6.01: Introduction to EECS 1 Week 6 October 15, 2009
|
|
- Eustace Neal
- 5 years ago
- Views:
Transcription
1 6.0: ntroducton to EECS Week 6 October 5, : ntroducton to EECS Crcuts The Crcut Abstracton Crcuts represent systems as connectons of component through whch currents (through arables) flow and across whch oltages (across arables) deelop. Week 6 October 5, 2009 The Crcut Abstracton Crcuts are mportant for two ery dfferent reasons: as physcal systems power (from generators and transformers to power lnes) electroncs (from cell phones to computers) as models of complex systems neurons bran cardoascular system hearng The Crcut Abstracton Crcuts are the bass of our enormously successful semconductor ndustry Dual-Core tanum 2 Pentum 4 Pentum Pentum Pentum tanum 2 tanum,000,000,000 00,000,000 0,000,000,000,000 00, , , year # of transstors The Crcut Abstracton Crcuts as models of complex systems: myelnated neuron. Model of Myelnated Nere Fber What s a Crcut? Crcuts are connectons of components through whch currents (through arables) flow and across whch oltages (across arables) deelop. _ nternode Node of Raner nternode Node of Raner nternode Dendrtc tree nternode Node of Raner Cell body Myelnated fber Axonal tree Fgure by MT OpenCourseWare.
2 6.0: ntroducton to EECS Week 6 October 5, 2009 Rules Goernng Flow Rule : Currents flow n loops. Example: flow of electrcal current through a flashlght Rules Goernng Flow Rule 2: Lke the flow of water, the flow of electrcal current (charged partcles) s ncompressble. Example: flow of water through a branchng pont 2 3 When the swtch s closed, electrcal current flows through the loop. The same amount of current flows nto the bulb (top path) and out of the bulb (bottom path). What comes n must go out. Here = 2 3. Krchoff s Current Law: the sum of the currents nto a node s zero. Rules Goernng Flow n electrcal crcuts, we represent current flow by arrows on lnes representng connectons (wres). Nodes Nodes are represented n crcut dagrams by lnes that connect crcut components. 2 The followng crcut has three components, each represented wth a box. = The dot represents a node whch represents a connecton of two or more segments. There are two nodes, each ndcated by a dot. The net current nto or out of each of these nodes s zero. Therefore 2 3 = 0. What s a Crcut? Crcuts are connectons of components through whch currents (through arables) flow and across whch oltages (across arables) deelop. Rules Goernng oltages oltages accumulate n loops. Example: the seres combnaton of two.5 batteres supples Krchoff s oltage Law: the sum of the oltages around a closed loop s zero. 2
3 6.0: ntroducton to EECS Week 6 October 5, 2009 Alternate Representaton: Node oltages Node oltages represent the oltage between each node n a crcut and an arbtrarly selected ground. e e e gnd Node oltages and component oltages are dfferent but equalent representatons of oltage. component oltages represent the oltages across components. node oltages represent the oltages n a crcut. Rules Goernng Components Each component s represented by a relatonshp between the oltage across the component to the current through the component. Examples: R = R 0 = 0 (regardless of ) 0 = 0 (regardless of ) Node-oltage-and-Component-Current (NCC) Method Combnng KCL, node oltages, and component equatons leads to the NCC method for solng crcuts: Assgn node oltage arables to eery node except ground (whose oltage s arbtrarly taken as zero). Assgn component current arables to eery component n the crcut. Wrte one consttute relaton for each component n terms of the component current arable and the component oltage, whch s the dfference between the node oltages at ts termnals. Express KCL at each node except ground n terms of the component currents. Sole the resultng equatons. Analyzng Smple Crcuts Analyzng smple crcuts s straghtforward. Ω The oltage source determnes the oltage across the resstor, =, so the current through the resstor s = /R = / = A. A Ω The current source determnes the current through the resstor, = A, so the oltage across the resstor s = R = =. What s the current through the resstor below? Ω A Common Patterns There are a number of common patterns that facltate desgn and analyss: seres resstances parallel resstances oltage dders current dders. A 2. 2A 3. 0A 4. cannot determne 5. none of the aboe 3
4 6.0: ntroducton to EECS Week 6 October 5, 2009 Seres Combnatons The seres combnaton of two resstors s equalent to a sngle resstor whose resstance s the sum of the two orgnal resstances. R R s Parallel Combnatons The parallel combnaton of two resstors s equalent to a sngle resstor whose conductance (/resstance) s the sum of the two orgnal conductances. R R p = R = R s = R = R p R s = R The resstance of a seres combnaton s always larger than ether of the orgnal resstances. = = R R p = R p R R R 2 R = R R R R 2 The resstance of a parallel combnaton s always smaller than ether of the orgnal resstances. oltage Dder Resstors n seres act as oltage dders. What s the equalent resstance of the followng crcut. R = R R = R = R 2 = = R Current Dder Resstors n parallel act as current dders. Fnd o. 2 = (R ) R 2 8 Ω 2 Ω 6 Ω o = R = R R = R R R = 2 = = R = R R = R R R 4
