= v 2. a c. = G m m 1 2. F g G = Review 5: Gravitation and Two-Dimensional Motion

Size: px
Start display at page:

Download "= v 2. a c. = G m m 1 2. F g G = Review 5: Gravitation and Two-Dimensional Motion"

Transcription

1 Review 5: Gavitation and Two-Dimensional Motion Review 5 Gavitation and Two-Dimensional Motion 2 d = 1 2 at F = ma 1. A busy waitess slides a plate of apple pie alon a counte to a huny custome sittin nea the end of the counte. The custome is not payin attention, and the plate slides off the counte hoizontally at 0.84 m/s. The counte is 1.38 m hih. a. How lon does it take the plate to fall to the floo? b. How fa fom the base of the counte does the plate hit the floo? 2. The Moon evolves aound Eath in a cicula obit with a adius of m. It takes 27.3 days fo the Moon to complete one obit aound Eath. What is the centipetal acceleation of the Moon? 3. A clown ides a small ca at a speed of 15 km/h alon a cicula path with a adius of 3.5 m. a. What is the manitude of the centipetal foce on a 0.18 k ball held by the clown? b. At the point whee the ca is headed due noth, the clown thows the ball vetically upwad with a speed of 5 m/s elative to the movin ca. To whee must a second clown un to catch the ball the same distance above the ound as it was thown? 4. A 0.45 k ball is attached to the end of a cod of lenth 1.4 m. The ball is whiled in a cicula path in a hoizontal plane. The cod can withstand a maximum tension of 57.0 N befoe it beaks. What is the maximum speed the ball can have without the cod beakin? net a c = v 2 = G m m 1 2 G = N m 2 k 2 5. A mable olls off the ede of a table that is m hih. The mable is movin at a speed of m/s at the moment that it leaves the ede of the table. How fa fom the table does the mable land? 6. A ca movin at m/s ounds a bend in the oad. The bend is semicicula and has a adius of 60 m. What is the centipetal acceleation of the ca? 7. A town has a lae clock on the hall in the town squae. The clock has hands that show the hous, minutes, and seconds. A fly is sittin on the tip of the hand that shows the seconds. If the lenth of the hand is 1.2 m, what is the fly s centipetal acceleation? 8. A ock is tied to a stin and spun in a hoizontal cicle. The stin is 1.8 m lon and the ock has an acceleation of 3.4 m/s 2. What is the tanential velocity of the ock? 9. The mass of Eath is k, the mass of the Moon is k, and the mean distance of the Moon fom the cente of Eath is km. Use these data to calculate the manitude of the avitational foce exeted by Eath on the Moon. 10. Two identical bowlin balls ae placed 1.00 m apat. The avitational foce between the bowlin balls is N. Find the mass of a bowlin ball.

2 Review 5: Gavitation and Two-Dimensional Motion 11. A plane dops a escue capsule fom an altitude of 8500 m. a. How lon does it take fo the capsule to fall to Eath, assumin ai esistance is neliible? b. If the plane is tavelin with a hoizontal speed of 483 km/h when the capsule is eleased, what is the hoizontal distance between the point at which the capsule is eleased and the point at which the capsule stikes the ound? 12. A satellite is placed in a cicula obit 100 km above Eath s suface. Eath s mass is k and its aveae adius is m. a. What is the speed of the satellite? b. How many minutes does it take the satellite to complete one obit? 13. The asteoid Vesta has a mass of k and an aveae adius of 510 km. a. What is the acceleation due to avity at its suface? b. How much would a 95 k astonaut weih at the suface of Vesta? 14. The mass of Eath is k and the mass of the Sun is 330,000 times eate than the mass of Eath. If the cente of Eath is, on aveae, m fom the cente of the Sun, calculate the manitude of the avitational foce the Sun exets on Eath. 15. Two metal sphees, each weihin 24 k ae placed 0.05 m apat. Calculate the manitude of the avitational foce the two sphees exet on each othe. 16. A ca and a tuck ae tavelin side by side on the hihway. The ca has a mass of k and the tuck has a mass of k. If the cas ae sepaated by 2.1 m, find the foce of avitational attaction between the ca and the tuck. 17. A 5 k mass weihs 8.1 N on the suface of the Moon. If the adius of the Moon is 1737 km, what is the mass of the Moon? 19. Acceleation due to avity on Eath s suface is 9.80 m/s 2. Thus, a 1.00 k mass weihs 9.80 N on the suface of Eath. If the adius of Eath was cut exactly in half but the mass of Eath emained unchaned, how much would a 1.00 k mass weih on the suface of Eath?

3 Review 5: Gavitation and Two-Dimensional Motion 1a s 1b. Δd = v 2( 1.38 m) ( 0.53 s) Δd = 0.84 m/s Δd = 0.45 m days = s Δd 2π 2π m s 1022 m/s m/s m m/s 2 3a. 15 km/h = 4.17 m/s F = mv2 ( 0.18 k) 4.17 m/s F = 3.5 m F = 0.89 N 2 3b. It will take 1 s fo the ball to etun so it will o 4.17 m F = mv2 F m ( 57 N) 1.4 m 0.45 k 13.3 m/s 0.39 s Δd = v 2( m) ( 0.39 s) Δd = m/s Δd = m m/s 60 m 2.7 m/s 2 Δd 2π 60 s 2π 1.2 m m/s m/s 1.2 m m/s 2

