ANALYSIS OF GATE 2017* Electrical Engineering

Size: px
Start display at page:

Download "ANALYSIS OF GATE 2017* Electrical Engineering"

Transcription

1 ANALYSS OF GATE 2017* Electrical Engineering Power Systems 10% General Aptitude 15% Engineering Mathematics 11% Network Theory 9% Signals & Systems 7% Electrical Machines 12% Control Systems 11% Power Electronics 7% Analog Circuits 6% Electromagnetic Theory 3% Measurement 4% Digital Circuits 5% : , info@thegateacademy.com Copyright reserved. Web: 1

2 EE ANALYSS-2017_11-Feb_Morning SUBJECT No. of Ques. Topics Asked in Paper(Memory Based) Engineering Mathematics Network Theory Signals & Systems Control Systems Analog Circuits Digital Circuits 1 Marks: 3 2 Marks: 4 1 Marks: 3 2 Marks: 3 1 Marks: 3 2 Marks: 2 1 Marks: 3 2 Marks: 4 1 Marks: 2 2 Marks: 2 1 Marks: 1 2 Marks: 2 Linear Algebra; Calculus; Complex ariables Differential Equations; Numerical Methods Network Solution Methodology; Two Port Networks; Transient/Steady State Analysis of LC Circuits to DC nput; Miscellaneous Fourier epresentation of Signals; Linear Time nvariant (LT) Systems;Z-Transform Stability & outh Hurwitz Criterion; Frequency esponse Analysis; State ariable Analysis; Time Domain Analysis; Basics of Control System; Time Domain Analysis Diode Circuits-Analysis and Application; Operational Amplifiers & ts Applications; AC & DC Biasing-BJT and FET; Miscellaneous Boolean Algebra and Karnaugh Maps Logic Gates Level of Ques. Total Marks Tough 11 Medium 9 Tough 7 Tough 11 Easy 6 Easy 5 Measurement 1 Marks: 2 2 Marks: 1 Measurements of Basic Electrical Quantities 1 Basic Electrical Quantities 2 Medium 4 Power Electronics 1 Marks: 3 2 Marks: 2 nverters; Basics of Power Semiconductor Devices; ectifiers; Choppers Tough 7 Electromagnetic Theory 1 Marks: 1 2 Marks: 1 Electromagnetic Field Medium 3 Electrical Machines Power Systems General Aptitude 1 Marks: 2 2 Marks: 5 1 Marks: 2 2 Marks: 4 1 Marks:5 2 Marks:5 Synchronous Machine; nduction Motor; DC Machines; Transformer Symmetrical Components and Faults Calculations; Transmission and Distribution; Power System Stability Easy 12 Tough 10 Medium 15 Total Faculty Feedback Majority of the question were concept based. Control, PS, Network EM, Maths weightage was comparatively high. GA was medium as compared to the last year. : , info@thegateacademy.com Copyright reserved. Web: 2

3 GATE 2017 Examination* Electrical Engineering Test Date: 11/02/2017 Test Time: 9:00 AM 12:00 PM Subject Name: Electrical Engineering Section: General Aptitude 1. Find the smallest number y such that y 162 is a perfect cube. (A) 24 (B) 27 (C) 32 (D) 36 [Ans. D] Factorization of 162 is y is a perfect cube y = Perfect cube For perfect cube s and s are two more required each i e y The smallest number of y 2. The probability that a k-digit number does NOT contain the digits 0, 5, or 9 is (A) (B) (C) (D) [Ans. C] K digits Each digit can be filled in 7 ways as 0, 5 and 9 is not allowed so, each of these places can be filled by 1, 2, 3, 4, 5, 6, 8. So required probability ( ) ( ) 3. After ajendra Chola returned from his voyage to ndonesia, he to visit the temple in Thanjavur. : , info@thegateacademy.com Copyright reserved. Web: 3

4 ahul rul. (A) was wishing (B) is wishing (C) wished (D) had wished [Ans. C] f the main clause is in the past the past tense, the subordinate clause also should be in the past tense. 4. ahul, Murali, Srinivas and Arul are seated around a square table. ahul is sitting to the left of Murali. Srinivas is sitting to the right of Arul. Which of the following pairs are seated opposite each other? (A) ahul and Murali (B) Srinivas and Arul (C) Srinivas and Murali (D) Srinivas and ahul [Ans. C] From the given data, the following seated arrangement is possible around a square table. Srinivas ahul Murali rul Srinivas Murali Srinivas and Murali are opposite to each other 5. esearch in the workplace reveals that people work for many reasons. (A) money beside (B) beside money (C) money besides (D) besides money [Ans. D] Besides means in addition to. 6. Six people are seated around a circular table. There are at least two men and two women. There are at least three right-handed persons. Every woman has a left-handed person to her immediate right. None of the women are right-handed. The number of women at the table is (A) 2 (B) 3 (C) 4 (D) Cannot be determined [Ans. A] The total Number of peoples are sitting around a circular table is 6, in which atleast 2 men, atleast 2 women and atleast three right handed persons are compulsory. From this data, the following circular form is possible. : , info@thegateacademy.com Copyright reserved. Web: 4

5 M() M() M() W(L) M(L) W(L) M = Male W = Women L = Left hand = ight hand The number of women on the table is 7. Arun, Gulab, Neel and Shweta must choose one shirt each from a pile of four shirts coloured red, pink, blue and white respectively. Arun dislikes the colour red and Shweta dislike the colour white. Gulab and Neel like all the colours. n how many different ways can they choose the shirts so that no one has a shirt with a colour he or she dislikes? (A) 21 (B) 18 (C) 16 (D) 14 [Ans. D] Persons are Arun, Gulab, Neel and Shweta shirt colours are red, pink, blue and white run dislike red colour means he like remaining three other colours Shweta dislike white colour means he like remaining three other colours Gulab and Neel are likes all the four colours The total Number of ways to choose shifts 8. The expression ( ) is equal to (A) The maximum of x and y (B) The minimum of x and y (C) 1 (D) None of the above [Ans. B] (x y) x y x y (x y) if(x y) when x y if (x y) (y x)when y x (x y) (x y) x y x y Minimum of (x y) as (x y) (x y) (y x) x y y x y y : , info@thegateacademy.com Copyright reserved. Web: 5

6 as x y x x Minimum of (x y) 9. The hold of the nationalist imagination on our colonial past is such that anything inadequately or improperly nationalist is just not history Which of the following statements best reflects the author s opinion? (A) Nationalists are highly imaginative (B) History is viewed through the filter of nationalism (C) Our colonial past never happened (D) Nationalism has to be both adequately and properly imagined [Ans. B] To refer is to reach an opinion The right opinion of the author is History is viewed through the filter of nationalism so, option B is the right opinion of the author. The key words in the statement are history and nationalist imagination 10. A contour line joins locations having the same height above the mean sea level. The following is a contour plot of a geographical region. Contour lines are shown at 25 m intervals in this plot. f in a flood the water level rises to 525 m, which of the villages P, Q,, S, T get submerged? Q P S T (A) P, Q (B) P, Q, T (C), S, T (D) Q,, S [Ans. C] The given contour is a hill station, the peak point of this hill station is P, it is under a contour of 550. At floods, the water level is 525 m. So, the village of, S and T are under a contour of 500. Therefore these villages are submerged. : , info@thegateacademy.com Copyright reserved. Web: 6

7 Section: Technical 1. The equivalent resistance between the terminals and B is [Ans. *] ange: 2.9 to 3.1 ] 2. The matrix [ ] has three distinct eigen values and one of its eigen vectors is [ ] Which one of the following can be another eigen vector of A? ( ) [ ] (B) [ ] ( ) [ ] ( ) [ ] [Ans. C] Since eigen values are distinct and the matrix is symmetric then the corresponding eigen vectors are orthogonal Then X X By verification from options, Given X [ ] Let X [ ] X X : , info@thegateacademy.com Copyright reserved. Web: 7

8 3. A 3-bus power system is shown in the figure below, where the diagonal elements of Y-bus matrix are: Y j pu Y j pu and Y j pu. Bus Bus jq ~ jr Bus jp The per unit values of the line reactances p, q and r shown in the figure are (A) p q r (B) p q r (C) p q r (D) p q r [Ans. B] jr jq jq jp jp jr j j j r q q p p r ( ) p q r ( ) p q r ( ) ( ) p p ( ) ( ) r r pu ( ) ( ) q q pu 4. The following measurements are obtained on a single phase load: and W W. f the power factor is calculated using these measurements, the worst case error in the calculated power factor in percent is. (Give answer up to one decimal place.) [Ans. *] ange: 4 to 4 P Power factor cos n multiplication and division percentage values will be added up. : , info@thegateacademy.com Copyright reserved. Web: 8

