ACEF/1213/06762 Decisão de apresentação de pronúncia
|
|
|
- Frederica Snow
- 5 years ago
- Views:
Transcription
1 ACEF/1213/06762 Decisão de apresentação de pronúncia ACEF/1213/06762 Decisão de apresentação de pronúncia Decisão de Apresentação de Pronúncia ao Relatório da Comissão de Avaliação Externa 1. Tendo recebido o Relatório de Avaliação elaborado pela Comissão de Avaliação Externa relativamente ao ciclo de estudos em funcionamento Engenharia Informática e de Computadores - Alameda 2. conferente do grau de Mestre 3. a ser leccionado na(s) Unidade(s) Orgânica(s) (faculdade, escola, instituto, etc.) Instituto Superior Técnico 4. a(s) Instituição(ões) de Ensino Superior / Entidade(s) Instituidora(s) Universidade De Lisboa 5. decide: Apresentar pronúncia 6. Pronúncia (Português): Encontra-se no ficheiro PDF em anexo. 7. Pronúncia (Português e Inglês, PDF, máx. 100kB): (impresso na página seguinte) pág. 1 de 1
2 Anexos
3 A BCB D EA A FD A A F BDA D D AD B B DA D B A D D A DFD D D AB AB CDE F AB B FC B B AB FAB C ABC B C F B B D AB AB F ABA F AB EB B BA B C DF A B B F BFC F A BC B CD CD B B B AA B B C CD B B CAF ABC BD B D F B B FAFD B C B AB F AB CD C B B B AA B B FAA B B B FA F FC D F B DF CD B AB C AB D C A B AB B B AA B B FAA BA EBA B CD C F B B FA F FC D F BA BC BA B D CD B BD AB AB F CA AB B D B A B B F B BC B B A F B B B AB B AB A AB B B B B CAFC B B CF B B FAB F ABFC C CD A BB EB B D CD B BB DF B B BAFAD B F B D ABFCD F B B A F F F B B B AA B B C BC A AB AD B CD A B B FD B AD B A B FA F FC B B A A A CD A B B B AA B D EDF B B B F B AB C AB FDF ABC B B F B AD AB CD AB B CD BC B B B FD AB AB A AB B C C F B B D A F BFC AD BC B B BD B AB C F D AB B B A B B BE B B D B BA F B D B B B B C B B CAFC B B C C F B C EDF B B BD B B B CF B B B B C C F B C EDF B B FAB F AB B AD BFC C CD AB BFCD B B B B C B B A BD B B FAA B F D B AB C A FDF ABC B B F B B C B C EDF BC B B F B AB BF B B AB C A C F D AB B AD ABFCD A B B B B F B B D AB A AB B B B C D D CF B B B D AB A AB B C B C EDF B B AB B B B B FC CD B B BC AA B C F CD B B D AB A AB B C C F B C EDF B B B B B D B B FAB F ABFC C CD AB CD BD B B FD D EDF B AB C F D ABFCD C A B B F B B FC B AB AB B BD B AD B BD BC B FA BA AD CDF B B B ADEB BA B B EB C B B F B BA B C CD B A CD CD B B F AB BA A DF B B B B B B AD B AB A AB DF AB AB CAD C F CD A AAF ABC B C B B AD AB B C AB B AB C AB FC B AB F AB A C AB B AD AB A C B CD B E F AB AB B FA F FC AB B ABA B A CD AB B B C CD AB CD AB CD BAF B B FAD AB B C B BB C C EDF B B B B A B CF A B F A B F D F A B FAA D D B B C C F B C EDF B B A B AA B BA B F FBD B C B B AAF F F B B F B BD AB D C AB B A F AB FADFCD A B B B BA B F B F F CD B BFC BD C F D A B B B BFC ADF B F CD F B FAA D A B AA A B B BFAA BC F B A CD CD B B F B BD AB BFC BC D AB CD D A B B A AB B B B C ABC B B B BA B B FB C CD B AB B F B FA CD CD B AB F CD AB F AB B F B AB B AD AB F F A B C CD B B D A B F F A B B F F F B A B F A B B F B A D A FAA D A B CD B AB AAF F F AB B F B AD ABD AB CD B
4 D F B A F B B F C B B B D CD B B D B B AB B AB B B DF CD B AD B B B BD B B AB E F AB F ABD AB AA B CF B AB AB B CF AB F AB B B FD AB B B B B B B BC B B CF AB F AB B CD B BA AD B B B FA F FC B B F F EB C B B D ABAF D C AB B A CD B AB A AB DF AB ABD AB F AB B C A B B CAF A FCA DFA D F A B AA B B B B F B B A D B B E F AB D A BC BA CD E FAB B AD B B A B B BFCD CA B B D C B AB C AB B A B FAA D B B FD AB A AB BD BC B AD C F B BFC F F F B B C A B C B B A B C B B B B B DF B B C AB BAFD B C C B B B C AB D B C B B FAA D BC BA CDF B B B FCF B B A B C B D C DF B B B BD B A C F BC BA B DF F B FAAF C B AA BA C BC BD B B FAA D D A B B D B A A A AD B B A D B DB A B B A B DFD D D BD C BD B CDAB BD B C B FD B F B B BFCB C B CB D BA B BD A AD B A AB B B FC BF CD B ABFC F D B B B B BAD DB FD