4 Review 5: Gavitation and Two-Dimensional Motion a. a 1.8 m 3.4 m/s m/s m 1 m 2 2 F= N m 2 /k 2 ( k) ( k) ( m) 2 F = N 2 m = F2 G m = ( N) 1.00 m G m = 6.8 k 41.6 s 2( 8500 m) 11b. 483 km/h = 134 m/s Δd = v Δd = 134 m/s 2 ( 41.6 m/s) Δd = 5588 m 12a. F c = F G 12b. 13a. mv 2 = GMm 2 GM G( k) m m 7840 m/s Δd Δd v 2π v 2π m m 7840 m/s 5190 s 86 min = GM 2 = G k m 2 = m/s 2 13b. = m 14. = ( 95 k) m/s 2 = 7.3 N m 1 m 2 2 ( k) ( ) ( k) ( m) 2 F= N m 2 /k 2 F = N

5 Review 5: Gavitation and Two-Dimensional Motion ( 24 k) 24 k 0.05 m F = N 2 2 ( 1370 k) 9920 k 2.1 m F = N 2 M = F2 Gm m 2 M = 8.1 N G 5 k M = k 18. If the adius was half, the foce would incease by a facto of 4, thus a 1.00 k mass would weih 39.2 N

Extra notes for circular motion: Circular motion : v keeps changing, maybe both speed and

Extra notes for circular motion: Circular motion : v keeps changing, maybe both speed and Exta notes fo cicula motion: Cicula motion : v keeps changing, maybe both speed and diection ae changing. At least v diection is changing. Hence a 0. Acceleation NEEDED to stay on cicula obit: a cp v /,

More information

Chapter 5: Uniform Circular Motion

Chapter 5: Uniform Circular Motion Chapte 5: Unifom Cicula Motion Motion at constant speed in a cicle Centipetal acceleation Banked cuves Obital motion Weightlessness, atificial gavity Vetical cicula motion Centipetal Foce Acceleation towad

More information

Gravitation. AP/Honors Physics 1 Mr. Velazquez

Gravitation. AP/Honors Physics 1 Mr. Velazquez Gavitation AP/Honos Physics 1 M. Velazquez Newton s Law of Gavitation Newton was the fist to make the connection between objects falling on Eath and the motion of the planets To illustate this connection

More information

Ch 13 Universal Gravitation

Ch 13 Universal Gravitation Ch 13 Univesal Gavitation Ch 13 Univesal Gavitation Why do celestial objects move the way they do? Keple (1561-1630) Tycho Bahe s assistant, analyzed celestial motion mathematically Galileo (1564-1642)

More information

Objective Notes Summary

Objective Notes Summary Objective Notes Summay An object moving in unifom cicula motion has constant speed but not constant velocity because the diection is changing. The velocity vecto in tangent to the cicle, the acceleation

More information

Recap. Centripetal acceleration: v r. a = m/s 2 (towards center of curvature)

Recap. Centripetal acceleration: v r. a = m/s 2 (towards center of curvature) a = c v 2 Recap Centipetal acceleation: m/s 2 (towads cente of cuvatue) A centipetal foce F c is equied to keep a body in cicula motion: This foce poduces centipetal acceleation that continuously changes

More information

Unit 6 Test Review Gravitation & Oscillation Chapters 13 & 15

Unit 6 Test Review Gravitation & Oscillation Chapters 13 & 15 A.P. Physics C Unit 6 Test Review Gavitation & Oscillation Chaptes 13 & 15 * In studying fo you test, make sue to study this eview sheet along with you quizzes and homewok assignments. Multiple Choice

More information

Lecture 52. Dynamics - Variable Acceleration

Lecture 52. Dynamics - Variable Acceleration Dynamics - Vaiable Acceleation Lectue 5 Example. The acceleation due to avity at a point outside the eath is invesely popotional to the squae of the distance x fom the cente, i.e., ẍ = k x. Nelectin ai

More information

Physics 201 Homework 4

Physics 201 Homework 4 Physics 201 Homewok 4 Jan 30, 2013 1. Thee is a cleve kitchen gadget fo dying lettuce leaves afte you wash them. 19 m/s 2 It consists of a cylindical containe mounted so that it can be otated about its

More information

CHAPTER 5: Circular Motion; Gravitation

CHAPTER 5: Circular Motion; Gravitation CHAPER 5: Cicula Motion; Gavitation Solution Guide to WebAssign Pobles 5.1 [1] (a) Find the centipetal acceleation fo Eq. 5-1.. a R v ( 1.5 s) 1.10 1.4 s (b) he net hoizontal foce is causing the centipetal

More information

Physics 107 TUTORIAL ASSIGNMENT #8

Physics 107 TUTORIAL ASSIGNMENT #8 Physics 07 TUTORIAL ASSIGNMENT #8 Cutnell & Johnson, 7 th edition Chapte 8: Poblems 5,, 3, 39, 76 Chapte 9: Poblems 9, 0, 4, 5, 6 Chapte 8 5 Inteactive Solution 8.5 povides a model fo solving this type

More information

Chapter 13: Gravitation

Chapter 13: Gravitation v m m F G Chapte 13: Gavitation The foce that makes an apple fall is the same foce that holds moon in obit. Newton s law of gavitation: Evey paticle attacts any othe paticle with a gavitation foce given

More information

DYNAMICS OF UNIFORM CIRCULAR MOTION

DYNAMICS OF UNIFORM CIRCULAR MOTION Chapte 5 Dynamics of Unifom Cicula Motion Chapte 5 DYNAMICS OF UNIFOM CICULA MOTION PEVIEW An object which is moing in a cicula path with a constant speed is said to be in unifom cicula motion. Fo an object

