Modeling prion dynamics (In progress)
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1 Modeling prion dynamics (In progress) Peter Olofsson and Suzanne Sindi Trinity University and Brown University Mathematics Department Division of Applied Mathematics August 21, 2012
2 PRIONS Infectious agents composed of misfolded protein (no DNA or RNA).
3 PRIONS Infectious agents composed of misfolded protein (no DNA or RNA). Mad cow disease, Creutzfeldt Jakob disease.
4 PRIONS Infectious agents composed of misfolded protein (no DNA or RNA). Mad cow disease, Creutzfeldt Jakob disease. Studied in yeast (does no harm).
5 !"#$%&'(' 1,.#'0(''(*# Transmission Synthesis )*#+&,'(*# Conversion Fragmentation -,./0&#$.$(*# Figure: Yeast Prion Cycle. There are four steps essential for the persistence of the prion state: synthesis, conversion, fragmentation and transmission from mother to daughter cell.
6 !"#$%&'(' 1,.#'0(''(*# Transmission Synthesis )*#+&,'(*# Conversion Fragmentation -,./0&#$.$(*# Figure: Yeast Prion Cycle. There are four steps essential for the persistence of the prion state: synthesis, conversion, fragmentation and transmission from mother to daughter cell. (Note to Kimmel: Branching within branching!)
7 CURING CURVE: The fraction of cells that have prions as a function of time. Starts at 100%, declines toward 0%. Many prions initially means slower decline. One goal: estimate number of prions in initial cell from curing curve.
8 SOME PREVIOUS WORK: L.J. Byrne, D.J. Cole, B.S. Cox, M.S. Ridout, B.J.T. Morgan, and M.F. Tuite. The number and transmission of [PSI+] prion seeds (propagons) in the yeast Saccharomyces cerevisiae. PLoS One, 4(3):4670, DJ Cole, BJT Morgan, MS Ridout, LJ Byrne, and MF Tuite. Estimating the number of prions in yeast cells. Mathematical Medicine and Biology, 21(4):369, 2004.
9 SOME PREVIOUS WORK: L.J. Byrne, D.J. Cole, B.S. Cox, M.S. Ridout, B.J.T. Morgan, and M.F. Tuite. The number and transmission of [PSI+] prion seeds (propagons) in the yeast Saccharomyces cerevisiae. PLoS One, 4(3):4670, DJ Cole, BJT Morgan, MS Ridout, LJ Byrne, and MF Tuite. Estimating the number of prions in yeast cells. Mathematical Medicine and Biology, 21(4):369, No conversion (prions do not grow). Tends to underestimate initial number of prions since larger prions are more difficult to pass on to daughter.
10 DISCRETE MODEL: Binary splitting, no death. After splitting: one mother, one daughter.
11 DISCRETE MODEL: Binary splitting, no death. After splitting: one mother, one daughter. Z n = number of cells with prions in nth generation.
12 DISCRETE MODEL: Binary splitting, no death. After splitting: one mother, one daughter. Z n = number of cells with prions in nth generation. Fraction of cells with prions: P n = E[Z n] 2 n
13 DISCRETE MODEL: Binary splitting, no death. After splitting: one mother, one daughter. Z n = number of cells with prions in nth generation. Fraction of cells with prions: P n = E[Z n] 2 n A given prion is transmitted to the daughter cell with probability p < 0.5.
14 Cell in nth generation has ancestry of the type of d daughters and m mothers. MMDDM...MMDM
15 Cell in nth generation has ancestry of the type of d daughters and m mothers. MMDDM...MMDM Without prion growth: Initial prion present with probability p d (1 p) m.
16 Cell in nth generation has ancestry of the type of d daughters and m mothers. MMDDM...MMDM Without prion growth: Initial prion present with probability p d (1 p) m. With prion growth: easier to be in MDMMM than in MMMMD.
17 Cell in nth generation has ancestry of the type of d daughters and m mothers. MMDDM...MMDM Without prion growth: Initial prion present with probability p d (1 p) m. With prion growth: easier to be in MDMMM than in MMMMD. Prions grow one unit at a time according to a Poisson process with rate β.
18 Assume a critical size after which prions can no longer be transmitted to the daughter cell.
19 Assume a critical size after which prions can no longer be transmitted to the daughter cell. Initial cell is i units (conversion events) from critical size.
20 Assume a critical size after which prions can no longer be transmitted to the daughter cell. Initial cell is i units (conversion events) from critical size. Consider sequences in generation n where the final daughter is in position k and there is a total of l daughters. There are ( k 1 l 1 ) such sequences.