B BA DB B CAF DF CAB FC BD B F ADB FCDB BD C AF CA B BD B D ABFC F D BD DBD B FAAF CB AABD BD B B FAB FA F FC D BFCB DF CBD B D C BAD CDA B B F BD DBD B FAAF CB AAB C C B B C AD B AB FA F FC D BF B B BC DB CAF B B F CAF CAB DBAD B B F BD BAD AAB F ADBD DBD FABFABC DBA F F BD B B DB CBD B B B A AB D FC BFAB CF BFCBD BFC C CDB A B C B BC BD BD BFCD B CDBD DBD D A B F BA AD BFCD BD BA B CD D B AD B A B A F F FD B FD BD B C B AABD DB ABD FABA B FA F FC DF C BFCBAF F B A A B F FC B D DF B AABD BD B C B BD BAD CDAB FDD BD BD B ADB BFCBFCD D AD AB AB ABFCB B C B AD BF BC DB B BD B C FC FC BA ABFCB D BFD B B C F BC DBD B D C BD BA B C FDBD B C F D AB B B BD DB AB A C D B BD BA F FDB BD B C B B CBD B B B BD BD B DF CB CF FC BD B A ABFCBD BFC C CDB AB FD BD BFCD DF CB BD B C B C BD B D DF B FAAF CB BAD CDAB FDD BFCBD B ADB B B C DF C AD AB C B D B C FC FC BD BD B C B B DABD B CB B FD BAD CDAB FC FCD D B AD B A B D BD B ADB AB B D B B A ABA B AB D F B C C BD B D B C DF AB ABFCB D B D A B CF AFDF AB A B AB B B FC B B B BD DB D B A ABFCB D B F C B B B F B D B BD FC C CDB A B A B CA B D DF B D C BD BFCD C B C F D A B ABC D B BD B C BD B C C B DB B AB CB FC B CB BA AD CDF B F B BD B B B B B C B B F BFAB CD BFCBD B AAB B FC BA FDD BD
5 B B B CBD B A BD B CDAB FC BD B AAF B CAD FCDAB CBD A AB B AA B BAD CDAB FC BD A ABD B F B AFC B D CB F A AB B A ABD DB CB B CDBA D BA B AB C DF CB AD A B B D FD B DB B B B C D B A A BC B AFA DBFCB C DF A C FC FC BD B F BFAB B B A B AA BD B AAF F FD B B DFC BD B D C AB A ABFCBD B FADFC D A B C BFCB F B C C AB F F BD C F BFCC DF CB D BFCAD B B B A F CDF F B A B B FAA D DF C B DBA B BAD AA B BD DBD FAB ABC D A CD B FC BFCC DF CB BFCB D B CD DA BA B AB FD B CF AB D BD CB ADB D B B FCB DF B ABD B FC B ABD B AB B CD BD B B F B D B F BD DBD A B C A BD D B FD B D BF AB B F FD DFC BD BF CD DF CB DAB B FAA D DF CA BFC A BD B C AB B B A BFCD DF CB FD BD B CD FA CFD B C B B D BFCBD B AB B C BD B B F B FC B C CDB B B C B BD BA B A ABD CB ABD B CFA BD BFCB A AB B B FDABFCAD B B B F B ABD BC B B A AB A AD B C B C BD BC B BAF D C AB C FC B DA B B A DF CB CB B DF CB D A B F B B CAF B CA DFA D BFAB B C C B A DFC B B F AB D A BC DB AB CD B BD B A B C CD BD BFCD CA B D C B C B BAD CDABFCBD B FAA D DF CBAD BFCB C B A AB B BFAB B B D BD BD FAB B DF CB D B B FC DF CB BD B AB C B B B B BAD CDAB B DB FD B C BD B FAA D DF CB B FAAFC A FC BD B FC B FD BD B CB D C DF B B BD B FAA D DF CBD F DBD DB C B AF B BFCD D B FD BD F B AAF C B DF FD B CB BA C B
D EFB B E B EAB ABC DEF C A F C D C DEF C AD C AEC D D E C D EF B ABC AB CD A EFD AD D E
D EFB B E BEAB ABC DEF C A F C D C DEF C AD C AEC D D E A B C D EF B ABC AB CD A EFD AD D E FFF A B FBC AE BC D AD A D F D F D F D D B D A D A ED D D DD F D D D D A A DA ADD D F AD AD C A DD D D F D A
L institution sportive : rêve et illusion
L institution sportive : rêve et illusion Hafsi Bedhioufi, Sida Ayachi, Imen Ben Amar To cite this version: Hafsi Bedhioufi, Sida Ayachi, Imen Ben Amar. L institution sportive : rêve et illusion. Revue
Architecture and development methodology for Location Based Services
The ITB Journal Volume 5 Issue 1 Article 13 2004 Architecture and development methodology for Location Based Services Aaron Hand School of Science, Institute of Technology at Tallaght, Dublin 24., aaron.hand@itnet.ie
An Adaptive elearning framework- Design Issues and Considerations
The ITB Journal Volume 5 Issue 1 Article 4 2004 An Adaptive elearning framework- Design Issues and Considerations Maria Brennan Institute of Technology Blanchardstown, maria.brennan@itb.ie Follow this
A B CDE F B FD D A C AF DC A F
International Journal of Arts & Sciences, CD-ROM. ISSN: 1944-6934 :: 4(20):121 131 (2011) Copyright c 2011 by InternationalJournal.org A B CDE F B FD D A C A BC D EF C CE C A D ABC DEF B B C A E E C A
