Direct Current Circuits
|
|
|
- Wesley Henry
- 5 years ago
- Views:
Transcription
1 Eler urren (hrges n Moon) Eler urren () The ne moun of hrge h psses hrough onduor per un me ny pon. urren s defned s: Dre urren rus = dq d Eler urren s mesured n oulom s per seond or mperes. ( = /s) n sngle ru, he urren ny nsn s he sme one pon s ny oher pon. (hrge s onsered.) Dre urren rus Dre urren rus 2 Drf Veloy Drf Veloy The free elerons n onduors re n onsn rndom moon, so here s no ne flow of hrge n ny one prulr dreon. f sedy eler feld E s eslshed nsde onduor henhrged prles re sujeed o sedy fore F = E. The ne effe of he eler feld s h n ddon o he rndom moon of he hrged prles whn onduor, here s lso ery smll ne moon or drf of he mong hrged prles s group n he dreon of he eler fore. The hrges mong n onduor he freuen ollsons wh he msse nerly sonry ons of he merl. Ths moon s desred n erms of he drf eloy d of he prles. Dre urren rus 3 Dre urren rus 4 urren Densy Drf Veloy The urren per un ross-seon re s lled he urren densy J. J= Q = Ne d N = onenron of hrges ( m 3 ) Q = = Ne d Dre urren rus Ne d = J = Ne d The eler felde n erms of urren densy J s: E = J The onsn s lled he ressy of he merl. 5 Dre urren rus 6
2 Beres (emf) Shem Dgrms n order o produe n eler urren n ru, poenl dfferene s needed. Beres re one wy of prodng dfferene n poenl (lled eleromoe fore or emf). The dreon of urren s y onenon he dreon pose hrge moes hrough he ru, whh s owrds he nege ermnl of he ery. Dre urren rus 7 Dre urren rus 8 Ohm s Lw Georg Ohm ( ) Found h he urren n mel wre s proporonl o he poenl dfferene V ppled o s ends. urren lso depends upon he onduy of he wre. s more ommon o lk ou ressne (nerse of onduy) nd express hs relonshp s: For power soures: Ohm s Lw For resse lods: = V or V = V = V V = V > V = V V = V < The un for ressne s lled he ohm nd s reed $ (omeg) Dre urren rus 9 Dre urren rus Termnl Volge The poenl dfferene n rel ery s no eul o he emf due o nernl ressne whn he ery. Ths lowers he olge lle o he ru. essne () nd essy () n e expermenlly deermned h he ressne of wre s drely proporonl o s lengh l nd nersely proporonl o s ross-seonl re. r V = r V s lled he ermnl olge of he ery. = l The proporonly onsn s lled he ressy nd depends upon he merl used for he wre. [=] $ m Dre urren rus Dre urren rus 2
3 Eler Power To fnd he power rnsformed y n eler dee rell h energy s Q%V. Power s he re energy s rnsformed n he dee or: P = QV = V The S un for power s J/s or w ( W = J/s). For ressors, omnng he oe wh Ohm s Lw resuls n: P = 2 = V 2 Mesurng Volge Volmeers re pled n prllel wh he pons eween whh he olge mesuremen s mde Volmeers he ery hgh ressne nd do no ffe he ru (hey drw ery smll urren) V V meer = V 3 Dre urren rus 3 Dre urren rus 4 Mesurng Volge Volmeers pled n seres wll lok he urren nd ree n open ru. = V Mesurng urren mmeers re pled n seres wh he dee hrough whh he urren mesuremen s mde mmeers he ery low ressne nd do no ffe he ru (he olge drop s ery low) V meer = E meer = 2 Dre urren rus 5 Dre urren rus 6 Mesurng urren essors n Seres mmeers pled n prllel wll ree shor ru. nyhng prllel o he meer wll he no olge ross hem nd herefore no urren V = V V 2 V 3 = = E = 2 = = V = ( ) V = V s Dre urren rus 7 Dre urren rus 8
4 essors n Seres urren s he sme hrough eh ressor nd s he sme s he urren n he eulen ressne Volge drop ross eh ressor s dfferen unless he ressne s he sme s = Dre urren rus 9 essors n Seres (Volge Dder) V = V = V 2 = = V = V 2 Dre urren rus 2 essors n Prllel essors n Prllel 2 3 = 2 3 = V = V V V p For ressors n prllel he eulen ressne s p = Dre urren rus 2 Volge drop s he sme ross eh ressor nd he sme s he olge drop ross he eulen ressne urren s dfferen hrough eh ressor, he hgher he ressne he lower he urren p = Dre urren rus 22 essors n Prllel (urren Dder) 2 = = = so nd V = & % ( $ ' = 2 & % ( 2 = V nd = & = V % ( $ ' $ ' Dre urren rus 23 Krhhoff s ules.) Junon ule (onseron of hrge) ny junon pon, he sum of ll urrens enerng he junon mus eul he sum of ll urrens leng he junon. 2 = Dre urren rus 24