9 5. Consider an electron, a neutron and a proton initially at rest and placed along a straight line such that the neutron is exactly at the center of the line joining the electron and proton. At t, the particles are released but are constrained to move along the same straight line. Which of these will collide first? (A) The particles will never collide (B) All will collide together (C) Proton and neutron (D) Electron and neutron [Ans. D] r m r m e n P q coul coul B q coul t < 0: The particles are at rest. No ext. field is mentioned in the problem. So the only force is that acting on e & p. This has a magnitude force neglected). (attractive). No force on n. (Gravitational 6. n the converter circuit shown below, the switches are controlled such that the load voltage v (t) is a Hz square wave. s s s Load (t) s The MS value of the fundamental component of (t) in volts is [Ans. *] ange: 196 to 200 Given circuit is 1 phase full bridge voltage source inverter. t is mentioned that output voltage is a square wave and its amplitude will be 220 Therefore, MS value of fundamental component of output voltage 7. Let c xy dxdy, where is the region shown in the figure and c. The value of equals. (Give the answer up to two decimal places) : , info@thegateacademy.com Copyright reserved. Web: 9

10 y x [Ans. *] ange: 0.99 to 1.01 Let c XY dxdy y x Now, XY dxdy XY dxdy XY dxdy XY dxdy XY dxdy ( X ) Y dy ( X ) y dy ( ) y dy ( y ) y dy y dy ( y y ) dy ( y ) ( y y ) dy ( y y ) ( ) ( ) : , info@thegateacademy.com Copyright reserved. Web: 10

11 8. For a complex number z, z lim z z i(z ) is (A) i (B) i (C) i (D) 2i [Ans. D] z lim z z i(z ) ( form) Applying L Hospital rule lim z z i( z) (i) ( ) i( i) i i 9. A solid iron cylinder is placed in a region containing a uniform magnetic field such that the cylinder axis is parallel to the magnetic field direction. The magnetic field lines inside the cylinder will (A) bend closer to the cylinder axis (B) bend farther away from the axis (C) remain uniform as before (D) cease to exist inside the cylinder [Ans. A] ron is a ferrormagnetic material. n such a material, there will be magnetic dipoles associated with the spins of unpaired electrons, just like in a paramagnetic material. n the absence of any external magnetic field: n a paramagnetic material these dipoles are oriented in all possible directions, and so their dipole, moments are cancelled out, and the material as a whole is non-magnetic. n a ferromagnetic material, all the dipoles point in only one direction. (This can be explained using quantum mechanics). But in that case, every nail, every piece of iron, must be a powerful permanent magnet; why is it not so? The alignment occurs in small patches, called domains. Each domain has several billions of dipoles, all pointing in one direction; but in any small piece of iron, there are billions of such domains, dipoles of each domain oriented randomly in some direction. The net magnetization of all these dipoles is zero. When an external magnetic field B is applied, domains with the same direction as B grow, others shrink; the material is magnetized in the direction of B. : , info@thegateacademy.com Copyright reserved. Web: 11

12 So when a solid iron cylinder is placed in a uniform B with the axis of the cylinder along the direction of B, the field lines in the cylinder remain parallel and uniform as before, but their density increases. 10. The slope and level detector circuit in a CO has a delay of 100 ns. The start-stop sweep generator has a response time of 50 ns. n order to display correctly, a delay line of (A) 150 ns has to be inserted into the y-channel (B) 150 ns has to be inserted into the x-channel (C) 150 ns has to be inserted into both x and y channels (D) 100 ns has to be inserted into both x and y channels [Ans. A] n order to display correctly, a delay line of 150 ns has to be inserted in to the Y-channel between output of vertical amplifier and Y-input of CT 11. onsider g(t) { t t t t t otherwise } where t Here, t represent the largest integer less than or equal to t and t denotes the smallest integer greater than or equal to t. The coefficient of the second harmonic component of the Fourier series representing g(t) is [Ans. *] ange: 0 to 0 Given g(t) { t t t t t otherwise } f we plot the above signal, we get g(t) Since this wave form contain hidden half wave symmetry, even harmonics does not exist. Thus coefficient of second harmonic component of Fourier series will be zero. 12. A 3-phase voltage source inverter is supplied from a 600 DC source as shown in the figure below. For a star connected resistive load of per phase, the load power for device conduction, in kw, is [Ans.*]ange: 8.5 to 9.5 MS value of phase voltage for conduction mode is : , info@thegateacademy.com Copyright reserved. Web: 12

13 (t) sin( t). Power delivered to load P ( ) kw 13. Let z(t) x(t) y(t). Where denotes convolution. Let c be a positive real-valued constant. Choose the correct expression for z(ct) (A) c x(ct) y(ct) (B) x(ct) y(ct) (C) c x(ct) y(ct) (D) c x(ct) y(t) [Ans. A] z(t) x(t) y(t) as per property of convolution x(ct) y(ct) c z(ct) z(ct) c x(ct) y(ct) Given c is a positive integer so z(ct) c x(ct) y(ct) 14. For the circuit shown in the figure below, assume that diodes, and are ideal. ~ The DC components of voltages v and v, respectively are (A) 0 and 1 (B) and (C) 1 and 0.5 (D) 1 and 1 [Ans. B] During ve cycle input: ON and OFF : , info@thegateacademy.com Copyright reserved. Web: 13

14 (t) sin( t) (t) sin( t). ~ ( ) During ve cycle input: OFF and ON ~ and (t) The voltage waveforms are shown in below figure. (t) t (t) (t) t t component of is component of is 15. For the power semiconductor devices GBT, MOSFET. Diode and Thyristor, which one of the following statements is TUE? (A) All the four are majority carrier devices (B) All the four are minority carrier devices : , info@thegateacademy.com Copyright reserved. Web: 14

15 (C) GBT and MOSFET are majority carrier devices, whereas Diode and Thyristor are minority carrier devices. (D) MOSFET is majority carrier device, whereas GBT, Diode, Thyristor are minority carrier devices. [Ans. D] Only MOSFET is majority carrier device. And remaining all other devices belongs to minority carrier devices 16. Consider the system with following input-output relation y n] ( ( ) )x n] Where, x[n] is the input and y[n] is the output. The system is (A) nvertible and time invariant (B) nvertible and time varying (C) Non-invertible and time invariant (D) Non-invertible and time varying [Ans. D] y(n) ( ) ]x(n) Y (n) ( ) ]x(n n ) y(n n ) ( ) ]x(n n ) y (n) y(n n so, time variant if x (n) u(n) y (n) ( n) ]u(n) ] x (n) ] y (n) ( ) ]x (n) ] Non-invertible, variant The system is time variant and non-invertible. 17. A three-phase, 50 Hz, star-connected cylindrical-rotor synchronous machine is running as a motor. The machine is operated from a 6.6 k grid and draws current at unity power factor (UPF). The synchronous reactance of the motor is per phase. The load angle is. The power delivered to the motor in kw is (Give the answer up to one decimal place) [Ans. *] ange: 8.35 to 8.42 (Unity Pf) X By neglecting armature resistance the active power drawn by a synchronous motor is p sin X ( X ) Ph : , info@thegateacademy.com Copyright reserved. Web: 15

16 cos ph cos ( ) cos( ) P ( ) [ ] sin ( ) P= kw 18. A source is supplying a load through a 2-phase, 3-wire transmission system as shown in figure below. The instantaneous voltage and current in phase-a are v sin( t) and i sin( t) A respectively. Similarly for phase-b, the instantaneous voltage and current are v cos( t) and i cos( t), respectively. Source a i b i n a b n Load The total instantaneous power flowing from the source to the load is (A) 2200 W (B) sin ( t) W (C) 4400 W (D) sin( t) cos( t) W [Ans. A] Total instantaneous power: s [ ] [ ] [ W ] [ ] 19. A closed loop system has the characteristic equation given by s Ks (K )s. For this system to be stable, which one of the following conditions should be satisfied? (A) 0 < K < 0.5 (B) 0.5 < K < 1 (C) 0 < K < 1 (D) K > 1 [Ans. D] s K s K 3 K K s K s 3 For stability K and K K So, K K i e K 20. The transfer function of a system is given by : , info@thegateacademy.com Copyright reserved. Web: 16

17 (s) (s) s s Let the output of the system be v (t) sin( t ) for the input v (t) sin ( t). Then the minimum and maximum values of (in radians) are respectively ( ) and (B) and ( ) and ( ) and [Ans. D] ( j j ) ( tan tan ) t (Maximum) t (Minimum) 21. A 10 bus power system consists of four generator buses indexed as G1, G2, G3, G4 and six load buses indexed as L1, L2, L3, L4, L5, L6. The generator-bus G1 is considered as slack bus, and the load buses L3 and L4 are voltage controlled buses. The generator at bus G2 cannot supply the required reactive power demand, and hence it is operating at its maximum reactive power limit. The number of non-linear equations required for solving the load flow problem using Newton-aphson method in polar form is. [Ans. *] ange: 14 to 14 G Slack bus G having reactive power Q min Q Q max When it is operating at Q max means there is a reactive power divergent. Hence it is working as load bus. G 2 equations G 1 equation G 1 equation L 2 equations L 2 equations L 2 equations L 2 equations L 1 equation L 1 equation Total Number of equations are Consider the unity feedback control system shown. The value of K that results in a phase margin of the system to be is. (Give the answer up to two decimal places). : , info@thegateacademy.com Copyright reserved. Web: 17

