Combined Flexure and Axial Load
|
|
- Kelley Pitts
- 5 years ago
- Views:
Transcription
1 Cobied Flexure ad Axial Load Iteractio Diagra Partiall grouted bearig wall Bearig Wall: Sleder Wall Deig Procedure Stregth Serviceabilit Delectio Moet Magiicatio Exaple Pilater Bearig ad Cocetrated Load Pretreed Maor Cobied Flexural ad Axial Load 1 Ke Code Sectio 5.3 Colu 5.4 Pilater 9.3. Deig auptio Noial tregth Noial axial ad lexural tregth Sectio Radiu o gratio Wall deig or out-o-plae load Scope Noial axial ad lexural tregth Noial hear tregth P-delta eect Delectio Cobied Flexural ad Axial Load
2 Cocetric Axial Copreio P h h A A A P t t 140r 70r h A A A 99 t t h r r =0.9 A t = area o laterall tied teel P euler EI h EA r h 900 A r h A 94. r h Equatio above or CMU; or cla (E = 700 ), ter i (83.1r/h) Code equatio actuall derived ro ureiorced aor ad a o-teio aterial, but iilar to Euler buclig Icluio o wall weight Wall weight provide uior axial load over height o wall. Reaoable approxiatio i to ue hal the weight o wall actig at top. Cobied Flexural ad Axial Load 3 Buclig Curve or A t = h/r = 99 P /(A ' ) A P h 1 140r 70r P A h h/r Cobied Flexural ad Axial Load 4
3 Radiu o Gratio Radiu o gratio Radiu o gratio hall be coputed uig average et cro-ectioal area o the eber coidered. Quetio: I thi a trict average or weighted average? What about dieret tpe o uit (which chage bloc area)? What i the eect o bod bea? NCMA ha tabulated value o average radii o gratio baed o average o ortar bedded area ad bloc area. Beett oe ue / i the exaple ad preadheet. Ureiorced Maor 5 Iteractio Diagra Aue trai/tre ditributio Copute orce i aor ad teel Su orce to get axial orce Su oet about ceterlie to get bedig oet Ke poit Pure axial load Pure bedig Balaced Cobied Flexural ad Axial Load 6
4 Exaple 8 i. CMU Bearig Wall Give: 1 high CMU bearig wall, Tpe S aor ceet ortar; Grade 60 teel i ceter o wall; 48 i.; partial grout; = 000 pi Required: Iteractio diagra i ter o capacit per oot Pure Moet: A Noial oet, M M A d 1 A 0.8b ' Deig oet, M M Chec to ae ure tre bloc i i ace hell A a 0.8b ' i 60i i.0 i 0.156i Cobied Flexural ad Axial Load 7 Exaple 8 i. CMU Bearig Wall Pure Axial: NCMA TEK 14-1B Sectio Propertie o Cocrete Maor Wall r =.66 i. A = 40.7i / I = 33.0 i 4 / Fid h/r Fid P P A A A t t h 1 140r P Uig h/r = 50.4 = 40.8 / Cobied Flexural ad Axial Load 9
5 Exaple 8 i. CMU Bearig Wall 0.8 = 1.6 i T Balaced: Strai C Stre 3.81 i a = 0.8c = 0.8(.09i.) = 1.67i. web legth = Fid C C, ace hell C, web Fid T Fid P i 60i T A 0 P M Fid M Cobied Flexural ad Axial Load 11 Exaple 8 i. CMU Bearig Wall Below Balaced: c = 1.5 i i 3.81 i Strai = 1.6 i a = 0.8c 1.00 i Stre T Fid C ab 0.8.0i1.00i1 i 19. C 0.8 Fid T Fid i 60i T A 0 C P -T 6 P M Fid M i i i Cobied Flexural ad Axial Load 13
6 Exaple 8 i. CMU Bearig Wall Above Balaced: c = 3.0 i i 3.81 i Strai = 1.6 i C Stre T a = 0.8c = 0.8(3.0i.) =.4i. web legth =....0 Fid C Fid T Fid i1.5i1 i C 4, ace hell i.40i 1.5i.0 i 3. C 68, web i T E A 9000i P P M Fid M 1.5i i i 6. 8 Cobied Flexural ad Axial Load 14 Exaple 8 i. CMU Bearig Wall Poit c (i) C, (ip/) C,web (ip/) T (ip/) P (ip/) M (ip-/) a = d c = d Balaced a = 1.5 i Pure Moet Cobied Flexural ad Axial Load 15
