Mathematics Paper- II
|
|
- Esmond Hodges
- 5 years ago
- Views:
Transcription
1 R Prerna Tower, Road No -, Conracors Area, Bisupur, Jamsedpur - 8, Tel - (65789, Maemaics Paper- II Jee Advance PART III - MATHEMATICS SECTION - : (One or more opions correc Type Tis secion conains muliple coice quesions. Eac quesion as four coices (A, (B, (C and (D, ou of wic ONLY ONE opion is correc.. Te quadraic equaion p( = wi real coefficiens as purely imaginary roos.ten p(p( = as (A only purely imaginary roos (B all real roos (C wo real and wo purely imaginary roos (D neier real nor purely imaginary roos. (D Since, b = for p( = a + b + c, as roos are pure imaginary. ( c i c wic are clearly neier pure real nor pure imaginary, as c. a. Tree boys and wo girls sand in a queue. Te probabiliy, a e number of boys aead of every girl is a leas one more an e number of girls aead of er, is (A / (B / (C / (D /. (A Possible cases : B, G, G, B, B G, G, B,B, B G, B, G, B, B G, B, B, G, B B, G, B, G, B n(e = 5 = 6 P(E = 6 / 5! = /.. Si cards and si envelopes are numbered,,,, 5, 6 and cards are o be placed in envelopes so a eac envelope conains eacly one card and no card is placed in e envelope bearing e same number and moreover e card numbered is always placed in envelope numbered. Ten e number of ways i can be done is (A 6 (B 65 (C 5 (D 67. (C Toal derrangemen of 6 cards = D(6 = = A( + A( + A( + A(5 + A(6 [Cases wen envelope (or A as or or or 5 or 6 numbered card all are equally likely] 65 = 5 A( A( = 5. JEE Advanced (5-May- Quesion & Soluions Paper-II -- www. prernaclasses.com
2 . In a riangle e sum of wo sides is and e produc of e same wo sids is y. If c = y, were c is e ird side of e riangle, en e raio of e in-radius o e circum-radius of e riangle is ( c (A (B c( c (C ( c. (B a + b =, ab = y, c = y a b c c S (D c( c c = y (a + b c a b c = ab / ab cos c = / c = /.. a. b. sin r / s R abc / abc. s c. y. c ( c. c 5. Te common angens o e circle + y = and e parabola y = 8 ouc e circle a e poins P, Q and e parabola a e poins R, S. Ten e area of e quardilaeral PQRS is (A (B 6 (C 9 (D 5 5. (D P Q Equaion of angen PR, P(, S y m, m Wic is also angen o circle + y =. m m = m Ps of conac R & S are (, and (, and P, Q are (, & (, Area of quardilaeral PQRS = ½ [ + 8] = 5. JEE Advanced (5-May- Quesion & Soluions Paper-II -- www. prernaclasses.com
3 6. Te funcion y = f ( is e soluion of e differenial equaion saisfying f ( =. Ten / f ( d is / dy y in (, d (A ( / ( / (B ( / ( / (C ( / 6 ( / (D ( / 6 ( / dy y 6. (B I.F. = d e Sol n 5 is y d ( / 5 c / 5 ( / 5 f ( =, c = f ( d ( / ( /. / / 7. Le f : [, ] R be a funcion wic is coninuous on [, ] and is differeniable on (, wi / f ( =. Le f ( f ( d for [, ]. If F' ( = f ' ( for all (,, en F( equals (A e (B e (C e (D e 7. (B F' ( = f (. f ' ( = f (. F( e d e. f ( e wi = 8. Coefficien of in e epansion of ( + ( + 7 ( + is (A 5 (B 6 (C (D 8. (C C. 7 C. C + C. 7 C. 6 C + 7 C C + 7 C C =. 9. For (,, e equaion sin + sin sin = as (A infiniely many soluions (B ree soluions (C one soluion (D no soluion 9. (D (sin sin + sin = sin (cos cos = cos cos = sin Clearly cos cos /, equaliy old wen cos = ½ sin sin Hence no soluion in (, JEE Advanced (5-May- Quesion & Soluions Paper-II -- www. prernaclasses.com
4 5. Te following inegral / 7 (cosec d is equal o / (A log( ( e u e u 6 du (B log( ( e u e u 7 du log( (C ( e u e u 7 du (D log( 5. (A Pu cosec = e u + e u co = e u e u I ln( ln( ( e u u 7 du u u 6 ( e e ( e e du. cosec u e u SECTION - (Paragrap Type Tis secion conains paragraps eac describing eory, eperimens, daa ec. Si quesions relae o ree paragraps wi wo quesions on eac paragrap. Eac quesion as only one correc answer among e four coices (A, (B, (C and (D. Paragrap for Quesions 5 and 5 Bo conains ree cards bearing numbers,,; bo conains five cards bearing numbers,,,, 5; and bo conains seven cards bearing numbers,,,, 5, 6, 7. A card is drawn from eac of e boes. Le i be e number on e card drawn from e i bo, i =,,. 5. Te probabiliy a + + is odd, is (A 9 / 5 (B 5 / 5 (C 57 / 5 (D / 5. Te probabiliy a,, are in an arimeic progression, is (A 9 / 5 (B / 5 (C / 5 (D 7 / 5 Sol. 5. (B 5. (C 5. n(s = 5 7 = : odd Case I : all ree odd =. Case II : wo even and one odd = + + n(e = 5 P(E = 5 / 5. 5.,, in A.P. AP wi cd =, (,,, (,, (,, 5 cd =, (,, 5, (,,6 (, 5, 7 cd =, (,, 7 cd =, (,,, (,, (,, cd =, (,, P(E = / 5. 6 du JEE Advanced (5-May- Quesion & Soluions Paper-II -- www. prernaclasses.com