5 Krhhoff s ules 2.) Loop ule (onseron of energy) The sum of he hnges n poenl round ny losed ph of ru s zero. V V 2 V 3 = Glnomeers glnomeer s smply meer h defles n proporon o he urren runnng hrough. The mxmum defleon s lled he full-sle defleon. The key hrerss of glnomeer re The urren fs reured for full-sle defleon. The ressne of he ol of wre n he meer. V = G Dre urren rus 25 Dre urren rus 26 Volmeers olmeer onsss of ressor pu n seres wh glnomeer. The lue of hs ressne s deermnes he full-sle redng of he meer V. fs s G V = fs ( s ) ( s = V fs ) fs Dre urren rus 28 Dre urren rus 27 mmeers n mmeer onsss of ressor pu n prllel (lled shun ressor or shun) wh glnomeer. The lue of hs ressne sh deermnes he fullsle redng of he meer. fs G sh sh = fs ( fs ) fs = ( fs ) sh rus (hrgng) rus Q o = = - = = Dre urren rus 29 Dre urren rus 3
6 rus (hrgng) = E d d = E d d = E d d = E d E = d d = d E d = d E Dre urren rus 3 rus (hrgng) d = d E = ln( E ) = ln( E ) ln ( E ) E & = ln% ( $ E ' e = E E Ee = E = E Ee () = Q f e ( ) where Q f = E Dre urren rus 32 rus (hrgng) The hrge on he por res ordng o: rus (hrgng) ( ) = Q f e ( ) = e ( ) () = Q f e ( ) Q f The urren ny me s gen y: = d d = = o e e o s lled he me onsn (& ) nd s he me kes he por o eome 63.2% hrged. Dre urren rus 33 = o e o /e Dre urren rus 34 rus (hrgng) rus (Dshrgng) Q f nresng = Q o -Q o = = = = d d - Dre urren rus 35 Dre urren rus 36
7 rus (Dshrgng) d d = d = d d d = Q o ln( ) ln( Q ) = ln$ % ' = ( Q & Q = e = Q e rus (Dshrgng) The hrge on he por res ordng o: The urren ny me s gen y: = d d = Q o e = Q o e = o e Dre urren rus 37 Dre urren rus 38 rus (Dshrgng) rus (Dshrgng) = Q o e Q o Q o Q o /e nresng o = o e o /e Dre urren rus 39 Dre urren rus 4 rus Unhrged = shor ru Fully hrged = open ru hrged por hs sme olge s he dee h s elerlly prllel o. Dre urren rus 4
" = #N d$ B. Electromagnetic Induction. v ) $ d v % l. Electromagnetic Induction and Faraday s Law. Faraday s Law of Induction
Eletromgnet Induton nd Frdy s w Eletromgnet Induton Mhel Frdy (1791-1867) dsoered tht hngng mgnet feld ould produe n eletr urrent n ondutor pled n the mgnet feld. uh urrent s lled n ndued urrent. The phenomenon
Lecture 7 Circuits Ch. 27
Leture 7 Cruts Ch. 7 Crtoon -Krhhoff's Lws Tops Dret Current Cruts Krhhoff's Two ules Anlyss of Cruts Exmples Ammeter nd voltmeter C ruts Demos Three uls n rut Power loss n trnsmsson lnes esstvty of penl
EE 247B/ME 218: Introduction to MEMS Design Lecture 27m2: Gyros, Noise & MDS CTN 5/1/14. Copyright 2014 Regents of the University of California
MEMSBase Fork Gyrosoe Ω r z Volage Deermnng Resoluon EE C45: Inrouon o MEMS Desgn LeM 15 C. Nguyen 11/18/08 17 () Curren (+) Curren Eleroe EE C45: Inrouon o MEMS Desgn LeM 15 C. Nguyen 11/18/08 18 [Zaman,
2/20/2013. EE 101 Midterm 2 Review
//3 EE Mderm eew //3 Volage-mplfer Model The npu ressance s he equalen ressance see when lookng no he npu ermnals of he amplfer. o s he oupu ressance. I causes he oupu olage o decrease as he load ressance
Physics 201 Lecture 2
Physcs 1 Lecure Lecure Chper.1-. Dene Poson, Dsplcemen & Dsnce Dsngush Tme nd Tme Inerl Dene Velocy (Aerge nd Insnneous), Speed Dene Acceleron Undersnd lgebrclly, hrough ecors, nd grphclly he relonshps
Motion in One Dimension
Moon n One Dmenson CHAPTER OUTLINE Poson, Veloy, nd Speed Insnneous Veloy nd Speed 3 Aeleron 4 Moon Dgrms 5 One-Dmensonl Moon w Consn Aeleron 6 Freely Fllng Objes 7 Knem Equons Dered rom Clulus ANSWERS
SOME USEFUL MATHEMATICS
SOME USEFU MAHEMAICS SOME USEFU MAHEMAICS I is esy o mesure n preic he behvior of n elecricl circui h conins only c volges n currens. However, mos useful elecricl signls h crry informion vry wih ime. Since
Pendulum Dynamics. = Ft tangential direction (2) radial direction (1)
Pendulum Dynams Consder a smple pendulum wh a massless arm of lengh L and a pon mass, m, a he end of he arm. Assumng ha he fron n he sysem s proporonal o he negave of he angenal veloy, Newon s seond law
Stability Analysis for VAR systems. )', a VAR model of order p (VAR(p)) can be written as:
Sbl Anlss for VAR ssems For se of n me seres vrbles (,,, n ', VAR model of order p (VAR(p n be wren s: ( A + A + + Ap p + u where he A s re (nxn oeffen mres nd u ( u, u,, un ' s n unobservble d zero men
Appendix C Partial discharges. 1. Relationship Between Measured and Actual Discharge Quantities
Appendi Prtil dishrges. Reltionship Between Mesured nd Atul Dishrge Quntities A dishrging smple my e simply represented y the euilent iruit in Figure. The pplied lternting oltge V is inresed until the
Electromagnetic waves in vacuum.