Day 6: Triangle Congruence, Correspondence and Styles of Proof
Name: Day 6: Triangle Congruence, Correspondence and Styles of Proof Date: Geometry CC (M1D) Opening Exercise Given: CE bisects BD Statements 1. bisects 1.Given CE BD Reasons 2. 2. Define congruence in
Consistency of Academic Performance in Higher Education: A Study of an Irish Business Degree Programme
The ITB Journal Volume 5 Issue 1 Article 5 2004 Consistency of Academic Performance in Higher Education: A Study of an Irish Business Degree Programme Julie Byrne Lecturer, School of Business and Humanities,
Developing a Distributed Java-based Speech Recognition Engine
The ITB Journal Volume 5 Issue 1 Article 2 2004 Developing a Distributed Java-based Speech Recognition Engine Tony Ayers Institute of Technology Blanchardstown, tony.ayers@itb.ie Brian Nolan Institute
Profiling the International New Venture -A literature review of the empirical evidence
The ITB Journal Volume 5 Issue 1 Article 11 2004 Profiling the International New Venture -A literature review of the empirical evidence Natasha Evers School ofbusiness & Humanities Institute of Technology,
The Future We Want: Stark Choices
ABC D EF B FB B FEFB FB B AF B D DB F F B B B B FCCF BACKGROUND The Future We Want: Stark Choices ABC DE FD FBC A FBC DE D A F FBC B A A E D AFD FD DE BF DE D DE AFBC FB DE A F F DB D B A A E NBSAP development
SHW 1-01 Total: 30 marks
SHW -0 Total: 30 marks 5. 5 PQR 80 (adj. s on st. line) PQR 55 x 55 40 x 85 6. In XYZ, a 90 40 80 a 50 In PXY, b 50 34 84 M+ 7. AB = AD and BC CD AC BD (prop. of isos. ) y 90 BD = ( + ) = AB BD DA x 60
Justification of Investment in IT systems
The ITB Journal Volume 5 Issue 1 Article 12 2004 Justification of Investment in IT systems Aidan Farrell School of Computing, Dublin Institute of Technology, Kevin Street, Dublin 8., aidan.farrell@dit.ie
Postulates and Theorems in Proofs
Postulates and Theorems in Proofs A Postulate is a statement whose truth is accepted without proof A Theorem is a statement that is proved by deductive reasoning. The Reflexive Property of Equality: a
Angles of Elevation and Depression
Angles of Elevation and Depression Study the following figure carefully. angle of elevation angle of depression When we see an object above us, the angle between our line of sight and the horizontal is
HKDSE2018 Mathematics (Compulsory Part) Paper 2 Solution 1. B 4 (2 ) = (2 ) 2. D. α + β. x x. α β 3. C. h h k k ( 4 ) 6( 2 )
HKDSE08 Mthemtics (Compulsory Prt) Pper Solution. B n+ 8 n+ 4 ( ) ( ) n+ n+ 6n+ 6n+ (6n+ ) (6n+ ). D α β x x α x β ( x) α x β β x α x + β x β ( α + β ) x β β x α + β. C 6 4 h h k k ( 4 ) 6( ) h k h + k
Chapter 7. Geometric Inequalities
4. Let m S, then 3 2 m R. Since the angles are supplementary: 3 2580 4568 542 Therefore, m S 42 and m R 38. Part IV 5. Statements Reasons. ABC is not scalene.. Assumption. 2. ABC has at least 2. Definition
TRIANGLES CHAPTER 7. (A) Main Concepts and Results. (B) Multiple Choice Questions
CHAPTER 7 TRIANGLES (A) Main Concepts and Results Triangles and their parts, Congruence of triangles, Congruence and correspondence of vertices, Criteria for Congruence of triangles: (i) SAS (ii) ASA (iii)
IB MYP Unit 6 Review
Name: Date: 1. Two triangles are congruent if 1. A. corresponding angles are congruent B. corresponding sides and corresponding angles are congruent C. the angles in each triangle have a sum of 180 D.
1. Prove that for every positive integer n there exists an n-digit number divisible by 5 n all of whose digits are odd.
32 nd United States of America Mathematical Olympiad Proposed Solutions May, 23 Remark: The general philosophy of this marking scheme follows that of IMO 22. This scheme encourages complete solutions.
