Specify and determine the limiting conditions for sliding, toppling, Describe the mechanism and characteristics of dry friction,

Size: px
Start display at page:

Download "Specify and determine the limiting conditions for sliding, toppling, Describe the mechanism and characteristics of dry friction,"

Transcription

1 5. Friction 4 Static, 0/ Department of Mechanical Engineering, Chulalongorn Univerit Objective Student mut be able to Coure Objective Include friction into equilibrium anale Chapter Objective For friction in machine Prove, tate limitation and appl formula for impending motion in wedge, ingle continuou thread/crew, flat belt, di/clutche, pivot/collar/thrut bearing, journal bearing Analze machine with friction 3 Objective Student mut be able to Coure Objective Include friction into equilibrium anale Chapter Objective For general dr friction Decribe the mechanim and characteritic of dr friction, coefficient of friction and angle of friction Specif and determine the limiting condition for liding, toppling, free rolling and driven wheel under dr friction b appropriate FBD Specif the limiting condition for rear/front wheel drive b appropriate FBD Analze bodie/tructure with friction for unnown load/reaction b appropriate FBD Content Dr friction Characteritic, theor, coefficient and angle of friction Application Wedge Thread, crew Belt Di and Clutche Collar, pivot, journal and thrut bearing 4

2 Friction Force of reitance acting on a bod which prevent or retard lipping of the bod relative to a urface with which it i in contact. The frictional force act tangent to the contacting urface in a direction oppoed to the relative motion or tendenc for motion of one urface againt another Two tpe of friction Fluid friction eit when the contacting urface are eparated b a film of fluid. Dr friction occur between contacting urface without lubricating fluid. Equilibrium Slipping and/or tipping effect Frictional force F increae with force P. 5 7 Theor # Friction force are tangential force generated between contacting urface. Friction force arie in part from the interaction of the roughnee or aperitie of the contacting urface. Static Friction Equilibrium Impending Motion Maimum value of frictional force F on the object in equilibrium i called the limiting tatic frictional force. 6 8

3 Impending Motion Static Friction Coefficient F N F N maimum tatic frictional force coefficient of tatic friction normal force F i the maim um friction force that can be eerted b dr, contacting urface that are tation ar relat ive t o each ot he r. 9 Impending Motion Static Friction Tpical Value Contact Material Metal / ice Wood / wood Leather / wood Leather / metal Aluminum / Aluminum.0.70 How to obtain value of? Impending Motion Static Friction Angle of Static Friction N R co φ F R in φ N F Rin φ tan φ N Rco φ φ tan 0 Frictional Force More force i required to tart liding than to eep it liding can be eplained b the neceit to brea thee bond. 3

4 Kinetic Friction Coefficient & Angle Motion F N F N inetic frictional force coefficient of inetic friction normal force φ tan 3 Characteritic Frictional force act tangentiall to the contacting urface, oppoing the relative or tendenc for motion. F i independent of the area of contact, provided that the normal preure i not ver low nor great enough for deformation of the urface. In equilibrium: Impending lipping: φ φ Slipping: φ φ Ver low velocit: φ φ 5 Motion Kinetic Friction Angle of Friction At φ φ, lip i impending. At φ φ, urfa ce are lidin relative to eac h other. g φ φ 4 Motion Sliding Relative liding (tranlation motion) between two urface Toppling Fall over (rotation) about the edge Topple, tipping, rolling, tumble, trip 6 4

5 Eample Friction # Place a heet of one material on a flat board. Bond a heet of other material to bloc A. Place the bloc onto the board and lowl increae the tilt a of the board until the board, and lowl increae the tilt a of the board until the bloc lip. Show that the coefficient of tatic friction between the two material i related to the angle a b tanα Eample Friction # Will thi crate lide or topple over? 7 9 Eample Friction # α N W A F The bloc i about to lip F 0 N W coα 0 N W co α () F 0 F + W inα 0 N W in α () ()/() tan α An Eample Friction # The crate i about to lide. F F N 8 0 5

6 Eample Friction #3 The crate i about to topple. F < F ( N ) The crate i about to lide and topple. F F N Eample Hibbeler E 8- # F + 0 (80 N)co30 F 0 F 69.3 N F + 0 (80 N)in N + N 0 N 36. N C C M + O 0 (80 N)in30 (0.4 m) (80 N)co30 (0. m) + N ( ) m 9.08 mm 3 C << 0.4 m The crate will not topple. F < N (70.8 N) The crate, i cloe to but doen't not lip. C 3 Eample Hibbeler E 8- # The uniform crate ha a ma of 0 g. If a force P 80 N i applied to the crate, determine if it remain in equilibrium. The coefficient of tatic friction 0.3. Eample Hibbeler E 8-3 # The rod with weight W i about to lip on rough urface at A and B. Find coefficient of tatic friction. 4 6

7 Eample Hibbeler E 8-3 # Impending lip F N A A F N B B 3 equilibrium equation, 3 unnown ( N, N, ) A B F 0 + NA + NB co30 NB in30 0 () F 0 + NA W + NB co30 + NB in30 0 () MA 0 + NBl W co30 ( l / ) 0 (3) Eample Hibbeler E 8-4 # Find minimum coefficient of tatic friction that eep the tem in equilibrium. 5 7 Eample Hibbeler E 8-3 #3 From (3) N W From () & () B 0.8 An Eample Hibbeler E 8-4 # Smmetr of lower pipe about vertical ai paing through O. Two tpe of contact: Pipe pipe Pipe ground N N, F F, A B A B F N A, p-p A F N C, p-g C 6 8 7

8 Eample Bedford E 9.5 # Suppoe that α 0 and the coefficient of friction between the urface of the wedge and the log are 0. and 0.0. Neglect the weight of the wedge. If the wedge i driven into the log at a contant rate b vertical force F, what are the magnitude of the normal force eerted on the log b the wedge? Will the wedge remain in place in the log when the force i removed? 9 On the verge of lipping Eample Bedford E 9.5 #3 Smmetr about the center of the wedge F 0 + Nin( α / ) + Nco( α / ) 0 tan( α / ) A, wedge will remain in place. An < 3 Driven at contant rate Eample Bedford E 9.5 # Smmetr about the center of the wedge F 0 + Nin( α / ) + Nco( α / ) F 0 N N F in( α /) + ( α /) F in(0 / ) + (0.0)(0 / ) N.75 F An Eample Bedford 9.0 # The coefficient of tatic friction between the two boe and between the lower bo and the inclined urface i. What i the larget angle α for which the lower bo will not lip

9 Eample Bedford 9.0 # FBD of upper bloc F 0 N W coα 0 N W co α FBD of lower bloc F 0 N + W coα N 0 N W co α F 0 N + N W inα 0 3W coα W inα tan α / 3 or α tan (3 ) An Eample Bedford 9.30 # Impending rotation F + 0 Nw + Nf W 0 F + 0 Nw Nf 0 M 0 + O M ( Nw + N) r 0 W W Nw, Nf + + ( + ) M Wr + An Eample Bedford 9.30 # The clinder ha weight W. The coefficient of tatic friction between the clinder and the floor and between the clinder and the wall i. What i the larget couple M that can be applied to the tationar clinder without cauing it to rotate. Eample Bedford 9.33 # The di of weight W and radiu R i held in equilibrium on the circular urface b a couple M. The coefficient of tatic friction between the di and the urface i. Show that the larget value M can have without cauing the di to lip i RW M