18 U(s) Ke s Y(s) [Ans. *] ange: 1.01 to 1.06 PM Ke j And K PM K 23. A 4 pole induction machine is working as an induction generator. The generator supply frequency is 60 Hz. The rotor current frequency is 5 Hz. The mechanical speed of the rotor in PM is (A) 1350 (B) 1650 (C) 1950 (D) 2250 [Ans. C] Supply frequency (f ) Hz Pole f N rpm P otor frequency (f ) = 5 Hz We know that f = sf (s)( ) But in induction generator, slip is a negative value N N rpm 24. The Boolean expression B B simplifies to (A) B (B) B B (C) B (D) B B [Ans. A] B B B( ) B B B B B ( ) (B ) : , info@thegateacademy.com Copyright reserved. Web: 18

19 B 25. The power supplied by the 25 source in the figure shown below is W. [Ans. *] ange: 248 to 252 From KCL, So, power supplied W 26. The figure below shows an uncontrolled diode bridge rectifier supplied from a 220, 50 Hz, 1-phase ac source. The load draws a constant. The conduction angle of the diode in degrees(rounded of to two decimal places) is L ~ mh Hz [Ans. *] ange: 220 to 230 When source inductance is not taken into account, each diode will conduct for 180 When source inductance is taken into account, each diode will conduct for ( ) Where is overlap angle and can be determined as follows: L cos cos Conduction angle for D1 is 27. The transfer function of the system Y(s)/U(s) whose state-space equations are given below is: [ x (t) x (t) ] * [x (t) x (t) ] * u(t) y(t) ] [ x (t) x (t) ] (s ) ( ) (s s ) : , info@thegateacademy.com Copyright reserved. Web: 19

20 (s ) (B) (s s ) (s ) ( ) (s s ) (s ) ( ) (s s ) [Ans. D] TF S ] B S * s s TF TF s ] * s s (s )(s) s s * 28. A function f(x) is defined as f(x) e x { ln x ax bx x Where x Which one of the following statements is TUE? (A) f(x) is NOT differentiable at x = 1 for any values of a and b (B) f(x) is differentiable at x = 1 for the unique values of a and b (C) f(x) is differentiable at x = 1 for all values of a and b such that a b = e (D) f(x) is differentiable at x = 1 for all values of a and b [Ans. B] f(x) e x { log x ax bx x e x f (x) { x ax b x At x=1, L H e H a b Since f(x) is differentiable at x = 1, a b e a b e Since f(x) is continuous at x = 1, t x L H L e H L a b a b e Solving and a b e a and b have unique values. 29. The approximate transfer characteristic for the circuit shown below with an ideal operational amplifier and diode will be : , info@thegateacademy.com Copyright reserved. Web: 20

21 ( ) (B) ( ) ( ) [Ans. A] The given circuit is redrawn as When, Diode is ON, then replaced by SC When, Diode OFF, then replaced by OC : , info@thegateacademy.com Copyright reserved. Web: 21

22 The output characteristic is shown below. 30. n the circuit shown below, the maximum power transferred to the resistor is W. [Ans. *] ange: 3 to 3.1 To find By applying KL to the above loop ( ) = 2.1 To find Maximum power transferred is ( ) ( ) Maximum power transferred = : , info@thegateacademy.com Copyright reserved. Web: 22

23 31. A separately excited DC generator supplies 150 A to a 145 DC grid. The generator is running at 800 PM. The armature resistance of the generator is. f the speed of the generator is increased to 1000 PM, the current in amperes supplied by the generator to the DC grid is. [Ans. *] ange: 548 to 552 (Grid) N rpm N rpm (Grid)? r ( )( ) N [ K const] N ( ) ( ) 32. Consider a causal and stable LT system with rotational transfer function H(z), whose corresponding impulse response begins at n = 0. Furthermore, H( ). The poles of H(z) are p exp (j ) for k. The zeros of H(z) are all at z. Let g n] j h n]. The value of g[8] equals (Give the answer up to three decimal places). [Ans. *] ange: 0.06 to The magnitude of magnetic flux density (B) in micro Teslas ( T), at the center of a loop of wire wound as a regular hexagon of side length 1 m carrying a current ( = 1A) and placed in vacuum as shown in the figure is. [Ans. *] ange: 0.65 to 0.75 : , info@thegateacademy.com Copyright reserved. Web: 23

24 H H H H H H H Since the figure is regular hexagon, the field magnitude is same and is in the same direction So H H tan d d H H d (sin sin ) d ( ) ( ) H H H B H B T 34. For a system having transfer function G(s) a unit step input is applied at time t = 0. The value of the response of the system at t = 1.5 sec (rounded off to three decimal places) is [Ans. *] ange: to s TF nput (unit step) s s Output (TF)(input) s ( s ) s Output L [ s s s ] e Output at(r ) e : , info@thegateacademy.com Copyright reserved. Web: 24

25 35. Consider the differential equation (t ) t y sin(t) with y( ). There exists a unique solution for this differential equation when t belongs to the interval (A) ( ) (B) ( ) (C) ( ) (D) ( ) [Ans. A] (t ) dy ty dt sint with y( ) dy dt t (t ) y sint (t ) The given differential equation has no solution when t. These values do not lie in the interval ( ) The solution of the given differential equation lies in the interval ( ) Option ( ) is correct 36. Consider the line integral (x iy ) dz, where z x iy. The line c is shown in the figure below. y i ( i) ( ) The value of is x ( ) i (B) i ( ) i ( ) i [Ans. B] Given is y x dy dx Then x varies from (x iy )dz to (x ix )(dx idx) : , info@thegateacademy.com Copyright reserved. Web: 25

26 ( i) x dx ( i i ) * x ( i ) ( ) i 37. The input voltage of the buck-boost converter shown below varies from 32 to 72. Assume that all components are ideal, inductor current is continuous, and output voltage is ripple free. The range of duty ratio D of the converter for which the magnitude of the steadystate output voltage remains constant at 48 is S L ( ) (B) ( ) ( ) [Ans. A] n Buck boost converter When When The range of will be or 38. The load shown in the figure is supplied by a 400 (line-to-line) 3-phase source (YB sequence). The load is balanced and inductive, drawing 3464 A. When the switch S is in position N, the three watt-meters W, W and W read W each. f the switch is moved to position Y, the readings of the watt-meters in watts will be: : , info@thegateacademy.com Copyright reserved. Web: 26

27 phase source LO. W Y W B W Y N (A) W and W W (B) W W and W (C) W W W (D) W W and W [Ans. D] S N P W W W Power factor cos lag When switch is in position N W W W W balanced load total power consumed by load is W W W W W W : , info@thegateacademy.com Copyright reserved. Web: 27

28 Given load is inductive And A draw from source = 3464 A W Power factor lag power factor angle ( lag) When switch is connected in Y position pressure coil of W is shorted So W diagrams for other two are as follows W cos( angle between and cos( ) W W cos( angle between and cos( ) W W1 = 0, W2 = 0, W3 = 1732 W and phasor 39. The circuit shown in the figure uses matched transistors with a thermal voltage m. The base currents of the transistors are negligible The value of the resistance in k that is required to provide bias current for the differential amplifier block shown is. Differential Amplifier m [Ans. *] ange: 170 to 174 : , info@thegateacademy.com Copyright reserved. Web: 28

29 Differential Amplifier m Q Q m As B&C shorted, Transistor behaves as diode. Then, e e e e e ( ) n ( nd ) n ( ) n ( ) n( ) k k 40. Two parallel connected, three-phase, 50 Hz, 11 k, star-connected synchronous machines A and B, are operating as synchronous condensers. They together supply 50 MA to a 11 k grid. Current supplied by both the machines are equal. Synchronous reactances of machine A and machine B are and, respectively. Assuming the magnetic circuit to be linear, the : , info@thegateacademy.com Copyright reserved. Web: 29

30 ratio of excitation current of machine A to that of machine B is. (Give the answer up to two decimal places). [Ans. *] ange: 2.05 to 2.13 Synchronous ondencors urrent s supplied both the machines are same mps As the two motors, supplying reactive power only, the phasor diagram will be k i ~ ~ j X j X onsider magnitudes ( X ) ( X ) ( ) olts ( ) olts B X M 41. The output expression for the Karnaugh map shown below is CD AB (A) B B (B) B B (C) B B (D) B B : , info@thegateacademy.com Copyright reserved. Web: 30

31 [Ans. D] B F B B 42. The bus admittance matrix for a power system network is j j j [ j j j ] pu j j j There is a transmission line connected between buses 1 and 3, which is represented by the circuit shown in figure. eactance is pu Suceptance is pu Suceptance is pu f this transmission line is removed from service what is the modified bus admittance matrix? j j (A) [ j j j ] pu j j j j (B) [ j j j ] pu j j j j (C) [ j j j ] pu j j j j j (D) [ j j j ] pu j j j [Ans. C] When the line is removed from buses 1 and 3 z j y j y y y j Half line shunt susceptance Y mod Y old y Y mod Y old y y y j ( j ) j j j ( j ) j j : , info@thegateacademy.com Copyright reserved. Web: 31