5 6.0: ntroducton to EECS Week 6 October 5, 2009 Loadng Addng (or changng the alue of) a component alters all of the oltages and currents n a crcut (except n degenerate cases). Consder dentcal lght bulbs connected n seres across a battery. What happens f we add thrd lght bulb? # #2 #3 Because the same current passes through both lght bulbs, they are equally brght. Closng the swtch wll make. bulb brghter 2. bulb 2 dmmer 3.. and bulbs, 2, & 3 equally brght 5. none of the aboe Loadng Loadng dd not occur n LT systems. Loadng Q: What s dfferent about a crcut? Example: addng H 2 has no effect on Y Y X H Y X H H 2 Y = H X regardless of H 2. Z L A: A new component generally alters the currents at the nodes to whch t connects. Bufferng Summary Effects of loadng can be dmnshed or elmnated wth a buffer. An deal buffer s an amplfer that senses the oltage at ts nput wthout drawng any current, and sets ts output oltage equal to the measured nput oltage. x L =0 y = x Crcuts represent systems as connectons of components through whch currents (through arables) flow and across whch oltages (across arables) deelop. There are a number of common patterns that facltate desgn and analyss: seres resstances parallel resstances oltage dders current dders Buffers elmnate loadng and thereby smplfy desgn and analyss. We wll dscuss how to use op-amps to make buffers n next lecture. 5
6 MT OpenCourseWare ntroducton to Electrcal Engneerng and Computer Scence Fall 2009 For nformaton about ctng these materals or our Terms of Use, st:
6.01: Introduction to EECS I Lecture 7 March 15, 2011
6.0: Introducton to EECS I Lecture 7 March 5, 20 6.0: Introducton to EECS I Crcuts The Crcut Abstracton Crcuts represent systems as connectons of elements through whch currents (through arables) flow and
More informationmatter consists, measured in coulombs (C) 1 C of charge requires electrons Law of conservation of charge: charge cannot be created or
Basc Concepts Oerew SI Prefxes Defntons: Current, Voltage, Power, & Energy Passe sgn conenton Crcut elements Ideal s Portland State Unersty ECE 221 Basc Concepts Ver. 1.24 1 Crcut Analyss: Introducton
More informationELECTRONICS. EE 42/100 Lecture 4: Resistive Networks and Nodal Analysis. Rev B 1/25/2012 (9:49PM) Prof. Ali M. Niknejad
A. M. Nknejad Unversty of Calforna, Berkeley EE 100 / 42 Lecture 4 p. 1/14 EE 42/100 Lecture 4: Resstve Networks and Nodal Analyss ELECTRONICS Rev B 1/25/2012 (9:49PM) Prof. Al M. Nknejad Unversty of Calforna,
More informationEnergy Storage Elements: Capacitors and Inductors
CHAPTER 6 Energy Storage Elements: Capactors and Inductors To ths pont n our study of electronc crcuts, tme has not been mportant. The analyss and desgns we hae performed so far hae been statc, and all
More informationCircuit Variables. Unit: volt (V = J/C)
Crcut Varables Scentfc nestgaton of statc electrcty was done n late 700 s and Coulomb s credted wth most of the dscoeres. He found that electrc charges hae two attrbutes: amount and polarty. There are
More informationEE215 FUNDAMENTALS OF ELECTRICAL ENGINEERING
EE215 FUNDAMENTALS OF ELECTRICAL ENGINEERING TaChang Chen Unersty of Washngton, Bothell Sprng 2010 EE215 1 WEEK 8 FIRST ORDER CIRCUIT RESPONSE May 21 st, 2010 EE215 2 1 QUESTIONS TO ANSWER Frst order crcuts
More informationCollege of Engineering Department of Electronics and Communication Engineering. Test 1 With Model Answer
Name: Student D Number: Secton Number: 01/0/03/04 A/B Lecturer: Dr Jamaludn/ Dr Jehana Ermy/ Dr Azn Wat Table Number: College of Engneerng Department of Electroncs and Communcaton Engneerng Test 1 Wth
More informationG = G 1 + G 2 + G 3 G 2 +G 3 G1 G2 G3. Network (a) Network (b) Network (c) Network (d)
Massachusetts Insttute of Technology Department of Electrcal Engneerng and Computer Scence 6.002 í Electronc Crcuts Homework 2 Soluton Handout F98023 Exercse 21: Determne the conductance of each network
More informationLinearity. If kx is applied to the element, the output must be ky. kx ky. 2. additivity property. x 1 y 1, x 2 y 2
Lnearty An element s sad to be lnear f t satsfes homogenety (scalng) property and addte (superposton) property. 1. homogenety property Let x be the nput and y be the output of an element. x y If kx s appled
More informationWeek 11: Differential Amplifiers
ELE 0A Electronc rcuts Week : Dfferental Amplfers Lecture - Large sgnal analyss Topcs to coer A analyss Half-crcut analyss eadng Assgnment: hap 5.-5.8 of Jaeger and Blalock or hap 7. - 7.3, of Sedra and
More informationCircuits Op-Amp. Interaction of Circuit Elements. Quick Check How does closing the switch affect V o and I o?
