Acceleration is the rate of change of velocity in a specific direction. It is a VECTOR quantity has magnitude & direction. Any change in the velocity

Transcription

1 Physics Ch. 4

2 Acceleration is the rate of change of velocity in a specific direction. It is a VECTOR quantity has magnitude & direction. Any change in the velocity (either in magnitude or direction) is acceleration.

3 1. Which car or cars (red, green, and/or blue) are undergoing an acceleration? Study each car individually in order to determine the answer. 2. Which car (red, green, or blue) experiences the greatest acceleration?

4 An object s motion is determined by a combination of velocity & acceleration. We have to look at the magnitude and direction of each. Objects that are in acceleration MUST have a changing velocity.

5 Constant Acceleration Changing Acceleration Velocity must be changing by a constant amount. In the table above, the velocity changes by 4 each second. Velocity is changing at each second. This table shows no consistency in the velocity, but it does show an increase in velocity over time.

6 Units for acceleration are m/s 2. Sometimes this is written as m/s/s.

7 Example A: Example B:

8 Example C: Example D:

9 1. As a shuttle bus comes to a normal stop. It slows from 9.0 m/s to 0.0 m/s in 5.0 s. Find the average acceleration of the bus. 2. Find the acceleration of an amusement park ride that starts from rest to a speed of 28 m/s in 3.0s. 3. A car traveling west on Plymouth Road initially starts at 8.0 m/s and accelerated 2.5 m/s 2 for 3.0 s. What is the final velocity of the car? 4. Find the time required for a dump truck with an average acceleration of 0.80 m/s 2 to reach 27 m/s from rest.

10 We can use a V-T graph to determine an object s acceleration. Constant Velocity = ZERO Acceleration + Velocity = + Acceleration

11 POSITIVE Velocity NEGATIVE Velocity

12 SPEEDING UP The MAGNITUDE of velocity is INCREASING. The line on the graph is going further away from the x-axis. +3 m/s to +9 m/s SLOWING DOWN The MAGNITUDE of the velocity DECREASING. The line on the graph is approaching the x-axis. +9 m/s to +3 m/s -3 m/s to -9 m/s -9 m/s to -3 m/s

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17 MOTION VELOCITY ACCELERATION Speeding UP + + Speeding UP - - Slowing DOWN + - Slowing DOWN - + Constant Velocity - or + 0 Speeding UP from REST 0 - or + Remaining at REST 0 0

18 Strobe Pictures / Motion Diagrams Determine the motion of the following balls: REST Constant Velocity Speeding Up Slowing Down

19 Describe the position, velocity, and acceleration shown by each motion diagram.(1second intervals) 0m 1m 2m 3m 4m 0m.2m.6m 1.4m 2.4m 3.6m 0m 1.6m 2.4m 2.8m 3.0m 3.1m 0m.5m 1.0m 1.5m 2.0m

20 Ball rolling to the right. (strobe flash every 0.5s) 1. Is the motion of the ball moving with a constant velocity or accelerating? Accelerating 2. Is the acceleration of the ball positive, negative, or zero? Positive (the velocity is increasing) 3. Estimate the velocity of the ball at a) 5 cm b) 20 cm c) 44 cm d) 79 cm 4. What is the average acceleration of the ball?

21 There are 5 variables we are interested in now. Δx, V f, V i, a, and t There are 4 equations which are used to calculate/solve a wide variety of problems. We will focus on these as we study free fall next. Notice that each equation has 4 variables and one missing.

22 Equation Missing v f v 0 a avg t x v v t x f a avg v x 2 f v 0 t v 2 0 a a avg t avg 2 x v f t

23 Looking for distance (no accel. given) Solution:

24 Vi = 22m/s Vf = 0m/s t = 10s Δx =? 1 x f 2 0 v v t Looking for ΔX Solution:

25 Vi = 22m/s Vf = 0m/s t = 10s Δx =? Δx = ½(22m/s + 0) 10s 1 x f 2 0 v v t Looking for ΔX Solution: Δx =110 m

26 An object is in free fall if it is moving under the sole influence of gravity. Free-falling objects speed up, or accelerate, as they fall. The acceleration of -9.8 m/s 2 is given its own name and symbol acceleration due to gravity (g).

27 The motion of an object in free fall is described by the equations for speed and position with constant acceleration. The acceleration (a) is replaced by the acceleration due to gravity (g) and the variable (x) is replaced by (y). + -

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29 When the initial speed is upward, at first the acceleration due to gravity causes the speed to decrease. After reaching the highest point, its speed increases exactly as if it were dropped from the highest point with zero initial speed.

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31 Most free-fall problems ask you to find either the height or the speed. Height problems often make use of the knowledge that the speed becomes zero at the highest point of an object s motion. If a problem asks for the time of flight, remember that an object takes the same time going up as it takes coming down.

32 A stone is dropped down a well and it takes 1.6 seconds to reach the bottom. How deep is the well? You may assume the initial speed of the stone is zero. 1. You are asked for distance. 2. You are given an initial speed and time of flight. 3. Use v = v 0 + gt and y = y 0 + v 0 t + ½ gt 2 4. Since y 0 and v 0 = 0, the equation reduces to y = ½ gt 2 y = (0.5) (-9.8 m/s 2 ) (1.6s) 2 y = m (The negative sign indicates the height is lower than the initial height)

33 The acceleration due to gravity does not depend on the mass of the object which is falling. Air creates friction that resists the motion of objects moving through it. All of the formulas and examples discussed in this section assume a vacuum (no air).

34 You may safely assume that a = g = -9.8 m/sec 2 for speeds up to several meters per second. The air resistance from friction increases as a falling object s speed increases. Eventually, the rate of acceleration is reduced to zero and the object falls with constant speed. The maximum speed at which an object falls when limited by air friction is called the terminal velocity.