32 43. A 375 W, 230, 50 Hz, capacitor start single-phase induction motor has the following constants for the main and auxiliary windings (at starting): Z ( j ) (main winding), Z ( j ) (auxiliary winding). Neglecting the magnetizing branch, the value of the capacitance (in F) to be added in series with the auxiliary winding to obtain maximum torque at staring is. [Ans. *] ange: 95 to 100 Given a single-phase capacitor start induction motor j j jx Fs To obtain maximum torque of starting, the main and auxiliary winding currents must have electrical tan ( X r ) tan ( X X r ) tan ( ) tan ( X ) X X fc F 44. Two passive two-port networks are connected in cascade as shown in figure. A voltage source is connected at port 1. ~ Two-port Network 1 Two-port Network 2 Port Port Port Given: B B, B,,,, B, and are the generalized circuit constants. f the Thevenin equivalent circuit at port 3 consists of a voltage source and an impedance Z, connected in series, then : , info@thegateacademy.com Copyright reserved. Web: 32

33 ( ) (B) ( ) ( ) [Ans. D] [ ] [ [ ] [ For Z Z B Z B B B B Z Z B B B B B B B B B ] [ ] [ ] B B B B Z ( ) ( B ) ( B B ) ( B B ) B B B Z B For and ( B ) B ] [ ] 45. Let the single x(t) ( ) (t ) be passed through an LT system with frequency response H( ), as given in the figure below. H( ) The Fourier series representation of the output is given as (A) cos( t) cos( t) (B) cos( t) cos( t) (C) cos( t) (D) cos( t) [Ans. C] : , info@thegateacademy.com Copyright reserved. Web: 33

34 X(t) t T x(t)e dt * x(t)e dt [ e ( ) ] [ e ( )( ) ] [ e ] ( ) ] X( ) ( n ) X( ) ( ( ) ) ( n ) X( ) ( ) ( ) ] X( ) ( ) ( ) ] X( ) cos( t) cos( t) ] H( ) The output of low part filter is y(t) cos( t) 46. The positive, negative, and zero sequence reactances of a wye-connected synchronous generator are 0.2 pu, 0.2 pu, and 0.1 pu, respectively. The generator is on open circuit with a terminal voltage of 1 pu. The minimum value of the inductive reactance, in pu, required to be connected between neutral and ground so that the fault current does not exceed 3.75 pu if a single line to ground fault occurs at the terminals is (Assume fault impedance to be zero). (Give the answer up to one decimal place) [Ans. *] ange: 0.1 to 0.1 X j X j X j X (zero fault reactance) : , info@thegateacademy.com Copyright reserved. Web: 34

35 X? L G Fault Z Z Z Z Z Z Z Z Z Z Z Z pu 47. The logical gate implemented using the circuit shown below where and are inputs (with 0 as digital 0 and 5 as digital 1) and is the output is k Q k k Q (A) NOT (B) NO (C) NAND (D) XO [Ans. B] 0 0 OFF OFF OFF ON ON 0FF ON ON 0 t is a NO gate 48. A 220 DC series motor runs drawing a current of 30 A from the supply. Armature and field circuit resistances are and respectively. The load torque varies as the square of the speed. The flux in the motor may be taken as being proportional to the armature current. To reduce the speed of the motor by 50% the resistance in ohms that should be added in series with the armature is. (Give the answer up to two decimal places) [Ans. *] ange: 9.5 to 12 Given a DC series motor Before adding extra resistor : , info@thegateacademy.com Copyright reserved. Web: 35

36 ( ) ( )( ) After adding extra resistor speed reduced by 50% T N N N T ( N ) T N T ( ) T T T T Ka a a T a T ( ) T a a a a a (r r r ) ( r ) N N ( ) ( N ) N olts eplace in equation ( )( r ) r 49. Only one of the real roots of f(x) x x lies in the interval x and bisection method is used to find its value. For achieving an accuracy of 0.001, the required minimum number of iterations is. [Ans. *] ange: 10 to 10 b a f(x) x x in ]we know that ln ln( ) n ln ln( ) n ln( ) ln : , info@thegateacademy.com Copyright reserved. Web: 36

37 n n 50. n the system whose signal flow graph is shown in the figure. U (s) and U (s) are inputs. The transfer function ( ) ( ) is U U L s k J s Y k k ( ) JLs Js k k k (B) JLs Js k k k U ( sl) ( ) JLs (J U L)s k k U k U (sl ) ( ) JLs (J U L)s k k U [Ans. A] Y(s) U (S) K *( ) ( ) (K ) ( ) ( ) ( K ) * K JLs JS K K 51. A three-phase, three winding Y (1.1 k/6.6 k/400 ) transformer is energized from AC mains at the 1.1 k side. t Supplies 900 ka load at 0.8 power factor lag from the 6.6 k winding and 300 ka load at 0.6 power factor lag from the 400 winding. The MS line current in ampere drawn by the 1.1 k winding from the mains is. [Ans. *] ange: 623 to 627 Given transformer is Y Wdg( ) Wdg( ) Wdg( ) Y k k By applying superposition theorem (a) Load on k ( ) side is k Pf lag (load) ph ph : , info@thegateacademy.com Copyright reserved. Web: 37

38 The current on k side will be (source) ( ) ph (b) Load on (Y) is k pf lag ph ph The current of source side ( k) will be (source) ] ph Total source phase current will be ph Pf lag ph The line current will be 52. A load is supplied by a 230, 50 Hz source. The active power P and the reactive power Q consumed by the load are such that kw P kw and k k. A capacitor connected across the load for power factor correction generates 1 ka reactive power. The worst case power factor after power factor correction is (A) lag (B) lag (C) lag (D) 1 [Ans. B] Worst power factor corresponding to P and Q P kw Q K Q K P kw Q K Power Factor cos [tan ( Q )] lag P 53. Let a causal LT system be characterized by the following differential equation, with initial rest condition : , info@thegateacademy.com Copyright reserved. Web: 38

39 d y dt dy dt y(t) dx(t) x(t) dt Where, x(t) and y(t) are the input and output respectively. The impulse response of the system is (u(t) is the unit step function) ( ) e u(t) e u(t) (B) e u(t) e u(t) ( ) e u(t) e u(t) ( ) e u(t) e u(t) [Ans. B] Taking the Laplace transform Y(s) s TF X(s) s s s (s )(s ) s s L TF] e u(t) e u(t) 54. The switch in the figure below was closed for a long time. t is opened at t = 0. The current in the inductor of 2 H for t, is H (A) e (B) e (C) e (D) e [Ans. A] This is source free, first order -L circuit i(t) e t i( ) L eq : , info@thegateacademy.com Copyright reserved. Web: 39

40 i(t) i(t) e e L 55. The figure shows the single line diagram of a power system with a double circuit transmission line. The expression for electrical power is sin where is the rotor angle. The system is operating at the stable equilibrium point with mechanical power equal to 1 pu. f one of the transmission line circuits is removed, the maximum value of, as the rotor swings is radian. f the expression for electrical power with one transmission line circuit removed is P sin the value of P in pu is. [Ans. *] ange: 1.21 to 1.23 With two lines P P P sin sin ( P ) sin ( ) P m rad rad Pe a X X X b X (P P )d (P P )d : , info@thegateacademy.com Copyright reserved. Web: 40

41 [P P cos ] [P P cos ] P Ps P cos P cos P Ps P cos Pm cos P ( ) P (cos cos ) P P ( ) P (cos cos ) P ( ) : , info@thegateacademy.com Copyright reserved. Web: 41

: 2 : EE GATE 2017 SOLUTIONS

: 2 : EE GATE 2017 SOLUTIONS : : EE GATE 7 SOLUTIONS. The following measurements are obtained on a single phase load: V = V %. I = 5. A % and W = 555 W %. If the power factor is calculated using these measurements, the worst case

More information

EE Branch GATE Paper 2010

EE Branch GATE Paper 2010 Q.1 Q.25 carry one mark each 1. The value of the quantity P, where, is equal to 0 1 e 1/e 2. Divergence of the three-dimensional radial vector field is 3 1/r 3. The period of the signal x(t) = 8 is 0.4

More information

GATE 2010 Electrical Engineering

GATE 2010 Electrical Engineering GATE 2010 Electrical Engineering Q.1 Q.25 carry one mark each 1. The value of the quantity P, where P = xe dx, is equal to (A) 0 (B) 1 (C) e (D) 1/e 2. Divergence of the three-dimensional radial vector

More information

Q. 1 Q. 5 carry one mark each.

Q. 1 Q. 5 carry one mark each. GATE 2019 General Aptitude (GA) Set-3 Q. 1 Q. 5 carry one mark each. Q.1 I am not sure if the bus that has been booked will be able to all the students. (A) sit (B) deteriorate (C) fill (D) accommodate

More information

ELECTRICAL ENGINEERING

ELECTRICAL ENGINEERING ELECTRICAL ENGINEERING Subject Code: EE Course Structure Sections/Units Section A Unit 1 Unit 2 Unit 3 Unit 4 Unit 5 Unit 6 Unit 7 Section B Section C Section D Section E Section F Section G Section H

More information

GATE Question Paper & Answer Keys

GATE Question Paper & Answer Keys Question Paper & Answer Keys Index 1 Question Paper Analysis 2 Question Paper & Answer keys : 080-617 66 222, info@thegateacademycom Copyright reserved Web:wwwthegateacademycom ANALSIS OF GATE 2010 Electrical