More information

Chap 5. Circular Motion: Gravitation

Chap 5. Circular Motion: Gravitation Chap 5. Cicula Motion: Gavitation Sec. 5.1 - Unifom Cicula Motion A body moves in unifom cicula motion, if the magnitude of the velocity vecto is constant and the diection changes at evey point and is

More information

Physics 101 Lecture 6 Circular Motion

Physics 101 Lecture 6 Circular Motion Physics 101 Lectue 6 Cicula Motion Assist. Pof. D. Ali ÖVGÜN EMU Physics Depatment www.aovgun.com Equilibium, Example 1 q What is the smallest value of the foce F such that the.0-kg block will not slide

More information

Chapter 13 Gravitation

Chapter 13 Gravitation Chapte 13 Gavitation In this chapte we will exploe the following topics: -Newton s law of gavitation, which descibes the attactive foce between two point masses and its application to extended objects

More information

m1 m2 M 2 = M -1 L 3 T -2

m1 m2 M 2 = M -1 L 3 T -2 GAVITATION Newton s Univesal law of gavitation. Evey paticle of matte in this univese attacts evey othe paticle with a foce which vaies diectly as the poduct of thei masses and invesely as the squae of

More information

= 4 3 π( m) 3 (5480 kg m 3 ) = kg.

= 4 3 π( m) 3 (5480 kg m 3 ) = kg. CHAPTER 11 THE GRAVITATIONAL FIELD Newton s Law of Gavitation m 1 m A foce of attaction occus between two masses given by Newton s Law of Gavitation Inetial mass and gavitational mass Gavitational potential

More information

10. Force is inversely proportional to distance between the centers squared. R 4 = F 16 E 11.

10. Force is inversely proportional to distance between the centers squared. R 4 = F 16 E 11. NSWRS - P Physics Multiple hoice Pactice Gavitation Solution nswe 1. m mv Obital speed is found fom setting which gives v whee M is the object being obited. Notice that satellite mass does not affect obital

More information

Between any two masses, there exists a mutual attractive force.

Between any two masses, there exists a mutual attractive force. YEAR 12 PHYSICS: GRAVITATION PAST EXAM QUESTIONS Name: QUESTION 1 (1995 EXAM) (a) State Newton s Univesal Law of Gavitation in wods Between any two masses, thee exists a mutual attactive foce. This foce

More information

OSCILLATIONS AND GRAVITATION

OSCILLATIONS AND GRAVITATION 1. SIMPLE HARMONIC MOTION Simple hamonic motion is any motion that is equivalent to a single component of unifom cicula motion. In this situation the velocity is always geatest in the middle of the motion,

More information

Physics 2001 Problem Set 5 Solutions

Physics 2001 Problem Set 5 Solutions Physics 2001 Poblem Set 5 Solutions Jeff Kissel Octobe 16, 2006 1. A puck attached to a sting undegoes cicula motion on an ai table. If the sting beaks at the point indicated in the figue, which path (A,

More information

Chapter 5. Uniform Circular Motion. a c =v 2 /r

Chapter 5. Uniform Circular Motion. a c =v 2 /r Chapte 5 Unifom Cicula Motion a c =v 2 / Unifom cicula motion: Motion in a cicula path with constant speed s v 1) Speed and peiod Peiod, T: time fo one evolution Speed is elated to peiod: Path fo one evolution:

More information

Potential Energy and Conservation of Energy

Potential Energy and Conservation of Energy Potential Enegy and Consevation of Enegy Consevative Foces Definition: Consevative Foce If the wok done by a foce in moving an object fom an initial point to a final point is independent of the path (A

More information

- 5 - TEST 1R. This is the repeat version of TEST 1, which was held during Session.

- 5 - TEST 1R. This is the repeat version of TEST 1, which was held during Session. - 5 - TEST 1R This is the epeat vesion of TEST 1, which was held duing Session. This epeat test should be attempted by those students who missed Test 1, o who wish to impove thei mak in Test 1. IF YOU

More information

06 - ROTATIONAL MOTION Page 1 ( Answers at the end of all questions )

06 - ROTATIONAL MOTION Page 1 ( Answers at the end of all questions ) 06 - ROTATIONAL MOTION Page ) A body A of mass M while falling vetically downwads unde gavity beaks into two pats, a body B of mass ( / ) M and a body C of mass ( / ) M. The cente of mass of bodies B and

More information

Unit 6 Practice Test. Which vector diagram correctly shows the change in velocity Δv of the mass during this time? (1) (1) A. Energy KE.

Unit 6 Practice Test. Which vector diagram correctly shows the change in velocity Δv of the mass during this time? (1) (1) A. Energy KE. Unit 6 actice Test 1. Which one of the following gaphs best epesents the aiation of the kinetic enegy, KE, and of the gaitational potential enegy, GE, of an obiting satellite with its distance fom the

More information

Physics 1114: Unit 5 Hand-out Homework (Answers)

Physics 1114: Unit 5 Hand-out Homework (Answers) Physics 1114: Unit 5 Hand-out Homewok (Answes) Poblem set 1 1. The flywheel on an expeimental bus is otating at 420 RPM (evolutions pe minute). To find (a) the angula velocity in ad/s (adians/second),

More information

Physics Fall Mechanics, Thermodynamics, Waves, Fluids. Lecture 6: motion in two and three dimensions III. Slide 6-1

Physics Fall Mechanics, Thermodynamics, Waves, Fluids. Lecture 6: motion in two and three dimensions III. Slide 6-1 Physics 1501 Fall 2008 Mechanics, Themodynamics, Waves, Fluids Lectue 6: motion in two and thee dimensions III Slide 6-1 Recap: elative motion An object moves with velocity v elative to one fame of efeence.

