|
|
- Damon Hampton
- 6 years ago
- Views:
Transcription
1 L A M P I R A N
2
3
4
5
6
7
8
9
10
11
12 SOURCE CODE (VISUAL BASIC 6.0) 1. Perhitungan awal dan perhitungan laju perpindahan panas. Gambar L.1. Form1.frm. Public Thi, Tho, Tci, mh, mc, d1, d2, Di, Pt, Nt, Lb, q, Pi, L, LMTD, hi, ho, P, R, F, De, numlnx Public CpAir, MiuAir, kair, PrAir, CpAirlaut, MiuAirlaut, kairlaut, PrAirlaut, Rec, Reh Private Sub Command1_Click() Thi = Val(Text3.Text) Tho = Val(Text4.Text) mh = Val(Text5.Text) TabelAir (Tho + Thi) / 2, Cph, Miuh, kh, Prh Label11.Caption = Cph Label12.Caption = Format(Miuh, "0.#########") Label13.Caption = kh Label14.Caption = Prh Private Sub Command2_Click() Thi = Val(Text3.Text) Tho = Val(Text4.Text) mh = Val(Text5.Text) TabelAir (Tho + Thi) / 2, Cph, Miuh, kh, Prh
13 q = mh * Cph * (Thi - Tho) Label19.Caption = q Private Sub Command3_Click() Form2.Show 2. Perhitungan LMTD dan faktor koreksi. Gambar L.2. Form2.frm. Public Thi, Tho, Tci, mh, mc, d1, d2, Di, Pt, Nt, Lb, q, Pi, L, LMTD, hi, ho, P, R, F, De, numlnx Public CpAir, MiuAir, kair, PrAir, CpAirlaut, MiuAirlaut, kairlaut, PrAirlaut, Rec, Reh Private Sub Command1_Click() Form4.Show Private Sub Command2_Click() t = Val(Form4.Label10) TabelAirlaut t, Cpc, Miuc, kc, Prc
14 Label11.Caption = Cpc Label12.Caption = Format(Miuc, "0.#########") Label13.Caption = kc Label14.Caption = Prc Label22.Caption = Val(Form4.Label9) Private Sub Command3_Click() Thi = Val(Form1.Text3.Text) Tho = Val(Form1.Text4.Text) Tci = Val(Form2.Text3.Text) Tco = Val(Form4.Label9) LMTD = ((Thi - Tco) - (Tho - Tci)) / (ln((thi - Tco) / (Tho - Tci))) Label18.Caption = LMTD Private Sub Command4_Click() Thi = Val(Form1.Text3.Text) Tho = Val(Form1.Text4.Text) Tci = Val(Form2.Text3.Text) Tco = Val(Form4.Label9) P = (Tco - Tci) / (Thi - Tci) R = (Thi - Tho) / (Tco - Tci) F = ((((R ^ 2) + 1) ^ 1 / 2) * (ln((1 - P) / (1 - (P * R))))) / ((R - 1) * ln((2 - (P * (R (((R ^ 2) + 1) ^ 1 / 2)))) / (2 - (P * (R (((R ^ 2) + 1) ^ 1 / 2)))))) Label19.Caption = F Private Sub Command5_Click() Form3.Show
15 Private Sub Form_Load() Label25.Caption = Val(Form1.Label19) 3. Perhitungan temperatur air laut keluar. Gambar L.3. Form4.frm. Public Thi, Tho, Tci, mh, mc, d1, d2, Di, Pt, Nt, Lb, q, Pi, L, LMTD, hi, ho, P, R, F, De, numlnx Public CpAir, MiuAir, kair, PrAir, CpAirlaut, MiuAirlaut, kairlaut, PrAirlaut, Rec, Reh Private Sub Command1_Click() Tci = Val(Form2.Text3.Text) mc = Val(Form2.Text5.Text) q = Val(Form1.Label19) Tsem = Val(Text1.Text) TabelAirlaut Tsem, Cpc, Miuc, kc, Prc Tco = Tci + (q / (mc * Cpc)) t = (Tci + Tco) / 2 Label6.Caption = Form1.Label19 Label8.Caption = Cpc
16 Label9.Caption = Tco Label10.Caption = t 4. Perhitungan koefisien perpindahan panas menyeluruh dan panjang APK. Gambar L.4. Form3.frm. Public Thi, Tho, Tci, mh, mc, d1, d2, Di, Pt, Nt, Lb, q, Pi, L, LMTD, hi, ho, P, R, F, De, numlnx Public CpAir, MiuAir, kair, PrAir, CpAirlaut, MiuAirlaut, kairlaut, PrAirlaut, Rec, Reh Private Sub Command1_Click() d1 = Val(Text1.Text) Nt = Val(Text2.Text) mc = Val(Form2.Text5.Text)
17 Pi = Miuc = Val(Form2.Label12) Rec = ((4 * mc) / (Nt * Pi * d1 * Miuc)) Label36.Caption = Rec Private Sub Command2_Click() Rec = Val(Label36) Prc = Val(Form2.Label14) d1 = Val(Text1.Text) La = Val(Text7.Text) If Rec < 2100 Then Nuc = 1.86 * ((Rec * Prc * d1 / La) ^ (1 / 3)) ElseIf Rec > Then Nuc = * (Rec ^ 0.8) * (Prc ^ 0.4) * (La / La) Else Nuc = * ((Rec ^ (2 / 3)) - 125) * (1 + ((d1 / La) ^ (2 / 3))) * (Prc ^ (1 / 3)) Label37.Caption = Nuc Private Sub Command3_Click() Nuc = Val(Label37) kc = Val(Form2.Label13) d1 = Val(Text1.Text) hi = Nuc * kc / d1 Label38.Caption = hi
18 Private Sub Command4_Click() d2 = Val(Text4.Text) Pt = Val(Text5.Text) Pi = If Option1.Value = True Then De = (3.44 * Pt ^ 2 - Pi * d2 ^ 2) / (Pi * d2) ElseIf Option2.Value = True Then De = (4 * Pt ^ 2 - Pi * d2 ^ 2) / (Pi * d2) Label39.Caption = Format(De, "0.#########") Private Sub Command5_Click() mh = Val(Form1.Text5.Text) Di = Val(Text3.Text) Lb = Val(Text6.Text) Pt = Val(Text5.Text) d2 = Val(Text4.Text) Gt = mh / (Di * Lb * (Pt - d2) / Pt) Label40.Caption = Gt Private Sub Command6_Click() Gt = Val(Label40) De = Val(Label39) Miuh = Val(Form1.Label12) Reh = Gt * De / Miuh Label41.Caption = Reh Private Sub Command7_Click()
19 Reh = Val(Label41) Prh = Val(Form1.Label14) Nuh = 0.36 * Reh ^ 0.55 * Prh ^ (1 / 3) Label42.Caption = Nuh Private Sub Command8_Click() Nuh = Val(Label42) kh = Val(Form1.Label13) De = Val(Label39) ho = Nuh * kh / De Label43.Caption = ho Private Sub Command9_Click() Thi = Val(Form1.Text3.Text) Tho = Val(Form1.Text4.Text) Tci = Val(Form2.Text3.Text) Tco = Val(Form2.Label22) Th = (Tho + Thi) / 2 Tc = (Tco + Tci) / 2 Tt = (((d2 / d1) * ho * Th) + (hi * Tc)) / (((d2 / d1) * ho) + hi) TabelTembaga Tt, kond TabelAir Tt, Cpht, Miuht, kht, Prht TabelAirlaut Tt, Cpct, Miuct, kct, Prct Label44.Caption = Tt Label13.Caption = kond Label17.Caption = Format(Miuct, "0.#########") Label18.Caption = Format(Miuht, "0.#########") Private Sub Command10_Click()