21 Assume a critical size after which prions can no longer be transmitted to the daughter cell. Initial cell is i units (conversion events) from critical size. Consider sequences in generation n where the final daughter is in position k and there is a total of l daughters. There are ( k 1 l 1 ) such sequences. Example: n = 5, k = 3, l = 2 : DMDMM, MDDMM
22 Assume a critical size after which prions can no longer be transmitted to the daughter cell. Initial cell is i units (conversion events) from critical size. Consider sequences in generation n where the final daughter is in position k and there is a total of l daughters. There are ( k 1 l 1 ) such sequences. Example: n = 5, k = 3, l = 2 : DMDMM, MDDMM Probability p nkl such a sequence has prions? Depends on critical generation G when initial prion gets too big. From G on, prion stays in mother.
23 Assume a critical size after which prions can no longer be transmitted to the daughter cell. Initial cell is i units (conversion events) from critical size. Consider sequences in generation n where the final daughter is in position k and there is a total of l daughters. There are ( k 1 l 1 ) such sequences. Example: n = 5, k = 3, l = 2 : DMDMM, MDDMM Probability p nkl such a sequence has prions? Depends on critical generation G when initial prion gets too big. From G on, prion stays in mother. If G < k, p nkl = 0 and if G = j k, p nkl = p l (1 p) j l.
24 Hence where p nkl = n 1 p l (1 p) j l P i (G = j) + p l (1 p) n l P i (G n) j=k P i (G = j) = H i (j + 1) H i (j) where H i is the distribution function for the gamma distribution with parameters i and β.
25 Now assume N i initial prions of size i. Conditional probability at least one is in given sequence: so that P N i nkl = 1 (1 p nkl) N i where ϕ is the pgf of N i. P nkl = 1 ϕ(1 p nkl )
26 All taken together: expected fraction of cells with prions is P n = 2 n [ n k=0 k l=0 ( ) ] k 1 (1 ϕ(1 p l 1 nkl ))
27 All taken together: expected fraction of cells with prions is P n = 2 n [ n k=0 k l=0 ( ) ] k 1 (1 ϕ(1 p l 1 nkl )) Obvious extension to many different i and N i : multivariate pgf s.
28 100 simulations, 5th and 95th percentiles (black), estimated curve (red), large β (fast growth) and small β (slow growth). Probability of Prion Aggregates Probability of Prion Aggregates
29 Initial number of prions n 0 = 209, our estimate n 0 = 191.8, disregarding prion growth n 0 = Probability of Prion Aggregates
30 CONTINUOUS MODEL: CMJ, not BH
31 CONTINUOUS MODEL: CMJ, not BH Newborn cell needs time T to grow and mature, produces first daughter cell at time D, then produces daughter cells at times D + M 1, D + M 1 + M 2,... Reproduction process ξ(dt) = δ D (dt) + N k=1 δ D+M1 + M k (dt) where N = total number of daughter cells (can practically assume N = ) [see Green (1981)].
32 CONTINUOUS MODEL: CMJ, not BH Newborn cell needs time T to grow and mature, produces first daughter cell at time D, then produces daughter cells at times D + M 1, D + M 1 + M 2,... Reproduction process ξ(dt) = δ D (dt) + N k=1 δ D+M1 + M k (dt) where N = total number of daughter cells (can practically assume N = ) [see Green (1981)]. Malthusian parameter determined by 0 ( e αt F D (dt) + e αt F M (dt) ) = 1 Expressions similar to but much more complicated than discrete case.
33 CONTINUOUS MODEL: CMJ, not BH Newborn cell needs time T to grow and mature, produces first daughter cell at time D, then produces daughter cells at times D + M 1, D + M 1 + M 2,... Reproduction process ξ(dt) = δ D (dt) + N k=1 δ D+M1 + M k (dt) where N = total number of daughter cells (can practically assume N = ) [see Green (1981)]. Malthusian parameter determined by 0 ( e αt F D (dt) + e αt F M (dt) ) = 1 Expressions similar to but much more complicated than discrete case.
34 where P(t) E[Z t] E[Y t ] E[Y t ] = 1 F A (t) + + n=1 n k=0 ( n 1 k 1 [( ) n 1 ( F A F n 1,k 1(t) F A F n,k(t)) k ) ( F A F n 1,k(t) F A F n,k(t)) ] and E[Z t ] = n n=0 k=0 k l=0 ( ) k 1 [1 ϕ(1 p l 1 nkl (t)))]
35 One detail: how does it start?
36 One detail: how does it start? Cole et al: Initial cell has excess life distribution, sampled from a renewal process. Pdf: f A (t) = q D 1 µ D (1 F D (t)) + q M 1 µ M (1 F M (t))
37 One detail: how does it start? Cole et al: Initial cell has excess life distribution, sampled from a renewal process. Pdf: f A (t) = q D 1 µ D (1 F D (t)) + q M 1 µ M (1 F M (t)) We: initial cell has stable age distribution, sampled from exponentially growing population. Pdf: f A (t) = α e αs (f D (s + t) + f M (s + t))ds 0 Note presence of Malthusian parameter α. Any practical relevance? Don t know.
38 Grant support: NIH grant 1 F32 GM (Sindi) NIH grant 1 R15 GM (O)
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