leromagne waves n vauum. The dsovery of dsplaemen urrens enals a peular lass of soluons of Maxwell equaons: ravellng waves of eler and magne felds n vauum. In he absene of urrens and harges, he equaons
A LOG IS AN EXPONENT.
Ojeives: n nlze nd inerpre he ehvior of rihmi funions, inluding end ehvior nd smpoes. n solve rihmi equions nlill nd grphill. n grph rihmi funions. n deermine he domin nd rnge of rihmi funions. n deermine
Comparative Evaluation of VSI and CSI based Unified Power Quality Conditioner
IOSR Journl of Elerl nd Elerons Engneerng IOSR-JEEE ISSN: 78-676 olume, Issue 6 Se-O. 0, PP 06-3 www.osrjournls.org Comre Eluon of SI nd CSI sed Unfed Power Quly Condoner K.drjhry, Prmod Agrwl, H.O.Gu
Advanced Electromechanical Systems (ELE 847)
(ELE 847) Dr. Smr ouro-rener Topc 1.4: DC moor speed conrol Torono, 2009 Moor Speed Conrol (open loop conrol) Consder he followng crcu dgrm n V n V bn T1 T 5 T3 V dc r L AA e r f L FF f o V f V cn T 4
Released Assessment Questions, 2017 QUESTIONS
Relese Assessmen Quesions, 17 QUESTIONS Gre 9 Assessmen of Mhemis Aemi Re he insruions elow. Along wih his ookle, mke sure ou hve he Answer Bookle n he Formul Shee. You m use n spe in his ook for rough
Chapter 28 - Circuits
Physics 4B Lecure Noes Chaper 28 - Circuis Problem Se #7 - due: Ch 28 -, 9, 4, 7, 23, 38, 47, 53, 57, 66, 70, 75 Lecure Ouline. Kirchoff's ules 2. esisors in Series 3. esisors in Parallel 4. More Complex
Displacement, Velocity, and Acceleration. (WHERE and WHEN?)
Dsplacemen, Velocy, and Acceleraon (WHERE and WHEN?) Mah resources Append A n your book! Symbols and meanng Algebra Geomery (olumes, ec.) Trgonomery Append A Logarhms Remnder You wll do well n hs class
Use 10 m/s 2 for the acceleration due to gravity.
ANSWERS Prjecle mn s he ecrl sum w ndependen elces, hrznl cmpnen nd ercl cmpnen. The hrznl cmpnen elcy s cnsn hrughu he mn whle he ercl cmpnen elcy s dencl ree ll. The cul r nsnneus elcy ny pn lng he prblc
( ) () we define the interaction representation by the unitary transformation () = ()
Hgher Order Perurbaon Theory Mchael Fowler 3/7/6 The neracon Represenaon Recall ha n he frs par of hs course sequence, we dscussed he chrödnger and Hesenberg represenaons of quanum mechancs here n he chrödnger
DIRECT CURRENT CIRCUITS
DRECT CURRENT CUTS ELECTRC POWER Consider the circuit shown in the Figure where bttery is connected to resistor R. A positive chrge dq will gin potentil energy s it moves from point to point b through
April 8, 2017 Math 9. Geometry. Solving vector problems. Problem. Prove that if vectors and satisfy, then.
