1 TM D ex j 1, C ex j 0 1, 1, 1 0, 0 1, 1, 0, 0 0 Scattering from layered media 5
4 Scattering matrix of the interface If the interface is not located at = 0, but at = 0 we can still use the same result, but should use the correct amlitudes at the interface ex j0, 0 B T ex j0, 0 A ex j C T ex j D 1, 0 1, 0 0 D ex j 1, 0, B ex j0, Aex j C ex j 1, 1, 0, 0 0 Scattering from layered media 6
5 Scattering by a dielectric slab Let us go one ste further and consider the scattering by a dielectric slab of finite thicness We again distinguish the and TM cases The tangential wave vector is again the same in all layers Solution can be obtained by matching the fields at the two interface lanes, 0 1, 0 0, 0 i i i t i d r Scattering from layered media 7
6 Scattering by a dielectric slab Solution for the electric field inside each layer for reduced fields, 0 1, 0 0, 0 D ex j 1, 0, B ex j0, Aex j E ex j, C ex j 1, d 0 Scattering from layered media 8
7 Scattering by a dielectric slab Instead of matching fields use the interface scattering matrices B 1 A C 1 D ex j 1 1 1, d D 1 ex j 1, d C d 1 1 ex j 1, d E , 1, 0, 1, 1 1,, 1,, Scattering from layered media 9
8 Scattering by a dielectric slab esulting overall reflection and transmission coefficients 10 1 B ex j1, d A j d ex 1, T ex j1, d ex 1, E A j d Similar results for TM scattering, just relace TM 1 0, 0 1, 1 0, 0 1, 1 1 TM 1, 1, 1, 1, Scattering from layered media 30
9 Scattering by a dielectric slab in vacuum A more ractical case: a dielectric slab in vacuum 10 cos sin cos sin 0, 1, i d i 0, 1, i d i i 1 1, 0, 10 1, 0, 10 TM cos sin d i d i cos sin d i d i 0 1 d0 d 0 i i 1 10 TM TM i r Scattering from layered media 31
10 Scattering by a dielectric slab in vacuum Overall reflection coefficient for scattering: 10 1 ex 1, 10 j1, d j d 1 ex 0, 1, 0, 1, j0, 1, cot 1, d cos, sin, ( ) sin 0, 0 i 1, 0 d i i d i 1 d j d cos ( ) cos cot ( ) d i i i i 0 Scattering from layered media 3
11 Scattering by a dielectric slab in vacuum Overall reflection coefficient for TM scattering: TM 1 ex 1, 10 TM j1, d j d 10 TM 1 ex 1 0, 0 1, 1 0, 0 1, 0 1 0, 1, cot 1, j d cos, sin, ( ) sin 0, 0 i 1, 0 d i i d i TM cos sin d i i d d i d i j d i i i cos sin ( ) cos cot ( ) d 0 Scattering from layered media 33
12 Scattering by a dielectric slab in vacuum eflection coefficient of the and TM mode becomes ero if 1 ex j d =0 1, n 1, d n, n 1,, sin i d 0d Phenomenon caused by (almost) standing waves in slab due to multile reflections, similar to Fabry-Perrot, resonant tunneling Can occur when the slab is thicer than half roagation wave length inside the slab d d d 0 d Scattering from layered media 34
13 Scattering by a dielectric slab in vacuum In addition, we have the usual Brewster angle for TM scattering where reflection becomes ero d cos sin 0 sin 1 d i i d i Normal incidence 0 same and TM values aart from a minus sign (why?) i 1 d 0d TM 1 j cot d d d d Almost horiontal incidence / 1 1 Scattering from layered media 35 i TM
14 eflection from a dielectric slab in vacuum Plots for a slab with a relative dielectric constant of 4 dd dd 6.5 TM TM i (deg) i (deg) Scattering from layered media 36
15 eflection from a dielectric slab in vacuum Note also that if we ee the angle constant and change the frequency then an oscillatory behavior is observed due to the standing wave henomenon i 0 i 45 deg TM 0d 0d Scattering from layered media 37
16 Scattering from a general layered medium So far we considered a number of secific cases, now we turn to the general case, N 1 0 N, 0 N, BN ex jn, A ex j N A ex j N 1 N 1, 1, 0 0, 0 B1 ex j1, A ex j 1 1, B0 ex j0, A ex j 0 0, x Scattering from layered media 38
