6.003: Signals and Systems. Feedback, Poles, and Fundamental Modes

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1 6.003: Sigals ad Systems Feedback, Poles, ad Fudametal Modes February 9, 2010

2 Last Time: Multiple Represetatios of DT Systems Verbal descriptios: preserve the ratioale. To reduce the umber of bits eeded to store a sequece of large umbers that are early equal, record the first umber, ad the record successive differeces. Differece equatios: mathematically compact. y[] =x[] x[ 1] Block diagrams: illustrate sigal flow paths. x[] + y[] 1 Delay Operator represetatios: aalyze systems as polyomials. Y =(1 R) X

3 Last Time: Feedback, Cyclic Sigal Paths, ad Modes Systems with sigals that deped o previous values of the same sigal are said to have feedback. Example: The accumulator system has feedback. X + Y Delay By cotrast, the differece machie does ot have feedback. X + Y 1 Delay

4 Last Time: Feedback, Cyclic Sigal Paths, ad Modes The effect of feedback ca be visualized by tracig each cycle through the cyclic sigal paths. X + Y p 0 Delay x[] =δ[] y[] Each cycle creates aother sample i the output.

5 Last Time: Feedback, Cyclic Sigal Paths, ad Modes The effect of feedback ca be visualized by tracig each cycle through the cyclic sigal paths. X + Y p 0 Delay x[] =δ[] y[] Each cycle creates aother sample i the output.

6 Last Time: Feedback, Cyclic Sigal Paths, ad Modes The effect of feedback ca be visualized by tracig each cycle through the cyclic sigal paths. X + Y p 0 Delay x[] =δ[] y[] Each cycle creates aother sample i the output.

7 Last Time: Feedback, Cyclic Sigal Paths, ad Modes The effect of feedback ca be visualized by tracig each cycle through the cyclic sigal paths. X + Y p 0 Delay x[] =δ[] y[] Each cycle creates aother sample i the output.

8 Last Time: Feedback, Cyclic Sigal Paths, ad Modes The effect of feedback ca be visualized by tracig each cycle through the cyclic sigal paths. X + Y p 0 Delay x[] =δ[] y[] Each cycle creates aother sample i the output.

9 Last Time: Feedback, Cyclic Sigal Paths, ad Modes The effect of feedback ca be visualized by tracig each cycle through the cyclic sigal paths. X + Y p 0 Delay x[] =δ[] y[] Each cycle creates aother sample i the output. The respose will persist eve though the iput is trasiet.

10 Geometric Growth: Poles These uit-sample resposes ca be characterized by a sigle umber the pole which is the base of the geometric sequece. X + Y p 0 Delay { y[] = p 0, if >=0; 0, otherwise. y[] y[] y[] p 0 =0.5 p 0 =1 p 0 =1.2

11 Check Yourself How may of the followig uit-sample resposes ca be represeted by a sigle pole?

12 Check Yourself How may of the followig uit-sample resposes ca be represeted by a sigle pole? 3

13 Geometric Growth The value of p 0 determies the rate of growth. y[] y[] y[] y[] z p 0 < 1: 1 < p 0 < 0: 0 < p 0 < 1: p 0 > 1: magitude diverges, alteratig sig magitude coverges, alteratig sig magitude coverges mootoically magitude diverges mootoically

14 Secod-Order Systems The uit-sample resposes of more complicated cyclic systems are more complicated. X + Y R 1.6 R 0.63 y[] Not geometric. This respose grows the decays.

15 Factorig Secod-Order Systems Factor the operator expressio to break the system ito two simpler systems (divide ad coquer). X + Y R 1.6 R 0.63 Y = X +1.6RY 0.63R 2 Y (1 1.6R +0.63R 2 ) Y = X (1 0.7R)(1 0.9R) Y = X

16 Factorig Secod-Order Systems The factored form correspods to a cascade of simpler systems. (1 0.7R)(1 0.9R) Y = X X + Y 2 + Y 0.7 R 0.9 R (1 0.7R) Y 2 = X (1 0.9R) Y = Y 2 X + Y 1 + Y 0.9 R 0.7 R (1 0.9R) Y 1 = X (1 0.7R) Y = Y 1 The order does t matter (if systems are iitially at rest).