5 Paragrap for quesion 5 and 5 Le a, r, s, be non zero real numbers. Le P(a, a, Q, R(ar, ar and S(as, as be disinc poins on e parabola y = a. Suppose a PQ is e focal cord and lines QR and PK are parallel, were K is e poin (a,. 5. Te value of r is (A / (B (C / (D 5. If s =, en e angen a P and e normal a S o e parabola mee a a poin wose ordinae is ( (A Sol. 5. (D 5. (B 5. m QR = m PK a( (B ar (a / a ar ( a / a a a( (C r = 5. Tangen a P : y = + a y s = a... (i Normal a s : y + s = as + as... (ii a( (i + (ii y = Given a for eac a (,,. a( (D ParParagrap for quesion 55 and 56agrap for quesion 5 and 5 Lim a a given a e funcion g(a is differeniable on (,. ( d eiss. Le is limi be g(a. In addiion, i is 55. Te value of g( / is (A (B (C / (D / 56. Te value of g' ( / is (A / (B (C / (D Sol. 55. (A 56. (D d 55. g(/ Lim Lim sin (( sin ( ( = sin ( sin ( =. a 56. g' ( a Lim g'. ( a. ln d b b Lim / / ( /. (. ln d [Using d a a / / Lim (.. ln d f ( f ( a b d ] JEE Advanced (5-May- Quesion & Soluions Paper-II -5- www. prernaclasses.com
6 g' ( / =. SECTION - : Macing Lis Type (Only One Opion Correc Tis secion conains four quesions, eac aving wo macing liss. Coices for e correc combinaion of elemens from Lis - I and Lis - II are given as opions (A, (B, (C and (D, ou of wic one is correc. 57. Lis I Lis II P. Te number of polynomials f ( wi non -negaive. 8 ineger coefficiens of degree, saisfying f ( = and f ( d, is Q. Te number of poins in e inerval [, ] a wic. f ( = sin ( + cos ( aains is maimum value, is R. S. ( e d equals. / cos log d / equals. / cos log d Codes P Q R S (A (B (C (D 57. (D (P f ( = a + b [ f ( = ] f ( d (a / + (b / = a + b = 6 Hence, a =, b = or a =, b = Hence only wo polynomials (Q f ( = sin ( + ( / f ' ( = cos ( + ( / = Hence, = or + ( / = (n + ( / Values of in [, ] are, ± /, ± /, ± /, ± / Hence poins of maima. (R I d d d 6 I = 8. e e JEE Advanced (5-May- Quesion & Soluions Paper-II -6- www. prernaclasses.com
7 / (S f ( cos log is an odd funcion. Hence f ( d. 58. Lis I Lis II P. Le y( = cos ( cos, [, ], ± /.. / d y( dy( Ten ( y( d d equals Q. Le A, A,..., A n (n > be e verices of a regular. polygon of n sides wi is cenre a e origin. Le a be e posiion vecor of e poin A k, k =,,..., n. k n n If a k ak a k. ak k k, en e minimum value of n is R. If e normal from e poin P(, on e ellipse. 8 y 6 is perpendicular o e line + y = 8, en e value of is S. Number of posiive soluions saisfying e equaion. 9 an an an Codes P Q R S (A (B (C (D 58. (A (P y( = cos ( = cos = y( is ( y'' y' ( ( 9 n n (Q a k ak a k. ak k k (n sin ( / n = (n cos ( / n an ( / n = minimum n = 8. (R Normal a, 6 sec y cosec = (6 sec / ( cosec = an = / Hence, normal y = n =. (S. =, /. JEE Advanced (5-May- Quesion & Soluions Paper-II -7- www. prernaclasses.com
8 Hence, number of posiive soluions =. 59. Le f : R R, f : [, R, f : R R and f : R [, be defined by if ( f ; f e if ( = sin if ; ( f( f( if f and f( if f( f( if Lis I Lis II P. f is. ono bu no one-one Q. f is. neier coninuous nor one-one R. f of is. differeniable bu no one-one S. f is. coninuous and one-one Codes P Q R S (A (B (C (D 59. (D f ( : f ( : f ( : f of ( e y = y = sin y = e y = f ( : No sarp corner Differeniable bu no one-one y = Ono bu no one-one,, N.D. y = e y = JEE Advanced (5-May- Quesion & Soluions Paper-II -8- www. prernaclasses.com
9 neier coninuous nor one-one. 6. k k Le z k cos i sin ; k =,,..., 9. Lis I Lis II P For eac z k ere eiss a z j suc a z k. z j =. True Q Tere eiss a k {,,..., 9} suc a. False z. z = z k as no soluion z in e se of comple numbers. R. z z... z9 equals. 9 k S. cos equals. k Codes P Q R S (A (B (C (D 6. (C Clearly, z k = k were z k For (P : z k. z j = e i ( / (k + j =, if k + j = muliple of i.e. possible for eac k. For (Q : z. z = z k is clearly incorrec. For (R : Epression = z Lim z z 9 k For (S + z k = cos k Epression =. JEE Advanced (5-May- Quesion & Soluions Paper-II -9- www. prernaclasses.com
Additional Exercises for Chapter What is the slope-intercept form of the equation of the line given by 3x + 5y + 2 = 0?
