Center of Mass and Linear

Size: px
Start display at page:

Download "Center of Mass and Linear"

Transcription

1 PH 22-3A Fall 2009 Cente of Mass and Linea Moentu Lectue 5 Chapte 8 (Halliday/Resnick/Walke, Fundaentals of Physics 8 th edition)

2 Chapte 9 Cente of Mass and Linea Moentu In this chapte we will intoduce the following new concepts: -Cente of ass (co) fo a syste of paticles -The velocity and acceleation of the cente of ass -Linea oentu fo a single paticle and a syste of paticles We will deive the equation of otion fo the cente of ass, and discuss the pinciple of consevation of linea oentu Finally we will use the consevation of linea oentu to study collisions in one and two diensions and deive the equation of otion fo ockets 2

3 The Cente of Mass: Conside a syste of two paticles of asses and 2 2 at positions x and x, espectively. We define the position of the cente of ass (co) as follows: x co = x + x We can genealize the above definition i i fo a syste of n paticles as follows: x x+ x + x x x+ x + x x n n n n n co = = = x i i n M M i = Hee M is the total ass of all the paticles M = n We can futhe genealize the definition fo the cente of ass of a syste of paticles in thee diensional space. We assue that the the i-th paticle ( ass i ) has position vecto i n co = i i M i = 3

4 The position vecto fo the cente of ass is given by the equation: The position vecto can be witten as: ˆ ˆ ˆ co = xcoi + yco j+ zcok The coponents of co ae given by the equations: n n n xco = x i i yco = i yi zco = z i i M M M i= i= i= co = M n i= i i The cente of ass has been defined using the equations given above so that t it has the following popety: The cente of ass of a syste of paticles oves as though all the syste's ass wee concetated thee, and that the vecto su of all the extenal foces wee applied thee The above stateent will be poved late. An exaple is given in the figue. A baseball bllbat is flipped dinto the ai and oves unde the influence of the gavitation foce. The cente of ass is indicated by the black dot. It follows ows a paabolic path as discussed in Chapte 4 (pojectile otion) All the othe points of the bat follow oe coplicated paths 4

5 The Cente of Mass fo Solid Bodies Solid bodies can be consideed as systes with continuous distibution of atte The sus that ae used fo the calculation of the cente of ass of systes with discete distibution of ass becoe integals: xco = xd yco yd zco zd M = M = M The integals above ae athe coplicated. A siple special case is that of d M unifo objects in which the ass density ρ = is constant and equal to dv V xco = xdv yco ydv zco zdv V = V = V In objects with syety eleents (syety point, syety line, syety plane) it is not necessay to eveluate the integals. Thecenteofassliesonthesyety on the syety eleent. Fo exaple the co of a unifo sphee coincides with the sphee cente In a unifo ectanglula object the co lies at the intesection of the diagonals C. C 5

6 6

7 F F 2 2 F 2 O x z 3 y Newton's Second Law fo a Syste of Paticles Conside a syste of paticles of asses,,..., and position vectos, 2, 3,..., n, espectively. The position vecto of the cente of ass is given by: n 2 3, n Mco = n n We take the tie deivative of both sides d d d d d M co = n n dt dt dt dt dt Mvco = v + 2v2 + 3v nvn Hee vco is the velocity of the co and v is the velocity of the i-th paticle. We take the tie deivative once oe i d d d d d M vco = v+ 2 v2 + 3 v n vn dt dt dt dt dt Maco = a + 2a2 + 3a nan Hee aco is the acceleation of the co and a is the acceleation of the i-th paticle i 7

8 F F 2 2 F 2 O x z Ma a a a a co = n n We apply Newton's second law fo the i-th paticle: 3 a i i = Fi Hee Fi is the net foce on the i-th paticle y Maco = F+ F2 + F Fn The foce Fi can be decoposed into two coponents: applied and intenal app int Fi = Fi + Fi The above equation takes the fo: app int app int app int app int Maco = ( F + F ) + ( F2 + F2 ) + ( F3 + F3 ) ( Fn + Fn ) Ma = F app + F app + F app F app + F int + F int + F int F int ( 2 3 ) ( 2 3 ) co n n The su in the fist paenthesis on the RHS of the equation above is just F net The su in the second paethesis on the RHS vanishes by vitue of Newton's thid law. The equation of otion fo the cente of ass becoes: In tes of coponents we have: Fnet, x = Maco, x Fnet, y = Maco, y Fnet, z = Ma co, z Ma co = F net 8

9 Ma co = F net F F F = Ma net, x co, x = Ma net, y co, y = Ma net, z co, z The equations above show that the cente of ass of a syste of paticles oves as though all the syste's ass wee concetated thee, and that the vecto su of all the extenal foces wee applied thee. A daatic exaple is given in the figue. In a fiewoks display a ocket is launched and oves unde the influence of gavity on a paabolic path (pojectile otion). At a cetain point the ocket explodes into fagents. If the explosion had not occued, the ocket would have continued to ove on the paabolic tajectoy (dashed line). The foces of the explosion, even though lage, ae all intenal and as such cancel out. The only extenal foce is that of gavity and this eains the sae befoe and afte the explosion. This eans that the cente of ass of the fagents folows the sae paabolic tajectoy that the ocket would have followed had it not exploded 9

10 p v = v Linea Moentu p Linea oentu p of a paticle of ass and velocity v is defined as: p= v The SI unit fo lineal oentu is the kg./s Below we will pove the following stateent: The tie ate of change of the linea oentu of a paticle is equal to the agnitude of net foce acting on the paticle and has the diection of the foce dp In equation fo: Fnet = We will pove this equation using dt Newton's second law dp d dv p = v = ( v) = = a = Fnet dt dt dt This equation is stating that the linea oentu of a paticle can be changed only by an extenal foce. If the net extenal foce is zeo, the linea oentu cannot change F net = dp dt 0

11 z p p 3 2 p 2 x O 3 y The Linea Moentu of a Syste of Paticles In this section we will extedend the definition of linea oentu to a syste of paticles. The i-th paticle has ass i, velocity v i, and linea oentu p i We define the linea oentu of a syste of n paticles as follows: P = p + p2 + p pn = v + 2v2 + 3v nvn = Mv co The linea oentu of a syste of paticles is equal to the poduct of the total ass M of the syste and the velocity v co of the cente of ass dp d The tie ate of change of P is: = ( Mvco ) = Maco = Fnet dt dt The linea oentu P of a syste of paticles il can be changed only by a net extenal foce F. If the net extenal foce F is zeo P cannot change net P = p + p + p + + p = Mv n co net dp Fnet dt =