SOLUTIONS SECTION A [1] = 27(27 15)(27 25)(27 14) = 27(12)(2)(13) = cm. = s(s a)(s b)(s c)
![SOLUTIONS SECTION A [1] = 27(27 15)(27 25)(27 14) = 27(12)(2)(13) = cm. = s(s a)(s b)(s c)](/thumbs/79/80187791.jpg "SOLUTIONS SECTION A [1] = 27(27 15)(27 25)(27 14) = 27(12)(2)(13) = cm. = s(s a)(s b)(s c)")
1. (A) 1 1 1 11 1 + 6 6 5 30 5 5 5 5 6 = 6 6 SOLUTIONS SECTION A. (B) Let the angles be x and 3x respectively x+3x = 180 o (sum of angles on same side of transversal is 180 o ) x=36 0 So, larger angle=3x
Questions of Ethical Responsibility in the Research of Unaccompanied Minors
The ITB Journal Volume 5 Issue 1 Article 27 2004 Questions of Ethical Responsibility in the Research of Unaccompanied Minors Oonagh Charleton School of Business and Humanities, Institute of Technology
Advanced Digital Design with the Verilog HDL, Second Edition Michael D. Ciletti Prentice Hall, Pearson Education, 2011
Problem 2-1 Recall that a minterm is a cube in which every variable appears. A Boolean expression in SOP form is canonical if every cube in the expression has a unique representation in which all of the
PERIODIC ORBITS FOR A GENERALIZED FRIEDMANN-ROBERTSON-WALKER HAMILTONIAN SYSTEM IN DIMENSION 6 FATIMA EZZAHRA LEMBARKI AND JAUME LLIBRE
This is a preprint of: Periodic orbits for a generalized Friedmann-Robertson-Walker Hamiltonian system in dimension 6, Fatima E. Lembarki, Jaume Llibre, Discrete Contin. Dyn. Syst. Ser. S, vol. 8(6, 1165
Firmware Versionen. FAX-Geräte (Tinte) FAX-Geräte (Laser) DCP-Geräte (Tinte)
FAX-Geräte (Tinte) FAX-1355 lz0819_l.pmu 20.05.2010 L 66A3 0003 FAX-1360 lz0819_l.pmu 20.05.2010 L 66A3 0103 FAX-1460 lz0819_l.pmu 20.05.2010 L 66A3 0203 FAX-1560 lz0819_l.pmu 20.05.2010 L 66A3 0303 FAX-1835C
Passerelle entre les arts : la sculpture sonore
Passerelle entre les arts : la sculpture sonore Anaïs Rolez To cite this version: Anaïs Rolez. Passerelle entre les arts : la sculpture sonore. Article destiné à l origine à la Revue de l Institut National
MetroCount Traffic Executive Individual Vehicles
Individual-34 Page 1 MetroCount Traffic Executive Individual Vehicles Individual-34 -- English (ENA) Datasets: Site: [00001] Old Coast Rd 4km N of Od Bunbury Rd Direction: 5 - South bound A>B, North bound
Given. Segment Addition. Substitution Property of Equality. Division. Subtraction Property of Equality
Mastery Test Questions (10) 1. Question: What is the missing step in the following proof? Given: ABC with DE AC. Prove: Proof: Statement Reason
32 nd United States of America Mathematical Olympiad Recommended Marking Scheme May 1, 2003
32 nd United States of America Mathematical Olympiad Recommended Marking Scheme May 1, 23 Remark: The general philosophy of this marking scheme follows that of IMO 22. This scheme encourages complete solutions.
NAME: Mathematics 133, Fall 2013, Examination 3
NAME: Mathematics 133, Fall 2013, Examination 3 INSTRUCTIONS: Work all questions, and unless indicated otherwise give reasons for your answers. If the problem does not explicitly state that the underlying
Common Core Math 3. Proofs. Can you find the error in this proof "#$%&!!""""""""""""""""""""""""""""""""""""""""""""""""""""""""""""""""""""""""!
Common Core Math 3 Proofs Can you find the error in this proof "$%& a = b'()$&2 = 1 *+,+$-$%+.. /$,0)%. " a = b $%&'( ) a 2 = ab = a 2 - b 2 = ab - b 2? (a + b)(a - b) = b(a - b) @ (a + b) = b B a + a
Class IX Chapter 8 Quadrilaterals Maths
Class IX Chapter 8 Quadrilaterals Maths Exercise 8.1 Question 1: The angles of quadrilateral are in the ratio 3: 5: 9: 13. Find all the angles of the quadrilateral. Answer: Let the common ratio between
Class IX Chapter 8 Quadrilaterals Maths
1 Class IX Chapter 8 Quadrilaterals Maths Exercise 8.1 Question 1: The angles of quadrilateral are in the ratio 3: 5: 9: 13. Find all the angles of the quadrilateral. Let the common ratio between the angles
Answer Key. 9.1 Parts of Circles. Chapter 9 Circles. CK-12 Geometry Concepts 1. Answers. 1. diameter. 2. secant. 3. chord. 4.