ddiional Eercises for Caper 5 bou Lines, Slopes, and Tangen Lines 39. Find an equaion for e line roug e wo poins (, 7) and (5, ). 4. Wa is e slope-inercep form of e equaion of e line given by 3 + 5y +
More informationADDITIONAL MATHEMATICS PAPER 1
000-CE A MATH PAPER HONG KONG EXAMINATIONS AUTHORITY HONG KONG CERTIFICATE OF EDUCATION EXAMINATION 000 ADDITIONAL MATHEMATICS PAPER 8.0 am 0.0 am ( hours This paper mus be answered in English. Answer
More informationThe Quantum Theory of Atoms and Molecules: The Schrodinger equation. Hilary Term 2008 Dr Grant Ritchie
e Quanum eory of Aoms and Molecules: e Scrodinger equaion Hilary erm 008 Dr Gran Ricie An equaion for maer waves? De Broglie posulaed a every paricles as an associaed wave of waveleng: / p Wave naure of
More informationSections 2.2 & 2.3 Limit of a Function and Limit Laws
Mah 80 www.imeodare.com Secions. &. Limi of a Funcion and Limi Laws In secion. we saw how is arise when we wan o find he angen o a curve or he velociy of an objec. Now we urn our aenion o is in general
More informationû s L u t 0 s a ; i.e., û s 0
Te Hille-Yosida Teorem We ave seen a wen e absrac IVP is uniquely solvable en e soluion operaor defines a semigroup of bounded operaors. We ave no ye discussed e condiions under wic e IVP is uniquely solvable.
More informationAP Calculus BC Chapter 10 Part 1 AP Exam Problems
AP Calculus BC Chaper Par AP Eam Problems All problems are NO CALCULATOR unless oherwise indicaed Parameric Curves and Derivaives In he y plane, he graph of he parameric equaions = 5 + and y= for, is a
More informationln y t 2 t c where c is an arbitrary real constant
SOLUTION TO THE PROBLEM.A y y subjec o condiion y 0 8 We recognize is as a linear firs order differenial equaion wi consan coefficiens. Firs we sall find e general soluion, and en we sall find one a saisfies
More informationPrerna Tower, Road No 2, Contractors Area, Bistupur, Jamshedpur , Tel (0657) , PART III MATHEMATICS
R Prerna Tower, Road No, Contractors Area, Bistupur, Jamshedpur 8300, Tel (0657)89, www.prernaclasses.com Jee Advance 03 Mathematics Paper I PART III MATHEMATICS SECTION : (Only One Option Correct Type)
More informationComparison between the Discrete and Continuous Time Models
Comparison beween e Discree and Coninuous Time Models D. Sulsky June 21, 2012 1 Discree o Coninuous Recall e discree ime model Î = AIS Ŝ = S Î. Tese equaions ell us ow e populaion canges from one day o
More information( ) 2. Review Exercise 2. cos θ 2 3 = = 2 tan. cos. 2 x = = x a. Since π π, = 2. sin = = 2+ = = cotx. 2 sin θ 2+
Review Eercise sin 5 cos sin an cos 5 5 an 5 9 co 0 a sinθ 6 + 4 6 + sin θ 4 6+ + 6 + 4 cos θ sin θ + 4 4 sin θ + an θ cos θ ( ) + + + + Since π π, < θ < anθ should be negaive. anθ ( + ) Pearson Educaion
More information02. MOTION. Questions and Answers
CLASS-09 02. MOTION Quesions and Answers PHYSICAL SCIENCE 1. Se moves a a consan speed in a consan direcion.. Reprase e same senence in fewer words using conceps relaed o moion. Se moves wi uniform velociy.
More informationVIVEKANANDA VIDYALAYA MATRIC HR SEC SCHOOL, RAMESWARAM. Lesson 1 & 7 & Exercise 9.1 ( Unit Test -1 ) 10th Standard
VIVEKANANDA VIDYALAYA MATRIC HR SEC SCHOOL, RAMESWARAM Lesson 1 & 7 & Exercise 9.1 ( Unit Test -1 ) 10 Standard Date : 6-Oct-18 MATHEMATICS Reg.No. : Time : 01:30:00 Hrs Total Marks : 50 I. CHOOSE THE
More informationANALYSIS OF LINEAR AND NONLINEAR EQUATION FOR OSCILLATING MOVEMENT
УД 69486 Anna Macurová arol Vasilko Faculy of Manufacuring Tecnologies Tecnical Universiy of ošice Prešov Slovakia ANALYSIS OF LINEAR AND NONLINEAR EQUATION FOR OSCILLATING MOVEMENT Macurová Anna Vasilko
More informationFuzzy Laplace Transforms for Derivatives of Higher Orders
Maemaical Teory and Modeling ISSN -58 (Paper) ISSN 5-5 (Online) Vol, No, 1 wwwiiseorg Fuzzy Laplace Transforms for Derivaives of Higer Orders Absrac Amal K Haydar 1 *and Hawrra F Moammad Ali 1 College
More informationMA6151 MATHEMATICS I PART B UNIVERSITY QUESTIONS. (iv) ( i = 1, 2, 3,., n) are the non zero eigen values of A, then prove that (1) k i.
UNIT MATRICES METHOD EIGEN VALUES AND EIGEN VECTORS Find he Eigen values and he Eigenvecors of he following marices (i) ** 3 6 3 (ii) 6 (iii) 3 (iv) 0 3 Prove ha he Eigen values of a real smmeric mari
More informationF (u) du. or f(t) = t
8.3 Topic 9: Impulses and dela funcions. Auor: Jeremy Orloff Reading: EP 4.6 SN CG.3-4 pp.2-5. Warmup discussion abou inpu Consider e rae equaion d + k = f(). To be specific, assume is in unis of d kilograms.