10 Eample Bedford 9.33 # Impending lip F N F F W in α 0 F 0 + N W co α 0 MO 0 + M + FR 0 tan α, N W co α co + tan, tan α α α M NR WRco α M W R + Eample Bedford 9.66 # F 0 O + A 0 F 0 O + A 4g 0 M 0 O A ( m)co45 ) A ( m)in45 ) (4 g N)(0.5 m)co45 ) Eample Bedford 9.66 # Each of the uniform -m bar ha a ma of 4 g. The coefficient of tatic friction between the bar and the urface at B i 0.. If the tem i in equilibrium, i what i the magnitude of the friction force eerted on the bar at B. 38 Eample Bedford 9.66 #3 F 0 A + Fco30 Nin30 0 F 0 A (4 g N) + Fin30 + Nco30 0 M B 0 A ( m)co 45 ) + A ( m)in 45 ) + (4 g N)(0.5 m)co 45 ) 0 A 0, A g N, O 4 g N, O g N, N 438 N, F.63 N An 40 0

11 Eample Bedford 9.66 #4 Eample Bedford 9.63 # The crate i about to move. F cn F 0 (450 g N) + N 0 F 0 P F 0 P 0.3(450 g N) 35 g N 4 43 Eample Bedford 9.63 # The coefficient of tatic friction between the tire of the 000-g tractor and the ground and between the 450-g crate and the ground are 0.8 and 0.3, repectivel. Starting from the ret, what torque mut the tractor engine eert on the rear wheel to caue the crate to move? The front wheel can turn freel. Eample Bedford 9.63 #3 F 0 P + F 0 F 67.5 g N M O 0 (0.8 m) F T 0 T (0.8 m)(35 g N).06 N m An 4 44,

12 Eample Bedford 9.65 # The ma of the vehicle i 900 g, it ha rear-wheel drive, and the coefficient of tatic friction between it tire and the urface i The coefficient of tatic friction between the crate and the urface i 0.4. If the vehicle attempt to pull the crate up the incline, what i the larget value of the ma of the crate for which it will lip up the incline before the vehicle tire lip? Eample Bedford 9.65 #3 The crate i about to move. F cn F 0 W co0 + N 0 F 0 P F W in0 0 W.3930 P N 770. N m W / g 785 g An Eample Bedford 9.65 # Impending motion: F t, N F 0 Pco 0 + F 0 F 0 N + N (900 g N) P in0 0 M 0 O (900 g N)( m) + Pco0 (0.8 m) + Pin0 (3.7 m) N (.5 m) 0 P g N, N g N, F g N, N g N Eample Bedford 9.65 #4 What i the maimum tenion in the cord that the tractor ma tow a crate over a ramp with 45 angle of incline before the tractor topple ,

13 Eample Bedford 9.65 #5 Impending topple: N 0 M Q 0 P(.0 m) / (900 g N)(.5 m) 0 F 0 N (900 g N) P/ 0 F t, N, tire do not lip. F 0 P 955 g N An P/ + F 0 P g N, N 575 g N, F 675 g N Wedge Wedge eert a large lateral force from the face a a reult of mall angle Friction in Machine Friction help ome machine function. Machine with friction Wedge Thread, crew Belt Di and clutche Bearing Wedge Anali # The bloc i about to raie. The lip of the load and wedge are impending. F N F N, 3 3 F 0 + N 3 + N in θ + N co θ 0 F 0 + N co θ N in θ N W

14 Wedge Anali # FBD of the wedge F 0 + Nin θ Nco θ N + P 0 F 0 + N N co θ + N in θ 0 ( ) ( ) tanθ + P W tanθ Thread Geometr θ l tan π r θ r lead angle pitch of the thread (lead) mean radiu of the thread Thread/Screw Aumption: the haft ha a ingle continuou thread. Thread Motion W W l

15 Thread Moving Upward F 0 + S Rin( θ + φ) 0 F 0 + Rco( θ + φ) W 0 S W tan( θ + φ) and M Sr M Wr tan( θ + φ ) On the verge of rotating: φ φ tan Uniform upward motion: φ φ tan Thread Moving Downward # M i removed: W i upported b friction alone, providing that φ θ Self-locing condition Thread Moving Downward # F 0 + S Rin( θ φ) 0 F 0 + Rco( θ φ) W 0 S W tan( θ φ) and M Sr M Wr tan( θ φ) On the verge of rotating: φ φ tan Uniform downward motion: φ φ tan Thread Moving Downward #3 F 0 + S + Rin( φ θ) 0 F 0 + Rco( φ θ) W 0 S W tan( φ θ) and M S r Ver rough urface θ < φ : Revered motion. φ θ tan( ) M Wr

16 Eample Wedge/Thread # The ma of bloc A i 60 g. Neglect the weight of the 5 wedge. The coefficient of inetic friction between the contacting urface of the bloc A A, the wedge, the table, and the wall i 0.4. The pitch of the threaded haft i 5 mm, the mean radiu i 5 mm, the coefficient of inetic friction between the thread and the mating groove i 0.. What couple mut be eerted on the threaded haft to raie the bloc A at a contant rate? Eample Wedge/Thread #3 l 5 mm r 5 mm 0. for thread/groove φ arctan( ).30 θ arctan(/ πr ) Draw FBD of the thread Find M that will puh the thread upward: M Fr tan( θ + φ ) M ( N)(0.05 m)tan( ) M.5609 N m.56 N m An 6 63 Eample Wedge/Thread # Draw FBD of the ma A and the wedge Then, follow the ame procedure for wedge anali: ( ) ( ) tanα + F W tanα Subtitute for all nown value: F N WL 60 g N W w 0N α for all non-thread contact 6 Flat Belt Involve lippage of fleible cable, belt and rope over heave and drum. 64 6

17 Flat Belt Anali # Conider line element F 0 dn + T co dθ ( T + dt )co dθ 0 dn dt d co θ F n 0 dn T in dθ ( T + dt )in dθ 0 dn T in dθ + dt in dθ Eample Flat Belt # Friction reit the lowering of m : T mg T P mg/6 β.5( π) A force P mg/6 i required to lower the clinder at a contant β T Te mg mg e low peed with the cord maing.5 turn around the fied haft. Calculate the coefficient of friction between the cord and the haft..5 π An Flat Belt Anali # (motion impending) (ongoing movement) d d θ θ d θ 0, co : d θ dn dt co dt dθ dθ 0, in : d θ dn T in Td θ T Te β T θ θ β dt T dt β d d ln T T T 0 T Eample Flat Belt # Calculate the force P on the handle of the differential band brae that will prevent the flwheel from turning on it haft to which the torque M 50 N m i applied. The coefficient of friction between the band and the flwheel i t

18 Eample Flat Belt # Friction reit the attempt of M to rotate the flwheel in the clocwie direction: T Te T Te β (7 π /6) M center 0 (50 N m) + (0.5 m)( T T) 0 T T 000 N () Solve () and () T 300 N, T 300 N () 69 Di & Clutche Ue to connect and diconnect two coaial rotating haft The haft can upport a couple due to friction force between the di. Determine the couple b uing coefficient of tatic friction in the flat-ended thrut equation. Draw force on the plane onl 7 Eample Flat Belt #3 M O 0 + (0.5 m) T + (0.075 m)( T in30 ) + (0.45 m) P 0 P 408 N An Di & Clutche Anali # da π r dr F 0 0 P w da R P p πr dr pπr o M 0 0 M wr da R M pr π r dr pπ R o 3 3 M 3 PR