20 hi = Val(Label38) Miuc = Val(Form2.Label12) Miuct = Val(Label17) If Rec < Then hi2 = hi * ((Miuc / Miuct) ^ 0.14) Label45.Caption = hi2 Private Sub Command11_Click() ho = Val(Label43) Miuh = Val(Form1.Label12) Miuht = Val(Label18) ho2 = ho * ((Miuh / Miuht) ^ 0.14) Label46.Caption = ho2 Private Sub Command12_Click() d1 = Val(Text1.Text) d2 = Val(Text4.Text) hi2 = Val(Label45) ho2 = Val(Label46) kond = Val(Label13) Ui = 1 / (d1 / (ho2 * d2) + ((d1 * ln(d2 / d1)) / (2 * kond)) + (1 / hi2)) Label47.Caption = Ui Private Sub Command13_Click() q = Val(Form1.Label19) LMTD = Val(Form2.Label18) Nt = Val(Text2.Text) Ui = Val(Label47)
21 F = Val(Form2.Label19) d1 = Val(Text1.Text) Pi = L = q / (LMTD * Nt * Ui * F * Pi * d1) Label48.Caption = L Private Sub Form_Load() 5. Simulasi APK yang telah dirancang. Gambar L.5. Form5.frm. Public Thi, Tho, Tci, mh, mc, d1, d2, Di, Pt, Nt, Lb, Lbi, Lbo, q, Pi, L, LMTD, hi, ho, P, R, F, De, numlnx Public CpAir, MiuAir, kair, PrAir, CpAirlaut, MiuAirlaut, kairlaut, PrAirlaut, Rec, Reh Private Sub Command1_Click() d1 = Val(Text1.Text) d2 = Val(Text2.Text) Nt = Val(Text3.Text) Nb = Val(Text20.Text) Di = Val(Text4.Text) L = Val(Text5.Text) Dctl = Val(Text6.Text) Dotl = Val(Text7.Text) Lsb = Val(Text8.Text)
22 Ltb = Val(Text9.Text) Lbb = Val(Text10.Text) Pt = Val(Text11.Text) mh = Val(Text12.Text) Thi = Val(Text13.Text) Thsem = Val(Text18.Text) mc = Val(Text14.Text) Tci = Val(Text15.Text) Tcsem = Val(Text19.Text) Lb = Val(Text16.Text) BC = Val(Text17.Text) Pi = 4 * Math.Atn(1) TabelAirlaut Tcsem, Cpc, Miuc, kc, Prc TabelAir Thsem, Cph, miuh, kh, Prh Rec = (4 * (mc / Nt)) / (Pi * d1 * Miuc) If Rec < 2100 Then Nuc = 1.86 * ((Rec * Prc * d1 / L) ^ (1 / 3)) ElseIf Rec > Then Nuc = * (Rec ^ 0.8) * (Prc ^ 0.4) * (L / L) Else Nuc = * ((Rec ^ (2 / 3)) - 125) * (1 + ((d1 / L) ^ (2 / 3))) * (Prc ^ (1 / 3)) hc = Nuc * kc / d1 Sm = Lb * (Lbb + ((Dctl / Pt) * (Pt - d2))) Gh = mh / Sm If BC > 10 Then Tetactl = (2 * (ArcCos((Di / Dctl) * (1 - (2 * (BC / 100)))))) * 180 / Pi Else Tetactl = 0 If BC > 10 Then Fw = (Tetactl / 360) - (Sin(Tetactl * Pi / 180) / (2 * Pi)) Else Fw = If BC > 10 Then Fc = 1 - (2 * Fw) Else Fc = 0.625
23 Reh = d2 * Gh / miuh Tetads = 2 * (ArcCos(1 - (2 * (BC / 100)))) * 180 / Pi Ssb = * Di * Lsb * (360 - Tetads) Stb = (((Pi / 4) * (((d2 + Ltb) ^ 2) - (d2 ^ 2))) * (Nt) * (1 - Fw)) rs = Ssb / (Ssb + Stb) rlm = (Ssb + Stb) / Sm Sb = Lb * (Di - Dotl) Fsbp = Sb / Sm If Reh > 100 Then Cbh = 1.25 Else Cbh = 1.35 If Option1.Value = True Then a1 = a2 = a3 = a4 = 0.37 ElseIf Option2.Value = True Then a1 = a2 = a3 = 1.45 a4 = A = a3 / (1 + (0.14 * (Reh ^ a4))) ji = a1 * ((1.33 / (Pt / d2)) ^ A) * (Reh ^ a2) If BC > 10 Then JC = (0.72 * Fc) Else JC = 1 JL = (0.44 * (1 - rs)) + ((1 - (0.44 * (1 - rs))) * Exp(-2.2 * rlm)) JB = Exp(-Cbh * Fsbp) Lbi = (L - ((Nb * 2 / 1000) + ((Nb - 1) * Lb))) / 2 Lbo = (L - ((Nb * 2 / 1000) + ((Nb - 1) * Lb))) / 2 JS = ((Nb - 1) + ((Lbi / Lb) ^ (1-0.6)) + ((Lbo / Lb) ^ (1-0.6))) / ((Nb - 1) + (Lbi / Lb) + (Lbo / Lb)) hoideal = ji * Cph * Gh * (Prh ^ (-2 / 3))
24 Tw = ((hoideal * d2 * (Thsem + 273)) + (hc * d1 * (Tcsem + 273))) / ((hc * d1) + (hoideal * d2)) TabelAir Tw - 273, cpw, miuw, kw, Prw TabelTembaga Tw - 273, kond Jmiu = (miuh / miuw) ^ 0.14 ho = JC * JL * JB * JS * Jmiu * hoideal TabelAirlaut Tw - 273, cpaw, miuaw, kaw, Praw hcbaru = hc * ((Miuc / miuaw) ^ 0.14) Uo = 1 / (((d2 / d1) * (1 / hcbaru)) + ((d2 / (2 * kond)) * (ln(d2 / d1))) + (1 / ho)) Ch = mh * Cph Cc = mc * Cpc Ao = Nt * Pi * d2 * L If Cc < Ch Then C = Cc / Ch Else C = Ch / Cc If Cc < Ch Then NTU = Uo * Ao / Cc Else NTU = Uo * Ao / Ch E = 2 * ((1 + C + ((1 + ((C ^ 2) ^ 0.5)) * ((1 + (Exp(-NTU * ((1 + (C ^ 2)) ^ 0.5)))) / (1 - (Exp(-NTU * ((1 + (C ^ 2)) ^ 0.5))))))) ^ -1) If Cc < Ch Then Tco = Tci + (E * (Thi - Tci)) Else Tho = Thi - (E * (Thi - Tci)) If Cc < Ch Then q = Cc * (Tco - Tci) Else q = Ch * (Thi - Tho) If Cc < Ch Then Tho = Thi - ((Cc / Ch) * (Tco - Tci)) Else Tco = Tci + ((Ch/Cc) * (Thi - Tho))
25 Tc = (Tci + Tco) / 2 Th = (Thi + Tho) / 2 Label34.Caption = Miuc Label35.Caption = Cpc Label36.Caption = kc Label37.Caption = Prc Label30.Caption = Rec Label31.Caption = Nuc Label32.Caption = hc Label46.Caption = Tco Label47.Caption = Tc Label52.Caption = miuh Label53.Caption = Cph Label55.Caption = kh Label56.Caption = Prh Label57.Caption = Gh Label58.Caption = Reh Label59.Caption = ho Label60.Caption = Tho Label61.Caption = Th Label62.Caption = Uo Label63.Caption = E * Modul tabel air, tabel air laut, dan fungsi ln. Public Thi, Tho, Tci, mh, mc, d1, d2, Di, Pt, Nt, Lb, q, Pi, L, LMTD, hi, ho, P, R, F, De, numlnx Public CpAir, MiuAir, kair, PrAir, CpAirlaut, MiuAirlaut, kairlaut, PrAirlaut, Rec, Reh Public i() As Variant 'Tabel Air berdasarkan Incropera sebagai berikut 'Urutannya Temperatur, Cp, Miu, k, Pr Sub TabelAir(Tem, ketcp, ketmiu, ketk, ketpr) Dim Daf(4, 21), Tes Dim i As Integer Temp = Val(Tem )