12 Exaple. Motion of the Cente of Mass 2

13 3

14 Collision and Ipulse We have seen in the pevious discussion that the oentu of an object can change if thee is a non-zeo extenal lfoce acting on the object. Such foces exist duing the collision of two objects. These foces act fo a bief tie inteval, they ae lage, and they ae esponsible fo the changes in the linea oentu of the colliding objects. Conside the collision of a baseball with a baseball bat The collision stats at tie ti when the ball touches the bat and ends at t f when the two objects sepaate The ball is acted upon by a foce F ( t) duing the collision The agnitude Ft ( ) of the foce is plotted vesus tin fig.a The foce is non-zeo only fo the tie inteval t i < t < t f dp Ft ( ) = Hee pis the linea oentu of the ball dt d tf tf p= Ftdt () dp= Ftdt () t i t i 4

15 dp = F () tdt dp = p p =Δ p = change in oentu t t t f f f t t t i i i t f F () tdt is known as the ipulse J of the collision t i t f J = F( t) dt The agnitude of J is equal to the aea t i unde the F vesus t plot of fig.a Δ p= J f In any situations we do not know how the foce changes with tie but we know the aveage agnitude F ave of the collision foce. The agnitude of the ipulse is given by: J = F Δt whee Δ t = t t ave f i Geoetically this eans that the the aea unde the F t l t (fi ) i l t th d th F vesus ave t plot (fig.b) Δ p = J vesus plot (fig.a) is equal to the aea unde the J = FaveΔt 5 i

16 Collisions. Ipulse and Moentu 6

17 The Ipulse-Moentu Theoe 7

18 F ave Seies of Collisions Conside a taget which collides with a steady stea of identical paticles of ass and velocity v along the x-axis A nube n of the paticles collides with the taget duing a tie inteval Δ t. Each paticle undegoes a change Δp in oentu due to the collision with the taget. Duing each collision a oentu change Δp is ipated on the taget. The Ipulse on the taget duing the tie inteval Δt is: J = nδp The aveage foce on the taget is: J n Δ p n Fave = = = Δv Hee Δv is the change in the velocity Δt Δt Δt of each paticle along the x-axis due to the collision with the taget Δ Δ Fave = Δv Hee is the ate at which ass collides with the taget Δt Δt If the paticles stop afte the collision then Δ v = 0 v = v If the paticles bounce backwads then Δ v = v v = 2v 8

19 z p p 3 2 p 2 x O 3 y Consevation of Linea Moentu Conside a syste of paticles fo which F net = 0 dp F net 0 P Constant dt = = = If no net extenal foce acts on a syste of paticles the total llinea oentu P cannot change total linea oentu total linea oentu at soe initial tie t = i at soe late tie t f The consevation of linea oentu is an ipotan pinciple in physics. It also povides a poweful ule we can use to solve pobles in echanics such as collisions. Nt Note : In systes in which h F net = 0 we can always apply consevation of linea oentu even when the intenal foces ae vey lage as in the case of colliding objects Note 2: We will encounte pobles (e.g. inelastic collisions) in which the enegy is not conseved but the linea oentu is 9

20 The Pinciple of Consevation of Linea Moentu 20

21 2

22 Moentu and Kinetic Enegy in Collisions Conside two colliding objects with asses and 2, initial velocities v and v and final velocities v and v, i 2i f 2 f espectively If the syste is isolated i.e. the net foce F net = 0 linea oentu is conseved The conevation of linea oentu is tue egadless of the the collision type This is a poweful ule that allows us to deteine the esults of a collision without knowing the details. Collisions ae divided into two boad classes: elastic and inelastic. A collision is elastic if thee is no loss of kinetic enegy i.e. K = K A collision is inelastic if kinetic enegy is lost duing the collision due to convesion it into othe fos of enegy. In this case we have: K < K A special case of inelastic collisions ae known as copletely inlelastic. In these collisions the two colliding objects stick togethe and they ove as a single body. In these collisions the loss of kinetic enegy 22 is axiu f i i f

23 One Diensional Inelastic Collisions In these collisions the linea oentiu of the colliding objects is conseved p i + p2i = pf + p2 f v + v = v + v i 2i f 2 f One Diensional Copletely Inelastic Collisions In these collisions the two colliding objects stick togethe and ove as a single body. In the figue to the leftwe show a special case in which v 2i = 0. v i = V + V 2 V = v i + 2 The velocity of the cente of ass in this collision P p i + p2i v i is vco = = = In the pictue to the left we show soe feeze-faesfaes of a totally inelastic collition 23

24 One-Diensional Elastic Collisons Conside two colliding objects with asses and 2, initial velocities v and v and final velocities v and v, espectively i 2i f 2 f Both linea oentu and kinetic enegy ae conseved. Linea oentu consevation: v + v = v + v (eqs.) i 2i f 2 f v i v v 2 f v i 2 2 f Kinetic enegy consevation: + = + (eqs.2) We have tw o equations and two unknowns, v and v 2 2 f i 2i f f f f If we solve equations and 2 fo v and v we get the following solutions: 2 v = v + v 2 v = v + v 2 2 f 2 + i i

25 The substitute v = 0inthe two solutions fo v and v ( v = ) Special Case of elastic Collisions-Stationay Taget 0 2i f f 2i 2 v = v + v v = f i 2i f i v = v + v v = 2 2 f i 2i 2 f i Below we exaine seveal special cases fo which we know the outcoe of the collision fo expeience. Equal asses = = 2 v = v = v = 2 f i i v = v = v = v 2 f i i i The two colliding objects have exchanged velocities 0 v v v i v 2i = 0 v f = 0 v 2f x x 25

26 v i 2 v 2i = 0 x v f 2 v 2f 2. A assive taget 2 v = v = v v f i i i x v2 f = v i = v i 2 v i Body (sall ass) bounces back along the incoing path with its speed pactically unchanged. Body 2 (lage ass) oves fowad with a vey sall speed because

27 v 2 i 2. A assive pojectil e 2 v 2i = 0 x v f v 2 2f v = v = v v x 2 2 f i i i v = v = v 2v f i i i Body (lage ass) keeps on going scacely slowed by the collision. Body 2 (sall ass) chages ahead at twice the speed of body 27

28 Elastic Collision 28

29 Inelastic Collision 29

30 Collisions in Two Diensions In this section we will eove the estiction that the colliding objects ove along one axis. Instead we assue that the two bodies that paticipate in the collision ove in the xy -plane. Thei asses ae and 2 The linea oentu of the syte is conseved: p + p = p + p i 2i f 2 f If the syste is elastic the kinetic enegy is also conseved: K + K = K + K 2 i 2 i f 2 f We assue that is stationay and that afte the collision paticle and paticle 2 ove at angles θ and θ with the initial diection of otion of axis: i = f θ+ v 2 2 f θ2 2 In this case the consevation of oentu and kinetic enegy take the fo: x v v cos cos (eqs.) y axis: 0= v sin θ + v sin θ (eqs.2) f 2 2 f v i = v 2 f + v 2 2 f (eqs.3) We have thee equations and seven vaiables: Two asses:, 2 thee speeds: v i, vf, v2 f and two angles: θ, θ2. If we know the values of fou of these paaetes we can calculate the eaining thee 30

