GRADE 11 NOVEMBER 2012 MATHEMATICAL LITERACY P1 MEMORANDUM
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1 Province of the EASTERN CAPE EDUCATION NATIONAL SENIOR CERTIFICATE GRADE 11 NOVEMBER 2012 MATHEMATICAL LITERACY P1 MEMORANDUM MARKS: 100 SYMBOL A CA C J M MA P R RT/RG S SF O EXPLANATION Accuracy Consistent Accuracy Conversion Justification (Reason/Opinion) Method Method with Penalty for no units, incorrect rounding off, etc. Rounding off Reading from table/graph Simplification Correct substitution in a formula Own opinion This memorandum consists of 6 pages.
2 2 MATHEMATICAL LITERACY P1 (NOVEMBER 2012) QUESTION Sale Price of CD = % M = R106,25 CA Sale Price of CD = 125 (125 x 0,15) M = ,75 = R106,25 CA Sale Price of DVD = 215 (215 x ) M Sale Price of DVD = 215 (215 x 0,25) M Sale Price of DVD = 215 (215 x25%) M Sale Price of DVD = %) M Mowing Lawn = SF = CA Watering the flowers: Time taken = SF = 25 minutes CA Watering time = SF = CA Flour = Cheese = x 50 M = g or 1 kg CA x 50 M = 750 g CA 1M Method 1M Method 1SF Correct substitution 1CA Accurate simplification Accuracy Accuracy (4)
3 (NOVEMBER 2012) MATHEMATICAL LITERACY P Using; Distance = Speed x Time 561 = Speed x 6 SF Litre/km = Speed = M = 93,5 km/h CA = 94 km/h R M = 17,9980 CA = 18 km/litre R Cost of Petrol = 31,17 x 10,05 SF M = R313,2585 = R313,26 CA substituted 1R Correctly rounded up (4) 1R Correctly rounded up 1CA Correct answer [25] QUESTION Fixed expenses = R200 RG 1RG Correct reading 1O Correct, logical opinion 2O any 2 correct materials given Rental, electricity, salaries, etc. Accept any logical answer here. O 2.2 Expenses making coffee tables = wood, nails glue, etc. Accept any material needed. O 2.3 Break-even = 6,5 RG = 7 tables CA 1RG Correct reading 1CA Correct answer 2.4 Expenses 20 tables = R500,00 RG A 1RG Correct reading 1A Accuracy in reading 2.5 Income 20 tables = R900,00 RG A 1RG Correct reading 1A Accuracy in reading 2.6 Profit 20 tables = SF M = R400,00 CA 2.7 Selling Price 1 table = SF M = R 45,00 CA Selling Price 1 table = = (any correct graph values ) SF M = R45,00 CA 2.8 Income 15 tables = 45 x 15 M = R675,00 CA
4 4 MATHEMATICAL LITERACY P1 (NOVEMBER 2012) 2.9 Profit would increase. O Reason: 60 x 20 tables = R1 200 M 2.10 No of tables sold = QUESTION cm 7,5 cm 7,5 cm = R300 more profit M CA M = 13 tables CA 25 cm 25 cm 7,5 cm 20 cm 20 cm 3.2 Surface Area = (2 x 20 x 25)+(2 x 20 x 7,5)+(2 x 25 x 7,5) SF and M = CA = CA 3.3 Cost of cardboard = x 0,06 M = 100,5 cents CA = 101 cents R 3.4 Cost of Printing = x 0,04 SF M = 67 cents CA 3.5 Volume = 25 x 20 x 7,5 SF M = CA 3.6 Grams in box = ,5 SF M = 500 g cereal CA 1O Correct opinion with graph values 1CA accurate calculations (4) 1CA consistent Correct net drawn with 6 rectangles correct measurements placed in required places (not all sides need measurements) (4) 3 SF M correct values and correct method x 3 1CA Correct answer (5) 1R Rounding up [24]
5 (NOVEMBER 2012) MATHEMATICAL LITERACY P m x 100 = 200 cm and 15 m x 100 = cm C Width of net = 7, ,5 = 40 cm M Length of net = , ,5 = 55 cm M = 5 widths = 27, = 27 lengths C Number of boxes = 5 x 27 = 135 boxes CA 2 m x 100 = 200 cm and 15 m x100 = cm C Area of roll = 200 x = MA Number of boxes = = 179,1044 = 179 boxes CA (1 mark less for not allowing for waste of space) Area of roll = 2 x 15 M = 30 A 1C conversion to cm 2 M Correct method 1C correct conversions (5) 1C Conversions to cm. 1MA Correct method and (4) 2MA Method and Accuracy Surface Area of box in m² = Number of boxes = = 179,104 = 179 boxes = 0,1675 C 1C Conversion to 1M Method 1A Accuracy [26] QUESTION Tazz RG 1 RG correct reading (1) Mercedes RG 1 RG correct reading (1) Suburb A much lower income than 1O Opinion Suburb B because Suburb A purchases lower cost range of cars in the main. OR (Accept any logical opinion and reasoning.) 1R Reason Not a realistic picture O as it only deals with Johannesburg and not the rest of the country where less money is earned R (Accept any logical opinion and reasoning.) 1O Opinion 1R Reason
6 Frequency 6 MATHEMATICAL LITERACY P1 (NOVEMBER 2012) (a) Mean = M 29 = 1853 MA 29 = 63, ,90 CA (b) Mode = 70 MA (c) Median = 66 M CA Interval Frequency M Correct Method 1MA Method and 1MA correct method and (1) 1 Mark for each correct frequency in the following intervals (Any 4) (4) Mark for correct Test Results Marks frequency intervals added 1 Mark for correct graph 3 Marks for any 3 correct bars on graph (5) Mean and median as both tell us that most learners got around the mark. This is also shown by the histogram. O R (Accept all valid choices and reasons.) The test was easy O because most learners got above 50%. R 1O Correct choice made 1R Valid reason given O Correct choice R Correct reason for choice [25] TOTAL: 100
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