9.1 Parts of Circles 1. diameter 2. secant 3. chord 4. point of tangency 5. common external tangent 6. common internal tangent 7. the center 8. radius 9. chord 10. The diameter is the longest chord in
A B C DEF A AE E F A A AB F F A
A B C DEF A AE E F A A AB F F A F A F A B E A A F DEF AE D AD A B 2 FED AE A BA B EBF A F AE A E F A A A F ED FE F A F ED EF F A B E AE F DEF A BA FA B E F F E FB ED AB ADA AD A BA FA B AE A EFB A A F
Revision Question Bank
Revision Question Bank Triangles 1. In the given figure, find the values of x and y. Since, AB = AC C = B [angles opposite to the equal sides are equal] x = 50 Also, the sum of all angles of a triangle
0113ge. Geometry Regents Exam In the diagram below, under which transformation is A B C the image of ABC?
0113ge 1 If MNP VWX and PM is the shortest side of MNP, what is the shortest side of VWX? 1) XV ) WX 3) VW 4) NP 4 In the diagram below, under which transformation is A B C the image of ABC? In circle
Math 3 Review Sheet Ch. 3 November 4, 2011
Math 3 Review Sheet Ch. 3 November 4, 2011 Review Sheet: Not all the problems need to be completed. However, you should look over all of them as they could be similar to test problems. Easy: 1, 3, 9, 10,
A MINIMAL VERSION OF HILBERT S AXIOMS FOR PLANE GEOMETRY
A MINIMAL VERSION OF HILBERT S AXIOMS FOR PLANE GEOMETRY WILLIAM RICHTER Abstract. This note is intended to be useful to good high school students wanting a rigorous treatment of Hilbert s axioms for plane
4.3 Analog Value Representation
4.3 Analog Value Representation Introduction This section describes the analog values for all the measuring ranges and output ranges which you can use with the analog modules. Converting analog values
EXAMPLE CFG. L = {a 2n : n 1 } L = {a 2n : n 0 } S asa aa. L = {a n b : n 0 } L = {a n b : n 1 } S asb ab S 1S00 S 1S00 100
EXAMPLE CFG L = {a 2n : n 1 } L = {a 2n : n 0 } S asa aa S asa L = {a n b : n 0 } L = {a n b : n 1 } S as b S as ab L { a b : n 0} L { a b : n 1} S asb S asb ab n 2n n 2n L {1 0 : n 0} L {1 0 : n 1} S
RFB 5 The Li - Yau Estimate for Curvature in the Ricci Flow
RFB 5 The Li - Yau Estimate for Curvature in the Ricci Flow I) The Li - Yau Estimate Suppose we have a solution of the Ricci Flow We define the tensors M ab and P abc by M ab = DRc ab - 1 2 D2 R ab + 2
Chapter 6, Solution 1. Joint B: Joint C: Joint FBDs: F = 800 lb T. F = 1700 lb C lb lb F
\ COSMOS: Complete Online Solutions Manual Organization Sstem Chapter 6, Solution 1. Joint FBDs: Joint B: FAB 800 lb F = = 1 8 17 BC so F = 100 lb T AB F = 1700 lb C BC Joint C: FAC Cx 1700 lb = = 8 1
International Mathematical Olympiad. Preliminary Selection Contest 2004 Hong Kong. Outline of Solutions 3 N
International Mathematical Olympiad Preliminary Selection Contest 004 Hong Kong Outline of Solutions Answers:. 8. 0. N 4. 49894 5. 6. 004! 40 400 7. 6 8. 7 9. 5 0. 0. 007. 8066. π + 4. 5 5. 60 6. 475 7.
G.CO.6-9 ONLY COMMON CORE QUESTIONS
Class: Date: G.CO.6-9 ONLY COMMON CORE QUESTIONS Multiple Choice Identify the choice that best completes the statement or answers the question. 1 The image of ABC after a rotation of 90º clockwise about
The One-Quarter Fraction
The One-Quarter Fraction ST 516 Need two generating relations. E.g. a 2 6 2 design, with generating relations I = ABCE and I = BCDF. Product of these is ADEF. Complete defining relation is I = ABCE = BCDF
Visit: ImperialStudy.com For More Study Materials Class IX Chapter 12 Heron s Formula Maths
Exercise 1.1 1. Find the area of a triangle whose sides are respectively 150 cm, 10 cm and 00 cm. The triangle whose sides are a = 150 cm b = 10 cm c = 00 cm The area of a triangle = s(s a)(s b)(s c) Here
Unit 3. Digital encoding
Unit 3. Digital encoding Digital Electronic Circuits (Circuitos Electrónicos Digitales) E.T.S.I. Informática Universidad de Sevilla 9/2012 Jorge Juan 2010, 2011, 2012 You are free to
Synchronous Machine Modeling
ECE 53 Session ; Page / Fall 07 Synchronous Machine Moeling Reference θ Quarature Axis B C Direct Axis Q G F D A F G Q A D C B Transient Moel for a Synchronous Machine Generator Convention ECE 53 Session
8-6. a: 110 b: 70 c: 48 d: a: no b: yes c: no d: yes e: no f: yes g: yes h: no
Lesson 8.1.1 8-6. a: 110 b: 70 c: 48 d: 108 8-7. a: no b: yes c: no d: yes e: no f: yes g: yes h: no 8-8. b: The measure of an exterior angle of a triangle equals the sum of the measures of its remote