More information

GATE : , Copyright reserved. Web:www.thegateacademy.com

GATE : , Copyright reserved. Web:www.thegateacademy.com GATE-2016 Index 1. Question Paper Analysis 2. Question Paper & Answer keys : 080-617 66 222, info@thegateacademy.com Copyright reserved. Web:www.thegateacademy.com ANALYSIS OF GATE 2016 Electrical Engineering

More information

GATE 2008 Electrical Engineering

GATE 2008 Electrical Engineering GATE 2008 Electrical Engineering Q.1 Q. 20 carry one mark each. 1. The number of chords in the graph of the given circuit will be + _ (A) 3 (B) 4 (C) 5 (D) 6 2. The Thevenin'a equivalent of a circuit operating

More information

Q. 1 Q. 25 carry one mark each.

Q. 1 Q. 25 carry one mark each. GATE 5 SET- ELECTRONICS AND COMMUNICATION ENGINEERING - EC Q. Q. 5 carry one mark each. Q. The bilateral Laplace transform of a function is if a t b f() t = otherwise (A) a b s (B) s e ( a b) s (C) e as

More information

GATE : , Copyright reserved. Web:www.thegateacademy.com

GATE : , Copyright reserved. Web:www.thegateacademy.com Index. Question Paper Analysis 2. Question Paper & Answer keys : 080-67 66 222, info@thegateacademy.com Copyright reserved. Web:www.thegateacademy.com ANALYSIS OF GATE 206 Electrical Engineering CN Mathematics

More information

Chapter 3 AUTOMATIC VOLTAGE CONTROL

Chapter 3 AUTOMATIC VOLTAGE CONTROL Chapter 3 AUTOMATIC VOLTAGE CONTROL . INTRODUCTION TO EXCITATION SYSTEM The basic function of an excitation system is to provide direct current to the field winding of the synchronous generator. The excitation

More information

Q. 1 Q. 5 carry one mark each.

Q. 1 Q. 5 carry one mark each. GATE 2016 General Aptitude - GA Set-6 Q. 1 Q. 5 carry one mark each. Q.1 The man who is now Municipal Commissioner worked as. (A) the security guard at a university (B) a security guard at the university

More information

GATEFORUM- India s No.1 institute for GATE training 1

GATEFORUM- India s No.1 institute for GATE training 1 EE-GATE-03 PAPER Q. No. 5 Carry One Mark Each. Given a vector field F = y xax yzay = x a z, the line integral F.dl evaluated along a segment on the x-axis from x= to x= is -.33 (B) 0.33 (D) 7 : (B) x 0.

More information

+ ( )= with initial condition

+ ( )= with initial condition Department of Electrical Engineering PhD. Admission Test Full Marks: 90 Time 90 minutes Date: 02.2.204 NAME: Appl. No: Write your answer on the question paper ONLY. All questions carry equal marks. PART

More information

ELECTRIC POWER CIRCUITS BASIC CONCEPTS AND ANALYSIS

ELECTRIC POWER CIRCUITS BASIC CONCEPTS AND ANALYSIS Contents ELEC46 Power ystem Analysis Lecture ELECTRC POWER CRCUT BAC CONCEPT AND ANALY. Circuit analysis. Phasors. Power in single phase circuits 4. Three phase () circuits 5. Power in circuits 6. ingle

More information

LO 1: Three Phase Circuits

LO 1: Three Phase Circuits Course: EEL 2043 Principles of Electric Machines Class Instructor: Dr. Haris M. Khalid Email: hkhalid@hct.ac.ae Webpage: www.harismkhalid.com LO 1: Three Phase Circuits Three Phase AC System Three phase

More information

Conventional Paper-I-2011 PART-A

Conventional Paper-I-2011 PART-A Conventional Paper-I-0 PART-A.a Give five properties of static magnetic field intensity. What are the different methods by which it can be calculated? Write a Maxwell s equation relating this in integral

More information

Q. 1 Q. 25 carry one mark each.

Q. 1 Q. 25 carry one mark each. Q. 1 Q. 25 carry one mark each. Q.1 Given ff(zz) = gg(zz) + h(zz), where ff, gg, h are complex valued functions of a complex variable zz. Which one of the following statements is TUE? (A) If ff(zz) is

More information

SECTION - A. A current impulse, 5δ(t), is forced through a capacitor C. The voltage, Vc(t), across the capacitor is given by. 5 t C.

SECTION - A. A current impulse, 5δ(t), is forced through a capacitor C. The voltage, Vc(t), across the capacitor is given by. 5 t C. SETION - A. This question consists of TWENTY-FIVE sub-questions (..5) of ONE mark each. For each of these sub-questions, four possible alternatives (A,B, and D) are given, out of which ONLY ONE is correct.

More information

Conventional Paper-I Part A. 1. (a) Define intrinsic wave impedance for a medium and derive the equation for intrinsic vy

Conventional Paper-I Part A. 1. (a) Define intrinsic wave impedance for a medium and derive the equation for intrinsic vy EE-Conventional Paper-I IES-01 www.gateforum.com Conventional Paper-I-01 Part A 1. (a) Define intrinsic wave impedance for a medium and derive the equation for intrinsic vy impedance for a lossy dielectric

More information

ELECTROMAGNETIC OSCILLATIONS AND ALTERNATING CURRENT

ELECTROMAGNETIC OSCILLATIONS AND ALTERNATING CURRENT Chapter 31: ELECTROMAGNETIC OSCILLATIONS AND ALTERNATING CURRENT 1 A charged capacitor and an inductor are connected in series At time t = 0 the current is zero, but the capacitor is charged If T is the

More information

Transformer. Transformer comprises two or more windings coupled by a common magnetic circuit (M.C.).

Transformer. Transformer comprises two or more windings coupled by a common magnetic circuit (M.C.). . Transformers Transformer Transformer comprises two or more windings coupled by a common magnetic circuit (M.C.). f the primary side is connected to an AC voltage source v (t), an AC flux (t) will be

More information

GATE ELECTRICAL ENGINEERING Vol 1 of 4

GATE ELECTRICAL ENGINEERING Vol 1 of 4 GATE ELECTRICAL ENGINEERING Vol 1 of 4 Second Edition GATE ELECTRICAL ENGINEERING Vol 1 of 4 RK Kanodia Ashish Murolia NODIA & COMPANY GATE Electrical Engineering Vol 1, 2e RK Kanodia & Ashish Murolia

More information

SEM-2016(02)-I ELECTRICAL ENGINEERING. Paper -1. Please read the following instructions carefully before attempting questions.

SEM-2016(02)-I ELECTRICAL ENGINEERING. Paper -1. Please read the following instructions carefully before attempting questions. Roll No. Candidate should write his/her Roll No. here. Total No. of Questions : 7 No. of Printed Pages : 8 SEM-2016(02)-I ELECTRICAL ENGINEERING Paper -1 Time : 3 Hours ] [ Total Marks ; 300 Instructions

More information

Q. 1 Q. 5 carry one mark each.

Q. 1 Q. 5 carry one mark each. GATE 08 General Aptitude (GA) Set6 Q. Q. 5 carry one mark each. Q. Since you have gone off the, the sand is likely to damage the car. The words that best fill the blanks in the above sentence are (A) course,

More information

GATE Question Paper & Answer Keys

GATE Question Paper & Answer Keys Question Paper & Answer Keys Index. Question Paper Analysis 2. Question Paper & Answer keys : 8-67 66 222, info@thegateacademy.com Copyright reserved. Web:www.thegateacademy.com ANALYSIS OF GATE 24 Electrical

More information

Introduction to Synchronous. Machines. Kevin Gaughan

Introduction to Synchronous. Machines. Kevin Gaughan Introduction to Synchronous Machines Kevin Gaughan The Synchronous Machine An AC machine (generator or motor) with a stator winding (usually 3 phase) generating a rotating magnetic field and a rotor carrying

More information

Total No. of Questions :09] [Total No. of Pages : 03

Total No. of Questions :09] [Total No. of Pages : 03 EE 4 (RR) Total No. of Questions :09] [Total No. of Pages : 03 II/IV B.Tech. DEGREE EXAMINATIONS, APRIL/MAY- 016 Second Semester ELECTRICAL & ELECTRONICS NETWORK ANALYSIS Time: Three Hours Answer Question

More information

SECOND ENGINEER REG III/2 MARINE ELECTRO-TECHNOLOGY. 1. Understands the physical construction and characteristics of basic components.