26 Daf(0, 0) = : Daf(1, 0) = 4217: Daf(2, 0) = : Daf(3, 0) = 0.659: Daf(4, 0) = Daf(0, 1) = 275: Daf(1, 1) = 4211: Daf(2, 1) = : Daf(3, 1) = 0.574: Daf(4, 1) = Daf(0, 2) = 280: Daf(1, 2) = 4198: Daf(2, 2) = : Daf(3, 2) = 0.582: Daf(4, 2) = Daf(0, 3) = 285: Daf(1, 3) = 4189: Daf(2, 3) = : Daf(3, 3) = 0.59: Daf(4, 3) = 8.81 Daf(0, 4) = 290: Daf(1, 4) = 4184: Daf(2, 4) = : Daf(3, 4) = 0.598: Daf(4, 4) = 7.56 Daf(0, 5) = 295: Daf(1, 5) = 4181: Daf(2, 5) = : Daf(3, 5) = 0.606: Daf(4, 5) = 6.62 Daf(0, 6) = 300: Daf(1, 6) = 4179: Daf(2, 6) = : Daf(3, 6) = 0.613: Daf(4, 6) = 5.83 Daf(0, 7) = 305: Daf(1, 7) = 4178: Daf(2, 7) = : Daf(3, 7) = 0.62: Daf(4, 7) = 5.2 Daf(0, 8) = 310: Daf(1, 8) = 4178: Daf(2, 8) = : Daf(3, 8) = 0.628: Daf(4, 8) = 4.62 Daf(0, 9) = 315: Daf(1, 9) = 4179: Daf(2, 9) = : Daf(3, 9) = 0.634: Daf(4, 9) = 4.16 Daf(0, 10) = 320: Daf(1, 10) = 4180: Daf(2, 10) = : Daf(3, 10) = 0.64: Daf(4, 10) = 3.77 Daf(0, 11) = 325: Daf(1, 11) = 4182: Daf(2, 11) = : Daf(3, 11) = 0.645: Daf(4, 11) = 3.42 Daf(0, 12) = 330: Daf(1, 12) = 4184: Daf(2, 12) = : Daf(3, 12) = 0.65: Daf(4, 12) = 3.15 Daf(0, 13) = 335: Daf(1, 13) = 4186: Daf(2, 13) = : Daf(3, 13) = 0.656: Daf(4, 13) = 2.88 Daf(0, 14) = 340: Daf(1, 14) = 4188: Daf(2, 14) = : Daf(3, 14) = 0.66: Daf(4, 14) = 2.66
27 Daf(0, 15) = 345: Daf(1, 15) = 4191: Daf(2, 15) = : Daf(3, 15) = 0.668: Daf(4, 15) = 2.45 Daf(0, 16) = 350: Daf(1, 16) = 4195: Daf(2, 16) = : Daf(3, 16) = 0.668: Daf(4, 16) = 2.29 Daf(0, 17) = 355: Daf(1, 17) = 4199: Daf(2, 17) = : Daf(3, 17) = 0.671: Daf(4, 17) = 2.14 Daf(0, 18) = 360: Daf(1, 18) = 4203: Daf(2, 18) = : Daf(3, 18) = 0.674: Daf(4, 18) = 2.02 Daf(0, 19) = 365: Daf(1, 19) = 4209: Daf(2, 19) = : Daf(3, 19) = 0.677: Daf(4, 19) = 1.91 Daf(0, 20) = 370: Daf(1, 20) = 4214: Daf(2, 20) = : Daf(3, 20) = 0.679: Daf(4, 20) = 1.8 Daf(0, 21) = : Daf(1, 21) = 4217: Daf(2, 21) = : Daf(3, 21) = 0.68: Daf(4, 21) = 1.76 For i = 0 To 21 Step 1 Tes = Daf(0, i) - Temp If Tes >= 0 Then ATem = Daf(0, i) ACp = Daf(1, i) AMiu = Daf(2, i) Ak = Daf(3, i) APr = Daf(4, i) Exit For Next i For i = 21 To 0 Step -1 Tes = Temp - Daf(0, i) If Tes > 0 Then BTem = Daf(0, i) BCp = Daf(1, i) BMiu = Daf(2, i) Bk = Daf(3, i)
28 BPr = Daf(4, i) Exit For Next i If ATem = BTem Then ketcp = ACp ketmiu = AMiu ketk = Ak ketpr = APr Else Perb = (BTem - Temp) / (BTem - ATem) ketcp = BCp - Perb * (BCp - ACp) ketmiu = BMiu - Perb * (BMiu - AMiu) ketk = Bk - Perb * (Bk - Ak) ketpr = BPr - Perb * (BPr - APr) Sub TabelAirlaut(Tem, ketcp, ketmiu, ketk, ketpr) 'Tabel Air Laut berdasarkan Mostafa sebagai berikut 'Urutannya adalah Temperatur, Cp, Miu, k, Pr Dim Daf(4, 10), Tes Dim i As Integer Temp = Val(Tem) Daf(0, 0) = 0: Daf(1, 0) = : Daf(2, 0) = : Daf(3, 0) = 0.57: Daf(4, 0) = Daf(0, 1) = 10: Daf(1, 1) = : Daf(2, 1) = : Daf(3, 1) = 0.587: Daf(4, 1) = Daf(0, 2) = 20: Daf(1, 2) = : Daf(2, 2) = : Daf(3, 2) = 0.602: Daf(4, 2) =
29 Daf(0, 3) = 30: Daf(1, 3) = : Daf(2, 3) = : Daf(3, 3) = 0.616: Daf(4, 3) = Daf(0, 4) = 40: Daf(1, 4) = : Daf(2, 4) = : Daf(3, 4) = : Daf(4, 4) = Daf(0, 5) = 50: Daf(1, 5) = : Daf(2, 5) = : Daf(3, 5) = : Daf(4, 5) = Daf(0, 6) = 60: Daf(1, 6) = : Daf(2, 6) = : Daf(3, 6) = 0.649: Daf(4, 6) = Daf(0, 7) = 70: Daf(1, 7) = : Daf(2, 7) = : Daf(3, 7) = : Daf(4, 7) = Daf(0, 8) = 80: Daf(1, 8) = : Daf(2, 8) = : Daf(3, 8) = : Daf(4, 8) = Daf(0, 9) = 90: Daf(1, 9) = : Daf(2, 9) = : Daf(3, 9) = 0.67: Daf(4, 9) = Daf(0, 10) = 100: Daf(1, 10) = : Daf(2, 10) = : Daf(3, 10) = 0.675: Daf(4, 10) = For i = 0 To 10 Step 1 Tes = Daf(0, i) - Temp If Tes >= 0 Then ATem = Daf(0, i) ACp = Daf(1, i) AMiu = Daf(2, i) Ak = Daf(3, i) APr = Daf(4, i) Exit For Next i For i = 10 To 0 Step -1 Tes = Temp - Daf(0, i) If Tes > 0 Then BTem = Daf(0, i) BCp = Daf(1, i)
30 BMiu = Daf(2, i) Bk = Daf(3, i) BPr = Daf(4, i) Exit For Next i If ATem = BTem Then ketcp = ACp ketmiu = AMiu ketk = Ak ketpr = APr Else Perb = (BTem - Temp) / (BTem - ATem) ketcp = BCp - Perb * (BCp - ACp) ketmiu = BMiu - Perb * (BMiu - AMiu) ketk = Bk - Perb * (Bk - Ak) ketpr = BPr - Perb * (BPr - APr) Sub TabelTembaga(Tem, ketkond) 'Tabel Tembaga berdasarkan Incropera sebagai berikut 'Urutannya adalah Temperatur, kond Dim Daf(1, 5), Tes Dim i As Integer Temp = Val(Tem ) Daf(0, 0) = 100: Daf(1, 0) = 482: Daf(0, 1) = 200: Daf(1, 1) = 413: Daf(0, 2) = 300: Daf(1, 2) = 401: Daf(0, 3) = 400: Daf(1, 3) = 393:
31 Daf(0, 4) = 600: Daf(1, 4) = 379: Daf(0, 5) = 800: Daf(1, 5) = 366: For i = 0 To 5 Step 1 Tes = Daf(0, i) - Temp If Tes >= 0 Then ATem = Daf(0, i) Akond = Daf(1, i) Exit For Next i For i = 5 To 0 Step -1 Tes = Temp - Daf(0, i) If Tes > 0 Then BTem = Daf(0, i) Bkond = Daf(1, i) Exit For Next i If ATem = BTem Then ketkond = Akond Else Perb = (BTem - Temp) / (BTem - ATem) ketkond = Bkond - Perb * (Bkond - Akond) Function ln(numx) ln = (Log(numX) / Log(Exp(1))) End Function
