NATIONAL SENIOR CERTIFICATE GRADE 12

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NATIONAL SENI CERTIFICATE GRADE 12 MATHEMATICAL LITERACY P1 NOVEMBER 2009 MEMANDUM MARKS: 150 Symbol M MA CA A C S RT/RG SF O P R Explanation Method Method with accuracy Consistent accuracy Accuracy

1 NATIONAL SENI CERTIFICATE GRADE 12 MATHEMATICAL LITERACY P1 NOVEMBER 2009 MEMANDUM MARKS: 150 Symbol M MA CA A C S RT/RG SF O P R Explanation Method Method with accuracy Consistent accuracy Accuracy Conversion Simplification Reading from a table/reading from a graph Correct substitution in a formula Opinion/Example Penalty, e.g. for no units, incorrect rounding off etc. Rounding off This memorandum consists of 16 pages. EXTERNAL MODERAT MR M.A. HENDRICKS INTERNAL MODERAT MRS J. SCHEIBER

2 Mathematical Literacy/P1 2 DoE/12 November 2009 QUESTION 1 [26] : 128 ( 16) 29 : 8 1A solution A solution = 1, CA rounding off 1,52 1,5 or 1,51 1 mark Any other incorrect answer (57) 3 = = = = 3 = 26 1A square root 1A simplifying brackets and dividing 1CA simplification ANSWER ONLY 2 marks , m l = m l 1M multiplying by A accurate conversion No penalty if units are omitted % of kg = kg 100 = 200,8 kg 1M calculating % 1A solution New amount = kg + 200,8 kg = 1 455,8 kg 1CA increase in % 16% increase = 1,16 1A total % New amount = 1, kg 1M multiplying = 1 455,8 kg 1CA solution No penalty if units are omitted

3 Mathematical Literacy/P1 3 DoE/12 November $1 = R10,52 $1 215,00 = R10, ,00 = R12 781,80 1M multiplying 1CA simplification R 399,00 30 = R13,30 A 1MA dividing 1A simplification Total number of grams in a box = 500 g 30 = g A 1MA multiplying R399,00 Cost of 500 g = = R13,30 1A simplification or 100% or certain 2A correct probability ANSWER WRITTEN AS A RATIO 1 mark Temp in o 9 F = 5 SF 225 o + 32 o = 405 o F + 32 o F S = 437 o F 435 o F 1SF substitution in formula 1S simplification 1CA rounded off to 5 degrees

4 Mathematical Literacy/P1 4 DoE/12 November R 9,00 Cost price of 1 orange = 12 = R0,75 R9, Cost price of 1 orange = 12 = 75 cents 1M division by 12 1CA simplification 0,75 with no units 2 marks 75 with no units 1 mark dozen oranges sell for R12,00 1A selling price for 1 dozen Profit = R12,00 R9,00 = R3,00 1CA difference Selling price per orange = 100 cents Cost price per orange = 75 cents Profit per orange = 25 cents 1A profit per orange Profit per dozen orgaanges = 25 cents 12 = 300 cents = R3,00 1CA profit per dozen

5 Mathematical Literacy/P1 5 DoE/12 November Cost = 108 R0,75 1CA cost per orange = R81,00 1CA cost for 108 oranges 12 oranges cost R9, R 9, oranges = 12 = R81,00 1M finding number of dozens 1CA cost for 108 oranges 108 Number of dozen = = M dividing Cost = 9 dozen R9,00 per dozen = R81,00 1CA cost for 108 oranges

6 Mathematical Literacy/P1 6 DoE/12 November 2009 QUESTION 2 [31] D = 10 cm 1A doubling the radius L = 29,5 cm 2,5 cm 2,5 cm /A 1MA reducing 29,5 cm = 24,5 cm 1CA length of certificate Only subtract 2,5 once 1 mark Use the width 1 mark Using a length = 29,5 cm and having an answer less than 29,5cm - 1 mark A = π r = 3,14 (5 cm) 2 = 78,5 cm SF P = 2 (29,5 cm + 21 cm) SF 1SF/CA substitution in formula (CA from A unit Accept calculator 22 π = or π on the 7 1SF substitution in formula = 101 cm A = 29,5 cm 21 cm 2 = 619,5 cm SF 1SF substitution in formula