SECOND ENGINEER REG III/2 MARINE ELECTRO-TECHNOLOGY. 1. Understands the physical construction and characteristics of basic components. SECOND ENGINEER REG III/ MARINE ELECTRO-TECHNOLOGY LIST OF TOPICS A B C D Electric and Electronic Components Electric Circuit Principles Electromagnetism Electrical Machines The expected learning outcome

More information

GATE 2012 Electrical Engineering Set - B

GATE 2012 Electrical Engineering Set - B GATE 2012 Electrical Engineering Set - B Q.1 Q.25 carry one mark each. 1. For the circuit shown in the figure, the voltage and current expressions are v(t) = and. The average power measured by the Wattmeter

More information

Synchronous Machines

Synchronous Machines Synchronous Machines Synchronous generators or alternators are used to convert mechanical power derived from steam, gas, or hydraulic-turbine to ac electric power Synchronous generators are the primary

More information

Basics of Network Theory (Part-I)

Basics of Network Theory (Part-I) Basics of Network Theory (PartI). A square waveform as shown in figure is applied across mh ideal inductor. The current through the inductor is a. wave of peak amplitude. V 0 0.5 t (m sec) [Gate 987: Marks]

More information

SSC-JE EE POWER SYSTEMS: GENERATION, TRANSMISSION & DISTRIBUTION SSC-JE STAFF SELECTION COMMISSION ELECTRICAL ENGINEERING STUDY MATERIAL

SSC-JE EE POWER SYSTEMS: GENERATION, TRANSMISSION & DISTRIBUTION SSC-JE STAFF SELECTION COMMISSION ELECTRICAL ENGINEERING STUDY MATERIAL 1 SSC-JE STAFF SELECTION COMMISSION ELECTRICAL ENGINEERING STUDY MATERIAL Power Systems: Generation, Transmission and Distribution Power Systems: Generation, Transmission and Distribution Power Systems:

More information

a. Type 0 system. b. Type I system. c. Type 2 system. d. Type 3 system.

a. Type 0 system. b. Type I system. c. Type 2 system. d. Type 3 system. 1-The steady-state error of a feedback control system with an acceleration input becomes finite in a a. Type 0 system. b. Type I system. c. Type 2 system. d. Type 3 system. 2-A good control system has

More information

INSTRUMENTAL ENGINEERING

INSTRUMENTAL ENGINEERING INSTRUMENTAL ENGINEERING Subject Code: IN Course Structure Sections/Units Section A Unit 1 Unit 2 Unit 3 Unit 4 Unit 5 Unit 6 Section B Section C Section D Section E Section F Section G Section H Section

More information

Power and Energy Measurement

Power and Energy Measurement Power and Energy Measurement EIE 240 Electrical and Electronic Measurement April 24, 2015 1 Work, Energy and Power Work is an activity of force and movement in the direction of force (Joules) Energy is

More information

Q. 1 Q. 25 carry one mark each.

Q. 1 Q. 25 carry one mark each. Q. Q. 5 carry one mark each. Q. Consider a system of linear equations: x y 3z =, x 3y 4z =, and x 4y 6 z = k. The value of k for which the system has infinitely many solutions is. Q. A function 3 = is

More information

SECTION 3 BASIC AUTOMATIC CONTROLS UNIT 12 BASIC ELECTRICITY AND MAGNETISM

SECTION 3 BASIC AUTOMATIC CONTROLS UNIT 12 BASIC ELECTRICITY AND MAGNETISM SECTION 3 BASIC AUTOMATIC CONTROLS UNIT 12 BASIC ELECTRICITY AND MAGNETISM Unit Objectives Describe the structure of an atom. Identify atoms with a positive charge and atoms with a negative charge. Explain

More information

Solved Problems. Electric Circuits & Components. 1-1 Write the KVL equation for the circuit shown.

Solved Problems. Electric Circuits & Components. 1-1 Write the KVL equation for the circuit shown. Solved Problems Electric Circuits & Components 1-1 Write the KVL equation for the circuit shown. 1-2 Write the KCL equation for the principal node shown. 1-2A In the DC circuit given in Fig. 1, find (i)

More information

fusion production of elements in stars, 345

fusion production of elements in stars, 345 I N D E X AC circuits capacitive reactance, 278 circuit frequency, 267 from wall socket, 269 fundamentals of, 267 impedance in general, 283 peak to peak voltage, 268 phase shift in RC circuit, 280-281

More information

Q. No. 5 Carry One Mark Each GATE question papers: Electrical Engineering 00 (EE) Published by:. The value of the quantity P, where P = xe x dx, is equal to o 0 e /e. Divergence of the threedimensional

More information

Electronics and Communication Exercise 1

Electronics and Communication Exercise 1 Electronics and Communication Exercise 1 1. For matrices of same dimension M, N and scalar c, which one of these properties DOES NOT ALWAYS hold? (A) (M T ) T = M (C) (M + N) T = M T + N T (B) (cm)+ =

More information

KINGS COLLEGE OF ENGINEERING Punalkulam

KINGS COLLEGE OF ENGINEERING Punalkulam KINGS COLLEGE OF ENGINEERING Punalkulam 613 303 DEPARTMENT OF ELECTRICAL AND ELECTRONICS ENGINEERING POWER SYSTEM ANALYSIS QUESTION BANK UNIT I THE POWER SYSTEM AN OVERVIEW AND MODELLING PART A (TWO MARK

More information

Work, Energy and Power

Work, Energy and Power 1 Work, Energy and Power Work is an activity of force and movement in the direction of force (Joules) Energy is the capacity for doing work (Joules) Power is the rate of using energy (Watt) P = W / t,

More information

Module 7. Transformer. Version 2 EE IIT, Kharagpur

Module 7. Transformer. Version 2 EE IIT, Kharagpur Module 7 Transformer ersion EE T, Kharagpur Lesson 5 Testing, Efficiency & Regulation ersion EE T, Kharagpur Contents 5 Testing, Efficiency & regulation 4 5. Goals of the lesson.. 4 5. Determination of

More information

Basics of Electric Circuits

Basics of Electric Circuits António Dente Célia de Jesus February 2014 1 Alternating Current Circuits 1.1 Using Phasors There are practical and economic reasons justifying that electrical generators produce emf with alternating and

More information

ONE MARK QUESTIONS. 1. The condition on R, L and C such that the step response y(t) in the figure has no oscillations, is

ONE MARK QUESTIONS. 1. The condition on R, L and C such that the step response y(t) in the figure has no oscillations, is ELECTRONICS & COMMUNICATION ENGINEERING ONE MARK QUESTIONS. The condition on R, L and C such that the step response y(t) in the figure has no oscillations, is (a.) R L C (b.) R L C (c.) R L C (d.) R LC

More information

Review of Basic Electrical and Magnetic Circuit Concepts EE

Review of Basic Electrical and Magnetic Circuit Concepts EE Review of Basic Electrical and Magnetic Circuit Concepts EE 442-642 Sinusoidal Linear Circuits: Instantaneous voltage, current and power, rms values Average (real) power, reactive power, apparent power,

More information

Massachusetts Institute of Technology Department of Electrical Engineering and Computer Science Electric Machines

Massachusetts Institute of Technology Department of Electrical Engineering and Computer Science Electric Machines Massachusetts Institute of Technology Department of Electrical Engineering and Computer Science 6.685 Electric Machines Problem Set 10 Issued November 11, 2013 Due November 20, 2013 Problem 1: Permanent

More information

Lecture (5) Power Factor,threephase circuits, and Per Unit Calculations

Lecture (5) Power Factor,threephase circuits, and Per Unit Calculations Lecture (5) Power Factor,threephase circuits, and Per Unit Calculations 5-1 Repeating the Example on Power Factor Correction (Given last Class) P? Q? S? Light Motor From source 1000 volts @ 60 Htz 10kW

More information

Lecture 11 - AC Power

Lecture 11 - AC Power - AC Power 11/17/2015 Reading: Chapter 11 1 Outline Instantaneous power Complex power Average (real) power Reactive power Apparent power Maximum power transfer Power factor correction 2 Power in AC Circuits

More information

mywbut.com Lesson 16 Solution of Current in AC Parallel and Seriesparallel

mywbut.com Lesson 16 Solution of Current in AC Parallel and Seriesparallel esson 6 Solution of urrent in Parallel and Seriesparallel ircuits n the last lesson, the following points were described:. How to compute the total impedance/admittance in series/parallel circuits?. How

More information

SYLLABI FOR THE WRITTEN TEST

SYLLABI FOR THE WRITTEN TEST G u w ahat i, A ssa m, I ND IA PI N - - 781039 PHONE: 91-361- 2582550 FAX: 91-361- 2582542 D epa rt m en t o f E l ec tr on i c s & E l ec tri ca l Eng i nee ri n g IIT GUWAHATI SYLLABI FOR THE WRITTEN

More information

E40M Review - Part 1

E40M Review - Part 1 E40M Review Part 1 Topics in Part 1 (Today): KCL, KVL, Power Devices: V and I sources, R Nodal Analysis. Superposition Devices: Diodes, C, L Time Domain Diode, C, L Circuits Topics in Part 2 (Wed): MOSFETs,

More information

Power System Analysis Prof. A. K. Sinha Department of Electrical Engineering Indian Institute of Technology, Kharagpur

Power System Analysis Prof. A. K. Sinha Department of Electrical Engineering Indian Institute of Technology, Kharagpur Power System Analysis Prof. A. K. Sinha Department of Electrical Engineering Indian Institute of Technology, Kharagpur Lecture - 9 Transmission Line Steady State Operation Welcome to lesson 9, in Power

More information

Power Factor Improvement

Power Factor Improvement Salman bin AbdulazizUniversity College of Engineering Electrical Engineering Department EE 2050Electrical Circuit Laboratory Power Factor Improvement Experiment # 4 Objectives: 1. To introduce the concept

