Shear Strength of. Charles Aubeny. Department of Civil Engineering Texas A&M University

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Shear Strength of Shallow Soils Charles Aubeny Associate Professor Department of Civil Engineering Texas A&M University

Issues 1. Relevant to practical problems Shallow slopes Organic soils Pipeline embedment 2. Technical difficulties Difficult to sample Not amenable to conventional strength tests 3. Perspectives Strength measurement Soil suction

Seafloor Pipelines Relevant Situations Shallow Slides Low Embankments

Difficulties in Measurement at Low Stress 1. Very soft (S u ~ 100 psf) difficult to sample 2 Limitations of testing equipment 2. Limitations of testing equipment σ vc > 600 psf for many devices

Evaluating Strength: Extended Mohr-Coulomb Criterion τ f = c + p tan φ + h m tan φ b Strength Suction τ f = shear strength c = effective cohesion p = net mechanical stress (σ -u a ) φ = mechanical stress friction angle h m = matric suction (u a -u w ) φ b = suction friction angle

Case Histories i 1. Organic soil deposits 2. Inorganic strength tests at low σ 3. Shallow slope failures

Sacramento-San Joaquin Delta Peat Deposits

Soil Profile Levee Fill - Sandy Upper Holocene - Loose sands, soft clays Holocene Organic - Peat Lower Holocene - Loose sands, soft clays Pleistocene - Dense sands, stiff clays

Sherman Island Soil Density

Sherman Island Pore Pressures

Sherman Island Effective Stress Profile

Undrained Strength Ratio, s u /σ v0 SHANSEP (Ladd, 1986) USR = s u /σ v0 = S (OCR) m OCR = over-consolidation ratio = σ p /σ v0 S = 0.22 Inorganic Soils (excl. high S t ) 0.25 +/- 0.05 Organic Soils (excl. peat) m = 0.8 Parameters independent of stress level

Measured Undrained Strength Ratio, DSS Sherman Island Cross Levee Study Brovold & Sisson (1995) Byron Tract Sherman Island Twitchell Island

Direct Correlation, s vs.σ u v0 Previous data supplemented by new tests in 2008

Conclusions from Peat Data Strength behavior linear Not normalizable due to intercept Undrained strength ratio tends to infinity Trend lines converge to a point (limited data for OC soil) Consistent w/previous data if strength intercept considered Physical source of intercept: fibers (?) Best fit equation: s u = s u0 + σ v0 S (OCR) m s u0 = strength intercept ~ 5.5 kpa S = 027 0.27 m = 0.8

Norwegian Geotechnical Institute (NGI) Investigations Lunne & Andersen (2008) Direct simple shear tests Inorganic soils Saturated Remolded (no cementation)

NGI Undrained Strength Ratio Data

Direct Correlation, s vs.σ u v0

Comments on NGI Data Strength behavior linear Not normalizable due to intercept Undrained strength ratio tends to infinity Trend lines converge to a point Consistent w/previous data if strength intercept considered Physical source of intercept: (?) Best fit equation: s u = s u0 + σ v0 S (OCR) m s u0 = strength intercept ~ 4.5 kpa S = 015 0.15 m = 0.8

Shallow Slope Failures

Beaumont Clay Slope Failures Kayyal and Wright (1991) Compacted fill, c =0 Age of fslopes 12-31 years Slope Angles β = 16-26 o from horizontal Depth of Slide Mass 0.6-1.5 meters 18 Failures Estimated Friction Angle φ = 25 o

Paris Clay Slope Failures Kayyal and Wright (1991) Compacted fill, c =0 Age of Slopes 14-1919 years Slope Angles β = 18-23 o from horizontal Depth of Slide Mass 0.6-3 meters 16 Failures Estimated Friction Angle φ = 25 o

Back- Analysis from Infinite Slope Analysis Aubeny & Lytton (2004) Critical elements of analysis: 1. Characterization of flow state 2. Pore pressure distribution ib ti 3. Shear-induced pore pressures

Infinite Slope Analysis: Flow State Uniform pore fluid pressure, u (negative) Non-uniform total head h = z + u/γ w Dynamic conditions: Flow parallel to slope Major destabilizing effect (failures observed on very flat slopes

Pore Pressure Distribution - Suction at Surface, u 0 unknown; to be back-calculated from analysis Hydrostatic Increase with Depth z z +