17 Scattering from a general layered medium Our aim is to find the overall reflection and, erhas, transmission coefficients B A 0 0 T A N 1 A 0 Lie for a single slab, we would lie to use the exressions for interface scattering But, the scattering matrix is not the right quantity for analying a stac of multile layers Combining scattering matrices of different layers is not easy Scattering from layered media 39
18 Scattering from a general layered medium Let us again return to a single interface between media B ex j, T A ex j, C ex j T D ex j 1, 1, Instead of relating amlitudes of scattered waves to those of incident waves, we relate waves in layer i+1 to those in layer i S D j ex 1,, B ex j, Aex j C j ex 1, 1, 0, 0 Scattering from layered media 40
19 Scattering from a general layered medium Let us again return to a single interface between media C ex j 1, 1 S ex 1S1 S A j 11S S, D ex j S S 1 B ex j 1, 1 11, In terms of the reflection coefficient M M D j ex 1, Transfer matrix, B ex j, Aex j C j ex 1, 1, 0, 0 Scattering from layered media 41
20 Scattering from a general layered medium Note again, that the matrix relates the wave amlitudes Now consider the full roblem N N N 1 N 1 0 B1 ex j1, A ex j 1 1, B0 ex j0, A ex j 0 0, N, BN ex jn, A ex j N BN 1 ex jn 1, A ex j N 1 N 1, Scattering from layered media 4
21 Scattering from a general layered medium We have ex j 1, A 1 ex j 1,, A M ex j B ex j B 1, 1, A A 1 1, 1,, B Q M Q 1 B Q ex j 0 0 ex j M 1, 1, 1 1 1, 1, 1 1 Scattering from layered media 43
22 Scattering from a general layered medium ex j A 1, 1 ex N N N j A 0, 0 0 M ex j B ex j B N 1, N N 1 0, 0 0 M M Q M Q M Q M N 1, N 3,,1 1,0 N 1 Q e j, 0 d d 1 e j 0, d N N 1 1 N 1 N 1 N, BN ex j N, A ex j N BN 1 ex j N 1, A ex j N 1 N 1, B1 ex j1, A ex j 1 1, 0 0 B0 ex j0, A ex j 0 0, Scattering from layered media 44
23 Scattering from a general layered medium We have found the overall transfer matrix of the structure The overall reflection and transmission coefficient: ex j A 1, 1 ex N N N j A M 11 M 1 0, 0 0 ex j B M M ex j B N 1, N N 1 1 0, 0 0 B N 1 ex 0, T ex ex j j j 0, 0 B A 0 M M N 1, N N M 11 ex j A 0, 0 0 M A M M Scattering from layered media 45
24 Scattering from a general layered medium Examle: single dielectric slab in vacuum M M Q M M M 1,0,1,1 1, d 0 d 0 ex( j d) , 1 ex j 1, d Q1 0 ex( j1, d) 10 1 ex 1, j d Scattering from layered media 46
25 Scattering from a general layered medium This method involves the multilication of a lot of matrices if there are many layers There exist another technique which yields a simler, recurrent equation for the reflection coefficient Consider two adjacent layers, and B 1 ex j 1, A ex j 1 1, A ex j, B ex j, Scattering from layered media 47
26 Scattering from a general layered medium Imagine that somehow we now the ratio of the forward and bacward moving waves in the (+1)-th layer at r 1 B ex j 1 1, 1 A ex j 1 1, 1 1 eflection coefficient at 1 What can be said of this ratio in the -th at? 1 1 B 1 ex j 1, A ex j 1 1, A ex j, B ex j, Scattering from layered media 48
27 Scattering from a general layered medium Use the transfer matrix (or scattering matrix) ex j A 1, 1, 1, 1 ex j A M 11 M 1, 1, 1, ex j B M 1, 1 1 M ex j B, r B ex j, A ex j, One finds the recurrent relationshi r M r M ex j d 1, 1, , 1 1, 1, M ex j 1, d 1 M1 r 1 Scattering from layered media 49
28 Scattering from a general layered medium In terms of interface reflection arameters: r r ex j d 1, 1 1, 1 1, ex j 1, d 1 r 1 emember that for and TM scattering: 1,, 1,, 1, 1, TM 1, 1, 1, 1, But, what about the initial condition of this recurrent relation? Scattering from layered media 50
29 Scattering from a general layered medium There is no reflection in the tomost layer! Our initial condition is rn 1 0 The recurrent relation can then N 1 N r N be calculated all the way down to the overall reflection coefficient 1 r 1 r 0 0 r 0 Scattering from layered media 51
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