7 Exaple 8 i. CMU Bearig Wall Cobied Flexural ad Axial Load 16 Iteractio Diagra Solid v. Partial Grout Cobied Flexural ad Axial Load 17
8 Iteractio Diagra Below Balaced Teio, T Copreio, C Noial Axial Stregth, P T A C 0. 8 ba P C T ba A Solve or a Noial Moet Stregth, M a M A P 0.80 b tp a 0.8 ba A t a tp d t p p P A A d Ca olve or M i P i ow Cobied Flexural ad Axial Load 18 Iteractio Diagra Below Balaced φp M u, P u I we could ol ow oe poit o the iteractio diagra, we would wat to ow the poit correpodig to P = P u φm a A P / 0.80 b u M t a p p Pu / A A d t Thee are equatio i coetar. The igore a teio i a poible ecod laer o teel ear the copreio ace). M For cetered bar: a Pu / A d Cobied Flexural ad Axial Load 19
9 Deig: Cobied Bedig ad Axial Load a d d Pu d t Calculate p 0.8 b / M u c a 0.8 YES I c c bal? For Grade 60 teel c bal = c bal u u d NO A 0.8 ba Pu / d c ue c Copreio cotrol A 0.8 ba Pu / Teio cotrol Cobied Flexural ad Axial Load 0 Exaple: Pilater Deig Give: Noial 16 i. wide x 16 i. deep CMU pilater; =000 pi; Grade 60 bar i each corer, ceter o cell; Eective height = 4 ; Dead load o 9.6 ip ad ow load o 9.6 ip act at a eccetricit o 5.8 i. ( i. iide o ace); Wid load o 6 p (preure ad uctio) ad upli o 8.1 ip (e=5.8 i.); Pilater paced at 16 o ceter; Wall i aued to pa horizotall betwee pilater; No tie. Required: Reiorceet Solutio: e=5.8 i.0 i Load d=11.8 i x Iide Lateral Load w = 6p(16) = 416lb/ d = / = 11.8 i Vertical Spaig Cobied Flexural ad Axial Load 1
10 Exaple: Pilater Deig Weight o pilater: Weight o ull grouted 8 i wall (lightweight uit) i 75 p. Pilater i lie a double thic wall. Weight i (75p)(16i)(1/1i) = 00 lb/ 1.D + 1.6S Critical locatio i top o pilater. P u = 6.9 ip M u = ip-i Fid a a d d 11.8i Pu d h / i b M u i 15.6i / i15.6i 156 i 1.04i c a / i./ 0.8 Chec c/d d d 11.8i. Teio cotrol Fid A 0.8 ba Pu / 0.8 A.0i15.6i1.04i 6.9 / i 0.066i Cobied Flexural ad Axial Load Exaple: Pilater Deig Wh the egative area o teel? Suiciet area ro jut aor to reit applied orce. Deterie a ro jut copreio. Pu 6.9ip a 1. 08i 0.8 b 0.8.0i 15.6i Fid the oet t a 15.6i 1.08i M P u 6.9ip 195ip i M u = 156 ip-i Suiciet capacit ro jut aor. No teel eeded. Cobied Flexural ad Axial Load 3
11 Exaple: Pilater Deig 0.9D + 1.0W Chec wid uctio At top o pilater. P u = 0.9(9.6) 1.0(8.1) = 0.54 ip M u = 0.54ip(5.8i) = 3.1 ip-i Locatio o axiu oet, x Maxiu oet, M u Axial orce, P u L M 88i 3.1ip i x i wl 0.416ip / 4 M u M wl 8 M wl 3.1 i / i 88i 8 (3.1 i) / i88i 0.0 / 143.7i1 /1i. P u Aue idheight oet i ~ M u. Third ter i M u add i i Deig or P u =.7 ip, M u = 361 -i Cobied Flexural ad Axial Load 4 Exaple: Pilater Deig 0.9D + 1.0W 1.D + 1.0W + 0.5S At top: P u =0.5 M u =3 -i x=144 i P u =.7 M u =361 -i a = 1.49 i A = 0.57 i At top: P u =8. M u =48-i x = 139i P u =11.0 M u =384-i a = 1.74 i A = 0.5 i 1.D + 1.6S + 0.5W At top: P u =.8 M u =13-i x=117i P u =5. M u =5-i a = 1.41 i A = 0.1 i Required teel = 0.57 i Ue -#5 each ace, A = 0.6 i Total bar, 4-#5, oe i each cell Cobied Flexural ad Axial Load 5
12 Exaple: Pilater Deig 1.D+1.6S 1.D+1.6S+0.5W 1.D+1.0W+0.5S 0.9D+1.0W Cobied Flexural ad Axial Load 6
Allowable Stress Design. Flexural Members - Allowable Stress Design. Example - Masonry Beam. Allowable Stress Design. k 3.