More information

( ) Tutorial 1 Practice, page (a) Given: d = 324 m or r = 162 m; F c = F g Required: v. Analysis: F c. = mv2 ; F g = mg. F c.

( ) Tutorial 1 Practice, page (a) Given: d = 324 m or r = 162 m; F c = F g Required: v. Analysis: F c. = mv2 ; F g = mg. F c. Section 3.4: Rotatin Fames of Refeence Mini Investiation: Foucault Pendulum, pae 128 Answes may vay. Sample answes: A. The otation does not affect the pendulum mass. Fom ou fame of efeence, the mass swins

More information

Hoizontal Cicula Motion 1. A paticle of mass m is tied to a light sting and otated with a speed v along a cicula path of adius. If T is tension in the sting and mg is gavitational foce on the paticle then,

More information

2013 Checkpoints Chapter 7 GRAVITY

2013 Checkpoints Chapter 7 GRAVITY 0 Checkpoints Chapte 7 GAVIY Question 64 o do this question you must et an equation that has both and, whee is the obital adius and is the peiod. You can use Keple s Law, which is; constant. his is a vey

More information

PS113 Chapter 5 Dynamics of Uniform Circular Motion

PS113 Chapter 5 Dynamics of Uniform Circular Motion PS113 Chapte 5 Dynamics of Unifom Cicula Motion 1 Unifom cicula motion Unifom cicula motion is the motion of an object taveling at a constant (unifom) speed on a cicula path. The peiod T is the time equied

More information

Physics 4A Chapter 8: Dynamics II Motion in a Plane

Physics 4A Chapter 8: Dynamics II Motion in a Plane Physics 4A Chapte 8: Dynamics II Motion in a Plane Conceptual Questions and Example Poblems fom Chapte 8 Conceptual Question 8.5 The figue below shows two balls of equal mass moving in vetical cicles.

More information

F g. = G mm. m 1. = 7.0 kg m 2. = 5.5 kg r = 0.60 m G = N m 2 kg 2 = = N

F g. = G mm. m 1. = 7.0 kg m 2. = 5.5 kg r = 0.60 m G = N m 2 kg 2 = = N Chapte answes Heinemann Physics 4e Section. Woked example: Ty youself.. GRAVITATIONAL ATTRACTION BETWEEN SMALL OBJECTS Two bowling balls ae sitting next to each othe on a shelf so that the centes of the

More information

SPH4U Unit 6.3 Gravitational Potential Energy Page 1 of 9

SPH4U Unit 6.3 Gravitational Potential Energy Page 1 of 9 SPH4 nit 6.3 Gavitational Potential negy Page of Notes Physics ool box he gavitational potential enegy of a syste of two (spheical) asses is diectly popotional to the poduct of thei asses, and invesely

More information

ω = θ θ o = θ θ = s r v = rω

ω = θ θ o = θ θ = s r v = rω Unifom Cicula Motion Unifom cicula motion is the motion of an object taveling at a constant(unifom) speed in a cicula path. Fist we must define the angula displacement and angula velocity The angula displacement

More information

Escape Velocity. GMm ] B

Escape Velocity. GMm ] B 1 PHY2048 Mach 31, 2006 Escape Velocity Newton s law of gavity: F G = Gm 1m 2 2, whee G = 667 10 11 N m 2 /kg 2 2 3 10 10 N m 2 /kg 2 is Newton s Gavitational Constant Useful facts: R E = 6 10 6 m M E

More information

Physics 111 Lecture 5 Circular Motion

Physics 111 Lecture 5 Circular Motion Physics 111 Lectue 5 Cicula Motion D. Ali ÖVGÜN EMU Physics Depatment www.aovgun.com Multiple Objects q A block of mass m1 on a ough, hoizontal suface is connected to a ball of mass m by a lightweight

More information

Uniform Circular Motion

Uniform Circular Motion Unifom Cicula Motion constant speed Pick a point in the objects motion... What diection is the velocity? HINT Think about what diection the object would tavel if the sting wee cut Unifom Cicula Motion

More information

From Newton to Einstein. Mid-Term Test, 12a.m. Thur. 13 th Nov Duration: 50 minutes. There are 20 marks in Section A and 30 in Section B.

From Newton to Einstein. Mid-Term Test, 12a.m. Thur. 13 th Nov Duration: 50 minutes. There are 20 marks in Section A and 30 in Section B. Fom Newton to Einstein Mid-Tem Test, a.m. Thu. 3 th Nov. 008 Duation: 50 minutes. Thee ae 0 maks in Section A and 30 in Section B. Use g = 0 ms in numeical calculations. You ma use the following epessions

More information

Orbits. Newton suggested that an object could be put into orbit if it were launched from a high hill at a high speed

Orbits. Newton suggested that an object could be put into orbit if it were launched from a high hill at a high speed Satellites & Obits Obits Newton suggested that an object could be put into obit if it wee launched fom a high hill at a high speed If the launch speed was high enough, the object would fall aound Eath

More information

AP Physics 1 - Circular Motion and Gravitation Practice Test (Multiple Choice Section) Answer Section

AP Physics 1 - Circular Motion and Gravitation Practice Test (Multiple Choice Section) Answer Section AP Physics 1 - Cicula Motion and Gaitation Pactice est (Multiple Choice Section) Answe Section MULIPLE CHOICE 1. B he centipetal foce must be fiction since, lacking any fiction, the coin would slip off.