More informationOn two general nonlocal differential equations problems of fractional orders
Malaya Journal of Maemaik, Vol. 6, No. 3, 478-482, 28 ps://doi.org/.26637/mjm63/3 On wo general nonlocal differenial equaions problems of fracional orders Abd El-Salam S. A. * and Gaafar F. M.2 Absrac
More informationApproximating the Powers with Large Exponents and Bases Close to Unit, and the Associated Sequence of Nested Limits
In. J. Conemp. Ma. Sciences Vol. 6 211 no. 43 2135-2145 Approximaing e Powers wi Large Exponens and Bases Close o Uni and e Associaed Sequence of Nesed Limis Vio Lampre Universiy of Ljubljana Slovenia
More informationMidterm Exam Review Questions Free Response Non Calculator
Name: Dae: Block: Miderm Eam Review Quesions Free Response Non Calculaor Direcions: Solve each of he following problems. Choose he BEST answer choice from hose given. A calculaor may no be used. Do no
More information1 1 + x 2 dx. tan 1 (2) = ] ] x 3. Solution: Recall that the given integral is improper because. x 3. 1 x 3. dx = lim dx.
. Use Simpson s rule wih n 4 o esimae an () +. Soluion: Since we are using 4 seps, 4 Thus we have [ ( ) f() + 4f + f() + 4f 3 [ + 4 4 6 5 + + 4 4 3 + ] 5 [ + 6 6 5 + + 6 3 + ]. 5. Our funcion is f() +.
More informationDIFFERENTIAL EQUATIONS
DIFFERENTIAL EQUATIONS PAGE # An equaion conaining independen variable, dependen variable & differenial coeffeciens of dependen variables wr independen variable is called differenial equaion If all he
More informationMath 2142 Exam 1 Review Problems. x 2 + f (0) 3! for the 3rd Taylor polynomial at x = 0. To calculate the various quantities:
Mah 4 Eam Review Problems Problem. Calculae he 3rd Taylor polynomial for arcsin a =. Soluion. Le f() = arcsin. For his problem, we use he formula f() + f () + f ()! + f () 3! for he 3rd Taylor polynomial
More information63487 [Q. Booklet Number]
WBJEE - 0 (Answers & Hints) 687 [Q. Booklet Number] Regd. Office : Aakash Tower, Plot No., Sector-, Dwarka, New Delhi-0075 Ph. : 0-7656 Fa : 0-767 ANSWERS & HINTS for WBJEE - 0 by & Aakash IIT-JEE MULTIPLE
More informationMath 116 Second Midterm March 21, 2016
Mah 6 Second Miderm March, 06 UMID: EXAM SOLUTIONS Iniials: Insrucor: Secion:. Do no open his exam unil you are old o do so.. Do no wrie your name anywhere on his exam. 3. This exam has pages including
More informationMath 2214 Solution Test 1A Spring 2016
Mah 14 Soluion Tes 1A Spring 016 sec Problem 1: Wha is he larges -inerval for which ( 4) = has a guaraneed + unique soluion for iniial value (-1) = 3 according o he Exisence Uniqueness Theorem? Soluion
More informationSMT 2014 Calculus Test Solutions February 15, 2014 = 3 5 = 15.
SMT Calculus Tes Soluions February 5,. Le f() = and le g() =. Compue f ()g (). Answer: 5 Soluion: We noe ha f () = and g () = 6. Then f ()g () =. Plugging in = we ge f ()g () = 6 = 3 5 = 5.. There is a
More informationJEE (Advanced) 2018 MATHEMATICS QUESTION BANK
JEE (Advanced) 08 MATHEMATICS QUESTION BANK Ans. A [ : a multiple of ] and B [ : a multiple of 5], then A B ( A means complement of A) A B A B A B A B A { : 5 0}, B {, }, C {,5}, then A ( B C) {(, ), (,
More informationChapters 6 & 7: Trigonometric Functions of Angles and Real Numbers. Divide both Sides by 180
Algebra Chapers & : Trigonomeric Funcions of Angles and Real Numbers Chapers & : Trigonomeric Funcions of Angles and Real Numbers - Angle Measures Radians: - a uni (rad o measure he size of an angle. rad
More information15. Vector Valued Functions
1. Vecor Valued Funcions Up o his poin, we have presened vecors wih consan componens, for example, 1, and,,4. However, we can allow he componens of a vecor o be funcions of a common variable. For example,
More informationAP Calculus BC - Parametric equations and vectors Chapter 9- AP Exam Problems solutions
AP Calculus BC - Parameric equaions and vecors Chaper 9- AP Exam Problems soluions. A 5 and 5. B A, 4 + 8. C A, 4 + 4 8 ; he poin a is (,). y + ( x ) x + 4 4. e + e D A, slope.5 6 e e e 5. A d hus d d
More information!!"#"$%&#'()!"#&'(*%)+,&',-)./0)1-*23)
"#"$%&#'()"#&'(*%)+,&',-)./)1-*) #$%&'()*+,&',-.%,/)*+,-&1*#$)()5*6$+$%*,7&*-'-&1*(,-&*6&,7.$%$+*&%'(*8$&',-,%'-&1*(,-&*6&,79*(&,%: ;..,*&1$&$.$%&'()*1$$.,'&',-9*(&,%)?%*,('&5
More informationSection 15.6 Directional Derivatives and the Gradient Vector
Section 15.6 Directional Derivatives and te Gradient Vector Finding rates of cange in different directions Recall tat wen we first started considering derivatives of functions of more tan one variable,