Loa Coiatio llowale Stre Deig () D () D + L () D + (L r or S or R) (4) D + 0.75L + 0.75(L r or S or R) (5) D + (0.6W or 0.7E) (6a) D + 0.75L + 0.75(0.6W) + 0.75(L r or S or R) (6) D + 0.75L + 0.75(0.7E)
More informationCombined Flexure and Axial Load
Cobied Flexre ad Axial Load teractio Diagra Solidl groted bearig wall Partiall groted bearig wall Bearig Wall: Sleder Wall Deig Procedre Stregt Serviceabilit Delectio Exaple Pilater Bearig ad Cocetrated
More informationS. K. Ghosh Associates Inc. Outline. q Introduction: masonry basics and code changes. q Beams and lintels. q Non-bearing walls: out-of-plane
S. K. Go Aociate Ic. Otlie ASD v. SD A aor Cage Figt Ricard Beett, PD, PE Te Uiverit o Teeee Cair, 016 TS 40/60 Code Coittee q Itrodctio: aor baic ad code cage q Bea ad litel q Nobearig wall: otoplae q
More informationUnreinforced Masonry Design. SD Interaction Diagram
Ureiforced asory Desig Code ectios, 9. 9.. cope 9.. Desig criteria 9.. Desig assptios 9..4 Noial flexral ad axial stregt 9..5 xial tesio 9..6 Noial sear stregt Key desig eqatio: f t c I Ureiforced asory
More informationTHE CONCEPT OF THE ROOT LOCUS. H(s) THE CONCEPT OF THE ROOT LOCUS
So far i the tudie of cotrol yte the role of the characteritic equatio polyoial i deteriig the behavior of the yte ha bee highlighted. The root of that polyoial are the pole of the cotrol yte, ad their
More informationInferences of Type II Extreme Value. Distribution Based on Record Values
Applied Matheatical Sciece, Vol 7, 3, o 7, 3569-3578 IKARI td, www-hikarico http://doiorg/988/a33365 Ierece o Tpe II tree Value Ditributio Baed o Record Value M Ahaullah Rider Uiverit, awreceville, NJ,
More informationARCH 631 Note Set 21.1 S2017abn. Steel Design
Steel Desig Notatio: a = ame or width dimesio A = ame or area Ag = gross area, equal to the total area igorig a holes Areq d-adj = area required at allowable stress whe shear is adjusted to iclude Aw sel
More informationFig. 1: Streamline coordinates
1 Equatio of Motio i Streamlie Coordiate Ai A. Soi, MIT 2.25 Advaced Fluid Mechaic Euler equatio expree the relatiohip betwee the velocity ad the preure field i ivicid flow. Writte i term of treamlie coordiate,
More informationWhat is Uniform flow (normal flow)? Uniform flow means that depth (and velocity) remain constant over a certain reach of the channel.
Hydraulic Lecture # CWR 4 age () Lecture # Outlie: Uiform flow i rectagular cael (age 7-7) Review for tet Aoucemet: Wat i Uiform flow (ormal flow)? Uiform flow mea tat det (ad velocity) remai cotat over
More informationStructural Eurocodes EN 1995 Design of Timber Structures
Structural Eurocoes EN 995 Design o Tiber Structures John J Murph Chartere Engineer EN 995-- Design o Tiber Structures General Coon Rules an Rules or Builings Liit state esign Tiber Properties IS-EN 338:
More informationChapter 9. Key Ideas Hypothesis Test (Two Populations)
Chapter 9 Key Idea Hypothei Tet (Two Populatio) Sectio 9-: Overview I Chapter 8, dicuio cetered aroud hypothei tet for the proportio, mea, ad tadard deviatio/variace of a igle populatio. However, ofte
More informationSection 7. Gaussian Reduction
7- Sectio 7 Gaussia eductio Paraxial aytrace Equatios eractio occurs at a iterace betwee two optical spaces. The traser distace t' allows the ray height y' to be determied at ay plae withi a optical space
More informationStatistical Inference Procedures
Statitical Iferece Procedure Cofidece Iterval Hypothei Tet Statitical iferece produce awer to pecific quetio about the populatio of iteret baed o the iformatio i a ample. Iferece procedure mut iclude a
More informationrad / sec min rev 60sec. 2* rad / sec s
EE 559, Exa 2, Spig 26, D. McCalley, 75 iute allowed. Cloed Book, Cloed Note, Calculato Peitted, No Couicatio Device. (6 pt) Coide a.5 MW, 69 v, 5 Hz, 75 p DFG wid eegy yt. he paaete o the geeato ae give
More informationQuestions about the Assignment. Describing Data: Distributions and Relationships. Measures of Spread Standard Deviation. One Quantitative Variable
Quetio about the Aigmet Read the quetio ad awer the quetio that are aked Experimet elimiate cofoudig variable Decribig Data: Ditributio ad Relatiohip GSS people attitude veru their characteritic ad poue
More informationCE 562 Structural Design I Midterm No. 1 Closed Book Portion (25 / 100 pts)
CE 56 Structural Desig I Name: Midterm No. 1 Closed Book Portio (5 / 100 pts) 1. [6 pts / 5 pts] Two differet tesio members are show below - oe is a pair of chaels coected back-to-back ad the other is
More informationChapter #5 EEE Control Systems
Sprig EEE Chpter #5 EEE Cotrol Sytem Deig Bed o Root Locu Chpter / Sprig EEE Deig Bed Root Locu Led Cotrol (equivlet to PD cotrol) Ued whe the tedy tte propertie of the ytem re ok but there i poor performce,
More informationCase Study in Steel adapted from Structural Design Guide, Hoffman, Gouwens, Gustafson & Rice., 2 nd ed.
Case Std i Steel adapted from Strctral Desig Gide, Hoffma, Gowes, Gstafso & Rice., d ed. Bildig descriptio The bildig is a oe-stor steel strctre, tpical of a office bildig. The figre shows that it has
More informationB U I L D I N G D E S I G N
B U I L D I N G D E S I G N 10.1 DESIGN OF SLAB P R I O D E E P C H O W D H U R Y C E @ K 8. 0 1 7 6 9 4 4 1 8 3 DESIGN BY COEFFICIENT METHOD Loads: DL = 150 pc LL = 85 pc Material Properties: c = 3000
More informationFlight and Orbital Mechanics. Exams
1 Flight ad Orbital Mechaics Exas Exa AE2104-11: Flight ad Orbital Mechaics (2 Noveber 2012, 14.00 17.00) Please put your ae, studet uber ad ALL YOUR INITIALS o your work. Aswer all questios ad put your
More informationSOLUTION: The 95% confidence interval for the population mean µ is x ± t 0.025; 49
C22.0103 Sprig 2011 Homework 7 olutio 1. Baed o a ample of 50 x-value havig mea 35.36 ad tadard deviatio 4.26, fid a 95% cofidece iterval for the populatio mea. SOLUTION: The 95% cofidece iterval for the
More informationX. Perturbation Theory
X. Perturbatio Theory I perturbatio theory, oe deals with a ailtoia that is coposed Ĥ that is typically exactly solvable of two pieces: a referece part ad a perturbatio ( Ĥ ) that is assued to be sall.