17 Factorig Secod-Order Systems The uit-sample respose of the cascaded system ca be foud by multiplyig the polyomial represetatios of the subsystems. Y X = (1 0.7R)(1 0.9R) = (1 0.7R) (1 0.9R) }{{}}{{} {}}{{}}{ = (1+0.7R R R 3 + ) (1+0.9R R R 3 + ) Multiply, the collect terms of equal order: Y =1+( )R +( )R 2 X +( )R 3 +

18 Multiplyig Polyomial Graphical represetatio of polyomial multiplicatio. Y =(1+aR + a 2 R 2 + a 3 R 3 + ) (1 + br + b 2 R 2 + b 3 R 3 + ) X 1 1 a R b R X a 2 R 2 + b 2 R 2 + Y a 3 R 3 b 3 R Collect terms of equal order: Y =1+(a + b)r +(a 2 + ab + b 2 )R 2 +(a 3 + a 2 b + ab 2 + b 3 )R 3 + X

19 Multiplyig Polyomials Tabular represetatio of polyomial multiplicatio. (1 + ar + a 2 R 2 + a 3 R 3 + ) (1 + br + b 2 R 2 + b 3 R 3 + ) 1 br b 2 R 2 b 3 R br b 2 R 2 b 3 R 3 ar ar abr 2 ab 2 R 3 ab 3 R 4 a 2 R 2 a 2 R 2 a 2 br 3 a 2 b 2 R 4 a 2 b 3 R 5 a 3 R 3 a 3 R 3 a 3 br 4 a 3 b 2 R 5 a 3 b 3 R 6 Group same powers of R by followig reverse diagoals: Y =1+(a + b)r +(a 2 + ab + b 2 )R 2 +(a 3 + a 2 b + ab 2 + b 3 )R 3 + X y[]

20 Partial Fractios Use partial fractios to rewrite as a sum of simpler parts. X + Y R 1.6 R 0.63 Y X = 1 1.6R +0.63R 2 = (1 0.9R)(1 0.7R) = 1 0.9R 1 0.7R

21 Secod-Order Systems: Equivalet Forms The sum of simpler parts suggests a parallel implemetatio. Y X = 1 0.9R 1 0.7R X + Y Y 0.9 R + Y R If x[] =δ[] the y 1 [] =0.9 ad y 2 [] =0.7 for 0. Thus, y[] =4.5(0.9) 3.5(0.7) for 0.

22 Partial Fractios Graphical represetatio of the sum of geometric sequeces. y 1 [] =0.9 for y 2 [] =0.7 for y[] =4.5(0.9) 3.5(0.7) for

23 Partial Fractios Partial fractios provides a remarkable equivalece. X + Y R 1.6 R 0.63 X + Y Y 0.9 R + Y R follows from thikig about system as polyomial (factorig).

24 Poles The key to simplifyig a higher-order system is idetifyig its poles. Poles are the roots of the deomiator of the system fuctioal whe R 1. z Start with system fuctioal: Y = = = X 1 1.6R+0.63R 2 (1 p 0 R)(1 p 1 R) (1 0.7R) (1 0.9R) }{{}}{{} p 0 =0.7 p 1 =0.9 1 Substitute R ad fid roots of deomiator: z Y 1 z 2 z 2 = = = X z 2 1.6z+0.63 (z 0.7) (z 0.9) }{{}}{{} z z z 0 =0.7 z 1 =0.9 The poles are at 0.7 ad 0.9.

25 Check Yourself Cosider the system described by y[] = 1 4 y[ 1] y[ 2] + x[ 1] x[ 2] 2 How may of the followig are true? 1. The uit sample respose coverges to zero. 2. There are poles at z = 1 2 ad z = There is a pole at z = There are two poles. 5. Noe of the above

26 Check Yourself y[] = 4 y[ 1] + 8 y[ 2] + x[ 1] 2 x[ 2] ( R 8 1 R 2 )Y =(R 2 1 R 2 )X R R 2 2 z H(R) = Y z 2 = = z = X 1+ 1 R z 4 8R 2 1 z 2 z 2 + z z 1 = ( )( 2 ) z +1 2 z The uit sample respose coverges to zero. 2. There are poles at z = 2 ad z = There is a pole at z = 1 X 4. There are two poles Noe of the above X X

27 Check Yourself Cosider the system described by y[] = 1 4 y[ 1] y[ 2] + x[ 1] x[ 2] 2 How may of the followig are true? 2 1. The uit sample respose coverges to zero. 2. There are poles at z = 1 2 ad z = There is a pole at z = There are two poles. 5. Noe of the above

28 Populatio Growth

29 Populatio Growth

30 Populatio Growth

31 Populatio Growth

32 Populatio Growth

33 Populatio Growth

34 Populatio Growth

35 Populatio Growth

36 Populatio Growth

37 Populatio Growth

38 Check Yourself What are the pole(s) of the Fiboacci system? ad ad ad oe of the above

39 Check Yourself What are the pole(s) of the Fiboacci system? Differece equatio for Fiboacci system: y[] = x[]+ y[ 1] + y[ 2] System fuctioal: Y 1 H = = X 1 R R 2 Deomiator is secod order 2 poles.