Crcuts Op-Amp ENGG1015 1 st Semester, 01 Interactn f Crcut Elements Crcut desgn s cmplcated by nteractns amng the elements. Addng an element changes vltages & currents thrughut crcut. Example: clsng a
More informationTUTORIAL PROBLEMS. E.1 KCL, KVL, Power and Energy. Q.1 Determine the current i in the following circuit. All units in VAΩ,,
196 E TUTORIAL PROBLEMS E.1 KCL, KVL, Power and Energy Q.1 Determne the current n the followng crcut. 3 5 3 8 9 6 5 Appendx E Tutoral Problems 197 Q. Determne the current and the oltage n the followng
More informationMassachusetts Institute of Technology Department of Electrical Engineering and Computer Science Circuits and Electronics Spring 2001
Massachusetts Insttute of Technology Department of Electrcal Engneerng and Computer Scence Read Chapters 11 through 12. 6.002 Crcuts and Electroncs Sprng 2001 Homework #5 Handout S01031 Issued: 3/8/2001
More informationCopyright 2004 by Oxford University Press, Inc.
JT as an Amplfer &a Swtch, Large Sgnal Operaton, Graphcal Analyss, JT at D, asng JT, Small Sgnal Operaton Model, Hybrd P-Model, TModel. Lecture # 7 1 Drecton of urrent Flow & Operaton for Amplfer Applcaton
More informationFE REVIEW OPERATIONAL AMPLIFIERS (OP-AMPS)( ) 8/25/2010
FE REVEW OPERATONAL AMPLFERS (OP-AMPS)( ) 1 The Op-amp 2 An op-amp has two nputs and one output. Note the op-amp below. The termnal labeled l wth the (-) sgn s the nvertng nput and the nput labeled wth
More informationMAE140 Linear Circuits (for non-electrical engs)
MAE4 Lnear Crcuts (for non-electrcal engs) Topcs coered Crcut analyss technques Krchoff s Laws KVL, KCL Nodal and Mesh Analyss Théenn and Norton Equalent Crcuts Resste crcuts, RLC crcuts Steady-state and
More informationSelected Student Solutions for Chapter 2
/3/003 Assessment Prolems Selected Student Solutons for Chapter. Frst note that we know the current through all elements n the crcut except the 6 kw resstor (the current n the three elements to the left
More informationPhysics 114 Exam 2 Spring Name:
Physcs 114 Exam Sprng 013 Name: For gradng purposes (do not wrte here): Queston 1. 1... 3. 3. Problem Answer each of the followng questons. Ponts for each queston are ndcated n red wth the amount beng
More informationPhysics 114 Exam 2 Fall 2014 Solutions. Name:
Physcs 114 Exam Fall 014 Name: For gradng purposes (do not wrte here): Queston 1. 1... 3. 3. Problem Answer each of the followng questons. Ponts for each queston are ndcated n red. Unless otherwse ndcated,
More informationMAE140 - Linear Circuits - Winter 16 Final, March 16, 2016
ME140 - Lnear rcuts - Wnter 16 Fnal, March 16, 2016 Instructons () The exam s open book. You may use your class notes and textbook. You may use a hand calculator wth no communcaton capabltes. () You have
More informationKey component in Operational Amplifiers
Key component n Operatonal Amplfers Objectve of Lecture Descrbe how dependent voltage and current sources functon. Chapter.6 Electrcal Engneerng: Prncples and Applcatons Chapter.6 Fundamentals of Electrc
More information55:141 Advanced Circuit Techniques Two-Port Theory
55:4 Adanced Crcut Technques Two-Port Theory Materal: Lecture Notes A. Kruger 55:4: Adanced Crcut Technques The Unersty of Iowa, 205 Two-Port Theory, Slde Two-Port Networks Note, the BJT s all are hghly
More informationMAE140 - Linear Circuits - Winter 16 Midterm, February 5
Instructons ME140 - Lnear Crcuts - Wnter 16 Mdterm, February 5 () Ths exam s open book. You may use whatever wrtten materals you choose, ncludng your class notes and textbook. You may use a hand calculator
More informationFEEDBACK AMPLIFIERS. v i or v s v 0
FEEDBCK MPLIFIERS Feedback n mplers FEEDBCK IS THE PROCESS OF FEEDING FRCTION OF OUTPUT ENERGY (VOLTGE OR CURRENT) BCK TO THE INPUT CIRCUIT. THE CIRCUIT EMPLOYED FOR THIS PURPOSE IS CLLED FEEDBCK NETWORK.