More information

r ˆr F = Section 2: Newton s Law of Gravitation m 2 m 1 Consider two masses and, separated by distance Gravitational force on due to is

r ˆr F = Section 2: Newton s Law of Gravitation m 2 m 1 Consider two masses and, separated by distance Gravitational force on due to is Section : Newton s Law of Gavitation In 1686 Isaac Newton published his Univesal Law of Gavitation. This explained avity as a foce of attaction between all atte in the Univese, causin e.. apples to fall

More information

Universal Gravitation

Universal Gravitation Chapte 1 Univesal Gavitation Pactice Poblem Solutions Student Textbook page 580 1. Conceptualize the Poblem - The law of univesal gavitation applies to this poblem. The gavitational foce, F g, between

More information

DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS

DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS DEVIL PHYSICS THE BADDEST CLASS ON CAMPUS IB PHYSICS LSN 10-: MOTION IN A GRAVITATIONAL FIELD Questions Fom Reading Activity? Gavity Waves? Essential Idea: Simila appoaches can be taken in analyzing electical

More information

Unit 6 Practice Test. Which vector diagram correctly shows the change in velocity Δv of the mass during this time? (1) (1) A. Energy KE.

Unit 6 Practice Test. Which vector diagram correctly shows the change in velocity Δv of the mass during this time? (1) (1) A. Energy KE. Unit 6 actice Test 1. Which one of the following gaphs best epesents the aiation of the kinetic enegy, KE, and of the gaitational potential enegy, GE, of an obiting satellite with its distance fom the

More information

Relative motion (Translating axes)

Relative motion (Translating axes) Relative motion (Tanslating axes) Paticle to be studied This topic Moving obseve (Refeence) Fome study Obseve (no motion) bsolute motion Relative motion If motion of the efeence is known, absolute motion

More information

c) (6) Assuming the tires do not skid, what coefficient of static friction between tires and pavement is needed?

c) (6) Assuming the tires do not skid, what coefficient of static friction between tires and pavement is needed? Geneal Physics I Exam 2 - Chs. 4,5,6 - Foces, Cicula Motion, Enegy Oct. 10, 2012 Name Rec. Inst. Rec. Time Fo full cedit, make you wok clea to the gade. Show fomulas used, essential steps, and esults with

More information

Physics: Work & Energy Beyond Earth Guided Inquiry

Physics: Work & Energy Beyond Earth Guided Inquiry Physics: Wok & Enegy Beyond Eath Guided Inquiy Elliptical Obits Keple s Fist Law states that all planets move in an elliptical path aound the Sun. This concept can be extended to celestial bodies beyond

More information

Midterm Exam #2, Part A

Midterm Exam #2, Part A Physics 151 Mach 17, 2006 Midtem Exam #2, Pat A Roste No.: Scoe: Exam time limit: 50 minutes. You may use calculatos and both sides of ONE sheet of notes, handwitten only. Closed book; no collaboation.

More information

1) Consider a particle moving with constant speed that experiences no net force. What path must this particle be taking?

1) Consider a particle moving with constant speed that experiences no net force. What path must this particle be taking? Chapte 5 Test Cicula Motion and Gavitation 1) Conside a paticle moving with constant speed that expeiences no net foce. What path must this paticle be taking? A) It is moving in a paabola. B) It is moving

More information

kg 2 ) 1.9!10 27 kg = Gm 1

kg 2 ) 1.9!10 27 kg = Gm 1 Section 6.1: Newtonian Gavitation Tutoial 1 Pactice, page 93 1. Given: 1.0 10 0 kg; m 3.0 10 0 kg;. 10 9 N; G 6.67 10 11 N m /kg Requied: Analysis: G m ; G m G m Solution: G m N m 6.67!10 11 kg ) 1.0!100

More information

HW Solutions # MIT - Prof. Please study example 12.5 "from the earth to the moon". 2GmA v esc

HW Solutions # MIT - Prof. Please study example 12.5 from the earth to the moon. 2GmA v esc HW Solutions # 11-8.01 MIT - Pof. Kowalski Univesal Gavity. 1) 12.23 Escaping Fom Asteoid Please study example 12.5 "fom the eath to the moon". a) The escape velocity deived in the example (fom enegy consevation)

More information

Quiz 6--Work, Gravitation, Circular Motion, Torque. (60 pts available, 50 points possible)

Quiz 6--Work, Gravitation, Circular Motion, Torque. (60 pts available, 50 points possible) Name: Class: Date: ID: A Quiz 6--Wok, Gavitation, Cicula Motion, Toque. (60 pts available, 50 points possible) Multiple Choice, 2 point each Identify the choice that best completes the statement o answes

More information

Kepler's 1 st Law by Newton

Kepler's 1 st Law by Newton Astonom 10 Section 1 MWF 1500-1550 134 Astonom Building This Class (Lectue 7): Gavitation Net Class: Theo of Planeta Motion HW # Due Fida! Missed nd planetaium date. (onl 5 left), including tonight Stadial

More information

1. A stone falls from a platform 18 m high. When will it hit the ground? (a) 1.74 s (b) 1.83 s (c) 1.92 s (d) 2.01 s

1. A stone falls from a platform 18 m high. When will it hit the ground? (a) 1.74 s (b) 1.83 s (c) 1.92 s (d) 2.01 s 1. A stone falls fom a platfom 18 m high. When will it hit the gound? (a) 1.74 s (b) 1.83 s (c) 1.9 s (d).01 s Constant acceleation D = v 0 t + ½ a t. Which, if any, of these foces causes the otation of