pril 8, 2017 Mth 9 Geometry Solving vetor prolems Prolem Prove tht if vetors nd stisfy, then Solution 1 onsider the vetor ddition prllelogrm shown in the Figure Sine its digonls hve equl length,, the prllelogrm
Lecture 11 Inductance and Capacitance
ecure Inducance and apacance EETRIA ENGINEERING: PRINIPES AND APPIATIONS, Fourh Edon, by Allan R. Hambley, 8 Pearson Educaon, Inc. Goals. Fnd he curren olage for a capacance or nducance gen he olage curren
Go over vector and vector algebra Displacement and position in 2-D Average and instantaneous velocity in 2-D Average and instantaneous acceleration
Mh Csquee Go oe eco nd eco lgeb Dsplcemen nd poson n -D Aege nd nsnneous eloc n -D Aege nd nsnneous cceleon n -D Poecle moon Unfom ccle moon Rele eloc* The componens e he legs of he gh ngle whose hpoenuse
( )a = "t = 1 E =" B E = 5016 V. E = BHv # 3. 2 %r. c.) direction of induced current in the loop for : i.) "t < 1
99 3 c dr b a µ r.? d b µ d d cdr a r & b d & µ c µ c b dr µ c µ c b & ' ln' a +*+* b ln r ln a a r a ' µ c b 'b* µ c ln' * & ln, &a a+ ncreang no he page o nduced curren wll creae a - feldou of he page
Take a length of copper wire and wrap it around a pencil to form a coil. If
30 ANING GOA By sudyng hs chper, you wll lern: How me-vryng curren n one col cn nduce n emf n second, unconneced col. How o rele he nduced emf n crcu o he re of chnge of curren n he sme crcu. How o clcule
First-order piecewise-linear dynamic circuits
Frs-order pecewse-lnear dynamc crcus. Fndng he soluon We wll sudy rs-order dynamc crcus composed o a nonlnear resse one-por, ermnaed eher by a lnear capacor or a lnear nducor (see Fg.. Nonlnear resse one-por
1.3 SCALARS AND VECTORS
Bridge Course Phy I PUC 24 1.3 SCLRS ND VECTORS Introdution: Physis is the study of nturl phenomen. The study of ny nturl phenomenon involves mesurements. For exmple, the distne etween the plnet erth nd
Chapters 2 Kinematics. Position, Distance, Displacement
Chapers Knemacs Poson, Dsance, Dsplacemen Mechancs: Knemacs and Dynamcs. Knemacs deals wh moon, bu s no concerned wh he cause o moon. Dynamcs deals wh he relaonshp beween orce and moon. The word dsplacemen
Energy Storage Devices
Energy Sorage Deces Objece of Lecure Descrbe he consrucon of a capacor and how charge s sored. Inroduce seeral ypes of capacors Dscuss he elecrcal properes of a capacor The relaonshp beween charge, olage,
Chapter 2 Linear Mo on
Chper Lner M n .1 Aerge Velcy The erge elcy prcle s dened s The erge elcy depends nly n he nl nd he nl psns he prcle. Ths mens h prcle srs rm pn nd reurn bck he sme pn, s dsplcemen, nd s s erge elcy s
EE 410/510: Electromechanical Systems Chapter 3
EE 4/5: Eleomehnl Syem hpe 3 hpe 3. Inoon o Powe Eleon Moelng n Applon of Op. Amp. Powe Amplfe Powe onvee Powe Amp n Anlog onolle Swhng onvee Boo onvee onvee Flyb n Fow onvee eonn n Swhng onvee 5// All
Linear Response Theory: The connection between QFT and experiments
Phys540.nb 39 3 Lnear Response Theory: The connecon beween QFT and expermens 3.1. Basc conceps and deas Q: ow do we measure he conducvy of a meal? A: we frs nroduce a weak elecrc feld E, and hen measure
Logarithms LOGARITHMS.
Logrithms LOGARITHMS www.mthletis.om.u Logrithms LOGARITHMS Logrithms re nother method to lulte nd work with eponents. Answer these questions, efore working through this unit. I used to think: In the
10. A.C CIRCUITS. Theoretically current grows to maximum value after infinite time. But practically it grows to maximum after 5τ. Decay of current :
. A. IUITS Synopss : GOWTH OF UNT IN IUIT : d. When swch S s closed a =; = d. A me, curren = e 3. The consan / has dmensons of me and s called he nducve me consan ( τ ) of he crcu. 4. = τ; =.63, n one
Chapter 6: AC Circuits
Chaper 6: AC Crcus Chaper 6: Oulne Phasors and he AC Seady Sae AC Crcus A sable, lnear crcu operang n he seady sae wh snusodal excaon (.e., snusodal seady sae. Complee response forced response naural response.
Review for the Midterm Exam.
Review for he iderm Exm Rememer! Gross re e re Vriles suh s,, /, p / p, r, d R re gross res 2 You should kow he disiio ewee he fesile se d he udge se, d kow how o derive hem The Fesile Se Wihou goverme
A capacitor consists of two conducting plates, separated by an insulator. Conduction plates: e.g., Aluminum foil Insulator: air, mica, ceramic, etc
3//7 haper 6 apacors and Inducors Makng preparaon for dynamc crcus, whch hae far more applcaons han he sac crcus we hae learned so far. 6. apacors Sore energy n elecrc feld nsulaor onducng plaes A capacor
1 PYTHAGORAS THEOREM 1. Given a right angled triangle, the square of the hypotenuse is equal to the sum of the squares of the other two sides.