32 Gambar L.6. Pemasangan sekat pada bundle tabung. Gambar L.7. Pemasangan bundle tabung ke cangkang.
33 Gambar L.8. APK yang siap diuji. Gambar L.9. Pemasangan APK pada rangkaian siklus.
34 Gambar L.10. Pengambilan data. Gambar L.11. Termokopel menunjukkan temperatur masuk air (fluida panas).
35 Gambar L.12. Jarak baffle 40 mm. Gambar L.13. Jarak baffle 44 mm.
36 Gambar L.14. Jarak baffle 49 mm. Gambar L.15. Jarak baffle 55 mm.
37 Gambar L.16. Jarak baffle 63 mm. Gambar L.17. Jarak baffle 73 mm.
$INCLUDE Moody.lib { }
File:F:\Thermal Systems Design\Design Problem 3 attempt 2.EES 11/12/2012 4:14:34 PM Page 1 $INCLUDE Moody.lib {Problem Statement} {In industrial applications, steam is often used as a heating medium. There
More informationHEAT EXCHANGER. Objectives
HEAT EXCHANGER Heat exchange is an important unit operation that contributes to efficiency and safety of many processes. In this project you will evaluate performance of three different types of heat exchangers
More informationPROBLEM The heat rate, q, can be evaluated from an energy balance on the cold fluid, 225 kg/h J. 3600s/h
PROBLEM 11.41 KNOWN: Concentric tube heat exchanger. FIND: Length of the exchanger. SCHEMATIC: ASSUMPTIONS: (1) Negligible heat loss to surroundings, () Negligible kinetic and potential energy changes,
More informationPROBLEM and from Eq. 3.28, The convection coefficients can be estimated from appropriate correlations. Continued...
PROBLEM 11. KNOWN: Type-30 stainless tube with prescribed inner and outer diameters used in a cross-flow heat exchanger. Prescribed fouling factors and internal water flow conditions. FIND: (a) Overall
More informationDesign and Temperature Analysis on Heat Exchanger with TEMA Standard Codes
Design and Temperature Analysis on Heat Exchanger with TEMA Standard Codes Adesh Dhope 1, Omkar Desai 2, Prof. V. Verma 3 1 Student, Department of Mechanical Engineering,Smt. KashibaiNavale college of
More informationTrade Patterns, Production networks, and Trade and employment in the Asia-US region
Trade Patterns, Production networks, and Trade and employment in the Asia-U region atoshi Inomata Institute of Developing Economies ETRO Development of cross-national production linkages, 1985-2005 1985
More informationWEAR A COLLAR RAISE A DOLLAR THIS
WEAR A COLLAR RAISE A DOLLAR THIS f Ac D A Wc Thk f k f Db. Db h f h f Ac D A b h Ocb., h W h f, b D. c h A D c f A Ab Ac D A T Rx A Ib T Ac D A Lb G R h h hc b. O, f h k, k k h b ffc, f b, f hch k k ch
More informationIntroduction to Heat and Mass Transfer
Introduction to Heat and Mass Transfer Week 16 Merry X mas! Happy New Year 2019! Final Exam When? Thursday, January 10th What time? 3:10-5 pm Where? 91203 What? Lecture materials from Week 1 to 16 (before
More informationHEAT TRANSFER LAB MANUAL
HEAT TRANSFER LAB MANUAL NIRMA UNIVERSITY INSTITUTE OF TECHNOLOGY CHEMICAL ENGINEERING DEPARTMENT List of Experiments: 1. Thermal conductivity apparatus 2. Thermal conductivity of metal rod 3. Thermal
More information1 Solution to Homework 4
Solution to Homework Section. 5. The characteristic equation is r r + = (r )(r ) = 0 r = or r =. y(t) = c e t + c e t y = c e t + c e t. y(0) =, y (0) = c + c =, c + c = c =, c =. To find the maximum value
More informationChapter 11: Heat Exchangers. Dr Ali Jawarneh Department of Mechanical Engineering Hashemite University
Chapter 11: Heat Exchangers Dr Ali Jawarneh Department of Mechanical Engineering Hashemite University Objectives When you finish studying this chapter, you should be able to: Recognize numerous types of
More informationDESIGN AND EXPERIMENTAL ANALYSIS OF SHELL AND TUBE HEAT EXCHANGER (U-TUBE)
DESIGN AND EXPERIMENTAL ANALYSIS OF SHELL AND TUBE HEAT EXCHANGER (U-TUBE) Divyesh B. Patel 1, Jayesh R. Parekh 2 Assistant professor, Mechanical Department, SNPIT&RC, Umrakh, Gujarat, India 1 Assistant
More informationHeat Exchangers: Rating & Performance Parameters. Maximum Heat Transfer Rate, q max
Heat Exchangers: Rating & Performance Parameters Dr. Md. Zahurul Haq HTX Rating is concerned with the determination of the heat transfer rate, fluid outlet temperatures, and the pressure drop for an existing
More informationCP 52 Page In & Zone Sensitivity
db SSM S R.0K R0.00K To Sheet ZA ON OFF C 0. R.K R 0.0K DUCK To Sheet Page Input Shield R 00 S PP Phantom Power 0/V L T C 0PF C L 0PF T EURO POS R0 0 R 0 R.0K 00/0V R Mic/Line.K R.K R.0K R 00 R. R0A KRD
More informationTHE MIDWAY & GAMES GRADE 4 SOCIAL STUDIES DEEP IN THE HEART OF TEXAS THE TEXAS STAR ILLUMINATED
THE MIDWY & GMES GRDE 4 SOCI STUDIES DEEP IN THE HERT OF TEXS THE TEXS STR IUMINTED T Mw TECHER G F SOCIIES STUD Dp H f Tx T Tx S Im I w: z pc mb p f. Smmz f S. U v pm c c cq fm b Tx. C w f Tx S., c v
More informationHow can we use Fundamental Heat Transfer to understand real devices like heat exchangers?
Lectures 7+8 04 CM30 /30/05 CM30 Transport I Part II: Heat Transfer Applied Heat Transfer: Heat Exchanger Modeling, Sizing, and Design Professor Faith Morrison Department of Chemical Engineering Michigan
More informationApplied Heat Transfer:
Lectures 7+8 CM30 /6/06 CM30 Transport I Part II: Heat Transfer Applied Heat Transfer: Heat Exchanger Modeling, Sizing, and Design Professor Faith Morrison Department of Chemical Engineering Michigan Technological
More informationRaman Amplifier Simulations with Bursty Traffic
R S h y Tc h N., k F, Jy K. c D Ecc E C Scc Uy ch b 3, Oc b, ch 489 X Cc, c. 5 W. hy D, S, Tx 753 Th h h bh R h bjc by c. y c c h h z c c c. Sch by c h -k c cy b. cc c, h c -- h h ych c k SONET), hch c
More informationBIG TEX GRADE 5 SOCIAL STUDIES CELEBRATING SYMBOLS: BIG TEX & LADY LIBERTY UNITE
GRA 5 SOCIA STUIS CBRATIG SYMBOS: & AY IBRTY UIT TACHR Cb Syb B Tx & y by U Fv G SOCIAIS STU I h w: x h fcc f yb k h Ac Tx bf c. c c h! A w Wh h c, y, Tx b c y w A h, x w y c f h, y cz. C c yb k h cb y.
