NATIONAL SENIOR CERTIFICATE GRADE 12

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NATIONAL SENI CERTIFICATE GRADE 12 MATHEMATICAL LITERACY P1 NOVEMBER 2012 FINAL MEMANDUM MARKS: 150 Symbol M M/A CA A C S RT/RG SF O P R Explanation Method Method with accuracy Consistent accuracy

1 NATIONAL SENI CERTIFICATE GRADE 12 MATHEMATICAL LITERACY P1 NOVEMBER 2012 FINAL MEMANDUM MARKS: 150 Symbol M M/A CA A C S RT/RG SF O P R Explanation Method Method with accuracy Consistent accuracy Accuracy Conversion Simplification Reading from a table/reading from a graph Correct substitution in a formula Opinion/Example Penalty, e.g. for no units, incorrect rounding off etc. Rounding off PLEASE NOTE: 1. If a candidate deletes a solution to a question without providing another solution, then the deleted solution must be marked. 2. If a candidate provides more than one solution to a question, then only the first solution must be marked and a line drawn through any other solutions to the question. This memorandum consists of 15 pages. EXTERNAL MODERAT EXTERNAL MODERAT INTERNAL MODERAT MR MA HENDRICKS MR RI SINGH MRS J SCHEIBER 15 NOVEMBER NOVEMBER NOVEMBER 2012

2 Mathematical Literacy/P1 2 DBE/November 2012 Rounding off penalty once only in question 5 QUESTION 1 [34 MARKS] Correct answer only: Full marks ,62 8,7 2 13, 26 = 1441,62 62, 43 S 1S simplifying = 1441,62 7, = 1 433, , ,0528 = = ,005 = 23, m = m R63,99/kg 2,5 kg = R159,975 R159, h15 min 1h18 min = 11h57 min /A (accept R159,97 - no rounding penalty) /A /A 1A writing as a common fraction 1CA simplifying 1M/A multiplying by if multiplied by power of 10 1M/A multiplication to nearest cent 1M/A subtracting 1h18 min Shameeg arrived at 11:57. 3 minutes to ,2584 /A 1CA arrival time (Accept 11H57) 1M/A dividing = 375, CERTAIN 2A conclusion R10,29 2A median

3 Mathematical Literacy/P1 3 DBE/November = R14,95 /A 1A one correct reading from graph 1A correct reading of the other two values from graph 1CA total of the three (values within the range) 1M/A multiplying = R44,85 (CA only when using R14,95 or multiplying 3 with a price on the slip) R167,45 24,95 97,65 = R44, R24,95 R21,89 14% of R21,89 = R3,06 97,65 /A 13,95 = 7 bangles /A /A 1M/A subtracting the values from the total 1CA the amount 1M/A dividing 1M/A subtracting/ calculating percentage to the nearest cent /A 14 R24,95 = R3, M/A multiplying 1 CA simplification to the nearest cent

4 Mathematical Literacy/P1 4 DBE/November R167,45 114% = R 146,89 1M dividing 1A correct values R167, = R146,89 14 VAT = R167,45 = R20, M dividing 1A correct values 1 M calculating VAT 1A correct values Total without VAT = R167,45 R20,56 = R146,89 /A (1, , , , ,264) millions of tons = 17,634 millions of tons tons (if 14% is calculated : 0 marks) 1 M/A adding 1CA total ( if using the wrong data set: max 1 mark) Iran 2A correct country (extra country: 0 marks) Saudi Arabia 2A correct country L 1 [34]

5 Mathematical Literacy/P1 5 DBE/November 2012 QUESTION 2 [29 MARKS] = 8 3 1M multiplying 1A simplification Correct answer only: full marks Spotted sector 2A correct sector (accept dotted sector, black & white sector) (a) (b) Circumference = 2 3,14 60 cm = 376,8 cm (Using π: 376,99 cm) 2 3,14 60 Area of a sector of a circle = cm² = cm² 24 = 471 cm² (using π: 471,24 cm²) 1SF substitution 1SF substitution [refer to radius used in (a)] 1A square unit shown anywhere in solution Difference in time Percentage increase in time = 100% original time 1,56 1,2 = 100% 1,2 = 30 % 0, Distance = (27,95 1,36) m = 38,012 m (any one) 38,01 m 1SF difference in time 1SF substituting 1,2 ( no subtraction no CA) 1SF substitution 1A simplification

6 Mathematical Literacy/P1 6 DBE/November :00 or nine o' clock or 9 am RG 1RG reading from graph Mr Nobi RG 1RG reading from graph hours or 3 hours RG 2RG reading from graph :47 RG (accept any time from 10:45 to 10:50) 2RG reading from graph :00 or nine o' clock or 9 am RG 2RG reading from graph Service fee (in rand) = 3,50 + 1,20% of the transaction amount = 3,50 + 1,20% 344,50 = 3,50 + 4,134 7, Service fee 3,50 Amount (in rand) = 1,20% 11,85 3,50 = 1,20% 8,35 = 0, ,83 1SF substituting 344,50 1A simplification 1CA amount to the nearest cent Correct answer only if correctly rounded : full marks 1SF substitution of 11,85 1A simplification 1CA amount to the nearest cent [29]

7 Mathematical Literacy/P1 7 DBE/November 2012 QUESTION 3 [16 MARKS] R deposit + R3 599,85 60 months = R R S 1S simplification = R A = P(1 i ) n ( 1 13,5% ) = R = R38 608,41 R R 2 Correct answer only: full marks 1 SF correct substitution 1 R rounding to the nearest R100 Correct answer only: full marks ,5 1A conclusion Petrol consumption (in litre per 100 km) distance covered = 12, = 12, = 40,625 (any one) 40,63 1SF substitution Petrol consumption (in litre per 100 km) = 12,5 3,25 = 40,625 (any one) 40,63 1SF substitution of factor 3,25 Correct answer only: full marks

