# 1 Fig. 3.1 shows the variation of the magnetic flux linkage with time t for a small generator. magnetic. flux linkage / Wb-turns 1.

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1 1 Fig. 3.1 shows the variation of the magnetic flux linkage with time t for a small generator. 2 magnetic 1 flux linkage / Wb-turns t / 10 3 s Fig. 3.1 The generator has a flat coil of negligible resistance that is rotated at a steady frequency in a uniform magnetic field. The coil has 400 turns and cross-sectional area m 2. The output from the generator is connected to a resistor of resistance 150 Ω. (a) Use Fig. 3.1 to calculate the frequency of rotation of the coil frequency =... Hz [1] calculate the magnetic flux density B of the magnetic field B =... T [3]

2 (iii) show that the maximum electromotive force (e.m.f.) induced in the coil is about 12 V. [3] (b) Hence calculate the maximum power dissipated in the resistor. power =... W [2] [Total: 9]

3 2 (a) Define electromotive force.... [1] (b) Define magnetic flux.... [1] (c) Fig. 1.1 shows a simple transformer. soft iron core n p n s output primary coil secondary coil Fig. 1.1 The primary coil is connected to an alternating voltage supply. Explain how an e.m.f. is induced in the secondary coil.... [3]

4 State how you could change the transformer to increase the maximum e.m.f. induced in the secondary coil.... [1] (d) A transformer with 4200 turns in the primary coil is connected to a 230 V mains supply. The e.m.f. across the output is 12 V. Assume the transformer is 100% efficient. Calculate the number of turns in the secondary coil. number of turns =... [2] The transformer output terminals are connected to a lamp using leads that have a total resistance of 0.35 Ω. The p.d. across the lamp is 11.8 V. Calculate 1 the current in the leads connected to the lamp current =... A [2] 2 the power dissipated in the leads. power =... W [2] [Total: 12]

5 3 Fig. 5.1 shows a rigid, straight metal rod XY placed perpendicular to a magnetic field. The magnetic field is produced by two magnets that are placed on a U-shaped steel core. The steel core sits on a digital balance. steel core X m magnets S Y A balance Fig. 5.1 The weight of the steel core and the magnets is N. The rod is clamped at points X and Y. The rod is connected to a battery, switch and ammeter as shown in Fig The direction of the magnetic field is perpendicular to the rod. Switch S is closed. (a) State the direction of the force that now acts on the rod due to the magnetic field.... [1] (b) State how you determined the direction of the force.... [1] (c) The length of the rod in the magnetic field is m and the current in the rod is 4.0 A. Assume that the magnets provide a uniform magnetic field of magnetic flux density 0.080T. Calculate the force acting on the rod due to the magnetic field. force =... N [1]

6 State and explain the new reading on the balance. reading on balance =... N... [3] (d) The rod is replaced by another rod of the same material having half the diameter of the first wire and the same length. The potential difference across this rod is the same. Calculate the force on this rod due to the magnetic field. force =... N [3] [Total: 9]

7 4 (a) Fig. 3.1 shows two charged horizontal plates. +60 V 5.0 mm 0 V Fig. 3.1 The potential difference across the plates is 60 V. The separation of the plates is 5.0 mm. On Fig. 3.1 draw the electric field pattern between the plates. Calculate the electric field strength between the plates. [2] electric field strength =...V m 1 [1] (b) Positive ions are accelerated from rest in the horizontal direction through a potential difference of 400 V. The charged plates in (a) are then used to deflect the ions in the vertical direction. Fig. 3.2 shows the path of these ions. source of ions +60 V 0 V 400 V 0 V 5.0 mm 16 mm Fig. 3.2

8 Each ion has a mass of kg and a charge of C. Show that the horizontal velocity of an ion after the acceleration by the 400 V potential difference is m s 1. [2] The ions enter at right angles to the uniform electric field between the plates. Calculate the vertical acceleration of an ion due to this electric field. acceleration =... m s 2 [2] (iii) The length of each of the charged plates is 16 mm. 1 Show that an ion takes about s to travel through the plates. [1] 2 Calculate the vertical deflection of an ion as it travels through the plates. deflection =... m [2]

9 (c) A uniform magnetic field is applied in the region between the plates in Fig The magnetic field is perpendicular to both the path of the ions and the electric field between the plates. Calculate the magnitude of the magnetic flux density of field needed to make the ions travel horizontally through the plates. magnetic flux density =... T [3] (d) Ions of the same charge but greater mass are accelerated by the potential difference of 400 V described in (b). Describe and explain the effect on the deflection of the ions after they have travelled between the plates using the same electric and magnetic fields of (c).. [2] [Total: 15]

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Coordinator: Saleem Rao Tuesday, August 22, 2017 Page: 1 Q1. A 125 cm long string has a mass of 2.00 g and a tension of 7.00 N. Find the lowest resonant frequency of the string. A) 2.5 Hz B) 53.0 Hz C)