More informationThe Performance of Feedback Control Systems
The Performace of Feedbac Cotrol Sytem Objective:. Secify the meaure of erformace time-domai the firt te i the deig roce Percet overhoot / Settlig time T / Time to rie / Steady-tate error e. ut igal uch
More information8.6 Order-Recursive LS s[n]
8.6 Order-Recurive LS [] Motivate ti idea wit Curve Fittig Give data: 0,,,..., - [0], [],..., [-] Wat to fit a polyomial to data.., but wic oe i te rigt model?! Cotat! Quadratic! Liear! Cubic, Etc. ry
More informationC. C. Fu, Ph.D., P.E.
ENCE710 C. C. Fu, Ph.D., P.E. Shear Coectors Desig by AASHTO RFD (RFD Art. 6.10.10) I the egative flexure regios, shear coectors shall be rovided where the logitudial reiforcemet is cosidered to be a art
More informationSTUDENT S t-distribution AND CONFIDENCE INTERVALS OF THE MEAN ( )
STUDENT S t-distribution AND CONFIDENCE INTERVALS OF THE MEAN Suppoe that we have a ample of meaured value x1, x, x3,, x of a igle uow quatity. Aumig that the meauremet are draw from a ormal ditributio
More informationWe will look for series solutions to (1) around (at most) regular singular points, which without
ENM 511 J. L. Baai April, 1 Frobeiu Solutio to a d order ODE ear a regular igular poit Coider the ODE y 16 + P16 y 16 + Q1616 y (1) We will look for erie olutio to (1) aroud (at mot) regular igular poit,
More informationREVIEW OF SIMPLE LINEAR REGRESSION SIMPLE LINEAR REGRESSION
REVIEW OF SIMPLE LINEAR REGRESSION SIMPLE LINEAR REGRESSION I liear regreio, we coider the frequecy ditributio of oe variable (Y) at each of everal level of a ecod variable (X). Y i kow a the depedet variable.
More informationPerformance-Based Plastic Design (PBPD) Procedure
Performace-Baed Platic Deig (PBPD) Procedure 3. Geeral A outlie of the tep-by-tep, Performace-Baed Platic Deig (PBPD) procedure follow, with detail to be dicued i ubequet ectio i thi chapter ad theoretical
More informationStatistics and Chemical Measurements: Quantifying Uncertainty. Normal or Gaussian Distribution The Bell Curve
Statitic ad Chemical Meauremet: Quatifyig Ucertaity The bottom lie: Do we trut our reult? Should we (or ayoe ele)? Why? What i Quality Aurace? What i Quality Cotrol? Normal or Gauia Ditributio The Bell
More information5.1 WORKED EXAMPLE Header plate connection Geometrical and mechanical data e 1. p 1. e 2 p 2 e 2
5.1 WORKED EXAMPLE Header late coectio 5.1.1 Geoetrical ad echaical data e 1 M20 1 HEA200 IPE300 1 e 1 e 2 2 e 2 Mai joit data Coiguratio Bea to colu lage Colu HEA 200 S 235 Bea IPE 300 S 235 Tye o coectio
More informationComments on Discussion Sheet 18 and Worksheet 18 ( ) An Introduction to Hypothesis Testing
Commet o Dicuio Sheet 18 ad Workheet 18 ( 9.5-9.7) A Itroductio to Hypothei Tetig Dicuio Sheet 18 A Itroductio to Hypothei Tetig We have tudied cofidece iterval for a while ow. Thee are method that allow
More informationThe Binomial Multi- Section Transformer
4/4/26 The Bioial Multisectio Matchig Trasforer /2 The Bioial Multi- Sectio Trasforer Recall that a ulti-sectio atchig etwork ca be described usig the theory of sall reflectios as: where: ( ω ) = + e +
More informationLenses and Imaging (Part II)
Lee ad Imagig (Part II) emider rom Part I Surace o poitive/egative power eal ad virtual image Imagig coditio Thick lee Pricipal plae 09/20/04 wk3-a- The power o urace Poitive power : eitig ray coverge
More informationEECE 301 Signals & Systems Prof. Mark Fowler
EECE 30 Sigal & Sytem Prof. Mark Fowler Note Set #8 C-T Sytem: Laplace Traform Solvig Differetial Equatio Readig Aigmet: Sectio 6.4 of Kame ad Heck / Coure Flow Diagram The arrow here how coceptual flow
More information1. Brillouin zones of rectangular lattice. Make a plot of the first two Brillouin zones of a primitive rectangular two-dimensional lattice with axes
Chap9 練 Brilloui oe of rectagular lattice Mae a plot of the firt two Brilloui oe of a priitive rectagular two-dieioal lattice with axe a b=3a Brilloui oe rectagular lattice A two-dieioal etal ha oe ato
More informationDouble Derangement Permutations