More informationINDUCTANCE. RC Cicuits vs LR Circuits
INDUTANE R cuts vs LR rcuts R rcut hargng (battery s connected): (1/ )q + (R)dq/ dt LR rcut = (R) + (L)d/ dt q = e -t/ R ) = / R(1 - e -(R/ L)t ) q ncreases from 0 to = dq/ dt decreases from / R to 0 Dschargng
More informationi I (I + i) 3/27/2006 Circuits ( F.Robilliard) 1
4V I 2V (I + ) 0 0 --- 3V 1 2 4Ω 6Ω 3Ω 3/27/2006 Crcuts ( F.obllard) 1 Introducton: Electrcal crcuts are ubqutous n the modern world, and t s dffcult to oerstate ther mportance. They range from smple drect
More informationMAE140 - Linear Circuits - Fall 13 Midterm, October 31
Instructons ME140 - Lnear Crcuts - Fall 13 Mdterm, October 31 () Ths exam s open book. You may use whatever wrtten materals you choose, ncludng your class notes and textbook. You may use a hand calculator
More informationBoise State University Department of Electrical and Computer Engineering ECE 212L Circuit Analysis and Design Lab
Bose State Unersty Department of Electrcal and omputer Engneerng EE 1L rcut Analyss and Desgn Lab Experment #8: The Integratng and Dfferentatng Op-Amp rcuts 1 Objectes The objectes of ths laboratory experment
More informationDiode. Current HmAL Voltage HVL Simplified equivalent circuit. V γ. Reverse bias. Forward bias. Designation: Symbol:
Dode Materal: Desgnaton: Symbol: Poste Current flow: ptype ntype Anode Cathode Smplfed equalent crcut Ideal dode Current HmAL 0 8 6 4 2 Smplfed model 0.5.5 2 V γ eal dode Voltage HVL V γ closed open V
More informationLecture #4 Capacitors and Inductors Energy Stored in C and L Equivalent Circuits Thevenin Norton
EES ntro. electroncs for S Sprng 003 Lecture : 0/03/03 A.R. Neureuther Verson Date 0/0/03 EES ntroducton to Electroncs for omputer Scence Andrew R. Neureuther Lecture # apactors and nductors Energy Stored
More informationMAE140 Linear Circuits (for non-electrical engs)
MAE4 Lnear Crcuts (for non-electrcal engs) Topcs coered Crcut analyss technques Krchoff s Laws KVL, KCL Nodal and Mesh Analyss Théenn and Norton Equalent Crcuts Resste crcuts, RLC crcuts Steady-state and
More informationUnit 1. Current and Voltage U 1 VOLTAGE AND CURRENT. Circuit Basics KVL, KCL, Ohm's Law LED Outputs Buttons/Switch Inputs. Current / Voltage Analogy
..2 nt Crcut Bascs KVL, KCL, Ohm's Law LED Outputs Buttons/Swtch Inputs VOLTAGE AND CRRENT..4 Current and Voltage Current / Voltage Analogy Charge s measured n unts of Coulombs Current Amount of charge
More informationI. INTRODUCTION. There are two other circuit elements that we will use and are special cases of the above elements. They are:
I. INTRODUCTION 1.1 Crcut Theory Fundamentals In ths course we study crcuts wth non-lnear elements or deces (dodes and transstors). We wll use crcut theory tools to analyze these crcuts. Snce some of tools
More informationI. INTRODUCTION. 1.1 Circuit Theory Fundamentals
I. INTRODUCTION 1.1 Crcut Theory Fundamentals Crcut theory s an approxmaton to Maxwell s electromagnetc equatons n order to smplfy analyss of complcated crcuts. A crcut s made of seeral elements (boxes
More informationE40M Device Models, Resistors, Voltage and Current Sources, Diodes, Solar Cells. M. Horowitz, J. Plummer, R. Howe 1
E40M Devce Models, Resstors, Voltage and Current Sources, Dodes, Solar Cells M. Horowtz, J. Plummer, R. Howe 1 Understandng the Solar Charger Lab Project #1 We need to understand how: 1. Current, voltage
More informationCOLLEGE OF ENGINEERING PUTRAJAYA CAMPUS FINAL EXAMINATION SPECIAL SEMESTER 2013 / 2014
OLLEGE OF ENGNEENG PUTAJAYA AMPUS FNAL EXAMNATON SPEAL SEMESTE 03 / 04 POGAMME SUBJET ODE SUBJET : Bachelor of Electrcal & Electroncs Engneerng (Honours) Bachelor of Electrcal Power Engneerng (Honours)
More informationIntroduction to circuit analysis. Classification of Materials
Introducton to crcut analyss OUTLINE Electrcal quanttes Charge Current Voltage Power The deal basc crcut element Sgn conventons Current versus voltage (I-V) graph Readng: 1.2, 1.3,1.6 Lecture 2, Slde 1
More informationELG 2135 ELECTRONICS I SECOND CHAPTER: OPERATIONAL AMPLIFIERS
ELG 35 ELECTONICS I SECOND CHAPTE: OPEATIONAL AMPLIFIES Sesson Wnter 003 Dr. M. YAGOUB Second Chapter: Operatonal amplfers II - _ After reewng the basc aspects of amplfers, we wll ntroduce a crcut representng
More informationV V. This calculation is repeated now for each current I.