19 Di & Clutche Worn Anali # Ditribution of force on worn plate are not uniformed. For eample, linear ditribution da π r dr At r R, w 0 At r 0, w p w p( R r)/ R Bearing Pivot Bearing M 3 PR (motion impending) (ongoing movement) Di & Clutche Worn Anali # Conider the left plate F 0 P w da 0 R π p P p( R r) π r dr / R R o 3 M 0 M wr da 0 R M pr ( R r) πr dr / R o M PR Bearing Collar Bearing R R 3 R R M 3 3 i o i o (motion impending) (ongoing movement)

20 Bearing Thrut Bearing # R i R o dr da πr d πr co θ R o R i P R π ( o R Ro Ri ) A da dr π R co θ co θ dr R θ 77 Bearing Journal Bearing # P P φ 79 Bearing Thrut Bearing # F 0 P paco θ 0 P P p A co θ π R R ( o i ) dr R o R i R θ P M 0 M R ( pda ) 0 R o P π R M R dr R π co θ ( Ro Ri ) M 3 3 P R o Ri 3co θ Ro Ri Bearing Journal Bearing # R R R f M z 0 + M P( Rin φ ) 0 M P R M PR in tan φ φ φ in M PR PR i i

21 Eample Hibbeler 8- # The 00-mm-diameter pulle fit looel on a 0-mmdiameter haft for which the coefficient of tatic friction i 0.4. Determine the minimum tenion T in the belt needed to (a) raie the 00-g bloc and (b) lower the bloc. Aume that no lipping occur between een the belt and pulle and neglect the weight of the pulle. Hibbeler Eample 8- #3 CCW rotation Lower the bloc r r in φ (5 mm)in(tan 0.4).8570 mm f M 0 + P (98 N)(50 mm.86 mm) T (50 mm +.86 mm) 0 T T N 9 N An 8 83 Eample Hibbeler 8- # Raie the bloc rf r in φ (5 mm)in(tan 0.4).8570 mm M P 0 + (98 N)(50 mm mm T (50 mm.86 mm) 0 T N T.06 N An Eample Borei 0.9 # CW rotation 8 84

22 Eample Borei 0.9 # A weight W i lifted at a contant rate b appling a couple Rd to the compound djaccrew. Derive a formula for R in term of the angle θ, the weight W, the length d of the lever rod, the pitch p of the crew thread, the mean radiu r of the crew thread, and the coefficient i of inetic friction of the crew. The friction of the vertical wall guide i negligible. For θ 5, W 000 lb, d 0 in, r 0.75 in, p in, and 0.5, calculate R. Eample Borei 0.9 #4 F 0 Qco θ Tco θ 0 Q T F 0 T inθ P 0 P T in θ () () + () P W tan θ B mmetr, FBD of the left nut i mirror image of the right nut FBD Eample Borei 0.9 #3 F 0 T coθ W 0 W T co θ () Eample Borei 0.9 #5 [ M Wr tan( φ + α ) ] Rd Pr tan( φ + α) p R ( W tan θ ) r tan(tan + tan ) / d π r Subtitute number in the equation R 4.48 lb An 86 88

23 Eample Hibbeler 8-0 (modif) # The ale of the pulle fit looel in a 50-mm-diameter pinhole. If 0.30 between the pinhole and the pulle ale and 0.0 between the pulle and the cord, determine the minimum tenion T required to turn the pulle counterclocwie at a contant velocit if the bloc weigh 60 N. Neglect the weight of the pulle. 89 Cae I Journal Bearing Eample Hibbeler 8-0 (modif) #3 If the cord doe not lip over the pulle, the minimum i: f β T Te f, 60 N (54.9 N) e f, f, ( π /) b, < 0., the aumption the the cord doe not lip i valid. T 54. N An 9 Cae I Journal Bearing Eample Hibbeler 8-0 (modif) # The haft i about to rotate. φ tan b tan r r in φ mm θ β - tan ( r/ r) 45 in ( r / r ).97 F Rin( θ + β ) 0 F 0 T Rco( θ + β) 0 R N, T 54.9 N Cae II Fleible Belt Eample Hibbeler 8-0 (modif) #4 The belt i about to lide. f β T Te 60 N Te 0.( π / ) T N , f, f,

24 Cae II Fleible Belt Eample Hibbeler 8-0 (modif) #5 If the haft doe not rotate, F 0 (60 N) + R in( θ + β ) 0 F 0 T Rco( θ + β) 0 T N, θ 45, β β in ( r / r ) r.77 mm f f r r in φ φ φ tan.77 b, b, b, > 0.3, the aumpt ion that the haft doe not rotate i invalid. 93 Eample Borei 0-86 # Given T N The belt i about to lip: β T Te 0.3 π T ( N) e 5.37 N T 5.3 N An M 0 O T + ( T T) r 0 T ( T T)(0. m) N m A tenion in the belt remain unchanged between the two pu lle, TB T 33 N m An 95 Eample Borei 0-86 # A torque T i applied to pulle A, which drive pulle B. The two pulle have equal radii. The tenion in the lac ide of the belt i N. The coefficient of friction between the belt and the pulle i What i the maimum poible torque that can be applied to pulle A? What torque i tranmitted to pulle B? Eample Borei 0-98 # In ome application of collar bearing, multiple collar are ued. Two collar are ued a hown to upport the 0,000 lb load ( 0.40 and 0.0) Determine the torque T required to initiate rotation of haft S, Aume that the load i divided equall between the collar and that the preure on each collar i uniform. Wh are multiple collar ued? f

25 Eample Borei 0-98 # The load i divided equall between the collar, thu, the load on each collar i 5 ip. For each collar that i about to rotate: 3 3 R R T P 3 R R 3 3 ( ft) (0.5 ft) T 0.4(5000 lb) lb ft ( ft) (0.5 ft) Total required torque T M 3. ip ft An Le load on each collar, le wear and tear. An 97 Concept # Review Friction i the tangent reitance force which prevent or retard lipping of the bod relative to a urface with which it i in contact. Maimum friction occur that the verge of impending motion which can be lipping or toppling or both together. Some machine function b friction. To ue the formula, the phical meaning underling the friction in machine mut be undertood. 98 5

PROBLEM 8.6 SOLUTION. FBD block (Impending motion up) = N. = tan (0.25) (a) (Note: For minimum P, P^ Then. = ( N)sin β = 14.

PROBLEM 8.6 SOLUTION. FBD block (Impending motion up) = N. = tan (0.25) (a) (Note: For minimum P, P^ Then. = ( N)sin β = 14. PROBLEM 8.6 Knowing that the coefficient of friction between the 25-kg block and the incline i μ =.25, determine (a) the mallet value of P required to tart the block moving up the incline, (b) the correponding

More information

ME 141. Lecture 7: Friction

ME 141. Lecture 7: Friction ME 141 Engineering Mechanic Lecture 7: riction Ahmad Shahedi Shail Lecturer, Dept. of Mechanical Engg, BUET E-mail: hail@me.buet.ac.bd, hail6791@gmail.com Webite: teacher.buet.ac.bd/hail Courtey: Vector

More information

Prof. Dr. Ibraheem Nasser Examples_6 October 13, Review (Chapter 6)

Prof. Dr. Ibraheem Nasser Examples_6 October 13, Review (Chapter 6) Prof. Dr. Ibraheem Naer Example_6 October 13, 017 Review (Chapter 6) cceleration of a loc againt Friction (1) cceleration of a bloc on horizontal urface When body i moving under application of force P,

More information

STATICS. Friction VECTOR MECHANICS FOR ENGINEERS: Eighth Edition CHAPTER. Ferdinand P. Beer E. Russell Johnston, Jr.

