Errata (Includes critical corrections only for the 1 st, 2 nd & 3 rd reprints)

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1 Errata (Includes critical corrections only for the 1 st, 2 nd & 3 rd reprints) Mechanics of Materials, 8e James M. Gere & Barry J. Goodno ISBN: Page Number Description of Correction 15 Example 1-1: in Part (1), on. p. 15, change asin to arcsin 17 Example 1-1 (cont.): on p. 17, change atan to arctan (3 occurrences) 50 Example 1-7, Part (b): just below Fig. 1-42, change atan to arctan 77 Example 1-13: 1/3 down page, two occurrences, change atan to arctan 89 Figure for Prob : in fig. part (a), dimension 241 mm at bottom left should be 254 mm (note that 241 mm dimension at top is OK) 91 Prob : Part (c) Wire 3 is supported at ( 10 ft, 85 ft, 75 ft). (i.e., sign is negative on 10-ft coordinate) 92 Prob (a), line 1: change T i (i = 1, 2, 3) to T 1 (i = 1, 2, 3) Note: Subscript i should be Use this revised problem statement for problem : A removable sign post on a hurricane evacuation route (see figure part a) consists of an upper pole with a slotted base plate which is bolted to a short post anchored in the ground. The lower post is capped with a separate conventional base plate having four holes of diameter d b. The upper slotted base plate has slots (or cut outs) at bolt locations 1 to 4 and is bolted to the conventional lower base plate at these four points (see figure part b). Each of the four bolts has a diameter of d b and a washer with diameter of d w. The bolts are arranged in a rectangular pattern (b h). Consider only wind force W y applied in the y direction at the center of pressure of the sign structure at height z = L above the base. Neglect the weight of the sign and post, and also neglect friction between the upper and lower base plates. Assume that the lower conventional base plate and short anchored post are rigid. (a) Find the average shear stress τ (MPa) at bolt 1 (see figure part c) due to the wind force W y ; repeat for bolt 4. (b) Find the average bearing stress σ b (MPa) between the bolt and the upper slotted base plate (thickness t) at bolt 1; repeat for bolt 4. (c) Find the average shear stress σ b (MPa) between the upper base plate and washer at bolt 4 due to the wind force W y (assume the initial bolt pretension is zero). (d) Find the average bearing stress τ (MPa) through the upper base plate at bolt 4 due to the wind force W y. (e) Find an expression for the normal stress σ in bolt 3 due to the wind force W y. [See Prob for additional discussion of wind on a sign, and the resulting forces acting on a conventional base plate.]

2 174 Eq (c) at bottom of page: insert missing parentheses 202 Fig. 2-67(b): should be ct not cl in equ. for σ nom 204 Fig. 2-67(b) repeated: should be ct not cl in equ. for σ nom ( t is for bar thickness) 281 Example 3-5, line 13: DELETE Δ3 in integral expression 288 Example 3-6, 4 th line from bottom: should read as (from Eq. 3-32) not Eq In Eq. (b), delete last part of equ. i.e., delete last phrase x = qxdx ( ) Prob : roller support is missing in drawing (Fig. (b)) Fig (b) should be the same as Fig (b) on p Example 5-1: in equ. at bottom of page, need an equal sign before 3.0 in./ ; so this part of eq. should be = ( 3.0 in.)/ Equation 5-19b: change to 485 Prob : In 2 nd fig., change in. to in. and change in. to in. 533 Typo in subscript in unnumbered equ. which follows Eq. 6-32; correction is as follows: 540 Example 6-8, last two lines on page: Just right of = sign: I z /I y, not I z /I z [i.e., y subscript in denom.] β = 78.6º [not 89.1] 587 Prob : yield stress σ Y = 36 ksi (not psi) 605 & repeated on 606 Example 7-3, Fig. 7-14(d): Direction of one arrow on top face of element should be reversed (i.e., arrow circled below)

3 653 Prob : Direction of arrows on top and left faces of element should be reversed (i.e., arrows circled below) nd part of Eq. 8-19b: (2 ν), not (2 2ν) i.e., delete 2 before ν in last term 700 Example 8-5: θ p = 9.11 (not 6.29 ) > see 3 rd line up from equ. at bottom of page 718 Prob : in 4 th line, change in MPa to in ksi 722 Prob : typo in prob. statement; pole weight is 4.0 kips, not 8.8 lb 727 Figure for Prob (b): use Greek symbols for stress, σ and τ, in fig. (b) [not s and t ] 758 Example 9-9: in Fig. 9-21(c), deflection is δ C, not d C [Use Greek letter delta]; also, in Fig. 9-21(c), deflections are δ 1 and δ 2, not d 1 and d 2 [Use Greek letter delta] 810 Prob : uniform load of intensity q (use q not a ) 1029 Prob. A-10.3: on fig. at bottom of page, θ B1 should be θ B2 (note that θ B1 is OK in middle fig.) 1096 part of answer for Prob (b): change 0.081% to 0.052% 1096 Prob : answer to (b) should be 4.92 mm (not 4.50 mm) 1097 Prob : Answer to (a) is mm (not 225 mm) Answer to (b) is mm (not 242 mm) 1101 Prob (b): d 2 = 80.5 mm (not 74.4) 1103 Prob (b): change P 2 = 9 kn to P 2 = 4 kn 1103 Prob (c): change P 1 = 2 kn (acting to right) to P 1 = 8 kn (acts to right) 1103 Prob Should provide numerical answers, not formula answers as follows: (a) Vmax = 800 lb, Mmax = 4800 ft-lb (b) Vmax = 1440 lb, Mmax = 8640 ft-lb 1104 Prob (b): h = 3.15 in. to h = 3.20 in Prob Answers

4 Change 424 lb/ft to 419 lb/ft and change 268 lb/ft to 264 lb/ft 1105 Prob (b): change d min = 45.2 mm, area (b) /area (a) = to d min = 42.4 mm, area (b) /area (a) = Prob : (a) Incorrect answers posted; correct answers are: (b) Part of answer is missing; please add 1111 Answer to Prob (b): ε r = Answer to Prob (b): ε r = Prob (a) Answers: replace answers with the following 1111 Prob (b) Answers: replace answers with the following 1111 Prob (a) Answers: replace answers with the following 1111 Prob (b) Answers: replace answers with the following 1111 Prob (b): answers for Part (b) are: σ 1 = 49.6 psi, σ 2 = 762 psi, τ max = 406 psi 1116 Answers for Prob :

5 1118 Answers for Prob : Wednesday, March 27, 2013

Errata (Includes critical corrections only for the 1 st, 2 nd & 3 rd reprints)

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