More information(π 3)k. f(t) = 1 π 3 sin(t)
Mah 6 Fall 6 Dr. Lil Yen Tes Show all our work Name: Score: /6 No Calculaor permied in his par. Read he quesions carefull. Show all our work and clearl indicae our final answer. Use proper noaion. Problem
More information2015 Practice Test #1
Pracice Te # Preliminary SATNaional Meri Scolarip Qualifying Te IMPORTANT REMINDERS A No. pencil i required for e e. Do no ue a mecanical pencil or pen. Saring any queion wi anyone i a violaion of Te Securiy
More informationComplete Syllabus of Class XI & XII
Regd. Office : Aakash Tower, 8, Pusa Road, New Delhi-0005 Ph.: 0-7656 Fa : 0-767 MM : 0 Sample Paper : Campus Recruitment Test Time : ½ Hr. Mathematics (Engineering) Complete Syllabus of Class XI & XII
More informationPhysics 101 Fall 2006: Exam #1- PROBLEM #1
Physics 101 Fall 2006: Exam #1- PROBLEM #1 1. Problem 1. (+20 ps) (a) (+10 ps) i. +5 ps graph for x of he rain vs. ime. The graph needs o be parabolic and concave upward. ii. +3 ps graph for x of he person
More informationModule 2 F c i k c s la l w a s o s f dif di fusi s o i n
Module Fick s laws of diffusion Fick s laws of diffusion and hin film soluion Adolf Fick (1855) proposed: d J α d d d J (mole/m s) flu (m /s) diffusion coefficien and (mole/m 3 ) concenraion of ions, aoms
More informationV.sin. AIM: Investigate the projectile motion of a rigid body. INTRODUCTION:
EXPERIMENT 5: PROJECTILE MOTION: AIM: Invesigae e projecile moion of a rigid body. INTRODUCTION: Projecile moion is defined as e moion of a mass from op o e ground in verical line, or combined parabolic
More informationMATH 4330/5330, Fourier Analysis Section 6, Proof of Fourier s Theorem for Pointwise Convergence
MATH 433/533, Fourier Analysis Secion 6, Proof of Fourier s Theorem for Poinwise Convergence Firs, some commens abou inegraing periodic funcions. If g is a periodic funcion, g(x + ) g(x) for all real x,
More informationKEY. Math 334 Midterm I Fall 2008 sections 001 and 003 Instructor: Scott Glasgow
1 KEY Mah 4 Miderm I Fall 8 secions 1 and Insrucor: Sco Glasgow Please do NOT wrie on his eam. No credi will be given for such work. Raher wrie in a blue book, or on our own paper, preferabl engineering
More informationCheck in: 1 If m = 2(x + 1) and n = find y when. b y = 2m n 2
7 Parameric equaions This chaer will show ou how o skech curves using heir arameric equaions conver arameric equaions o Caresian equaions find oins of inersecion of curves and lines using arameric equaions
More information12 TH STD - MATHEMATICS
e e e e e e e e e e a TH STD - MATHEMATICS HALF YEARLY EXAMINATION 7 b) d) ANSWER KEY (8 - - 7) ONE MARK QUESTIONS : X k n ( a d j I ) d) no soluion 5 d) d) has onl rivial soluion onl if rank of he oeffiien
More informationPSAT/NMSQT PRACTICE ANSWER SHEET SECTION 3 EXAMPLES OF INCOMPLETE MARKS COMPLETE MARK B C D B C D B C D B C D B C D 13 A B C D B C D 11 A B C D B C D
PSTNMSQT PRCTICE NSWER SHEET COMPLETE MRK EXMPLES OF INCOMPLETE MRKS I i recommended a you ue a No pencil I i very imporan a you fill in e enire circle darkly and compleely If you cange your repone, erae
More informationTMA4329 Intro til vitensk. beregn. V2017
Norges eknisk naurvienskapelige universie Insiu for Maemaiske Fag TMA439 Inro il viensk. beregn. V7 ving 6 [S]=T. Sauer, Numerical Analsis, Second Inernaional Ediion, Pearson, 4 Teorioppgaver Oppgave 6..3,
More informationMethod For Solving Fuzzy Integro-Differential Equation By Using Fuzzy Laplace Transformation
INERNAIONAL JOURNAL OF SCIENIFIC & ECHNOLOGY RESEARCH VOLUME 3 ISSUE 5 May 4 ISSN 77-866 Meod For Solving Fuzzy Inegro-Differenial Equaion By Using Fuzzy Laplace ransformaion Manmoan Das Danji alukdar
More informationChapter 2 Limits and Continuity
4 Section. Capter Limits and Continuity Section. Rates of Cange and Limits (pp. 6) Quick Review.. f () ( ) () 4 0. f () 4( ) 4. f () sin sin 0 4. f (). 4 4 4 6. c c c 7. 8. c d d c d d c d c 9. 8 ( )(
More informationMATH 31B: MIDTERM 2 REVIEW. x 2 e x2 2x dx = 1. ue u du 2. x 2 e x2 e x2] + C 2. dx = x ln(x) 2 2. ln x dx = x ln x x + C. 2, or dx = 2u du.
MATH 3B: MIDTERM REVIEW JOE HUGHES. Inegraion by Pars. Evaluae 3 e. Soluion: Firs make he subsiuion u =. Then =, hence 3 e = e = ue u Now inegrae by pars o ge ue u = ue u e u + C and subsiue he definiion
More informationYimin Math Centre. 4 Unit Math Homework for Year 12 (Worked Answers) 4.1 Further Geometric Properties of the Ellipse and Hyperbola...