STATICS. Friction VECTOR MECHANICS FOR ENGINEERS: Eighth Edition CHAPTER. Ferdinand P. Beer E. Russell Johnston, Jr. Eighth E 8 Friction CHAPTER VECTOR MECHANICS FOR ENGINEERS: STATICS Ferdinand P. Beer E. Russell Johnston, Jr. Lecture Notes: J. Walt Oler Texas Tech University Contents Introduction Laws of Dry Friction.

More information

ME 141. Engineering Mechanics

ME 141. Engineering Mechanics ME 141 Engineering Mechanic Lecture 14: Plane motion of rigid bodie: Force and acceleration Ahmad Shahedi Shakil Lecturer, Dept. of Mechanical Engg, BUET E-mail: hakil@me.buet.ac.bd, hakil6791@gmail.com

More information

Overview. Dry Friction Wedges Flatbelts Screws Bearings Rolling Resistance

Overview. Dry Friction Wedges Flatbelts Screws Bearings Rolling Resistance Friction Chapter 8 Overview Dry Friction Wedges Flatbelts Screws Bearings Rolling Resistance Dry Friction Friction is defined as a force of resistance acting on a body which prevents slipping of the body

More information

Engineering Mechanics: Statics

Engineering Mechanics: Statics Engineering Mechanics: Statics Chapter 6B: Applications of Friction in Machines Wedges Used to produce small position adjustments of a body or to apply large forces When sliding is impending, the resultant

More information

CHAPTER VII FRICTION

CHAPTER VII FRICTION CHAPTER VII FRICTION 1- The block brake conit of a pin-connected lever and friction block at B. The coefficient of tatic friction between the wheel and the lever i and a torque of i applied to the wheel.

More information

Engineering Mechanics: Statics

Engineering Mechanics: Statics Engineering Mechanics: Statics Chapter 6B: Applications of Friction in Machines Wedges Used to produce small position adjustments of a body or to apply large forces When sliding is impending, the resultant

More information

3. In an interaction between two objects, each object exerts a force on the other. These forces are equal in magnitude and opposite in direction.

3. In an interaction between two objects, each object exerts a force on the other. These forces are equal in magnitude and opposite in direction. Lecture quiz toda. Small change to webite. Problem 4.30 the peed o the elevator i poitive even though it i decending. The WebAign anwer i wrong. ewton Law o Motion (page 9-99) 1. An object velocit vector

More information

Engineering Mechanics. Friction in Action

Engineering Mechanics. Friction in Action Engineering Mechanics Friction in Action What is friction? Friction is a retarding force that opposes motion. Friction types: Static friction Kinetic friction Fluid friction Sources of dry friction Dry

More information

DYNAMICS OF ROTATIONAL MOTION

DYNAMICS OF ROTATIONAL MOTION DYNAMICS OF ROTATIONAL MOTION 10 10.9. IDENTIFY: Apply I. rad/rev SET UP: 0 0. (400 rev/min) 419 rad/ 60 /min EXECUTE: 0 419 rad/ I I (0 kg m ) 11 N m. t 800 EVALUATE: In I, mut be in rad/. 10.. IDENTIFY:

More information

CHARACTERISTICS OF DRY FRICTION & PROBLEMS INVOLVING DRY FRICTION

CHARACTERISTICS OF DRY FRICTION & PROBLEMS INVOLVING DRY FRICTION CHARACTERISTICS OF DRY FRICTION & PROBLEMS INVOLVING DRY FRICTION Today s Objective: Students will be able to: a) Understand the characteristics of dry friction. b) Draw a FBD including friction. c) Solve

More information

Frictional Forces. Friction has its basis in surfaces that are not completely smooth: 1/29

Frictional Forces. Friction has its basis in surfaces that are not completely smooth: 1/29 Frictional Force Friction ha it bai in urface that are not completely mooth: 1/29 Microcopic Friction Surface Roughne Adheion Magnified ection of a polihed teel urface howing urface irregularitie about

More information

SOLUTION 8 1. a+ M B = 0; N A = 0. N A = kn = 16.5 kn. Ans. + c F y = 0; N B = 0

SOLUTION 8 1. a+ M B = 0; N A = 0. N A = kn = 16.5 kn. Ans. + c F y = 0; N B = 0 8 1. The mine car and its contents have a total mass of 6 Mg and a center of gravity at G. If the coefficient of static friction between the wheels and the tracks is m s = 0.4 when the wheels are locked,

More information

Lecture 6 Friction. Friction Phenomena Types of Friction

Lecture 6 Friction. Friction Phenomena Types of Friction Lecture 6 Friction Tangential forces generated between contacting surfaces are called friction forces and occur to some degree in the interaction between all real surfaces. whenever a tendency exists for

More information

Engineering Mechanics

Engineering Mechanics Engineering Mechanics Continued (5) Mohammed Ameen, Ph.D Professor of Civil Engineering B Section Forces in Beams Beams are thin prismatic members that are loaded transversely. Shear Force, Aial Force

More information

Application of Newton s Laws. F fr

Application of Newton s Laws. F fr Application of ewton Law. A hocey puc on a frozen pond i given an initial peed of 0.0/. It lide 5 before coing to ret. Deterine the coefficient of inetic friction ( μ between the puc and ice. The total

More information

PHYSICS 151 Notes for Online Lecture 2.3

PHYSICS 151 Notes for Online Lecture 2.3 PHYSICS 151 Note for Online Lecture.3 riction: The baic fact of acrocopic (everda) friction are: 1) rictional force depend on the two aterial that are liding pat each other. bo liding over a waed floor

More information

SOLUTION 8 7. To hold lever: a+ M O = 0; F B (0.15) - 5 = 0; F B = N. Require = N N B = N 0.3. Lever,

SOLUTION 8 7. To hold lever: a+ M O = 0; F B (0.15) - 5 = 0; F B = N. Require = N N B = N 0.3. Lever, 8 3. If the coefficient of static friction at is m s = 0.4 and the collar at is smooth so it only exerts a horizontal force on the pipe, determine the minimum distance x so that the bracket can support

More information

Newton s Laws & Inclined Planes

Newton s Laws & Inclined Planes GP: ewton Law & Inclined Plane Phyic Mcutt Date: Period: ewton Law & Inclined Plane The ormal orce, Static and Kinetic rictional orce The normal orce i the perpendicular orce that a urace exert on an object.

More information

Example 1: Example 1: Example 2: a.) the elevator is at rest. Example 2: Example 2: c.) the elevator accelerates downward at 1.

Example 1: Example 1: Example 2: a.) the elevator is at rest. Example 2: Example 2: c.) the elevator accelerates downward at 1. Exaple 1: 60 kg, v 1 100 N (wet), v 2 220 N (eat), a? Exaple 1: wo force parallel to the ground act upon a box with a a of 60 kg. One force i directed wet and ha a trength of 100 N. he other force i directed

More information

Halliday/Resnick/Walker 7e Chapter 6

Halliday/Resnick/Walker 7e Chapter 6 HRW 7e Chapter 6 Page of Halliday/Renick/Walker 7e Chapter 6 3. We do not conider the poibility that the bureau might tip, and treat thi a a purely horizontal motion problem (with the peron puh F in the

More information

Problems (Equilibrium of Particles)

Problems (Equilibrium of Particles) 1. he 4kg block rests on the rough surface. Length of the spring is 18 mm in the position shown. Unstretched length of the spring is 2 mm. Determine the coefficient of friction required for the equilibrium.