More information

PHYSICS NOTES GRAVITATION

PHYSICS NOTES GRAVITATION GRAVITATION Newton s law of gavitation The law states that evey paticle of matte in the univese attacts evey othe paticle with a foce which is diectly popotional to the poduct of thei masses and invesely

More information

Physics 231 Lecture 17

Physics 231 Lecture 17 Physics 31 Lectue 17 Main points of today s lectue: Centipetal acceleation: a c = a c t Rotational motion definitions: Δω Δω α =, α = limδ t 0 Δt Δt Δ s= Δ θ;t = ω;at = α Rotational kinematics equations:

More information

1121 T Question 1

1121 T Question 1 1121 T1 2008 Question 1 ( aks) You ae cycling, on a long staight path, at a constant speed of 6.0.s 1. Anothe cyclist passes you, tavelling on the sae path in the sae diection as you, at a constant speed

More information

ROTATORY MOTION HORIZONTAL AND VERTICAL CIRCULAR MOTION

ROTATORY MOTION HORIZONTAL AND VERTICAL CIRCULAR MOTION ROTATORY MOTION HORIZONTAL AND VERTICAL CIRCULAR MOTION POINTS TO REMEMBER 1. Tanslatoy motion: Evey point in the body follows the path of its peceding one with same velocity including the cente of mass..

More information

Lecture 1a: Satellite Orbits

Lecture 1a: Satellite Orbits Lectue 1a: Satellite Obits Outline 1. Newton s Laws of Motion 2. Newton s Law of Univesal Gavitation 3. Calculating satellite obital paametes (assuming cicula motion) Scala & Vectos Scala: a physical quantity

More information

Uniform Circular Motion

Uniform Circular Motion Unifom Cicula Motion Have you eve idden on the amusement pak ide shown below? As it spins you feel as though you ae being pessed tightly against the wall. The ide then begins to tilt but you emain glued

More information

Version 001 Gravitation ramadoss (171) 1. I) On Earth, X experiences twice the gravitational

Version 001 Gravitation ramadoss (171) 1. I) On Earth, X experiences twice the gravitational Vesion 001 Gavitation amadoss (171) 1 This pint-out should have 108 questions. Multiple-choice questions may continue on the next column o pae find all choices befoe answein. Do 10 poblems pe day AP B

More information

Chap13. Universal Gravitation

Chap13. Universal Gravitation Chap13. Uniesal Gaitation Leel : AP Physics Instucto : Kim 13.1 Newton s Law of Uniesal Gaitation - Fomula fo Newton s Law of Gaitation F g = G m 1m 2 2 F21 m1 F12 12 m2 - m 1, m 2 is the mass of the object,

More information

PHYSICS 220. Lecture 08. Textbook Sections Lecture 8 Purdue University, Physics 220 1

PHYSICS 220. Lecture 08. Textbook Sections Lecture 8 Purdue University, Physics 220 1 PHYSICS 0 Lectue 08 Cicula Motion Textbook Sections 5.3 5.5 Lectue 8 Pudue Univesity, Physics 0 1 Oveview Last Lectue Cicula Motion θ angula position adians ω angula velocity adians/second α angula acceleation

More information

b) (5) What average force magnitude was applied by the students working together?

b) (5) What average force magnitude was applied by the students working together? Geneal Physics I Exam 3 - Chs. 7,8,9 - Momentum, Rotation, Equilibium Nov. 3, 2010 Name Rec. Inst. Rec. Time Fo full cedit, make you wok clea to the gade. Show fomulas used, essential steps, and esults

More information

Circular-Rotational Motion Mock Exam. Instructions: (92 points) Answer the following questions. SHOW ALL OF YOUR WORK.

Circular-Rotational Motion Mock Exam. Instructions: (92 points) Answer the following questions. SHOW ALL OF YOUR WORK. AP Physics C Sping, 2017 Cicula-Rotational Motion Mock Exam Name: Answe Key M. Leonad Instuctions: (92 points) Answe the following questions. SHOW ALL OF YOUR WORK. ( ) 1. A stuntman dives a motocycle

More information

Chapter 5. really hard to start the object moving and then, once it starts moving, you don t have to push as hard to keep it moving.

Chapter 5. really hard to start the object moving and then, once it starts moving, you don t have to push as hard to keep it moving. Chapte 5 Fiction When an object is in motion it is usually in contact with a viscous mateial (wate o ai) o some othe suface. So fa, we have assumed that moving objects don t inteact with thei suoundings

More information

Unit 4 Circular Motion and Centripetal Force

Unit 4 Circular Motion and Centripetal Force Name: Unit 4 Cicula Motion and Centipetal Foce H: Gading: Show all wok, keeping it neat and oganized. Show equations used and include all units. Vocabulay Peiod: the time it takes fo one complete evolution

More information

7 Circular Motion. 7-1 Centripetal Acceleration and Force. Period, Frequency, and Speed. Vocabulary

7 Circular Motion. 7-1 Centripetal Acceleration and Force. Period, Frequency, and Speed. Vocabulary 7 Cicula Motion 7-1 Centipetal Acceleation and Foce Peiod, Fequency, and Speed Vocabulay Vocabulay Peiod: he time it takes fo one full otation o evolution of an object. Fequency: he numbe of otations o

More information

Physics 111. Lecture 14 (Walker: Ch. 6.5) Circular Motion Centripetal Acceleration Centripetal Force February 27, 2009