A MINIMAL VERSION OF HILBERT S AXIOMS FOR PLANE GEOMETRY
A MINIMAL VERSION OF HILBERT S AXIOMS FOR PLANE GEOMETRY WILLIAM RICHTER Abstract. This note is intended to be useful to good high school students wanting a rigorous treatment of Hilbert s axioms for plane
Geometry 3 SIMILARITY & CONGRUENCY Congruency: When two figures have same shape and size, then they are said to be congruent figure. The phenomena between these two figures is said to be congruency. CONDITIONS
Collinearity/Concurrence
Collinearity/Concurrence Ray Li (rayyli@stanford.edu) June 29, 2017 1 Introduction/Facts you should know 1. (Cevian Triangle) Let ABC be a triangle and P be a point. Let lines AP, BP, CP meet lines BC,
Common Core Math 3. Can you find the error in this proof. Unit 2B - Proofs
Common Core Math 3 Unit 2B - Proofs Can you find the error in this proof "$%& a = b'()$& 2 = 1 *+,+$-$%+.. /$,0)%. " a = b $%&'( ) a 2 = ab = a 2 - b 2 = ab - b 2? (a + b)(a - b) = b(a - b) @ (a + b) =
Chapter 1 Problem Solving: Strategies and Principles
Chapter 1 Problem Solving: Strategies and Principles Section 1.1 Problem Solving 1. Understand the problem, devise a plan, carry out your plan, check your answer. 3. Answers will vary. 5. How to Solve
8-6. a: 110 b: 70 c: 48 d: a: no b: yes c: no d: yes e: no f: yes g: yes h: no
Lesson 8.1.1 8-6. a: 110 b: 70 c: 48 d: 108 8-7. a: no b: yes c: no d: yes e: no f: yes g: yes h: no 8-8. b: The measure of an exterior angle of a triangle equals the sum of the measures of its remote
The Advanced Encryption Standard
Lecturers: Mark D. Ryan and David Galindo. Cryptography 2017. Slide: 48 The Advanced Encryption Standard Successor of DES DES considered insecure; 3DES considered too slow. NIST competition in 1997 15
Honors Geometry Exam Review January 2015
Class: Date: Honors Geometry Exam Review January 2015 Multiple Choice Identify the choice that best completes the statement or answers the question. 1. How many planes can be drawn through any three noncollinear
Website: Page 152»Exercise 6.6» Page 1. Question 1:
Page 152»Exercise 6.6» Question 1: In the given figure, PS is the bisector of QPR of ΔPQR. Prove that. Let us draw a line segment RT parallel to SP which intersects extended line segment QP at point T.
Open Intelligence Changing the Definition of Human Identity
Open Intelligence Changing the Definition of Human Identity B A L A N C E D V I E W T E A M ABC DEFAAEF ABCDEFAD BA AF First Edition 2011 Balanced View Media: Mill Valley, California USA 2011 Open Intelligence:
Functional Dependencies
Functional Dependencies P.J. M c.brien Imperial College London P.J. M c.brien (Imperial College London) Functional Dependencies 1 / 41 Problems in Schemas What is wrong with this schema? bank data no sortcode
GS trapezoids in GS quasigroups
Mathematical Communications 7(2002), 143-158 143 GS trapezoids in GS quasigroups Vladimir Volenec and Zdenka Kolar Abstract. In this paper the concept of a GS trapezoid in a GS quasigroup is defined and
Class X Chapter 15 Similarity Maths
EXERCISE 15(A) Book Name: Selina Concise Question 1: State, true or false: (i) Two similar polygons are necessarily congruent. (ii) Two congruent polygons are necessarily similar. (iii) all equiangular
Rhombi, Rectangles and Squares
Rhombi, Rectangles and Squares Math Practice Return to the Table of Contents 1 Three Special Parallelograms All the same properties of a parallelogram apply to the rhombus, rectangle, and square. Rhombus
Mathematics 2260H Geometry I: Euclidean geometry Trent University, Winter 2012 Quiz Solutions
Mathematics 2260H Geometry I: Euclidean geometry Trent University, Winter 2012 Quiz Solutions Quiz #1. Tuesday, 17 January, 2012. [10 minutes] 1. Given a line segment AB, use (some of) Postulates I V,
Honors Geometry Review Exercises for the May Exam
Honors Geometry, Spring Exam Review page 1 Honors Geometry Review Exercises for the May Exam C 1. Given: CA CB < 1 < < 3 < 4 3 4 congruent Prove: CAM CBM Proof: 1 A M B 1. < 1 < 1. given. < 1 is supp to
Triangles. 3.In the following fig. AB = AC and BD = DC, then ADC = (A) 60 (B) 120 (C) 90 (D) none 4.In the Fig. given below, find Z.
Triangles 1.Two sides of a triangle are 7 cm and 10 cm. Which of the following length can be the length of the third side? (A) 19 cm. (B) 17 cm. (C) 23 cm. of these. 2.Can 80, 75 and 20 form a triangle?