31 Poble 72. Two 2.0 kg bodies, A and B collide. The velocities befoe the collision ae ˆ ˆ v (5 30 ) /s and ( 0 ˆ 5.0 ˆ A = i + j vb = i + j) /s. Afte the collision, v = ( 5.0iˆ + 20 ˆj) /s. What ae (a) the final velocity of B and (b) the change ' A in the total kinetic enegy (including sign)? (a) Consevation of linea oentu iplies v + v = v' + v'. A A B B A A B B Since A = B = = 2.0 kg, the asses divide out and we obtain v (5i ˆ 30ˆj)/s ( 0ˆi 5j)/s ˆ ( 5ˆi 20ˆ B = va + vb v A = j)/s = (0 ˆi + 5 ˆj) /s. (b) The final and initial kinetic enegies ae c h J K v 2 v f = ' A+ ' B = ( 2. 0) ( 5) = Ki = va + vb = ( 2. 0) c ( 0) + 5 h = 3. 0 J The change kinetic enegy is then ΔK = J (that is, 500 J of the initial kinetic enegy is lost). 3

32 Systes with Vaying Mass: The Rocket A ocket of ass M and speed v ejects ass backwads dm at a constant ate. The ejected ateial is expelled at a dt constant speed vel elative to the ocket. T hus the ocket loses ass and acceleates fowad. We will use the consevation of linea oentu to deteine the speed v of the ocket In figues (a) and (b) we show the ocket at ties t and t+ dt. If we assue that thee ae no extenal foces acting on the ocket, linea oentu is conseved ( ) ( )( ) p( t) = p t + dt Mv = UdM + M + dm v + dv (eqs.) Hee dm is a negative nube because the ocket's ass deceases with tie t U is the velocity of fthe ejected gases with espect to the inetial efeence fae in which we easue the ocket's speed v. We use the tansfoation equation fo velocities (Chapte 4) to expess U in tes of v el which is easued with epsect to the ocket. U = v+ dv vel We substitute U in equation and we get: 32 Mdv = dmvel

33 Using the consevation of linea oentu we deived the equation of otion fo the ocket Mdv = dmv el (eqs.2) We assue that ateial is ejected fo the ocet's nozzle at a constant ate dm = R (eqs.3) Hee R is a constant positive nube dt dv dm We devide both sides of eqs.(2) by dt M = vel = Rvel dt dt Ma = Rvel (Fist ocket equation) Hee a is the ocket's acceleation We use equation 2todeteinetheocket's the ocket speedasfunction of tie t f f dm dm dv = vel We integate both sides dv vel M = M f [ ] [ ] M M i f i el M el el i M f M f i v v = v ln M = v ln M =v ln M i vf vi = vel ln (Second ocket equation) v i M i /M f M 33 f v v i M M M i O v f

34 Poble 78. A 6090 kg space pobe oving nose-fist towad Jupite at 05 /s elative to the Sun fies its ocket engine, ejecting 80.0 kg of exhaust at a speed of 253 /s elative to the space pobe. What is the final velocity of the pobe? M i 6090 kg vf = vi + vel ln = 05 /s + (253 /s) ln = 08 /s. M f 600 kg 34

Center of Mass and Linear

Center of Mass and Linear PH 221-3A Fall 2010 Center of Mass and Linear Momentum Lecture 15 Chapter 8 (Halliday/Resnick/Walker, Fundamentals of Physics 8 th edition) 1 Chapter 9 Center of Mass and Linear Momentum In this chapter

More information

LINEAR MOMENTUM Physical quantities that we have been using to characterize the motion of a particle

LINEAR MOMENTUM Physical quantities that we have been using to characterize the motion of a particle LINEAR MOMENTUM Physical quantities that we have been using to chaacteize the otion of a paticle v Mass Velocity v Kinetic enegy v F Mechanical enegy + U Linea oentu of a paticle (1) is a vecto! Siple

More information

Physics Fall Mechanics, Thermodynamics, Waves, Fluids. Lecture 18: System of Particles II. Slide 18-1

Physics Fall Mechanics, Thermodynamics, Waves, Fluids. Lecture 18: System of Particles II. Slide 18-1 Physics 1501 Fall 2008 Mechanics, Themodynamics, Waves, Fluids Lectue 18: System of Paticles II Slide 18-1 Recap: cente of mass The cente of mass of a composite object o system of paticles is the point

More information

r dt dt Momentum (specifically Linear Momentum) defined r r so r r note: momentum is a vector p x , p y = mv x = mv y , p z = mv z

r dt dt Momentum (specifically Linear Momentum) defined r r so r r note: momentum is a vector p x , p y = mv x = mv y , p z = mv z Moentu, Ipulse and Collisions Moentu eeyday connotations? physical eaning the tue easue of otion (what changes in esponse to applied foces) d d ΣF ( ) dt dt Moentu (specifically Linea Moentu) defined p

More information

1121 T Question 1

1121 T Question 1 1121 T1 2008 Question 1 ( aks) You ae cycling, on a long staight path, at a constant speed of 6.0.s 1. Anothe cyclist passes you, tavelling on the sae path in the sae diection as you, at a constant speed

More information

Momentum is conserved if no external force

Momentum is conserved if no external force Goals: Lectue 13 Chapte 9 v Employ consevation of momentum in 1 D & 2D v Examine foces ove time (aka Impulse) Chapte 10 v Undestand the elationship between motion and enegy Assignments: l HW5, due tomoow

More information

Lecture 23: Central Force Motion

Lecture 23: Central Force Motion Lectue 3: Cental Foce Motion Many of the foces we encounte in natue act between two paticles along the line connecting the Gavity, electicity, and the stong nuclea foce ae exaples These types of foces

More information

EN40: Dynamics and Vibrations. Midterm Examination Tuesday March

EN40: Dynamics and Vibrations. Midterm Examination Tuesday March EN4: Dynaics and Vibations Midte Exaination Tuesday Mach 8 16 School of Engineeing Bown Univesity NME: Geneal Instuctions No collaboation of any kind is peitted on this exaination. You ay bing double sided

More information

ATMO 551a Fall 08. Diffusion

ATMO 551a Fall 08. Diffusion Diffusion Diffusion is a net tanspot of olecules o enegy o oentu o fo a egion of highe concentation to one of lowe concentation by ando olecula) otion. We will look at diffusion in gases. Mean fee path

More information

FARADAY'S LAW. dates : No. of lectures allocated. Actual No. of lectures 3 9/5/09-14 /5/09