40 Check Yourself Fid the poles by substitutig R 1/z i system fuctioal. Y 1 1 z 2 H = = = X 1 R R z 2 z 1 2 Poles are at 1 ± 5 1 z = = φ, 2 φ z 1 z where φ represets the golde ratio 1+ 5 φ = The two poles are at 1 z 0 = φ ad z 1 = φ

41 Check Yourself What are the pole(s) of the Fiboacci system? ad ad ad oe of the above

42 Example: Fiboacci s Buies Each pole correspods to a fudametal mode. 1 φ ad φ φ ( ) 1 φ Oe mode diverges, oe mode oscillates!

43 Example: Fiboacci s Buies The uit-sample respose of the Fiboacci system ca be writte as a weighted sum of fudametal modes. φ 5 1 φ 5 Y 1 H = = = + X 1 R R 2 1 φr 1+ 1 R φ φ h[] = φ 1 + ( φ) ; 0 5 φ 5 But we already kow that h[] is the Fiboacci sequece f: f :1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89,... Therefore we ca calculate f[] without kowig f[ 1] or f[ 2]!

44 Complex Poles What if a pole has a o-zero imagiary part? Example: Y 1 = X 1 R+ R 2 1 z 2 = = 1 z z 2 z +1 z 2 Poles are z = 2 1 ± 2 3 j = e ±jπ/3. What are the implicatios of complex poles?

45 Complex Poles Partial fractios work eve whe the poles are complex. ( ) Y e jπ/3 e jπ/3 X = 1 e jπ/3 R 1 e jπ/3 R = j 3 1 e jπ/3 R 1 e jπ/3 R There are two fudametal modes (both geometric sequeces): e jπ/3 = cos(π/3) + j si(π/3) ad e jπ/3 = cos(π/3) j si(π/3)

46 Complex Poles Complex modes are easier to visualize i the complex plae. e j2π/3 e jπ/3 = cos(π/3) + j si(π/3) Im e j1π/3 e j3π/3 e j0π/3 Re e e j4π/3 j4π/3 e j5π/3 e jπ/3 = cos(π/3) j si(π/3) Im e j5π/3 e j3π/3 e j0π/3 Re e j2π/3 e j1π/3

47 Complex Poles The output of a real system has real values. y[] = x[]+ y[ 1] y[ 2] Y H = = X 1 h[] = 1 1 R+ R = 1 e ( jπ/3 R 1 e jπ/3 R ) 1 e jπ/3 e jπ/3 = j 3 1 e jπ/3 R 1 e jπ/3 R ( ) e j(+1)π/3 e j(+1)π/3 2 ( +1)π = si j h[] 1 1

48 Check Yourself Uit-sample respose of a system with poles at z = re ±jω. Which of the followig is/are true? 1. r<0.5 ad Ω < r<1 ad Ω r<0.5 ad Ω < r<1 ad Ω oe of the above

49 Check Yourself Uit-sample respose of a system with poles at z = re ±jω. Which of the followig is/are true? 2 1. r<0.5 ad Ω < r<1 ad Ω r<0.5 ad Ω < r<1 ad Ω oe of the above

50 Check Yourself X + R R R Y How may of the followig statemets are true? 1. This system has 3 fudametal modes. 2. All of the fudametal modes ca be writte as geometrics. 3. Uit-sample respose is y[] :0, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, Uit-sample respose is y[] :1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, Oe of the fudametal modes of this system is the uit step.

51 Check Yourself X + R R R Y How may of the followig statemets are true? 4 1. This system has 3 fudametal modes. 2. All of the fudametal modes ca be writte as geometrics. 3. Uit-sample respose is y[] :0, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, Uit-sample respose is y[] :1, 0, 0, 1, 0, 0, 1, 0, 0, 1, 0, 0, Oe of the fudametal modes of this system is the uit step.

52 Summary Systems composed of adders, gais, ad delays ca be characterized by their poles. The poles of a system determie its fudametal modes. The uit-sample respose of a system ca be expressed as a weighted sum of fudametal modes. These properties follow from a polyomial iterpretatio of the system fuctioal.

53 MIT OpeCourseWare Sigals ad Systems Sprig 2010 For iformatio about citig these materials or our Terms of Use, visit:

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