Page1 Page2 The power supply oltage V = +5 olts and the load resstor R = 1 k. For the range of collector bas currents, I = 0.5 ma, 1 ma, 2.5 ma, 4 ma and 4.5 ma, determne the correspondng collector-to-emtter
More information55:141 Advanced Circuit Techniques Two-Port Theory
55:4 Adanced Crcut Technques Two-Port Theory Materal: Lecture Notes A. Kruger 55:4: Adanced Crcut Technques The Unersty of Iowa, 03 Two-Port Theory, Slde What Are Two-Ports? Basc dea: replace a complex
More informationCollege of Engineering Department of Electronics and Communication Engineering. Test 2
Name: Student D Number: Secton Number: 01/0/03/04 A/B Lecturer: Dr Jamaludn/ Dr Azn Wat/ Dr Jehana Ermy/ Prof Md Zan Table Number: ollege of Engneerng Department of Electroncs and ommuncaton Engneerng
More informationBoise State University Department of Electrical and Computer Engineering ECE 212L Circuit Analysis and Design Lab
Bose State Unersty Department of Electrcal and omputer Engneerng EE 1L rcut Analyss and Desgn Lab Experment #8: The Integratng and Dfferentatng Op-Amp rcuts 1 Objectes The objectes of ths laboratory experment
More informationPhysics 4B. A positive value is obtained, so the current is counterclockwise around the circuit.
Physcs 4B Solutons to Chapter 7 HW Chapter 7: Questons:, 8, 0 Problems:,,, 45, 48,,, 7, 9 Queston 7- (a) no (b) yes (c) all te Queston 7-8 0 μc Queston 7-0, c;, a;, d; 4, b Problem 7- (a) Let be the current
More informationEE C245 ME C218 Introduction to MEMS Design
EE C45 ME C8 Introducton to MEM Desgn Fall 7 Prof. Clark T.C. Nguyen Dept. of Electrcal Engneerng & Computer cences Unersty of Calforna at Berkeley Berkeley, C 947 Dscusson: eew of Op mps EE C45: Introducton
More informationSections begin this week. Cancelled Sections: Th Labs begin this week. Attend your only second lab slot this week.
Announcements Sectons begn ths week Cancelled Sectons: Th 122. Labs begn ths week. Attend your only second lab slot ths week. Cancelled labs: ThF 25. Please check your Lab secton. Homework #1 onlne Due
More informationPHYSICS - CLUTCH CH 28: INDUCTION AND INDUCTANCE.
!! www.clutchprep.com CONCEPT: ELECTROMAGNETIC INDUCTION A col of wre wth a VOLTAGE across each end wll have a current n t - Wre doesn t HAVE to have voltage source, voltage can be INDUCED V Common ways
More informationDriving your LED s. LED Driver. The question then is: how do we use this square wave to turn on and turn off the LED?
0//00 rng your LE.doc / rng your LE s As we hae preously learned, n optcal communcaton crcuts, a dgtal sgnal wth a frequency n the tens or hundreds of khz s used to ampltude modulate (on and off) the emssons
More information3.2 Terminal Characteristics of Junction Diodes (pp )
/9/008 secton3_termnal_characterstcs_of_juncton_odes.doc /6 3. Termnal Characterstcs of Juncton odes (pp.47-53) A Juncton ode I.E., A real dode! Smlar to an deal dode, ts crcut symbol s: HO: The Juncton
More informationFormulation of Circuit Equations
ECE 570 Sesson 2 IC 752E Computer Aded Engneerng for Integrated Crcuts Formulaton of Crcut Equatons Bascs of crcut modelng 1. Notaton 2. Crcut elements 3. Krchoff laws 4. ableau formulaton 5. Modfed nodal
More informationAnnouncements. Lecture #2
Announcements Lectures wll be n 4 LeConte begnnng Frday 8/29 Addtonal dscusson TA Denns Chang (Sectons 101, 105) Offce hours: Mo 2-3 PM; Th 5-6 PM Lab sectons begn Tuesday 9/2 Read Experment #1 onlne Download
More informationTransfer Characteristic
Eeld-Effect Transstors (FETs 3.3 The CMS Common-Source Amplfer Transfer Characterstc Electronc Crcuts, Dept. of Elec. Eng., The Chnese Unersty of Hong Kong, Prof. K.-L. Wu Lesson 8&9 Eeld-Effect Transstors
More informationGraphical Analysis of a BJT Amplifier
4/6/2011 A Graphcal Analyss of a BJT Amplfer lecture 1/18 Graphcal Analyss of a BJT Amplfer onsder agan ths smple BJT amplfer: ( t) = + ( t) O O o B + We note that for ths amplfer, the output oltage s
More informationELCT 503: Semiconductors. Fall 2014
EL503 Semconductors Fall 2014 Lecture 09: BJ rcut Analyss Dr. Hassan Mostafa د. حسن مصطفى hmostafa@aucegypt.edu EL 503: Semconductors ntroducton npn transstor pnp transstor EL 503: Semconductors ntroducton
More informationElectrical Circuits 2.1 INTRODUCTION CHAPTER
CHAPTE Electrcal Crcuts. INTODUCTION In ths chapter, we brefly revew the three types of basc passve electrcal elements: resstor, nductor and capactor. esstance Elements: Ohm s Law: The voltage drop across
More informationMAE140 - Linear Circuits - Fall 10 Midterm, October 28
M140 - Lnear rcuts - Fall 10 Mdterm, October 28 nstructons () Ths exam s open book. You may use whatever wrtten materals you choose, ncludng your class notes and textbook. You may use a hand calculator
More informationPHY2049 Exam 2 solutions Fall 2016 Solution:
PHY2049 Exam 2 solutons Fall 2016 General strategy: Fnd two resstors, one par at a tme, that are connected ether n SERIES or n PARALLEL; replace these two resstors wth one of an equvalent resstance. Now
More informationVI. Transistor Amplifiers
VI. Transstor Amplfers 6. Introducton In ths secton we wll use the transstor small-sgnal model to analyze and desgn transstor amplfers. There are two ssues that we need to dscuss frst: ) What are the mportant
More informationPHYSICS - CLUTCH 1E CH 28: INDUCTION AND INDUCTANCE.