7 Mathematical Literacy/P1 7 DoE/12 November : A 1MA ratio in correct order = 3 : 10 1 mark if one of the numbers is 1 Accept notation 10 3 but refer to question guests 7 = 90 guests 1A correct fraction CRECT ANSWER ONLY FULL MARKS 2.2.3* 1 litre concentrate makes 5 litres of juice A 5 litres concentrate makes 5 5 l = 25 l Number of litres of juice = 4 5 l l A = 20 l + 5 l = 25 l 1MA dilution ratio 1MA dilution ratio 20 l 1 mark

8 Mathematical Literacy/P1 8 DoE/12 November Eastern Cape or A 1A correct province D = 100% 15% 6% 13% 50% A 1MA setting up model 16 = 16 % or 0,16 or 100 ANSWER ONLY FULL MARKS Gauteng or B 1CA correct province Check the answer to D (2.3.2) A 18 A vehicles 0, = ,92 vehicles vehicles R 1MA 18% of vehicles stolen 1MA correct no. of vehicles the product 1R rounding ANSWER ONLY FULL MARKS (4) (a) (b) (c) R750 Loss RG 1 RG reading from graph 10 RG 2RG reading from graph Profit Percentage profit = 100% Expenses SF R400 = 100% R850 1A 1SF substitution into formula = 47, % S 1S simplification 47,1% R 1R rounding off

9 Mathematical Literacy/P1 9 DoE/12 November 2009 QUESTION 3 [19] years 1A modal age years 1A median Mean 1M sum of values = = years 15 A 1MA dividing by size of sample = 17,8666 years R = 17,87 years 1R rounding off ANSWER ONLY FULL MARKS (4) (a) (b) % 1A lowest 100% 1A highest PERF- MANCE LEVEL PERCENTAGE RANGE TALLY FRE- QUENCY 1 0 to 29 //// to 39 //// to 49 //// //// / to 59 //// /// to 69 //// to 79 //// /// to 100 //// //// / 11 1A learners in level 1 1A learners in level 2 1A learners in level 3 1A learners in level 4 1A learners in level 5 1A learners in level 6 1A learners in level 7 (7) If cumulative frequency is correct, maximum of 3 marks. If addition shown in cumulative frequency, maximum of 4 Ignore cumulative frequency if both are given

10 Mathematical Literacy/P1 10 DoE/12 November learners 1,6 m 2 /learner /A 1M/A multiplication = 83,2 m 2 1A simplifying Number of learners = 96 1,6 1M division/correct values = 60 learners 1A solution

11 Mathematical Literacy/P1 11 DoE/12 November 2009 QUESTION 4 [23] km C R 1C conversion to time 08:30 1R reading from table :45 RT 2RT reading from table km Speed = SF 1SF substitution into formula (a) 2 h = 60 km/h 1CA solution (b) 72 minutes = 1,2 hours Distance = 80 km/h SF 1,2h Distance = 80 1,2 km = 96 km 1A conversion to hours 1SF substitution into formula 1CA solution minutes 80 km 1A distance for 1 hour minutes 80 km = 16 km minutes = 80 km + 16 km = 96 km 1A distance for 12 minutes 1CA distance for 72 minutes 80 X 72-1 Mark

12 Mathematical Literacy/P1 12 DoE/12 November DISTANCE TRAVELLED AGAINST TIME TAKEN 120 Mr Lebelo Mr Goldman Distance in km A starting point for Mr Lebelo at 07: A plot any 4 points 20 1CA joining all points plotted :00 07:15 07:30 07:45 08:00 08:15 08:30 08:45 09:00 Time CRECT GRAPH WITHOUT PLOTTING INDIVIDUAL POINTS FULL MARKS (4) (a) (b) (c) 1 hour (in terms of Mr Goldman) RG ¾ hour or 45 minutes (in terms of Mr Lebelo) 60 km RG RG RG RG 100 km 90 km 1RG Reading from the graph or table 2RG Reading from the graph or table 1M subtraction 1RG reading from graph or table 1RG reading from graph or table = 10 km (4) 4.2* Cost of petrol = 10 journeys 8 l R8,23 per l = R658,40 1A Number of journeys 1M multiplication