Circles. 1. In the accompanying figure, the measure of angle AOB is 50. Find the measure of inscribed angle ACB.
ircles Name: Date: 1. In the accompanying figure, the measure of angle AOB is 50. Find the measure of inscribed angle AB. 4. In the accompanying diagram, P is tangent to circle at and PAB is a secant.
2008 Euclid Contest. Solutions. Canadian Mathematics Competition. Tuesday, April 15, c 2008 Centre for Education in Mathematics and Computing
Canadian Mathematics Competition An activity of the Centre for Education in Mathematics and Computing, University of Waterloo, Waterloo, Ontario 008 Euclid Contest Tuesday, April 5, 008 Solutions c 008
NACC Uniform Data Set (UDS) FTLD Module
NACC Uniform Data Set (UDS) FTLD Module Data Template For Initial Visit Packet Version 2.0, January 2012 Copyright 2013 University of Washington Created and published by the FTLD work group of the ADC
CMPT 882 Machine Learning
CMPT 882 Machine Learning Lecture Notes Instructor: Dr. Oliver Schulte Scribe: Qidan Cheng and Yan Long Mar. 9, 2004 and Mar. 11, 2004-1 - Basic Definitions and Facts from Statistics 1. The Binomial Distribution
Vectors 1C. 6 k) = =0 = =17
Vectors C For each problem, calculate the vector product in the bracet first and then perform the scalar product on the answer. a b c= 3 0 4 =4i j 3 a.(b c=(5i+j.(4i j 3 =0 +3= b c a = 3 0 4 5 = 8i+3j+6
Homework 3/ Solutions
MTH 310-3 Abstract Algebra I and Number Theory S17 Homework 3/ Solutions Exercise 1. Prove the following Theorem: Theorem Let R and S be rings. Define an addition and multiplication on R S by for all r,
NACC Uniform Data Set (UDS) FTLD Module
NACC Uniform Data Set (UDS) FTLD Module Data Template For FOLLOW-UP Visit Packet Version 2.0, January 2012 Copyright 2013 University of Washington Created and published by the FTLD work group of the ADC
Cristina Nita-Rotaru. CS355: Cryptography. Lecture 9: Encryption modes. AES
CS355: Cryptography Lecture 9: Encryption modes. AES Encryption modes: ECB } Message is broken into independent blocks of block_size bits; } Electronic Code Book (ECB): each block encrypted separately.
PLC Papers. Created For:
PLC Papers Created For: ed by use of accompanying mark schemes towards the rear to attain 8 out of 10 marks over time by completing Circle Theorems 1 Grade 8 Objective: Apply and prove the standard circle
Class IX Chapter 7 Triangles Maths. Exercise 7.1 Question 1: In quadrilateral ACBD, AC = AD and AB bisects A (See the given figure).
Exercise 7.1 Question 1: In quadrilateral ACBD, AC = AD and AB bisects A (See the given figure). Show that ABC ABD. What can you say about BC and BD? In ABC and ABD, AC = AD (Given) CAB = DAB (AB bisects
Fractional Replications
Chapter 11 Fractional Replications Consider the set up of complete factorial experiment, say k. If there are four factors, then the total number of plots needed to conduct the experiment is 4 = 1. When
6 CHAPTER. Triangles. A plane figure bounded by three line segments is called a triangle.
6 CHAPTER We are Starting from a Point but want to Make it a Circle of Infinite Radius A plane figure bounded by three line segments is called a triangle We denote a triangle by the symbol In fig ABC has
MATH1050 Greatest/least element, upper/lower bound
MATH1050 Greatest/ element, upper/lower bound 1 Definition Let S be a subset of R x λ (a) Let λ S λ is said to be a element of S if, for any x S, x λ (b) S is said to have a element if there exists some
Question 1: In quadrilateral ACBD, AC = AD and AB bisects A (See the given figure). Show that ABC ABD. What can you say about BC and BD?