!! www.clutchprep.com CONCEPT: ELECTROMAGNETIC INDUCTION A col of wre wth a VOLTAGE across each end wll have a current n t - Wre doesn t HAVE to have voltage source, voltage can be INDUCED V Common ways
More informationCHAPTER 13. Exercises. E13.1 The emitter current is given by the Shockley equation:
HPT 3 xercses 3. The emtter current s gen by the Shockley equaton: S exp VT For operaton wth, we hae exp >> S >>, and we can wrte VT S exp VT Solng for, we hae 3. 0 6ln 78.4 mv 0 0.784 5 4.86 V VT ln 4
More informationDepartment of Electrical and Computer Engineering FEEDBACK AMPLIFIERS
Department o Electrcal and Computer Engneerng UNIT I EII FEEDBCK MPLIFIES porton the output sgnal s ed back to the nput o the ampler s called Feedback mpler. Feedback Concept: block dagram o an ampler
More informationKirchhoff second rule
Krchhoff second rule Close a battery on a resstor: smplest crcut! = When the current flows n a resstor there s a voltage drop = How much current flows n the crcut? Ohm s law: Krchhoff s second law: Around
More informationChapter 6 Electrical Systems and Electromechanical Systems
ME 43 Systems Dynamcs & Control Chapter 6: Electrcal Systems and Electromechancal Systems Chapter 6 Electrcal Systems and Electromechancal Systems 6. INTODUCTION A. Bazoune The majorty of engneerng systems
More informationECE 320 Energy Conversion and Power Electronics Dr. Tim Hogan. Chapter 1: Introduction and Three Phase Power
ECE 3 Energy Conerson and Power Electroncs Dr. Tm Hogan Chapter : ntroducton and Three Phase Power. eew of Basc Crcut Analyss Defntons: Node - Electrcal juncton between two or more deces. Loop - Closed
More informationDC Circuits. Crossing the emf in this direction +ΔV
DC Crcuts Delverng a steady flow of electrc charge to a crcut requres an emf devce such as a battery, solar cell or electrc generator for example. mf stands for electromotve force, but an emf devce transforms
More informationEE 2006 Electric Circuit Analysis Spring January 23, 2015 Lecture 02
EE 2006 Electrc Crcut Analyss Sprng 2015 January 23, 2015 Lecture 02 1 Lab 1 Dgtal Multmeter Lab nstructons Aalable onlne Prnt out and read before Lab MWAH 391, 4:00 7:00 pm, next Monday or Wednesday (January
More informationχ x B E (c) Figure 2.1.1: (a) a material particle in a body, (b) a place in space, (c) a configuration of the body
Secton.. Moton.. The Materal Body and Moton hyscal materals n the real world are modeled usng an abstract mathematcal entty called a body. Ths body conssts of an nfnte number of materal partcles. Shown
More informationPhysics 2102 Spring 2007 Lecture 10 Current and Resistance
esstance Is Futle! Physcs 0 Sprng 007 Jonathan Dowlng Physcs 0 Sprng 007 Lecture 0 Current and esstance Georg Smon Ohm (789-854) What are we gong to learn? A road map lectrc charge lectrc force on other
More information55:041 Electronic Circuits
55:04 Electronc Crcuts Feedback & Stablty Sectons of Chapter 2. Kruger Feedback & Stablty Confguraton of Feedback mplfer Negate feedback β s the feedback transfer functon S o S S o o S S o f S S S S fb
More information8.022 (E&M) Lecture 8
8.0 (E&M) Lecture 8 Topcs: Electromotve force Crcuts and Krchhoff s rules 1 Average: 59, MS: 16 Quz 1: thoughts Last year average: 64 test slghtly harder than average Problem 1 had some subtletes math
More informationCircuits II EE221. Instructor: Kevin D. Donohue. Instantaneous, Average, RMS, and Apparent Power, and, Maximum Power Transfer, and Power Factors
Crcuts II EE1 Unt 3 Instructor: Ken D. Donohue Instantaneous, Aerage, RMS, and Apparent Power, and, Maxmum Power pp ransfer, and Power Factors Power Defntons/Unts: Work s n unts of newton-meters or joules
More informationCoupling Element and Coupled circuits. Coupled inductor Ideal transformer Controlled sources
Couplng Element and Coupled crcuts Coupled nductor Ideal transformer Controlled sources Couplng Element and Coupled crcuts Coupled elements hae more that one branch and branch oltages or branch currents
More informationEE 2006 Electric Circuit Analysis Fall September 04, 2014 Lecture 02
EE 2006 Electrc Crcut Analyss Fall 2014 September 04, 2014 Lecture 02 1 For Your Informaton Course Webpage http://www.d.umn.edu/~jngba/electrc_crcut_analyss_(ee_2006).html You can fnd on the webpage: Lecture:
More information(b) i(t) for t 0. (c) υ 1 (t) and υ 2 (t) for t 0. Solution: υ 2 (0 ) = I 0 R 1 = = 10 V. υ 1 (0 ) = 0. (Given).