1 PYTHAGORAS THEOREM 1 1 Pythgors Theorem In this setion we will present geometri proof of the fmous theorem of Pythgors. Given right ngled tringle, the squre of the hypotenuse is equl to the sum of the
Learning Enhancement Team
Lernng Enhnement Tem Worsheet: The Cross Produt These re the model nswers for the worsheet tht hs questons on the ross produt etween vetors. The Cross Produt study gude. z x y. Loong t mge, you n see tht
Generation of Crowned Parabolic Novikov gears
Engneerng Leers, 5:, EL_5 4 Generon o Crowned Prol Novkov gers Somer M. Ny, Memer, IAENG, Mohmmd Q. Adullh, nd Mohmmed N.Mohmmed Asr - The Wldher-Novkov ger s one o he rulr r gers, whh hs he lrge on re
For the flux through a surface: Ch.24 Gauss s Law In last chapter, to calculate electric filede at a give location: q For point charges: K i r 2 ˆr
Ch.24 Guss s Lw In lst hpter, to lulte eletri filed t give lotion: q For point hrges: K i e r 2 ˆr i dq For ontinuous hrge distributions: K e r 2 ˆr However, for mny situtions with symmetri hrge distribution,
VECTORS VECTORS VECTORS VECTORS. 2. Vector Representation. 1. Definition. 3. Types of Vectors. 5. Vector Operations I. 4. Equal and Opposite Vectors
1. Defnton A vetor s n entt tht m represent phsl quntt tht hs mgntude nd dreton s opposed to slr tht ls dreton.. Vetor Representton A vetor n e represented grphll n rrow. The length of the rrow s the mgntude
Graduate Algorithms CS F-18 Flow Networks
Grue Algorihm CS673-2016F-18 Flow Nework Dvi Glle Deprmen of Compuer Siene Univeriy of Sn Frnio 18-0: Flow Nework Diree Grph G Eh ege weigh i piy Amoun of wer/eon h n flow hrough pipe, for inne Single
Mechanics Physics 151
Mechancs Physcs 5 Lecure 0 Canoncal Transformaons (Chaper 9) Wha We Dd Las Tme Hamlon s Prncple n he Hamlonan formalsm Dervaon was smple δi δ Addonal end-pon consrans pq H( q, p, ) d 0 δ q ( ) δq ( ) δ
Surds and Indices. Surds and Indices. Curriculum Ready ACMNA: 233,
Surs n Inies Surs n Inies Curriulum Rey ACMNA:, 6 www.mthletis.om Surs SURDS & & Inies INDICES Inies n surs re very losely relte. A numer uner (squre root sign) is lle sur if the squre root n t e simplifie.
1. Consider a PSA initially at rest in the beginning of the left-hand end of a long ISS corridor. Assume xo = 0 on the left end of the ISS corridor.
In Eercise 1, use sndrd recngulr Cresin coordine sysem. Le ime be represened long he horizonl is. Assume ll ccelerions nd decelerions re consn. 1. Consider PSA iniilly res in he beginning of he lef-hnd
Calculus 241, section 12.2 Limits/Continuity & 12.3 Derivatives/Integrals notes by Tim Pilachowski r r r =, with a domain of real ( )
Clculu 4, econ Lm/Connuy & Devve/Inel noe y Tm Plchow, wh domn o el Wh we hve o : veco-vlued uncon, ( ) ( ) ( ) j ( ) nume nd ne o veco The uncon, nd A w done wh eul uncon ( x) nd connuy e he componen
TOPICAL PROBLEMS OF FLUID MECHANICS 141
TOPIL PROBLEMS OF FLUID MEHNIS 4 DOI: h://dx.do.org/.43/tpfm.6.9 BIPLNE ERODYNMIS REISITED E. Morsh ollege of Engneerng nd Desgn, Shur Insue of Tehnology, 37, Fuksku, Mnum-ku, Sm-sh, 337 857, Sm, Jn sr
Problems set # 3 Physics 169 February 24, 2015
Prof. Anhordoqui Problems set # 3 Physis 169 Februry 4, 015 1. A point hrge q is loted t the enter of uniform ring hving liner hrge density λ nd rdius, s shown in Fig. 1. Determine the totl eletri flux
I 3 2 = I I 4 = 2A
ECE 210 Eletril Ciruit Anlysis University of llinois t Chigo 2.13 We re ske to use KCL to fin urrents 1 4. The key point in pplying KCL in this prolem is to strt with noe where only one of the urrents
Trigonometry. Trigonometry. Solutions. Curriculum Ready ACMMG: 223, 224, 245.
Trgonometry Trgonometry Solutons Currulum Redy CMMG:, 4, 4 www.mthlets.om Trgonometry Solutons Bss Pge questons. Identfy f the followng trngles re rght ngled or not. Trngles,, d, e re rght ngled ndted
Three Dimensional Coordinate Geometry
HKCWCC dvned evel Pure Mhs. / -D Co-Geomer Three Dimensionl Coordine Geomer. Coordine of Poin in Spe Z XOX, YOY nd ZOZ re he oordine-es. P,, is poin on he oordine plne nd is lled ordered riple. P,, X Y
Week 8 Lecture 3: Problems 49, 50 Fourier analysis Courseware pp (don t look at French very confusing look in the Courseware instead)
Week 8 Lecure 3: Problems 49, 5 Fourier lysis Coursewre pp 6-7 (do look Frech very cofusig look i he Coursewre ised) Fourier lysis ivolves ddig wves d heir hrmoics, so i would hve urlly followed fer he
EEM 486: Computer Architecture
EEM 486: Compuer Archecure Lecure 4 ALU EEM 486 MIPS Arhmec Insrucons R-ype I-ype Insrucon Exmpe Menng Commen dd dd $,$2,$3 $ = $2 + $3 sub sub $,$2,$3 $ = $2 - $3 3 opernds; overfow deeced 3 opernds;
Chapter E - Problems
Chpter E - Prolems Blinn College - Physics 2426 - Terry Honn Prolem E.1 A wire with dimeter d feeds current to cpcitor. The chrge on the cpcitor vries with time s QHtL = Q 0 sin w t. Wht re the current
Chapter 1 Relativity
Chaper Relaii - Posulaes of Speial Relaii and Loren Transformaion The s posulae: The laws of phsis ma be epressed in equaions haing he same form in all frames of referene moing a onsan eloi wih respe o
Fatigue life prediction for cyclically bent threaded connections
ISSN 9-7. MECHNIK.. 7: -9 Fgue lfe predon for yllly en hreded onneons Ž. Juhnevus,. Krenevus Vlnus Gedns Tehnl Unversy, Suleko l., Vlnus, Lhun, E-l: @f.vgu.l Vlnus Gedns Tehnl Unversy, Suleko l., Vlnus,
Notes on the stability of dynamic systems and the use of Eigen Values.