More information

PHYSICS LAB Experiment 5 Fall 2004 FRICTION

PHYSICS LAB Experiment 5 Fall 2004 FRICTION FRICTION In thi experiment we will meaure the effect of friction on the motion of a body in contact with a particular urface. When a body lide or roll over another, it motion i oppoed by the force of friction

More information

a = f s,max /m = s g. 4. We first analyze the forces on the pig of mass m. The incline angle is.

a = f s,max /m = s g. 4. We first analyze the forces on the pig of mass m. The incline angle is. Chapter 6 1. The greatet deceleration (of magnitude a) i provided by the maximum friction force (Eq. 6-1, with = mg in thi cae). Uing ewton econd law, we find a = f,max /m = g. Eq. -16 then give the hortet

More information

7.6 Journal Bearings

7.6 Journal Bearings 7.6 Journal Bearings 7.6 Journal Bearings Procedures and Strategies, page 1 of 2 Procedures and Strategies for Solving Problems Involving Frictional Forces on Journal Bearings For problems involving a

More information

PROBLEMS ON EQUILIBRIUM OF PARTICLES

PROBLEMS ON EQUILIBRIUM OF PARTICLES O EQUILIBRIUM O PRICLES 1. ind the angle of tilt q with the horiontal so that the contact force at B will be one-half that at for the smooth clinder. (3/15) q?, contact force at B will be one-half that

More information

Chapter 10: Friction A gem cannot be polished without friction, nor an individual perfected without

Chapter 10: Friction A gem cannot be polished without friction, nor an individual perfected without Chapter 10: Friction 10-1 Chapter 10 Friction A gem cannot be polished without friction, nor an individual perfected without trials. Lucius Annaeus Seneca (4 BC - 65 AD) 10.1 Overview When two bodies are

More information

M D P L sin x FN L sin C W L sin C fl cos D 0.

M D P L sin x FN L sin C W L sin C fl cos D 0. 789 roblem 9.26 he masses of the ladder and person are 18 kg and 90 kg, respectively. he center of mass of the 4-m ladder is at its midpoint. If D 30, what is the minimum coefficient of static friction

More information

b) Fluid friction: occurs when adjacent layers in a fluid are moving at different velocities.

b) Fluid friction: occurs when adjacent layers in a fluid are moving at different velocities. Ch.6 Friction Types of friction a) Dry friction: occurs when non smooth (non ideal) surfaces of two solids are in contact under a condition of sliding or a tendency to slide. (also called Coulomb friction)

More information

However, the friction forces are limited in magnitude and will not prevent motion if sufficiently large forces are applied.

However, the friction forces are limited in magnitude and will not prevent motion if sufficiently large forces are applied. FRICTION 1 Introduction In preceding chapters, it was assumed that surfaces in contact were either frictionless (surfaces could move freely with respect to each other) or rough (tangential forces prevent

More information

Chapter 5 Equilibrium of a Rigid Body Objectives

Chapter 5 Equilibrium of a Rigid Body Objectives Chapter 5 Equilibrium of a Rigid Bod Objectives Develop the equations of equilibrium for a rigid bod Concept of the free-bod diagram for a rigid bod Solve rigid-bod equilibrium problems using the equations

More information

Unit 21 Couples and Resultants with Couples

Unit 21 Couples and Resultants with Couples Unit 21 Couples and Resultants with Couples Page 21-1 Couples A couple is defined as (21-5) Moment of Couple The coplanar forces F 1 and F 2 make up a couple and the coordinate axes are chosen so that

More information

Course Material Engineering Mechanics. Topic: Friction

Course Material Engineering Mechanics. Topic: Friction Course Material Engineering Mechanics Topic: Friction by Dr.M.Madhavi, Professor, Department of Mechanical Engineering, M.V.S.R.Engineering College, Hyderabad. Contents PART I : Introduction to Friction

More information

Dry Friction Static vs. Kinetic Angles

Dry Friction Static vs. Kinetic Angles Outline: Types of Friction Dry Friction Static vs. Kinetic Angles Applications of Friction 1 Contacting surfaces typically support normal and tangential forces Friction is a tangential force Friction occurs

More information

SPH3UW/SPH4UI Unit 2.4 Friction Force Page 1 of 8. Notes. : The kind of friction that acts when a body slides over a surface. Static Friction Force, f

SPH3UW/SPH4UI Unit 2.4 Friction Force Page 1 of 8. Notes. : The kind of friction that acts when a body slides over a surface. Static Friction Force, f SPH3UW/SPH4UI Unit 2.4 Friction Force Page o 8 ote Phyic Tool Box Kinetic Friction Force, : The ind o riction that act when a body lide over a urace. Static Friction Force, : Friction orce when there i

More information

EQUILIBRIUM OF PARTICLES (PROBLEMS)

EQUILIBRIUM OF PARTICLES (PROBLEMS) EQUILIRIUM OF PARICLES (PROLEMS) 1. Determine the force P required to maintain the 2-kg engine in the position for which q=3 o. he diameter of the pulle at is negligible. 2. 4-kg sphere rests on the smooth

More information

FRICTION. k 9) For a body moving up a rough inclined plane under the action of a force F,

FRICTION. k 9) For a body moving up a rough inclined plane under the action of a force F, FRICTION POINTS TO REMEMBER ) The force that alway oppoe the relative motion between two urface in contact and parallel to the urface, oppoite to the direction of motion i called frictional force. ) The

More information

Phys 201A. Homework 8 Solutions

Phys 201A. Homework 8 Solutions Phys 01A Homewor 8 Solutions 15. (b) The static frictional force that blocs A and B eert on each other has a magnitude f. The force that B eerts on A is directed to the right (the positive direction),

More information

0.5 rad r C 20 mm. 30 deg r s 50 mm. r A. 200 mm. Solution: v C 0.01 m s. v C. r s. 0.2 rad. v A v E s r A

0.5 rad r C 20 mm. 30 deg r s 50 mm. r A. 200 mm. Solution: v C 0.01 m s. v C. r s. 0.2 rad. v A v E s r A 16 29. The mechanim for a car window winder i hown in the figure. Here the handle turn the mall cog C, which rotate the pur gear S, thereby rotating the fixed-connected lever which raie track D in which

More information

Conservation of Energy

Conservation of Energy Conervative Force Conervation of Energ force i conervative if the work done b the force from r to r, but depend on initial and final poition onl Conervative Non-conervative Section #4.5 #4.6 Conervation

More information

Outline: Types of Friction Dry Friction Static vs. Kinetic Angles Applications of Friction. ENGR 1205 Appendix B

Outline: Types of Friction Dry Friction Static vs. Kinetic Angles Applications of Friction. ENGR 1205 Appendix B Outline: Types of Friction Dry Friction Static vs. Kinetic Angles Applications of Friction ENGR 1205 Appendix B 1 Contacting surfaces typically support normal and tangential forces Friction is a tangential

More information

SKAA 1213 Engineering Mechanics

SKAA 1213 Engineering Mechanics SKAA 1213 Engineering Mechanics TOPIC 6 FRICTION Lecturers: Rosli Anang Dr. Mohd Yunus Ishak Dr. Tan Cher Siang Lesson 7 Outline Introduction Equilibrium on a horizontal plane Equilibrium i on an inclined

More information

Physics 6A. Practice Midterm #2 solutions. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB

Physics 6A. Practice Midterm #2 solutions. Prepared by Vince Zaccone For Campus Learning Assistance Services at UCSB Phyic 6A Practice Midter # olution or apu Learning Aitance Service at USB . A locootive engine of a M i attached to 5 train car, each of a M. The engine produce a contant force that ove the train forward

More information

PHYSICS 211 MIDTERM II 12 May 2004

PHYSICS 211 MIDTERM II 12 May 2004 PHYSIS IDTER II ay 004 Exa i cloed boo, cloed note. Ue only your forula heet. Write all wor and anwer in exa boolet. The bac of page will not be graded unle you o requet on the front of the page. Show

More information

CHAPTER 4 FORCES AND NEWTON'S LAWS OF MOTION

CHAPTER 4 FORCES AND NEWTON'S LAWS OF MOTION CHAPTER 4 ORCES AND NEWTON'S LAWS O MOTION CONCEPTUAL QUESTIONS 1. REASONING AND SOLUTION When the car come to a udden halt, the upper part of the bod continue forward (a predicted b Newton' firt law)

More information

two equations that govern the motion of the fluid through some medium, like a pipe. These two equations are the

two equations that govern the motion of the fluid through some medium, like a pipe. These two equations are the Fluid and Fluid Mechanic Fluid in motion Dynamic Equation of Continuity After having worked on fluid at ret we turn to a moving fluid To decribe a moving fluid we develop two equation that govern the motion

More information

CEE 271: Applied Mechanics II, Dynamics Lecture 25: Ch.17, Sec.4-5

CEE 271: Applied Mechanics II, Dynamics Lecture 25: Ch.17, Sec.4-5 1 / 36 CEE 271: Applied Mechanics II, Dynamics Lecture 25: Ch.17, Sec.4-5 Prof. Albert S. Kim Civil and Environmental Engineering, University of Hawaii at Manoa Date: 2 / 36 EQUATIONS OF MOTION: ROTATION

More information

What Are Newton's Laws of Motion?

What Are Newton's Laws of Motion? Phyic Review What Are Newton' Law of Motion? Intel Corporation or it ubidiarie in the U.S. and other countrie. orce Puh or Pull that act between two bodie Tenion Gravitational force rictional force Air

More information

STATICS. FE Review. Statics, Fourteenth Edition R.C. Hibbeler. Copyright 2016 by Pearson Education, Inc. All rights reserved.

STATICS. FE Review. Statics, Fourteenth Edition R.C. Hibbeler. Copyright 2016 by Pearson Education, Inc. All rights reserved. STATICS FE Review 1. Resultants of force systems VECTOR OPERATIONS (Section 2.2) Scalar Multiplication and Division VECTOR ADDITION USING EITHER THE PARALLELOGRAM LAW OR TRIANGLE Parallelogram Law: Triangle

More information

Eng Sample Test 4

Eng Sample Test 4 1. An adjustable tow bar connecting the tractor unit H with the landing gear J of a large aircraft is shown in the figure. Adjusting the height of the hook F at the end of the tow bar is accomplished by

More information

Physics 20 Lesson 17 Elevators and Inclines

Physics 20 Lesson 17 Elevators and Inclines Phic 0 Leon 17 Elevator and Incline I. Vertical force Tenion Suppoe we attach a rope to a teel ball and hold the ball up b the rope. There are two force actin on the ball: the force due to ravit and the

More information

Determine the gravitational attraction between two spheres which are just touching each other. Each sphere has a mass M and radius r.

Determine the gravitational attraction between two spheres which are just touching each other. Each sphere has a mass M and radius r. Problem 13-1 Determine the gravitational attraction between two phere which are jut touching each other. Each phere ha a ma M and radiu r. r 00 mm M 10 kg G 66.73 10 1 m 3 kg nn 1 10 9 N F GM ( r) F 41.7

More information

See exam 1 and exam 2 study guides for previous materials covered in exam 1 and 2. Stress transformation. Positive τ xy : τ xy

See exam 1 and exam 2 study guides for previous materials covered in exam 1 and 2. Stress transformation. Positive τ xy : τ xy ME33: Mechanic of Material Final Eam Stud Guide 1 See eam 1 and eam tud guide for previou material covered in eam 1 and. Stre tranformation In ummar, the tre tranformation equation are: + ' + co θ + in

More information

PROBLEM 16.4 SOLUTION

PROBLEM 16.4 SOLUTION PROBLEM 16.4 The motion of the.5-kg rod AB is guided b two small wheels which roll freel in horizontal slots. If a force P of magnitude 8 N is applied at B, determine (a) the acceleration of the rod, (b)

More information

t α z t sin60 0, where you should be able to deduce that the angle between! r and! F 1

t α z t sin60 0, where you should be able to deduce that the angle between! r and! F 1 PART III Problem Problem1 A computer dik tart rotating from ret at contant angular acceleration. If it take 0.750 to complete it econd revolution: a) How long doe it take to complete the firt complete

More information

15 N 5 N. Chapter 4 Forces and Newton s Laws of Motion. The net force on an object is the vector sum of all forces acting on that object.

15 N 5 N. Chapter 4 Forces and Newton s Laws of Motion. The net force on an object is the vector sum of all forces acting on that object. Chapter 4 orce and ewton Law of Motion Goal for Chapter 4 to undertand what i force to tudy and apply ewton irt Law to tudy and apply the concept of a and acceleration a coponent of ewton Second Law to

More information

Physics 6A. Practice Midterm #2 solutions

Physics 6A. Practice Midterm #2 solutions Phyic 6A Practice Midter # olution 1. A locootive engine of a M i attached to 5 train car, each of a M. The engine produce a contant force that ove the train forward at acceleration a. If 3 of the car

More information

MAE 101A. Homework 3 Solutions 2/5/2018

MAE 101A. Homework 3 Solutions 2/5/2018 MAE 101A Homework 3 Solution /5/018 Munon 3.6: What preure gradient along the treamline, /d, i required to accelerate water upward in a vertical pipe at a rate of 30 ft/? What i the anwer if the flow i

More information

APPLYING NEWTON S LAWS

APPLYING NEWTON S LAWS APPLYING NEWTON S LAWS 5 igible mass. Let T r be the tension in the rope and let T c be the tension in the chain. EXECUTE: (a) The free-bod diagram for each weight is the same and is given in Figure 5.1a.

More information

PROBLEMS. (a) s cable length. mg = 10(9.81) =98.1 N. F spring

PROBLEMS. (a) s cable length. mg = 10(9.81) =98.1 N. F spring . he ytem i releaed from ret with no lack in the cable and with the prin tretched mm. Determine the ditance traveled by the -k cart before it come to ret (a) if m approache zero and (b) if m = k. ume no

More information

PROBLEMS ON WORK AND ENERGY PRINCIPLE

PROBLEMS ON WORK AND ENERGY PRINCIPLE PROLEMS ON WORK ND ENERGY PRINCIPLE PROLEMS. he.8 kg collar lide with negligible friction on the fixed rod in the vertical plane. If the collar tart from ret at under the action of the contant 8-N horizontal

More information

PROBLEM = Knowing that P = 50 N, determine (a) the acceleration of block B, (b) the tension in the cord.

PROBLEM = Knowing that P = 50 N, determine (a) the acceleration of block B, (b) the tension in the cord. PROLEM 1.16 lock ha a ma of 40 k, and block ha a ma of 8 k. The coefficient of friction between all urface of contact are 0.0 m k = 0.15. Knowin that P = 50 N, determine (a) the acceleration of block,

More information

Problems (Equilibrium of Particles)

Problems (Equilibrium of Particles) 1. he -kg block rests on the rough surface. Length of the spring is 18 mm in the position shown. Unstretched length of the spring is mm. Determine the coefficient of friction required for the equilibrium.