Ope Joural of iscrete Matheatics, 206, 6, 99-04 Published Olie April 206 i SciRes http://wwwscirporg/joural/ojd http://dxdoiorg/04236/ojd2066200 ouble erageet Perutatios Pooya aeshad, Kayar Mirzavaziri
More informationQueueing Theory (Part 3)
Queueig Theory art 3 M/M/ Queueig Sytem with Variatio M/M/, M/M///K, M/M//// Queueig Theory- M/M/ Queueig Sytem We defie λ mea arrival rate mea ervice rate umber of erver > ρ λ / utilizatio ratio We require
More informationStatistics Parameters
Saplig Ditributio & Cofidece Iterval Etiator Statitical Iferece Etiatio Tetig Hypothei Statitic Ued to Etiate Populatio Paraeter Statitic Saple Mea, Saple Variace, Saple Proportio, Paraeter populatio ea
More informationSTRUNET CONCRETE DESIGN AIDS
Itrodutio to Corete Colum Deig Flow Chrt he Colum Deig Setio i Struet oti two mi prt: Chrt to develop tregth itertio digrm for give etio, d red -mde Colum Itertio Digrm, for quik deig of give olum. Corete
More informationMATH 2411 Spring 2011 Practice Exam #1 Tuesday, March 1 st Sections: Sections ; 6.8; Instructions:
MATH 411 Sprig 011 Practice Exam #1 Tuesday, March 1 st Sectios: Sectios 6.1-6.6; 6.8; 7.1-7.4 Name: Score: = 100 Istructios: 1. You will have a total of 1 hour ad 50 miutes to complete this exam.. A No-Graphig
More information5.6 Binomial Multi-section Matching Transformer
4/14/21 5_6 Bioial Multisectio Matchig Trasforers 1/1 5.6 Bioial Multi-sectio Matchig Trasforer Readig Assiget: pp. 246-25 Oe way to axiize badwidth is to costruct a ultisectio Γ f that is axially flat.
More informationChapter #3 EEE Subsea Control and Communication Systems
EEE 87 Chter #3 EEE 87 Sube Cotrol d Commuictio Sytem Cloed loo ytem Stedy tte error PID cotrol Other cotroller Chter 3 /3 EEE 87 Itroductio The geerl form for CL ytem: C R ', where ' c ' H or Oe Loo (OL)
More informationMultistep Runge-Kutta Methods for solving DAEs
Multitep Ruge-Kutta Method for olvig DAE Heru Suhartato Faculty of Coputer Sciece, Uiverita Idoeia Kapu UI, Depok 6424, Idoeia Phoe: +62-2-786 349 E-ail: heru@c.ui.ac.id Kevi Burrage Advaced Coputatioal
More informationA typical reinforced concrete floor system is shown in the sketches below.
CE 433, Fall 2006 Flexure Anali for T- 1 / 7 Cat-in-place reinforced concrete tructure have monolithic lab to beam and beam to column connection. Monolithic come from the Greek word mono (one) and litho
More information(s)h(s) = K( s + 8 ) = 5 and one finite zero is located at z 1
ROOT LOCUS TECHNIQUE 93 should be desiged differetly to eet differet specificatios depedig o its area of applicatio. We have observed i Sectio 6.4 of Chapter 6, how the variatio of a sigle paraeter like
More informationChapter 8.2. Interval Estimation
Chapter 8.2. Iterval Etimatio Baic of Cofidece Iterval ad Large Sample Cofidece Iterval 1 Baic Propertie of Cofidece Iterval Aumptio: X 1, X 2,, X are from Normal ditributio with a mea of µ ad tadard deviatio.
More informationEULER-MACLAURIN SUM FORMULA AND ITS GENERALIZATIONS AND APPLICATIONS
EULER-MACLAURI SUM FORMULA AD ITS GEERALIZATIOS AD APPLICATIOS Joe Javier Garcia Moreta Graduate tudet of Phyic at the UPV/EHU (Uiverity of Baque coutry) I Solid State Phyic Addre: Practicate Ada y Grijalba
More informationSpecial Notes: Filter Design Methods
Page Special Note: Filter Deig Method Spectral Poer epoe For j j j exp What i j Magitude (ut be the ae!): N M Q i i p z K j Phae: N M Q i i a p a z a j ta ta ta N M Q i i a p a z a j ta ta ta herefore
More informationSTABILITY OF THE ACTIVE VIBRATION CONTROL OF CANTILEVER BEAMS
Iteratioal Coferece o Vibratio Problem September 9-,, Liboa, Portugal STBILITY OF THE CTIVE VIBRTIO COTROL OF CTILEVER BEMS J. Tůma, P. Šuráe, M. Mahdal VSB Techical Uierity of Otraa Czech Republic Outlie.
More informationExercise 8 CRITICAL SPEEDS OF THE ROTATING SHAFT
Exercise 8 CRITICA SEEDS OF TE ROTATING SAFT. Ai of the exercise Observatio ad easureet of three cosecutive critical speeds ad correspodig odes of the actual rotatig shaft. Copariso of aalytically coputed
More informationCase Study in Steel adapted from Structural Design Guide, Hoffman, Gouwens, Gustafson & Rice., 2 nd ed.