FARADAY'S LAW. dates : No. of lectures allocated. Actual No. of lectures 3 9/5/09-14 /5/09 FARADAY'S LAW No. of lectues allocated Actual No. of lectues dates : 3 9/5/09-14 /5/09 31.1 Faaday's Law of Induction In the pevious chapte we leaned that electic cuent poduces agnetic field. Afte this

More information

Chapter 13 Gravitation

Chapter 13 Gravitation Chapte 13 Gavitation In this chapte we will exploe the following topics: -Newton s law of gavitation, which descibes the attactive foce between two point masses and its application to extended objects

More information

Chapter 8. Linear Momentum, Impulse, and Collisions

Chapter 8. Linear Momentum, Impulse, and Collisions Chapte 8 Lnea oentu, Ipulse, and Collsons 8. Lnea oentu and Ipulse The lnea oentu p of a patcle of ass ovng wth velocty v s defned as: p " v ote that p s a vecto that ponts n the sae decton as the velocty

More information

30 The Electric Field Due to a Continuous Distribution of Charge on a Line

30 The Electric Field Due to a Continuous Distribution of Charge on a Line hapte 0 The Electic Field Due to a ontinuous Distibution of hage on a Line 0 The Electic Field Due to a ontinuous Distibution of hage on a Line Evey integal ust include a diffeential (such as d, dt, dq,

More information

Class 6 - Circular Motion and Gravitation

Class 6 - Circular Motion and Gravitation Class 6 - Cicula Motion and Gavitation pdf vesion [http://www.ic.sunysb.edu/class/phy141d/phy131pdfs/phy131class6.pdf] Fequency and peiod Fequency (evolutions pe second) [ o ] Peiod (tie fo one evolution)

More information

r ˆr F = Section 2: Newton s Law of Gravitation m 2 m 1 Consider two masses and, separated by distance Gravitational force on due to is

r ˆr F = Section 2: Newton s Law of Gravitation m 2 m 1 Consider two masses and, separated by distance Gravitational force on due to is Section : Newton s Law of Gavitation In 1686 Isaac Newton published his Univesal Law of Gavitation. This explained avity as a foce of attaction between all atte in the Univese, causin e.. apples to fall

More information

= 4 3 π( m) 3 (5480 kg m 3 ) = kg.

= 4 3 π( m) 3 (5480 kg m 3 ) = kg. CHAPTER 11 THE GRAVITATIONAL FIELD Newton s Law of Gavitation m 1 m A foce of attaction occus between two masses given by Newton s Law of Gavitation Inetial mass and gavitational mass Gavitational potential

More information

Test 2 phy a) How is the velocity of a particle defined? b) What is an inertial reference frame? c) Describe friction.

Test 2 phy a) How is the velocity of a particle defined? b) What is an inertial reference frame? c) Describe friction. Tet phy 40 1. a) How i the velocity of a paticle defined? b) What i an inetial efeence fae? c) Decibe fiction. phyic dealt otly with falling bodie. d) Copae the acceleation of a paticle in efeence fae

More information

FZX: Personal Lecture Notes from Daniel W. Koon St. Lawrence University Physics Department CHAPTER 7

FZX: Personal Lecture Notes from Daniel W. Koon St. Lawrence University Physics Department CHAPTER 7 FZX: Pesonal Lectue Notes fom Daniel W. Koon St. Lawence Univesity Physics Depatment CHAPTER 7 Please epot any glitches, bugs o eos to the autho: dkoon at stlawu.edu. 7. Momentum and Impulse Impulse page

More information

AP-C WEP. h. Students should be able to recognize and solve problems that call for application both of conservation of energy and Newton s Laws.

AP-C WEP. h. Students should be able to recognize and solve problems that call for application both of conservation of energy and Newton s Laws. AP-C WEP 1. Wok a. Calculate the wok done by a specified constant foce on an object that undegoes a specified displacement. b. Relate the wok done by a foce to the aea unde a gaph of foce as a function

More information

PHYS 172: Modern Mechanics. Summer Lecture 4 The Momentum Principle & Predicting Motion Read

PHYS 172: Modern Mechanics. Summer Lecture 4 The Momentum Principle & Predicting Motion Read PHYS 172: Moden Mechanics Summe 2010 Δp sys = F net Δt ΔE = W + Q sys su su ΔL sys = τ net Δt Lectue 4 The Momentum Pinciple & Pedicting Motion Read 2.6-2.9 READING QUESTION #1 Reading Question Which of

More information

Today s s topics are: Collisions and Momentum Conservation. Momentum Conservation

Today s s topics are: Collisions and Momentum Conservation. Momentum Conservation Today s s topics are: Collisions and P (&E) Conservation Ipulsive Force Energy Conservation How can we treat such an ipulsive force? Energy Conservation Ipulsive Force and Ipulse [Exaple] an ipulsive force

More information

SPH4U Unit 6.3 Gravitational Potential Energy Page 1 of 9

SPH4U Unit 6.3 Gravitational Potential Energy Page 1 of 9 SPH4 nit 6.3 Gavitational Potential negy Page of Notes Physics ool box he gavitational potential enegy of a syste of two (spheical) asses is diectly popotional to the poduct of thei asses, and invesely

More information

Easy. r p 2 f : r p 2i. r p 1i. r p 1 f. m blood g kg. P8.2 (a) The momentum is p = mv, so v = p/m and the kinetic energy is

Easy. r p 2 f : r p 2i. r p 1i. r p 1 f. m blood g kg. P8.2 (a) The momentum is p = mv, so v = p/m and the kinetic energy is Chapte 8 Homewok Solutions Easy P8. Assume the velocity of the blood is constant ove the 0.60 s. Then the patient s body and pallet will have a constant velocity of 6 0 5 m 3.75 0 4 m/ s 0.60 s in the

More information

LECTURE 14. m 1 m 2 b) Based on the second law of Newton Figure 1 similarly F21 m2 c) Based on the third law of Newton F 12

LECTURE 14. m 1 m 2 b) Based on the second law of Newton Figure 1 similarly F21 m2 c) Based on the third law of Newton F 12 CTU 4 ] NWTON W O GVITY -The gavity law i foulated fo two point paticle with ae and at a ditance between the. Hee ae the fou tep that bing to univeal law of gavitation dicoveed by NWTON. a Baed on expeiental

More information

Rigid Body Dynamics 2. CSE169: Computer Animation Instructor: Steve Rotenberg UCSD, Winter 2018

Rigid Body Dynamics 2. CSE169: Computer Animation Instructor: Steve Rotenberg UCSD, Winter 2018 Rigid Body Dynamics 2 CSE169: Compute Animation nstucto: Steve Rotenbeg UCSD, Winte 2018 Coss Poduct & Hat Opeato Deivative of a Rotating Vecto Let s say that vecto is otating aound the oigin, maintaining