Noes on he sabl of dnamc ssems and he use of Egen Values. Source: Macro II course noes, Dr. Davd Bessler s Tme Seres course noes, zarads (999) Ineremporal Macroeconomcs chaper 4 & Techncal ppend, and Hamlon
Chapter Simpson s 1/3 Rule of Integration. ( x)
Cper 7. Smpso s / Rule o Iegro Aer redg s per, you sould e le o. derve e ormul or Smpso s / rule o egro,. use Smpso s / rule o solve egrls,. develop e ormul or mulple-segme Smpso s / rule o egro,. use
Physics 114 Exam 2 Fall 2014 Solutions. Name:
Physcs 114 Exam Fall 014 Name: For gradng purposes (do not wrte here): Queston 1. 1... 3. 3. Problem Answer each of the followng questons. Ponts for each queston are ndcated n red. Unless otherwse ndcated,
On Fractional Operational Calculus pertaining to the product of H- functions
nenonl eh ounl of Enneen n ehnolo RE e-ssn: 2395-56 Volume: 2 ue: 3 une-25 wwwene -SSN: 2395-72 On Fonl Oeonl Clulu enn o he ou of - funon D VBL Chu, C A 2 Demen of hem, Unve of Rhn, u-3255, n E-ml : vl@hooom
CS434a/541a: Pattern Recognition Prof. Olga Veksler. Lecture 4
CS434a/54a: Paern Recognon Prof. Olga Veksler Lecure 4 Oulne Normal Random Varable Properes Dscrmnan funcons Why Normal Random Varables? Analycally racable Works well when observaon comes form a corruped
PYTHAGORAS THEOREM WHAT S IN CHAPTER 1? IN THIS CHAPTER YOU WILL:
PYTHAGORAS THEOREM 1 WHAT S IN CHAPTER 1? 1 01 Squres, squre roots nd surds 1 02 Pythgors theorem 1 03 Finding the hypotenuse 1 04 Finding shorter side 1 05 Mixed prolems 1 06 Testing for right-ngled tringles
Potential Changes Around a Circuit. You must be able to calculate potential changes around a closed loop.
Tody s gend: Potentil Chnges Around Circuit. You must e le to clculte potentil chnges round closed loop. Electromotive force (EMF), Terminl Voltge, nd Internl Resistnce. You must e le to incorporte ll
ANSWERS TO EVEN NUMBERED EXERCISES IN CHAPTER 2
ANSWERS TO EVEN NUMBERED EXERCISES IN CHAPTER Seion Eerise -: Coninuiy of he uiliy funion Le λ ( ) be he monooni uiliy funion defined in he proof of eisene of uiliy funion If his funion is oninuous y hen
Section 1.3 Triangles
Se 1.3 Tringles 21 Setion 1.3 Tringles LELING TRINGLE The line segments tht form tringle re lled the sides of the tringle. Eh pir of sides forms n ngle, lled n interior ngle, nd eh tringle hs three interior
An object moving with speed v around a point at distance r, has an angular velocity. m/s m
Roion The mosphere roes wih he erh n moions wihin he mosphere clerly follow cure phs (cyclones, nicyclones, hurricnes, ornoes ec.) We nee o epress roion quniiely. For soli objec or ny mss h oes no isor
Magnetostatics Bar Magnet. Magnetostatics Oersted s Experiment
Mgneosics Br Mgne As fr bck s 4500 yers go, he Chinese discovered h cerin ypes of iron ore could rc ech oher nd cerin mels. Iron filings "mp" of br mgne s field Crefully suspended slivers of his mel were
two values, false and true used in mathematical logic, and to two voltage levels, LOW and HIGH used in switching circuits.
Digil Logi/Design. L. 3 Mrh 2, 26 3 Logi Ges nd Boolen Alger 3. CMOS Tehnology Digil devises re predominnly mnufured in he Complemenry-Mel-Oide-Semionduor (CMOS) ehnology. Two ypes of swihes, s disussed
5. Every rational number have either terminating or repeating (recurring) decimal representation.
CHAPTER NUMBER SYSTEMS Points to Rememer :. Numer used for ounting,,,,... re known s Nturl numers.. All nturl numers together with zero i.e. 0,,,,,... re known s whole numers.. All nturl numers, zero nd
CHAPTER 12 DIRECT CURRENT CIRCUITS
CHAPTER 12 DIRECT CURRENT CIUITS DIRECT CURRENT CIUITS 257 12.1 RESISTORS IN SERIES AND IN PARALLEL When wo resisors are conneced ogeher as shown in Figure 12.1 we said ha hey are conneced in series. As
Average & instantaneous velocity and acceleration Motion with constant acceleration
Physics 7: Lecure Reminders Discussion nd Lb secions sr meeing ne week Fill ou Pink dd/drop form if you need o swich o differen secion h is FULL. Do i TODAY. Homework Ch. : 5, 7,, 3,, nd 6 Ch.: 6,, 3 Submission
2D Motion WS. A horizontally launched projectile s initial vertical velocity is zero. Solve the following problems with this information.