Physics 111. Lecture 14 (Walker: Ch. 6.5) Circular Motion Centripetal Acceleration Centripetal Force February 27, 2009 Physics 111 Lectue 14 (Walke: Ch. 6.5) Cicula Motion Centipetal Acceleation Centipetal Foce Febuay 7, 009 Midtem Exam 1 on Wed. Mach 4 (Chaptes 1-6) Lectue 14 1/8 Connected Objects If thee is a pulley,

More information

Physics 231 Lecture 21

Physics 231 Lecture 21 Physics 3 Lectue Main points o today s lectue: Angula momentum: L Newton s law o univesal gavitation: GMm F PE GMm Keple s laws and the elation between the obital peiod and obital adius. T π GM 4 3 Rolling

More information

Department of Physics, Korea University Page 1 of 5

Department of Physics, Korea University Page 1 of 5 Name: Depatment: Student ID #: Notice ˆ + ( 1) points pe coect (incoect) answe. ˆ No penalty fo an unansweed question. ˆ Fill the blank ( ) with ( ) if the statement is coect (incoect). ˆ : coections to

More information

Circular Motion & Torque Test Review. The period is the amount of time it takes for an object to travel around a circular path once.

Circular Motion & Torque Test Review. The period is the amount of time it takes for an object to travel around a circular path once. Honos Physics Fall, 2016 Cicula Motion & Toque Test Review Name: M. Leonad Instuctions: Complete the following woksheet. SHOW ALL OF YOUR WORK ON A SEPARATE SHEET OF PAPER. 1. Detemine whethe each statement

More information

b) (5) What is the magnitude of the force on the 6.0-kg block due to the contact with the 12.0-kg block?

b) (5) What is the magnitude of the force on the 6.0-kg block due to the contact with the 12.0-kg block? Geneal Physics I Exam 2 - Chs. 4,5,6 - Foces, Cicula Motion, Enegy Oct. 13, 2010 Name Rec. Inst. Rec. Time Fo full cedit, make you wok clea to the gade. Show fomulas used, essential steps, and esults with

More information

A car of mass m, traveling at constant speed, rides over the top of a circularly shaped hill as shown.

A car of mass m, traveling at constant speed, rides over the top of a circularly shaped hill as shown. A ca of mass m, taveling at constant speed, ides ove the top of a ciculaly shaped hill as shown. The magnitude of the nomal foce N of the oad on the ca is. A) Geate than the weight of the ca, N > mg. B)

More information

PROBLEM (page 126, 12 th edition)

PROBLEM (page 126, 12 th edition) PROBLEM 13-27 (page 126, 12 th edition) The mass of block A is 100 kg. The mass of block B is 60 kg. The coefficient of kinetic fiction between block B and the inclined plane is 0.4. A and B ae eleased

More information

Sections and Chapter 10

Sections and Chapter 10 Cicula and Rotational Motion Sections 5.-5.5 and Chapte 10 Basic Definitions Unifom Cicula Motion Unifom cicula motion efes to the motion of a paticle in a cicula path at constant speed. The instantaneous

More information

TAMPINES JUNIOR COLLEGE 2009 JC1 H2 PHYSICS GRAVITATIONAL FIELD

TAMPINES JUNIOR COLLEGE 2009 JC1 H2 PHYSICS GRAVITATIONAL FIELD TAMPINES JUNIOR COLLEGE 009 JC1 H PHYSICS GRAVITATIONAL FIELD OBJECTIVES Candidates should be able to: (a) show an undestanding of the concept of a gavitational field as an example of field of foce and

More information

Centripetal Force. Lecture 11. Chapter 8. Course website:

Centripetal Force. Lecture 11. Chapter 8. Course website: Lectue 11 Chapte 8 Centipetal Foce Couse website: http://faculty.uml.edu/andiy_danylov/teaching/physicsi PHYS.1410 Lectue 11 Danylov Depatment of Physics and Applied Physics Today we ae going to discuss:

More information

Describing Circular motion

Describing Circular motion Unifom Cicula Motion Descibing Cicula motion In ode to undestand cicula motion, we fist need to discuss how to subtact vectos. The easiest way to explain subtacting vectos is to descibe it as adding a

More information

Objects usually are charged up through the transfer of electrons from one object to the other.

Objects usually are charged up through the transfer of electrons from one object to the other. 1 Pat 1: Electic Foce 1.1: Review of Vectos Review you vectos! You should know how to convet fom pola fom to component fom and vice vesa add and subtact vectos multiply vectos by scalas Find the esultant

More information

CIRCULAR MOTION. Particle moving in an arbitrary path. Particle moving in straight line

CIRCULAR MOTION. Particle moving in an arbitrary path. Particle moving in straight line 1 CIRCULAR MOTION 1. ANGULAR DISPLACEMENT Intoduction: Angle subtended by position vecto of a paticle moving along any abitay path w..t. some fixed point is called angula displacement. (a) Paticle moving

More information

Uniform Circular Motion

Uniform Circular Motion Unifom Cicula Motion Intoduction Ealie we defined acceleation as being the change in velocity with time: a = v t Until now we have only talked about changes in the magnitude of the acceleation: the speeding

More information

Chapter 4: The laws of motion. Newton s first law

Chapter 4: The laws of motion. Newton s first law Chapte 4: The laws of motion gavitational Electic magnetic Newton s fist law If the net foce exeted on an object is zeo, the object continues in its oiginal state of motion: - an object at est, emains

More information

4. Two and Three Dimensional Motion

4. Two and Three Dimensional Motion 4. Two and Thee Dimensional Motion 1 Descibe motion using position, displacement, elocity, and acceleation ectos Position ecto: ecto fom oigin to location of the object. = x i ˆ + y ˆ j + z k ˆ Displacement:

More information

F(r) = r f (r) 4.8. Central forces The most interesting problems in classical mechanics are about central forces.