More information

Bernoulli s equation may be developed as a special form of the momentum or energy equation.

Bernoulli s equation may be developed as a special form of the momentum or energy equation. BERNOULLI S EQUATION Bernoulli equation may be developed a a pecial form of the momentum or energy equation. Here, we will develop it a pecial cae of momentum equation. Conider a teady incompreible flow

More information

STATICS. Equivalent Systems of Forces. Vector Mechanics for Engineers: Statics VECTOR MECHANICS FOR ENGINEERS: Contents & Objectives.

STATICS. Equivalent Systems of Forces. Vector Mechanics for Engineers: Statics VECTOR MECHANICS FOR ENGINEERS: Contents & Objectives. 3 Rigid CHATER VECTOR ECHANICS FOR ENGINEERS: STATICS Ferdinand. Beer E. Russell Johnston, Jr. Lecture Notes: J. Walt Oler Teas Tech Universit Bodies: Equivalent Sstems of Forces Contents & Objectives

More information

PROBLEMS. m s TAC. m = 60 kg/m, determine the tension in the two supporting cables and the reaction at D.

PROBLEMS. m s TAC. m = 60 kg/m, determine the tension in the two supporting cables and the reaction at D. 1. he uniform I-beam has a mass of 60 kg per meter of its length. Determine the tension in the two supporting cables and the reaction at D. (3/62) A( 500) m (5 23) m m = 60 kg/m determine the tension in

More information

EF 151 Final Exam, Spring, 2009 Page 2 of 10. EF 151 Final Exam, Spring, 2009 Page 1 of 10. Name: Section: sina ( ) ( )( ) 2. a b c = = cosc.

EF 151 Final Exam, Spring, 2009 Page 2 of 10. EF 151 Final Exam, Spring, 2009 Page 1 of 10. Name: Section: sina ( ) ( )( ) 2. a b c = = cosc. EF 5 Final Exam, Spring, 9 Page of EF 5 Final Exam, Spring, 9 Page of Name: Section: Guideline: Aume 3 ignificant figure for all given number unle otherwie tated Show all of your work no work, no credit

More information

Physics Sp Exam #4 Name:

Physics Sp Exam #4 Name: Phyic 160-0 Sp. 017 Ea #4 Nae: 1) A coputer hard dik tart ro ret. It peed up with contant angular acceleration until it ha an angular peed o 700 rp. I it coplete 150 revolution while peeding up, what i

More information

RIN: Monday, May 16, Problem Points Score Total 100

RIN: Monday, May 16, Problem Points Score Total 100 RENSSELER POLYTEHNI INSTITUTE TROY, NY FINL EXM INTRODUTION TO ENGINEERING NLYSIS ENGR-00) NME: Solution Section: RIN: Monda, Ma 6, 06 Problem Points Score 0 0 0 0 5 0 6 0 Total 00 N.B.: You will be graded

More information

UNIVERSITY OF SASKATCHEWAN GE MECHANICS III FINAL EXAM APRIL 18, 2011 Professor A. Dolovich A CLOSED BOOK EXAMINATION TIME: 3 HOURS

UNIVERSITY OF SASKATCHEWAN GE MECHANICS III FINAL EXAM APRIL 18, 2011 Professor A. Dolovich A CLOSED BOOK EXAMINATION TIME: 3 HOURS UNIVERSITY OF SASKATCHEWAN GE 226.3 MECHANICS III FINAL EXAM APRIL 18, 2011 Professor A. Dolovich A CLOSED BOOK EXAMINATION TIME: 3 HOURS LAST NAME (printed): FIRST NAME (printed): STUDENT NUMBER: EXAMINATION

More information

5. Plane Kinetics of Rigid Bodies

5. Plane Kinetics of Rigid Bodies 5. Plane Kinetics of Rigid Bodies 5.1 Mass moments of inertia 5.2 General equations of motion 5.3 Translation 5.4 Fixed axis rotation 5.5 General plane motion 5.6 Work and energy relations 5.7 Impulse

More information

h p://edugen.wileyplus.com/edugen/courses/crs1404/pc/b02/c2hlch...

h p://edugen.wileyplus.com/edugen/courses/crs1404/pc/b02/c2hlch... If you a empt to slide one... 1 of 1 16-Sep-12 19:29 APPENDIX B If you attempt to slide one solid object across another, the sliding is resisted by interactions between the surfaces of the two objects.

More information

( kg) (410 m/s) 0 m/s J. W mv mv m v v. 4 mv

( kg) (410 m/s) 0 m/s J. W mv mv m v v. 4 mv PHYS : Solution to Chapter 6 Home ork. RASONING a. The work done by the gravitational orce i given by quation 6. a = (F co θ). The gravitational orce point downward, oppoite to the upward vertical diplacement

More information

Problems (Equilibrium of Particles)

Problems (Equilibrium of Particles) 1. he kg block rests on the rough surface. Length of the spring is 18 mm in the position shown. Unstretched length of the spring is mm. Determine the coefficient of friction required for the equilibrium.

More information

Chapter 9-10 Test Review

Chapter 9-10 Test Review Chapter 9-10 Test Review Chapter Summary 9.2. The Second Condition for Equilibrium Explain torque and the factors on which it depends. Describe the role of torque in rotational mechanics. 10.1. Angular

More information

On completion of this short tutorial you should be able to do the following. Calculate the effort and torque needed to raise and lower a load.

On completion of this short tutorial you should be able to do the following. Calculate the effort and torque needed to raise and lower a load. CITY AND GUILDS 9210 Unit 130 MECHANICS OF MACHINES AND STRENGTH OF MATERIALS OUTCOME 6 TUTORIAL 3 - SCREW DRIVES Outcome 6 Explain the concepts of friction and friction devices. The learner can: 1. Explain

More information

Reading Quiz. Chapter 5. Physics 111, Concordia College

Reading Quiz. Chapter 5. Physics 111, Concordia College Reading Quiz Chapter 5 1. The coefficient of static friction is A. smaller than the coefficient of kinetic friction. B. equal to the coefficient of kinetic friction. C. larger than the coefficient of kinetic

More information

d. Determine the power output of the boy required to sustain this velocity.

d. Determine the power output of the boy required to sustain this velocity. AP Physics C Dynamics Free Response Problems 1. A 45 kg boy stands on 30 kg platform suspended by a rope passing over a stationary pulley that is free to rotate. The other end of the rope is held by the

More information

Lecture 15 - Current. A Puzzle... Advanced Section: Image Charge for Spheres. Image Charge for a Grounded Spherical Shell

Lecture 15 - Current. A Puzzle... Advanced Section: Image Charge for Spheres. Image Charge for a Grounded Spherical Shell Lecture 15 - Current Puzzle... Suppoe an infinite grounded conducting plane lie at z = 0. charge q i located at a height h above the conducting plane. Show in three different way that the potential below

More information

Solution 11. Kinetics of rigid body(newton s Second Law)

Solution 11. Kinetics of rigid body(newton s Second Law) Solution () urpose and Requirement Solution Kinetics of rigid bod(newton s Second Law) In rob, kinematics stud regarding acceleration of mass center should be done before Newton s second law is used to

More information

PHYS1100 Practice problem set, Chapter 8: 5, 9, 14, 20, 22, 25, 28, 30, 34, 35, 40, 44

PHYS1100 Practice problem set, Chapter 8: 5, 9, 14, 20, 22, 25, 28, 30, 34, 35, 40, 44 PHYS00 Practice problem set, Chapter 8: 5, 9, 4, 0,, 5, 8, 30, 34, 35, 40, 44 8.5. Solve: The top figure shows the pulle (P), block A, block B, the surface S of the incline, the rope (R), and the earth

More information

Easy. P5.3 For equilibrium: f = F and n = F g. Also, f = n, i.e., f n F F g. (a) 75.0 N N N N (b) ma y.