Class IX - NCERT Maths Exercise (7.1) Question 1: In quadrilateral ACBD, AC = AD and AB bisects A (See the given figure). Show that ABC ABD. What can you say about BC and BD? Solution 1: In ABC and ABD,
Class IX Chapter 7 Triangles Maths
Class IX Chapter 7 Triangles Maths 1: Exercise 7.1 Question In quadrilateral ACBD, AC = AD and AB bisects A (See the given figure). Show that ABC ABD. What can you say about BC and BD? In ABC and ABD,
Euclidean Geometry Proofs
Euclidean Geometry Proofs History Thales (600 BC) First to turn geometry into a logical discipline. Described as the first Greek philosopher and the father of geometry as a deductive study. Relied on rational
Computer Organization I. Lecture 13: Design of Combinational Logic Circuits
Computer Organization I Lecture 13: Design of Combinational Logic Circuits Overview The optimization of multiple-level circuits Mapping Technology Verification Objectives To know how to optimize the multiple-level
Higher Order Thinking Skill questions
Higher Order Thinking Skill questions TOPIC- Constructions (Class- X) 1. Draw a triangle ABC with sides BC = 6.3cm, AB = 5.2cm and ÐABC = 60. Then construct a triangle whose sides are times the corresponding
Reformulation of the Hadamard conjecture via Hurwitz-Radon word systems
Reformulation of the Hadamard conjecture via Hurwitz-Radon word systems Miklós Ujvári Abstract. The Hadamard conjecture (unsolved since 1867) states that there exists an orthogonal matrix with entries
REGIONAL MATHEMATICAL OLYMPIAD-2010
REGIONAL MATHEMATICAL OLYMPIAD-00 Time: 3 hrs December 05, 00 Instructions: Calculator (in any form) and protractors are not allowed. Rulers and compasses are allowed. Answer all the questions. Maximum
Nozha Directorate of Education Form : 2 nd Prep
Cairo Governorate Department : Maths Nozha Directorate of Education Form : 2 nd Prep Nozha Language Schools Geometry Revision Sheet Ismailia Road Branch Sheet ( 1) 1-Complete 1. In the parallelogram, each
Right Derivations on Semirings
International Mathematical Forum, Vol. 8, 2013, no. 32, 1569-1576 HIKARI Ltd, www.m-hikari.com http://dx.doi.org/10.12988/imf.2013.38150 Right Derivations on Semirings S. P. Nirmala Devi Department of
Parts Manual. EPIC II Critical Care Bed REF 2031
EPIC II Critical Care Bed REF 2031 Parts Manual For parts or technical assistance call: USA: 1-800-327-0770 2013/05 B.0 2031-109-006 REV B www.stryker.com Table of Contents English Product Labels... 4
Edison product catalog. Circuit Protection Products
Edison product catalog Circuit Protection Products Index Catalog Number Page : = ( & : = & : = & : = &* : = ( ( : = ( & % : = & % : = & : = & : = & : = : = ( & : = & : = & : = &* : = : = ) : = : = % :
arxiv: v1 [math.ra] 11 Aug 2010
![arxiv: v1 [math.ra] 11 Aug 2010](/thumbs/91/106787441.jpg "arxiv: v1 [math.ra] 11 Aug 2010")
ON THE DEFINITION OF QUASI-JORDAN ALGEBRA arxiv:1008.2009v1 [math.ra] 11 Aug 2010 MURRAY R. BREMNER Abstract. Velásquez and Felipe recently introduced quasi-jordan algebras based on the product a b = 1
CCE PR Revised & Un-Revised
D CCE PR Revised & Un-Revised 560 00 KARNATAKA SECONDARY EDUCATION EXAMINATION BOARD, MALLESWARAM, BANGALORE 560 00 08 S.S.L.C. EXAMINATION, JUNE, 08 :. 06. 08 ] MODEL ANSWERS : 8-K Date :. 06. 08 ] CODE
7.5 Proportionality Relationships
www.ck12.org Chapter 7. Similarity 7.5 Proportionality Relationships Learning Objectives Identify proportional segments when two sides of a triangle are cut by a segment parallel to the third side. Extend
Euclidean Geometry & Measurement
Euclidean Geometry & Measuerement Worksheet Compiled by : T Remias 2015 Page 1 WORKSHEET ON EUCLIDIAN GOEMETRY QUESTION 1 1.1 Complete the statements below by filling in the missing word(s) so that the
Triangle Congruence and Similarity Review. Show all work for full credit. 5. In the drawing, what is the measure of angle y?
Triangle Congruence and Similarity Review Score Name: Date: Show all work for full credit. 1. In a plane, lines that never meet are called. 5. In the drawing, what is the measure of angle y? A. parallel
CONGRUENCE OF TRIANGLES
Congruence of Triangles 11 CONGRUENCE OF TRIANGLES You might have observed that leaves of different trees have different shapes, but leaves of the same tree have almost the same shape. Although they may
Preliminary Mathematics
NORTH SYDNEY GIRLS HIGH SCHOOL 010 YEARLY EXAMINATION Preliminary Mathematics General Instructions Reading Time 5 minutes Working Time hours Write using black or blue pen Board-approved calculators may
Collisions Of SHA-0 and Reduced SHA-1
Collisions Of SHA-0 and Reduced SHA-1 Eli Biham, Rafi Chen Antoine Joux, Patrick Carribault, Christophe Lemuet, and William Jalby Presnted by: Nael Masalha OUTLINE Neutral bits Multi-block technique Multi-block
CHAPTER 5 A BLOCK CIPHER INVOLVING A KEY APPLIED ON BOTH THE SIDES OF THE PLAINTEXT
82 CHAPTER 5 A BLOCK CIPHER INVOLVING A KEY APPLIED ON BOTH THE SIDES OF THE PLAINTEXT 83 5.1 Introduction In a pioneering paper, Hill [5] developed a block cipher by using the modular arithmetic inverse
Data Mining Concepts & Techniques
Data Mining Concepts & Techniques Lecture No. 05 Sequential Pattern Mining Naeem Ahmed Email: naeemmahoto@gmail.com Department of Software Engineering Mehran Univeristy of Engineering and Technology Jamshoro