More informationc Dr. Md. Zahurul Haq (BUET) Heat Exchangers: Rating & Sizing - I ME 307 (2017) 2 / 32 T666
Heat Exchanger: Rating & Sizing Heat Exchangers: Rating & Sizing - I Dr. Md. Zahurul Haq Professor Department of Mechanical Engineering Bangladesh University of Engineering & Technology (BUET) Dhaka-000,
More informationLast 4 Digits of USC ID:
Chemistry 05 B Practice Exam Dr. Jessica Parr First Letter of last Name PLEASE PRINT YOUR NAME IN BLOCK LETTERS Name: Last 4 Digits of USC ID: Lab TA s Name: Question Points Score Grader 8 2 4 3 9 4 0
More informationGlobally Optimal Linear Approach for the Design of Process Equipment: The Case of Air Coolers
Globally Optimal Linear Approach for the Design of Process Equipment: The Case of Air Coolers Priscila A. Souza and Andre L. H. Costa Instituto de Quımica, Rio de Janeiro State University (UERJ), Rio de
More informationCHEM 4641 Fall questions worth a total of 32 points. Show your work, except on multiple-choice questions. 1 V α=
Physical Chemistry I Final Exam Name: KEY CHEM 4641 Fall 017 15 questions worth a total of 3 points. Show your work, except on multiple-choice questions. 1 V 1 V α= κt = V T P V P T Gas constant R = 8.314
More informationTHERMODYNAMIC PERFORMANCE EVALUATION FOR HELICAL PLATE HEAT EXCHANGER BASED ON SECOND LAW ANALYSIS
THE PUBLISHING HOUSE PROCEEDINGS OF THE ROMANIAN ACADEMY, Series A, OF THE ROMANIAN ACADEMY Special Issue/2018, pp. 237 242 THERMODYNAMIC PERFORMANCE EVALUATION FOR HELICAL PLATE HEAT EXCHANGER BASED ON
More informationJ. Org. Chem., 1997, 62(12), , DOI: /jo961896m
J. Org. Chem., 1997, 62(12), 392-399, DO:1.121/jo961896m Terms & Conditions Electronic Supporting nformation files are available without a subscription to ACS Web Editions. The American Chemical Society
More informationP a g e 5 1 of R e p o r t P B 4 / 0 9
P a g e 5 1 of R e p o r t P B 4 / 0 9 J A R T a l s o c o n c l u d e d t h a t a l t h o u g h t h e i n t e n t o f N e l s o n s r e h a b i l i t a t i o n p l a n i s t o e n h a n c e c o n n e
More informationFAIR FOOD GRADE 8 SOCIAL STUDIES ICONIC EDIBLES LIGHTS CAMERA ACTION!
FAIR FOO GRAE 8 SOCIA IES ICONIC EIBES IGHTS CAMERA ACTION! F F G Egh Icc Eb gh Cm Ac! I h w: cm c fm b q f h S F f Tx. Az h cb f v c hc gp. cb vpm h c h q Amc c. W, pc, cm b cc b f h Tx S F. m w f j v
More information>> Taste from our extensive collection. >> Meet the chefs and producers. >> Connect with our team to chat
P j S h 2016 Sy, Mch 20 TH 10 m - 5 m My, Mch 21 ST 10 m - 4 m Wh S Cv C >> T m xv cc vy w >> M h ch c bh m w m vv c >> Cc wh m ch b wy c w y b Shw b q. R h Mch 18h www.wvchw.cm Ah c m h Gk wy my wh c
More informationto Highbury via Massey University, Constellation Station, Smales Farm Station, Akoranga Station and Northcote
b v Nc, g, F, C Uv Hgb p (p 4030) F g (p 4063) F (p 3353) L D (p 3848) 6.00 6.0 6.2 6.20 6.30 6.45 6.50 6.30 6.40 6.42 6.50 7.00 7.5 7.20 7.00 7.0 7.2 7.20 7.30 7.45 7.50 7.30 7.40 7.42 7.50 8.00 8.5 8.20
More information5 questions, 3 points each, 15 points total possible. 26 Fe Cu Ni Co Pd Ag Ru 101.
Physical Chemistry II Lab CHEM 4644 spring 2017 final exam KEY 5 questions, 3 points each, 15 points total possible h = 6.626 10-34 J s c = 3.00 10 8 m/s 1 GHz = 10 9 s -1. B= h 8π 2 I ν= 1 2 π k μ 6 P
More informationPERFORMANCE ANALYSIS OF SHELL AND TUBE HEAT EXCHANGERS USING AN EDUCATIONAL APPLICATION
Fundamental J. Thermal Science and Engineering, Vol. 2, Issue 1, 2012, Pages 37-52 Published online at http://www.frdint.com/ PERFORMANCE ANALYSIS OF SHELL AND TUBE HEAT EXCHANGERS USING AN EDUCATIONAL
More informationINSTRUCTOR: PM DR MAZLAN ABDUL WAHID
SMJ 4463: HEAT TRANSFER INSTRUCTOR: PM DR MAZLAN ABDUL WAHID http://www.fkm.utm.my/~mazlan TEXT: Introduction to Heat Transfer by Incropera, DeWitt, Bergman, Lavine 5 th Edition, John Wiley and Sons DR
More informationBENGKEL TEKNIK FIZIK SPA Maktab Tentera Diraja. Success is depend on your mind and your will. You are the one, who decide it. PROVE IT!!
thongks 2012 1 BENGKEL TEKNIK FIZIK 2016 SPA Maktab Tentera Diraja Success is depend on your mind and your will. You are the one, who decide it. PROVE IT!! Penceramah : Thong Kum Soon 1 thongks 2012 2
More informationLAMPIRAN A: LISTING PROGRAM
LAMPIRAN A: LISTING PROGRAM 1. Form Reduksi Aritmetik (AMF)Noise Dim BC Dim AA, BB, AAA, BBB As Integer Dim JB Private Declare Function SetPixel Lib "gdi32" (ByVal hdc As Long, ByVal X As Long, ByVal Y
More information[ ]:543.4(075.8) 35.20: ,..,..,.., : /... ;. 2-. ISBN , - [ ]:543.4(075.8) 35.20:34.
.. - 2-2009 [661.87.+661.88]:543.4(075.8) 35.20:34.2373-60..,..,..,..,.. -60 : /... ;. 2-. : -, 2008. 134. ISBN 5-98298-299-7 -., -,,. - «,, -, -», - 550800,, 240600 «-», -. [661.87.+661.88]:543.4(075.8)
More informationFRAGMENT REWEIGHTING IN LIGAND-BASED VIRTUAL SCREENING ALI AHMED ALFAKIABDALLA ABDELRAHIM
i FRAGMENT REWEIGHTING IN LIGAND-BASED VIRTUAL SCREENING ALI AHMED ALFAKIABDALLA ABDELRAHIM A thesis submitted in fulfilment of the requirements for the award of the degree of Doctor of Philosophy (Computer
More information02/05/09 Last 4 Digits of USC ID: Dr. Jessica Parr
Chemistry 05 B First Letter of PLEASE PRINT YOUR NAME IN BLOCK LETTERS Exam last Name Name: 02/05/09 Last 4 Digits of USC ID: Dr. Jessica Parr Lab TA s Name: Question Points Score Grader 2 2 9 3 9 4 2
More informationQRPA calculations of stellar weak-interaction rates
QRPA calculations of stellar weak-interaction rates P. Sarriguren Instituto de Estructura de la Materia CSIC, Madrid, Spain Zakopane Conference on Nuclear Physics: Extremes of Nuclear Landscape. August
More informationHeat Transfer Enhancement of Shell and Tube Heat Exchanger Using Conical Tapes.