8 Mathematical Literacy/P1 8 DBE/November C 4 4 C 1A C 1A Long Street and Marsh Street (or High Street) 2A any two correct (1 Penalty if other street names are given) Right (accept Easterly direction) 2A conclusion cm represents 0,3 km 8,9 cm represents 0,3 km 8,9 = 2,67 km 1M multiplying by 8,9 1 A simplification : 0,3 8,9: 0,3 8,9 8,9 : 2,67 1M multiplying by 8,9 1 A simplification (If unit is incorrect: 1 mark) [16]

9 Mathematical Literacy/P1 9 DBE/November 2012 QUESTION 4 [24 MARKS] M ascending order 1 A all correct (descending order: 1 mark, one number omitted: 1 mark, Using names of the dogs: 1 mark) Dog K 2A conclusion (Dog G: give 1 mark) A mode CA from Range = 9 1 = Mean = = 11 = 6 CA : 4 = 5 : 2 1M identifying 1 and 9 1CA range 1M sum of the values (no penalty for omitting 0) 1M dividing by 11 1CA mean Correct answer only: full marks 1A correct ratio 1CA simplified ratio (unit ratio 1: 0,4 or 2,5 : 1 give 1 mark; written as a fraction 0 marks; Inverting the ratio 1 mark) Correct answer only: full marks

10 Mathematical Literacy/P1 10 DBE/November THE LITTER SIZE OF 11 DOGS Number of puppies Female Male A B C D E F G H I J K Name of Dog 1A for each bar drawn correctly (correct litter size only, max 3 marks) cm 1, cm 100 1M multiplying (7) = 131,25 cm = 131,25 cm 1A length Correct answer only: full marks ,5 cm 1M multiplying = 15 cm 1A height Correct answer only: full marks [24]

11 Mathematical Literacy/P1 11 DBE/November 2012 QUESTION 5 [19 MARKS] Once off penalty for rounding off A 1A conclusion mm : mm /A 1M/A correct ratio = 1: 100 Note: AFRIKAANS additional options mm mm = mm /A 1M/A subtraction Perimeter = = mm % 39,54 m 2 28,47 m 2 area of the kitchen = 39,54 m 2 28,47 m 2 = 11,07 m 2 100% 72% = 28% area of the kitchen =28% 39,54 m 2 11,07 m 2 1 M finding perimeter 1 CA simplification (no penalty for units) 1M % concept 1M concept of decrease of area 1M concept of decrease of % 1M % concept (no penalty for units)

12 Mathematical Literacy/P1 12 DBE/November cement : stone = 1 : 4 1,5 bags of cement = 1,5 wheelbarrows of cement 1 For 1 2 wheelbarrows of cement, 1M concept she will need wheelbarrows of stone 1M multiply by 4 = 6 wheelbarrows of stone Correct answer only: full marks Volume of the step = Area of the trapezium height of the step = 2,52 m 2 0,12 m 1SF substitution = 0,3024 m 3 0,30 m 3 or 0,3 1A simplification (no penalty for units) Total tiled area (in m 2 ) = A + (2s+f) h = 2,52 + (2 1,6+1,3) 0,12 = 3,06 3,1 R Total length of the strip = 1,3 m + 2 1,6 m = 4,5 m 1 SF substitution two correct 1 SF substitution another two correct 1R rounding (4) 1SF substitution [19]

13 Mathematical Literacy/P1 13 DBE/November 2012 QUESTION 6 [28 MARKS] 6.1 In 4 minutes she covers 450 m minute she covers m = 112,5 m 4 1M working with ratio in 9 minutes she covers 112,5 9 m = 1 012,5 m 4 minutes: 450 m minutes: 4 m = 1012,5 m 1M working with ratio 6.2 Grams of carbohydrate = 2,27 65 = 147,55 1A using 2,27 1M multiplying Correct answer only: full marks minutes RT 1RT reading from table Average pace (in km per minute) = = = S ,27 1SF distances 1SF times 1S simplification 1CA average pace (if inverted, max 2 marks; if using other values from the table, max 2 marks) (4)

14 Mathematical Literacy/P1 14 DBE/November GRACIA'S PLAN F THE RACE Distance (in km) Time (in minutes) No penalty for omitting (0;0) and joining 6A any 6 points plotted correctly 1A all correct points joined 1M correct shape (not a straight line) If only a Bar graph is correctly drawn - max 4 marks (8)

15 Mathematical Literacy/P1 15 DBE/November ATHLETIC CLUB FREQUENCY Liberty 5 Striders 5 Ramblers 4 Harmony (a) (b) (c) Striders Club = 100% ( )% /A = 16% Liberty or club E or E Actual number of Ramblers athletes = 12% 300 /A = 36 4A one mark for each correct frequency (just tallies or frequencies as fractions :MAX 2 marks) (4) 1M/A subtracting from 100% Correct answer only: full marks 2A correct club 1M/A calculating actual number TOTAL: [28]

NATIONAL SENIOR CERTIFICATE GRADE 12

NATIONAL SENIOR CERTIFICATE GRADE 12 NATIONAL SENI CERTIFICATE GRADE 12 MATHEMATICAL LITERACY P1 NOVEMBER 2009 MEMANDUM MARKS: 150 Symbol M MA CA A C S RT/RG SF O P R Explanation Method Method with accuracy Consistent accuracy Accuracy Conversion