More information

Physics 107 TUTORIAL ASSIGNMENT #8

Physics 107 TUTORIAL ASSIGNMENT #8 Physics 07 TUTORIAL ASSIGNMENT #8 Cutnell & Johnson, 7 th edition Chapte 8: Poblems 5,, 3, 39, 76 Chapte 9: Poblems 9, 0, 4, 5, 6 Chapte 8 5 Inteactive Solution 8.5 povides a model fo solving this type

More information

Physics C Rotational Motion Name: ANSWER KEY_ AP Review Packet

Physics C Rotational Motion Name: ANSWER KEY_ AP Review Packet Linea and angula analogs Linea Rotation x position x displacement v velocity a T tangential acceleation Vectos in otational motion Use the ight hand ule to detemine diection of the vecto! Don t foget centipetal

More information

C3 Interactions transfer momentum. C4 - Particles and Systems. General Physics 1

C3 Interactions transfer momentum. C4 - Particles and Systems. General Physics 1 C3 Inteactions tansfe momentum C4 - Paticles and Systems Geneal Physics 1 Solutions to HW Download PobViewe 1.4 www.physics.pomona.edu/sixideas/sicp.html Passwod fo daily HW poblems kllxjks8 Geneal Physics

More information

Orbital Angular Momentum Eigenfunctions

Orbital Angular Momentum Eigenfunctions Obital Angula Moentu Eigenfunctions Michael Fowle 1/11/08 Intoduction In the last lectue we established that the opeatos J Jz have a coon set of eigenkets j J j = j( j+ 1 ) j Jz j = j whee j ae integes

More information

Chapter 31 Faraday s Law

Chapter 31 Faraday s Law Chapte 31 Faaday s Law Change oving --> cuent --> agnetic field (static cuent --> static agnetic field) The souce of agnetic fields is cuent. The souce of electic fields is chage (electic onopole). Altenating

More information

FARADAY'S LAW dt

FARADAY'S LAW dt FAADAY'S LAW 31.1 Faaday's Law of Induction In the peious chapte we leaned that electic cuent poduces agnetic field. Afte this ipotant discoey, scientists wondeed: if electic cuent poduces agnetic field,

More information

b) (5) What average force magnitude was applied by the students working together?

b) (5) What average force magnitude was applied by the students working together? Geneal Physics I Exam 3 - Chs. 7,8,9 - Momentum, Rotation, Equilibium Nov. 3, 2010 Name Rec. Inst. Rec. Time Fo full cedit, make you wok clea to the gade. Show fomulas used, essential steps, and esults

More information

Movie Review Part One due Tuesday (in class) please print

Movie Review Part One due Tuesday (in class) please print Movie Review Pat One due Tuesday (in class) please pint Test in class on Fiday. You may stat at 8:30 if you want. (The topic of powe is not on test.) Chaptes 4-6 Main Ideas in Class Today Afte class, you

More information

CHAPTER 5: Circular Motion; Gravitation

CHAPTER 5: Circular Motion; Gravitation CHAPER 5: Cicula Motion; Gavitation Solution Guide to WebAssign Pobles 5.1 [1] (a) Find the centipetal acceleation fo Eq. 5-1.. a R v ( 1.5 s) 1.10 1.4 s (b) he net hoizontal foce is causing the centipetal

More information

Tidal forces. m r. m 1 m 2. x r 2. r 1

Tidal forces. m r. m 1 m 2. x r 2. r 1 Tidal foces Befoe we look at fee waves on the eath, let s fist exaine one class of otion that is diectly foced: astonoic tides. Hee we will biefly conside soe of the tidal geneating foces fo -body systes.

More information

Momentum and Collisions

Momentum and Collisions SOLUTIONS TO PROBLES Section 8. P8. m 3.00 kg, (a) omentum and Collisions Linea omentum and Its Consevation v ( 3.00î 4.00ĵ ) m s p mv ( 9.00î.0ĵ ) kg m s Thus, p x 9.00 kg m s and p y.0 kg m s. p p x

More information

Chapter 7. Impulse and Momentum

Chapter 7. Impulse and Momentum Chapter 7 Ipulse and Moentu 7. The Ipulse-Moentu Theore 7. The Ipulse-Moentu Theore There are any situations when the force on an object is not constant. 7. The Ipulse-Moentu Theore DEFINITION OF IMPULSE

More information

b) (5) What is the magnitude of the force on the 6.0-kg block due to the contact with the 12.0-kg block?

b) (5) What is the magnitude of the force on the 6.0-kg block due to the contact with the 12.0-kg block? Geneal Physics I Exam 2 - Chs. 4,5,6 - Foces, Cicula Motion, Enegy Oct. 13, 2010 Name Rec. Inst. Rec. Time Fo full cedit, make you wok clea to the gade. Show fomulas used, essential steps, and esults with

More information

Rotational Motion: Statics and Dynamics

Rotational Motion: Statics and Dynamics Physics 07 Lectue 17 Goals: Lectue 17 Chapte 1 Define cente of mass Analyze olling motion Intoduce and analyze toque Undestand the equilibium dynamics of an extended object in esponse to foces Employ consevation

More information

PHYS Summer Professor Caillault Homework Solutions. Chapter 9

PHYS Summer Professor Caillault Homework Solutions. Chapter 9 PHYS - Summe 007 - Pofesso Caillault Homewok Solutions Chapte 9 3. Pictue the Poblem The owne walks slowly towad the notheast while the cat uns eastwad and the dog uns nothwad. Stategy Sum the momenta

More information

c) (6) Assuming the tires do not skid, what coefficient of static friction between tires and pavement is needed?

c) (6) Assuming the tires do not skid, what coefficient of static friction between tires and pavement is needed? Geneal Physics I Exam 2 - Chs. 4,5,6 - Foces, Cicula Motion, Enegy Oct. 10, 2012 Name Rec. Inst. Rec. Time Fo full cedit, make you wok clea to the gade. Show fomulas used, essential steps, and esults with

More information

1131 T Question 1

1131 T Question 1 1131 T1 2008 Question 1 ( aks) You ae cycling, on a long staight path, at a constant speed of 6.0.s 1. Anothe cyclist passes you, taelling on the sae path in the sae diection as you, at a constant speed

More information

Chapter 5 Force and Motion

Chapter 5 Force and Motion Chapte 5 Foce and Motion In chaptes 2 and 4 we have studied kinematics i.e. descibed the motion of objects using paametes such as the position vecto, velocity and acceleation without any insights as to

More information

Chapter 5 Force and Motion

Chapter 5 Force and Motion Chapte 5 Foce and Motion In Chaptes 2 and 4 we have studied kinematics, i.e., we descibed the motion of objects using paametes such as the position vecto, velocity, and acceleation without any insights