ISSN : 2248-9622, Vol. 4, Issue 12( Part 3), December 214, pp.6-11 RESEARCH ARTICLE OPEN ACCESS Heat Transfer Enhancement of Shell and Tube Heat Exchanger Using Conical Tapes. Dhanraj S.Pimple 1,Shreeshail.B.H
More information35H MPa Hydraulic Cylinder 3.5 MPa Hydraulic Cylinder 35H-3
- - - - ff ff - - - - - - B B BB f f f f f f f 6 96 f f f f f f f 6 f LF LZ f 6 MM f 9 P D RR DD M6 M6 M6 M. M. M. M. M. SL. E 6 6 9 ZB Z EE RC/ RC/ RC/ RC/ RC/ ZM 6 F FP 6 K KK M. M. M. M. M M M M f f
More informationNUMERICAL ANALYSIS OF PARALLEL FLOW HEAT EXCHANGER
NUMERICAL ANALYSIS OF PARALLEL FLOW HEAT EXCHANGER 1 Ajay Pagare, 2 Kamalnayan Tripathi, 3 Nitin Choudhary 1 Asst.Profesor at Indore institute of science and technology Indore, 2 Student at Indore institute
More informationInvesting in Brownfields: The Economic Benefits of the Clean Ohio Revitalization Fund
v Bwf: T E Bf f C O Rvz G O P C 2013 E v 21 S Pj 1!! 3 2 4! 5! 6 7! 8!! 9 10!! 11! 12 17! 18! 19 14 15! 16 13 20! 21! 1. N C Pk 2. Rvf 3. Tw 4. G Lk Tw 5. C C C/ H 6. Bk -U Rv Pj 7. S R S C 8. C Rv C 9.
More informationContents FREE!
Fw h Hu G, h Cp h w bu Vy Tu u P. Th p h pk wh h pp h. Th u y D 1 D 1 h h Cp. Th. Th hu K E xp h Th Hu I Ch F, bh K P pp h u. Du h p, K G u h xp Ch F. P u D 11, 8, 6, 4, 3. Th bk w K pp. Wh P p pp h p,
More informationChemistry 2 Exam Roane State Academic Festival. Name (print neatly) School
Name (print neatly) School There are fifteen question on this exam. Each question is weighted equally. n the answer sheet, write your name in the space provided and your answers in the blanks provided.
More informationRSU.Open App.Path & "/" & "RSI.mdb", "admin", "" End Sub
1 LISTING PROGRAM Program Modul Utama Global RSU As New ADODB.Connection Global rsrsu As New ADODB.Recordset Global rsganti As New ADODB.Recordset Global rsobat As New ADODB.Recordset Global rsdokter As
More informationOKANAGAN LANDING SEWER EXTENSION PROJEC
I XI PJC HICHCCK 2 - / P H I F CU PK HIC UI CK U UI P HC 35 X P B PX IV I IX PH MUI HI C CP P I M HI I. VI C F IV FHI BCK CMB CK B MM 30 C CH PI C MB P KM IZ B MB IV I H BCKC K 32 K V I I H I MU HI U KICKI
More informationThermal Design of Shell and tube heat Exchanger
King Abdulaziz University Mechanical Engineering Department MEP 460 Heat Exchanger Design Thermal Design of Shell and tube heat Exchanger March 2018 1 Contents 1-Introduction 2-Basic components Shell types
More informationOKANAGAN LANDING SEWER EXTENSION PROJEC
I XI PJC HICHCCK 1 - I /MI /P H I F CU PK HIC UI CK U UI P HC 35 X P B PX IV I IX PH MUI HI C CP P I M HI I. VI C F IV FHI BCK CMB CK B MM 30 C CH PI C MB P KM IZ B MB IV I H BCKC K 32 K V I I H I MU HI
More informationINSTRUCTION: This section consists of THREE (3) structured questions. Answer ALL questions.
SECTION A : 75 MARKS BAHAGIAN A : 75 MARKAH INSTRUCTION: This section consists of THREE (3) structured questions. Answer ALL questions. ARAHAN: Bahagian ini mengandungi TIGA (3) soalan berstruktur. Jawab
More informationLAMPIRAN A LISTING PROGRAM
LAMPIRAN A LISTING PROGRAM 1. Listing Program Utama Dim h As Integer, i As Integer, j As Integer Dim db(37, 2) As String Dim angka As String Private Sub Command1_Click() Command1.enabled = False Call TWAIN_LogFile(1)
More informationTHE INSTITUTE OF PAPER CHEMISTRY, APPLETON, WISCONSIN
BASE-LIE THE ISTITUTE OF PAPER CHEMISTRY, APPLETO, WISCOSI COTIUOUS BASE-LIE STUDY (MODIFIED) (MILL CORRUGATIG MEDIUM DATA FOR JAUARY, FEBRUARY, MARCH, 198) Project 69- Report Fifty-One A Progress Report
More informationFlint Ward 1 !( 1. Voting Precinct Map «13 «15 «10. Legend. Precinct Number. Precinct Boundaries. Streets. Hydrography. Date: 1/18/2017.
T c K Tb K p b b F H O N F H ff ff p V H G F Y 2 Rx G J J Kcbc T H F H p p p p H Hb Gc O R IOOO RTENT V Jc K Ox F Hb Ox F G x R b 6 1 R F R b c j p G E F 1 R p bb G H Gc Y Hb 2 F 3 4 b R K K V R H p Rbb
More information176 5 t h Fl oo r. 337 P o ly me r Ma te ri al s
A g la di ou s F. L. 462 E l ec tr on ic D ev el op me nt A i ng er A.W.S. 371 C. A. M. A l ex an de r 236 A d mi ni st ra ti on R. H. (M rs ) A n dr ew s P. V. 326 O p ti ca l Tr an sm is si on A p ps
More informationTHE QUALITY IMPROVEMENT OF CONCRETE PAVING PRODUCTS USING TAGUCHI METHODS
Jurnal Ilmiah Teknik Industri (207), Vol. 5 No., 44 53 THE QUALITY IMPROVEMENT OF CONCRETE PAVING PRODUCTS USING TAGUCHI METHODS Yulia Dwi Angelina and Sunday Noya Industrial Engineering Study Program
More informationAnswer all questions Jawab semua soalan [80 marks] [80 markah] f(x)
1 Diagram 1 shows the linear functions f. Rajah 1 menunjukkan fungsi linear f. Answer all questions Jawab semua soalan [80 marks] [80 markah] x 7 7 Set P f(x) 9 9 Set Q Diagram 1 Rajah 1 1 2 (a) State
More informationSOUTH. Bus Map. From 25 October travelsouthyorkshire.com/sbp
SOUT SFFIL u Mp F Ocb 1 N Sff p vb f Tv Su Y If Sff vuc/sp Sff u Pp - v Sff Sff u Pp cu w pv u w: u p bu w b vu c f u-p v Fqu vc ub f u Fw u c bu w w f cc v w cv f? 3 f-p p Sff bu Ipv cu fc b up % 0,000
More information[Lihat sebelah 50/2 SULIT
SULIT 5 50/ For Examiner s Use [Lihat sebelah 50/ SULIT For examiner s use SULIT 6 50/ Answer all questions. Jawab semua soalan. 1 Calculate the value of 15 4. Hitung nilai bagi 15 4. [ marks] [ markah]
More informationPART 1 Introduction to Theory of Solids
Elsevier UK Job code: MIOC Ch01-I044647 9-3-2007 3:03p.m. Page:1 Trim:165 240MM TS: Integra, India PART 1 Introduction to Theory of Solids Elsevier UK Job code: MIOC Ch01-I044647 9-3-2007 3:03p.m. Page:2
More informationEmpowers Families Unites Communities Builds Capacity. An In. Read and Rise. Cultivates Literacy
8 Emw Fm U Cmm B Cc g A I Y h P R c L DY : U T S E CAS g L b U N ff H I h H c D Sch R R Cv Lc CASE STUDY A Ig P h Y Lc R Th N Ub Lg H ff wh H I Sch Dc (HISD) c Schc R R, fcg cfc hw gg mw fm f h ch c h
More informationNapa Valley Intergroup July 8, 2017
Vy g Jy, g Mm f c & y y w g / w Cm ck: Y Wm mg mg, D G Wh f by by Bhy h Mh: L mh m (Yw Cy) & g h b (Wh Cy) M v h y bjc h g- h *vc Mhy g & Dc Dc- h g hmv gh b fy by h vy cb f h w mmb W hk h ch g h chv h
More informationHeroes. of the New Testament. Creative. Communications. Sample