Nme D Moion WS The equions of moion h rele o projeciles were discussed in he Projecile Moion Anlsis Acii. ou found h projecile moes wih consn eloci in he horizonl direcion nd consn ccelerion in he ericl
Electromagnetism Notes, NYU Spring 2018
Eletromgnetism Notes, NYU Spring 208 April 2, 208 Ation formultion of EM. Free field desription Let us first onsider the free EM field, i.e. in the bsene of ny hrges or urrents. To tret this s mehnil system
X-Ray Notes, Part III
oll 6 X-y oe 3: Pe X-Ry oe, P III oe Deeo Coe oupu o x-y ye h look lke h: We efe ue of que lhly ffee efo h ue y ovk: Co: C ΔS S Sl o oe Ro: SR S Co o oe Ro: CR ΔS C SR Pevouly, we ee he SR fo ye hv pxel
Magnetically Coupled Coil
Mgnetilly Coupled Ciruits Overview Mutul Indutne Energy in Coupled Coils Liner Trnsformers Idel Trnsformers Portlnd Stte University ECE 22 Mgnetilly Coupled Ciruits Ver..3 Mgnetilly Coupled Coil i v L
Capacitance and Inductance. The Capacitor
apaiane and Induane OUTINE apaiors apaior volage, urren, power, energy Induors eure 9, 9/9/5 Reading Hambley haper 3 (A) EE4 Fall 5 eure 9, Slide The apaior Two onduors (a,b) separaed by an insulaor: differene
e t dt e t dt = lim e t dt T (1 e T ) = 1
Improper Inegrls There re wo ypes of improper inegrls - hose wih infinie limis of inegrion, nd hose wih inegrnds h pproch some poin wihin he limis of inegrion. Firs we will consider inegrls wih infinie
6. Gas dynamics. Ideal gases Speed of infinitesimal disturbances in still gas
6. Gs dynmics Dr. Gergely Krisóf De. of Fluid echnics, BE Februry, 009. Seed of infiniesiml disurbnces in sill gs dv d, dv d, Coninuiy: ( dv)( ) dv omenum r r heorem: ( ( dv) ) d 3443 4 q m dv d dv llievi
PHY2053 Summer C 2013 Exam 1 Solutions
PHY053 Sue C 03 E Soluon. The foce G on o G G The onl cobnon h e '/ = doubln.. The peed of lh le 8fulon c 86,8 le 60 n 60n h 4h d 4d fonh.80 fulon/ fonh 3. The dnce eled fo he ene p,, 36 (75n h 45 The
Modeling and Simulation of Real Gas Flow in a Pipeline
Jornl of ppled Mhems nd Physs, 6, 4, 65-68 Pblshed Onlne gs 6 n SRes. hp://www.srp.org/jornl/jmp hp://d.do.org/.436/jmp.6.4875 Modelng nd Smlon of Rel Gs Flow n Ppelne gegneh en, lhn Mhe Deprmen of Mhems,
Ordinary Differential Equations in Neuroscience with Matlab examples. Aim 1- Gain understanding of how to set up and solve ODE s
Ordnary Dfferenal Equaons n Neuroscence wh Malab eamples. Am - Gan undersandng of how o se up and solve ODE s Am Undersand how o se up an solve a smple eample of he Hebb rule n D Our goal a end of class
ENGR 1990 Engineering Mathematics The Integral of a Function as a Function
ENGR 1990 Engineering Mhemics The Inegrl of Funcion s Funcion Previously, we lerned how o esime he inegrl of funcion f( ) over some inervl y dding he res of finie se of rpezoids h represen he re under
Let s treat the problem of the response of a system to an applied external force. Again,
Page 33 QUANTUM LNEAR RESPONSE FUNCTON Le s rea he problem of he response of a sysem o an appled exernal force. Agan, H() H f () A H + V () Exernal agen acng on nernal varable Hamlonan for equlbrum sysem
Verifcaton. Staemnt. Treasur( Oficeholdr, TREASU, Terminato) reasonbl. informat. aplicbe: DIFERNT) knowledg. Contrled Comite: schedul.