4 Uni Mah Homework for Year 12 (Worked Answers) Suden Name: Grade: Dae: Score: Table of conens 4 Topic 2 Conics (Par 4) 1 4.1 Furher Geomeric Properies of he Ellipse and Hyperbola............... 1 4.2
More informationJEE ADVANCED EXAMINATION 2014 QUESTIONS WITH SOLUTIONS PAPER - 2 [CODE - 1]
JEE ADVANCED EXAMINATION 4 QUESTIONS WITH SOLUTIONS PAPER - [CODE - ] 94,5 - Rajeev Gandhi Nagar Koa, Ph. No. : 94-8748, 744-967 IVRS No : 744-495, 5, 5, www. moioniijee.com, info@moioniijee.com IIT-JEE
More informationAP Calculus BC 2004 Free-Response Questions Form B
AP Calculus BC 200 Free-Response Quesions Form B The maerials included in hese files are inended for noncommercial use by AP eachers for course and exam preparaion; permission for any oher use mus be sough
More informationJEE ADVANCED EXAMINATION 2014 QUESTIONS WITH SOLUTIONS PAPER - 2 [CODE - 4]
JEE ADVANCED EXAMINATION 4 QUESTIONS WITH SOLUTIONS PAPER - [CODE - 4] 94,5 - Rajeev Gandhi Nagar Koa, Ph. No. : 94-8748, 744-967 IVRS No : 744-495, 5, 5, www. moioniijee.com, info@moioniijee.com IIT-JEE
More informationObjective Mathematics
. A tangent to the ellipse is intersected by a b the tangents at the etremities of the major ais at 'P' and 'Q' circle on PQ as diameter always passes through : (a) one fied point two fied points (c) four
More informationAnswers to 1 Homework
Answers o Homework. x + and y x 5 y To eliminae he parameer, solve for x. Subsiue ino y s equaion o ge y x.. x and y, x y x To eliminae he parameer, solve for. Subsiue ino y s equaion o ge x y, x. (Noe:
More informationRegd. Office : Aakash Tower, Plot No.-4, Sec-11, MLU, Dwarka, New Delhi Ph.: Fax : Answers & Solutions
DATE : 5/05/04 CDE 5 Regd. ffice : Aakash Tower, Plo No.-4, Sec-, MLU, Dwarka, New Delhi-0075 Ph.: 0-476456 Fax : 0-47647 Answers & Soluions Time : hrs. Max. Marks: 80 for JEE (Advanced)-04 PAPER - (Code
More informationTHE SINE INTEGRAL. x dt t
THE SINE INTEGRAL As one learns in elemenary calculus, he limi of sin(/ as vanishes is uniy. Furhermore he funcion is even and has an infinie number of zeros locaed a ±n for n1,,3 Is plo looks like his-
More informationAP CALCULUS BC 2016 SCORING GUIDELINES
6 SCORING GUIDELINES Quesion A ime, he posiion of a paricle moving in he xy-plane is given by he parameric funcions ( x ( ), y ( )), where = + sin ( ). The graph of y, consising of hree line segmens, is
More informationLet ( α, β be the eigenvector associated with the eigenvalue λ i
ENGI 940 4.05 - Sabiliy Analysis (Linear) Page 4.5 Le ( α, be he eigenvecor associaed wih he eigenvalue λ i of he coefficien i i) marix A Le c, c be arbirary consans. a b c d Case of real, disinc, negaive
More informationAP CALCULUS AB 2003 SCORING GUIDELINES (Form B)
SCORING GUIDELINES (Form B) Quesion A blood vessel is 6 millimeers (mm) long Disance wih circular cross secions of varying diameer. x (mm) 6 8 4 6 Diameer The able above gives he measuremens of he B(x)
More informationMockTime.com. (b) 9/2 (c) 18 (d) 27
212 NDA Mathematics Practice Set 1. Let X be any non-empty set containing n elements. Then what is the number of relations on X? 2 n 2 2n 2 2n n 2 2. Only 1 2 and 3 1 and 2 1 and 3 3. Consider the following
More information10.1 EXERCISES. y 2 t 2. y 1 t y t 3. y e
66 CHAPTER PARAMETRIC EQUATINS AND PLAR CRDINATES SLUTIN We use a graphing device o produce he graphs for he cases a,,.5,.,,.5,, and shown in Figure 7. Noice ha all of hese curves (ecep he case a ) have
More informationSolutions to the Olympiad Cayley Paper
Soluions o he Olympiad Cayley Paper C1. How many hree-digi muliples of 9 consis only of odd digis? Soluion We use he fac ha an ineger is a muliple of 9 when he sum of is digis is a muliple of 9, and no
More informationMath 116 Practice for Exam 2
Mah 6 Pracice for Exam Generaed Ocober 3, 7 Name: SOLUTIONS Insrucor: Secion Number:. This exam has 5 quesions. Noe ha he problems are no of equal difficuly, so you may wan o skip over and reurn o a problem
More information2. Random Search with Complete BST
Tecnical Repor: TR-BUAA-ACT-06-0 Complexiy Analysis of Random Searc wi AVL Tree Gongwei Fu, Hailong Sun Scool of Compuer Science, Beiang Universiy {FuGW, SunHL@ac.buaa.edu.cn April 7, 006 TR-BUAA-ACT-06-0.
More information1. VELOCITY AND ACCELERATION
1. VELOCITY AND ACCELERATION 1.1 Kinemaics Equaions s = u + 1 a and s = v 1 a s = 1 (u + v) v = u + as 1. Displacemen-Time Graph Gradien = speed 1.3 Velociy-Time Graph Gradien = acceleraion Area under
More informationES.1803 Topic 22 Notes Jeremy Orloff
ES.83 Topic Noes Jeremy Orloff Fourier series inroducion: coninued. Goals. Be able o compue he Fourier coefficiens of even or odd periodic funcion using he simplified formulas.. Be able o wrie and graph
More informationLecture 23 Damped Motion
Differenial Equaions (MTH40) Lecure Daped Moion In he previous lecure, we discussed he free haronic oion ha assues no rearding forces acing on he oving ass. However No rearding forces acing on he oving
More informationMultiple Choice Solutions 1. E (2003 AB25) () xt t t t 2. A (2008 AB21/BC21) 3. B (2008 AB7) Using Fundamental Theorem of Calculus: 1
Paricle Moion Soluions We have inenionally included more maerial han can be covered in mos Suden Sudy Sessions o accoun for groups ha are able o answer he quesions a a faser rae. Use your own judgmen,
More informationMath 334 Test 1 KEY Spring 2010 Section: 001. Instructor: Scott Glasgow Dates: May 10 and 11.