F(r) = r f (r) 4.8. Central forces The most interesting problems in classical mechanics are about central forces. 4.8. Cental foces The most inteesting poblems in classical mechanics ae about cental foces. Definition of a cental foce: (i) the diection of the foce F() is paallel o antipaallel to ; in othe wods, fo

More information

Circular Motion. Mr. Velazquez AP/Honors Physics

Circular Motion. Mr. Velazquez AP/Honors Physics Cicula Motion M. Velazquez AP/Honos Physics Objects in Cicula Motion Accoding to Newton s Laws, if no foce acts on an object, it will move with constant speed in a constant diection. Theefoe, if an object

More information

Chapter 12. Kinetics of Particles: Newton s Second Law

Chapter 12. Kinetics of Particles: Newton s Second Law Chapte 1. Kinetics of Paticles: Newton s Second Law Intoduction Newton s Second Law of Motion Linea Momentum of a Paticle Systems of Units Equations of Motion Dynamic Equilibium Angula Momentum of a Paticle

More information

Understanding the Concepts

Understanding the Concepts Chistian Bache Phsics Depatment Bn Maw College Undestanding the Concepts PHYSICS 101-10 Homewok Assignment #5 - Solutions 5.7. A cclist making a tun must make use of a centipetal foce, one that is pependicula

More information

Spring 2001 Physics 2048 Test 3 solutions

Spring 2001 Physics 2048 Test 3 solutions Sping 001 Physics 048 Test 3 solutions Poblem 1. (Shot Answe: 15 points) a. 1 b. 3 c. 4* d. 9 e. 8 f. 9 *emembe that since KE = ½ mv, KE must be positive Poblem (Estimation Poblem: 15 points) Use momentum-impulse

More information

Ch. 4: FOC 9, 13, 16, 18. Problems 20, 24, 38, 48, 77, 83 & 115;

Ch. 4: FOC 9, 13, 16, 18. Problems 20, 24, 38, 48, 77, 83 & 115; WEEK-3 Recitation PHYS 3 eb 4, 09 Ch. 4: OC 9, 3,, 8. Pobles 0, 4, 38, 48, 77, 83 & 5; Ch. 4: OC Questions 9, 3,, 8. 9. (e) Newton s law of gavitation gives the answe diectl. ccoding to this law the weight

More information

Exam 3: Equation Summary

Exam 3: Equation Summary MAACHUETT INTITUTE OF TECHNOLOGY Depatment of Physics Physics 8. TEAL Fall Tem 4 Momentum: p = mv, F t = p, Fext ave t= t f t = Exam 3: Equation ummay = Impulse: I F( t ) = p Toque: τ =,P dp F P τ =,P

More information

SAMPLE QUIZ 3 - PHYSICS For a right triangle: sin θ = a c, cos θ = b c, tan θ = a b,

SAMPLE QUIZ 3 - PHYSICS For a right triangle: sin θ = a c, cos θ = b c, tan θ = a b, SAMPLE QUIZ 3 - PHYSICS 1301.1 his is a closed book, closed notes quiz. Calculatos ae pemitted. he ONLY fomulas that may be used ae those given below. Define all symbols and justify all mathematical expessions

More information

Radius of the Moon is 1700 km and the mass is 7.3x 10^22 kg Stone. Moon

Radius of the Moon is 1700 km and the mass is 7.3x 10^22 kg Stone. Moon xample: A 1-kg stone is thown vetically up fom the suface of the Moon by Supeman. The maximum height fom the suface eached by the stone is the same as the adius of the moon. Assuming no ai esistance and

More information

Lecture 1a: Satellite Orbits

Lecture 1a: Satellite Orbits Lectue 1a: Satellite Obits Outline 1. Newton s Laws of Mo3on 2. Newton s Law of Univesal Gavita3on 3. Calcula3ng satellite obital paametes (assuming cicula mo3on) Scala & Vectos Scala: a physical quan3ty

More information

Phys 201A. Homework 6 Solutions. F A and F r. B. According to Newton s second law, ( ) ( )2. j = ( 6.0 m / s 2 )ˆ i ( 10.4m / s 2 )ˆ j.

Phys 201A. Homework 6 Solutions. F A and F r. B. According to Newton s second law, ( ) ( )2. j = ( 6.0 m / s 2 )ˆ i ( 10.4m / s 2 )ˆ j. 7. We denote the two foces F A + F B = ma,sof B = ma F A. (a) In unit vecto notation F A = ( 20.0 N)ˆ i and Theefoe, Phys 201A Homewok 6 Solutions F A and F B. Accoding to Newton s second law, a = [ (

More information

Motion in Two Dimensions

Motion in Two Dimensions SOLUTIONS TO PROBLEMS Motion in Two Dimensions Section 3.1 The Position, Velocity, and Acceleation Vectos P3.1 x( m) 0!3 000!1 70!4 70 m y( m)!3 600 0 1 70! 330 m (a) Net displacement x + y 4.87 km at

More information

GRAVITATION. Contents. Theory Exercise Exercise Exercise Exercise Answer Key

GRAVITATION. Contents. Theory Exercise Exercise Exercise Exercise Answer Key GAVITATION Contents Topic Page No. Theoy 0-0 Execise - 0 - Execise - - 8 Execise - 8 - Execise - 4 - Answe Key - 4 Syllabus Law of gavitation; Gavitational potential and field; Acceleation due to gavity;

More information