hv x x x x / b j ^ Z( _ D w D D D G g Vf NL: h Y x LNG h Y 809 R FX / Lk - L 965 D R 507 HN D/ b g, F Rb f - F H: K - F F F ( 866/ 75 - Z D X L DR f, 6) HN LNG h Y x LNG NY h Z D RU ( ) 8 v - ( F x 0 )
Concept of Activity. Concept of Activity. Thermodynamic Equilibrium Constants [ C] [ D] [ A] [ B]
![Concept of Activity. Concept of Activity. Thermodynamic Equilibrium Constants [ C] [ D] [ A] [ B]](/thumbs/80/81967334.jpg "Concept of Activity. Concept of Activity. Thermodynamic Equilibrium Constants [ C] [ D] [ A] [ B]")
Conept of Atvty Equlbrum onstnt s thermodynm property of n equlbrum system. For heml reton t equlbrum; Conept of Atvty Thermodynm Equlbrum Constnts A + bb = C + dd d [C] [D] [A] [B] b Conentrton equlbrum
Properties of Logarithms. Solving Exponential and Logarithmic Equations. Properties of Logarithms. Properties of Logarithms. ( x)
Properies of Logrihms Solving Eponenil nd Logrihmic Equions Properies of Logrihms Produc Rule ( ) log mn = log m + log n ( ) log = log + log Properies of Logrihms Quoien Rule log m = logm logn n log7 =
CAPACITANCE AND INDUCTANCE
APAITANE AND INDUTANE Inroduces wo passve, energy sorng devces: apacors and Inducors LEARNING GOALS APAITORS Sore energy n her elecrc feld (elecrosac energy) Model as crcu elemen INDUTORS Sore energy n
ECE Microwave Engineering. Fall Prof. David R. Jackson Dept. of ECE. Notes 10. Waveguides Part 7: Transverse Equivalent Network (TEN)
EE 537-635 Microwve Engineering Fll 7 Prof. Dvid R. Jcson Dep. of EE Noes Wveguides Pr 7: Trnsverse Equivlen Newor (N) Wveguide Trnsmission Line Model Our gol is o come up wih rnsmission line model for
Chapter 2. Review of Hydrodynamics and Vector Analysis
her. Ree o Hdrodmcs d Vecor Alss. Tlor seres L L L L ' ' L L " " " M L L! " ' L " ' I s o he c e romed he Tlor seres. O he oher hd ' " L . osero o mss -dreco: L L IN ] OUT [mss l [mss l] mss ccmled h me
Three-Phase Voltage-Source Converters
CURET Fll Three-Phe olge-soure Coerer Oule B Oero & Alo Pule-Wh oulo AC-Se Curre Corol DC-k olge Regulo Su C 85, ju@r.eu Three-Phe SC Three-Phe SC Cru / / S S S S S S A erle erfe ewee DC Three-Phe AC le
Abhilasha Classes Class- XII Date: SOLUTION (Chap - 9,10,12) MM 50 Mob no
hlsh Clsses Clss- XII Dte: 0- - SOLUTION Chp - 9,0, MM 50 Mo no-996 If nd re poston vets of nd B respetvel, fnd the poston vet of pont C n B produed suh tht C B vet r C B = where = hs length nd dreton
Field due to a collection of N discrete point charges: r is in the direction from
Physcs 46 Fomula Shee Exam Coulomb s Law qq Felec = k ˆ (Fo example, f F s he elecc foce ha q exes on q, hen ˆ s a un veco n he decon fom q o q.) Elecc Feld elaed o he elecc foce by: Felec = qe (elecc
Classification of Equations Characteristics
Clssiiion o Eqions Cheisis Consie n elemen o li moing in wo imensionl spe enoe s poin P elow. The ph o P is inie he line. The posiion ile is s so h n inemenl isne long is s. Le he goening eqions e epesene
Block 5 Transport of solutes in rivers
Nmeral Hydrals Blok 5 Transpor of soles n rvers Marks Holzner Conens of he orse Blok 1 The eqaons Blok Compaon of pressre srges Blok 3 Open hannel flow flow n rvers Blok 4 Nmeral solon of open hannel flow
John Geweke a and Gianni Amisano b a Departments of Economics and Statistics, University of Iowa, USA b European Central Bank, Frankfurt, Germany
Herarchcal Markov Normal Mxure models wh Applcaons o Fnancal Asse Reurns Appendx: Proofs of Theorems and Condonal Poseror Dsrbuons John Geweke a and Gann Amsano b a Deparmens of Economcs and Sascs, Unversy
Physics 120 Spring 2007 Exam #1 April 20, Name
Phc 0 Spng 007 E # pl 0, 007 Ne P Mulple Choce / 0 Poble # / 0 Poble # / 0 Poble # / 0 ol / 00 In eepng wh he Unon College polc on cdec hone, ued h ou wll nehe ccep no pode unuhozed nce n he copleon o
I I M O I S K J H G. b gb g. Chapter 8. Problem Solutions. Semiconductor Physics and Devices: Basic Principles, 3 rd edition Chapter 8
emcouc hyscs evces: Bsc rcles, r eo Cher 8 oluos ul rolem oluos Cher 8 rolem oluos 8. he fwr s e ex f The e ex f e e f ex () () f f f f l G e f f ex f 59.9 m 60 m 0 9. m m 8. e ex we c wre hs s e ex h
PHYS 1443 Section 001 Lecture #4
PHYS 1443 Secon 001 Lecure #4 Monda, June 5, 006 Moon n Two Dmensons Moon under consan acceleraon Projecle Moon Mamum ranges and heghs Reerence Frames and relae moon Newon s Laws o Moon Force Newon s Law
Chapter Lagrangian Interpolation
Chaper 5.4 agrangan Inerpolaon Afer readng hs chaper you should be able o:. dere agrangan mehod of nerpolaon. sole problems usng agrangan mehod of nerpolaon and. use agrangan nerpolans o fnd deraes and