13 Mathematical Literacy/P1 13 DoE/12 November 2009 Question 5 [18] 2A ascending order ,51 ; 7,51 ; 7,64 ; 7,71 ; 7,81 ; 7,91 ; 8,05 ; 8, Descending order 1 mark Leave off 1 value 1 mark ,51 metres 1A mode Range = 8,02 m 7,23 m 1M largest smallest = 0,79 m 1CA solution ANSWER ONLY FULL MARKS Shortest jump = 7,23 m 1A shortest jump ,23 m = 7, cm = 723 cm C 1C conversion 1CA answer in cm ANSWER ONLY FULL MARKS ,64+ 7,82 Median = m 2 = 7,73 m 1M method 1A solution ANSWER ONLY FULL MARKS Charles 5.2 V = 9 m 2,75 m 0,07 m 3 = 1,7325 m 1,733m 3 SF 2A solution 1SF substitution 1CA simplification 1CA rounding off and correct unit ANSWER ONLY FULL MARKS August 1991 October 1968 A = 22 years 10 months 23 years Also accept = 23 years 1MA method 1CA solution 1CA rounding off ANSWER ONLY FULL MARKS

14 Mathematical Literacy/P1 14 DoE/12 November 2009 QUESTION 6 [18] ,2% RT 1RT reading from table RT RT Difference = RT reading from table = CA difference (a) A = 100% 22,3% 60,2% 3,6% = 13,9% A 1MA correct values 1CA value of A A = 100% = 13,9 % A (b) RT B = = RT reading from table 1CA finding the sum

15 Mathematical Literacy/P1 15 DoE/12 November GRANT TYPES AS A PERCENTAGE OF TOTAL GRANTS 1A Old-age RECEIVED 2007 (accept 18%) Percentage A Child support in 2007 (accept 66%) 1A Disability in 2007 (accept 12%) 1A Other 2007 (accept 4%) Old-age Child support Disability Other (take out bold lines in English memo) = 32 RT 0,03 3,13% Types of grants S (4) 1RT reading correct value for burial policy 1M dividing value by total 1S simplifying RT R960 R15,45 R24,50 R60,00 R30,00 R40,00 R86,40 = R703,65 ANSWER ONLY FULL MARKS 1RT correct values 1M method 1CA simplifying ANSWER ONLY FULL MARKS

16 Mathematical Literacy/P1 16 DoE/November 2009 NSC Memorandum QUESTION 7 [15] (a) A = SF = 7 1 SF substitution into formula 1CA value of A (b) 10 = B B = 9 S B = 3 SF 1 SF substitution into formula 1S simplifying equation 1CA value of B = B = 3 SF S 1SF substitution into formula 1S simplifying equation 1CA value of B St Patrick s College RT RT 2RT reading from the table C2 (or 2C) RG 1RG reading from the map 7.2.2** From Kokstad College turn right /NE into Elliot Street. Continue At Barclay Road turn right/ SE. Kokstad Rugby Club will be on the left. 2A correct directions (Street name and direction) ** South-east/North-west 1A correct direction cm represents cm 1A scale interpretation Therefore, 5 cm would represent cm 1M multiplication S = cm 1S simplification = m C 1C conversion (4) TOTAL: 150 marks

NATIONAL SENIOR CERTIFICATE GRADE 12

NATIONAL SENIOR CERTIFICATE GRADE 12 MATHEMATICAL LITERACY P1 NOVEMBER 2009 MEMORANDUM MARKS: 150 Symbol M MA CA A C S R/RG SF O P R Explanation Method Method with accuracy Consistent accuracy Accuracy