1 Mah 334 Tes 1 KEY Spring 21 Secion: 1 Insrucor: Sco Glasgow Daes: Ma 1 and 11. Do NOT wrie on his problem saemen bookle, excep for our indicaion of following he honor code jus below. No credi will be
More informationRegd. Office : Aakash Tower, Plot No.-4, Sec-11, MLU, Dwarka, New Delhi Ph.: Fax : Answers & Solutions
DATE : 5/05/04 CDE 7 Regd. ffice : Aakash Tower, Plo No.-4, Sec-, MLU, Dwarka, New Delhi-0075 Ph.: 0-476456 Fax : 0-47647 Answers & Soluions Time : hrs. Max. Marks: 80 for JEE (Advanced)-04 PAPER - (Code
More informationName: Total Points: Multiple choice questions [120 points]
Name: Toal Poins: (Las) (Firs) Muliple choice quesions [1 poins] Answer all of he following quesions. Read each quesion carefully. Fill he correc bubble on your scanron shee. Each correc answer is worh
More informationEXERCISES FOR SECTION 1.5
1.5 Exisence and Uniqueness of Soluions 43 20. 1 v c 21. 1 v c 1 2 4 6 8 10 1 2 2 4 6 8 10 Graph of approximae soluion obained using Euler s mehod wih = 0.1. Graph of approximae soluion obained using Euler
More informationMEI STRUCTURED MATHEMATICS 4758
OXFORD CAMBRIDGE AND RSA EXAMINATIONS Advanced Subsidiary General Cerificae of Educaion Advanced General Cerificae of Educaion MEI STRUCTURED MATHEMATICS 4758 Differenial Equaions Thursday 5 JUNE 006 Afernoon
More informationV L. DT s D T s t. Figure 1: Buck-boost converter: inductor current i(t) in the continuous conduction mode.
ECE 445 Analysis and Design of Power Elecronic Circuis Problem Se 7 Soluions Problem PS7.1 Erickson, Problem 5.1 Soluion (a) Firs, recall he operaion of he buck-boos converer in he coninuous conducion
More informationMATH 351 Solutions: TEST 3-B 23 April 2018 (revised)
MATH Soluions: TEST -B April 8 (revised) Par I [ ps each] Each of he following asserions is false. Give an eplici couner-eample o illusrae his.. If H: (, ) R is coninuous, hen H is unbounded. Le H() =
More information2.7. Some common engineering functions. Introduction. Prerequisites. Learning Outcomes
Some common engineering funcions 2.7 Inroducion This secion provides a caalogue of some common funcions ofen used in Science and Engineering. These include polynomials, raional funcions, he modulus funcion
More informationKinematics Vocabulary. Kinematics and One Dimensional Motion. Position. Coordinate System in One Dimension. Kinema means movement 8.
Kinemaics Vocabulary Kinemaics and One Dimensional Moion 8.1 WD1 Kinema means movemen Mahemaical descripion of moion Posiion Time Inerval Displacemen Velociy; absolue value: speed Acceleraion Averages
More informationObjective Mathematics
Chapter No - ( Area Bounded by Curves ). Normal at (, ) is given by : y y. f ( ) or f ( ). Area d ()() 7 Square units. Area (8)() 6 dy. ( ) d y c or f ( ) c f () c f ( ) As shown in figure, point P is
More informationHigher Order Difference Schemes for Heat Equation
Available a p://pvau.edu/aa Appl. Appl. Ma. ISSN: 9-966 Vol., Issue (Deceber 009), pp. 6 7 (Previously, Vol., No. ) Applicaions and Applied Maeaics: An Inernaional Journal (AAM) Higer Order Difference
More information23.5. Half-Range Series. Introduction. Prerequisites. Learning Outcomes
Half-Range Series 2.5 Inroducion In his Secion we address he following problem: Can we find a Fourier series expansion of a funcion defined over a finie inerval? Of course we recognise ha such a funcion
More informationExponential and Logarithmic Functions
Chaper 5 Eponenial and Logarihmic Funcions Chaper 5 Prerequisie Skills Chaper 5 Prerequisie Skills Quesion 1 Page 50 a) b) c) Answers may vary. For eample: The equaion of he inverse is y = log since log
More informationThe Fundamental Theorem of Calculus Solutions
The Fundamenal Theorem of Calculus Soluions We have inenionally included more maerial han can be covered in mos Suden Sudy Sessions o accoun for groups ha are able o answer he quesions a a faser rae. Use
More informationThe equation to any straight line can be expressed in the form:
Sring Graphs Par 1 Answers 1 TI-Nspire Invesigaion Suden min Aims Deermine a series of equaions of sraigh lines o form a paern similar o ha formed by he cables on he Jerusalem Chords Bridge. Deermine he
More informationInnova Junior College H2 Mathematics JC2 Preliminary Examinations Paper 2 Solutions 0 (*)
Soluion 3 x 4x3 x 3 x 0 4x3 x 4x3 x 4x3 x 4x3 x x 3x 3 4x3 x Innova Junior College H Mahemaics JC Preliminary Examinaions Paper Soluions 3x 3 4x 3x 0 4x 3 4x 3 0 (*) 0 0 + + + - 3 3 4 3 3 3 3 Hence x or
More informationChallenge Problems. DIS 203 and 210. March 6, (e 2) k. k(k + 2). k=1. f(x) = k(k + 2) = 1 x k
Challenge Problems DIS 03 and 0 March 6, 05 Choose one of he following problems, and work on i in your group. Your goal is o convince me ha your answer is correc. Even if your answer isn compleely correc,
More informationDifferential Equations
Mah 21 (Fall 29) Differenial Equaions Soluion #3 1. Find he paricular soluion of he following differenial equaion by variaion of parameer (a) y + y = csc (b) 2 y + y y = ln, > Soluion: (a) The corresponding
More informationKINEMATICS IN ONE DIMENSION
KINEMATICS IN ONE DIMENSION PREVIEW Kinemaics is he sudy of how hings move how far (disance and displacemen), how fas (speed and velociy), and how fas ha how fas changes (acceleraion). We say ha an objec
More informationY 0.4Y 0.45Y Y to a proper ARMA specification.