H f h Nw T c My Dd y kw h y h? Y, y. Y h bc h hw Gd d y. Gd cd y h w g. Gd gd. Gd hy. Gd. Gd cd y b h hg. Wh y d hg h gd, hy g, y g h hc f Gd w f y. Af J, h g h h wh wd f-y-d g. Th gh. My w ch d h y wh
More informationOptimization of Radioisotope Production at Rsg-Gas Reactor Using Deterministic Method
Teknologi Indonesia 35 (2) Edisi Khusus 2012: 37 45 Teknologi Indonesia LIPI Press 2012 Optimization of Radioisotope Production at Rsg-Gas Reactor Using Deterministic Method S. Pinem, J. Susilo, Tukiran,
More informationDiagram 1 Rajah 1. Diagram 2 Rajah 2
1 Diagram 1 shows a circle WYZ with centre O. WXY and ZOX are straight lines. Rajah 1 menunjukkan sebuah bulatan WYZ yang berpusat O. WXY dan ZOX ialah garis lurus. Diagram 1 Rajah 1 Given that OX = 9
More informationANOLYTE SOLUTION GENERATED FROM ELECTROCHEMICAL ACTIVATION PROCESS FOR THE TREATMENT OF PHENOL
ANOLYTE SOLUTION GENERATED FROM ELECTROCHEMICAL ACTIVATION PROCESS FOR THE TREATMENT OF PHENOL By ZAULFIKAR Thesis Submitted to the School of Graduate Studies, Universiti Putra Malaysia, in Fulfilment
More informationHANDOUT SET GENERAL CHEMISTRY II
HANDOUT SET GENERAL CHEMISTRY II Periodic Table of the Elements 1 2 3 4 5 6 7 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 IA VIIIA 1 2 H He 1.00794 IIA IIIA IVA VA VIA VIIA 4.00262 3 Li 6.941 11 Na 22.9898
More informationPhysics 100 Lecture 5. Laws of Thermodynamics February 5, 2018
3 Physics 100 Lecture 5 Laws of Thermodynamics February 5, 2018 4 Class Quiz 2-3: A block of wood loses 100 J of gravitational potential energy as it slides down a ramp. If it has 90 J of kinetic energy
More informationOverload Relays. SIRIUS 3RU1 Thermal Overload Relays. 3RU11 for standard applications. 5/46 Siemens LV 1 AO 2011
SIRIUS 3RU1 Thermal Overview 1 2 7 3 4 6 "Increased safety" type of EEx e according to ATEX directive 94/9/EC The 3RU11 thermal overload relays are suitable for the overload of explosion-proof motors with
More informationMONTE CARLO SIMULATION OF NEUTRON RADIOGRAPHY 2 (NUR-2) SYSTEM AT TRIGA MARK II RESEARCH REACTOR OF MALAYSIAN NUCLEAR AGENCY
MONTE CARLO SIMULATION OF NEUTRON RADIOGRAPHY 2 (NUR-2) SYSTEM AT TRIGA MARK II RESEARCH REACTOR OF MALAYSIAN NUCLEAR AGENCY MASITAH BINTI OTHMAN UNIVERSITI TEKNOLOGI MALAYSIA MONTE CARLO SIMULATION OF
More informationMAT 101 Calculus [ Kalkulus]
UNIVERSITI SAINS MALAYSIA Peperiksaan Kursus Semasa Cuti Panjang 01/013 Sidang Akademik Ogos 013 MAT 101 Calculus [ Kalkulus] Duration : 3 hours [Masa : 3 jam] Please check that this eamination paper consists
More information8. Relax and do well.
CHEM 1515 Exam II John II. Gelder October 14, 1993 Name TA's Name Lab Section INSTRUCTIONS: 1. This examination consists of a total of 8 different pages. The last two pages include a periodic table, a
More informationT718. c Dr. Md. Zahurul Haq (BUET) HX: Energy Balance and LMTD ME 307 (2018) 2/ 21 T793
HX: Energy Balance and LMTD Dr. Md. Zahurul Haq Professor Department of Mechanical Engineering Bangladesh University of Engineering & Technology (BUET) Dhaka-000, Bangladesh http://zahurul.buet.ac.bd/
More informationMATEMATIK KERTAS 1 (1449/1) SET 6
MATEMATIK KERTAS 1 (1449/1) SET 6 1 Round off 34. 376 correct to three significant figures. Bundarkan 34. 376 betul kepada tiga angka bererti. A 34. 3 B 34. 4 C 34. 38 D 34. 40 2 Express 395 000 in the
More informationCSE 215: Foundations of Computer Science Recitation Exercises Set #5 Stony Brook University. Name: ID#: Section #: Score: / 4
CSE 215: Foundations of Computer Science Recitation Exercises Set #5 Stony Brook University Name: ID#: Section #: Score: / 4 Unit 10: Proofs by Contradiction and Contraposition 1. Prove the following statement
More informationBlues. G.S.P.T. Blue. U7233 Blue with a green face and slightly red flop. H.S. Indo Blue
Bs C Bs C p.s.p.t. B U7233 B wh fc shy fp. H.S. I B U7235 O s sh b h fc fp. vs cs bh s mc cs. Apps vy y wh s mm k s bs. Occ B U7046 B wh fc fp. Az B U7048 B wh vy fc fp. L.S. B U7276 Us cs mx cccy whs,
More informationCh. 9 NOTES ~ Chemical Bonding NOTE: Vocabulary terms are in boldface and underlined. Supporting details are in italics.
Ch. 9 NOTES ~ Chemical Bonding NOTE: Vocabulary terms are in boldface and underlined. Supporting details are in italics. I. Review: Comparison of ionic and molecular compounds Molecular compounds Ionic
More informationADORO TE DEVOTE (Godhead Here in Hiding) te, stus bat mas, la te. in so non mor Je nunc. la in. tis. ne, su a. tum. tas: tur: tas: or: ni, ne, o:
R TE EVTE (dhd H Hdg) L / Mld Kbrd gú s v l m sl c m qu gs v nns V n P P rs l mul m d lud 7 súb Fí cón ví f f dó, cru gs,, j l f c r s m l qum t pr qud ct, us: ns,,,, cs, cut r l sns m / m fí hó sn sí
More informationCoolsicles. Chicken Tenders. Hearty Beef Stew
Cck T M B Cck P Cc Hy B Sw D Ec, Ec pp y y cc y w C F K TM c p b y by N Fz R F Ac (NFRA) pp w cc pc Y M Ip (YMI). T p y cc w $50 pp y c ( ). C F K TM p c b cc, p c, b pyc cvy. I w y wk b pv w v w pc w
More information-$! " #$%&! ' () * +,,,)* -./ ( 01! 6 %&! +,,.: - 1?* 'F! %&! '3*4 -$ ):7 +,,
((((( +,-. ()* $%&' "#! : :!, %& ' ()*+ $ " -$! " #$%&! ' () * +,,,)* -. ( 01! '% 6):7 -$'1& '*6 )78 %&! +,, 79.& 2* '3*4 0 (A 6>* & ' BC D$!E.?@$* '*! ;4 6 %&! +,,.: - 1?* 'F! %&! '3*4 -$ ):7
More informationNumerical Investigation of Heat Transfer Enhancement and Pressure Drop of a Double Tube Heat Exchanger with Rectangular Fins in the Annulus Side
International Journal of Dynamics of Fluids. ISSN 0973-1784 Volume 13, Number 2 (2017), pp. 295-308 Research India Publications http://www.ripublication.com Numerical Investigation of Heat Transfer Enhancement
More informationFaculty of Natural and Agricultural Sciences Chemistry Department. Semester Test 1. Analytical Chemistry CMY 283. Time: 120 min Marks: 100 Pages: 6
Faculty of Natural and Agricultural Sciences Chemistry Department Semester Test 1 Analytical Chemistry CMY 283 Date: 5 September 2016 Lecturers : Prof P Forbes, Dr Laurens, Mr SA Nsibande Time: 120 min
More informationDiagram 1.1. (ii) Compare the change of momentum of Plasticine A and B Bandingkan perubahan momentum bagi plastesin A dan B.