Easy. P5.3 For equilibrium: f = F and n = F g. Also, f = n, i.e., f n F F g. (a) 75.0 N N N N (b) ma y. Chapter 5 Homework Solutions Easy P5.3 For equilibrium: f = F and n = F g. Also, f = n, i.e., (a) f n F F g s k 75.0 N 25.09.80 N 0.306 60.0 N 25.09.80 N 0.245 ANS. FIG. P5.3 P5.4 F y ma y : n mg 0 f s

More information

KINGS COLLEGE OF ENGINEERING ENGINEERING MECHANICS QUESTION BANK UNIT I - PART-A

KINGS COLLEGE OF ENGINEERING ENGINEERING MECHANICS QUESTION BANK UNIT I - PART-A KINGS COLLEGE OF ENGINEERING ENGINEERING MECHANICS QUESTION BANK Sub. Code: CE1151 Sub. Name: Engg. Mechanics UNIT I - PART-A Sem / Year II / I 1.Distinguish the following system of forces with a suitable

More information

Simple Machines. Bởi: OpenStaxCollege

Simple Machines. Bởi: OpenStaxCollege F Simple Machines Simple Machines Bởi: OpenStaxCollege Simple machines are devices that can be used to multiply or augment a force that we apply often at the expense of a distance through which we apply

More information

Plane Motion of Rigid Bodies: Forces and Accelerations

Plane Motion of Rigid Bodies: Forces and Accelerations Plane Motion of Rigid Bodies: Forces and Accelerations Reference: Beer, Ferdinand P. et al, Vector Mechanics for Engineers : Dynamics, 8 th Edition, Mc GrawHill Hibbeler R.C., Engineering Mechanics: Dynamics,

More information

DYNAMICS ME HOMEWORK PROBLEM SETS

DYNAMICS ME HOMEWORK PROBLEM SETS DYNAMICS ME 34010 HOMEWORK PROBLEM SETS Mahmoud M. Safadi 1, M.B. Rubin 2 1 safadi@technion.ac.il, 2 mbrubin@technion.ac.il Faculty of Mechanical Engineering Technion Israel Institute of Technology Spring

More information

if the initial displacement and velocities are zero each. [ ] PART-B

if the initial displacement and velocities are zero each. [ ] PART-B Set No - 1 I. Tech II Semester Regular Examinations ugust - 2014 ENGINEERING MECHNICS (Common to ECE, EEE, EIE, io-tech, E Com.E, gri. E) Time: 3 hours Max. Marks: 70 Question Paper Consists of Part- and

More information

Webreview Torque and Rotation Practice Test

Webreview Torque and Rotation Practice Test Please do not write on test. ID A Webreview - 8.2 Torque and Rotation Practice Test Multiple Choice Identify the choice that best completes the statement or answers the question. 1. A 0.30-m-radius automobile

More information

Position. If the particle is at point (x, y, z) on the curved path s shown in Fig a,then its location is defined by the position vector

Position. If the particle is at point (x, y, z) on the curved path s shown in Fig a,then its location is defined by the position vector 34 C HAPTER 1 KINEMATICS OF A PARTICLE 1 1.5 Curvilinear Motion: Rectangular Component Occaionall the motion of a particle can bet be decribed along a path that can be epreed in term of it,, coordinate.

More information

2.3. Applying Newton s Laws of Motion. Objects in Equilibrium

2.3. Applying Newton s Laws of Motion. Objects in Equilibrium Appling Newton s Laws of Motion As ou read in Section 2.2, Newton s laws of motion describe ow objects move as a result of different forces. In tis section, ou will appl Newton s laws to objects subjected

More information

FALL TERM EXAM, PHYS 1211, INTRODUCTORY PHYSICS I Thursday, 11 December 2014, 6 PM to 9 PM, Field House Gym

FALL TERM EXAM, PHYS 1211, INTRODUCTORY PHYSICS I Thursday, 11 December 2014, 6 PM to 9 PM, Field House Gym FALL TERM EXAM, PHYS 1211, INTRODUCTORY PHYSICS I Thursday, 11 December 2014, 6 PM to 9 PM, Field House Gym NAME: STUDENT ID: INSTRUCTION 1. This exam booklet has 13 pages. Make sure none are missing 2.

More information

UNIT 2 FRICTION 2.1 INTRODUCTION. Structure. 2.1 Introduction

UNIT 2 FRICTION 2.1 INTRODUCTION. Structure. 2.1 Introduction UNIT FICTION Structure.1 Introduction Objectives. Types of.3 Laws of Dry.4 Static and Kinetic.5 Coefficient of.6 Angle of epose.7 Least Force equired to Drag a Body on a ough Horizontal Plane.8 Horizontal

More information

66 Chapter 6: FORCE AND MOTION II

66 Chapter 6: FORCE AND MOTION II Chapter 6: FORCE AND MOTION II 1 A brick slides on a horizontal surface Which of the following will increase the magnitude of the frictional force on it? A Putting a second brick on top B Decreasing the

More information

Angular velocity and angular acceleration CHAPTER 9 ROTATION. Angular velocity and angular acceleration. ! equations of rotational motion

Angular velocity and angular acceleration CHAPTER 9 ROTATION. Angular velocity and angular acceleration. ! equations of rotational motion Angular velocity and angular acceleration CHAPTER 9 ROTATION! r i ds i dθ θ i Angular velocity and angular acceleration! equations of rotational motion Torque and Moment of Inertia! Newton s nd Law for

More information

Name. ME 270 Fall 2005 Final Exam PROBLEM NO. 1. Given: A distributed load is applied to the top link which is, in turn, supported by link AC.

Name. ME 270 Fall 2005 Final Exam PROBLEM NO. 1. Given: A distributed load is applied to the top link which is, in turn, supported by link AC. Name ME 270 Fall 2005 Final Exam PROBLEM NO. 1 Given: A distributed load is applied to the top link which is, in turn, supported by link AC. Find: a) Draw a free body diagram of link BCDE and one of link

More information

Physics. TOPIC : Friction. 1. To avoid slipping while walking on ice, one should take smaller steps because of the

Physics. TOPIC : Friction. 1. To avoid slipping while walking on ice, one should take smaller steps because of the TOPIC : Friction Date : Marks : 0 mks Time : ½ hr. To avoid slipping while walking on ice, one should take smaller steps because of the Friction of ice is large (b Larger normal reaction (c Friction of

More information

PROBLEMS ON WORK AND ENERGY PRINCIPLE

PROBLEMS ON WORK AND ENERGY PRINCIPLE ON WORK ND ENERGY PRINCIPLE . he ytem i releaed from ret with no lack in the cable and with the prin tretched mm. Determine the ditance traveled by the -k cart before it come to ret (a) if m approache

More information

AP Physics Charge Wrap up

AP Physics Charge Wrap up AP Phyic Charge Wrap up Quite a few complicated euation for you to play with in thi unit. Here them babie i: F 1 4 0 1 r Thi i good old Coulomb law. You ue it to calculate the force exerted 1 by two charge

More information