More information

EE 6501 POWER SYSTEMS UNIT I INTRODUCTION

EE 6501 POWER SYSTEMS UNIT I INTRODUCTION EE 6501 POWER SYSTEMS UNIT I INTRODUCTION PART A (2 MARKS) 1. What is single line diagram? A Single line diagram is diagrammatic representation of power system in which the components are represented by

More information

Engineering Fundamentals Exam. Study Guide For Electrical Engineering Exam

Engineering Fundamentals Exam. Study Guide For Electrical Engineering Exam Engineering Fundamentals Exam Study Guide For Electrical Engineering Exam COPYRIGHT NOTICE Copyrights 2014 National Center for Assessment in Higher Education (QIYAS) and Saudi Council of Engineers (SCE)

More information

Electric Machines I Three Phase Induction Motor. Dr. Firas Obeidat

Electric Machines I Three Phase Induction Motor. Dr. Firas Obeidat Electric Machines I Three Phase Induction Motor Dr. Firas Obeidat 1 Table of contents 1 General Principles 2 Construction 3 Production of Rotating Field 4 Why Does the Rotor Rotate 5 The Slip and Rotor

More information

GATE 2017 ECE Session 3 Answer Key

GATE 2017 ECE Session 3 Answer Key 1. Three pair cubical dice are thrown simultaneously. What is the probability that all three dice have same number is... Ans. ( 1 36 ). The one of the eigen value is real, rest are imaginary the real value

More information

The simplest type of alternating current is one which varies with time simple harmonically. It is represented by

The simplest type of alternating current is one which varies with time simple harmonically. It is represented by ALTERNATING CURRENTS. Alternating Current and Alternating EMF An alternating current is one whose magnitude changes continuously with time between zero and a maximum value and whose direction reverses

More information

EEE3405 ELECTRICAL ENGINEERING PRINCIPLES 2 - TEST

EEE3405 ELECTRICAL ENGINEERING PRINCIPLES 2 - TEST ATTEMPT ALL QUESTIONS (EACH QUESTION 20 Marks, FULL MAKS = 60) Given v 1 = 100 sin(100πt+π/6) (i) Find the MS, period and the frequency of v 1 (ii) If v 2 =75sin(100πt-π/10) find V 1, V 2, 2V 1 -V 2 (phasor)

More information

Module 4. Single-phase AC circuits. Version 2 EE IIT, Kharagpur

Module 4. Single-phase AC circuits. Version 2 EE IIT, Kharagpur Module 4 Single-phase circuits ersion EE T, Kharagpur esson 6 Solution of urrent in Parallel and Seriesparallel ircuits ersion EE T, Kharagpur n the last lesson, the following points were described:. How

More information

Module 3 : Sequence Components and Fault Analysis

Module 3 : Sequence Components and Fault Analysis Module 3 : Sequence Components and Fault Analysis Lecture 12 : Sequence Modeling of Power Apparatus Objectives In this lecture we will discuss Per unit calculation and its advantages. Modeling aspects

More information

R. W. Erickson. Department of Electrical, Computer, and Energy Engineering University of Colorado, Boulder

R. W. Erickson. Department of Electrical, Computer, and Energy Engineering University of Colorado, Boulder . W. Erickson Department of Electrical, Computer, and Energy Engineering University of Colorado, Boulder 2.4 Cuk converter example L 1 C 1 L 2 Cuk converter, with ideal switch i 1 i v 1 2 1 2 C 2 v 2 Cuk

More information

Chapter 3. Steady-State Equivalent Circuit Modeling, Losses, and Efficiency

Chapter 3. Steady-State Equivalent Circuit Modeling, Losses, and Efficiency Chapter 3. Steady-State Equivalent Circuit Modeling, Losses, and Efficiency 3.1. The dc transformer model 3.2. Inclusion of inductor copper loss 3.3. Construction of equivalent circuit model 3.4. How to

More information

Magnetic Force on a Moving Charge

Magnetic Force on a Moving Charge Magnetic Force on a Moving Charge Electric charges moving in a magnetic field experience a force due to the magnetic field. Given a charge Q moving with velocity u in a magnetic flux density B, the vector

More information

B.E. / B.Tech. Degree Examination, April / May 2010 Sixth Semester. Electrical and Electronics Engineering. EE 1352 Power System Analysis

B.E. / B.Tech. Degree Examination, April / May 2010 Sixth Semester. Electrical and Electronics Engineering. EE 1352 Power System Analysis B.E. / B.Tech. Degree Examination, April / May 2010 Sixth Semester Electrical and Electronics Engineering EE 1352 Power System Analysis (Regulation 2008) Time: Three hours Answer all questions Part A (10

More information

3 d Calculate the product of the motor constant and the pole flux KΦ in this operating point. 2 e Calculate the torque.

3 d Calculate the product of the motor constant and the pole flux KΦ in this operating point. 2 e Calculate the torque. Exam Electrical Machines and Drives (ET4117) 11 November 011 from 14.00 to 17.00. This exam consists of 5 problems on 4 pages. Page 5 can be used to answer problem 4 question b. The number before a question

More information

ANALYSIS OF GATE 2018* (Memory Based) Electronics and Communication Engineering

ANALYSIS OF GATE 2018* (Memory Based) Electronics and Communication Engineering ANALYSS OF GATE 2018* (Memory Based) Electronics and Communication Engineering Electromagnetic Theory 8% Electronic Device Circuits 12% General Aptitude 15% Engineering Mathematics 14% Network Theory 7%

More information

ECE 420. Review of Three Phase Circuits. Copyright by Chanan Singh, Panida Jirutitijaroen, and Hangtian Lei, For educational use only-not for sale.

ECE 420. Review of Three Phase Circuits. Copyright by Chanan Singh, Panida Jirutitijaroen, and Hangtian Lei, For educational use only-not for sale. ECE 40 Review of Three Phase Circuits Outline Phasor Complex power Power factor Balanced 3Ф circuit Read Appendix A Phasors and in steady state are sinusoidal functions with constant frequency 5 0 15 10

More information

Chapter 32A AC Circuits. A PowerPoint Presentation by Paul E. Tippens, Professor of Physics Southern Polytechnic State University

Chapter 32A AC Circuits. A PowerPoint Presentation by Paul E. Tippens, Professor of Physics Southern Polytechnic State University Chapter 32A AC Circuits A PowerPoint Presentation by Paul E. Tippens, Professor of Physics Southern Polytechnic State University 2007 Objectives: After completing this module, you should be able to: Describe

More information

EE2351 POWER SYSTEM OPERATION AND CONTROL UNIT I THE POWER SYSTEM AN OVERVIEW AND MODELLING PART A

EE2351 POWER SYSTEM OPERATION AND CONTROL UNIT I THE POWER SYSTEM AN OVERVIEW AND MODELLING PART A EE2351 POWER SYSTEM OPERATION AND CONTROL UNIT I THE POWER SYSTEM AN OVERVIEW AND MODELLING PART A 1. What are the advantages of an inter connected system? The advantages of an inter-connected system are

More information

ECE Branch GATE Paper The order of the differential equation + + = is (A) 1 (B) 2

ECE Branch GATE Paper The order of the differential equation + + = is (A) 1 (B) 2 Question 1 Question 20 carry one mark each. 1. The order of the differential equation + + = is (A) 1 (B) 2 (C) 3 (D) 4 2. The Fourier series of a real periodic function has only P. Cosine terms if it is

More information

Basic Electronics. Introductory Lecture Course for. Technology and Instrumentation in Particle Physics Chicago, Illinois June 9-14, 2011

Basic Electronics. Introductory Lecture Course for. Technology and Instrumentation in Particle Physics Chicago, Illinois June 9-14, 2011 Basic Electronics Introductory Lecture Course for Technology and Instrumentation in Particle Physics 2011 Chicago, Illinois June 9-14, 2011 Presented By Gary Drake Argonne National Laboratory drake@anl.gov

More information

Chapter 1W Basic Electromagnetic Concepts

Chapter 1W Basic Electromagnetic Concepts Chapter 1W Basic Electromagnetic Concepts 1W Basic Electromagnetic Concepts 1W.1 Examples and Problems on Electric Circuits 1W.2 Examples on Magnetic Concepts This chapter includes additional examples

More information

11. AC Circuit Power Analysis

11. AC Circuit Power Analysis . AC Circuit Power Analysis Often an integral part of circuit analysis is the determination of either power delivered or power absorbed (or both). In this chapter First, we begin by considering instantaneous

More information

Sinusoidal Response of RLC Circuits

Sinusoidal Response of RLC Circuits Sinusoidal Response of RLC Circuits Series RL circuit Series RC circuit Series RLC circuit Parallel RL circuit Parallel RC circuit R-L Series Circuit R-L Series Circuit R-L Series Circuit Instantaneous

More information

EE 212 PASSIVE AC CIRCUITS

EE 212 PASSIVE AC CIRCUITS EE 212 PASSIVE AC CIRCUITS Condensed Text Prepared by: Rajesh Karki, Ph.D., P.Eng. Dept. of Electrical Engineering University of Saskatchewan About the EE 212 Condensed Text The major topics in the course

More information

Power and Energy Measurement

Power and Energy Measurement Power and Energy Measurement ENE 240 Electrical and Electronic Measurement Class 11, February 4, 2009 werapon.chi@kmutt.ac.th 1 Work, Energy and Power Work is an activity of force and movement in the direction

More information

GATE 2007 Electrical Engineering

GATE 2007 Electrical Engineering Q.1 Q. 20 carry one mark each GATE 2007 Electrical Engineering 1. The common emitter forward current gain of the transistor shown is β F = 100. 10V 1kΩ 270kΩ 1kΩ The transistor is operating in (A) Saturation

More information

Notes on Electric Circuits (Dr. Ramakant Srivastava)

Notes on Electric Circuits (Dr. Ramakant Srivastava) Notes on Electric ircuits (Dr. Ramakant Srivastava) Passive Sign onvention (PS) Passive sign convention deals with the designation of the polarity of the voltage and the direction of the current arrow

More information

SE]y[-2017(02)-I ELECTRICAL ENGINEERING. Paper. Please read each of the following instructions carefully before attempting questions.