HG Jan 04 ECON 50 Exercises II - 0 Feb 04 (wih answers Exercise. Read secion 8 in lecure noes 3 (LN3 on he common facor problem in ARMA-processes. Consider he following process Y 0.4Y 0.45Y 0.5 ( where
More informationON DIFFERENTIABILITY OF ABSOLUTELY MONOTONE SET-VALUED FUNCTIONS
Folia Maemaica Vol. 16, No. 1, pp. 25 30 Aca Universiais Lodziensis c 2009 for Universiy of Lódź Press ON DIFFERENTIABILITY OF ABSOLUTELY MONOTONE SET-VALUED FUNCTIONS ANDRZEJ SMAJDOR Absrac. We prove
More informationACCUMULATION. Section 7.5 Calculus AP/Dual, Revised /26/2018 7:27 PM 7.5A: Accumulation 1
ACCUMULATION Secion 7.5 Calculus AP/Dual, Revised 2019 vie.dang@humbleisd.ne 12/26/2018 7:27 PM 7.5A: Accumulaion 1 APPLICATION PROBLEMS A. Undersand he quesion. I is ofen no necessary o as much compuaion
More informationCHAPTER 2 Signals And Spectra
CHAPER Signals And Specra Properies of Signals and Noise In communicaion sysems he received waveform is usually caegorized ino he desired par conaining he informaion, and he undesired par. he desired par
More informationAn Introduction to Malliavin calculus and its applications
An Inroducion o Malliavin calculus and is applicaions Lecure 5: Smoohness of he densiy and Hörmander s heorem David Nualar Deparmen of Mahemaics Kansas Universiy Universiy of Wyoming Summer School 214
More informationMEI Mechanics 1 General motion. Section 1: Using calculus
Soluions o Exercise MEI Mechanics General moion Secion : Using calculus. s 4 v a 6 4 4 When =, v 4 a 6 4 6. (i) When = 0, s = -, so he iniial displacemen = - m. s v 4 When = 0, v = so he iniial velociy
More informationParametrics and Vectors (BC Only)
Paramerics and Vecors (BC Only) The following relaionships should be learned and memorized. The paricle s posiion vecor is r() x(), y(). The velociy vecor is v(),. The speed is he magniude of he velociy
More informationMATHEMATICS. metres (D) metres (C)
MATHEMATICS. If is the root of the equation + k = 0, then what is the value of k? 9. Two striaght lines y = 0 and 6y 6 = 0 never intersect intersect at a single point intersect at infinite number of points
More informationMA 214 Calculus IV (Spring 2016) Section 2. Homework Assignment 1 Solutions
MA 14 Calculus IV (Spring 016) Secion Homework Assignmen 1 Soluions 1 Boyce and DiPrima, p 40, Problem 10 (c) Soluion: In sandard form he given firs-order linear ODE is: An inegraing facor is given by
More information1 Solutions to selected problems
1 Soluions o seleced problems 1. Le A B R n. Show ha in A in B bu in general bd A bd B. Soluion. Le x in A. Then here is ɛ > 0 such ha B ɛ (x) A B. This shows x in B. If A = [0, 1] and B = [0, 2], hen
More informationMULTIPLE CHOICE QUESTIONS SUBJECT : MATHEMATICS Duration : Two Hours Maximum Marks : 100. [ Q. 1 to 60 carry one mark each ] A. 0 B. 1 C. 2 D.
M 68 MULTIPLE CHOICE QUESTIONS SUBJECT : MATHEMATICS Duration : Two Hours Maimum Marks : [ Q. to 6 carry one mark each ]. If sin sin sin y z, then the value of 9 y 9 z 9 9 y 9 z 9 A. B. C. D. is equal
More informationMath 333 Problem Set #2 Solution 14 February 2003
Mah 333 Problem Se #2 Soluion 14 February 2003 A1. Solve he iniial value problem dy dx = x2 + e 3x ; 2y 4 y(0) = 1. Soluion: This is separable; we wrie 2y 4 dy = x 2 + e x dx and inegrae o ge The iniial
More informationRandom variables. A random variable X is a function that assigns a real number, X(ζ), to each outcome ζ in the sample space of a random experiment.
Random variables Some random eperimens may yield a sample space whose elemens evens are numbers, bu some do no or mahemaical purposes, i is desirable o have numbers associaed wih he oucomes A random variable
More informationMath 1b. Calculus, Series, and Differential Equations. Final Exam Solutions
Mah b. Calculus, Series, and Differenial Equaions. Final Exam Soluions Spring 6. (9 poins) Evaluae he following inegrals. 5x + 7 (a) (x + )(x + ) dx. (b) (c) x arcan x dx x(ln x) dx Soluion. (a) Using
More information