More information

AH Mechanics Checklist (Unit 2) AH Mechanics Checklist (Unit 2) Circular Motion

AH Mechanics Checklist (Unit 2) AH Mechanics Checklist (Unit 2) Circular Motion AH Mechanics Checklist (Unit ) AH Mechanics Checklist (Unit ) Cicula Motion No. kill Done 1 Know that cicula motion efes to motion in a cicle of constant adius Know that cicula motion is conveniently descibed

More information

Chapter 13: Gravitation

Chapter 13: Gravitation v m m F G Chapte 13: Gavitation The foce that makes an apple fall is the same foce that holds moon in obit. Newton s law of gavitation: Evey paticle attacts any othe paticle with a gavitation foce given

More information

7.2. Coulomb s Law. The Electric Force

7.2. Coulomb s Law. The Electric Force Coulomb s aw Recall that chaged objects attact some objects and epel othes at a distance, without making any contact with those objects Electic foce,, o the foce acting between two chaged objects, is somewhat

More information

Physics 235 Chapter 5. Chapter 5 Gravitation

Physics 235 Chapter 5. Chapter 5 Gravitation Chapte 5 Gavitation In this Chapte we will eview the popeties of the gavitational foce. The gavitational foce has been discussed in geat detail in you intoductoy physics couses, and we will pimaily focus

More information

Physics 4A Chapter 8: Dynamics II Motion in a Plane

Physics 4A Chapter 8: Dynamics II Motion in a Plane Physics 4A Chapte 8: Dynamics II Motion in a Plane Conceptual Questions and Example Poblems fom Chapte 8 Conceptual Question 8.5 The figue below shows two balls of equal mass moving in vetical cicles.

More information

1 Random Variable. Why Random Variable? Discrete Random Variable. Discrete Random Variable. Discrete Distributions - 1 DD1-1

1 Random Variable. Why Random Variable? Discrete Random Variable. Discrete Random Variable. Discrete Distributions - 1 DD1-1 Rando Vaiable Pobability Distibutions and Pobability Densities Definition: If S is a saple space with a pobability easue and is a eal-valued function defined ove the eleents of S, then is called a ando

More information

Applied Physics I (Phys 182)

Applied Physics I (Phys 182) Applied Physics I (Phys 182) Dr. Joseph J. Trout E-ail: joseph.trout@drexel.edu Cell: (610)348-6495 Office: Disque 902 1 Moentu Ipulse Conservation of Moentu Explosions Inelastic Collisions Elastic Collisions

More information

d 2 x 0a d d =0. Relative to an arbitrary (accelerating frame) specified by x a = x a (x 0b ), the latter becomes: d 2 x a d 2 + a dx b dx c

d 2 x 0a d d =0. Relative to an arbitrary (accelerating frame) specified by x a = x a (x 0b ), the latter becomes: d 2 x a d 2 + a dx b dx c Chapte 6 Geneal Relativity 6.1 Towads the Einstein equations Thee ae seveal ways of motivating the Einstein equations. The most natual is pehaps though consideations involving the Equivalence Pinciple.

More information

Ch 13 Universal Gravitation

Ch 13 Universal Gravitation Ch 13 Univesal Gavitation Ch 13 Univesal Gavitation Why do celestial objects move the way they do? Keple (1561-1630) Tycho Bahe s assistant, analyzed celestial motion mathematically Galileo (1564-1642)

More information

(a) Calculate the apparent weight of the student in the first part of the journey while accelerating downwards at 2.35 m s 2.

(a) Calculate the apparent weight of the student in the first part of the journey while accelerating downwards at 2.35 m s 2. Chapte answes Heineann Physics 1 4e Section.1 Woked exaple: Ty youself.1.1 CALCULATING APPARENT WEIGHT A 79.0 kg student ides a lift down fo the top floo of an office block to the gound. Duing the jouney

More information

Appendix B The Relativistic Transformation of Forces

Appendix B The Relativistic Transformation of Forces Appendix B The Relativistic Tansfomation of oces B. The ou-foce We intoduced the idea of foces in Chapte 3 whee we saw that the change in the fou-momentum pe unit time is given by the expession d d w x

More information

OSCILLATIONS AND GRAVITATION

OSCILLATIONS AND GRAVITATION 1. SIMPLE HARMONIC MOTION Simple hamonic motion is any motion that is equivalent to a single component of unifom cicula motion. In this situation the velocity is always geatest in the middle of the motion,

More information

Gravitation. Chapter 12. PowerPoint Lectures for University Physics, Twelfth Edition Hugh D. Young and Roger A. Freedman. Lectures by James Pazun

Gravitation. Chapter 12. PowerPoint Lectures for University Physics, Twelfth Edition Hugh D. Young and Roger A. Freedman. Lectures by James Pazun Chapte 12 Gavitation PowePoint Lectues fo Univesity Physics, Twelfth Edition Hugh D. Young and Roge A. Feedman Lectues by James Pazun Modified by P. Lam 5_31_2012 Goals fo Chapte 12 To study Newton s Law

More information

06 - ROTATIONAL MOTION Page 1 ( Answers at the end of all questions )

06 - ROTATIONAL MOTION Page 1 ( Answers at the end of all questions ) 06 - ROTATIONAL MOTION Page ) A body A of mass M while falling vetically downwads unde gavity beaks into two pats, a body B of mass ( / ) M and a body C of mass ( / ) M. The cente of mass of bodies B and

More information

Chapter. s r. check whether your calculator is in all other parts of the body. When a rigid body rotates through a given angle, all

Chapter. s r. check whether your calculator is in all other parts of the body. When a rigid body rotates through a given angle, all conveted to adians. Also, be sue to vanced to a new position (Fig. 7.2b). In this inteval, the line OP has moved check whethe you calculato is in all othe pats of the body. When a igid body otates though

More information

Physics Fall Mechanics, Thermodynamics, Waves, Fluids. Lecture 6: motion in two and three dimensions III. Slide 6-1

Physics Fall Mechanics, Thermodynamics, Waves, Fluids. Lecture 6: motion in two and three dimensions III. Slide 6-1 Physics 1501 Fall 2008 Mechanics, Themodynamics, Waves, Fluids Lectue 6: motion in two and thee dimensions III Slide 6-1 Recap: elative motion An object moves with velocity v elative to one fame of efeence.

More information

KEPLER S LAWS OF PLANETARY MOTION

KEPLER S LAWS OF PLANETARY MOTION EPER S AWS OF PANETARY MOTION 1. Intoduction We ae now in a position to apply what we have leaned about the coss poduct and vecto valued functions to deive eple s aws of planetay motion. These laws wee

More information

When a mass moves because of a force, we can define several types of problem.