CERAMAH FIZIK 2013 SMS SERI PUTERI (TKS) 1.Diagram 1.1 shows identical spherical plasticine balls, A and B, before being released from the same height. Diagram 1.2 shows the state of the plasticine balls
More informationUniversitas Sumatera Utara
Lampiran 1 function [PN1]=pnsequence(d) G=d*2; % Code length %Generation of first m-sequence using generator polynomial [45] sd1 =[0 0 0 0 1]; % Initial state of Shift register PN1=[]; % First m-sequence
More informationSIMULATION OF THE SEAWATER HEAT EXCHANGER WITH HELICAL BAFFLES. Qingnan Huang Shanghai Jiao Tong University, China
SIMULATION OF THE SEAWATER HEAT EXCHANGER WITH HELICAL BAFFLES Qingnan Huang Shanghai Jiao Tong University, China Outlines Background Simulation Methods Property Calculation Method Algorithm Design Flow
More informationMath 308 Exam I Practice Problems
Math 308 Exam I Practice Problems This review should not be used as your sole source of preparation for the exam. You should also re-work all examples given in lecture and all suggested homework problems..
More informationExecutive Committee and Officers ( )
Gifted and Talented International V o l u m e 2 4, N u m b e r 2, D e c e m b e r, 2 0 0 9. G i f t e d a n d T a l e n t e d I n t e r n a t i o n a2 l 4 ( 2), D e c e m b e r, 2 0 0 9. 1 T h e W o r
More informationElement Cube Project (x2)
Element Cube Project (x2) Background: As a class, we will construct a three dimensional periodic table by each student selecting two elements in which you will need to create an element cube. Helpful Links
More informationRanking accounting, banking and finance journals: A note
MPRA Munich Personal RePEc Archive Ranking accounting, banking and finance ournals: A note George Halkos and Nickolaos Tzeremes University of Thessaly, Department of Economics January 2012 Online at https://mpra.ub.uni-muenchen.de/36166/
More informationThese notes will supplement the textbook not replace what is there. defined for α >0
Gamma Distribution These notes will supplement the textbook not replace what is there. Gamma Function ( ) = x 0 e dx 1 x defined for >0 Properties of the Gamma Function 1. For any >1 () = ( 1)( 1) Proof
More informationFormulas and Constants (you may remove this page)
Formulas and Constants (you may remove this page) NA = 6.0x0 3 mol - h = 6.66x0-34 J s c =.99x0 m s - e =.60x0-9 C me = 9.09x0-3 kg Å = x0-0 m = 00 pm atm = 760 torr R = 0.006 L atm K - mol - =.34 J K
More informationOIL & GAS EQUIPMENT RENTAL SOLUTIONS
I A EQUIE EA UI by.c YE Eqp Wh v 65% f h w v 40% f h w v h E. W hv cy p p c h c q. y Eqp w f h UAE h y 1990 c h h w bc f h p qp cp h E. Wh 15 p b cv h UAE KA Kw Q h w hv f f v 10000 f p f v 800 pp. W ff
More informationComputational Fluid Dynamics of Parallel Flow Heat Exchanger
International Journal of Sciences: Basic and Applied Research (IJSBAR) ISSN 2307-4531 (Print & Online) http://gssrr.org/index.php?journal=journalofbasicandapplied ---------------------------------------------------------------------------------------------------------------------------
More informationPart Two. Southern Florida s Early Native People
19 www.m.. 2002 F Mm N H, G, F P Tw S F E N P 20 2002 F Mm N H, G, F www.m.. P b P O b gg g c. I c m c Iq Bx Mm. S F E N P T m S F E N P Iq Bx, Mm wb www.m... W w F w? T g m w c w F 500 BCE c C ( m g -cc),
More informationReanalysis of the Reactor Neutrino Anomaly
LA-UR-13-24535 Reanalysis of the Reactor Neutrino Anomaly A. Hayes, J. Friar, G. Garvey, G. Jungman (LANL) G. Jonkmans (Chalk River) INT 5 th Nov 2013 The Reactor Antineutrino Anomaly The Reactor Neutrino
More informationDesigning Steps for a Heat Exchanger ABSTRACT
Designing Steps for a Heat Exchanger Reetika Saxena M.Tech. Student in I.F.T.M. University, Moradabad Sanjay Yadav 2 Asst. Prof. in I.F.T.M. University, Moradabad ABSTRACT Distillation is a common method
More informationSolving Integral Equations by Petrov-Galerkin Method and Using Hermite-type 3 1 Elements
5 1 July 24, Antalya, Turkey Dynamical Systems and Applications, Proceedings, pp. 436 442 Solving Integral Equations by Petrov-Galerkin Method and Using Hermite-type 3 1 Elements M. Karami Department of
More informationATTACHMENT 1. MOUNTAIN PARK LAND Page 2 of 5
ATTACHMENT 53 YOBA LINDA Gyp Yb gl 9 Gt Fthly gl t 247 Mt Utct cl Mt Gyp 248 248X A0 A0 Hghy G:\jct\K00074232_p_Iv_Cp_L_Dt_204\MXD\p_Iv_Cp_L_Dt_(K00074232)_0-29-204.x C ( l t b t f y p b lc ly ) Ch Hll
More informationTUESDAY JULY Concerning an Upcoming Change Order for the Clearwell Project. Pages 28 SALLISAW MUNICIPAL AUTHORITY SPECIAL MEETING
SSW MUCP UTHOT SPEC MEETG TUESD U 2 200 0 00M SSW WTE TETMET PT COEECE OOM EPPE OD GED Mg Cd T Od 2 Dc Quum 3 c B P m B P h H W Eg Ccg Upcmg Chg Od h C Pjc Cd d Cc d Ep Ph Pjc Pg 28 dju Pd u 22 200 Tm
More informationMAA Calculus for Science Students I [Kalkulus untuk Pelajar Sains I]
UNIVERSITI SAINS MALAYSIA First Semester Eamination Academic Session 6/7 December 6 / January 7 MAA - Calculus for Science Students I [Kalkulus untuk Pelajar Sains I] Duration : 3 hours [Masa : 3 jam]
More informationPFR with inter stage cooling: Example 8.6, with some modifications
PFR with inter stage cooling: Example 8.6, with some modifications Consider the following liquid phase elementary reaction: A B. It is an exothermic reaction with H = -2 kcal/mol. The feed is pure A, at
More informationParts Manual. EPIC II Critical Care Bed REF 2031
EPIC II Critical Care Bed REF 2031 Parts Manual For parts or technical assistance call: USA: 1-800-327-0770 2013/05 B.0 2031-109-006 REV B www.stryker.com Table of Contents English Product Labels... 4
More information