ARCH 631 Note Set F014ab Case Std i Steel adapted from Strctral Desig Gide, Hoffma, Gowes, Gstafso & Rice., d ed. Bildig descriptio The bildig is a oe-stor steel strctre, tpical of a office bildig. The
More informationTESTS OF SIGNIFICANCE
TESTS OF SIGNIFICANCE Seema Jaggi I.A.S.R.I., Library Aveue, New Delhi eema@iari.re.i I applied ivetigatio, oe i ofte itereted i comparig ome characteritic (uch a the mea, the variace or a meaure of aociatio
More information4.8,.13 Friction and Buoyancy & Suction
Mo. Tue We. Lab ri. 4.8,.13 rictio a Buoac & Suctio 5.1-.5 Rate of Chae & Copoet Quiz 4 L4b: Buoac, Review for Ea 1(Ch 1-4) Ea 1 (Ch 1-4) RE 4. EP 4, HW4: Ch 4 Pr 46, 50, 81, 88 & CP RE 5.a bri laptop,
More informationCheck the strength of each type of member in the one story steel frame building below.
CE 33, Fall 200 Aalysis of Steel Baced Fame Bldg / 7 Chec the stegth of each type of membe the oe stoy steel fame buildg below. A 4 @ 8 B 20 f 2 3 @ 25 Side Elevatio 3 4 Pla View 32 F y 50 si all membes
More informationMath 21C Brian Osserman Practice Exam 2
Math 1C Bria Osserma Practice Exam 1 (15 pts.) Determie the radius ad iterval of covergece of the power series (x ) +1. First we use the root test to determie for which values of x the series coverges
More informationRAYLEIGH'S METHOD Revision D
RAYGH'S METHOD Revisio D B To Irvie Eail: toirvie@aol.co Noveber 5, Itroductio Daic sstes ca be characterized i ters of oe or ore atural frequecies. The atural frequec is the frequec at which the sste
More informationChapter Vectors
Chapter 4. Vectors fter readig this chapter you should be able to:. defie a vector. add ad subtract vectors. fid liear combiatios of vectors ad their relatioship to a set of equatios 4. explai what it
More informationMATH Exam 1 Solutions February 24, 2016
MATH 7.57 Exam Solutios February, 6. Evaluate (A) l(6) (B) l(7) (C) l(8) (D) l(9) (E) l() 6x x 3 + dx. Solutio: D We perform a substitutio. Let u = x 3 +, so du = 3x dx. Therefore, 6x u() x 3 + dx = [
More informationm = Statistical Inference Estimators Sampling Distribution of Mean (Parameters) Sampling Distribution s = Sampling Distribution & Confidence Interval
Saplig Ditributio & Cofidece Iterval Uivariate Aalyi for a Nueric Variable (or a Nueric Populatio) Statitical Iferece Etiatio Tetig Hypothei Weight N ( =?, =?) 1 Uivariate Aalyi for a Categorical Variable
More informationEigenfrequencies and Critical Speeds on a Beam due to Travelling Waves
The Ope echaic Joural, 9,, -9 Ope cce igefrequecie ad Critical Speed o a Bea due to Travellig Wave T.G. Kotatakopoulo, I.G. Raftoiai ad G.T. ichalto* Departet of Civil gieerig, Natioal Techical Uiverit
More informationBinomial transform of products
Jauary 02 207 Bioial trasfor of products Khristo N Boyadzhiev Departet of Matheatics ad Statistics Ohio Norther Uiversity Ada OH 4580 USA -boyadzhiev@ouedu Abstract Give the bioial trasfors { b } ad {
More informationSupplementary Information
Suppleetary Iforatio -Breakdow of cotiuu fracture echaics at the aoscale- Takahiro Shiada,,* Keji Ouchi, Yuu Chihara, ad Takayuki Kitaura Departet of echaical Egieerig ad Sciece, Kyoto Uiversity, Nishikyo-ku,
More informationChapter 2. Asymptotic Notation
Asyptotic Notatio 3 Chapter Asyptotic Notatio Goal : To siplify the aalysis of ruig tie by gettig rid of details which ay be affected by specific ipleetatio ad hardware. [1] The Big Oh (O-Notatio) : It
More information18.05 Problem Set 9, Spring 2014 Solutions
18.05 Problem Set 9, Sprig 2014 Solutio Problem 1. (10 pt.) (a) We have x biomial(, θ), o E(X) =θ ad Var(X) = θ(1 θ). The rule-of-thumb variace i jut 4. So the ditributio beig plotted are biomial(250,
More informationMechanical Vibrations
Mechaical Vibratios Cotets Itroductio Free Vibratios o Particles. Siple Haroic Motio Siple Pedulu (Approxiate Solutio) Siple Pedulu (Exact Solutio) Saple Proble 9. Free Vibratios o Rigid Bodies Saple Proble
More informationSHEAR LAG MODELLING OF THERMAL STRESSES IN UNIDIRECTIONAL COMPOSITES
ORA/POSER REFERENCE: ICF00374OR SHEAR AG MODEING OF HERMA SRESSES IN UNIDIRECIONA COMPOSIES Chad M. adis Departet o Mechaical Egieerig ad Materials Sciece MS 3 Rice Uiversity P.O. Box 89 Housto X 7705
More informationExample of CLT for Symmetric Laminate with Mechanical Loading
Exaple of CL for Syetric Laate with Mechaical Loadg hese are two probles which detail the process through which the laate deforatios are predicted usg Classical Laatio theory. he first oly cludes echaical