When a mass moves because of a force, we can define several types of problem. Mechanics Lectue 4 3D Foces, gadient opeato, momentum 3D Foces When a mass moves because of a foce, we can define seveal types of poblem. ) When we know the foce F as a function of time t, F=F(t). ) When

More information

Chapter 7 Impulse and Momentum. So far we considered only constant force/s BUT There are many situations when the force on an object is not constant

Chapter 7 Impulse and Momentum. So far we considered only constant force/s BUT There are many situations when the force on an object is not constant Chapter 7 Ipulse and Moentu So far we considered only constant force/s BUT There are any situations when the force on an object is not constant Force varies with tie 7. The Ipulse-Moentu Theore DEFINITION

More information

Kinematics in 2-D (II)

Kinematics in 2-D (II) Kinematics in 2-D (II) Unifom cicula motion Tangential and adial components of Relative velocity and acceleation a Seway and Jewett 4.4 to 4.6 Pactice Poblems: Chapte 4, Objective Questions 5, 11 Chapte

More information

PS113 Chapter 5 Dynamics of Uniform Circular Motion

PS113 Chapter 5 Dynamics of Uniform Circular Motion PS113 Chapte 5 Dynamics of Unifom Cicula Motion 1 Unifom cicula motion Unifom cicula motion is the motion of an object taveling at a constant (unifom) speed on a cicula path. The peiod T is the time equied

More information

m1 m2 M 2 = M -1 L 3 T -2

m1 m2 M 2 = M -1 L 3 T -2 GAVITATION Newton s Univesal law of gavitation. Evey paticle of matte in this univese attacts evey othe paticle with a foce which vaies diectly as the poduct of thei masses and invesely as the squae of

More information

PHYSICS NOTES GRAVITATION

PHYSICS NOTES GRAVITATION GRAVITATION Newton s law of gavitation The law states that evey paticle of matte in the univese attacts evey othe paticle with a foce which is diectly popotional to the poduct of thei masses and invesely

More information

Principles of Physics I

Principles of Physics I Pinciples of Physics I J. M. Veal, Ph. D. vesion 8.05.24 Contents Linea Motion 3. Two scala equations........................ 3.2 Anothe scala equation...................... 3.3 Constant acceleation.......................

More information

Gravitation. AP/Honors Physics 1 Mr. Velazquez

Gravitation. AP/Honors Physics 1 Mr. Velazquez Gavitation AP/Honos Physics 1 M. Velazquez Newton s Law of Gavitation Newton was the fist to make the connection between objects falling on Eath and the motion of the planets To illustate this connection

More information

Experiment 09: Angular momentum

Experiment 09: Angular momentum Expeiment 09: Angula momentum Goals Investigate consevation of angula momentum and kinetic enegy in otational collisions. Measue and calculate moments of inetia. Measue and calculate non-consevative wok

More information

Probability Distribution (Probability Model) Chapter 2 Discrete Distributions. Discrete Random Variable. Random Variable. Why Random Variable?

Probability Distribution (Probability Model) Chapter 2 Discrete Distributions. Discrete Random Variable. Random Variable. Why Random Variable? Discete Distibutions - Chapte Discete Distibutions Pobability Distibution (Pobability Model) If a balanced coin is tossed, Head and Tail ae equally likely to occu, P(Head) = = / and P(Tail) = = /. Rando

More information

Uniform Circular Motion

Uniform Circular Motion Unifom Cicula Motion constant speed Pick a point in the objects motion... What diection is the velocity? HINT Think about what diection the object would tavel if the sting wee cut Unifom Cicula Motion

More information

Physics 207 Lecture 5. Lecture 5

Physics 207 Lecture 5. Lecture 5 Lectue 5 Goals: Addess sstems with multiple acceleations in 2- dimensions (including linea, pojectile and cicula motion) Discen diffeent efeence fames and undestand how the elate to paticle motion in stationa

More information

Motion in Two Dimensions

Motion in Two Dimensions SOLUTIONS TO PROBLEMS Motion in Two Dimensions Section 3.1 The Position, Velocity, and Acceleation Vectos P3.1 x( m) 0!3 000!1 70!4 70 m y( m)!3 600 0 1 70! 330 m (a) Net displacement x + y 4.87 km at

More information

- 5 - TEST 1R. This is the repeat version of TEST 1, which was held during Session.

- 5 - TEST 1R. This is the repeat version of TEST 1, which was held during Session. - 5 - TEST 1R This is the epeat vesion of TEST 1, which was held duing Session. This epeat test should be attempted by those students who missed Test 1, o who wish to impove thei mak in Test 1. IF YOU

More information

Chapter 7. Impulse and Momentum

Chapter 7. Impulse and Momentum Chapter 7 Ipulse and Moentu 7. The Ipulse-Moentu Theore There are any situations when the force on an object is not constant. 7. The Ipulse-Moentu Theore DEFINITION OF IMPULSE The ipulse of a force is

More information

SOLUTIONS TO CONCEPTS CHAPTER 12

SOLUTIONS TO CONCEPTS CHAPTER 12 SOLUTONS TO CONCEPTS CHPTE. Given, 0c. t t 0, 5 c. T 6 sec. So, w sec T 6 t, t 0, 5 c. So, 5 0 sin (w 0 + ) 0 sin Sin / 6 [y sin wt] Equation of displaceent (0c) sin (ii) t t 4 second 8 0 sin 4 0 sin 6

More information

Astronomy 421 Concepts of Astrophysics I. Astrophysics Talks at UNM. Course Logistics. Backgrounds. Other Opportunities

Astronomy 421 Concepts of Astrophysics I. Astrophysics Talks at UNM. Course Logistics. Backgrounds. Other Opportunities Astonoy 421 Concepts of Astophysics I Couse Logistics Goals: - Ipove knowledge of astophysics - develop eseach skills ain Aeas of Study: - Obital echanics - Radiation and atte - Relativity - Stas - Stella

More information

Physics 2212 GH Quiz #2 Solutions Spring 2016

Physics 2212 GH Quiz #2 Solutions Spring 2016 Physics 2212 GH Quiz #2 Solutions Sping 216 I. 17 points) Thee point chages, each caying a chage Q = +6. nc, ae placed on an equilateal tiangle of side length = 3. mm. An additional point chage, caying

More information

Review: Electrostatics and Magnetostatics

Review: Electrostatics and Magnetostatics Review: Electostatics and Magnetostatics In the static egime, electomagnetic quantities do not vay as a function of time. We have two main cases: ELECTROSTATICS The electic chages do not change postion

More information

On the Correct Formulation of the Starting Point of Classical Mechanics

On the Correct Formulation of the Starting Point of Classical Mechanics Intenational Jounal of dvanced Reseach in Physical Science (IJRPS) Volue 4, Issue 6, 27, PP -22 ISSN No. (Online) 2349-7882 www.acjounals.og On the Coect oulation of the Stating Point of Classical echanics

More information

You are to turn in this final and the scantron to the front when finished.