Problem 5.37 Pror to t =, capactor C 1 n the crcut of Fg. P5.37 was uncharged. For I = 5 ma, R 1 = 2 kω, = 5 kω, C 1 = 3 µf, and C 2 = 6 µf, determne: (a) The equvalent crcut nvolvng the capactors for
More informationChapter 6. Operational Amplifier. inputs can be defined as the average of the sum of the two signals.
6 Operatonal mpler Chapter 6 Operatonal mpler CC Symbol: nput nput Output EE () Non-nvertng termnal, () nvertng termnal nput mpedance : Few mega (ery hgh), Output mpedance : Less than (ery low) Derental
More informationSurface Charge and Resistors
Surface Charge and Resstors Just after connecton: E may be the same everywhere nav naue thn thck na na thn thck ue ue After steady state s reached: thn thck na thn thck na thn thck ue thn ue thck E thn
More informationLecture 5: Operational Amplifiers and Op Amp Circuits
Lecture 5: peratonal mplers and p mp Crcuts Gu-Yeon We Dson o Engneerng and ppled Scences Harard Unersty guyeon@eecs.harard.edu We erew eadng S&S: Chapter Supplemental eadng Background rmed wth our crcut
More informationWeek3, Chapter 4. Position and Displacement. Motion in Two Dimensions. Instantaneous Velocity. Average Velocity
Week3, Chapter 4 Moton n Two Dmensons Lecture Quz A partcle confned to moton along the x axs moves wth constant acceleraton from x =.0 m to x = 8.0 m durng a 1-s tme nterval. The velocty of the partcle
More informationECSE Linearity Superposition Principle Superposition Example Dependent Sources. 10 kω. 30 V 5 ma. 6 kω. 2 kω
S-00 Lnearty Superposton Prncple Superposton xample Dependent Sources Lecture 4. sawyes@rp.edu www.rp.edu/~sawyes 0 kω 6 kω 8 V 0 V 5 ma 4 Nodes Voltage Sources Ref Unknown Node Voltage, kω If hae multple
More informationR. W. Erickson. Department of Electrical, Computer, and Energy Engineering University of Colorado, Boulder
R. W. Erckson Department of Electrcal, Computer, and Energy Engneerng Unersty of Colorado, Boulder 3.5. Example: ncluson of semconductor conducton losses n the boost conerter model Boost conerter example
More informationAdvanced Circuits Topics - Part 1 by Dr. Colton (Fall 2017)
Advanced rcuts Topcs - Part by Dr. olton (Fall 07) Part : Some thngs you should already know from Physcs 0 and 45 These are all thngs that you should have learned n Physcs 0 and/or 45. Ths secton s organzed
More informationElectrical Engineering Department Network Lab.
Electrcal Engneerng Department Network Lab. Objecte: - Experment on -port Network: Negate Impedance Conerter To fnd the frequency response of a smple Negate Impedance Conerter Theory: Negate Impedance
More informationThe optimal delay of the second test is therefore approximately 210 hours earlier than =2.