Stability Equation for Infinite Slope FS γ tan φ ' u tan φ ' γ tanββ γ H sinβcosββ β b 0 = 2/3a tanφ ' f Mechanical Stress Contribution Suction Contribution (u 0 < 0) Shear-Induced Pore Pressure Effect

Back-Calculated Suction and Dimensionless Time Factors at Failure for Shallow Slides in Beaumont Clays Case Back-Calculated Surface Suction, a f =0 Back-Calculated Surface Suction, a f =0.7 Time Factor at Failure,T T f 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 Best estimate of u w0 u w0 u w0 u w0 α = α = suction at surface: (kpa) (pf) (kpa) (pf) 0.044 m 2 /yr -6.5-5.1-2.6-2.6-6.8-3.2-10.1-2.7-7.7 77-3.1-7.8-8.5-3.5-3.8-4.7-2.4-6.1-3.8 1.8 1.7 1.4 1.4 1.8 1.5 2.0 1.4 19 1.9 1.5 1.9 1.9 1.6 16 1.6 1.7 1.4 1.8 1.6-14.7-13.3-7.1-8.7-15.5-8.8-21.7-7.4-15.4-7.3-18.4-19.4-9.3-10.3-10.3-6.2-13.0-10.3 2.2 2.1 1.9 1.9 2.2 2.0 2.3 1.9 22 2.2 1.9 2.3 2.3 2.0 20 2.0 2.0 1.8 2.1 2.0 0.76 0.88 2.79 1.29 0.67 1.15 0.44 1.66 109 1.09 2.54 0.38 0.54 0.81 059 0.59 1.05 2.35 1.47 0.93 0.126 m 2 /yr 2.25 2.61 8.32 3.85 2.01 3.44 1.31 4.95 325 3.25 7.56 1.15 1.61 2.42 177 1.77 3.12 7.00 4.38 2.78 Average -5.0 1.7-12.0 2.1 1.23 3.67 Std. 2.5 0.2 4.8 0.2 0.75 2.25 Dev. u 0 = 7.8 kpa 0

Back-Calculated Suction and Dimensionless Time Factors at Failure for Shallow Slides in Paris Clays Case Back-Calculated Surface Suction, a f =0 Back-Calculated Surface Suction, a f =0.7 Time Factor at Failure,T T f 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 u w0 u w0 u w0 u w0 α = α = Best estimate of (pf) (kpa) (pf) 0.044 0.126 m 2 /yr m 2 /yr suction at surface: (kpa) -4.9-7.5-10.8-8.9-16.0-8.8-8.9-13.2-6.2-6.4-2.1-6.4-13.2-13.2-4.9-6.4 1.7 1.9 2.0 2.0 2.2 2.0 2.0 2.1 1.8 1.8 1.3 1.8 2.1 21 2.1 1.7 1.8-12.7-16.5-26.9-21.3-37.2-18.3-21.3-27.5-15.9-14.9-5.8-14.9-27.5-27.5-12.7-14.9 2.1 2.2 2.4 2.3 2.6 2.3 2.3 2.4 2.2 2.2 1.8 2.2 2.4 24 2.4 2.1 2.2 0.62 0.48 0.15 0.27 0.10 0.66 0.27 0.28 0.38 0.60 2.32* 0.62 0.29 029 0.29 0.62 0.63 1.85 1.42 0.44 0.79 0.29 1.98 0.79 0.83 1.12 1.79 6.92* 1.89 0.88 088 0.88 1.85 1.89 u 0 = 12 kpa Average Std. Dev. -8.6 38 3.8 1.9 02 0.2-19.8 79 7.9 2.3 02 0.2 0.42 020 0.20 1.25 059 0.59 *Excluded from average.

Estimated Strength: Wetted Soils for Zero Applied Stress Beaumont Clays: s = 78kPa 0 u0 7.8 x tan 25 = 36kPa 3.6 Paris Clays: s u0 = 12 kpa x tan 25 0 = 5.6 kpa Note: NGI data showed s u0 = 4.5 kpa

Implications of Shallow Slope Studies Wetting of slope triggers failures Suction decreases as wetting occurs Suction does not trend to zero Lower limit of suction on order of 7-12 kpa Lower suction limit consistent with totally independent assessment of strength at low stress levels l measured by DSS

Conclusions Non-zero strength intercept in peat expected Non-zero intercept in inorganic soils also Lower bound strength & suction consistent USR approach not applicable at low stress SHANSEP still applicable if modified

Thank You!