More informationName Period ALGEBRA II Chapter 1B and 2A Notes Solving Inequalities and Absolute Value / Numbers and Functions
Nae Period ALGEBRA II Chapter B ad A Notes Solvig Iequalities ad Absolute Value / Nubers ad Fuctios SECTION.6 Itroductio to Solvig Equatios Objectives: Write ad solve a liear equatio i oe variable. Solve
More informationEngineering Mechanics Dynamics & Vibrations. Engineering Mechanics Dynamics & Vibrations Plane Motion of a Rigid Body: Equations of Motion
1/5/013 Egieerig Mechaics Dyaics ad Vibratios Egieerig Mechaics Dyaics & Vibratios Egieerig Mechaics Dyaics & Vibratios Plae Motio of a Rigid Body: Equatios of Motio Motio of a rigid body i plae otio is
More informationUNIVERSITY OF NORTHERN COLORADO MATHEMATICS CONTEST. First Round For all Colorado Students Grades 7-12 November 3, 2007
UNIVERSITY OF NORTHERN COLORADO MATHEMATICS CONTEST First Roud For all Colorado Studets Grades 7- November, 7 The positive itegers are,,, 4, 5, 6, 7, 8, 9,,,,. The Pythagorea Theorem says that a + b =
More informationProblem Cosider the curve give parametrically as x = si t ad y = + cos t for» t» ß: (a) Describe the path this traverses: Where does it start (whe t =
Mathematics Summer Wilso Fial Exam August 8, ANSWERS Problem 1 (a) Fid the solutio to y +x y = e x x that satisfies y() = 5 : This is already i the form we used for a first order liear differetial equatio,
More informationDefine a Markov chain on {1,..., 6} with transition probability matrix P =
Pla Group Work 0. The title says it all Next Tie: MCMC ad Geeral-state Markov Chais Midter Exa: Tuesday 8 March i class Hoework 4 due Thursday Uless otherwise oted, let X be a irreducible, aperiodic Markov
More information6.4 Binomial Coefficients
64 Bioial Coefficiets Pascal s Forula Pascal s forula, aed after the seveteeth-cetury Frech atheaticia ad philosopher Blaise Pascal, is oe of the ost faous ad useful i cobiatorics (which is the foral ter
More information5.6 Binomial Multi-section Matching Transformer
4/14/2010 5_6 Bioial Multisectio Matchig Trasforers 1/1 5.6 Bioial Multi-sectio Matchig Trasforer Readig Assiget: pp. 246-250 Oe way to axiize badwidth is to costruct a ultisectio Γ f that is axially flat.
More informationTESTING GEOGRIDS. Test Procedure for. TxDOT Designation: Tex-621-J 1. SCOPE 2. DEFINITION 3. SAMPLING 4. DETERMINING APERTURE SIZE
est Procedure for xdo Desigatio: ex-621- Effective Date: August 1999 1. SCOPE 1.1 Use this method to sample ad test geogrid materials used i costructio. 1.2 Characteristics Covered aperture size percet
More informationAnswer keys. EAS 1600 Lab 1 (Clicker) Math and Science Tune-up. Note: Students can receive partial credit for the graphs/dimensional analysis.
Anwer key EAS 1600 Lab 1 (Clicker) Math and Science Tune-up Note: Student can receive partial credit for the graph/dienional analyi. For quetion 1-7, atch the correct forula (fro the lit A-I below) to
More informationCALCULUS BASIC SUMMER REVIEW
CALCULUS BASIC SUMMER REVIEW NAME rise y y y Slope of a o vertical lie: m ru Poit Slope Equatio: y y m( ) The slope is m ad a poit o your lie is, ). ( y Slope-Itercept Equatio: y m b slope= m y-itercept=
More information: Transforms and Partial Differential Equations
Trasforms ad Partial Differetial Equatios 018 SUBJECT NAME : Trasforms ad Partial Differetial Equatios SUBJECT CODE : MA 6351 MATERIAL NAME : Part A questios REGULATION : R013 WEBSITE : wwwharigaeshcom
More informationConfidence Intervals. Confidence Intervals
A overview Mot probability ditributio are idexed by oe me parameter. F example, N(µ,σ 2 ) B(, p). I igificace tet, we have ued poit etimat f parameter. F example, f iid Y 1,Y 2,...,Y N(µ,σ 2 ), Ȳ i a poit
More informationGeometry Unit 3 Notes Parallel and Perpendicular Lines
Review Cocepts: Equatios of Lies Geoetry Uit Notes Parallel ad Perpedicular Lies Syllabus Objective:. - The studet will differetiate aog parallel, perpedicular, ad skew lies. Lies that DO NOT itersect:
More informationISSN Author: Ramesh Chandra Bagadi. Affiliation 3: Affiliation 1: Affiliation 2: Founder & Owner Ramesh Bagadi Consulting LLC (R420752),
Bagadi, R. (07). The Recursive Future Ad Past Equatio Based O The Aada-Daaathi Noralized iilarit Measure Cosidered To Exhaustio {Latest Ultiate Correct Versio}. IN 75-3030. PHILICA.COM Article uber 04.