You are to turn in this final and the scantron to the front when finished. Physics Fall 00: Final Exa Vesion B Nae: Quiz Code Nube: Closed book. No wok needs to be shown fo ultiple-choice questions.. Conside a ass on a sping that is undegoing siple haonic otion. In this siple

More information

System of Particles: Center-of-Mass

System of Particles: Center-of-Mass System of Paticles: Cente-of-ass The cente-of-mass of a system of paticles is the point that moes as though () all of the systems mass wee concentated thee and () all etenal foces wee applied thee. Location

More information

Lecture 19 Angular momentum. Chapter

Lecture 19 Angular momentum. Chapter PHYS 172H: Moden Mechanics Fall 2010 Lectue 19 ngula momentum Chapte 11.4 11.7 The angula momentum pinciple dp = F dl =? net d ( p ) d dp = p+ = v γ mv = = 0 The angula momentum pinciple fo a point paticle

More information

Central Force Motion

Central Force Motion Cental Foce Motion Cental Foce Poblem Find the motion of two bodies inteacting via a cental foce. Examples: Gavitational foce (Keple poblem): m1m F 1, ( ) =! G ˆ Linea estoing foce: F 1, ( ) =! k ˆ Two

More information

10. Force is inversely proportional to distance between the centers squared. R 4 = F 16 E 11.

10. Force is inversely proportional to distance between the centers squared. R 4 = F 16 E 11. NSWRS - P Physics Multiple hoice Pactice Gavitation Solution nswe 1. m mv Obital speed is found fom setting which gives v whee M is the object being obited. Notice that satellite mass does not affect obital

More information

Revision Guide for Chapter 11

Revision Guide for Chapter 11 Revision Guide fo Chapte 11 Contents Revision Checklist Revision Notes Momentum... 4 Newton's laws of motion... 4 Wok... 5 Gavitational field... 5 Potential enegy... 7 Kinetic enegy... 8 Pojectile... 9

More information

Chapter 7-8 Rotational Motion

Chapter 7-8 Rotational Motion Chapte 7-8 Rotational Motion What is a Rigid Body? Rotational Kinematics Angula Velocity ω and Acceleation α Unifom Rotational Motion: Kinematics Unifom Cicula Motion: Kinematics and Dynamics The Toque,

More information

12.1 Introduction 12-1

12.1 Introduction 12-1 12.1 Intoduction So fa we have esticted ouselves to consideing systems consisting of discete objects o point-like objects that have fixed amounts of mass. We shall now conside systems in which mateial

More information

F g. = G mm. m 1. = 7.0 kg m 2. = 5.5 kg r = 0.60 m G = N m 2 kg 2 = = N

F g. = G mm. m 1. = 7.0 kg m 2. = 5.5 kg r = 0.60 m G = N m 2 kg 2 = = N Chapte answes Heinemann Physics 4e Section. Woked example: Ty youself.. GRAVITATIONAL ATTRACTION BETWEEN SMALL OBJECTS Two bowling balls ae sitting next to each othe on a shelf so that the centes of the

More information

2. Electrostatics. Dr. Rakhesh Singh Kshetrimayum 8/11/ Electromagnetic Field Theory by R. S. Kshetrimayum

2. Electrostatics. Dr. Rakhesh Singh Kshetrimayum 8/11/ Electromagnetic Field Theory by R. S. Kshetrimayum 2. Electostatics D. Rakhesh Singh Kshetimayum 1 2.1 Intoduction In this chapte, we will study how to find the electostatic fields fo vaious cases? fo symmetic known chage distibution fo un-symmetic known

More information

Chapter 6 Differential Analysis of Fluid Flow

Chapter 6 Differential Analysis of Fluid Flow 1 Chapte 6 Diffeential Analysis of Fluid Flow Inviscid flow: Eule s equations of otion Flow fields in which the sheaing stesses ae zeo ae said to be inviscid, nonviscous, o fictionless. fo fluids in which

More information

The Concept of the Effective Mass Tensor in GR. Clocks and Rods

The Concept of the Effective Mass Tensor in GR. Clocks and Rods The Concept of the Effective Mass Tenso in GR Clocks and Rods Miosław J. Kubiak Zespół Szkół Technicznych, Gudziądz, Poland Abstact: In the pape [] we pesented the concept of the effective ass tenso (EMT)

More information

Numerical Integration

Numerical Integration MCEN 473/573 Chapte 0 Numeical Integation Fall, 2006 Textbook, 0.4 and 0.5 Isopaametic Fomula Numeical Integation [] e [ ] T k = h B [ D][ B] e B Jdsdt In pactice, the element stiffness is calculated numeically.

More information

An Exact Solution of Navier Stokes Equation

An Exact Solution of Navier Stokes Equation An Exact Solution of Navie Stokes Equation A. Salih Depatment of Aeospace Engineeing Indian Institute of Space Science and Technology, Thiuvananthapuam, Keala, India. July 20 The pincipal difficulty in

More information

Recap. Centripetal acceleration: v r. a = m/s 2 (towards center of curvature)

Recap. Centripetal acceleration: v r. a = m/s 2 (towards center of curvature) a = c v 2 Recap Centipetal acceleation: m/s 2 (towads cente of cuvatue) A centipetal foce F c is equied to keep a body in cicula motion: This foce poduces centipetal acceleation that continuously changes

More information

PHYS 172: Modern Mechanics. Fall Lecture 6 Fundamental Forces, Reciprocity Read

PHYS 172: Modern Mechanics. Fall Lecture 6 Fundamental Forces, Reciprocity Read PHYS 172: Moden Mechanics Fall 2009 Lectue 6 Fundamental Foces, Recipocity Read 3.9 3.14 Exam 1 - Tuesday Septembe 15, 8:00-10:00 PM Elliott Hall of Music 1. The exam will be witten as a standad 1 hou

More information

2.2 This is the Nearest One Head Gravitational Potential Energy 14.8 Energy Considerations in Planetary and Satellite Motion

2.2 This is the Nearest One Head Gravitational Potential Energy 14.8 Energy Considerations in Planetary and Satellite Motion 2.2 This is the Neaest One Head 423 P U Z Z L E R Moe than 300 yeas ago, Isaac Newton ealized that the sae gavitational foce that causes apples to fall to the Eath also holds the Moon in its obit. In ecent

More information

Physics 181. Assignment 4

Physics 181. Assignment 4 Physics 181 Assignment 4 Solutions 1. A sphee has within it a gavitational field given by g = g, whee g is constant and is the position vecto of the field point elative to the cente of the sphee. This

More information

Rotational Motion. Lecture 6. Chapter 4. Physics I. Course website:

Rotational Motion. Lecture 6. Chapter 4. Physics I. Course website: Lectue 6 Chapte 4 Physics I Rotational Motion Couse website: http://faculty.uml.edu/andiy_danylov/teaching/physicsi Today we ae going to discuss: Chapte 4: Unifom Cicula Motion: Section 4.4 Nonunifom Cicula

More information