THE IEC 61508 FORMULAS 223 The optmal delay of the second test s therefore approxmately 210 hours earler than =2. 8.4 The IEC 61508 Formulas IEC 61508-6 provdes approxmaton formulas for the PF for smple
More informationVoltage and Current Laws
CHAPTER 3 Voltage and Current Laws KEY CONCEPTS INTRODUCTION In Chap. 2 we were ntroduced to ndependent voltage and current sources, dependent sources, and resstors. We dscovered that dependent sources
More information55:041 Electronic Circuits
55:04 Electronc Crcuts Feedback & Stablty Sectons of Chapter 2. Kruger Feedback & Stablty Confguraton of Feedback mplfer S o S ε S o ( S β S ) o Negate feedback S S o + β β s the feedback transfer functon
More informationPhysics 1202: Lecture 11 Today s Agenda
Physcs 122: Lecture 11 Today s Agenda Announcements: Team problems start ths Thursday Team 1: Hend Ouda, Mke Glnsk, Stephane Auger Team 2: Analese Bruder, Krsten Dean, Alson Smth Offce hours: Monday 2:3-3:3
More informationFE REVIEW OPERATIONAL AMPLIFIERS (OP-AMPS)
FE EIEW OPEATIONAL AMPLIFIES (OPAMPS) 1 The Opamp An opamp has two nputs and one output. Note the opamp below. The termnal labeled wth the () sgn s the nvertng nput and the nput labeled wth the () sgn
More informationTitle Chapters HW Due date. Lab Due date 8 Sept Mon 2 Kirchoff s Laws NO LAB. 9 Sept Tue NO LAB 10 Sept Wed 3 Power
Schedule Date Day Class No. Ttle Chapters HW Due date Lab Due date 8 Sept Mon Krchoff s Laws..3 NO LAB Exam 9 Sept Tue NO LAB 10 Sept Wed 3 Power.4.5 11 Sept Thu NO LAB 1 Sept Fr Rectaton HW 1 13 Sept
More informationElectrical Circuits II (ECE233b)
Electrcal Crcuts (ECE33b SteadyState Power Analyss Anests Dounas The Unersty of Western Ontaro Faculty of Engneerng Scence SteadyState Power Analyss (t AC crcut: The steady state oltage and current can
More informationDEMO #8 - GAUSSIAN ELIMINATION USING MATHEMATICA. 1. Matrices in Mathematica
demo8.nb 1 DEMO #8 - GAUSSIAN ELIMINATION USING MATHEMATICA Obectves: - defne matrces n Mathematca - format the output of matrces - appl lnear algebra to solve a real problem - Use Mathematca to perform
More informationELE B7 Power Systems Engineering. Power Flow- Introduction
ELE B7 Power Systems Engneerng Power Flow- Introducton Introducton to Load Flow Analyss The power flow s the backbone of the power system operaton, analyss and desgn. It s necessary for plannng, operaton,
More informationCircuit Theory I
16.1 Crcut Theory I Tngshu Hu Offce: Ball Hall 45 Phone: 4374, Fax: 37 Emal: tngshu_hu@uml.edu Offce Hours: MW: 1am-1pm http://faculty.uml.edu/thu/ http://faculty.uml.edu/thu/16.1/materal.htm http://faculty.uml.edu/thu/16.1/lecture_note.htm
More informationComplex Numbers, Signals, and Circuits
Complex Numbers, Sgnals, and Crcuts 3 August, 009 Complex Numbers: a Revew Suppose we have a complex number z = x jy. To convert to polar form, we need to know the magntude of z and the phase of z. z =
More information5.6 Small-Signal Operation and Models
3/16/2011 secton 5_6 Small Sgnal Operaton and Models 1/2 5.6 Small-Sgnal Operaton and Models Readng Assgnment: 443-458 Now let s examne how we use BJTs to construct amplfers! The frst mportant desgn rule
More informationElectricity and Magnetism Lecture 07 - Physics 121 Current, Resistance, DC Circuits: Y&F Chapter 25 Sect. 1-5 Kirchhoff s Laws: Y&F Chapter 26 Sect.
Electrcty and Magnetsm Lecture 07 - Physcs Current, esstance, DC Crcuts: Y&F Chapter 5 Sect. -5 Krchhoff s Laws: Y&F Chapter 6 Sect. Crcuts and Currents Electrc Current Current Densty J Drft Speed esstance,
More informationLinear Feature Engineering 11
Lnear Feature Engneerng 11 2 Least-Squares 2.1 Smple least-squares Consder the followng dataset. We have a bunch of nputs x and correspondng outputs y. The partcular values n ths dataset are x y 0.23 0.19
More informationNote: Please use the actual date you accessed this material in your citation.
MIT OpenCourseWare http://ocw.mt.edu 6.13/ESD.13J Electromagnetcs and Applcatons, Fall 5 Please use the followng ctaton format: Markus Zahn, Erch Ippen, and Davd Staeln, 6.13/ESD.13J Electromagnetcs and
More informationFormulas for the Determinant
page 224 224 CHAPTER 3 Determnants e t te t e 2t 38 A = e t 2te t e 2t e t te t 2e 2t 39 If 123 A = 345, 456 compute the matrx product A adj(a) What can you conclude about det(a)? For Problems 40 43, use
More informationCircuit Theory I
16.1 Crcut Theory I Tngshu Hu Offce: Ball Hall 45 Phone: 4374, Fax: 37 Emal: tngshu@gmal.com Offce Hours: 9-1am, 11am-1pm, Monday, Wednesday http://faculty.uml.edu/thu/ http://faculty.uml.edu/thu/16.1/materal.htm
More information4.1 The Ideal Diode. Reading Assignment: pp Before we get started with ideal diodes, let s first recall linear device behavior!
1/25/2012 secton3_1the_ideal_ode 1/2 4.1 The Ideal ode Readng Assgnment: pp.165-172 Before we get started wth deal dodes, let s frst recall lnear dece behaor! HO: LINEAR EVICE BEHAVIOR Now, the deal dode
More informationThe Decibel and its Usage
The Decbel and ts Usage Consder a two-stage amlfer system, as shown n Fg.. Each amlfer rodes an ncrease of the sgnal ower. Ths effect s referred to as the ower gan,, of the amlfer. Ths means that the sgnal
More information