More informationUNIFORM FLOW. U x. U t
UNIFORM FLOW if : 1) there are o appreciable variatios i the chael geometry (width, slope, roughess/grai size), for a certai legth of a river reach ) flow discharge does ot vary the, UNIFORM FLOW coditios
More informationGroup Technology and Facility Layout
Group Techology ad Facility Layout Chapter 6 Beefits of GT ad Cellular Maufacturig (CM) REDUCTIONS Setup tie Ivetory Material hadlig cost Direct ad idirect labor cost IMPROVEMENTS Quality Material Flow
More informationIntegrals of Functions of Several Variables
Itegrals of Fuctios of Several Variables We ofte resort to itegratios i order to deterie the exact value I of soe quatity which we are uable to evaluate by perforig a fiite uber of additio or ultiplicatio
More informationLLT Education Services
Pract Quet 1. Prove th Equal chord of a circle ubted equal agle the cetre.. Prove th Chord of a circle which ubted equal agle the cetre are equal. 3. Prove th he perpedicular from the cetre of a circle
More informationA string of not-so-obvious statements about correlation in the data. (This refers to the mechanical calculation of correlation in the data.
STAT-UB.003 NOTES for Wedesday 0.MAY.0 We will use the file JulieApartet.tw. We ll give the regressio of Price o SqFt, show residual versus fitted plot, save residuals ad fitted. Give plot of (Resid, Price,
More informationThe Coupon Collector Problem in Statistical Quality Control
The Coupo Collector Proble i Statitical Quality Cotrol Taar Gadrich, ad Rachel Ravid Abtract I the paper, the author have exteded the claical coupo collector proble to the cae of group drawig with iditiguihable
More informationThe picture in figure 1.1 helps us to see that the area represents the distance traveled. Figure 1: Area represents distance travelled
1 Lecture : Area Area ad distace traveled Approximatig area by rectagles Summatio The area uder a parabola 1.1 Area ad distace Suppose we have the followig iformatio about the velocity of a particle, how
More informationExplicit scheme. Fully implicit scheme Notes. Fully implicit scheme Notes. Fully implicit scheme Notes. Notes
Explicit cheme So far coidered a fully explicit cheme to umerically olve the diffuio equatio: T + = ( )T + (T+ + T ) () with = κ ( x) Oly table for < / Thi cheme i ometime referred to a FTCS (forward time
More informationChapter 2: Numerical Methods
Chapter : Numerical Methods. Some Numerical Methods for st Order ODEs I this sectio, a summar of essetial features of umerical methods related to solutios of ordiar differetial equatios is give. I geeral,
More informationy = f x x 1. If f x = e 2x tan -1 x, then f 1 = e 2 2 e 2 p C e 2 D e 2 p+1 4
. If f = e ta -, the f = e e p e e p e p+ 4 f = e ta -, so f = e ta - + e, so + f = e p + e = e p + e or f = e p + 4. The slope of the lie taget to the curve - + = at the poit, - is - 5 Differetiate -
More informationThe Binomial Multi-Section Transformer
4/15/2010 The Bioial Multisectio Matchig Trasforer preset.doc 1/24 The Bioial Multi-Sectio Trasforer Recall that a ulti-sectio atchig etwork ca be described usig the theory of sall reflectios as: where:
More informationSTA 4032 Final Exam Formula Sheet
Chapter 2. Probability STA 4032 Fial Eam Formula Sheet Some Baic Probability Formula: (1) P (A B) = P (A) + P (B) P (A B). (2) P (A ) = 1 P (A) ( A i the complemet of A). (3) If S i a fiite ample pace
More information3.185 Problem Set 6. Radiation, Intro to Fluid Flow. Solutions
3.85 Proble Set 6 Radiation, Intro to Fluid Flow Solution. Radiation in Zirconia Phyical Vapor Depoition (5 (a To calculate thi viewfactor, we ll let S be the liquid zicronia dic and S the inner urface
More informationMasonry Design. = calculated compressive stress in masonry f. = masonry design compressive stress f
ARCH 614 Note Set 7.1 S014bn Monry Deign Nottion: A = ne or re A n = net re, equl to the gro re ubtrcting ny reinorceent A nv = net her re o onry A = re o teel reinorceent in onry deign A t = re o teel
More informationGotta Keep It Correlatin
Gotta Keep It Correlati Correlatio.2 Learig Goals I this lesso, ou will: Determie the correlatio coefficiet usig a formula. Iterpret the correlatio coefficiet for a set of data. ew Stud Liks Dark Chocolate
More informationState space systems analysis
State pace ytem aalyi Repreetatio of a ytem i tate-pace (tate-pace model of a ytem To itroduce the tate pace formalim let u tart with a eample i which the ytem i dicuio i a imple electrical circuit with
More informationECE 422 Power System Operations & Planning 6 Small Signal Stability. Spring 2015 Instructor: Kai Sun
ECE 4 Power Sytem Operatio & Plaig 6 Small Sigal Stability Sprig 15 Itructor: Kai Su 1 Referece Saadat Chapter 11.4 EPRI Tutorial Chapter 8 Power Ocillatio Kudur Chapter 1 Power Ocillatio The power ytem
More informationElectric Torques. Damping and Synchronizing Torques. Mechanical Loop. Synchronous Machine Model
Electric Torques Dapig a ychroizig Torques ohae. El-harkawi Departet of Electrical Egieerig Uiversity of Washigto eattle, W 9895 http://arteergylab.co Eail: elsharkawi@ee.washigto.eu echaical torque fro
More information