SE]y[-2017(02)-I ELECTRICAL ENGINEERING. Paper. Please read each of the following instructions carefully before attempting questions. RoU No. 300218 Candidate should write his/her Roll No. here. Total No. of Questions : 7 No. of Printed Pages : 7 SE]y[-2017(02)-I ELECTRICAL ENGINEERING Paper Time : 3 Hours ] [ Total Marks : 300 Instructions

More information

Control of Wind Turbine Generators. James Cale Guest Lecturer EE 566, Fall Semester 2014 Colorado State University

Control of Wind Turbine Generators. James Cale Guest Lecturer EE 566, Fall Semester 2014 Colorado State University Control of Wind Turbine Generators James Cale Guest Lecturer EE 566, Fall Semester 2014 Colorado State University Review from Day 1 Review Last time, we started with basic concepts from physics such as

More information

Ver 3537 E1.1 Analysis of Circuits (2014) E1.1 Circuit Analysis. Problem Sheet 1 (Lectures 1 & 2)

Ver 3537 E1.1 Analysis of Circuits (2014) E1.1 Circuit Analysis. Problem Sheet 1 (Lectures 1 & 2) Ver 3537 E. Analysis of Circuits () Key: [A]= easy... [E]=hard E. Circuit Analysis Problem Sheet (Lectures & ). [A] One of the following circuits is a series circuit and the other is a parallel circuit.

More information

Gen. Phys. II Exam 2 - Chs. 21,22,23 - Circuits, Magnetism, EM Induction Mar. 5, 2018

Gen. Phys. II Exam 2 - Chs. 21,22,23 - Circuits, Magnetism, EM Induction Mar. 5, 2018 Gen. Phys. II Exam 2 - Chs. 21,22,23 - Circuits, Magnetism, EM Induction Mar. 5, 2018 Rec. Time Name For full credit, make your work clear. Show formulas used, essential steps, and results with correct

More information

Lesson 17: Synchronous Machines

Lesson 17: Synchronous Machines Lesson 17: Synchronous Machines ET 332b Ac Motors, Generators and Power Systems Lesson 17_et332b.pptx 1 Learning Objectives After this presentation you will be able to: Explain how synchronous machines

More information

Conventional Paper I-2010

Conventional Paper I-2010 Conventional Paper I-010 1. (a) Sketch the covalent bonding of Si atoms in a intrinsic Si crystal Illustrate with sketches the formation of bonding in presence of donor and acceptor atoms. Sketch the energy

More information

ROEVER COLLEGE OF ENGINEERING & TECHNOLOGY ELAMBALUR, PERAMBALUR DEPARTMENT OF ELECTRICAL AND ELECTRONICS ENGINEERING ELECTRICAL MACHINES I

ROEVER COLLEGE OF ENGINEERING & TECHNOLOGY ELAMBALUR, PERAMBALUR DEPARTMENT OF ELECTRICAL AND ELECTRONICS ENGINEERING ELECTRICAL MACHINES I ROEVER COLLEGE OF ENGINEERING & TECHNOLOGY ELAMBALUR, PERAMBALUR-621220 DEPARTMENT OF ELECTRICAL AND ELECTRONICS ENGINEERING ELECTRICAL MACHINES I Unit I Introduction 1. What are the three basic types

More information

GATE 20 Years. Contents. Chapters Topics Page No.

GATE 20 Years. Contents. Chapters Topics Page No. GATE 0 Years Contents Chapters Topics Page No. Chapter- Chapter- Chapter- Chapter-4 Chapter-5 GATE Syllabus for this Chapter Topic elated to Syllabus Previous 0-Years GATE Questions Previous 0-Years GATE

More information

GATE-2015 ELECTRICAL ENGG 7th February 2015 Forenoon Session

GATE-2015 ELECTRICAL ENGG 7th February 2015 Forenoon Session Page Section - I (General Aptitude) Q. Which one of the following combinations is incorrect? Acquiescence - Submission Wheedle - Roundabout Flippancy - Lightness Profligate - Extravagant Q. Didn t you

More information

Physics 142 AC Circuits Page 1. AC Circuits. I ve had a perfectly lovely evening but this wasn t it. Groucho Marx

Physics 142 AC Circuits Page 1. AC Circuits. I ve had a perfectly lovely evening but this wasn t it. Groucho Marx Physics 142 A ircuits Page 1 A ircuits I ve had a perfectly lovely evening but this wasn t it. Groucho Marx Alternating current: generators and values It is relatively easy to devise a source (a generator

More information

THE UNIVERSITY OF NEW SOUTH WALES. School of Electrical Engineering & Telecommunications FINALEXAMINATION. Session

THE UNIVERSITY OF NEW SOUTH WALES. School of Electrical Engineering & Telecommunications FINALEXAMINATION. Session Name: Student ID: Signature: THE UNIVERSITY OF NEW SOUTH WALES School of Electrical Engineering & Telecommunications FINALEXAMINATION Session 00 ELEC46 Power System Analysis TIME ALLOWED: 3 hours TOTAL

More information

Full Length Test Electronics and Communication Engineering

Full Length Test Electronics and Communication Engineering 1 [Ans A] PQRS P PQRSS P S QR P S Q QR Q P S R Q P S R (Q P S ) SPQ Full Length Test Electronics and Communication Engineering Answer Keys and Eplanations 2 [Ans A] Green s theorem and stokes theorem convert

More information

RLC Circuit (3) We can then write the differential equation for charge on the capacitor. The solution of this differential equation is

RLC Circuit (3) We can then write the differential equation for charge on the capacitor. The solution of this differential equation is RLC Circuit (3) We can then write the differential equation for charge on the capacitor The solution of this differential equation is (damped harmonic oscillation!), where 25 RLC Circuit (4) If we charge

More information

ECE 325 Electric Energy System Components 7- Synchronous Machines. Instructor: Kai Sun Fall 2015

ECE 325 Electric Energy System Components 7- Synchronous Machines. Instructor: Kai Sun Fall 2015 ECE 325 Electric Energy System Components 7- Synchronous Machines Instructor: Kai Sun Fall 2015 1 Content (Materials are from Chapters 16-17) Synchronous Generators Synchronous Motors 2 Synchronous Generators

More information

3. (a) Figure 3(a) shows a Bridge T network used in control systems. The element values are clearly marked in the figure.

3. (a) Figure 3(a) shows a Bridge T network used in control systems. The element values are clearly marked in the figure. I.E.S.-(Conv.) 1987 ELECTRICAL ENGINEERING PAPER - I PART A 1. (a) Define precisely unit step and unit impulse functions. Sketch the following function from t = 0 to t = 10 units, indicating all salient

More information

ENGG4420 LECTURE 7. CHAPTER 1 BY RADU MURESAN Page 1. September :29 PM

ENGG4420 LECTURE 7. CHAPTER 1 BY RADU MURESAN Page 1. September :29 PM CHAPTER 1 BY RADU MURESAN Page 1 ENGG4420 LECTURE 7 September 21 10 2:29 PM MODELS OF ELECTRIC CIRCUITS Electric circuits contain sources of electric voltage and current and other electronic elements such

More information

Prince Sattam bin Abdulaziz University College of Engineering. Electrical Engineering Department EE 3360 Electrical Machines (II)

Prince Sattam bin Abdulaziz University College of Engineering. Electrical Engineering Department EE 3360 Electrical Machines (II) Chapter # 4 Three-Phase Induction Machines 1- Introduction (General Principles) Generally, conversion of electrical power into mechanical power takes place in the rotating part of an electric motor. In

More information

DEHRADUN PUBLIC SCHOOL I TERM ASSIGNMENT SUBJECT- PHYSICS (042) CLASS -XII

DEHRADUN PUBLIC SCHOOL I TERM ASSIGNMENT SUBJECT- PHYSICS (042) CLASS -XII Chapter 1(Electric charges & Fields) DEHRADUN PUBLIC SCHOOL I TERM ASSIGNMENT 2016-17 SUBJECT- PHYSICS (042) CLASS -XII 1. Why do the electric field lines never cross each other? [2014] 2. If the total

More information